Oof, I'm to tired to remember how to do this T-T
Can anyone help asap? This is timed. Brainliest for best answer!!

Answer:

Volumen A = 30000 cm³

Volumen B = 35000 cm³

Volumen C = 72000 cm³

Step-by-step explanation:

a) Volumen A

Largo = 50 cm, Ancho = 30 cm Alto = 20 cm

Volumen = Largo × Ancho × Alto

= 50 cm × 30 cm × 20 cm

= 30000 cm³

b) Volumen B

Largo = 35 cm, Ancho = 20 cm Alto = 50 cm

Volumen = Largo × Ancho × Alto

= 35 cm × 20 cm × 50 cm

= 35000 cm³

c) Volumen C

Largo = 40 cm, Ancho = 60 cm Alto = 30 cm

Volumen = Largo × Ancho × Alto

= 40 cm × 60 cm × 30 cm

= 72000 cm³

Answer:

Ascending order

Step-by-step explanation:

Ascending numbers are numbers that begin from smallest to biggest.

Answer:

[tex]ML=9,MN=8[/tex]

[tex]MK=ML+LK[/tex]

[tex]9+-3+x[/tex]

[tex]=9-3+x[/tex]

[tex]MK=6+x[/tex]

[tex]ME=MN+NE[/tex]

[tex]ME=8+x[/tex]

Now using Secant secant theorem:-

[tex]ML*MK=MN*ME[/tex]

[tex]9(6+x)=8(8+x)[/tex]

[tex]54+9x=64+8x[/tex]

Subtracting 8x and 54 on both sides:-

[tex]54+9x-8x-54=64+8x-8x-54[/tex]

[tex]x=10[/tex]

[tex]KL=-3+x[/tex]

[tex]KL=-3+10[/tex]

[tex]KL=7[/tex]

so, your answer is C) 7

-------------------------

hope it helps....

Answer:

C.) 7

Step-by-step explanation:

I got it correct on founders edtell

Answer:

answer is 18.76 percent.

Step-by-step explanation:

CP= $40

SP= $32.5

Markdown percent=?

now,

markdown %= CP-Sp/CP×100%

=7.5/40×100%

=750/40

=18.75%

The amount to be reduced is:  $40 -  $32.5 =  $7.5

The percentage decrease is: (7.5 : 40) * 100 = 18.25%

9514 1404 393

Answer:

  13311₅

Step-by-step explanation:

Each column gets the sum mod 5, with a carry to the next column of the quotient of the sum and 5. For example, in the units column, 2+4 = 11₅, so 1 is written in the units column as the sum, and 1 is carried to the 5s column (next one to the left).

Continuing in this fashion gives the sum 13311₅.

__

If you recognize that 3444₅ = 4000₅ -1, you can subtract 1 from 4312₅ and add 4 in the 5³ place (4th column from the right). That gives you ...

  4311₅ +4000₅ = 13311₅

_____

The base-5 addition table is attached.

Answer:

11/2 miles per hour

Step-by-step explanation:

that is the procedure above

Answer:

I think it is k(2,5) or k'(-2, -5

Step-by-step explanation:

Hope This Helps Have A Good Day

70% sure that it is K(2,5)

Answer:

68°

Step-by-step explanation:

If a quadrilateral is inscribed in a cirle, the sum of its opposite angles is 180°. Angles B and D are opposite => B+D=180° => D=180°-B=180°-112°=68°

Answer:

68°

Step-by-step explanation:

Since angles B and D are opposite each other, they are supplementary.

Answer:

35.333333333...%

Step-by-step explanation:

954/2700 = 35.33333333333333...%

You could use a calculator to solve these types of problems, but I'm not saying you should use one for every single problem.

Anyway, hope this helps.

Answer:

(1,3)

Hope this helps! :)

3.1 x 22 1/2 = 69.75 rounded is 70

Answer:

333831

Step-by-step explanation:

Answer:

10^7 is 10,000,000

3 x 10^3 is 3000

Therefore to find how many times 10^7 is as large as 3.10^3, divide 10,000,000 by 3000

& you’ll get 3333.3

Step-by-step explanation:

[tex]\large\mathfrak{{\pmb{\underline{\red{Step-by-step\:explanation}}{\orange{:}}}}}[/tex]

[tex]( { {5}^{3} })^{ - 3} \\ \\ which\:means \:that \: {5}^{3}\: is \:multiplied \:thrice\: with\: itself\\ \\ = {5}^{3 \times - 3} \\ \\ = {5}^{ - 9} \\ \\= \frac{1}{ {5}^{9} } \\ \\ = \frac{1}{5 \times 5 \times 5 \times 5 \times 5 \times 5 \times 5 \times 5 \times 5} \\ \\ = \frac{1}{1953125} [/tex]

Note:-

[tex]( { {a}^{m} })^{n} = {a}^{m \times n} [/tex]

[tex]{a}^{ - m} = \frac{1}{ {a}^{m} }[/tex]

[tex]\large\mathfrak{{\pmb{\underline{\orange{Happy\:learning }}{\orange{!}}}}}[/tex]

Answer:

3

Step-by-step explanation:

5(x-1)-2

5(2-1)-2

5×1-2

5-2

3

Hope this helps you :)

please mark brainliest

Answer:

sympathise or strategies

Answer: The correct option is B.

Step-by-step explanation:

(x+5)(2x-1)=3(x+5)

Multiply the parentheses

2x^2 - x + 10x - 5 = 3x + 15

Collect like terms

2x^2 + 9x - 5 = 3x + 15

Move the expression to the left hand side and change its sign, then equate it to 0

2x^2 + 9x - 5 - 3x -15 = 0

Collect like terms

2x^2 + 6x - 20 = 0

Divide each term of the equation by 2

x^2 + 3x - 10 = 0

Rewrite the expression in factorized form

x^2 + 5x - 2x - 10 = 0

Factor the expression

x(x + 5) - 2(x + 5) = 0

(x + 5) (x - 2) = 0

Separate into possible cases but when the product of factors equals 0, at least one factor is 0.

x + 5 = 0———equation (1)

x - 2 = 0———-equation (2)

Solve the equations

x + 5 = 0———equation (1)

Make x the subject

x = 0 - 5

x = -5

x - 2 = 0———equation (2)

Make x the subject

x = 0 + 2

x = 2

Hence, the possible values of x are -5 and 2.

Answer:

5/24.

Step-by-step explanation:

2/6 of 5/8 were beginners and girls

= 1/3 * 5/8

= 5/24.

Answer:

-0.67 rounded to hundredths

Step-by-step explanation:

3×(q + 4/3) = 2

q + 4/3 = 2/3

q = -2/3 = -0.666666666666...

Answer:

6

Step-by-step explanation:

1/4= 6 men

1/2=12 men

therefore 24-12-6=6 men

Answer:

$1.62

Step-by-step explanation:

Answer:

4.12m

Step-by-step explanation:

(distance of whole shadow - distance of Aisha from tree)

17.95-12.5=5.45m

17.95/5.45=3.29...(scale factor)

3.29...*1.25=4.12m(to the nearest hundredth)

Step-by-step explanation:

hakdogg happyly ever after

Answer:

2 hours

Step-by-step explanation:

Y=25x+30

80=25x+30

50=25x

2=x

Answer:

4

Step-by-step explanation:

each term is 4 times the previous term

the common ration is 4

Answer:

r = 4

Step-by-step explanation:

The common ratio r of the geometric sequence is calculated as

r = [tex]\frac{a_{2} }{a_{1} }[/tex] = [tex]\frac{4}{1}[/tex] = 4

Answer:

neither

Step-by-step explanation:

Slope of the first line: (y2 -y1)/(x2-x1) = (3-(-5)/-1 = 8/-1 = -8

Slope of the second line: (2-3)/4-(-4) = -1/8

They are neither parallel nor perpendicular. In fact the two lines have different slope so they can’t be parallel. In addition the product of their slope is not -1, so they can’t be perpendicular,