Physical safeguards, also called logical safeguards, and are applied in the hardware and software of information systems.

a. True
b. False

Answer:

The modified program in Python is as follows:

triangle_char = input('Enter a character:\n')

triangle_height = int(input('Enter triangle height:\n'))  

for i in range(triangle_height):

   print(triangle_char * (i+1))

Explanation:

This gets the character from the user

triangle_char = input('Enter a character:\n')

This gets the height of the triangle from the user

triangle_height = int(input('Enter triangle height:\n'))  

This iterates through the height

for i in range(triangle_height):

This prints extra characters up to the height of the triangle

   print(triangle_char * (i+1))

Here's the modified program that incorporates the requested changes:

python

Copy code

triangle_char = input('Enter a character:\n')

triangle_height = int(input('Enter triangle height:\n'))

print('')

for i in range(1, triangle_height + 1):

   line = triangle_char * i + ' ' * (triangle_height - i)

   print(line)

This program uses a loop to iterate from 1 to triangle_height. In each iteration, it creates a line by concatenating triangle_char repeated i times with spaces (' ') repeated (triangle_height - i) times. The resulting line is then printed.

For example, if the user enters % as the character and 5 as the height, the output will be to make sure to maintain the indentation properly in your code for it to work correctly.

Learn more about python on:

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Which XXX declares a student's name.

public class Student {

   XXX

   private double myGPA;  

   private int myID;

   public int getID() {

        return myID;

   }

}

Group of answer choices

a. String myName;

b. public String myName;

c. private myName;

d. private String myName;

private String myName;

To declare a student's name, the following should be noted.

i. The name of the student is of type String

ii. Since all of the instance variables (myGPA and myID) have a private access modifier, then myName (which is the variable name used to declare the student's name) should be no exception. In other words, the student's name should also have a private access.

Therefore, XXX which declares a student's name should be written as

private String myName;

Option (a) would have been a correct option if it had the private keyword

Option (b) is not the correct option because it has a public access rather than a private access.

Option (c) is not a valid syntax since, although it has a private access, the data type of the variable myName is not specified.

Option (d) is the correct option.

Answer: Its............ A Chromebook type of Chromebook...??

Explanation:

Ion know I aint a geek, geezer -_- (Thats a lie)

Answer:

128 KB      

Explanation:

Given data :

The block size = 512 bytes

Block pointer size = 2 bytes

In an indexed allocation, a special block named Index Block contains all the pointers to the blocks that the file had occupied.

Therefore, the maximum number of block pointer in 1 block :

[tex]$=\frac{\text{block size}}{\text{pointer size}}$[/tex]

[tex]$=\frac{512}{2}$[/tex]

= 256

Thus, a block can hold maximum 256 pointers.

It is given the level of indexing is one. So,

Maximum size of the file =  maximum number of block pointers in 1 file x block size

                                          = 256 x 512

                                          [tex]$=2^8 \times 2^9$[/tex]

                                          [tex]$=2^{8+9}$[/tex]

                                           [tex]$=2^{17}$[/tex]

                                          [tex]$=2^7 \times 2^{10}$[/tex]

                                          [tex]$=128 \times 2^{10}$[/tex]

                                          = 128 KB   (∵ 1 KB = [tex]2^{10} \ B[/tex] )

Therefore, the largest file that 1 level if indexed allocation method can handle is 128 KB.

Answer:

an optical instrument used for viewing very small objects, such as mineral samples or animal or plant cells, typically magnified several hundred times

Answer:

A microscope is a laboratory instrument used to examine objects that are too small to be seen by the naked eyes.

Answer:

Explanation:

1) Chart area: This is the area where the chart is inserted. 2) Data series: This comprises of the various series which are present in a chart i.e., the row and column of numbers present. 3) Axes: There are two axes present in a chart. ... 4)Plot area: The main area of the chart is the plot area

Explanation:

The following six steps must be followed to solve a problem using computer.

Problem Analysis.

Program Design - Algorithm, Flowchart and Pseudocode.

Coding.

Compilation and Execution.

Debugging and Testing.

Program Documentation.

Answer:

A. true

Explanation:

because 5s is the.................