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Answer:

19.9 cm²

Step-by-step explanation:

The following data were obtained from the question:

Angle at the centre (θ) = 150°

Diameter (d) = 7.8 cm

Area of sector =.?

Next, we shall determine the radius.

This can be obtained as illustrated below:

Radius (r) = Diameter (d) /2

r = d/2

Diameter (d) = 7.8 cm

Radius (r) =.?

r = d/2

r = 7.8/2

r = 3.9 cm

Finally, we shall determine the area of the sector as follow:

Angle at the centre (θ) = 150°

Radius (r) = 3.9 cm

Pi (π) = 3.14

Area of sector (A) =.?

A = θ/360 × πr²

A = 150/360 × 3.14 × 3.9²

A = 15/36 × 3.14 × 15.21

A = 19.9 cm²

Therefore, the area of the sector is 19.9 cm²

Answer:

1 miles/hour = 1.467·feet/second

Step-by-step explanation:

The given measurement unit are;

88 feet/second = 60 miles/hour

The number of feet per second that is equal to one mile per hour is found as follows;

88 feet/second = 60 miles/hour

To have a unit measure of one mile per hour , we divide both sides of the equation by 60 to get

(88 feet/second)/60 = (60 miles/hour)/60

Which gives;

(88/60 feet/second) = (60/60 miles/hour) = 1 miles/hour

22/15 × feet/second =  1 miles/hour

1.46667·feet/second =  1 miles/hour

Rounding to the nearest thousandth gives;

1.467·feet/second =  1 miles/hour

The number of feet per second that is in 1 mile per hour is 1.467·feet/second.

Answer:

1,4,9,16

Step-by-step explanation:

those are the squares

1 = 1²

4 = 2²

9 = 3²

16 = 4²

Step-by-step explanation:

[tex] {1}^{2} = 1 \times 1 = 1 \\ {2}^{2} = 2 \times 2 = 4 \\ {3}^{2} = 3 \times 3 = 9 \\ {4}^{2} = 4 \times 4 = 16 \\[/tex]

[tex] {5}^{2} = 5 \times 5 = 25 \\ [/tex]

[tex] {10}^{2} = 10 \times 10 = 100[/tex]

[tex] {6}^{2} = 6 \times 6 = 36 \\ {7}^{2} = 7 \times 7 = 49 \\ {8}^{2} = 8 \times 8 = 64 \\ {9}^{2} = 9 \times 9 = 81 \\ [/tex]

[tex] {11}^{2} = 11 \times 11 = 121 \\ {12}^{2} = 12 \times 12 = 144 \\ {13}^{2} = 13 \times 13 = 169 \\ {14}^{2} = 14 \times 14 = 196 \\ [/tex]

[tex] {15}^{2} = 15 \times 15 = 225 \\ {16}^{2} = 16 \times 16 = 256 \\ {17}^{2} = 17\times 17 = 289 \\ {18}^{2} = 18 \times 18 = 324[/tex]

[tex] {19}^{2} = 19 \times 19 = 361 \\ {20}^{2} = 20 \times 20 = 400[/tex]

Answer:

135 cubes

Step-by-step explanation:

First, find the volume of the box with the equation V = Bh, where B is the area of the base and h is the height.

V = (2.25)(0.75)(1.25)

V = 2.109375

Next, find the volume of one cube with the side length 1/4 with V = Bh:

V = (0.25)(0.25)(0.25)

V = 0.015625

Then, divide the volume of the box by the volume of one cube:

2.109375 / 0.015625

= 135

Answer:

Perimeter = 8x - 12

Step-by-step explanation:

The perimeter of a square is:

p = 4(side length)

on this case:

p = 4(2x-3)

p = 4*2x + 4*-3

p = 8x - 12

Answer:

0

Step-by-step explanation:

Hello, do you agree that 25 * 2 = 50 ?

So, we can write that [tex]50 = 25 * \boxed{2} + \boxed{0}[/tex]

the remainder is 0.

Thank you

Greetings from Brasil...

2X/(X + 2) = 6/(X + 4)

2X(X + 4) = 6(X + 2)

2X² + 2X - 12 = 0     ÷2

2X²/2 + 2X/2 - 12/2 = 0/2

Δ = 25

S = {-3, 2}

By using factorization,  [tex]\frac{2x}{x+2} =\frac{6}{x+4}[/tex] , values of x are -2, 3.

Factorization can be defined as the process of breaking down a number into smaller numbers which when multiplied together arrive at the original number. These numbers are broken down into factors or divisors.

Given

[tex]\frac{2x}{x+2} =\frac{6}{x+4}[/tex]

⇒ 2x(x + 4) = 6(x + 2)

⇒ [tex]2x^{2} +8x = 6x + 12[/tex]

⇒ [tex]2x^{2} +8x-6x-12=0[/tex]

⇒ [tex]2x^{2} +2x -12=0[/tex]

Divide above equation by 2, we get

⇒ [tex]x^{2} +x -6=0[/tex]

⇒ [tex]x^{2} +2x-3x-6=0[/tex]

⇒ [tex]x(x+2)-3(x+2)=0[/tex]

⇒ [tex](x+2)(x-3)=0[/tex]

⇒ x = -2, 3

By using factorization,  [tex]\frac{2x}{x+2} =\frac{6}{x+4}[/tex] , values of x are -2, 3.

Find out more information about factorization here

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Answer:

1. 38.3 x 10^5

2. 6.67 x 10^9

3. 4.48 x 10^4

Step-by-step explanation:

4.2 X 10 ^6 - 1.2 X 10^5 - 2.5 x 10^5

For the above question, we need to make the exponents equal

=> 42 x 10^5  -  1.2 x 10^5  -  2.5 x  10^5

SInce, all the exponents are equal, we can now add and subtract the normally.

=> (42 - 1.2 -2.5) x 10^5

=> (42 - 3.7) x 10^5

=> 38.3 x  10^5

So, the answer to the 1st question is 38.3 x 10^5

Next question:

=> 3.3 x 10^9 + 2.6 x 10^9 +7.7 x 10^8

=>  we need to make the exponents equal

=> 3.3 x 10^9 + 2.6 x 10^9 + .77 x 10^9

=> All the exponents are equal, we can now add and subtract the normally.

=> (3.3 + 2.6 + .77) x 10^9

=> 6.67 x 10^9

=> So the answer to the 2nd question is 6.67 x 10^9

Next question,

=> 8 X 10^4 - 3.4 x 10^4  - 1.2 x 10^3

=> we need to make the exponents equal

=> 8 x 10^4 - 3.4 x 10^4 - .12 x 10^4

=> All the exponents are equal, we can now add and subtract the normally.

=> (8 - 3.4 - .12) x 10^4

=> 4.48 x 10^4

=> So the answer to the 3rd question is 4.48 x 10^4

The solutions to the expressions are:

[tex]4.2 \times 10^6 - 1.2 \times 10^5 - 2.5 \times 10^5[/tex]=[tex]38.3\times 10^5[/tex]

[tex]3.3 \times 10^9 + 2.6 \times 10^9 + 7.7 \times 10^8[/tex] = [tex]6.67\times 10^9[/tex]

[tex]8.0 \times 10^4 -3.4 \times 10^4 - 1.2 \times 10^3[/tex] = [tex]4.48 \times 10^4[/tex]

[tex]4.2 \times 10^6 - 1.2 \times 10^5 - 2.5 \times 10^5[/tex]

Combine like terms:

[tex]4.2 \times 10^6 - (1.2+2.5) \times 10^5[/tex]

[tex]4.2 \times 10^6 - 3.7 \times 10^5[/tex]

[tex]42 \times 10^5 - 3.7 \times 10^5[/tex]

[tex](42-3.7)\times 10^5[/tex]

[tex]38.3\times 10^5[/tex]

[tex]3.3 \times 10^9 + 2.6 \times 10^9 + 7.7 \times 10^8[/tex]

Convert all terms with same power:

[tex]3.3 \times 10^9 + 2.6 \times 10^9 + 0.77 \times 10^9[/tex]

[tex](3.3+2.6+0.77) \times 10^9[/tex]

[tex]6.67\times 10^9[/tex]

[tex]8.0 \times 10^4 -3.4 \times 10^4 - 1.2 \times 10^3[/tex]

[tex]8.0 \times 10^4 - 3.4 \times 10^4 - 0.12 \times 10^4[/tex]

[tex](8.0-3.4-0.12) \times 10^4[/tex]

[tex]4.48 \times 10^4[/tex]

To learn more on Number system click:

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Answer:

r = 1

Step-by-step explanation:

6r - 1 + 6r = 11

Adding 6r and 6r (because they're like terms) gives us:

12r - 1 = 11

Adding 1 to both sides of the equation gives us:

12r - 1 + 1 = 11 + 1

12r = 12

Dividing both sides of the equation by 12 gives us:

12r/12 = 12/12

r = 1

Answer:

It is c

Step-by-step explanation:

because five is bigger than zero

Answer:

Step-by-step explanation:

The arrow points to all values greater than 0. And the point at 0 is not filled in. So, the inequality represents everything strictly greater than 0.

[tex]\bf x > 0[/tex]

___________________

Hope this helps!

Have a great day!

Answer:

12.25

Step-by-step explanation:

73.50 divided by 6 for each shirt is 12.25 a shirt

Answer:

2.7 hours

Step-by-step explanation:

We can use the formula

1/a + 1/b = 1/c

where a and b are the times working alone and c is the time working together

1/8 + 1/b = 1/2

Multiply each side by 8b to get rid of the fractions

8b( 1/8 + 1/b = 1/2)

b + 8 = 4b

Subtract b from each side

b+8-b = 4b-b

8 = 3b

Divide each side by 3

8/3 = 3b/3

2.666666repeating = b

Round to 1 decimal place

2.7 = b

Answer:

2.7 hr

Step-by-step explanation:

2/8 +2/x = 1

2x+16 =8

16/8

x=8/3 =2.7

The value of the unknown number is calculated as - 3

Let the unknown number = y

5  less than the number is written as = y - 5

1 more than three times the number is written as = 1 + 3y

Since the first statement and the second statement are equal, we can equate the two and solve for y.

y - 5 = 1 + 3y

collect similar terms together

y - 3y = 1 + 5

-2y = 6

y = -6/2

y = -3

Therefore, the number is - 3

learn more here: https://brainly.com/question/22548668

Building and solving the expression, it is found that the number is -3.

------------------

They are equivalent, thus:

[tex]x - 5 = 1 + 3x[/tex]

Solving for x.

[tex]3x - x = -5 - 1[/tex]

[tex]2x = -6[/tex]

[tex]x = -\frac{6}{2}[/tex]

[tex]x = -3[/tex]

The number is -3.

A similar problem is given at https://brainly.com/question/20742606

Answer:

y=x+-5

Step-by-step explanation:

y is x+-5 because as you can see in the graph the difference in everysingle one is -5 so y=x-5

Answer:

y=x+(-5)

Step-by-step explanation:

d=-3-(-4)=-3+4=1

y-(-4)=1(x-1)

y+4=x-1

y=x-1-4

or y=x+(-5)

Answer:

13x3= 39

Step-by-step explanation:

10x3=30

3x3=9

30+9=39

Hope it helps!

Answer:

d. [tex]\angle BIJ \cong \angle CGJ\ and\ \angle BJI \cong \angle CJG[/tex]

Step-by-step explanation:

Here, we are given a diagram in which there are two triangles to be considered:

[tex]\triangle CJG \ and\ \triangle BJI[/tex].

We can consider the whole diagram in the form as attached in the answer area.

To find:

The conditions to prove [tex]\triangle CJG \sim \triangle BJI[/tex].

Solution:

First of all, let us learn about AAA similarity.

AAA stands for Angle Angle Angle.

i.e. when we prove that the all the three corresponding angles of two triangles are equal ,the triangles are similar.

There is one more property of the triangles, that if two angles of two triangles are equal then the third angle of the triangles will also be equal to each other.

So, actually, to prove that [tex]\triangle CJG \sim \triangle BJI[/tex], we need the conditions that two corresponding angles of the triangles are equal to each other, then we can say that third angle will also be equal. Therefore the triangles will be similar to each other.

Let us consider the corresponding angles:

[tex]\angle BIJ \ and \ \angle CGJ\ ,\ \angle BJI \ and \ \angle CJG\ , \ \angle IBJ\ and \ \angle GCJ[/tex]

So, if we are given that any of the two above three pairs are equal/congruent to each other, we can prove [tex]\triangle CJG \sim \triangle BJI[/tex].

Therefore, the correct answer is:

d. [tex]\angle BIJ \cong \angle CGJ\ and\ \angle BJI \cong \angle CJG[/tex]

Answer:

it's true

Step-by-step explanation:

Answer:

41.4 kgs

Step-by-step explanation:

Take the number of bags times the weight of each bag

6 * 6.9

41.4 kgs

Answer:

41.4 kilograms of sugar

Step-by-step explanation:

its 41.4 kilograms of sugar because you take the 6 bags and multiply that by the 6.9

Answer:

Option A

Step-by-step explanation:

Expression: y = 12h

If h = 15, then:

y = 12(15)

y =  $180

Option A

Answer:

(4x + 1)(2x² - 5)

Step-by-step explanation:

Given

8x³ + 2x² - 20x - 5 ( factor the first/second and third/fourth terms )

= 2x²(4x + 1) - 5(4x + 1) ← factor out (4x + 1) from each term

= (4x + 1)(2x² - 5)

Answer:

blank 1 is -20-5

blank 2 is 4x+1

blank 3 is -5

blank 4 is 2x^2-5

Step-by-step explanation:

Answer:

(B) A location

Step-by-step explanation:

If you have a point on a graph or number line, it always represents a certain location on the graph.

For instance, if we have a point on the x=3 line and the y=4 line, the point would represent the location (3,4).

Hope this helped!

Answer: find the answer in the explanation.

Step-by-step explanation:

To increase the time the fireworks stays in the air by 2 seconds to build up the suspense, 2 should be added to the time t.

T + 2 = t

T = t - 2

Substitute T for t in the function g(t)

The company will make this happen without changing the length of the fuse by substituting T for t which will lead to

g(t) = -16(t - 2)^2 + 224(t - 2) + 120

How will this affect the maximum height of the firework?

Initially the function is:

g(t) = -16t2 + 224t + 120

Where the time at maximum height is found by using the formula

t = -b/2a

b = 224, a = -16

Substitutes both into the formula

t = -224/2(-16)

t = -224/-32

t = 7

Substitute 7 for t in the first equation

g(t) = -16(7)^2 + 224(7) + 120

g(t) = -16(49) + 224(7) + 120

g(t) = -784 + 1568 + 120

g(t) = 904 metres

But when the time is delayed by 2 seconds in the air, the maximum height will be

g(t) = -16( 7 - 2 )^2 + 224(7 - 2) + 120

g(t) = -16(5)^5 + 224(5) + 120

g(t) = -16(25) + 224(5) + 120

g(t) = -400 + 1120 + 120

g(t) = 840

The effect will surely reduce the maximum height of the fireworks.

Average rate of change ... of what?

Given some continuous function [tex]f(x)[/tex] and some interval [tex][a,b][/tex], its average rate of change over the interval is

[tex]\dfrac{f(b)-f(a)}{b-a}[/tex]

Without knowing what your function is exactly, I can only give a symbolic answer,

[tex]\dfrac{f(18)-f(0)}{18}[/tex]

Answer: -5/18

Step-by-step explanation: edg

Answer:

5/12

Step-by-step explanation:

4√y√y / 3√y

The above equation can be simplified as follow:

4√y√y / 3√y

4√y × √y ÷ 3√y

Recall:

√a = a^1/2

m√a = a^1/m

Therefore,

4√y√y ÷ 3√y

y^1/4 × y^1/2 ÷ y^1/3

Recall:

a^m × a^n = a^(m+n)

Therefore,

y^1/4 × y^1/2 ÷ y^1/3

y^(1/4 + 1/2) ÷ y^1/3

y^3/4 ÷ y^1/3

Recall:

a^m ÷ a^n = a^(m–n)

Therefore,

y^3/4 ÷ y^1/3

y^(3/4 – 1/3)

y^5/12

Comparing the above with y^m, we have

y^5/12 = y^m

m = 5/12

Therefore, the value of m is 5/12

Answer:

3.2 cm = h

Step-by-step explanation:

The area of a triangle is

A = 1/2 bh

where b is the base and h is the height

b = 10  and the area is 16

16 =1/2 *10 *h

16 = 5h

Divide each side by 5

16/5 = 5h/5

3.2 cm = h

Answer:

[tex]\huge\boxed{x = -\frac{5}{6}}[/tex]

Step-by-step explanation:

[tex]f(x) = -12x+7[/tex]

Given that f(x) = 17

[tex]17 = -12x+7[/tex]

Subtracting 7 to both sides

[tex]17-7 = -12x[/tex]

10 =  -12 x

Dividing both sides by 12

[tex]x = - \frac{10}{12}[/tex]

[tex]x = -\frac{5}{6}[/tex]

Answer:

-5/6 =x

Step-by-step explanation:

f(x) = -12x+7

We want to find x when f(x) = 17

17 = -12x+7

Subtract 7 from each side

17-7 = -12x +7-7

10 = -12x

Divide each side by 12

10/-12 = -12x/-12

-5/6 =x

Answer:

It would be difficult to see what you are doing if the line segments overlapped, making it easier to make a mistake and harder to check your work.

Answer:

20°

Step-by-step explanation:

The measure of the inscribed angle is equal to the half of the arc it sees

Since AC is the diameter the measure of arc ABC is 180°

and since A sees arc BC and C sees the arc AB

A< + C< = 90° so angle C = 20°

Answer:

[tex]\boxed{2\pm \frac{\sqrt{2}}{2}}[/tex]

Step-by-step explanation:

[tex]2x^2-8x=-7[/tex]

[tex]\sf Add \ 7 \ on \ both \ sides}.[/tex]

[tex]2x^2-8x+7=-7+7[/tex]

[tex]2x^2-8x+7=0[/tex]

[tex]ax^2 +bx+c=0[/tex]

[tex]\sf Apply \ quadratic \ formula.[/tex]

[tex]a=2 \ \ \ b=-8 \ \ \ c = 7[/tex]

[tex]x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}[/tex]

[tex]x=\frac{-(-8)\pm\sqrt{(-8)^2-4(2)(7)}}{2(2)}[/tex]

[tex]x=\frac{8\pm\sqrt{64-56}}{4}[/tex]

[tex]x=\frac{8\pm\sqrt{8}}{4}[/tex]

[tex]x=\frac{8\pm2\sqrt{2}}{4}[/tex]

[tex]x=2\pm \frac{\sqrt{2}}{2}[/tex]