Answer:
Explanation:
The dimension less constants are the constants having no dimensions and also have a constant value.
For example, 1, 2, 3... numbers, e (exponent), [tex]\pi[/tex], etc.
The dimension less variables are the variables having no dimensions.
For example, refractive index, angle, strain, etc.
a teacher and two students are mesuring the speed of sound. the teacher makes loud sound by hitting two cymbals together. each students starts a stopwatch then they see the teacher hit the cymbals, they each stop their stop watch when they hear the sound. describe how a sound wave moves through the air.
Answer:
Slowly and smoothly lol
Answer:
S.I. on Rs. 1600 = T.D. on Rs. 1680. Rs. 1600 is the P.W. of Rs. 1680, i.e., Rs. 80 is on Rs. 1600 at 15%. Time =100 x 80year=1year = 4 months.1600 x 153
Explanation:
Is this you are?
State newton's universal law of gravitation
Every particle of mass is attracted to every other particle of mass. The magnitude of the force between two objects is proportional to the product of their masses, and inversely proportional to the square of the distance between them. The direction of the force is along the line between their centers.
(NOTE: Newton's 3rd law of motion tells us that gravitational forces always come in pairs. Between two objects, there are two forces ... one in each direction. Their strengths are equal ... Your weight on Earth is exactly equal to the Earth's weight on YOU.)
A force of 10 N is making an angle of 30° with the horizontal. Its horizontal component will be:
A. 4N
B. 5N
C. 7N
D. 8.7 N
Answer:The answer is A
Explanation:just did it on a test
the hydrometer with the density of liquid to be 800 kg metre per square is the volume of the submerged part of the hydrometer is 5 into 10 to the power minus 5 calculate the mass of the hydrometer
Answer:
Mass = 0.04 Kg
Explanation:
Given the following data;
Density = 800 kg/m³
Volume = 5 * 10^{-5} m³
To find the mass of the object;
Density can be defined as mass all over the volume of an object.
Simply stated, density is mass per unit volume of an object.
Mathematically, density is given by the formula;
[tex] Density = \frac {mass}{volume} [/tex]
Making mass the subject of formula, we have;
[tex] Mass = density * volume [/tex]
Substituting the values into the formula, we have;
[tex] Mass = 800 * 5 * 10^{-5} [/tex]
Mass = 0.04 Kg
A student project is required to be portable and hand held. It requires 6 V DC power at a current of 150 mA. The batteries for the power supply must last for a minimum of 7 hours of continuous operation. NiMH rechargeable batteries in AA size are to be used. A) How many batteries are needed
Answer:
a. 5 batteries b. 1050 mAh
Explanation:
Here is the complete question
A student project is required to be portable and hand held. It requires 6 V DC power at a current of 150 mA. The batteries for the power supply must last for a minimum of 7 hours of continuous operation. NiMH rechargeable batteries in AA size are to be used. A) How many batteries are needed? B) What mAh capacity should the batteries have?
Solution
A) How many batteries are needed?
Since the nominal voltage for a single NiMH battery is 1.2 V per battery and we require 6V DC power, we combine the batteries in series to obtain a total voltage of 6 V. The number of batteries required, n = total voltage/voltage per cell = 6V/1.2V per battery = 5 batteries
So, the number of batteries needed is 5.
B) What mAh capacity should the batteries have?
Since the batteries are in series, they would each deliver a current of 150 mA. Since we require a current of 150 mA for 7 hours, the number of milliampere-hours capacity mAh of batteries required is Q = It where I = current = 150 mA and t = time = 7 hours.
So, Q = It = 150 mA × 7 h = 1050 mAh.
So, the batteries should have a mAh of 1050 mAh
A scientist measures the light from a distant star
at 525 nm. The constant for Wien's
displacement law is 2.9 x 10-3 m K. What is the
approximate temperature of the star in Kelvins?
A) 1500 K
B) 180,000 K
C) 1.5 K
D) 5500 K
The approximate temperature of the star as determined is D) 5500 K.
The Wien's displacement law relates the maximum wavelength of a body to its absolute temperature. Wien's displacement law states that:
λ = [tex]\frac{b}{T}[/tex]
where λ is the maximum wavelength of the body, b is the constant of proportionality and T is the absolute temperature.
Thus from the given question, λ = 525 nm (525 x [tex]10^{-9}[/tex]), and b = 2.9 x [tex]10^{-3}[/tex] mK.
So that,
525 x [tex]10^{-9}[/tex] = [tex]\frac{2.9*10^{-3} }{T}[/tex]
Make T the subject of the formula to have;
T = [tex]\frac{2.9*10^{-3} }{525*10^{-9} }[/tex]
= 5523.81
T = 5523.81 K
T ≅ 5500.00 K
The approximate temperature of the star in Kelvin is 5500 K.
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briefly explain what EMF of a cell cell is
Answer:
The emf of a cell is the sum of the electric potential differences (PDs) produced by a separation of charges (electrons or ions) that can occur at each phase boundary (or interface) in the cell. The magnitude of each PD depends on the chemical nature of the two contacting phases.
Explanation:
pls mark brainliest
A position of a particle moving on an x axis is given by x=7•4 + 9•2t - 2•1 t^3, with x in meters and t in seconds. what is its velocity at t=3•5s? is the velocity,or is it Continuously changing?
Answer:
The velocity at that time would be [tex](-67.975\; \rm s)[/tex]. The velocity of this particle is continuously changing.
Explanation:
Differentiate the expression for position [tex]x[/tex] with respect to time [tex]t[/tex] to find an expression for velocity.
[tex]\begin{aligned}v(t) &= \frac{d}{dt}[x(t)] \\ &= \frac{d}{dt} \left[ 7.4 + 9.2\, t - 2.1\, t^{3}\right]\\ &= 9.2 - 6.3\, t^{2}\end{aligned}[/tex].
Hence, at [tex]t = 3.5\; \rm s[/tex], velocity would be [tex]v(3.5) = 9.2 - 6.3 \times (3.5)^{2} = -67.975\; \rm m[/tex].
Since velocity [tex]v(t)[/tex] changes with time [tex]t[/tex], the velocity of this particle is continuously changing.
define Neutons 3rd law .
Answer:
that when two object interact, they apply forces to one another that are equal in magnitude and opposite in direction.
Explanation:
Newton's third law: the law of action and reaction
It takes Serina 1.81 hours to drive to school. Her route is 36 km long. What is Serina's average speed on her drive to school?
Answer:
60
Explanation:
because it shows he is moving at a low speed
I need help asap please
Answer:
I dont know answer Sorry For that thank u
A 63 kg kg person starts traveling from rest down a waterslide 6.0 mm above the ground. At the bottom of the waterslide, it then curves upwards by 1.0 mm above the ground such that the person is consequently launched into the air. Ignoring friction, how fast is the person moving upon leaving the waterslide
Answer:
change waterslide according to question. and you are good to go. check photo for solve
The person moving with speed upon leaving the waterslide is equal to 0.313 m/s while ignoring the friction.
What is the law of conservation of energy?If there is a loss of energy in any part of the system, there must be the same amount of a gain of energy in some other part of the isolated system.
Kinetic energy + Potential energy = constant
Therefore, the initial kinetic and potential energy of the person must be equal to the final kinetic and potential energy.
mgh₁ + mv₁²/2 = mgh₂ + mv₂²/2
gh₁ + v₁²/2 = gh₂ + v₂²/2
2gh₁ + v₁² = 2gh₂ + v₂²
2g(h₁ - h₂) = v₂² - v₁²
[tex]v_2=\sqrt{2g(h_2-h_1) + v^2_1}[/tex] .................(1)
Given, the mass of the person, m = 63 Kg
The initial speed of the person as at rest, v₁ = 0
Consider that the speed of the person while leaving the waterslide is v₂
The initial height of the person above the ground, h₁ = 6.0 mm
The height of the person leaving the waterslide, h₂= 1.0 mm
Substitute, the value of m, v₁, h₁ and h₂ in equation (1):
[tex]v_2 = \sqrt{2(9.8m/s^2)(6mm-1mm) + (0)^2}[/tex]
[tex]v_2 =\sqrt{2(9.8)\times 5 \times 10^{-3}} \;m/s[/tex]
[tex]v_2 =\sqrt{0.098}\; m/s[/tex]
v₂ = 0.313 m/s
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PLEASE HELP!!
A set of water waves travels at 20.0 m/s , and 5.0 waves pass you in 4.0 s. What is the wavelengths of the waves?
a. 0.25 m
b. 8.0 m
c. 0.20 m
d. 4.0 m
Answer:
Explanation:
[tex]\lambda\\[/tex] = v/f
^That is the formula we are going to use.
Now, we were given the speed (v), which is 20.
Now we need to find frequency, in order to solve for the wavelength.
Frequency is the amount of waves in a fixed unit of one second, meaning our F value is the value of 5 divided by 4.
5/4 = 1.25
Therefore our F is 1.25
Now lets plug it in
[tex]\lambda\\[/tex] = v/f
[tex]\lambda\\[/tex] = 20/1.25
[tex]\lambda\\[/tex] = 16
Conversion:
[tex]\lambda\\[/tex] = 8
A car increase its speed steadily from 30km/hr to 60km/hr in 1 min A what is the average speed during this time
Explanation:
initial velocity(u)=30km/hr = 30*1000/60*60=8.33 m/s
final velocity(v) =60km/hr = 60*1000/60*60 =16.67 m/s
time taken(t) = 1 minutes
= 60 seconds
Now,
Average velocity = u+v/2
= 8.33 m/s + 16.67m/s÷2
=12.5 m/s
Using deductive reasoning, write the converse, inverse, and contra positive of an if-then statement. Part I: Write an if-then statement below. (1 point)
Converse:
if q , then p
Inverse:
If not p , the not q.
Contra Positive:
If not q, then not p.
If then statement is a conditional statement. In this statement there is some condition at the first part of the sentence and then in the second part there is a conclusion.
The example of if then sentence is as follows,
If this camel is thirsty, then it will drink water from the well.
In this example there is a condition in first part that if camel is thirsty, in the second part there is conclusion which states that then it will drink water from well.
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A converging lens of focal length 20cm, forms a real image twice the size of the object. Calculate:
i) the power of the lens;
ii) the position of the image.
Answer:
Solition given:
focal length(f)=20cm
size of image(v)=2x
size of object(u)=x
we have
power of lens= reciprocal to focal length=1/20=0.05/cm
ii.
the position of the image is beyond C.
Explanation:
See the attachment !!!!!!!
define mass defect and binding energy
Answer:
About Transcript. Nuclear binding energy is the energy required to split an atom's nucleus into protons and neutrons. Mass defect is the difference between the predicted mass and the actual mass of an atom's nucleus. The binding energy of a system can appear as extra mass, which accounts for this difference.
Explanation:
PLZ MARK AS THE BRAINLIEST
I NEED IT URGENTLY
HAVE A GOOD DAY
MAY GOD BLESS U
: )
At the end of an investigation, you must__________ ____________. Your results may or may not support your hypothesis.
Answer:
could and largejsjisj and we look like they can get to
A rocket blasts off. In 10.0 seconds it is at 10,000 ft, traveling at 3600 mph. Assuming the direction is up, calculate the acceleration.
Answer:
Explanation:
Givens
t = 10 seconds
vi = 0
vf = 3600 mph
a = ?
d = 10000 feet
Formula
a = (vf - vi)/t
Solution
vf = 3600 mph * 1 hr / 3600 seconds * 5280 feet / 1 mile = 5280 ft / sec
a = (5280 - 0)/10
a = 528 ft/sec^2
If the force on a spring is 2 N and it stretched 0.5 m, what is the spring constant?
O A. 2 N/m
OB. 0.2 N/m
OC. 0.4 N/m
OD. 4 N/m
answer is
0.4n/mIn a simple machine the energy input is 120J if the efficiency of the machine is 80% calculate the energy output
Answer:
E_O = 96J
Explanation:
E_O = E_I*(%e/100%)
E_O = 120J*(80%/100%)
E_O = 96J
Define the term ‘matter’ in physics.
Answer:
Matter is any substance that has mass and takes up space by having volume
If we aim a radio telescope at a distant spiral arm of the Milky Way Galaxy, we will probably observe a 21-cm line. If we point a large optical telescope at this same region, we will probably not be able to detect the neutral hydrogen that gives rise to the 21-cm radio signal. Why not
Answer:
Because of the interstellar dust and interior location of the solar system.
Explanation:
We will probably not be able to detect the neutral hydrogen that gives rise to the 21-cm radio signal if we point a large optical telescope to the region because, the interstellar dust obscures the location of the spiral arm of the Milky way galaxy and this makes neutral hydrogen that gives rise to the 21-cm radio signal difficult to detect.
Also, the interior location of the solar system also makes the neutral hydrogen that gives rise to the 21-cm radio signal difficult to detect.
So, the interstellar dust and the interior location of the solar system makes it difficult to detect the neutral hydrogen that gives rise to the 21-cm radio signal with a large optical telescope.
An astronaut on Pluto attaches a small brass ball to a 1.00-m length of string and makes a simple pendulum. She times 10 complete swings in a time of 257 seconds. From this measurement she calculates the acceleration due to gravity on Pluto. What is her result
Answer:
The acceleration due to gravity at Pluto is 0.0597 m/s^2.
Explanation:
Length, L = 1 m
10 oscillations in 257 seconds
Time period, T = 257/10 = 25.7 s
Let the acceleration due to gravity is g.
Use the formula of time period of simple pendulum
[tex]T = 2\pi\sqrt{\frac{L}{g}}\\\\25.7 = 2 \times 31.4\sqrt{\frac{1}{g}}\\\\g = 0.0597 m/s^2[/tex]
how much would a 70 kg mean weight on the Moon what should be its mass on the earth and on the moon
Answer:
I don't know sorry' please
When 24.0 V is applied to a
capacitor, it stores 3.92 x 10-4 J of
energy. What is the capacitance?
[?] x 10!? E
[tex]\boxed{\sf E=QV^2}[/tex]
[tex]\\ \sf\longmapsto Q=\dfrac{E}{V^2}[/tex]
[tex]\\ \sf\longmapsto Q=\dfrac{3.92\times 10^{-4}}{24^2}[/tex]
[tex]\\ \sf\longmapsto Q=\dfrac{3.92\times 10^{-4}}{576}[/tex]
[tex]\\ \sf\longmapsto Q=0.006\times 10^{-4}C[/tex]
[tex]\\ \sf\longmapsto Q=6\times 10^{-1}C[/tex]
[tex]\\ \sf\longmapsto Q=0.6C[/tex]
Now
[tex]\boxed{\sf Q=CV}[/tex]
[tex]\\ \sf\longmapsto C=\dfrac{Q}{V}[/tex]
[tex]\\ \sf\longmapsto C=\dfrac{0.6}{24}[/tex]
[tex]\\ \sf\longmapsto C=0.025F[/tex]
Note:-
SI unit of charge is Coulomb(C)SI unitvof Capacitance is Farad(F)5. A child rides a pony on a circular track with a radius of 5 m Find the distance traveled and the placement
after the child has gone halfway around the track (8) Does the distance traveled increase, decrease, or stay the
same when the child completes one circuit of the track? Does the displacement increase, decrease, or stay the
same? Explain. (C) Find the distance and displacement ter a complete circuit of the track
The answer are :
A. Distance = 15.71 m , The displacement = 10 m
B. distance traveled will increase, displacement will decrease
C. The distance = 31.42 m , Displacement = 0
Difference between Distance and DisplacementDistance is a scalar quantity, while displacement is a vector quantity. Displacement is the distance travelled in a specific direction.
Given that a child rides a pony on a circular track with a radius of 5 m, after the child has gone halfway around the track
(A)
The distance traveled will be = 2[tex]\pi[/tex]r / 2
The distance = πr
The distance = 22/7 x 5
The distance = 15.71 m
The displacement = 2r
The displacement = 2 x 5
The displacement = 10 m
(B) The distance traveled will increase as the child completes one circle of the track but the displacement will decrease because the displacement in one cycle of a circular motion is zero since it is a vector quantity.
(C) The distance after a complete circuit of the track = 2πr
The distance = 2 × 22/7 × 5
The distance = 31.42 m
The displacement after a complete circuit of the track will be zero.
That is;
Displacement = 0
Therefore, the distance traveled and the displacement after the child has gone halfway around the track are 15.7 m and 10 m respectively. While the distance and displacement after a complete circle of the track are 31.42 m and 0 respectively.
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Write any three importance of Measurement.
Stay Safe,Stay Healthy and Stay Happy
Please answer me this question fast, PLEASE
Explanation:
The three importance of measurement are as follows :-
measurement is used to compare the items when barter system takes place .measurement helps in weighing the foods , groceries etc .Measurement are important in laboratory when there experiments is being taken for different purposes .Hope it is helpful to you
✌️✌️✌️✌️✌️✌️✌️
How does 'g' vary from place to place?
Explanation:
The acceleration g varies by about 1/2 of 1 percent with position on Earth's surface, from about 9.78 metres per second per second at the Equator to approximately 9.83 metres per second per second at the poles.
How many meters are in 10 miles?
Answer:
Explanation:
16093.4
