Answer:
3
3+3=6
3+3+5=11
13
13-3=10
10-3=7
15
15-7=8
8-5=3
32+43=75
75-40(highest ten)=35
76+15=91
91-70=21
12. Write 0.8 as a fraction,
Pls explain in full detail.
Answer:
8/10
Step-by-step explanation:
10x10 is 100 8x10 would be 80 so 80/100=8/10
Answer:
8/10 = 4/5
Step-by-step explanation:
0.8 is 8-10th which means 8 divided by 10
reducing 8/10 to its lowest term since 8 and 10 has 2 as common factor, then
(8=2*4)/(10=2*5)
if 2 cancels out, then you are left with 4/5
The diagram below is divided into equal parts. Which ratio correctly compares the number of shaded sections to the total number of sections? A diagram is divided into 4 shaded parts and 4 white parts. One-half 4 to 4 2:1 StartFraction 8 Over 4 EndFraction
Answer: 1/2 is correct.
Step-by-step explanation:
There are 8 total parts, and 4 of them are shaded. 4 is half of 8, therefore, your answer is 1/2.
Hope this helps!
Answer:
The answer is A
Step-by-step explanation:
because there are 4 shaded parts and 8 parts in total.
4/8=1/2
It's A
The formula for the area (A) of a circle is A = π • r2, where r is the radius of the circle. Ronisha wants to find the area of a sector of a circle that has a central angle of π6 radians. Enter the number that Ronisha should multiply by to find the area of the sector of the circle. Round your answer to the nearest hundredth.
Greetings from Brasil...
Here we will apply rule of 3...
This formula, A = πR², its for the whole circle, that is, 360° (2π)
We want the area of only a part, that is, a circular sector whose angle π/6
sector area
2π ----- πR²
π/6 ----- X
2πX = (π/6).πR²
2πX = π²R²/6
X = π²R²/12π
X = πR²/12If Ronisha multiply the area by 1/12 she will get the area of sector with angle of π/6
Ernesto solves the equation below by first squaring both sides of the equation. \sqrt{\dfrac{1}{2}w+8}=-2 2 1 w+8 =−2square root of, start fraction, 1, divided by, 2, end fraction, w, plus, 8, end square root, equals, minus, 2 What extraneous solution does Ernesto obtain?
Answer:
w = -8Step-by-step explanation:
Given the equation solved by Ernesto expressed as [tex]\sqrt{\dfrac{1}{2}w+8}=-2[/tex], the extraneous solution obtained by Ernesto is shown below;
[tex]\sqrt{\dfrac{1}{2}w+8}=-2\\\\square\ both \ sides \ of \ the \ equation\\(\sqrt{\dfrac{1}{2}w+8})^2=(-2)^2\\\\\dfrac{1}{2}w+8 = 4\\\\Subtract \ 8 \ from \ both \ sides\\\\\dfrac{1}{2}w+8 - 8= 4- 8\\\\\dfrac{1}{2}w= -4\\\\multiply \ both \ sides \ by \ 2\\\\\dfrac{1}{2}w*2= -4*2\\\\w = -8[/tex]
Hence, the extraneous solution that Ernesto obtained is w = -8
factorize
2ab+abk-2m-mk
Answer:
=2ab +abk -2m- mk
= ab(2+k) -m(2+k)
=(2+k)(ab-m)
Step-by-step explanation:
13. Choose the correct option: If 5 p + 6 = 7, then p = ? 2 a) p = 7 ×2−6 b) p = ( 7−6)×5 c) p = ( 7−6)×2 5 2 5
Answer:
p = (7 - 6)/5Step-by-step explanation:
Given the expression 5 p + 6 = 7, to know the value of variable p. we need to make p the subject of the formula as shown;
Given 5 p + 6 = 7
Step 1: Subtract 6 from both sides
5p+6-6 = 7-6
5p = 7-6
Step 2: We will then divide both sides by the coefficient of p i.e 5 to have;
5p/5 = (7 - 6)/5
p = (7 - 6)/5
Hence, the correct expression of variable p is p = (7 - 6)/5
Consider the equation: x 2 − 6 = 2 − 18 x x 2 −6=2−18xx, squared, minus, 6, equals, 2, minus, 18, x 1) Rewrite the equation by completing the square. Your equation should look like ( x + c ) 2 = d (x+c) 2 =dleft parenthesis, x, plus, c, right parenthesis, squared, equals, d or ( x − c ) 2 = d (x−c) 2 =dleft parenthesis, x, minus, c, right parenthesis, squared, equals, d. 2) What are the solutions to the equation? Choose 1 answer: Choose 1 answer: (Choice A) A x = 9 ± 89 x=9±89x, equals, 9, plus minus, 89 (Choice B) B x = − 9 ± 89 x=−9±89x, equals, minus, 9, plus minus, 89 (Choice C) C x = 9 ± 89 x=9± 89 x, equals, 9, plus minus, square root of, 89, end square root (Choice D) D x = − 9 ± 89 x=−9± 89 x, equals, minus, 9, plus minus, square root of, 89, end square root
Answer:
1. (x+9)^2 = 89
2. (Choice D) D x = − 9 ± 89 x=−9± 89 x, equals, minus, 9, plus minus, square root of, 89, end square root
Step-by-step explanation:
x^2 - 6 = 2 - 18x
1) rewrite the equation by completing the square
x^2 - 6 = 2 - 18x
x^2 + 18x = 2+6
x^2 + 18x = 8
Find the half of the coefficient of x and square it
18x
Half=9
Square half=(9)^2
=81
Add 81 to both sides
x^2 + 18x = 8
x^2 + 18x + 81 = 8 + 81
x^2 + 18x + 81 = 89
(x+9)^2 = 89
Check:
(x+9)(x+9)=89
x^2 + 9x + 9x + 81=89
x^2 + 18x +81 =89
2) (x+9)^2 = 89
√(x+9)^2 = √89
x+9=√89
x=√89 - 9
It can be rewritten as
x= -9 ± √89
(Choice D) D x = − 9 ± 89 x=−9± 89 x, equals, minus, 9, plus minus, square root of, 89, end square root
What is the value of the expression below when y = 2 and z
8?
8y - 2
A
Step-by-step explanation:
Need help 24 to 28 giving 30 points
Answer:
24 is a and d
25 is c
26 is b
27 is a and b
28 is b
Step-by-step explanation:
Your car gets 15 miles per gallon and your friend's car averages 25 mpg. You decide
head off to St. George Island on vacation, 361 miles away. If gas costs $2.79/gallon and you decide to split the
gas costs, how much money will you save by driving your friend's car?
Answer:
the answer is $27.90
Step-by-step explanation:
if you do 15 times 2.79 you will get $41.85
then do 25 times 2.79 and you will get $69.75
then subtract 69.75 from 41.85 and your answer will be $27.90
i hope this helps this is the only way i could find the answer!
$29.4864 money will you save by driving your friend's car.
Given that, your car gets 15 miles per gallon and your friend's car averages 25 mpg.
You decide to go on a road trip to St. George Island, which is 361 miles away.
What are Gallons?A unit of volume for measuring liquids. 1 gallon = 4 quarts = 8 pints = 16 cups = 128 fluid ounces. 1 US gallon = 231 cubic inches = 3.785411784 liters exactly.
Gallons needed for your car =361/15=24.06 gallons
Cost of 24.06 gallons of gas=24.06×2.79=$69.774
Gallons needed for friends car =361/25=14.44 gallons
Cost of 4.44 gallons of gas=14.44×2.79=$40.2876
Hence, while driving a friend's car you will save 69.774-40.2876=$29.4864
Therefore, $29.4864 money will you save by driving your friend's car.
To learn more about the gallons visit:
https://brainly.com/question/9917229.
#SPJ5
8 is subtracted from the square of a number
Answer:
n^2-8 is the answer
Step-by-step explanation:
can someone please help me
Answer:
y=3
Step-by-step explanation:
7y-(5y+4)=10
7y-5y+4=10
-4 -4
7y-5y=6
2y=6
÷2 ÷2
y=3
is 1 whole 1 by 3 considered as an integer??
Answer:
No it's not.
Step-by-step explanation:
[tex]1 \frac{1}{3} = \frac{4}{3} = 1.333333[/tex]
Integers are set of numbers consisting
Whole numberNatural numberNegative numbersIt doesn't consist
Fractions &DecimalsHope this helps ;) ❤❤❤
Answer:
[tex]\boxed{\sf No}[/tex]
Step-by-step explanation:
[tex]\displaystyle 1 \frac{1}{3} =1.3333333...[/tex]
Integers are whole numbers that can be positive or negative. Integers do not include fractions and decimals.
Sylvia burns 6 calories per minute when she runs, How many calories does she burn when
she runs for 15 minutes?
Write an absolute value equation to satisfy the given solution set shown on a number line.
Answer:
Step-by-step explanation:
|x-a|≤b
-b≤x-a≤b
add a
a-b≤x≤a+b
put a-b=-8
a+b=-4
add
2a=-12
a=-12/2=-6
-6+b=-4
b=-4+6=2
so |x+6|≤2
Compare the functions shown below: f(x) cosine graph with points at 0, negative 1 and pi over 2, 1 and pi, 3 and 3 pi over 2, 1 and 2 pi, negative 1 g(x) x y −6 −11 −5 −6 −4 −3 −3 −2 −2 −3 −1 −6 0 −11 h(x) = 2 cos x + 1 Which function has the greatest maximum y-value?
Answer:
f(x) and h(x) have the same maximum value: 3
Step-by-step explanation:
The maximum value of f(x) is 3 at (π, 3).
The maximum value of g(x) is -2 at (-3, -2).
The maximum value of h(x) is 3 at (0, 3).
Both f(x) and h(x) have the same (greatest) maximum value.
PLEASE HELP ASAP! If t is a real number, what is the maximum possible value of the expression -t^2 + 8t -4?
Answer:
12
Step-by-step explanation:
Hello, as the coefficient of the leading term is negative we know that the vertex of the parabola is a maximum. So we need to find the vertex.
This expression is maximum for
[tex]t=-\dfrac{b}{2a} \text{ where the parabola equation is}\\\\ax^2+bx+c=0[/tex]
So, here, it gives t = 8/2=4, and then, the maximum is
[tex]-4^2+8*4-4=-16+32-4=32-20=12[/tex]
So the answer is 12.
Thanks
Answer ASAP, will give brainliest
Answer:
Step-by-step explanation:
1) Diagonal bisect the angles of Rhombus
∠CAB = ∠CAD
∠CAB = 71
2) ∠DAB = ∠CAB + ∠CAD
∠DAB = 71 + 71 = 142
In Rhombus, adjacent angles are supplementary
∠DAB + ∠ABC = 180
142 + ∠ABC = 180
∠ABC = 180 - 142
∠ABC = 38
3) In rhombus, opposite angles are congruent
∠ADC = ∠ABC
∠ABC = 38
In rhombus, diagonal bisect angles
∠BDC = (1/2)*∠ADC
∠BDC= 38/2
∠BDC = 19
4) Diagonals bisect each other at 90
∠DEC = 90
5) Diagonals bisect each other
BE = DE
BE + DE = DB
7x -2 +7x -2 =24 {add like terms}
14x - 4 =24
14x = 24+4
14x = 28
x = 28/14
x = 2 m
6) AB = 13m
BE = 7x - 2 = 7*2 -2 = 14 -2 = 12 m
In right angle ΔAEB, {use Pythagorean theorem}
AE² + BE² = AB²
AE² + 12² = 13²
AE² + 144 = 169
AE² = 169 - 144
AE² = 25
AE = √25
AE = 5 m
Diagonals bisect each other
AE = EC
AC = 2*5
AC = 10 m
7)Side = 13 m
Perimeter = 4*side
= 4*13
Perimeter = 52 m
8) d1 = AC = 10 m
d2 = DB = 24 m
Area = [tex]\frac{d_{1}*d_{2}}{2}[/tex]
[tex]=\frac{10*24}{2}\\[/tex]
= 10 *12
= 120 m²
Drag the tiles to the boxes to form correct pairs. Not all tiles will be used. The height (in feet) of a rocket launched from the ground is given by the function f(t) = -16t2 + 160t. Match each value of time elapsed (in seconds) after the rocket’s launch to the rocket's corresponding instantaneous velocity (in feet/second).
Answer:
The pairs are;
t, v
2, 96
4, 32
5, 0
6, -32
7, -64
9, -128
Step-by-step explanation:
The given equation is f(t) = -16·t² + 160·t
We have, the velocity, v = d(f(t))/dt = d(-16·t² + 160·t)/dt = -32·t + 160
Which gives;
t, v
0, -32×(0) + 160 = 160
1, -32×(1) + 160 = 128
2, -32×(2) + 160 = 96
3, -32×(3) + 160 = 64
4, -32×(4) + 160 = 32
5, -32×(5) + 160 = 0
6, -32×(6) + 160 = -32
7, -32×(7) + 160 = -64
8, -32×(8) + 160 = -96
9, -32×(9) + 160 = -128
The given velocity values are;
96, -64, 32, 0, -128, -32 which correspond to 2, 7, 4, 5, 9, 6
The pairs are;
t, v
2, 96
4, 32
5, 0
6, -32
7, -64
9, -128
The average weight of the three lion cubs at the zoo was 288 pounds. Two of the cubs weighed 261 and 252 pounds. What was the weight of the third cub?
Answer:
351 pounds
Step-by-step explanation:288 x 3 = 864 pounds
864 - 261 - 252 = 351 pounds
Therefore (261 + 252 + 351)/3 = 288.
So the answer is 351 pounds
Nikki gathered data about the length of time she spent listening to the radio and the number of commercials she heard. She organized the data in a scatter plot, where x represents the minutes spent listening and y represents the number of commercials. Then she used the graphing tool to find the equation of the line of best fit: y = 0.338x − 1.387. Based on the line of best fit, for approximately how many minutes will Nikki need to listen to the radio to hear 20 commercials?
Answer:
The number of minutes Nikki needs to listen to the radio to hear 20 commercials is 63.275 minutes
Step-by-step explanation:
The given dependent and independent variables are;
The number of minutes spent by Nikki listening = x
The number of commercials aired = y
The relationship between the independent variable, x ans the dependent variable, y, was given by the Nikki's graphing tool line of best fit as follows;
y = 0.338·x - 1.387
Therefore, the number of minutes, x, Nikki needs to listen to the radio to hear 20 commercials, y is given as follows;
20 = 0.338·x - 1.387
20 + 1.387 = 0.338·x
0.338·x =20 + 1.387 = 21.387
x = 21.387/0.338 = 63.275 minutes
The number of minutes, x, Nikki needs to listen to the radio to hear 20 commercials, y = 63.275 minutes.
Answer:
C. 63 minutes
Step-by-step explanation:
Fachorise completely
x^2y^2-1
Answer:
[tex](xy+1)(xy-1)[/tex]
Step-by-step explanation:
x²y²-1
=(xy)²-(1)²
=(xy+1)(xy-1)
Given TS¯¯¯¯¯¯¯ and TU¯¯¯¯¯¯¯ are midsegments, PR=18.2, TS=6.5. Find QU . A. 9.1 B. 3.25 C. 13 D. 6.5
Answer:
The correct option is;
D. 6,5
Step-by-step explanation:
TS and TU are midsegments
Segment PR = 18.2
Segment TS = 6.5
Given that TS is the midsegment of PR and PQ, therefore, TS = 1/2×QR
Which gives;
Segment QR = 2×TS = 2 × 6.5 = 13
Segment QR = 13
Given that TU is a midsegment to PQ and QR, we have that QU = UR
Segment QR = QU + UR (segment addition postulate)
Therefore, QR = QU + QU (substitute property of equality)
Which gives;
QR = 2×QU
13 = 2×QU
Segment QU = 13/2 = 6.5
The length of segment QU is 6.5.
What is the image point of (-5,9) after a translation left 1 unit and down 1 unit?
Answer: (-6,8)
Step-by-step explanation:
Translation is a rigid motion inn which every point of the figure moved in the same direction and for the same distanceTranslation rules are
Left c units : [tex](x,y)\to(x-c,y)[/tex]
Down c units : [tex](x,y)\to(x,y-c)[/tex]
The image point of (-5,9) after a translation left 1 unit and down 1 unit will be:
[tex](-5,9)\to(-5-1,9-1)=(-6,8)[/tex]
Hence, the image point is (-6,8).
15 Points and Brainliest :)
Answer:
Step-by-step explanation:
Hello, please consider the following.
Option A. First week we got $200.
Week 2, we got $200+$50=$250
Week 3, we got $250+$50=$300
Week 4, we got $300+$50=$350
Week 5, we got $350+$50=$400
Week 6, we got $400+$50=$450
[tex]\begin{array}{c |c |c |c |c |c |c|}Week & 1 & 2 & 3 & 4 & 5 & 6\\----&---&---&---&---&---&---\\Amount &200 &250 &300 &350 & 400 &450\end{array}[/tex]
Option B. First week we got $200.
Week 2, we got $200+$200*10%=$200+$20=$220
Week 3, we got $220(1+10%)=$220(1.10)=$242
Week 4, we got $242(1.10)=$266.2
Week 5, we got $266.2(1.10)=$292.82
Week 6, we got $292.82(1.10)=$322.102
[tex]\begin{array}{c |c |c |c |c |c |c|}Week & 1 & 2 & 3 & 4 & 5 & 6\\----&---&---&---&---&---&---\\Amount &200 &220 &242 &266.2 & 292.82 &322.102\end{array}[/tex]
Thank you.
The circle shown above has a radius of 5 units, and the central angle of the sector that is shaded is 25π radians. Determine the area of the shaded sector, in terms of π. Enter the area of the sector.
Answer:
The answer is below
Step-by-step explanation:
Given that:
The radius of the circle (r) = 5 units
The central angle (θ) = 25π
A sector of a circle is the portion of a circle made up of two of its radii and an arc. The area of a sector that subtends with a central angle (θ) and a radius (r) is given by the formula:
[tex]Area\ of\ sector=\frac{\theta}{360} *\pi r^2[/tex]
Substituting the radius of the circle and the central angle:
[tex]Area\ of\ sector=\frac{\theta}{360} *\pi r^2\\\\Area\ of\ sector=\frac{25\pi}{360} *\pi (5)^2\\\\Area\ of\ sector=\frac{125\pi^2}{72}[/tex]
(-6x)(½y)(-⅓z) what is the product?
Answer:
xyz
Step-by-step explanation:
[tex](-6x)(\frac{1}{2}y)(-\frac{1}{3}z) = (-6)*\frac{1}{2}*(-\frac{1}{3}) * xyz = \frac{6}{6} xyz = xyz[/tex]
Write a number sentence that
illustrates the associative property
of addition,
Please, someone help.
Answer:
ok so
faf
Step-by-step explanation:
Factor 20x2 + 25x – 12x – 15 by grouping.
1. Group terms with common factors.
2. Factor the GCF from each group.
3. Write the polynomial as a product of binomials.
(20x2 – 12x) + (25x– 15)
4x(5x – 3) + 5(5x – 3)
(5x – 3)(
x +
)
Use the number line to plot –3, 1, and 3.
Which statements are true? Select all that apply.
–3 > 1
–3 = 3
1 < 3
–3 < 1
Answer:
Options 3 and 4 are correct
Step-by-step explanation:
-3>1 is false bc a positive is always greater than a negative
-3=3 is false because a positive is not equal to a negative
1<3 is correct because 1 is less than 3
-3<1 is correct because a negative is always less than a positive.
Answer:
1 < 3
–3 < 1
Step-by-step explanation:
Given that ΔABC is a right triangle with the right angle at C, which of the following is true?
1. tan A = 1/(tan B)
2. tan A = sin B
3. cos A = 1/(cos B)
4. sin B = 1/(sin A)
Answer:
1. tan A = 1/(tan B)
Step-by-step explanation:
By definition,
tangent A = opposite / adjacent = a / b
and
tangent B = opposite / adjacent = b / a
Therefore tangent A = a/b = 1/tan(B)
Answer: Tan a=tan b
I belive
Step-by-step explanation:
