Answer:
-15,-5,0,10,25
Step-by-step explanation:
List pairs of congruent angles and the extended proportion that relates the corresponding sides for the similar polygons. Given ABDF ~ VXZT
** I NEED HELP I KEEP GETTING IT WRONG**
Given:
[tex]ABDF\sim VXZT[/tex]
To find:
The pairs of congruent angles and the extended proportion that relates the corresponding sides for the similar polygons.
Solution:
We have,
[tex]ABDF\sim VXZT[/tex]
The corresponding angles of similar polygons are congruent. So,
[tex]\angle A\cong \angle V[/tex]
[tex]\angle B\cong \angle X[/tex]
[tex]\angle D\cong \angle Z[/tex]
[tex]\angle F\cong \angle T[/tex]
The corresponding sides of similar polygons are proportional. So,
[tex]\dfrac{AB}{VX}=\dfrac{BD}{XZ}=\dfrac{DF}{ZT}=\dfrac{A F}{VT}[/tex]
Therefore, the required solutions are [tex]\angle A\cong \angle V,\angle B\cong \angle X,\angle D\cong \angle Z,\angle F\cong \angle T[/tex] and [tex]\dfrac{AB}{VX}=\dfrac{BD}{XZ}=\dfrac{DF}{ZT}=\dfrac{A F}{VT}[/tex].
Find the length of each side and the
perimeter.
(5n -17) cm
(2n + 1) cm
n cm
7n-16
Step-by-step explanation:
Sry can u give me the picture
Find KL
IJ=9
JK=11
KL?
Answer:
KL = 6
Step-by-step explanation:
IL = 26
IJ = 9
JK = 11
KL = ?
To find KL
Let KL be x
IJ + JK + KL = IL
9 + 11 + x = 26
20 + x = 26
transpose to find KL that is x
x = 26 - 20
x = 6
therefore KL = 6
Answer:
KL = 6
Step-by-step explanation:
First step is to create an equation
Given: IL = 26
This means that the sum of the segments that make up IL also equal 26
In other words, IJ + JK + KL = 26 ( note that this is the equation that we will use to solve for the missing segment )
Given: IJ = 9 , JK = 11 and KL = ?
To find the length of the missing segment we simply plug in the known segment lengths into the equation we created and solve for the unknown one.
Equation created: IJ + JK + KL = 26
Variables: IJ = 9 , JK = 11 and KL = ?
Plug in variables into equation
9 + 11 + KL = 26
Now solve for KL
Step 1 Combine like terms ( 9 + 11 = 20 )
20 + KL = 26
Step 2 Subtract 20 from both sides
20 - 20 + KL = 26 - 20
KL = 6
And we are done!
in a 41-49 right triangle, the hypotenuse is 28.83 centimeters. if cos 41= 0.7547, find the length of the side opposite the 49 angle. Estimate your answer to three decimal places
Answer:
21.758
Step-by-step explanation:
If you draw the triangle out, you find that cos 41 = x/28.83, when x is equal to the side opposite the 49 angle
Simplify this into 28.83 cos 41, and plug it into the calculator and you get
21.75827.
f(x) = 2x + 7 with domain: x = {2, 3, 5, 9}
Answer:
2(2)+7=11
2(3)+7=13
2(4)+7=15
2(5)+7=17
2(9)+7=25
Step-by-step explanation:
2(2)+7
4+7=11
2(3)+7
6+7=13
2(4)+7
8+7=15
2(5)+7
10+7=17
2(9)+7
18+7=25
can someone pls help w finding the x and y intercepts of this?
y=x^2-2x
Answer:
y-intercept is 0, x-intercept is 0 and 1
Step-by-step explanation:
For y-intercept, x=0 :
[tex]{ \tt{y = {(0)}^{2} - 2(0) }} \\ { \tt{y = 0}}[/tex]
For x-intercept, y=0 :
[tex]{ \tt{0 = {2x}^{2} - 2x }} \\ { \tt{2x(x - 1) = 0}} \\ { \tt{x = 0 \: \: and \: \: 1}}[/tex]
find the radius of a circle for which an arc 6 cm long subtends an angle of 1/3 radians at the center?
plz some one can help to solve the question??
Step-by-step explanation:
Eueydhhdgdgdbdbddbdbhd
Answer:
Hello,
[tex]R=\dfrac{18}{\pi}\ (cm)[/tex]
Step-by-step explanation:
[tex]Formula: \ L=\theta*R\\[/tex]
[tex]R=\dfrac{6}{\dfrac{\pi}{3} } =\dfrac{6*3}{\pi} =\dfrac{18}{\pi}\ (cm)[/tex]
The amount of money lana earns for tutoring is proportional to the time she spends tutoring. She earns $24 for tutoring 1 1/2 hours. what is the constant of proportionality for the relationship between dollars earned and number of hours?
Answer:
y=16x
Step-by-step explanation:
24=1 1/2x=3/2x
x=24*(2/3)=16
y= total money earned; x=number of hours worked
Plsss help will mark brainliest
Answer:
394
Step-by-step explanation:
11^2+8*11*3+3^2
121+8*11*3+9
121+264+9
385+9
394
Statement: If two noncollinear rays join at a common endpoint, then an angle is created. Which geometry term does the statement represent?
A. Defined term
B. Postulate
C. Theorem
D. Undefined term
The statement if two noncollinear rays join at a common endpoint, then an angle is created is a DEFINED TERM.
A defined term is a sentence or expression used to define a concept, statement or confusing words.
From the question shown, we can see that a statement was created which is defined as "If two noncollinear rays join at a common endpoint, then an angle is created". This can be said to be a defined term since there are presence of keywords that made the statement meaningful and easily understandable.
Hence we can conclude that the statement is neither postulate, theorem nor an undefined term rather we can say it is a DEFINED term.
Learn more about definition here: https://brainly.com/question/9823471
The person above is correct defined term :)
PLEASE HELPPPPPPPP!!!!!!!!
Answer:
True
Step-by-step explanation:
tan B = sin B / cos B = 3/4 Let sin B =3 and cos B = 4
Cot B = cos B / sin B = 4/3
This is true
Question Number 19 of 40 - Algebra II Boyle's Law states that, for a fixed amount of gas, the volume of the gas at a constant temperature is inversely proportional to the pressure. If a certain gas occupies 9.84 liters at a pressure of 50 centimeters of mercury (cm Hg), what is the approximate pressure when the volume is increased to 12 liters
Answer:
41 cm Hg
Step-by-step explanation:
In algebraic expression
Three-fourths the square of a number.
Answer:
3/4x^2
Step-by-step explanation:
Answer:
[tex] \frac{3}{4} \sqrt{x} [/tex]
where 'X' is the number
Step-by-step explanation:
hope this helps
lvan earned $8 each time he walks his neighbor's dog. he already walked the dog 5 times.
How many more times does her need to walk the dog to earn enough money to buy a game that costs $88
__? more times
(84)/(12)+(5-7)^(2)-72-6x2
Answer:
[tex]-73[/tex]
Step-by-step explanation:
Note: My explanation is based of the order-of-operations
First, using the order-of-operations, we evaluate the expressions in parentheses. Fully simplifying [tex](5-7)^2[/tex] gives us: [tex](5-7)^2 = -2^2 = 4[/tex].
Next, we do [tex]6\cdot2[/tex] giving us [tex]12[/tex]. So far, our expression is simplified to [tex]\frac{84}{12} + 4 - 72 - 12[/tex].
We also know that [tex]\frac{84}{12}[/tex] is just [tex]7[/tex] so we can replace that value in the expression leaving us with: [tex]7+4-72-12[/tex]. Now, we can solve it in simple steps!
1) [tex]7+4=11[/tex]
3) [tex]11-72=-61[/tex]
4) [tex]-61-12=-73[/tex]
Our answer is [tex]-73[/tex]
Hopefully this helped you out! Please (please) tell me if their is a mistake in the solution and I will correct it as fast as possible for me.
what is the equation in slope intercept form 3 y - 9= 12x please help fast
Answer:
Step-by-step explanation:
Slope intercept form is y = mx + b where m is the slope and b is the y intercept SO
y = mx + b
3y - 9 = 12x
3y = 12x + 9 (divide by common denominator 3)
y = 4x + 3
what is the measure of angle k?
Answer:
Hence the answer is Letter B.
Step-by-step explanation:
° ° °
If the area of a rectangular field is x2 – 3x + 4 units and the width is 2x – 3, then find the length of the rectangular field.
Answer:x²-3 x+4/ 2x-3 units
Step-by-step explanation:
Area = Length * Width sq. units
x^2 - 3x + 4 = Length * 2x - 3
=>Length = x^2- 3 x + 4/ 2 x − 3 units
What is the measure of m?
5
15
E
n
m = [?]
====================================================
Explanation:
The two smaller triangles are proportional, which lets us set up this equation
5/n = n/15
Cross multiplying leads to
5*15 = n*n
n^2 = 75
----------
Apply the pythagorean theorem on the smaller triangle on top, or on the right.
a^2+b^2 = c^2
5^2+n^2 = m^2
25+75 = m^2
100 = m^2
m^2 = 100
m = sqrt(100)
m = 10
The scores of James in his math test are 75, 78, 89, and 71. What score on the next test will make James’ average at least 80 ?
x > 87
x > 87
x < 87
x < 87
Answer: x ≥ 87
Step-by-step explanation:
Set the minimum score on the next test as x & calculate it:
[tex]\frac{75+78+89+71+x}{5} =80\\\\75+78+89+71+x=80(5)\\\\313+x=400\\\\x=400-313=87[/tex]
So they need at least a score of 87 for the average to be 80+.
Answer:
x ≥ 87
Step-by-step explanation:
how did they get 3/4 ?
someone please help me explain
Answer: 0.6/0.8
= (0.6*100)/(0.8*100) {multiplying by 100 in both numerator and denominator}
= 60/80 (cut the zero)
= 6/8 (cut by 2)
= 3/4
Marla noticed that her friend Ron had three times as many pieces of candy as she did. She told him, "If you give me seven pieces of your candy, we'll have exactly the same number of pieces." Ron responded, "I didn't know that until you mentioned it. But I'll make you a deal: If you can show me how to solve this puzzle using algebra, I'll give you the seven pieces. "One minute later, Ron was shocked to see that Marla had solved it perfectly. Can you do the same?
Answer:
This question seems to be asking for the work, so I put it below.
Anyhow, Marla had 3.5 candies, and Ron had 10.5.
Step-by-step explanation:
x = 3x - 7 (lets set this as "a") { a = 3x - 7}
x + 7 = 3x -7 + 7
x + 7 = 3x
( x + 7 ) / 3 = 3/3x
( x + 7 ) / 3 = x = *(same as "a") {a}
( x + 7 ) / 3 = 3x - 7
( x + 7 ) / 3 * 3 = ( 3x - 7 ) * 3
x + 7 = 9x - 21
x - x + 7 = 9x - x - 21
7 = 8x - 21
7 + 21 = 8x - 21 + 21
28 = 8x
28 / 8 = 8/8x
3.5 = x
We can plug this back into the original equation and find that it is correct because:
x = 3x - 7
x = 3.5 =====
3.5 = 3( 3.5 ) - 7
3.5 = 10.5 - 7
3.5 = 3.5
Answer:
Marla has 7 and Ron has 21
Step-by-step explanation:
lets take
no. of candies Marla has as "x"
and no. of candies Ron has will be "3x"
Marla says if Ron gives her seven candies, they will have the same no. of candies
so your equation will be -
x + 7 = 3x - 7 (as Marla gets the candy, Ron loses the candy)
3x - x = 7 + 7
2x = 14
∴x = 7
and 3x = 3 x 7 = 21
YOUR WELCOME
The equations of four lines are given. Identify which lines are perpendicular.
Line 1: y=2
Line 2: y=15x−3
Line 3: x=−4
Line 4: y+1=−5(x+2)
Answer:
lines 1 and 3
Step-by-step explanation:
y = 2 is a horizontal line parallel to the x- axis
x = - 4 is a vertical line parallel to the y- axis
Then these 2 lines are perpendicular to each other
y = 15x - 3 ( in the form y = mx + c ) with m = 15
y + 1 = - 5(x + 2) ( in the form y - b = m(x - a) with m = - 5
For the lines to be perpendicular the product of their slopes = - 1
However
15 × - 5 = - 75 ≠ - 1
The 2 lines 1 and 3 are perpendicular
Find m so that the equation msin²x+cos²x=m-1 has a solution on the interval (0;π/4)
msin²x+cos²x=m-1
since the interval are 0 and π/4
Therefore
msin²(0)+cos²(0)=m-1
m(0)+1=m-1
1=m-1
m=2
use π/4 now
msin²(π/4)+cos²(π/4)=m-1
m(1/2)+(1/2)=m-1
m+1=2(m-1)
m+1=2m-2
-m=-3
m=3
Therefore
m=2 or 3
take a square of arbitary measure assuming its area is one square unit.divide it in to four equal parts and shade one of them.again take one shaded part of that square and shade one fourth of it.repeat the same process continuously and find the sum area of shaded region
Answer:
In recreational mathematics, a square array of numbers, usually positive integers, is called a magic square if the sums of the numbers in each row, each column, and both main diagonals are the same.[1][2] The order of the magic square is the number of integers along one side (n), and the constant sum is called the magic constant. If the array includes just the positive integers {\displaystyle 1,2,...,n^{2}}{\displaystyle 1,2,...,n^{2}}, the magic square is said to be normal. Some authors take magic square to mean normal magic square.[3]
The smallest (and unique up to rotation and reflection) non-trivial case of a magic square, order 3
Magic squares that include repeated entries do not fall under this definition and are referred to as trivial. Some well-known examples, including the Sagrada Família magic square and the Parker square are trivial in this sense. When all the rows and columns but not both diagonals sum to the magic constant we have semimagic squares (sometimes called orthomagic squares).
The mathematical study of magic squares typically deals with its construction, classification, and enumeration. Although completely general methods for producing all the magic squares of all orders do not exist, historically three general techniques have been discovered: by bordering method, by making composite magic squares, and by adding two preliminary squares. There are also more specific strategies like the continuous enumeration method that reproduces specific patterns. Magic squares are generally classified according to their order n as: odd if n is odd, evenly even (also referred to as "doubly even") if n is a multiple of 4, oddly even (also known as "singly even") if n is any other even number. This classification is based on different techniques required to construct odd, evenly even, and oddly even squares. Beside this, depending on further properties, magic squares are also classified as associative magic squares, pandiagonal magic squares, most-perfect magic squares, and so on. More challengingly, attempts have also been made to classify all the magic squares of a given order as transformations of a smaller set of squares. Except for n ≤ 5, the enumeration of higher order magic squares is still an open challenge. The enumeration of most-perfect magic squares of any order was only accomplished in the late 20th century.
Magic squares have a long history, dating back to at least 190 BCE in China. At various times they have acquired occult or mythical significance, and have appeared as symbols in works of art. In modern times they have been generalized a number of ways, including using extra or different constraints, multiplying instead of adding cells, using alternate shapes or more than two dimensions, and replacing numbers with shapes and addition with geometric operations.
The sum area of shaded region is [tex]\frac{1}{3}[/tex].
Summation formula for geometric progressionThe formula to find the sum of infinite geometric progression is
[tex]S_{n}=\frac{a_{1}(1-q^{n}) }{1-q} \ \ q \ne 1[/tex]
Given
S = [tex]\frac{1}{4} +\frac{1}{16} +\frac{1}{64} +.........[/tex]
Using geometric progression
S = [tex]\lim_{h \to \infty} [\frac{1}{4} +(\frac{1}{4} )^{2} +(\frac{1}{4} )^{3} +.........+(\frac{1}{4} )^{n}][/tex]
Using summation formula for geometric progression
[tex]S_{n}=\frac{a_{1}(1-q^{n}) }{1-q} \ \ q \ne 1[/tex]
= [tex]\lim_{h \to \infty} \frac{\frac{1}{4} (1-(\frac{1}{4} )^{n} }{1-\frac{1}{4} }[/tex]
= [tex]\lim_{h \to \infty} \frac{\frac{1}{4} (1-\frac{1}{4^{n} }) }{\frac{3}{4} }[/tex]
= [tex]\lim_{h\to \infty} \frac{1}{3}(1-\frac{1}{4^{n} } )[/tex]
[tex]\lim_{h\to \infty} \frac{1}{4^{n} }[/tex] = 0
S = [tex]\frac{1}{3}(1-0) = \frac{1}{3}[/tex]
The sum area of shaded region is [tex]\frac{1}{3}[/tex].
Find out more information about summation formula for geometric progression here
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evaluate the expression. check all possible sets that the solution may belong in. 40-5^2
Answer:
15
Step-by-step explanation:
following PEMDAS, we don't have () so we move on to exponents
5^2 is equal to 5 x 5 which is 25
40-25=15
[tex]\huge\textsf{Hey there!}[/tex]
[tex]\large\textsf{40 - 5}\mathsf{^2}\\\\\\\large\textsf{5}\mathsf{^2}\\\large\textsf{= 5}\times\large\textsf{5}\\\large\textsf{= \bf 25}\\\\\\\large\textsf{= 40 - 25}\\\\\\\large\textsf{= \bf 15}\\\\\\\\\\\\\boxed{\boxed{\huge\textsf{Therefore your answer is: \bf 15}}}\huge\checkmark[/tex]
[tex]\huge\textsf{Good luck on your assignment \& enjoy your day!}[/tex]
~[tex]\textsf{Amphitrite1040:)}[/tex]
The lengths of the sides of a triangle are 3, 3, 312. Can the tangle be a right triangle?
Answer:
Yes it can be right angle triangle
tan30°+cos30°÷tan30°×cos30°
Answer:
{1/√3+1/2} ÷{1/√3× 1/2}
(2+√3)/2√3÷(1/2√3)2+√3+1 /2√3(2+1 )+√3 /2√33 +√3 /2√3Find the surface area of a cylinder with a base diameter of 6yd and a height of 8yd.
Write your answer in terms of pi, and be sure to include the correct unit.
Answer:
207.35yd²
Step-by-step explanation:
what value of x is in the solution set of -5-15>10+20x
Answer:
-3/2 >x
Step-by-step explanation:
-5-15>10+20x
Combine like terms
-20 > 10 +20x
Subtract 20 from each side
-20 -10 > 10+20x-10
-30> 20x
Divide by 20
-30/20 >20x/20
-3/2 >x
Answer:
-3/2 > x
Step-by-step explanation:
-5 - 15 > 10 + 20x
^ ^
-20
-20 > 10 + 20x
-10 -10
---------------------
-30 > 20x
----- -------
20 20
-3/2 > x
Hope this helped.
