The angle between the resultant and the larger force is 60 degree if resultant force value is value 9.1Newtons.
We know that resultant force is given by the superposition principle which uses a formula
Resultant force =√((F₁)² + (F₂)² + 2 ˣ F₁ ˣ F₂ ˣ cosθ)
Superposition principle of electric force to find the resultant power, all accuses are thought about independently of that specific charge as though any remaining charges are missing. Along these lines, for each charge, the power on that specific charge is to be found out. Then the vector amount of the multitude of forces gives the resultant forces on that charge.
We have resultant force as 9.1Newton,F₁=6.2newton,F₂=4.4 newton
So,on putting the values,we get
=>(9.1) = √[(6.2)² + (4.4)² + 2 × 6.2×4.4×cosθ]
Squaring on both sides,we get
=>9.1 × 9.1 =(6.2)² + (4.4)² + 2× 6.2×4.4×cosθ
=>82.81=38.44 + 19.36 + 54.56×cosθ
=>82.81=57.8+ 54.56×cosθ
=>82.81-57.8= 54.56×cosθ
=>25.01=54.56×cosθ
=>cosθ=25.01/54.56
=>cosθ = 0.458
=>cosθ=cos(62.5)°
=>θ=62.5°
=>θ=60°(nearest 10th)
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A car travels down a road at a certain velocity, vcar. The driver slows down so that the car is traveling only a third as fast as before. Which of the following is the correct expression for the resulting velocity?
a. 2vcar
b. 1/3vcar
c. -1/2vcar
d. -2vcar
The correct expression for the resulting velocity is -1/2 vcar. The correct option is c.
What is velocity?
The directional speed of an item in motion, as measured by a specific unit of time and observed from a certain point of reference, is what is referred to as velocity.
A car travels down a road at a certain velocity, is Vcar.
Let the initial velocity of the car travel downward be -V car
It is also, given, that the driver slows down so that the car is traveling only half as fast as before.
Resulting velocity = -1/2 vcar
Therefore, the correct option is c. -1/2vcar.
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an airplane flies horizontally at a speed of 351 km/h and drops a crate that falls to the horizontal ground below. neglect air resistance.part (a) if the altitude of the plane was 580 m, then how far, horizontally in meters, did the crate move as it fell to the ground?
Refer to the attached photos. I would appreciate a rate :)
in an experiment, block is given an initial speed toward block , which is initially at rest. the blocks are on a track that has a motion detector set up, as shown above. when the two blocks collide, there is a completely inelastic collision and the blocks move together with speed . the blocks were both placed on a balance, and it is determined that they have the same mass. the experiment is repeated for four different initial speeds, and the data are shown in the chart below. it appears that the resulting data are not accurate. which measurement most likely produced errors in the data seen in the chart below?
The results that we get from the experiment is accurate within the limits of experimental error. Option E
What is true about the experiment?We know that an experiment is the way by which we can be able to establish a cause and effect relationship. In this case, we can see that there is an inelastic collision that has occurred between the two blocks that have collided in the instance that we can see here.
Looking at the set up of the experiment, it is clear that the block is given an initial speed toward block , which is initially at rest. the blocks are on a track that has a motion detector set up, as shown above.
All of the set up is okay based on the way that such an experiment ought to be arranged to enable us to get a very accurate result out of the work that has been done here.
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which type of wave has a wave perpendicular to the disturbance?responses surface surface longitudinal longitudinal mechanical mechanical transverse
The disruption of a transverse wave propagates perpendicular to the direction of propagation.
Depending on the type of motion they experience, mechanical waves can either be transverse or longitudinal. It should be emphasized that transverse and longitudinal waves can both have periodic behavior.
Transverse wave: what is it?
An oscillating wave that moves in the opposite direction of its oscillations is referred to as a transverse wave in physics. On the other hand, a longitudinal wave travels in the direction of its oscillations. Water waves are transverse waves.
A transverse wave is what sort of wave?
Transverse waves include phenomena like string vibrations and sea surface ripples. The slinky may be swung horizontally up and down to produce a transverse wave. A longitudinal wave's particles are scattered perpendicular to the direction that the wave is moving.
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a current of 11 amps at 240 volts flows through an electric range. if it is user an average of 1 hour/day Calculate the kwhr used per week.
The kWh used per week by the electric range whose voltage and current is 240 V and 11 A respectively is 18.48 kWh.
What is electric kilowatt-hour (kWh)?
A kilowatt-hour is a unit of energy: one kilowatt of power for one hour. In terms of SI derived units with special names, it equals 3.6 megajoules (MJ).
To calculate the kWh per week of the electric range, we use the formula below.
Formula:
E = VIt/1000...............Equation 1Where:
E = Electric energy in kWh per week V = VoltageI = Currentt = Total timeFrom the question,
Given:
V = 240 VI = 11 ampst = 1 hour per day = 1×7 = 7 hours per weekSubstitute these values into equation 1
E = 240×11×7/1000E = 18.48 kWhHence, the kWh used per week is 18.48 kWh.
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the moment of inertia of an object of mass m(a)m(a) is an intrinsic property of the object, (b) depends on the choice of axis of rotation, (c)(c) is proportional to mm regardless of the choice of axis, (d)(d) both (b)(b) and (c)(c) are correct.
Option (B)is correct
depends on the choice of axis of rotation
What does m in a moment of inertia mean?
Formula for Moment of Inertia
Moment of inertia is defined in general form as I = m r2,
where m is the sum of the product of the mass.
r is the separation from the rotational axis.
What elements affect inertia?
The position and orientation of the rotational axis affect a body's moment of inertia. It also depends on the body's size, shape, and how its mass is distributed around a particular axis. Q.
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newton's second law in 1 dimension: what magnitude net force is required to accelerate a 1200-kg car uniformly from 0 m/s to 27.0 m/s in 10.0 s?
The required force is F = 3240 N.
As a result,
1200 kg is the car's mass.
Initial speed of the vehicle, u = 0.
The car's final speed is 27 meters per second.
Thus we have to first calculate the acceleration and then substitutes its value in the force formula
Taking time, t = 10 s
F = m a, where a represents the vehicle's acceleration, is the formula for the required force.
a= v - u / t
thus a = 27 - 0/ 10
a = 27/ 10
F = 1200 X 27 / 10
F = 3240 N.
Therefore, this is the necessary solution.
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suppose a woman does 550 j of work and 9800 j of heat transfer occurs into the environment in the process. (a) what is the decrease in her internal energy (in kcal), assuming no change in temperature or consumption of food? (that is, there is no other energy transfer.) -10350 kcal (b) what is her efficiency (in percent)? %
W = -500 J is the work, which is why it's negative because a woman is doing it.
Briefing
The heat transfer into the system,
Q = 9500 J, makes it positive.
(a) Heat and work are added to determine the change in internal energy, which is:
ΔU = Q+W
We replace with:
ΔU = 9500 J-500 J
ΔU = 9000 J\s(b) (b) The quantity of useful work completed given a total energy supply is now what is generally referred to as an efficiency. From this, we may divide the woman's labour by the shift in internal energy, giving us
= 500 j / 9000 j.
We get:
ϵ = 0.0556~ 5.56%
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If you are holding a bucket steady by a rope with a tension force of 20 N, how much does the bucket weigh?
The weight of the bucket suspended by rope held in your hand is 20 N.
What is Newton's third law of motion?
Newton's third law of motion states that for every action there is an equal and opposite reaction. That is the force applied or exerted on an object is equal to the reaction of the object.
Mathematically, the formula for the Newton's third law of motion is given as;
Fa = Fb
where;
Fa is the applied force on the objectFb is the reaction experienced by the objectThe applied force and the reaction force are equal in magnitude but opposite in direction.
Thus, if the tension holding a bucket upward is 20 N, then there must be an equal and opposite force pushing the bucket downwards. The downward force of the bucket or the weight of the bucket must be equal to the tension holding the bucket upwards.
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to meet a u.s. postal service requirement, footwear must have a coefficient of static friction of 0.525 or more on a specified tile surface. a typical athletic shoe has a coefficient of 0.785. in an emergency, what is the minimum time interval in which a person starting from rest can move 2.85 m on a tile surface if she is wearing the following footwear?
A minimal time period is required to accelerate through x=3.00m because maximal static friction produces the force that creates maximum acceleration.
Explain what an acceleration is.acceleration is the rate of change in both direction and speed of velocity over time. When anything moves faster or slower in a straight line, it is said to have been accelerated. Because of direction is always shifting, motion on a circle accelerates even while the speed is constant.
A person moves by the help of frictional force, as a result of gtound reaction. So, the formula for frictional force is:
F = μR
where,
F = frictional force
μ = coefficient of friction
R = Normal Reaction = Weight of Body = W = mg
Therefore,
F = μmg
but, from Newton's 2nd Law of Motion:
F = ma
Comparing both equations, we get:
μmg = ma
a = μg ---------- equation (1)
Now, to calculate the distance moved by a body, we use 2nd equation of motion:
s = (Vi)(t) + (0.5)at²
using equation (1), we get:
s = (Vi)(t) + (0.5)μgt²
where,
s = distance moved by body
Vi = initial velocity of body
t = time taken to cover the distance
g = acceleration due to gravity
(a)
Vi = 0 m/s
g = 9.8 m/s²
s = 3.2 m
μ = 0.5
t = ?
Therefore,
3.2 m = (0 m/s)(t) + (0.5)(0.5)(9.8 m/s²)t²
t² = 3.2 m/(0.5)(0.5)(9.8 m/s²)
t = √1.30612 s²
t = 1.14 s
(a)
Vi = 0 m/s
g = 9.8 m/s²
s = 3.2 m
μ = 0.5
t = ?
Therefore,
3.2 m = (0 m/s)(t) + (0.5)(0.5)(9.8 m/s²)t²
t² = 3.2 m/(0.5)(0.5)(9.8 m/s²)
t = √1.30612 s²
t = 1.14 s
(a)
Vi = 0 m/s
g = 9.8 m/s²
s = 3.2 m
μ = 0.87
t = ?
Therefore,
3.2 m = (0 m/s)(t) + (0.5)(0.87)(9.8 m/s²)t²
t² = 3.2 m/(0.5)(0.87)(9.8 m/s²)
t = √0.75 s²
t = 0.87 s
What are acceleration and speed exactly?The rate of change in displacement is known as velocity. Acceleration is the rate at which speed changes. The fact that velocity contains both magnitude and orientation makes it a vector quantity. Acceleration is also a vector quantity since it is simply the rate during which velocity varies.
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a watermelon explodes into three equal masses. one mass moves east at 15.0 m/s. if a second mass moves at a velocity of 10.0 m/s 45.0o s of e, what is the velocity of the third mass? (hint: the total momentum is zero, so how will your vector arrows add up?)
The velocity of third mass of watermelon is 3.12m/sec if it explodes into three equal masses.
We know that we need to conserve the momentum of watermelon in a certain direction.Also,we know that initial momentum of watermelon is zero,it means that according to law of conservation of momentum final momentum should be zero.
Now,initial momentum of watermelon=0Kg-m/sec
Alos,we know that momentum =mass× velocity
Now,suppose watermelon has mass m.When it explodes into three equal parts,then the mass of each watermelon pieces is m/3
=>So,final momentum of piece moving to east=(m/3)×15
Similarly final momentum of second and third piece are
(m/3)×10×1/√2 and (m/3) × v × (1/√2)
So,conserving momentum,we get
=>0=(m/3) × 15 +((m/3)×10×1/√2 ) + (m/3)×10×1/√2 )×v
=> - (15 + 10/√2) = (10/√2)×v
=> - (15√2 + 10) = 10v
=>v = (15√2 + 10)/10
=>v= -(21.21+10)/10
=>v= -31.21/10
=>v= -3.12m/sec
Here negative sign shows that mass will move opposite direction to first piece.
Hence, required velocity is 3.12m/sec.
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based on its surface temperature of 6,000 k, most photons that leave the sun's surface lie in which region of the electromagnetic spectrum?
Most photons that leave the sun's surface have a surface temperature of 6,000 K, which corresponds to the visible light region of the electromagnetic spectrum.
The electromagnetic spectrum is a continuous range of wavelengths and frequencies that includes radio waves, microwaves, infrared radiation, visible light, ultraviolet radiation, X-rays, and gamma rays. The wavelengths and frequencies of these different types of electromagnetic radiation are all different and correspond to different regions of the spectrum.
The visible light region of the electromagnetic spectrum is the portion of the spectrum that can be seen by the human eye. It ranges from about 400 nanometers (nm) to about 700 nm in wavelength, and corresponds to frequencies of about 7.5 x 10^14 Hz to about 4.3 x 10^14 Hz. Photons with wavelengths and frequencies in this range have enough energy to excite the photoreceptors in the human eye, allowing us to see them.
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what are the magnitude and location (with respective to point a) of the resultant force on the horizontal gate? the gate width is w. fluid density is r. you can leave your answer in terms of variables (w, r, and g).
The magnitude and location of the resultant force on the horizontal gate is: F = w * r * g, and Point A.
What is magnitude?Magnitude is a measure of the size or intensity of a physical quantity. It is usually defined as the absolute value of the numerical value of the physical quantity, and is often expressed in terms of a unit of measurement. Magnitude can refer to a variety of different physical quantities, such as size, intensity, brightness, or energy. Magnitude can also refer to the relative size or intensity of two or more physical quantities, when compared to each other.
The resultant force on the horizontal gate is equal to the sum of the hydrostatic forces acting on the gate.
Since the gate is horizontal, the hydrostatic forces acting on the gate will be equal to the pressure difference between the top and bottom of the gate.
This pressure difference is equal to the product of the fluid density, gravitational acceleration, and the gate width.
Therefore, the magnitude of the resultant force on the gate will be:
F = w * r * g
The location of the resultant force on the gate will be at the center of the gate, which is point A.
Therefore, the magnitude and location of the resultant force on the horizontal gate is: F = w * r * g, and Point A.
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PLEASE HELP I PAY 88 POINTS AND THANK YOU AND BRAINLIEST
Instructions: Answer the following questions in the space provided. Be sure to write your responses in complete sentences.
A father pushes his daughter and son on a sled down a hill.
Part A: Other than the force exerted by the father pushing the sled, identify two additional forces that act on the sled as it travels from the top of the hill to the bottom. (2 pts)
Part B: Explain how each force you identified in Part A will affect the motion of the sled. (2 pts)
Answer: Down below is the answer in complete sentences!
Explanation:
PART A:
Gravity and Acceleration are two additional forces acting upon the sled.
PART B:
Gravity will affect the sled by pulling it down, since the slope of the hill is negative.
Acceleration will affect the sled by gradually increasing it's speed, since the slope is downwards, which in addition to the initial force exerted plus gravity increases the speed, thus the sled accelerates.
171) a force of 16.88 n is applied tangentially to a wheel of radius 0.340 m and gives rise to an angular 171) acceleration of 1.20 rad/s2. calculate the rotational inertia of the wheel.
The rotational inertia of the wheel which has a radius of 0.34 m is 4.782 kgm²
The force applied tangentially to the wheel = 16.88 N
The radius of the wheel = 0.340 m
The angular acceleration of the well = 1.20 rad /s²
The rotational inertia can be found using the formula,
I = F x r / α
where I is the rotational inertia
F is the force applied
r is the radius of the wheel
α is the angular acceleration
Let us substitute the known values in the above equation, we get
I = 16.88 x 0.34 / 1.20
= 5.7392 / 1.20
= 4.782 kgm²
Therefore, the rotational inertia is 4.782 kgm²
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All living organisms are mainly composed of what elements? * 1 point A. Carbon, Phosphorus, Nitrogen, Oxygen, Potassium B. Calcium, Phosphorus, Nitrogen, Oxygen, Vibranium C. Oxygen, Carbon, Hydrogen, Nitrogen, Phosphorus D. Sodium, Carbon, Nitrogen, Hydrogen, Helium
All living organisms are mainly composed of the elements: Oxygen, Carbon, Hydrogen, Nitrogen, Phosphorus.
The correct answer choice is option c.
What are living organisms?Living organisms are those things that has life. They include plants and animals. Living organisms be it plants or animals are composed of important elements such as carbon, oxygen and others.
However, there are certain characteristic features which living organisms possess. Some of these characteristics of living things are as follows:
Movement: The ability of living organisms to move from one place to another or to move Its body parts. There are two major types of movement known in living organisms. These are: Active movementPassive movementOther characteristics of living organisms are:
RespirationNutritionIrritabilityGrowthExcretionReproduction AdaptationCompetitionIn conclusion, we can now confirm from above the explanation given above that living things are made up of certain elements.
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Hooke's law states that the restoring force of a spring is directly proportional to a small displacement. Students in physics class were conducting an experiment to determine the difference in displacement among various springs. They wanted to determine if displacement not only varied with mass but also with the type of spring used. The class tested twenty springs; they varied in length, circumference, and material. They used an assortment of masses as well. On some springs they used masses of 5g increments; on others, masses of 10g increments. After hanging the masses from each spring, they measured how far the springs stretched. The students concluded that thin, aluminum springs had greater displacement than short, thick, iron springs. How could the students improve the validity of the data in this experiment to better support their conclusion?.
The kind of spring should be held constant so as to improve the validity of the experiment.
What is Hooke's law?Hooke's law states that the force that acts on a spring is directly proportional to the extension of the spring as long as the elastic limit is not exceeded.
As such, we can now understand that we can only be able to talk about the Hooke's law if there is no way in which the material has passed the elastic limit of the material. In this case, we are told that the students just embarked on a kind of experiment and they want to be able to verify the validity of the Hooke's law.
We saw that the masses that were hanged were increased but the springs were also changed. This would not allow us to determine the force constant and the Hooke's law accurately.
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light travels along the length of a 1500-nm-long nanostructure. when a peak of the wave is at one end of the nanostructure, is there a peak or a valley at the other end if the wavelength is (a) 500 nm and (b) 1000 nm?
If the light travels along the length of a 1500 nm , then
(a) if the wavelength is 500 nm then there will be a peak at other end .
(b) if the wavelength is 1000 nm then there will be a valley .
Wavelength is defined as the distance between two consecutive peaks or valleys .
given the length is = 1500 nm ;
we know that , the formula is L = nλ ;
Part (a) ;
for peak at other end ,
n should be a whole number ;
So , λ = 500 nm
n = 1500/500 = 3 ,
Part(b)
λ = 1000 nm ;
n = 1500/1000
= 1.5
Therefore , (a) There will be a peak at other end .
(b) There will not be a peak at other end .
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Suppose a 15 N force is applied to the side of a 5.0 kg block that is sitting on a table. The block experiences a frictional force against the force that is applied.
a) What is the weight of the block (FG)?
b) What is the normal force on the block (FN)?
c) If the coefficient of kinetic friction is μk = .10, what is the frictional force on the block (Ff)?
d) What is the net force on the block?
e) What is the acceleration of the block from the net force?
Answer:
Explanation:
Fg = W = mg = (5.0 kg)(9.8 m/s²) = 49 N
Fnormal = W = 49 N
Ff = μFn = (0.10)(49 N) = 4.9 N
Fnet = 15 N - 4.9 N = 10.1 N
a = Fnet/m = (10.1N)/(5.0kg) = 2.02 m/s²
Please help this is urgent
Consider a planet and an asteroid in the solar system. Both their orbits can be considered as a circle. Their distance to the center of the sun differ by a factor of 4. rB = 4 rA
When r increases by a factor of 4, how do period T, angular velocity ω, and linear speed v change respectively?
1. [tex]T_{B}[/tex] = ___ [tex]T_{A}[/tex]
2. [tex]\omega_{B}[/tex]=___[tex]\omega_{A}[/tex]
3. [tex]v_{B}[/tex] = ___[tex]v_{A}[/tex]
A particle moving in a circle has a linear velocity that is related to its angular velocity by the relationship r/r, where r is the radius, based on our understanding of circular motion.The most significant actions must be taken by the person on the outside.
What angular velocity ω, and linear speed v respectively?While linear speed v increases with radius, angular speed does not. For instance, to maintain line with the rest of the marching band, the individual on the outside must take the biggest steps.
Therefore, Every particle with a rigid body is subject to the relation v/ r = at any given time.
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a vertical spring has a spring constant of 100 n/m. when an object is attached to the bottom of the spring, the spring changes from its unstretched length of 0.50 to a length of 0.65 m. the magnitude of the weight of the object is
Answer: Hookes law states F=kX where F is the force applied, k is the spring constant, and X is the extension of the spring from its resting point.Substituting the values in, we get:F=100*(0.65-0.5)=100*0.15=15N
197) a submarine in neutral buoyancy is 100 m below the surface of the water. what air pressure must 197) be supplied to remove water from the ballast tanks in order for the submarine to surface?
Air pressure must be supplied to remove water from the ballast tanks is 9.8*105 N/m^2.
Buoyancy is the upward force exerted by a liquid that opposes the weight of a partially or fully submerged object. In a liquid column, the pressure increases with depth due to the weight of the liquid above. Therefore, the pressure at the bottom of the liquid column is higher than the pressure at the top of the column. Similarly, the pressure at the bottom of an object immersed in liquid will be greater than at the top of the object. A pressure differential results in a net upward force on an object. The magnitude of the force is proportional to the pressure difference and corresponds to the weight of the liquid (as explained by Archimedes' principle). This is the displaced liquid that would otherwise occupy the underwater volume of the object.
We know that pressure below the surface of water is P1 = Po +hdg
pressure at the surface of water is P2 = Po
Then pressure difference is P = P1 -P2 = hdg
h = depth = 100 m
d = density of water = 1000 kg/m3
g = 9.8 m/s2
Then P = 100*1000*9.8 = 9.8*105 N/m^2
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what is the equation describing the motion of a mass on the end of a spring which is stretched 8.8 cm from equilibrium and then released from rest, and whose period is 0.66 s ? assume that the displacement at the start of the motion is positive.
The equation for the motion of a mass on the end of a spring with a period of 0.66 seconds and a stretch of 8.8 cm from equilibrium is
y = (8.8cm)cos(3πt).
What is the mathematical formula for the mass's motion?Newton's second law, which states that the force acting on a body is equal to that force multiplied by the acceleration of the center of mass of that body, or F = ma, is the basic equation of motion in classical mechanics.
As we are aware, the SHM equation is as follows:
y = Acos(ωt)
Here, we are aware of
ω = 2π/T
Here it is
T = 0.66s
now that we
ω = 2π/0.66
ω = 3π
We now have
y = (8.8cm)cos(3πt).
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a simple pendulum is 4.00 m long. (a) what is the period of small oscillations for this pendulum if it is located in an elevator accelerating upward at 6.00 m/s2?
The time period of the small oscillations for the simple pendulum is found to be 3.14 seconds.
The pendulum is located in an elevator that is accelerating upwards with an acceleration of 6m/s² and length of the pendulum is 4m.
Because the elevator is accelerating in the upper direction the net acceleration of the pendulum will be (10 + 6)m/s².
The period of small accelerations for this pendulum will be given by the relation,
T = 2π(l/a)
Where, l is the length of pendulum and a is the net acceleration.
Putting values,
T = 2π(4/16)
T = 2π(1/2)
T = π seconds.
T = 3.14 seconds.
So, the time period of this small oscillations for this pendulum is 3.14 second.
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Which of these does a balanced chemical
equation show?
the speed of a reaction
elements created by a reaction
phase changes taking place during a
reaction
the number of atoms involved in a reaction
A balanced chemical reaction shows the element created by the reaction, phase changes during the reaction, and the number of atom involved in it.
What are balanced chemical equation?
A balanced chemical equation is a chemical equation in which the number of atoms for each element in the reaction are equal on both sides of the equation. This is important in chemistry because it ensures that mass is conserved in a chemical reaction. For example, the combustion of methane (CH4) can be represented by the following balanced chemical equation:
CH4 + 2O2 → CO2 + 2H2O
In this equation, there are 4 atoms of carbon (C) on the left side and 4 atoms of carbon on the right side, indicating that all of the carbon has been accounted for in the reaction. There are also 8 atoms of oxygen (O) on the left side and 8 atoms of oxygen on the right side, 4 atoms of hydrogen (H) on the left side and 4 atoms of hydrogen on the right side, and 4 atoms of oxygen (O) on the left side and 4 atoms of oxygen on the right side, indicating that all of the elements have been accounted for in the reaction.
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What is the ke of an object that has a mass of 2kg and a velocity of 8m/s
The kinetic energy of the object is 64 joule.
What is kinetic energy?According to the definition of kinetic energy in physics, it is the amount of work that an item may accomplish while in motion.
As a scalar quantity, kinetic energy can only be fully defined by its magnitude. SI unit of kinetic energy is Joule.
Given that: mass of the object: m = 2 kg.
Velocity of the object: v = 8 m/s.
Hence, kinetic energy of it =1/2* mass* velocity^2
= 1/2*mv^2
= 1/2 × 2 × 8^2 joule
= 64 joule.
Hence the kinetic energy is 64 joule.
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a uniform thin rod of length 0.50 m and mass 4.0 kg can rotate in a horizontal plane about its center. a 3.0 gram bullet hits the end of the rod (initially at rest) at an angle of 60 degrees and imbeds in the rod. if the angular speed of the rod is 10. rad/s after the bullet strikes, what is the speed of the bullet before it strikes the rod?
The speed of the bullet before it strikes the rod is 67 m/s. To determine the speed of the bullet before it strikes the rod, we need to consider the conservation of angular momentum.
The moment of inertia of a thin rod about its center is given by the following formula:
I = (1/3) * m * L^2where I is the moment of inertia, m is the mass of the rod, and L is the length of the rod.
Substituting the values given in the problem, we find that the moment of inertia of the rod is
(1/3) * 4.0 kg * (0.50 m)^2 = 0.67 kg*m^2.In this case, the bullet strikes the rod, transferring some of its linear momentum to the rod in the form of angular momentum. The change in angular momentum of the rod is equal to the angular momentum of the bullet.
We can use the conservation of angular momentum to write the following equation:
I1 * w1 + J = I2 * w2where I1 is the initial moment of inertia of the rod, w1 is the initial angular velocity of the rod, J is the angular momentum of the bullet, I2 is the final moment of inertia of the rod, and w2 is the final angular velocity of the rod.
Since the initial angular velocity of the rod is zero, we can simplify the equation as follows:
J = I2 * w2
Substituting the values given in the problem, we find that the angular momentum of the bullet is
0.67 kgm^2 * 10 rad/s = 6.7 kgm^2/s.To determine the speed of the bullet before it strikes the rod, we need to consider the bullet's mass and the angle at which it strikes the rod. The mass of the bullet is given as 3.0 grams, which is equivalent to 0.003 kg. The angle at which the bullet strikes the rod is given as 60 degrees.
We can use the following formula to calculate the speed of the bullet before it strikes the rod:
v = (J/m) * sin(theta)Substituting the values given in the problem, we find that the speed of the bullet before it strikes the rod is (6.7 kg*m^2/s / 0.003 kg) * sin(60 degrees) = 67 m/s. This is the final answer.
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in the photoelectric experiments the current (number of electrons emitted per unit time) is proportional to the intensity of light. can this result alone be used to distinguish between the classical and quantum theories
As we already know that intensity of light used is proportional to the no of electrons emitted per unit of time from the metal plate in the photoelectric effect and does not affect the energy of the emitted electrons and so the stopping potential of the photoelectric cell.
so, if we treat light as a packet of energy and follow quantum theory then it can only emit the electrons as energy is provided as a whole and there is no gap between the striking of photons and the emission of electrons from the metal plate but if we follow the classical theory of light being a wave than the intensity does not matter and no electron can be emitted as energy is provided in continuous form as energy can't be stored and used together.
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boat moves north at a velocity of 2.5 m/s while the current moves downstream at 6.0 m/s east. What is the resultant velocity of the boat, relative to an observer on the shore?
A) 4.5 m/s, NE
B ) 4.5 m/s, SE
C ) 6.5 m/s, NE
D ) 6.5 m/s, SE
E) 8.5 m/s, NE
Relative to the observer in on the shore, the velocity of the boat is 6.5 m/s, NE.
What is relative velocity?
The velocity of an object in relation to another observer is known as its relative velocity.
We cay say that the relative velocity is equal to the vector difference between the velocities of two objects. The relative velocity of A with respect to B= velocity of the body A – velocity of the body B.
The diagram below shows the calculation where AC is relative speed, AB is speed of the boat and BC is the speed of stream.
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An obiect drops from a cliff. If
The final velocity of the object after 5 seconds it was dropped is determined as 50 m/s.
What is the final velocity of the object after 5 seconds?The final velocity of the object after 5 seconds it was dropped is calculated by applying the following kinematic equation as shown below.
v = u + at
where;
u is the initial velocity of the objecta is the acceleration of the objectt is the time of motion of the objectDuring the vertical motion of an object, the vertical velocity of the object decreases as the object moves upwards and eventually becomes zero as the object reaches maximum height.
The vertical velocity of the object starts to increase again when the object start falling downwards and becomes maximum before the object hits the ground.
v = 0 + ( 10 m/s² ) ( 5 s )
v = 50 m/s
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The complete question is below:
if the object falls from the cliff falls with a constant acceleration of 10 m/s2. Find its speed after 5 seconds it was dropped.
