Please help due very soon!!!!

[tex]( - \frac{3}{4} )( \frac{7}{8} )[/tex]

[tex] = \frac{ - 3}{4} \times \frac{7}{8} [/tex]

[tex] = \frac{ - 21}{32} [/tex]

_______________________________________

[tex]( \frac{2}{3} )( - 4)(9)[/tex]

[tex] = \frac{2}{3} \times - 4 \times 9[/tex]

[tex] = \frac{ - 72}{3} [/tex]

[tex] = - 24[/tex]

_______________________________________

[tex]( \frac{5}{16} )( - 2)( - 4)( - \frac{4}{5} )[/tex]

[tex] = \frac{5}{16} \times - 2 \times - 4 \times \frac{ - 4}{5} [/tex]

[tex] = \frac{ - 160}{80} [/tex]

[tex] = \frac{ - 16}{8} [/tex]

[tex] = - 2[/tex]

_______________________________________

[tex](2 \frac{3}{5} )( \frac{7}{9} )[/tex]

[tex] = \frac{13}{5} \times \frac{7}{9} [/tex]

[tex] = \frac{91}{45} [/tex]

Answer:

Moses ran 8 Luis ran 12.

Step-by-step explanation:

.

Number of laps to Louis run is 12 when Moses ran 8 laps.

What is mean by Ratio?

A ratio indicates how many times one number contain in another number. The ratio of two number is written as x : y, which is equivalent to x/y.

Where, x and y are individual amount of two quantities.

And, Total quantity gives after combine as x + y.

Given that;

The ratio of the number of laps Moses ran to the number of laps Louis ran = 2 : 3

Now,

Since,  The ratio of the number of laps Moses ran to the number of laps Louis ran = 2 : 3

So, Number of laps Moses ran = 2x

And, Number of laps Louis ran = 3x

If Moses ran 8 laps.

Then, we get;

2x = 8

x = 4

Then, Number of laps Louis ran = 3x

                                                 = 3 × 4

                                                 = 12

Thus, Number of laps to Louis run is 12 when Moses ran 8 laps.

Learn more about the ratio visit:

https://brainly.com/question/25927869

#SPJ2

Answer:

Kenji is wrong

Step-by-step explanation:

3⁵ · 4⁵ = (3 · 4)⁵ = 12⁵

but 12¹⁰ ≠ 12⁵

so , kenji is wrong

Answer:

[tex]x_{1}[/tex] = [tex]\frac{\pi }{6}[/tex] and [tex]x_{2}[/tex] = [tex]\frac{5\pi }{6}[/tex]

Step-by-step explanation:

Answer:

Step-by-step explanation:

First of all the first term is a1 and that's equal to -3

Every term is multiplied by 7

So the recursive formula is

an = 7*a_(n-1)

a2 = 7*a_(1 -1)

a2 = 7*-3

a2 = - 21

Now try a_4

a_4 = 7*a_3

a_3 = -147

a_4 = 7*(-147)

a_4 = -1029

Answer:

is there is no value of April

Step-by-step explanation:

so the value of the month April is zero

Answer:

2nd one, 3rd one and last one

Answer:

[tex]\rm x = 2 , 2 [/tex]

Step-by-step explanation:

A quadratic equation is given to us and we need to find the solution of the equation. The given equation is ,

[tex]\implies x^2 -4x + 4 = 0 [/tex]

Now for finding the roots of the equation , let's use the quadratic formula , or by factorising out the equation . Here I would be using the factorization method , as ,

[tex]\implies x^2 -4x + 4 = 0\\\\\implies x^2-2x-2x+4 = 0 \\\\\implies x(x-2) -2(x-2) = 0 \\\\\implies (x-2)(x-2) = 0 \\\\\implies x = 2, 2 [/tex]

Hence the Solution of the equation is 2,2.

Answer:

Step-by-step explanation:

x² - 4x  +4 = 0

Factorization method:

Sum = -4

Product = 4

Factor = (-2) ; (-2)    {-2 * -2 = 4  & (-2) + (-2) = -4}

x² -4x + 4 = 0

x² - 2x - 2x  + (-2)*(-2) = 0

x(x - 2) - 2 (x - 2) = 0

(x - 2) (x - 2) = 0

x - 2 = 0  or x -2 = 0

 x = 2      or x = 2

x = 2 , 2

Answer:

Step-by-step explanation:

Range goes from the lowest point on a graph to the highest point, not including anything in between those 2 extremes. We will evaluate the quadratic for the values given. First f(2):

[tex]f(2)=(2)^2-5[/tex] so

f(2) = -1

Now, f(4):

[tex]f(4)=(4)^2-5[/tex] so

f(4) = 11

Now, f(7):

[tex]f(7)=(7)^2-5[/tex] so

f(7) = 44

The lowest y value is -1 and the highest is 44, so the range is from -1 to 44 (I can't tell which of your choices reflects that because it's too small!)

Answer:

slope is zero

Step-by-step explanation:

This is a horizontal line parallel to the x- axis

Since the slope of the x- axis is zero then the slope of the line is zero

Answer:

its slope is zero

Step-by-step explanation:

the slope of a line is simply the ratio between y- and x-change from one point of the line to another.

you can express it as y/x.

e.g. 5/2 - meaning that when x changes by 2 units, y changes by 5 units (so, it goes up steeply).

now, the line in the graph is just a flat line. no matter how many units we change x and move to the right, y won't change and simply stay at 2.5.

so, 0 change in y.

and the slope is 0/"delta x" for "delta x">0

all that means the slope is 0, as 0 divided by anything is always 0.

the function for that line is therefore

y = 0×x + 2.5 or simply

y = 2.5

and the factor of x (in this case 0) is always the slope of the line.

Answer:

Step-by-step explanation:

Cylinder volume:

Substitute values:

As we know the,

General formula for volume of cylinder,

→ V = πr²h

Now we can find,

The volume of the cylinder,

→ πr²h

→ π(24/2)² × 8

→ π × 12² × 8

→ 3619.11 in³

Hence, volume of cylinder is 3619.11 in³.

bAnswer: the answers is most likely a because of the nomination

Step-by-step explanation:

Answer:

6, -5 and 6. Assume the leading coefficient of f(x) is 1. Write the equation of the cubic polynomial in standard form.

Answer:

A

Step-by-step explanation:

Just did it

Answer:

c

Step-by-step explanation:

Answer:

answer will be the integer only which was added to zero

Answer:

Step-by-step explanation:

Given:

Use point slope form:

So the equation is:

❀ [tex]\huge\underline{ \underline{Solution :-}}[/tex]

[tex]( {y}^{2} + \frac{5}{7} )( {y}^{2} - \frac{14}{5} )[/tex]

To solve, use the algebraic identity ➺

[tex]( {y}^{2} + \frac{5}{7} )( {y}^{2} - \frac{14}{5} ) \\ = ({y}^{2}) ^{2} + ( \frac{5}{7} + - \frac{14}{5} ) {y}^{2} + \frac{5}{7} \times - \frac{14}{5} \\ = {y}^{4} - \frac{73}{35} {y}^{2} - 2[/tex]

ʰᵒᵖᵉ ⁱᵗ ʰᵉˡᵖˢ

꧁❣ ʀᴀɪɴʙᴏᴡˢᵃˡᵗ2²2² ࿐

1/4 or 25 percent because there is a 1/2 chance to get a boy or girl so the probability that will be boys us 1/2 x 1/2= 1/4

Answer:

From what I learn it is 360 degrees

Answer:

A. 9x

B. ( 2 + 3 + 4 ) x

Step-by-step explanation:

2x + 3x + 4x = 9x

2x + 3x + 4x

= ( 2 + 3 + 4 ) x

Answer:

The answer is the first one

Step-by-step explanation:

[tex] {\bold{\red{\huge{\mathbb{QUESTION}}}}} [/tex]

The semicircle shown at left has center X and diameter W Z. The radius XY of the semicircle has length 2. The chord Y Z has length 2. What is the area of the shaded sector formed by obtuse angle WXY?

[tex]\bold{ \red{\star{\blue{GIVEN }}}}[/tex]

RADIUS = 2

CHORD = 2

RADIUS --> XY , XZ , WX

( BEZ THEY TOUCH CIRCUMFERENCE OF THE CIRCLES AFTER STARTING FROM CENTRE OF THE CIRCLE)

[tex]\bold{\blue{\star{\red{TO \: \: FIND}}}}[/tex]

THE AREA OF THE SHADED SECTOR FORMED BY OBTUSE ANGLE WXY.

[tex] \bold{ \green{ \star{ \orange{FORMULA \: USED}}}}[/tex]

AREA COVERED BY THE ANGLE IN A SEMI SPHERE

[tex]AREA = ANGLE \: \: IN \: \: RADIAN \times RADIUS[/tex]

[tex] \huge\mathbb{\red A \pink{N}\purple{S} \blue{W} \orange{ER}}[/tex]

Total Area Of The Semi Sphere:-

[tex]AREA = \pi \times radius \\ \\ AREA = \pi \times 2 = 2\pi[/tex]

Area Under Unshaded Part .

Given a triangle with each side 2 units.

This proves that it's is a equilateral triangle which means it's all angles r of 60° or π/3 Radian

So AREA :-

[tex]AREA = \frac{\pi}{3} \times radius \\ \\ AREA = \frac{\pi}{3} \times 2 \\ \\ AREA = \frac{2\pi}{3} [/tex]

[tex] \green{Now:- } \\ \green{ \: Area \: Under \: Unshaded \: Part }[/tex]

Total Area - Area Under Unshaded Part

[tex] Area= 2\pi - \frac{2\pi}{3} \\ Area = \frac{6\pi - 2\pi}{3} \\ Area = \frac{4\pi}{3} \: \: ans[/tex]

[tex] \red \star{Thanks \: And \: Brainlist} \blue\star \\ \green\star If \: U \: Liked \: My \: Answer \purple \star[/tex]

Answer: False

Step-by-step explanation:

There is no such deduction when a participation's questions are not answered correctly the first time. Whatever answer is given is part of the learning curve and ensures that the activity can be improved upon.

Had there been a small point deduction then there would be no opportunity to learn because there would be too much fear associated with the wrong answer.

Answer:

square tables

round tables

12

Step-by-step explanation:

is this really that difficult ?

just think logically.

a square table sits 8 people. that means every square table "stands" for 8 people present.

a round table sits 6 people. so, every round table "stands" for 6 people present.

now, the whole party has 150 people.

that means the sum of all people on all tables is 150.

so, if we count all square tables, we know how many people are sitting at square tables, as each table "stands" for 8 people (we multiply the number of square tables by 8).

similar for the round tables.

so, we say we have x square tables and y round tables.

therefore the equation is

150 = 8×x + 6×y

the variable with the factor 8 must be describing the square tables (due to the reasons above).

that is x.

and the variable with the factor 6 must describe the round tables.

that is y.

now we are told that there are 9 round tables (y=9).

using the equation from above

150 = 8×x + 6×9 = 8×x + 54

96 = 8×x

x = 12

so, we must have 12 square tables to satisfy the condition that we have in total 150 people present.

Answer:

super find out how many of

[tex]\sf\huge\underline\red{SOLUTION:}[/tex]

[tex]\sf\huge\underline\red{ANSWER:}[/tex]

✍︎☘︎ᴍᴀᴛʜᴅᴇᴍᴏɴǫᴜᴇᴇɴ☘︎

✍︎ꕥᴄᴀʀʀʏᴏɴʟᴇᴀʀɴɪɴɢꕥ

Answer:

ハハハハハハハバカあなたも答えがわからない質問でも簡単に黙ってバカバカバカバカゴッド

[tex]\displaystyle\bf \boxed{V=abh \ ; \ 1dm^3=1litre=1000cm^3} \\\\a=12cm \ ; \ b=8 cm ;\: h_1=7 \; ; \ h_0=h_1+h_2=?\\\\abh_2=1,2litre=1,2dm^3\ = 1200cm^3\\\\ 8\cdot 12 h_2=1200\\\\h_2=12.5 cm\: then \\\\h_0= 7+12,5=19,5 \\\\Answer : the \ height \ of \ the \ tank \ is \ 19,5 cm[/tex]

Answer:

∠CAB

Step-by-step explanation:

Exterior angles include two corner points and one point not on the triangle. Thus, ∠CAD would be an exterior angle.

Answer:

Step-by-step explanation:

A triangle has 3 interior angles. In this case, they are

<ABF

<BFA

<FAB

An exterior angle is the supplement of one of the angles. In this case, there is only 1 angle that qualifies -- <CAB which is the supplement of BAF.

All the other choices are not supplements to any of the interior angles such as

<BAD

<AFE

<CAD

Answer:

[tex]{ \tt{27 = {3}^{3} }} \\ { \tt{}} \sqrt[4]{27} = {27}^{ \frac{1}{4} } \\ { \tt{ = {3}^{3( \frac{1}{4}) } }} \\ = { \tt{ {3}^{ \frac{3}{4} } }} \\ { \boxed{ \bf{a = 3 \: \: and \: \: k = \frac{3}{4} }}}[/tex]