PLEASE HELP DO IN 20 MIN WILL MARK BRAINLIEST PLEASE SHOW WORK!

Let's say someone throws a candy bar of their choice at a wall which is set as the positive direction with a velocity of 28.0 m/s. After it hits the wall, it takes 0.020 s to stop. What is the acceleration (in m/s^2) of the candy bar when it hits the wall?

Answers

Answer 1

Answer:

6997200

Explanation:

plz mark as the brainliest


Related Questions

Nikolas had an idea that he could use the compressed carbon dioxide in a fire extinguisher to propel him on his skateboard.

Nikolas, the fire extinguisher, and the skateboard have a combined mass of 50 kg. What force would the fire extinguisher have to produce to propel Nikolas if he wanted to accelerate at a rate of 1.2 m/s2? Round your answer to the nearest whole newton.

60 N

Which of Newton’s laws did Nikolas have to use to calculate this force?

Answers

Answer:

I'm terrible at explaining so here's a screenshot, please do not listen to the other answer, it is wrong.

- Ripper

Explanation:

Answer:

C is the correct answer !!!

Explanation:

The time it takes for a dragster to cross the finish line is unknown. The dragster accelerates from rest at 26 m/s2 for a quarter-mile (402 m). What is the final velocity of the dragster?

Answers

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[tex] {v}^{2} - {v(0)}^{2} = 2.a.∆x[/tex]

[tex]v = final \: \: velocity[/tex]

[tex]v(0) = the \: \: velocity \: \: in \: \: the \: \: rest \: \: which \: \: is \: \: zero \\ [/tex]

[tex]a = acceleration[/tex]

[tex]∆x = covered \: \: distance[/tex]

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[tex] {v}^{2} - ({0})^{2} = 2 \times 26 \times 402 [/tex]

[tex] v = \sqrt{2 \times 26 \times 402} [/tex]

[tex]v = \sqrt{20904} [/tex]

[tex]v = 144.58 \: \: \frac{m}{s} [/tex]

Done...

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În ce raport de mase trebuie amestecate două cantități din același lichid, având temperaturile t1=10 grade Celsius, respectiv t2=65 grade Celsius, pentru a obține o temperatură de echilibru t=45 grade Celsius?

Answers

Răspuns:

7: 4

Explicaţie:

Formula pentru calcularea cantității de căldură absorbită este exprimată ca;

Q = mc∆t

m este masa substanței

c este capacitatea termică specifică

∆t este schimbarea temperaturii

Conform legii calorimetriei, căldura pierdută de substanța rece = căldura câștigată de substanța fierbinte.

Folosind formula

(mc∆t) rece = (mc∆t) fierbinte

McCw∆tc = MhCw∆th

Deoarece au aceeași capacitate de căldură specifică, se vor anula. Ecuația devine;

Mc∆tc = Mh∆th ...... 1

Pentru apa rece;

∆tc = 45 ° C - 10 ° C

∆tc = 35 ° C

Pentru apa fierbinte:

∆th = 65 ° C - 45 ° C

∆th = 20 ° C

Înlocuiți în ecuația 1;

Mc (35) = Mh (20)

35Mc = 20Mh

Luând raportul dintre masa apei reci și cea fierbinte:

Mh / Mc = 35/20

Mh / Mc = 7/4

Prin urmare, lichidul trebuie amestecat împreună în raportul 7: 4

Los satélites de televisión giran alrededor de la Tierra en una órbita de 42370 km de radio. a) ¿Cuánto vale la aceleración de la gravedad en esa órbita? (Resultado: g = 0,22 m/s2 ) b) ¿Cuánto pesará allí un satélite de 1200 kg? (Resultado: P = 264 N) Datos: G = 6,67 10-11 Nm2 /kg masa de la Tierra: 6 1024 kg

Answers

Answer:

(a) La aceleración de la gravedad en esa órbita es 0.22 [tex]\frac{m}{s^{2} }[/tex]

(b) Un satélite de 1,200 kg pesará allí 264 N.

Explanation:

(a) Cada punto del espacio tiene un  valor del campo proporcional a la función, siguiendo el modelo de gravitación de Newton:

[tex]g=G*\frac{m}{r^{2} }[/tex]

donde m será masa, r  la distancia entre los objetos y G la constante de gravitación universal, cuyo valor es [tex]G=6.672*10^{-11}\frac{N*m^{2} }{kg }[/tex]

En este caso:

m= 6*10²⁴ kgr=42,370 km= 42,370,000 m

Reemplazando:

[tex]g=6.672*10^{-11}\frac{N*m^{2} }{kg }*\frac{6*10^{24}kg }{(42,370,000 m)^{2} }[/tex]

Resolviendo, obtenes:

g= 0.22 [tex]\frac{m}{s^{2} }[/tex]

La aceleración de la gravedad en esa órbita es 0.22 [tex]\frac{m}{s^{2} }[/tex]

(b) La ley fundamental de la dinámica o segunda ley de Newton expresa que la fuerza neta que es aplicada sobre un cuerpo es proporcional a la aceleración que adquiere en su trayectoria.  Esto se expresa matemáticamente como:

F= m*a

en donde  F es fuerza neta , m la masa y a la aceleración.

El peso es la fuerza que ejerce la gravedad sobre una masa, por lo que se obtiene de manera análoga a la fuerza:

P=m*g

En este caso la masa m tiene un valor de 1,200 kg y la gravedad g un valor de 0.22 [tex]\frac{m}{s^{2} }[/tex].

Reemplazando:

P=1,200 kg*0.22 [tex]\frac{m}{s^{2} }[/tex]

Resolviendo:

P= 264 N

Un satélite de 1,200 kg pesará allí 264 N.

Jen had an average speed of 2.5 m/s when hopping on one foot. If she hopped for 5.0 seconds, for what distance was she hopping?

Answers

Explanation:

distance

speed =_________

time

distance = speed × time

= 2.5 × 5.0

distance = 12.5 m

A person travels by car from one city to another. He drives for 30.0 min at 80.0 km/h, 12.0 min at 105 km/h, and 45.0 min at 40.0 km/h, and he spends 15.0 min eating lunch and buying gas. What is the average speed for the trip?

Answers

Answer:

53.53 km/h

Explanation:

Given that the person drives for 30.0 min at 80.0 km/h, 12.0 min at 105 km/h, and 45.0 min at 40.0 km/h, and he spends 15.0 min eating lunch and buying gas.

So, the total time to complete the journey is

t=30+12+45+15=102 min

[tex]=\frac{102}{60}=1.7[/tex] hours

As distance=(speed)x(time), so

the distance covered in 30 minutes with a speed of 80 km/h

[tex]d_1=80 \times \frac{30}{60}=40[/tex] km.

The distance covered in 12 minutes with a speed of 105 km/h

[tex]d_2=105 \times \frac{12}{60}=21 km[/tex].

The distance covered in 45 minutes with a speed of 40 km/h

[tex]d_3=40 \times \frac{45}{60}=30 km[/tex].

So, to the total distance covered is

[tex]d=d_1+d_2+d_3[/tex]

[tex]=40+21+30=91 km[/tex]

As the average speed = (Total distance covered)/(Total time taken)

So, the average speed for the whole journey

[tex]=\frac{d}{t}[/tex]

[tex]=\frac{91}{1.7}= 53.53 km/h[/tex].

Hence, the average speed for the trip is 53.53 km/h.

when a car suddenly stops,the objects in the backseat are thrown forward.this is explained by-

A.Newton's first law of motion
B.Newton's second law of motion
C.Newton's third law of motion
D.the universal law of gravitation

Answers

Answer:law of interia(1st law)

Explanation:

PLEASE HELP THE question on picture

Answers

Vertical:

(20 m/s) sin(25º) ≈ 8.45 m/s

Horizontal:

(20 m/s) cos(25º) ≈ 18.1 m/s

the faster particles move the less kinetic energy they have true or false

Answers

Answer:

False

Explanation:

You get more kinetic energy the more the particles and less kinetic energy with less particles

What is one physical benefit that can be obtained from participating in field events?

A) strengthen balance
B) better sleep pattern
C) increase capacity for learning
D) all of the above

Answers

Answer:

D

Explanation:

It does all three

find acceleration of block and tension in strings if m1 =8kg m2= 4kg and take g=10m/s²​

Answers

[tex]\large\bold{\underline{\underline{Given:-}}}[/tex]

[tex]\sf{m_1}[/tex] = 8kg

[tex]\sf{m_2}[/tex] = 4kg

g = 10m/s²

[tex]\large\bold{\underline{\underline{To \: Find:-}}}[/tex]

→Acceleration of block

→Tension in strings

[tex]\large\bold{\underline{\underline{Solution:-}}}[/tex]

Let, the two equation will be ,

[tex]\leadsto[/tex] 8g - T = 8a ..... Equation no (1)

[tex]\leadsto[/tex] T - 4g = 4a ..... Equation no (2)

Putting the value of equation no (1) and (2) we get,

[tex]\implies[/tex] 4g = 12a

[tex]\implies[/tex] 4 × 10 = 12a

[tex]\implies[/tex] 40 = 12a

[tex]\implies[/tex] a = [tex]\sf\dfrac{\cancel{40}}{\cancel{12}}[/tex]

[tex]\dashrightarrow[/tex] a = [tex]\dfrac{10}{3}[/tex]

Again, we have to putting the value of a in the equation no (2) we get,

[tex]\implies[/tex] T - 4g = 4 × [tex]\dfrac{10}{3}[/tex]

[tex]\implies[/tex] T - 4 × 10 = 4 × [tex]\dfrac{10}{3}[/tex]

[tex]\implies[/tex] T - 40 = [tex]\dfrac{40}{3}[/tex]

[tex]\implies[/tex] T = [tex]\dfrac{40}{3}[/tex] + 40

[tex]\implies[/tex] T = [tex]\dfrac{40 + 120}{3}[/tex]

[tex]\dashrightarrow[/tex] T = [tex]\dfrac{160}{3}[/tex] N

[tex]\therefore[/tex] Acceleration of block = [tex]\dfrac{10}{3}[/tex] m/s².

And, Tension in strings = [tex]\dfrac{160}{3}[/tex] N

Light travels in a transparent material at 2.5 x 10 m/s. Find the index of refraction of the
material.

Answers

I would say 5.6 to the 4 and I’ll I did was add it to both side

We have that for the Question "Light travels in a transparent material at 2.5 x 10 m/s. Find the index of refraction of the material." it can be said that

From the question we are told

Light travels in a transparent material at 2.5 x 10 m/s. Find the index of refraction of the  material.

Generally the equation for the  index of refraction  is mathematically given as

[tex]n=\frac{C}{v}\\\\Therefore\\\\n=\frac{3*10^8}{2.5 * 10 }\\\\n=12000000\\\\[/tex]

Therefore

The  index of refraction  of the material is

n=12000000

For more information on this visit

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Athlete’s foot is also called...
A.) pedicure sickness Not Quite!
B.) runner’s bacteria Not Quite!
C.) toe virus Not Quite!
D.) tinea pedis

Answers

Answer:

Your answer is: D) Tinea Pedis

Explanation:

Hope this helped : )

A family decides to travel from
Watsonville, CA to Guadalajara, Mexico
for the holidays. The family has to
travel 2,172 miles. The trip takes them a
total of 39.5 hours. What is their
velocity?

Answers

D=vt
V=d/t
V=2,172 mi / 39.5 h
V=54.987 mi/h

hey pls help with this HDJSJDH im rlly bad at this kinda stuff :,) i'll mark the correct answer brainliest

Answers

I am pretty sure it’s A
The cue exerts force onto the white ball which pushes the blue ball into the direction of the hole.

Answer:

A. Cue, White Ball, Blue Ball

Explanation:

Visualize in which order things are being hit

A stunt man launches a car from the edge of a cliff horizontally. If he is launching off a
30-meter high cliff and must hit a mark 268-meters down range, with what speed
must he leave the cliff?

Answers

Answer:

All i got to say is that he is dead dead

Explanation:

What is the mass of a falling rock if it produces a force of 147 N with an acceleration of 9.8 m/s2? ​

Answers

Answer:

15 kg

Explanation:

The mass of the object can be found by using the formula

[tex]m = \frac{f}{a} \\ [/tex]

f is the force

a is the acceleration

From the question we have

[tex]m = \frac{147}{9.8} \\ [/tex]

We have the final answer as

15 kg

Hope this helps you

HELP PLEASE

A load is a device that changes electrical energy into other forms of energy. Which load converts electrical energy into thermal energy by passing an electric current through a high-resistance material?



A.
Hand-powered generator

B.
Toaster

C.
Fan

D.
Electrical drill

Answers

Answer:

A toaster because you plug it up for electric energy and heat to toast it

Which statement is supported by the information in the diagram and table below?

Answers

Answer:

a

Explanation:

a

What is the speed of a car that
accelerates at a rate of 10 m/s2 for a
total of 25 seconds?

Answers

Answer:

250 m/s

Explanation:

The speed of the car can be found by using the formula

v = a × t

where

a is the acceleration

v is the speed

t is the time

From the question we have

v = 10 × 25

We have the final answer as

250 m/s

Hope this helps you

Which of the following statements best describes the corn plants below?

Answers

Answer:

The Bt gene is inserted into one plant cell by using a bacterial plasmid.

Explanation:

A rubber-wheeled 50 kg cart rolls down a 35 degree concrete incline. Coefficient of rolling friction between rubber and concrete is = 0.02. (a) What is the cart's acceleration if rolling friction is neglected? (b) What is the cart's acceleration if rolling friction is included?

Answers

Answer:

(a) 5.62 m/s²

(b) 5.46 m/s²

Explanation:

The given values are:

mass,

m = 50 kg

angle

= 35°

(a)

If friction neglected,

⇒ [tex]F_x=mgSin \theta=ma[/tex]

⇒ [tex]a_x=gSin \theta[/tex]

       [tex]=9.8 \ Sin35^{\circ}[/tex]

       [tex]=5.62 \ m/s^2[/tex]

(b)

If friction present,

⇒ [tex]F_x=mgCos \theta[/tex]

⇒ [tex]F_x=mgSin \theta-\mu_r mgCos \theta[/tex]

⇒ [tex]a=gSin \theta-\mu_rgCos \theta[/tex]

      [tex]=9.8 \ Sin35^{\circ}-0.02\times 9.8 \ Cos30^{\circ}[/tex]

      [tex]=5.46 \ m/s^2[/tex]

Space-shuttle astronauts experience accelerations of about 35 m/s2 during takeoff. What force does a 75 kg astronaut experience during an acceleration of this magnitude?

Answers

Answer:

The answer is 2625 N

Explanation:

The force acting on an object given it's mass and acceleration can be found by using the formula

force = mass × acceleration

From the question we have

force = 75 × 35

We have the final answer as

2625 N

Hope this helps you

What is the speed of a
rocket that travels
8,000m in 13 seconds?

Answers

Answer:

speed of rocket=615.38m/s

Explanation:

When dribbling you should?
a. Use both feet.

b.Use frequent small touches of the ball.

C.Protect the ball with your body.

D. All of the above.

Answers

D all of the above (:

Marlene loves astronomy and has enrolled in an online course to learn more about space. The course gives Marlene access to a digital classroom.

What does this enable her to do? Check all that apply.

discuss the solar system with others in the class
attend a field trip to a planetarium at a local college
upload an amateur video of a shooting star
make a presentation about her favorite planet
take notes, tests, and quizzes
watch instructional videos made by a teacher

Answers

Answer:

A E and F are the correct answers

Explanation:

Answer:

A E F are correct

Explanation:

If your body were a tall building, your skeleton would be

Answers

The Beams And Joints That Hold It .

The unit of force is the newton (N). One newton is the force required to accelerate a 1-kg object at a rate of 1 m/s2. Suppose each fan supplies a force of 2 N.

Answers

Answer:

Explanation:

According to Newton's second law of lmotion

Force = mass × acceleration

Given

Mass = 1kg

Force = 2N

Required

Acceleration of the 2N body

From the formula

Acceleration = Force/mass

Acceleration = 2N/1

Acceleration = 2m/s²

When the energy of a wave increases, what happens to the amplitude?

Answers

Answer:

The energy transported by a wave is directly proportional to the square of the amplitude. So whatever change occurs in the amplitude, the square of that effect impacts the energy. This means that a doubling of the amplitude results in a quadrupling of the energy.

Explanation:

When the energy of a wave increases, the amplitude also increases. This is because the amplitude of the wave is directly proportional to the energy of a wave.

What is the amplitude of a wave?

The amplitude of a wave may be defined as the maximum displacement or distance moved by a point on a vibrating body or wave measured from its equilibrium position. It is equal to one-half the length of the vibration path.

It is the principle of physics that when the amplitude of the wave is higher, the energy also gets higher. To summarise, waves carry energy. The amount of energy they carry is related to their frequency and their amplitude. The higher the frequency, the more energy, and the higher the amplitude, the more energy.

Therefore, when the energy of a wave increases, the amplitude also increases. This is because the amplitude of the wave is directly proportional to the energy of a wave.

To learn more about Energy and amplitude, refer to the link:

https://brainly.com/question/19036728

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The lens in the eyepiece of a reflecting telescope breaks. How will this most affect the function of the telescope?
A. Magnified images will appear upside down. B. Magnified images will not be created.
C. Light from distant objects will not be captured.
D. Light rays will not be sent to the eyepiece.​

Answers

Answer:

B

Magnified images will not be created.

Explanation:

I did it and this was the correct answer

Answer:

B is correct the person above me is also correct. Hope this helps

Explanation:

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