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Answer:

4x^2 + 2x + 4

Step-by-step explanation:

5x^2 + 2x + 4 - x^2

4x^2 + 2x + 4

Answer:

2(2x^2 + x + 2)

Step-by-step explanation:

5x^2+2x + 4-x^2

Re arrange so like terms are next to each other

Keep the same symbol that is at the front of the term when moving it

5x^2 - x^2 + 2x + 4

We will just do the first part first

5x^2 - x^2

5x^2 - 1x^2 (is the same thing as above)

So because they are like terms (are both x^2)

We can just minus 1 from 5

5-1=4

So 4x^2

Now the equation is

4x^2 + 2x + 4

This is as small as it gets but you can also bring it to this

4, 2 and 4 all are divisible by 2 so

2(2x^2 + x + 2)

Answer:

Hi, there the answer is

These are the equations with exactly one solution

-5x + 12 = –12x – 12

-5x + 12 = 5x + 12

-5x + 12 = 5x – 5

Hope This Helps :)

Step-by-step explanation:

First degree equations

A first degree equation has the form

ax + b = 0

There are some special cases where the equation can have one, infinitely many or no solution

If , the equation has exactly one solution

If a=0 and b=0 the equation has infinitely many solutions, because it doesn't matter the value of x, it will always be true that 0=0

If a=0 and  the equation has no solution, because it will be equivalent to b=0 and we are saying it's not true. No matter what x is, it's a false statement.

We have been given some equations, we only need to put them in standard form

-5x + 12 = –12x – 12

Rearranging

7x + 24 = 0

It has exactly one solution because a is not zero

.......................

-5x + 12 = 5x + 12

Rearranging

-10x + 0 = 0

It has exactly one solution because a is not zero

.......................

-5x + 12 = 5x – 5

Rearranging

-10x + 17 = 0

It has exactly one solution because a is not zero

.......................

-5x + 12 = -5x – 12

Rearranging

0x + 24 = 0

It has no solution, no matter what the value of x is, it's impossible that 24=0

Answer: These are the equations with exactly one solution

-5x + 12 = –12x – 12

-5x + 12 = 5x + 12

-5x + 12 = 5x – 5

Answer:

F(-2)= g(-2)

Step-by-step explanation:

F(-2)= g(-2), both function have the same points of intersect.

Answer:

First find the SA of the triangular figure

4 x 3 = 12 cm^2 (the triangles on the sides)

2 x 3 = 6 cm^2 (the back square)

2 x 5 = 10 cm^2 (the slanted square)

*I'm not sure if this question includes the bottom of the triangle but here it is anyways

4 x 2 = 8 cm^2

Including the bottom the SA of the triangular figure is:

12 + 6 + 10 + 8 = 36 cm^2

Find the SA of the rectangular shape

4 x 2 = 8 cm^2 (the bottom square)

2 x 6 = 12 x 2 = 24 cm^2 (the sides)

4 x 6 = 24 x 2 = 48 cm^2 (the front and back)

Add them up

8 + 24 + 48 = 80 cm^2

If you wanted to find the SA of the whole figure it would be:

12 + 6 + 10 + 8 + 24 + 48 = 108 cm^2

Hope this helps!

Answer:

100°

Step-by-step explanation:

the lower right angle is 180-149 = 31°

the sum of all three angles in a triangle is 180°.

so the solution is 180-31-49

Answer:

after 10 months

Step-by-step explanation:

Let x be the number of months and y be the amount they still owe.

Sin Ian borrows $1000 from his parents, then the y-intercept b= 1000 since he owes $1000 when x = 0. He pays them back $60 each month The slope is then m = -60 . Substituting in b = 1000 and m = -60 into the slope-intercept form of a line then gives y= mx + b=-60x +1000.

Sin Ken borrows $600 from his parents, then the y-intercept b = 600 since he owes $600 When x= 0. He pays them back $20 per month so the amount he owes decreases $20 each month. The slope is then m = -20 . Substituting in

b= 600 and m = -20 into the slope-intercept form then gives y = mx +b = -20x + 600.

They will owe the same amount when they have the same y-coordinate. Therefore -60x+ 1000= y= -20x+600. Solve this equation for x:

-60x+ 1000 = -20x+ 600

1000 = 40x+ 600

400 = 40x

10=x

They will then owe the same amount after 10 months.

Answer:

7x - 8

Step-by-step explanation:

Hope this helps!

Step-by-step explanation:

Given: [∀x(L(x) → A(x))] →

[∀x(L(x) ∧ ∃y(L(y) ∧ H(x, y)) → ∃y(A(y) ∧ H(x, y)))]

To prove, we shall follow a proof by contradiction. We shall include the negation of the conclusion for

arguments. Since with just premise, deriving the conclusion is not possible, we have chosen this proof

technique.

Consider ∀x(L(x) → A(x)) ∧ ¬[∀x(L(x) ∧ ∃y(L(y) ∧ H(x, y)) → ∃y(A(y) ∧ H(x, y)))]

We need to show that the above expression is unsatisfiable (False).

¬[∀x(L(x) ∧ ∃y(L(y) ∧ H(x, y)) → ∃y(A(y) ∧ H(x, y)))]

∃x¬((L(x) ∧ ∃y(L(y) ∧ H(x, y))) → ∃y(A(y) ∧ H(x, y)))

∃x((L(x) ∧ ∃y(L(y) ∧ H(x, y))) ∧ ¬(∃y(A(y) ∧ H(x, y))))

E.I with respect to x,

(L(a) ∧ ∃y(L(y) ∧ H(a, y))) ∧ ¬(∃y(A(y) ∧ H(a, y))), for some a

(L(a) ∧ ∃y(L(y) ∧ H(a, y))) ∧ (∀y(¬A(y) ∧ ¬H(a, y)))

E.I with respect to y,

(L(a) ∧ (L(b) ∧ H(a, b))) ∧ (∀y(¬A(y) ∧ ¬H(a, y))), for some b

U.I with respect to y,

(L(a) ∧ (L(b) ∧ H(a, b)) ∧ (¬A(b) ∧ ¬H(a, b))), for any b

Since P ∧ Q is P, drop L(a) from the above expression.

(L(b) ∧ H(a, b)) ∧ (¬A(b) ∧ ¬H(a, b))), for any b

Apply distribution

(L(b) ∧ H(a, b) ∧ ¬A(b)) ∨ (L(b) ∧ H(a, b) ∧ ¬H(a, b))

Note: P ∧ ¬P is false. P ∧ f alse is P. Therefore, the above expression is simplified to

(L(b) ∧ H(a, b) ∧ ¬A(b))

U.I of ∀x(L(x) → A(x)) gives L(b) → A(b). The contrapositive of this is ¬A(b) → ¬L(b). Replace

¬A(b) in the above expression with ¬L(b). Thus, we get,

(L(b) ∧ H(a, b) ∧ ¬L(b)), this is again false.

This shows that our assumption that the conclusion is false is wrong. Therefore, the conclusion follows

from the premise.

15

Answer:

Step-by-step explanation:

Given that:

[tex]y^2 (y^2-4) = x^2(x^2 -5)[/tex]

at point (0, -2)

[tex]\implies y^4 -4y^2 = x^4 -5x^2[/tex]

Taking the differential from the equation above with respect to x;

[tex]4y^3 \dfrac{dy}{dx}-8y \dfrac{dy}{dx}= 4x^3 -10x[/tex]

Collect like terms

[tex](4y^3 -8y)\dfrac{dy}{dx}= 4x^3 -10x[/tex]

[tex]\dfrac{dy}{dx}= \dfrac{4x^3 -10x}{4y^3-8y}[/tex]

Hence, the slope of the tangent line m can be said to be:

[tex]\dfrac{dy}{dx}= \dfrac{4x^3 -10x}{4y^3-8y}[/tex]

At point (0,-2)

[tex]\dfrac{dy}{dx}= \dfrac{4(0)^3 -10(0)}{4(-2)^3-8-(2)}[/tex]

[tex]\dfrac{dy}{dx}= \dfrac{0 -0}{4(-8)+16}[/tex]

[tex]\dfrac{dy}{dx}= 0[/tex]

m = 0

So, we now have the equation of the tangent line with slope m = 0 moving through the point (x, y) = (0, -2) to be:

(y - y₁ = m(x - x₁))

y + 2 = 0(x - 0)

y + 2 = 0

y = -2

Answer:

x = -5y

Step-by-step explanation:

x = ay

-10 = 2a

a = -5

x = ay

-15 = 3a

a = -5

x = ay

-25 = 5a

a = -5

Answer:

27

Step-by-step explanation:

The expected count in a χ² test can be obtained thus :

Expected count for each each point in a two way table ::

(row total * column total) / total

Therefore, expected count for cell corresponding to people from United Kingdom whose favorite sport is tennis :

Row total = (51+14+86+29) = 180

Column total = (25 + 29) = 54

Total = 360

Hence,

Expected count = (180 * 54) / 360

Expected count = 27

Answer:

Angle A = [tex]77^{o}[/tex]

Step-by-step explanation:

cos A = adjacent / hypotenuse

cos A = 18/82

cos A = 0.22

A = [tex]cos ^{-1}[/tex]0.22

A = [tex]77^{o}[/tex]

Answer:

Your answer would be B

Step-by-step explanation:

So right away you can get rid of a and d since they are positive numbers, there is no positive numbers in the graph were the line is.

So we know that the y-intercept is -2 (as you can see the line pass through (0,-2))

And we know the y intercept is -8 (since the line pass through (-8,0))

so you are left with b and c, c is incorrect because the -2 goes through the y-intercept not the x.

The right choice is b, it states that the x-intercept -8 pass through the line, the y-intercept is -2

Your welcome and hoped this helped!

Answer:

54 pounds

Step-by-step explanation:

To find out how much flour is needed to make 9 cakes, we first need to find out how much much flour is needed to make 1 cake. For that, we need to divide 6 by 36. That will give you 6. Now that we know how much flour is needed to make 1 cake, we will just have to multiply 6 by 9 to find out how much flour is needed to make 9 cakes. That will give you 54 pounds, which is your final answer.

Answer:

The smallest possible length is 0.83m

Step-by-step explanation:

Given

[tex]Volume = 565L[/tex]

Required

The smallest length of the tank

Since the tank is cubical, then the volume is:

[tex]Volume = Length^3[/tex]

This gives:

[tex]565L= Length^3[/tex]

Express as [tex]m^3[/tex]

[tex]\frac{565m^3}{1000} = Length^3[/tex]

[tex]0.565m^3 = Length^3[/tex]

Take cube roots of both sides

[tex]0.8267m = Length[/tex]

Rewrite as:

[tex]Length = 0.8267m[/tex]

Approximate

[tex]Length = 0.83m[/tex]

Step-by-step explanation:

we can simplify the stuff inside the parentheses to

[tex] \frac{ {x}^{3} }{2y} [/tex]

now we need to multiply it with itself, giving us

[tex] \frac{ {x}^{6} }{4 {y}^{2} } [/tex]

so yeah, D is the correct answer

Answer:

[tex]\displaystyle x \approx 9.9[/tex]

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Equality Properties

Trigonometry

Step-by-step explanation:

Step 1: Define

Identify variables

Angle θ = 64°

Opposite Leg = x

Hypotenuse = 11

Step 2: Solve for x

Answer:

its c

Step-by-step explanation:

9514 1404 393

Answer:

  (x, y) = (5, -2)

Step-by-step explanation:

Equating expressions for y, we have ...

  x^2 -9x +18 = x -7

  x^2 -10x +25 = 0 . . . . . add 7-x to both sides

  (x -5)^2 = 0 . . . . . . . . factor

The value of x that makes the factor(s) zero is x=5. The corresponding value of y is ...

  y = x -7 = 5 -7 = -2

The solution is (x, y) = (5, -2).

Answer:

17

Step-by-step explanation:

2a+30 = 4a-4

+4 +4

2a+34 = 4a

-2a -2a

34 = 2a

÷2 ÷2

a=17

Hope this helps! :)

Answer:

A = 17

Step-by-step explanation:

Opposite angles are congruent in a parallelogram

Hence 2a + 30 = 4a - 4

( Note that we've just created an equation that we can use to solve for a)

We now solve for a

2a + 30 = 4a - 4

Add 4 to both sides

2a + 34 = 4a

Subtract 2a from both sides

34 = 2a

Divide both sides by 2

a = 17

9514 1404 393

Answer:

  x = 8/7

Step-by-step explanation:

The only real zero of this linear function is the value of x that makes y=0:

  0 = -7x +8

  7x = 8 . . . . . . add 7x

  x = 8/7 . . . . . .divide by 7

9514 1404 393

Answer:

  a.  x + 4y = 160

  b.  160

  c.  40

Step-by-step explanation:

a. We can define the variables as ...

  x = number of 1/2-liter bottles

  y = number of 2-liter bottles

For the total number of liters to be 80, we require

  1/2x + 2y = 80

We can multiply this by 2 to eliminate the fraction.

  x + 4y = 160

__

b. The x-intercept is 160. It is the number of 1/2-liter bottles required when no 2-liter bottles are used.

__

c. The y-intercept is 40. It is the number of 2-liter bottles required when no 1/2-liter bottles are used.

Answer:

Area = 96 square m

Step-by-step explanation:

[tex]Area = base \times height = 12 \times 8 = 96 \ m^2[/tex]

Answer:

The area of parallelogram is 96 m ².

Step-by-step explanation:

According to the question , we have given a parallelogram with base 12 m and height is 8 m. We need to find the area of parallelogram.

Using Formula

Area of parallelogram = Base × Height

Substitute the values into this formula

Area of parallelogram = 12 m × 8 m

multiply, we get

Area of parallelogram = 96 m²

Therefore, The area of parallelogram is 96 m ².

Answer: B

Step-by-step explanation:

Answer:

-5ºC < 5ºC is an inequality that compares temperatures.

B is the correct answer for the multiple choice question.

Answer:

13.96units

Step-by-step explanation:

To get the length of CD, we will use the cosine rule as shown:

CD² = DE²+CE²-2(DE)(CE)cos m<E

Substitute the given values

CD² = 14²+9²-2(14)(9)cos71

CD² = 196 + 81 - 252cos71

CD² =277 - 252cos71

CD² = 277 - 82.0431

CD² = 194.95682

CD = √194.95682

CD = 13.96 units

Hence the length of CD of 13.96units

Answer:

D. 3

Step-by-step explanation:

Distance between A and D = AD = 9 units

Distance between A and B = AB = 3 units

[tex] \frac{AD}{AB} = \frac{9}{3} [/tex]

Simplify by dividing

[tex] \frac{AD}{AB} = \frac{3}{1} [/tex]

[tex] \frac{AD}{AB} = 3 [/tex]

The answer is 3

[tex]\implies {\blue {\boxed {\boxed {\purple {\sf {D. \:= 2 {x}^{2} - \frac{1}{3} x}}}}}}[/tex]

[tex]\sf \bf {\boxed {\mathbb {STEP-BY-STEP\:EXPLANATION:}}}[/tex]

[tex] \frac{1}{3} x \: ( \: 6x - 1 \: )\\[/tex]

[tex] = \frac{x \: ( \: 6x - 1 \: )}{3}\\[/tex]

[tex] = \frac{6 {x}^{2} - x}{3} \\[/tex]

[tex] = \frac{6 {x}^{2} }{3} - \frac{x}{3}\\ [/tex]

[tex] = 2 {x}^{2} - \frac{1}{3} x\\[/tex]

[tex]\red{\large\qquad \qquad \underline{ \pmb{{ \mathbb{ \maltese \: \: Mystique35♛}}}}}[/tex]