True. The Big Bang Theory is the current scientific explanation for the origin and evolution of the universe. According to this theory, the universe was initially in a state of extremely high density and temperature, and it has been expanding and cooling since its inception.
One reason we cannot directly observe the Big Bang is that the universe's density was so low at that time that there were no solid particles, such as atoms or molecules, that could have formed into stars or galaxies. Instead, the universe was filled with a hot, ionized plasma that was too diffuse to be observed by telescopes. Another reason is that the expansion of the universe has caused the light and other electromagnetic radiation that was emitted during the Big Bang to become redshifted, or stretched out in wavelength, over time. This means that the light from the earliest moments of the universe has shifted into the microwave and radio frequency ranges, which are not visible to the human eye. Therefore, while we can infer some details about the conditions of the early universe based on observations of the cosmic microwave background radiation and the large-scale structure of the universe, we cannot directly observe the Big Bang itself.
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Newton's third law states that any action will have a(n) _______ and ______ reaction.
Newton's third law states that any action will have a(n) equal and opposite reaction.
when you looked at solar activity on the heliophysics event registry website, on which date did you find activity on the sun?
You did look at solar activity on the heliophysics event registry website, and we found activity on the sun on the specified day.
What three sorts of solar occurrences are there?Any natural occurrence in the upper atmosphere of the sun is referred to as a solar phenomenon. Solar flares, prominences and filaments, and coronal mass ejections are three different categories of solar phenomena.
How can I follow the cycle of solar activity the best?The simplest way we can investigate how solar activity changes over time is to survey sunspots, which is also how we track the solar cycle. Sunspots are associated with the Sun's natural 11-year cycle, during which the planet's surface changes from calm to turbulent.
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Maher is trying to find the density of a plastic toy. The toy’s mass is 160 g.
Maher placed the toy in a graduated cylinder that has 70 ml of water, the water level increased
till 150 ml.
a) Find the toy’s volume.
The volume of the toy is 80 ml.
To find the volume of the plastic toy, Maher can use the principle of buoyancy. When an object is placed in a fluid, it will displace an amount of fluid equal to its own volume. The volume of the displaced fluid can be measured and used to calculate the volume of the object.
In this case, Maher has placed the toy in a graduated cylinder filled with water, and he has observed that the water level increased from 70 ml to 150 ml. This means that the toy displaced 150 - 70 = 80 ml of water.
The volume of the toy is equal to the volume of the displaced water, so the toy's volume is 80 ml. This is the volume of the toy when it is completely submerged in water.
It's important to note that the volume of an object can change depending on its temperature, pressure, and other factors. To get an accurate measurement of the volume of the toy, Maher should make sure to measure the volume of the displaced water carefully and under controlled conditions.
Answer:
Volume of the toy: [tex]80\; {\rm mL}[/tex].
Average density of the toy: [tex]2\; {\rm g\cdot mL^{-1}}[/tex] (or equivalently, [tex]2\; {\rm g \cdot cm^{-3}}[/tex].)
Explanation:
The graduated cylinder initially measures the volume of water in this cylinder:
[tex]V(\text{water}) = 70\; {\rm mL}[/tex].
Assume that the toy is submerged in the water. The graduated cylinder would then measure the volume of the water and the toy, combined:
[tex]V(\text{water}) + V(\text{toy}) = 150\; {\rm mL}[/tex].
Rearrange to find the volume of the toy:
[tex]\begin{aligned}V(\text{toy}) &= 150\; {\rm mL} - V(\text{water}) \\ &= 150\; {\rm mL} - 70\; {\rm mL} \\ &= 80\; {\rm mL}\end{aligned}[/tex].
To find the average density of this toy, divide mass by volume:
[tex]\begin{aligned}(\text{average density}) &= \frac{(\text{mass})}{(\text{volume})} \\ &= \frac{160\; {\rm g}}{80\; {\rm mL}} \\ &= 2\; {\rm g\cdot mL^{-1}}\end{aligned}[/tex].
a uniform meter stick of mass 24 g with two weights hanging from it is balanced on a knife edge at the 40 cm mark. a weight of mass 96 g hangs from the 9 cm mark. at which cm mark must the other weight of mass 96 g be located to keep the meter stick balanced?
The second weight of mass 96 g must be located at the 9 cm mark on the meter stick to keep it balanced.
To determine the location of the second weight that will keep the meter stick balanced, we need to consider the principles of equilibrium.
The weight of the meter stick can be calculated as follows:
Weight of meter stick = mass * acceleration due to gravity
= 24 g * 9.8 m/s^2
= 235.2 N
The total weight of the two hanging weights is 96 g + 96 g = 192 g = 1.92 N.
The sum of the forces acting on the meter stick is equal to zero when:
235.2 N + 1.92 N = 0
This equation tells us that the sum of the forces acting on the meter stick is equal to zero when the total weight of the two hanging weights is equal to the weight of the meter stick.
To determine the location of the second weight, we also need to consider the moments about the pivot point. The moment of a force is calculated as the product of the force and the distance from the pivot point. The moments about the pivot point are equal to zero when the sum of the moments of the forces on one side of the pivot point is equal to the sum of the moments of the forces on the other side of the pivot point.
The moment of the weight of the meter stick about the pivot point is calculated as follows:
Moment of the weight of meter stick = force * distance from pivot point
= 235.2 N * 0.4 m
= 94.08 N*m
The moment of the weight hanging from the 9 cm mark about the pivot point is calculated as follows:
Moment of weight hanging from 9 cm mark = force * distance from pivot point
= 1.92 N * 0.09 m
= 0.1728 N*m
To keep the meter stick balanced, the moment of the second weight must be equal in magnitude but opposite in direction to the moment of the weight hanging from the 9 cm mark. The moment of the second weight can be calculated as follows:
Moment of second weight = force * distance from pivot point
= 1.92 N * distance from pivot point
Substituting the value of the force and setting the moment equal to the negative of the moment of the weight hanging from the 9 cm mark, we get the following equation:
1.92 N * distance from pivot point = -0.1728 N*m
Solving for the distance from the pivot point, we find that the second weight must be located at a distance of 0.09 m from the pivot point, or 9 cm. This is the same distance from the pivot point as the weight hanging from the 9 cm mark.
Therefore, the second weight of mass 96 g must be located at the 9 cm mark on the meter stick to keep it balanced.
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a dog lifts a 0.75 kg bone straight up through a distance of 0.11 m. How much work was done by the dog ?
The work done by the dog is 0.81J.
What is work done?Work done is a measure of energy expended in moving an object; most commonly calculated by multiplying the force by the distance.
It is said that no work is done if the object does not move.
The work done on an object is the amount of energy transferred to an object through work.
According to this question, a dog lifts a 0.75 kg bone straight up through a distance of 0.11 m. The force applied to break the bone must be calculated first as follows:
Force = mass × acceleration
Force = 0.75kg × 9.8m/s²
Force = 7.35N
Work done = 7.35N × 0.11m = 0.81J
Therefore, 0.81J is the work done by the dog.
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how long (in s) does it take a child on a swing to complete one swing if her center of gravity is 5.53 m below the pivot?
4.71 s long (in s) does it take a child on a swing to complete one swing if her center of gravity is 5.53 m below the pivot.
What is the center of the gravity?The average position of an object's weight is known as its center of gravity. Any object's travel through space may be entirely explained in terms of how its gravitational center moves from one location to another and, if it is free to spin, how it rotates around that center of gravity. Calculations combining gravitation and dynamics may be made much simpler by treating an object's mass as though it were concentrated at a single location.
Briefing:T=2π√(l/g)
T=2π√(5.53/9.81)
T=4.71
T =4.71 s
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a vertical spring scale can measure weights up to 210 n . the scale extends by an amount of 13.5 cm from its equilibrium position at 0 n to the 210 n mark. a fish hanging from the bottom of the spring oscillates vertically at a frequency of 2.15 hz . part a ignoring the mass of the spring, what is the mass m of the fish?
sheesh sheesh
Explanation:
a typical tendon has a strength of 16000 pounds per square inch (psi). let's assume the achilles tendon is roughly rectangular in cross section with dimension of .4 inches x .2 inches. you can use this to calculate the force at which the achilles tendon will start to fail. at what force might the achilles tendon start to fail (in pounds, lb)?
An average tendon can withstand 16000 per square inch of force (psi). The Achilles tendon may begin to fail at a force of F = 1280 pounds.
How does science define force?That meaning of the term "force" is obvious. At this point, it is quite acceptable to refer to a force as a push or possibly a pull. An item does not "have energy in it" or "encompass energy." A force is applied to one thing by another. A factor is anything that affects non-living things as well.
Inertia or a force?Inertia is what holds the cosmos together. Literally. That could prevent matter from having the electric forces necessary to produce its system layout. Vibrating particles generate heat and rotational motion, which operate to counteract inertia.
Briefing:Area of tendon 0.4×0.2
=0.08 square inch.
0.08 square inch tendon =16000×0.08
F =1280 pound.
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A car travels down a road at a certain velocity, vcar. The driver slows down so that the car is traveling only a third as fast as before. Which of the following is the correct expression for the resulting velocity?
a. 2vcar
b. 1/3vcar
c. -1/2vcar
d. -2vcar
The correct expression for the resulting velocity is -1/2 vcar. The correct option is c.
What is velocity?
The directional speed of an item in motion, as measured by a specific unit of time and observed from a certain point of reference, is what is referred to as velocity.
A car travels down a road at a certain velocity, is Vcar.
Let the initial velocity of the car travel downward be -V car
It is also, given, that the driver slows down so that the car is traveling only half as fast as before.
Resulting velocity = -1/2 vcar
Therefore, the correct option is c. -1/2vcar.
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a vertical spring has a spring constant of 100 n/m. when an object is attached to the bottom of the spring, the spring changes from its unstretched length of 0.50 to a length of 0.65 m. the magnitude of the weight of the object is
Answer: Hookes law states F=kX where F is the force applied, k is the spring constant, and X is the extension of the spring from its resting point.Substituting the values in, we get:F=100*(0.65-0.5)=100*0.15=15N
A robot that is exploring the surface of Mars has a mass of 136 kg. If the gravitational force acting on the robot is 504.6 N downward, what is the free-fall acceleration on Mars?
The free-fall acceleration on Mars is 3.71 m/s²
What do you mean by free fall?A body is said to be in freefall when it only moves in relation to the Earth's gravity. An external force exerted on the ball will cause its motion to accelerate. Gravitational acceleration is another name for this rate of free fall.According to Newton's second law of motion, force (F) = mass (m) times acceleration, an item in free fall will move with an acceleration (a). We can use a little mathematics to determine the object's acceleration in terms of the net external force and the object's mass (a = F / m).Given :
gravitational force acting on the robot is 504.6 N
F= 504.6 N
mass of the robot = 136 kg
a = F/ m
= 504.6/ 136 =3.71 m/s²
The free-fall acceleration on Mars is 3.71 m/s²
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which sentence correctly describes when the triple-alpha process occurs in the life cycle of an average-mass star
Three helium-4 nuclei (alpha particles) are turned into carbon by a series of nuclear fusion processes known as the triple-alpha process.
What results from the triple-alpha procedure as the finished product?
The triple-alpha process and the alpha process are two classes of nuclear fusion reactions that stars use to change helium into heavier elements. The alpha process is also referred to as the alpha ladder. [1] Only helium is used in the triple-alpha process, which also yields carbon.
Which statement concerning alpha particles in an atom is accurate?
Two protons and two neutrons make up alpha particles, which are identical to helium nuclei and have a positive charge.
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what is the effective spring constant k of the two-spring system? express the effective spring constant in terms of k 1 and k 2 .
The Effective Spring Constant is [tex](\frac{k1k2}{k1 + k2} )[/tex] for a system of 2 springs with spring constant k1 and k2.
What is Spring Constant ?The term "spring constant" refers to the proportional constant k. It gauges the stiffness of the spring. A spring exerts a force F = -kx in the direction of its equilibrium position when it is stretched or compressed to a length that differs by an amount x from its equilibrium length.
Spring constants are available in plural (physics) a quality of a spring that is determined by the force acting on the spring to the displacement it produces.
K stands for the proportionality constant, commonly referred to as the "spring constant." In layman's words, stiffness and strength are shown by the k variable in Hooke's law (F = -kx). An item requires more force to be stretched to a specific length the greater the value of k.
Let the force actiong be F N
then , if k1 is the spring constant of spring 1
F = x1 * k1
or, x1 = F/k1.
Similarly for spring 2
x2 = F/k2
Now x1 + x2 = F (1/k1 + 1/k2)
or effective displacement
X= [tex]F(\frac{1}{k1} + \frac{1}{k2} )[/tex]
or, F = [tex]X * (\frac{k1k2}{k1 + k2} )[/tex]
So the Effective Spring Constant is [tex](\frac{k1k2}{k1 + k2} )[/tex].
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Three point charges are arranged in a straight line. The point charges are q1 = 10.0 μC, q2 = –40.0 μC, and q3 = –30.0 μC. Charge q1 is 10.0 cm from charge q2, and charge q3 is 20.0 cm from charge q2. Determine the magnitude of the net electric force on charge q1.
Let us find first the forces at 1, 2 & 3 points.
We know that ke= 8.99 * 109N.m2 / C2
The forces are: -
F1 = keq1q2 / r212 = {8.99 * 109N.m2 / C2} * {10 * 10-6 C} * {40 * 10-6 C} / {10 * 10-2 m}2
F1 = 359.6 N
F2 =keq1q3 / r213 = {8.99 * 109N.m2 / C2} * {10 * 10-6 C} * {30 * 10-6 C} / {30 * 10-2 m}2
F2 = 29.96 N
F3 = keq2q3 / r213 = {8.99 * 109N.m2 / C2} * {40 * 10-6 C} * {30 * 10-6 C} / {20 * 10-2 m}2
F3 = 269.7 N
Now,
The net force on q1 is F1 – F2,
i.e. F1 + F2 = 359.6 + 29.96
F(q1) = 389.56 N to the left
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9. a soap bubble is 100 nm thick and illuminated by white light incident perpendicular to its surface. what wavelength and color of visible light is most constructively reflected, assuming the same index of refraction as water?
When a soap bubble 100 nm thick and illuminated by white light incident perpendicular to its surface, then wavelength, λ is calculated = 5.32 *10^-7 m.
What is index of refraction?The ratio of the speed of light in a vacuum, c, to the speed of light in a medium, c' is called as index of refraction. One of the consequence of this difference in speed is that when light goes from one medium to another at an angle, then the propagation vector in the new medium has a different angle with respect to normal.
Given, t= 100nm= 100 * 10 ^-9 n= 1.33
ΔФ1 = λ/4
ΔФ2 = 2√2 t λ n/2 λ
=2 t n
=2 * 100 * 10 ^-9 * 1.33
= 2.66 *10^-7
2.66 *10^-7= λ/2
λ= 5.32 *10^-7 m.
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Study the following systems: SYSTEM A: Electricity is used to heat a hot plate which heats water making steam which powers a turbine and a generator which makes electricity which is used to power a radio. SYSTEM B: Electricity is used to power a radio. Which system (A or B) is more energy efficient and explain why.
The system that is more energy efficient is system A because it makes use of electricity to produce more results.
What is energy efficiency?Energy efficiency is the use of less energy to perform the same task or produce the same result.
Energy-efficient homes and buildings use less energy to heat, cool, and run appliances and electronics, and energy-efficient manufacturing facilities use less energy to produce goods.
Energy efficiency has the following benefits:
It saves moneyIt increases the resilience and reliability of the electric gridIt provides environmental, community, and health benefitsAccording to this question, the following applies:
SYSTEM A: Electricity is used to heat a hot plate which heats water making steam which powers a turbine and a generator which makes electricity which is used to power a radioSYSTEM B: Electricity is used to power a radioBased on the above explanation, it can be observed that system A is more energy efficient because it uses the same electricity to achieve more.
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5. if the star sirius emits 23 times more energy than the sun, why does the sun appear brighter in the sky? include the terms luminosity and apparent brightness in your response.
The star Sirius is indeed brighter but our Sun appears to be brighter because it is closer to us.
The intrinsic luminosity of Sirius is exactly 25.4 times more than the sun but if we compare the distances of these stars, Sirius is 8.6 light years away from us and the Sun is just 8 light minutes away from us. This marks the obvious reason why our Sun appears more bright.
Even mathematically, it can be justified as the apparent brightness of any luminous object depends on the inverse square of the distance of that luminous object. Therefore the sun's light energy dominates our sky and we can't see any traces of Sirius from the earth.
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sir lancelot, who weighs 800 n, is assaulting a castle by climbing a uniform ladder that is 5.0 m long and weighs 180 n. the bottom of the ladder rests on a ledge and leans across the moat in equilibrium against a frictionless, vertical castle wall. the ladder makes an angle of 53.1 deg with the horizontal. lancelot pauses one third of the way up the ladder. (a) find the normal force and friction forces on the base of the ladder. (b) find the minimum coefficient of static friction needed to prevent slipping at the base. (c) find the magnitude and direction of the contact force on the base of the ladder. (that is, the vector sum of the forces at the base.)
(a) The normal force is 267.7 N and frictional force is 980 N.
(b) The minimum coefficient of static friction is 0.27, which is needed to prevent slipping at the base.
(c) The direction of the contact force is 1016 N.
∈(t) = 0
N₂ ( L sinθ ) = 800 ( [tex]\frac{L}{3}[/tex] cosθ )
N₂ = 267.7 N
(a) Normal force F(d) = N₂ = 267.7 N
Frictional force N = 800 + 180
N = 980 N
(b) The minimum coefficient of static friction,
F(d) = μ N₁
μ = F / N₁
μ = 267.7 / 980
μ = 0.27
(c) The direction of the contact force,
R = [tex]\sqrt{(980)^{2} + (267.7)^{2} }[/tex]
R = 1016 N
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what force must be exerted on the master cylinder of a hydraulic lift to support the weight of a 2500 kg car (a big car) resting on the slave cylinder? the master cylinder has a 1.93 cm diameter, while the slave's is 24.9 cm. 1900 n 150 n 15 n 4.1e 06 n 74 n
The force that must be exerted on the master cylinder of the hydraulic lift to support the weight of car is 147.2 N .
The Pascal's Law states that the relation between the pressure , force and area is given as :
Pressure = Force/Area ;
given that the diameter of the master cylinder is = 1.93 cm ;
so radius of master cylinder = 1.93/2 = 0.965 cm = 0.00965 m ;
the diameter of slave cylinder is = 24.9 cm ;
the radius of the slave cylinder = 24.9/2 = 12.45 m = 0.1245 m ;
Area of slave cylinder (A₁)= π(0.1245)² = 0.0486 m²
Area of the master cylinder (A₂) = π(0.00965)² = 0.000292 m² ;
given mass of the car = 2500 Kg ,
the force exerted will be : F = m*a
F₁ = 2500*9.8 = 24500 N ;
F₁/A₁ = F₂/A₂
So , 24500/0.0486 = F₂/0.000292
F₂ = (24500/0.0486)×0.000292
F₂ = 147.2 N
Therefore , the force exerted on the master cylinder is 147.2 N .
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a 6.2 kg object heading north at 3.0 m/s collides with an 8.0 kg object heading west at 3.5 m/s. if these two masses stick together upon collision, what is their velocity after collision?
The velocity of both objetcs after the collision is 3.07m/sec if both object masses are 6.2 kg and 8.0kg respectively.
To find the velocity of both objects we need to conserve the momentum. We need to follow the law of conservation of momentum which states that initial momentum is equal to final momentum.
Now, we know that momentum =mass × velocity
So, initial momentum of first object=6.2×3=18.6Kg-m/sec
Similarly, initial momentum of second object=8×3.5=28.0kg-m/sec
Now, it is given that both object stick together, so total mass of both objects are=(6.2+8)=14.2kg
Now, both objects are moving with common velocity, so assume both have velocity v
=>So, final momentum of both objects is =14.2×v
according to law of conservation of momentum
=>18.6+25=14.2v
=>43.6=14.2v
=>v=43.6/14.2
=>v=3.07m/sec
Hence, final velocity of objects are 3.07m/sec.
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Which of the following identifies a treatment method developed after the discovery of germ theory?
O Perform a bloodletting procedure.
O Recommend frequent hand washing.
O Induce the patient to vomit.
O Treat the infection with an antibiotic.
Recommend frequent hand washing are the treatment method developed after the discovery of germ theory.
What is the importance and benefits of proper handwashing?Handwashing reduces the spread of contagious diseases: Contaminated hands can transmit a variety of contagious illnesses from one person to another. These illnesses include respiratory infections like the flu, colds, and coronavirus (COVID-19), as well as gastrointestinal infections like salmonellosis.The simplest and most reliable approach we all have to stop the transmission of illnesses spread through touch is to practise good hygiene. Our hands are home to more than 150 different types of germs. Additionally, compared to men, women's hands often have more germs on them.Thus, eliminating germs by handwashing aids in the prevention of diarrhoea, respiratory infections, and maybe even skin and eye diseases.Learn more about steps of proper handwashing refer to :
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a 23-month-old child pulls a pan of hot water off the stove and spills it onto her chest and arms. her mother is right there when it happens. what should the mother do immediately?
When it happens mother should have to do cool the burn with tap water for 10 to 20 minutes immediately.
What are the steps to give first aid to a person with a large burn?Stop the burning process. Cool the burn. Supply pain relief.
Before the arrival of qualified emergency help, you should:
Remove restrictive items such as rings, watches, and bracelets.Use a fresh, cool bandage that is moist to cover the burnt area.Raise your hand so that it is higher than your heart.Is burning from boiling water serious?Pain and skin injury from wet heat or vapors can result from hot water scalding. Because the damaged tissues and cells are destroyed, this kind of burn can be deadly. The heat could even cause your body to go into shock. These burns can be fatal in more severe circumstances.
What should I do right away if I am burned?Cool the burn.
Place the affected area under cool (not cold) flowing water for about 10 minutes. Until the pain goes away, apply a cool, wet cloth to the burned area of the face. If you have a mouth burn from hot food or drink, place a piece of ice in your mouth for a while.
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The diagram below represents a wave.
What is the speed of the wave if its wavelength is 3.0 m?
The speed of the wave is determined as 18 m/s.
option D is the correct answer.
What is the speed of the wave?
The speed of the wave is the rate of change of wave's displacement with time.
The speed of the wave is calculated by applying the formula relating speed, wavelength and frequency of the wave as shown below.
v = fλ
where;
v is the speed of the wavef is the frequency of the waveλ is the wavelength of the waveThe frequency of the wave is calculated as follows;
f = 1 / T
where;
T is the period of the waveThe period of a wave is the time taken for the wave to complete one cycle.
In the picture given, 3 cycles of the wave = 0.5 s
1 cycle of the wave = ?
= 0.5 s / 3
= 0.16667 s
f = 1 / T
f = 1 / 0.16667
f = 6 Hz
The speed of the wave is calculated as follows;
v = fλ
v = 6 Hz x 3 m
v = 18 m/s
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The adjacent figure shows a solid 'S' of weight 15N connected to a thread and put on an inclined plane. 1) a-Is the weight of solid 'S' a contact force or a force acting from a distance? b- List the characteristics of the weight of solid 'S'. Thread Inclined plane c- Represent the weight of solid 'S' by a vector. Choose a convenient scale. 2) a- Name the other forces acting on solid 'S' and indicate their types. b- Represent each force by a vector without respecting a scale. c- List the characteristics of each of the above forces. (Without the magnitude) 3) The thread is cut and solid 'S' moves as shown in the adjacent figure a- Name the new force that acts on solid 'S' and indicate its type. b- List the characteristics of this force.(scale 1cm-1.3N). Thread Inclined plane Solid 'S' Solid 'S'
Answer:
Here is answer
Explanation:
a) The weight of the solid 'S' is a contact force because it acts on the solid 'S' through physical contact with the ground.
b) The characteristics of the weight of solid 'S' are:
It acts in the downward direction.
It is a gravitational force that is exerted by the Earth on the solid 'S'.
It is equal to the mass of the solid 'S' multiplied by the acceleration due to gravity (W = m*g).
c) The weight of solid 'S' can be represented by a vector as shown below:
[asy]
unitsize(1cm);
draw((0,0)--(0,15),Arrow(6));
label("$W$", (0,7.5), W);
[/asy]
a) The other forces acting on solid 'S' are the normal force exerted by the inclined plane on the solid 'S' and the frictional force exerted by the inclined plane on the solid 'S'. The normal force is a contact force, while the frictional force is also a contact force.
b) These forces can be represented by vectors as shown below:
[asy]
unitsize(1cm);
draw((0,0)--(0,15),Arrow(6));
label("$W$", (0,7.5), W);
draw((0,0)--(15sqrt(2)/2,15/2),Arrow(6));
label("$N$", (7.5sqrt(2),7.5), NE);
draw((0,0)--(-15sqrt(2)/2,-15/2),Arrow(6));
label("$F_f$", (-7.5sqrt(2),-7.5), SW);
[/asy]
c) The characteristics of these forces are:
The normal force acts perpendicular to the surface of the inclined plane.
The frictional force acts in the opposite direction to the direction of motion or intended motion of the solid 'S'.
The magnitude of the normal force is equal to the weight of the solid 'S', but in the opposite direction.
The magnitude of the frictional force depends on the coefficient of friction between the solid 'S' and the inclined plane, as well as the normal force.
a) The new force acting on solid 'S' is the gravitational force, which is a force acting from a distance.
b) The characteristics of the gravitational force are:
It acts in the downward direction.
It is a force that is exerted by the Earth on the solid 'S'.
Its magnitude can be represented by the vector shown below (using a scale of 1 cm to represent 1.3 N):
[asy]
unitsize(1cm);
draw((0,0)--(0,-1.3),Arrow(6));
label("$W$", (0,-0.65), S);
[/asy]
A physics student walks 6 meters east, 4 meters north, then 9 meters
west. What is the student's magnitude of displacement from starting
position?
Answer:
5 m
Explanation:
Displacement is the straight-line distance from the starting point to the end point. Student ends up 4m north and 3m west from where he started. Use pythagorean theorem to solve for displacement (d).
d² = 3² + 4² = 25
d = [tex]\sqrt{25}[/tex] = 5 m
Or, if you remember from geometry, a right triangle with legs of 3 and 4 has a hypotenuse of 5 (3-4-5 right triangle)
Maddy tripped and accidentally threw her phone off the hollywood cliff at 5m/s. It landed 20 away from the base of the cliff. how high is the cliff then?
The height of the cliff, given that her phone landed 20 m away when she accidentally threw her phone with a velocity of 5 m/s is 78.4 m
How do I determine the height of the cliff?To determine the height of the cliff, we must first obtain the time taken for her phone to reach the ground. This is obtained as follow:
Horizontal velocity (u) = 5 m/sHorizontal distance (s) = 20 mTime taken (t) =?s = ut
20 = 5 × t
Divide both sides by 5
t = 20 / 5
t = 4 s
Finally, we shall determine the height of the cliff. Details below:
Time taken (t) = 4 sAcceleration due to gravity (g) = 9.8 m/s²Height (h) = ?h = ½gt²
h = ½ × 9.8 × 4²
h = 4.9 × 16
h = 78.4 m
Thus, the height of the cliff is 78.4 m
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perceiving the color, motion, and form of a bird in flight illustrates a. parallel processing. %. opponent-process theory. q. trichromatic theory. d. serial processing. place theory.
parallel processing perceiving the color, motion, and form of a bird in flight illustrates.
Option a is correct.
The trichromatic hypothesis of colour perception is what?According to the trichromatic theory, our ability to perceive red, green, and blue hues as well as how they affect our cerebral activity are both explained by cones (Like a projection T.V.). Consequently, the precise colour we see is determined by the proportion of each colour to the others.
What foundation does trichromatic theory have?The three kinds of cone receptors that are responsible for colour vision are the foundation of the trichromatic hypothesis of colour vision. Beginning in the 18th century, this hypothesis has a very long history.
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what is the kinetic energy of a 60.0 g tennis ball traveling at 177.0 kilometers per hour? report your answer in joules (j).
The kinetic energy is 939.87 J.
what is kinetic energy?Kinetic energy is the power that an object has as a result of motion. If we want to accelerate an object, we have to exert force. Applying force requires effort on our part. The object will be moving at a new, constant speed once the work is done because energy has been transferred to it.
A particle, an object, or a collection of particles can move because of kinetic energy, which is the force that drives motion. Kinetic energy is used by objects in motion like a person walking, a baseball being thrown, food falling from a table, and charged particles in an electric field.
Kinetic energy = 1/2mv²
Kinetic energy = 1/2×0.06×177²
Kinetic energy = 939.87 J.
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a simple harmonic oscillator takes 11.5 s to undergo five complete vibrations. (a) find the period of its motion. s (b) find the frequency in hertz. hz (c) find the angular frequency in radians per second. rad/s
The required values are a) T = 2.3 seconds, b) f = 0.434 Hz, c) ω = 2.7 rd/s.
Which of the following motions is simply harmonic?Simple harmonic motion, a particular kind of periodic motion in which a particle repeatedly oscillates around a mean location, In U-tube oscillating liquid column motion is hence simple harmonic.
According to question:Given,
Time = 11.5 seconds to five complete vibrations.
a) Time period is time taken to complete one vibration,
So T = 11.5/5 = 2.3 seconds
b) Frequency(f) = 1/T
f = 1/2.3 = 0.434 second inverse.
c) By using formula of angular frequency ω = 2π/T
ω = 2π/2.3 = 2.7 hz
Thus, final values are a) T = 2.3 seconds, b) f = 0.434 second inverse, c) ω = 2.7 rd/s.
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1. a 1.4 x 103 kg car is westbound at a velocity of 37.0 km/h when it collides with a 2.0 x 103 kg truck northbound at a velocity of 35 km/h. if these two vehicles lock together upon collision, what is the initial velocity of the vehicles after collision? (7.2 m/s 37o w of n) 2. a 6.2 kg object heading north at 3.0 m/s collides with an 8.0 kg object heading west at 3.5 m/s. if these two masses stick together upon collision, what is their velocity after collision? (2.4 m/s 56o w of n) 3. a 4.0 x 104 n truck moving west at a velocity of 8.0 m/s collides with a 3.0x104 n truck heading south at a velocity of 5.0 m/s. if these two vehicles lock together upon impact, what is their velocity?(5.0 m/s 25o s of w)
The velocity of vehicles after the collision is 15.82m/sec if car mass is 1.4 × 10³kg and truck mass is 2×10³kg
We know that we need to conserve the momentum of watermelon in a certain direction. Also,we know that initial momentum of watermelon is zero,it means that according to law of conservation of momentum final momentum should be zero.
We know that momentum =mass × velocity
So,initial momentum of car is =1.4 × 10³kg × 37km/hr
Similarly,,initial momentum of truck=2×10³kg × 35km/hr
Now,it is given that both vehicles lock together,so total mass of both vehicles is =1.4 × 10³kg + 2×10³kg=3.4 ×10³kg
Assume final velocity of both vehicle is v
So,following the law of conservation,we get
=>1.4 × 10³kg × 37 + 2×10³kg × 35 = 3.4 ×10³ ×v
=>51.8 ×10³ + 2×10³=3.4×10³ ×v
=>53.8 ×10³ kg-m/sec = 3.4×10³ ×v
=>v = 53.8/3.4
=>v=15.82m/sec
Hence,final velocity of both vehicle after collision is 15.82m/sec.
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