Answer:
Explanation:
Given the equation:
[tex]\implies \dfrac{[9.8(\pm0.3)-2.31(\pm 0.01)]}{8.5(\pm0.6)}[/tex]
The absolute uncertainty in a measurement is the term used to describe the degree of inaccuracy.
The first step is to determine the algebraic value on the numerator.
Algebraic value = 9.8 - 231
= 7.49
The absolute uncertainty = [tex]\sqrt{(abs. uncertainty_{v_1})^2+(abs. uncertainty_{v_2})^2}[/tex]
absolute uncertainty = [tex]\sqrt{(0.3)^3 + (0.01)^2}[/tex]
= [tex]\sqrt{0.09 + 0.0001}[/tex]
= 0.300167
∴
[9.8(±0.3) - 2.31(±0.01)] = 7.49(±0.300167)
The division process now is:
[tex]\implies \dfrac{[9.8(\pm0.3)-2.31(\pm 0.01)]}{8.5(\pm0.6)}= \dfrac{7.49 (\pm 0.300167)}{8.5 (\pm0.6)}[/tex]
Relative uncertainty = [tex]\dfrac{(\pm 0.300167)}{7.49}\times 100 \ , \ \dfrac{(\pm 0.6) }{8.5} \times 100[/tex]
Relative uncertainty = ±4.007565% , ±7.058824%
[tex]\text{Relative uncertainty} = \sqrt{(4.007565)^2+(7.058824)^2}[/tex]
[tex]\text{Relative uncertainty} = \sqrt{16.06057723+49.82699626}[/tex]
[tex]\text{Relative uncertainty} = \sqrt{65.88757349}[/tex]
[tex]\text{Relative uncertainty} = 8.117116[/tex]
≅ 8%
The algebraic value = [tex]\dfrac{7.49}{8.5}[/tex]
= 0.881176
≅ 0.88
The percentage of the relative uncertainty =[tex]\dfrac{\text{Absolute uncertainty }}{\text{calculated value} }\times 100[/tex]
By cross multiplying:
[tex]\text{Absolute uncertainty} (\%) = \dfrac{\text{relative uncertainty} \times \text{calculated value}}{100}[/tex]
[tex]\text{Absolute uncertainty} (\%) = \dfrac{8.117116\times 0.881176}{100}[/tex]
[tex]\text{Absolute uncertainty} (\%) = 0.0715260[/tex]
[tex]\mathbf{\text{Absolute uncertainty} (\%) \simeq 0.07}[/tex]
Finally:
[tex]\mathbf{\implies \dfrac{[9.8(\pm0.3)-2.31(\pm 0.01)]}{8.5(\pm0.6)}= 0.88 \pm (0.07) \pm 8\%}[/tex]
how many s electrons are there in potassium?
Answer: 19
Explanation:
In order to write the Potassium electron configuration we first need to know the number of electrons for the K atom (there are 19 electrons). When we write the configuration we'll put all 19 electrons in orbitals around the nucleus of the Potassium atom.
The mass percent of element X
in X(NO3)2 is 52.55%.
Chemical analysis of a pure
sample of X(NO3)2 shows that
it contains 67.50 g of element
X. What is the total mass of
the pure sample?
Answer:
128.4 g
Explanation:
Step 1: Given data
Mass percent of element X in X(NO₃)₂: 52.55%Mass of the element X in the sample: 67.50 gStep 2: Determine the total mass of the sample
The mass percent of element X in X(NO₃)₂ is 52.55%, that is, there are 52.55 g of X every 100 g of X(NO₃)₂. Then, the mass of X(NO₃)₂ that contains 67.50 g of X is:
67.50 g X × 100 g X(NO₃)₂/52.55 g X = 128.4 g X(NO₃)₂
How did the development of the earliest idea about atoms differ from the later work of scientists?
It was based on sound evidence.
There were explanations for the idea.
It was based on the thoughts of an early philosopher.
There were experiments conducted to support the idea.
Answer:
C. It was based on the thoughts of an early philosopher.
g a commercial product for treating injuries contains 35.0 g of MgSO4 in one bag and 250 mL of water in a seperate bag. When the bags are broken and their contents mixed, the temperature of the system changes. Calculate this temperature change
Answer:
he a real G
Explanation:
og tripple og
Almost 99% of Earth's atmosphere is made up of two gases. What are the two gases and the percents of each?
A)
21% oxygen and 78% nitrogen
B)
21% water vapor and 78% oxygen
09
21% nitrogen and 78% oxygen
D)
21% carbon dioxide and 78% oxygen
20)
Which substance is an acid?
A)
Ba(OH)2
B)
CH3COOCH3
C)
H3PO4
D)
NaCl
help
Answer:
C.
Explanation:
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Verdadero o falso si un átomo presenta de 5 a 7 electrones en su nivel más extremo tenderá a perderlos?
sound waves? like what they do.
Answer:
A sound wave is the pattern of disturbance caused by the movement of energy traveling through a medium (such as air, water, or any other liquid or solid matter) as it propagates away from the source of the sound. The source is some object that causes a vibration, such as a ringing telephone, or a person's vocal chords.
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P4 + NaOH + H2O——> PH3 + Na2HPO3
Balance given equation by oxidation no. Method
Answer:
P4 + 4NaOH + 2H2O → 2PH3 + 2Na2HPO3
Explanation:
A chemical equation is said to be balanced if the quantity of each type of atom in the reaction is the same on both the reactant and product sides. In a balanced chemical equation, the mass and the charge are both equal.
A chemical equation must balance according to the rule of conservation of mass. According to the rule, mass cannot be generated or removed during a chemical process.
Chemical equations must be balanced, which means that the atom types and numbers on both sides of the reaction arrow must match. Coefficients are the values added in front of formulas to balance equations; they multiply each atom in a formula.
Here the given equation is balanced as:
P₄ + 4NaOH + 2H₂O——> 2PH₃ + 2Na₂HPO₃
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How many moles of fluorine are in 100.0 g
Using the periodic table,
choose the more reactive nonmetal. Br or as
Answer:
Br
Explanation:
because bromine is more reactive as reactivity increases on moving from left to right in p-block. hope this make sense :)
Given the Vapour Density of a hydrocarbon is 150, what is it's molecular formula.
Chromium (VI) forms two different oxyanions, the orange dichromate ion, Cr2o72-, And the yellow chromate ion, CrO4 2-. The equilibrium reaction between the ions is:
Cr2O7 2- (aq) + H2O(l)→ 2CrO4 2-(aq) + 2H(aq)
Explain
a) Why does the orange dichromate solution turn yellow when sodium hydroxide is added. Write the net ionic equation for this shift.
b) How will this system shift at equilibrium if the temperature is increased
Answer:
See explanation
Explanation:
Let us look at the reaction again;
Cr2O7 2- (aq) + H2O(l)⇄ 2CrO4 2-(aq) + 2H^+(aq)
When we add sodium hydroxide to the system as shown, the hydroxide ion removes the hydrogen ion thereby leaving a large concentration CrO4^2-(aq) in the system this causes the solution to turn green(equilibrium position shifts to the right).
The net ionic equation is;
OH^-(aq) + H^+(aq) ----> H2O(l)
The reaction;
OH^-(aq) + H^+(aq) ----> H2O(l) is exothermic hence, if the temperature of the system is increased, the equilibrium position will shift towards the left hand side and the solution turns orange.
A. Direction: Identify the word or phrase being described in the sentence. Write your
answers in your notebook.
1. It is an electronic measuring instrument that combines several
measurement functions in one unit.
2. In diodes, what do the silver stripe represents?
3. This is an Electronic/Electrical component that stores energy in
the form of Electric Charge.
4. This allows you to change the function between volts, ohms, and
amps, and to change the scale of the meter.
5. In testing capacitor, if the multimeter shows very low resistance,
it means that the capacitor is .
6. These are components used to resist the flow of electric current.
7. It is a system used to determine the value of a resistor without
using a multimeter.
8. What defective capacitor that shows very low Resistance?
9. A type of transformer that is used to increase the output voltage.
10. A type of transformer that is used to decrease the output voltage.
Answer:
1. Multimeter
2. Cathode
3. Capacitor
4. Selector switch
5. Short or Shorted
6. Resistors
7. Resistor color coding
8. Open Capacitor
9. Step-up transformer
10. Step-down transformer
Explanation:
The above-described elements are electronic components. Resistors for instance are designed to resist the flow of electric current. They are also standardized such that a deviation from the set resistance level will indicate a problem. The capacitor is another electrical component that stores energy as an electrical charge. Knowledge of these electrical components and the ways they are tested will make a person proficient in electrical electronics.
What is the mass of 8.12 ×10^23
Answer:
59.3g
Explanation:
Mole = no. Molecules/6.02×10^23
Mole = (8.12×10^23)/(6.02×10^23)
Mole = 1.35mole
Molar mass of CO2 = 12+ 2(16)
Molar mass= 12 + 32= 44g/mol
Mole = mass/molar mass
Mass = Mole × molar mass
Mass = 1.35× 44
Mass= 59.35g
What is one way in which a field investigation can differ from a classroom or laboratory experiment?
Answer:
□In field investigations, you are usually working with much larger animals than in the lab. In field investigations, it is much more difficult to separate your control and experimental groups.
There are many ways in which a field experiment can differ form of a classroom or a laboratory experiment, one of which can be the environmental condition.
What is a field experiment?A field experiment Is an experiment which is performed in practically Outside the classroom or a laboratory in live situtations .
Environmental factors may deter the results of a field experiment or may alter the physical conditions of the object, For example an anhydrous substance may become hygroscopic, Which may Alter the result of the field experiment.
Hence, field experiment can differ from a classroom or a laboratory experiment due to environmental conditions .
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What is the pH of a solution whose hydronium ion [H20+] (or proton [H+1)
concentration is 7.6' 10-5 M?
Answer:
[tex]pH = - log(7.6 \times {10}^{ - 5} ) \\ pH = 4.12[/tex]
What three parts of your eye work together to create a clear image?
Answer:
cornea,Jens and pupil
tma Po yan
A sample of gas with an initial volume of 9.35 L at a pressure of 784 torr and a temperature of 295 K is compressed to a volume of 2.84 L and warmed to a temperature of 310 K. What is the final pressure of the gas in atmospheres (atm)?
a. 4.97 atm.
b. 0.113 atm.
c. 5.95 atm.
d. 7.03x10^3 atm.
Answer:
D
Explanation:
The largest number of stable nuclei have an ________ number of protons and an ________ number of neutrons.
Answer:
did it give you answers to in blanks
given two equations representing reactions: which type of reaction is represented by each of these equations?
Answer:
Equation 1 - nuclear fission
Equation 2 - nuclear fusion
Explanation:
Nuclear fission is a reaction in which a large nucleus is split into smaller nuclei when it is bombarded by neutrons. The process produces more neutrons to continue the chain reaction. This is clearly depicted in equation 1 as shown in the question.
Nuclear fusion is a reaction in which two light nuclei combine in order to form a larger nuclei. This is clearly depicted in equation 2 as shown in the question.
In the first reaction, a neutron is released, and in the second a helium atom is released. The given two equations represent nuclear fission and fusion.
What are nuclear reactions?A nuclear reaction is a reaction that involves the nuclei of the atom and the absorption and release of energy. In the first reaction, a big nucleus is split by the neutron bombardment into smaller nuclei.
In the second reaction the process of nuclear fusion, two nuclei combine into a single larger nucleus that is shown as:
₁¹H+ ²₁H → ³₂He
Therefore, nuclear fission and fusion are represented by each of these equations.
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Classify each of the following as a Strong acid (sa) or a Weak acid (wa) and indicate how each should be written in aqueous solution.
1. hydrobromic acid
2. hydrochloric acid
3. carbonic acid
Write a net ionic equation for the reaction that occurs when aqueous solutions of hydrochloric acid and barium hydroxide are combined.
Answer:
A. 1. Strong acid (sa): Hydrobromic acid: HBr (aq)
2. Strong acid (sa); Hydrochloric acid: HCl (aq)
3. Weak acid (wa); Carbonic acid: H₂CO₃ (aq)
B. H+ (aq) + OH- (aq) ----> H₂O (l)
Explanation:
Strong acids are which ionize completely in aqueous solution into hydrogen ions and the corresponding anion. Examples of strong acids include hydrobromic acid, hydrochloric acid, tetraoxosulfate (vi) acid.
The ionization of hdyrobromic and hydrochloric acids in aqueous solution is given below:
1. Hydrobromic acid: HBr (aq) ----> H+ (aq) + Br- (aq)
Hydrobromic acid in aqueous solution ionizes completely into hydrogen ions and bromide ions
2. Hydrochloric acid: HCl (aq) ----> H+ (aq) + Cl- (aq)
Hydrochloric acid in aqueous solution ionizes completely into hydrogen ions and chloride ions
Weak acids are acids which ionizes only partially in aqueous solutions to hydrogen ions and the corresponding anions. Examples of weak acids are carbonic acid and ethanoic acid. The ionization of carbonic acid in aqueous solution is shown below:
3. Carbonic acid: H₂CO₃ (aq) ⇄ 2 H+ (aq) + CO₃²- (aq)
Carbonic acid ionizes partially only to give hydrogen ions and trioxocarbonate (iv) ions. The unionized acid exists in equilibrium with the ions produced by the partial ionization of the acid.
Part B:
The reaction between hydrochloric acid and barium hydroxide is a neutralization reaction producing barium chloride salt and water.
The net ionic equation of the neutralization reaction is given below :
H+ (aq) + OH- (aq) ----> H₂O (l)
Ammonia burns in the presence of a copper catalyst to form nitrogen gas. 4 NH3(g) + 3 O2(g) → 2 N2(g) + 6 H2O(g) ΔΗ = -1267 kJ What is the enthalpy change to burn 38.4 g of ammonia?
Answer:
-713 kJ
Explanation:
Step 1: Write the balaned thermochemical equation
4 NH₃(g) + 3 O₂(g) → 2 N₂(g) + 6 H₂O(g) ΔΗ = -1267 kJ
Step 2: Calculate the moles corresponding to 38.4 g of NH₃
The molar mass of NH₃ is 17.03 g/mol.
38.4 g × 1 mol/17.03 g = 2.25 mol
Step 3: Calculate the enthalpy change to burn 2.25 mol of ammonia
According to the thermochemical equation, 1267 kJ are released per 4 moles of ammonia that react.
2.25 mol × (-1267 kJ/4 mol) = -713 kJ
In the electrolysis of water, how long will it take to produce 75.00 L of H2 at 1.0 atm and 273 K using an electrolytic cell through which the current is 205.0 mA
answer is 2546 h
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Question on the image
Answer: The mass of carbon dioxide required is 308 g
Explanation:
The number of moles is defined as the ratio of the mass of a substance to its molar mass.
The equation used is:
[tex]\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}[/tex] ......(1)
Given mass of octane = 100.0 g
Molar mass of octane = 114.23 g/mol
Putting values in equation 1, we get:
[tex]\text{Moles of octane}=\frac{100.0g}{114.23g/mol}=0.875mol[/tex]
For the given chemical reaction:
[tex]2C_8H_{18}+25O_2\rightarrow 16CO_2+18H_2O[/tex]
By the stoichiometry of the reaction:
2 moles of octane produces 16 moles of carbon dioxide
So, 0.875 moles of octane will produce = [tex]\frac{16}{2}\times 0.875=7mol[/tex] of carbon dioxide
Molar mass of carbon dioxide = 44 g/mol
Plugging values in equation 1:
[tex]\text{Mass of carbon dioxide}=(7mol\times 44g/mol)=308g[/tex]
Hence, the mass of carbon dioxide required is 308 g
The chemical formula for an emerald is Be3Al2(SiO3)6. An emerald can be described as
Answer:
Emerald is a compound made of Beryllium, Aluminium, Silicon and Oxygen with the formula, Be3Al2(SiO3)6
Explanation:
Answer:
A pure substance because its a compound
Explanation:
How many grams of hydrogen gas, H, are necessary to produce 119.0 g of ammonia, NH3?
Answer:
What's the equation?
Answer:
14.5 g
Explanation:
its true
How many molecules are there in 4.27 mol of tungsten(VI) oxide, WO3
Answer:
Molar mass of WO3 = 231.8382 g/mol Convert grams Tungsten(VI) Oxide to moles or moles Tungsten(VI) Oxide to grams Molecular weight calculation: 183.84 + 15.9994*3Explanation:
#hopeithelpsbrainliest me later.25.71 × 10²³ molecules are there in 4.27 mol of tungsten (VI) oxide, [tex]WO_3[/tex].
How to find the number of molecules ?To find the Number of molecules of substance multiply the number of moles of given substance by Avogadro number
Number of molecules = Number of moles × Avogadro's Number
Avogadro's NumberAvogadro's number [tex](N_{A})[/tex] is the number of particles in one mole of substance. 6.023 × 10²³ is known as Avogadro's constant / Avogadro's number.
Avogadro's number = 6.023 × 10²³ [tex]mol^{-}[/tex]
Now,
Number of molecules in 4.27 moles of [tex]WO_{3}[/tex]
= Number of moles of [tex]WO_{3}[/tex] × Avogadro's Number
= 4.27 × 6.023 × 10²³
= 25.71 × 10²³ molecules
Thus, we can say that 25.71 × 10²³ molecules are there in 4.27 moles of tungsten (VI) oxide, [tex]WO_3[/tex].
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What was one idea Dalton taught about atoms?
Explanation:
All atoms of one type were identical in mass and properties.
Completa las siguientes reacciones, nombrando todos los compuestos que intervienen:
a) CH2=CH2 + energía
b) CH2=CH2 + H2O
c) CH2=CH2 + HCl
d) CH2=CH2 + Cl2
e) CH2=CH2 + H2
2 Completa las siguientes reacciones, nombrando todos los compuestos que intervienen:
a) CH4 + Cl2
b) CH2=CH2 + H2O
c) CH≡CH + H2
d) CH3-COOH + KOH
e) CH3OH + CH3-COOH
3 Completa y ajusta la siguientes reacciones nombrando todos los compuestos que intervienen en cada una de ellas:
a) CH3-COOH + NaOH
b) CH3-CH2I + NH3
c) CH2=CH2 + H2O
d) CH3-CH=CH2 + Br2
Answer:
1
Explanation:
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