Noemy had homework three days of the school week. What is the ratio of days with homework to days without homework?

Answer:  Answer:

Company C

Step-by-step explanation:

Company A sells 12 tigers for $33.24.

Cost per tiger = $33.34 / 12

= $2.78

Company B sells 16 tigers for $44.80. Company

Cost per tiger = $44.80 / 16

= $2.8

C charges $41.10 for 15 tigers.

Cost per tiger = $41.10 / 15

= $2.74

The company that has the best buy is company C that charges $2.74 per tiger

Brainliest please

A. is the correct answer

Answer:

A

Step-by-step explanation:

(x-3)(2x+1)= (due to FOIL(First Outer Inner Last)) (First)2x^2-(Outer+Inner)5x-(Last)3. 2x^2-5x-3 is what A says, so A is the answer.

Answer:

81[tex]y^{8}[/tex][tex]z^{4}[/tex]

Step-by-step explanation:

Answer:

17) 19

19) 8

Step-by-step explanation:

17)

(6 +6² -4)÷2

(6 +36 -4)÷2

(38)÷2

19

19)

3³ ÷3 - 1

27 ÷3 -1

9 -1

8

Answer:

[tex]x = \frac{5}{13} [/tex]

Step-by-step explanation:

[tex] \frac{3}{4} x + \frac{5}{4} = 4x[/tex]

[tex]3x + 5 = 16x[/tex]

[tex]3x - 16x = - 5[/tex]

[tex] - 13x = - 5[/tex]

[tex]x = \frac{5}{13} [/tex]

[tex]\\ \tt\longmapsto \dfrac{d}{dx}\sqrt{x}+\dfrac{1}{5x}-3[/tex]

[tex]\\ \tt\longmapsto \dfrac{d}{dx}x^{\frac{1}{2}}+5x^{-1}-3[/tex]

[tex]\\ \tt\longmapsto \dfrac{d}{dx}x^{\frac{1}{2}}+5x^{-1}[/tex]

[tex]\boxed{\sf \dfrac{d(x^n)}{dx}=nx^{n-1}}[/tex]

[tex]\\ \tt\longmapsto \dfrac{1}{2}x^{\frac{-1}{2}}-5x^{-2}[/tex]

[tex]\\ \tt\longmapsto \dfrac{x}{2}^{\frac{-1}{2}}-\dfrac{1}{5x^2}[/tex]

[tex]\\ \tt\longmapsto -\sqrt{\dfrac{x}{2}}-\dfrac{1}{5x^2}[/tex]

Answer:

[tex]4y + 6y = 90 \\ 10y = 90 \\ y = 9 \\ thank \: you[/tex]

Answer:

True

Step-by-step explanation:

[tex]f(x)=y=-8x+5: exchanging\ x\ and\ y\\\\x=-8y+5\\\\8y=-x+5\\\\f^{-1}(x)=y=\dfrac{-x}{8}+\dfrac{5}{8} =g(x)\\\\\\[/tex]

The two functions are inverses.

Answer:

[tex]2(3m + 6n) + 3(5m - 2n) + 5( - 6m + n) \\ [/tex]

open the brackets:

[tex] = (6m + 12n) + (15m - 6n) + ( - 30m + 5n) \\ [/tex]

group the coefficients of m and n in their brackets:

[tex] = (6 + 15 - 30)m + (12 - 6 + 5)n \\ [/tex]

then operate the brackets:

[tex] = - 9m + 11n[/tex]

Answer:

766?

Step-by-step explanation:

Answer and Step-by-step explanation:

Three Digit Number.

***

Second digit = Last digit

*xx

I multiplied 45 from numbers 1-23, with 22 being the maximum # to multiply to get a 3 digit number that is divisible by 45, and 3 being the minimum # to multiply to get a 3 digit number that is divisible by 45.

Now to check which number it is.

When you multiply 45 by 17, you get 765. This number is supposed to be 1 less than the riddle's number. It also has to have the last 2 digits be the same.

So, lets add one to 765 to see if we solved the riddle.

765 + 1 = 766

766 is the answer!

#teamtrees #PAW (Plant And Water)

I hope this helps!

Answer:

6.72

Step-by-step explanation:

I multiplied both numbers by 10 to make it easier in my opinion. That made the equation 994.66 x 148

Then, I divided it until i got to the thousandths place. Lastly, i just rounded making it 6.72

SORRYYYYYYYYYYYYYYY I DONT KNOWWWWW

Answer:

In algebra, like terms are terms that have the same variables and powers. ... Unlike terms are two or more terms that are not like terms, i.e. they do not have the same variables or powers. The order of the variables does not matter unless there is a power.

Answer:

These are not like terms.

Step-by-step explanation:

Although their variables are the same, the exponents are different.  LIke terms must have the same variables AND same exponents.  The first term's variables are: x raised to the second power times y, while the other term's variables are:  y times x times 2

2x ≠ x²

Answer:

Yes

Step-by-step explanation:

6 × 18.75 = 112.50

8 × 18.75 = 150.00

11 × 18.75 = 206.25

15:-

[tex]\\ \qquad\quad\sf\longmapsto \dfrac{x^5y^6}{xy^2}[/tex]

[tex]\\ \qquad\quad\sf\longmapsto x^{5-1}y^{6-2}[/tex]

[tex]\\ \qquad\quad\sf\longmapsto x^4y^4[/tex]

16:-

[tex]\\ \qquad\quad\sf\longmapsto \dfrac{x^2y^5}{xy^4}[/tex]

[tex]\\ \qquad\quad\sf\longmapsto x^{2-1}y^{5-4}[/tex]

[tex]\\ \qquad\quad\sf\longmapsto xy[/tex]

17;-

[tex]\\ \qquad\quad\sf\longmapsto \left(\dfrac{4x^5y}{16xy^4}\right)^3[/tex]

[tex]\\ \qquad\quad\sf\longmapsto (4^{1-2}x^{5-1}y^{1-4})^3[/tex]

[tex]\\ \qquad\quad\sf\longmapsto (4^{-1}x^4y^{-3})^3[/tex]

[tex]\\ \qquad\quad\sf\longmapsto 4^{-3}x^{12}y^{-9}[/tex]

18:-

[tex]\\ \qquad\quad\sf\longmapsto \left(\dfrac{5x^3y}{20xy^5}\right)^4[/tex]

[tex]\\ \qquad\quad\sf\longmapsto (4^{-1}x^{2}y^{-4})^4[/tex]

[tex]\\ \qquad\quad\sf\longmapsto 4^{-4}x^8y^{-16}[/tex]

19:-

[tex]\\ \qquad\quad\sf\longmapsto y^{-7}[/tex]

[tex]\\ \qquad\quad\sf\longmapsto \dfrac{1}{y^7}[/tex]

20:-

[tex]\\ \qquad\quad\sf\longmapsto 7^{-2}[/tex]

[tex]\\ \qquad\quad\sf\longmapsto \dfrac{1}{7^2}[/tex]

[tex]\\ \qquad\quad\sf\longmapsto \dfrac{1}{49}[/tex]

21:-

[tex]\\ \qquad\quad\sf\longmapsto \dfrac{1}{x^{-5}}[/tex]

[tex]\\ \qquad\quad\sf\longmapsto x^5[/tex]

22:-

[tex]\\ \qquad\quad\sf\longmapsto \dfrac{1}{2^{-4}}[/tex]

[tex]\\ \qquad\quad\sf\longmapsto 2^4[/tex]

[tex]\\ \qquad\quad\sf\longmapsto 16[/tex]

23:-

[tex]\\ \qquad\quad\sf\longmapsto x^5\times x^{-1}[/tex]

[tex]\\ \qquad\quad\sf\longmapsto x^{5-1}[/tex]

[tex]\\ \qquad\quad\sf\longmapsto x^4[/tex]

24:-.

[tex]\\ \qquad\quad\sf\longmapsto x^{-6}[/tex]

[tex]\\ \qquad\quad\sf\longmapsto \dfrac{1}{x^6}[/tex]

25:-

[tex]\\ \qquad\quad\sf\longmapsto x^9(x^{-7})[/tex]

[tex]\\ \qquad\quad\sf\longmapsto x^{9-7}[/tex]

[tex]\\ \qquad\quad\sf\longmapsto x^2[/tex]

To graph an exponential,

d. T-chart using random values for x and y.

The set of ordered pairings (x, y) where f(x) = y makes up the graph of a function.

These pairs are Cartesian coordinates of points in two-dimensional space and so constitute a subset of this plane in the general case when f(x) are real values.

Now,

We know an exponential function is a function in which the independent variable is the exponent.

One such function is y = eˣ

Now, To graph an exponential function you come up with values to use in the graph should be a T-chart using random values for x and y.

As it would result in graphing the complete nature of the function.

Learn more about graphs here :

brainly.com/question/2288321

#SPJ7

Answer:

14.76482306

Step-by-step explanation:

distance equals the square root of (x2-x1)^2 + (y2-y1)^2.

think of your ordered pairs as set 1 and set 2. (-4, 6) would be set 1 and (3, -7) would be set 2. so your equation will look similar to: (3- -4)^2 + (-7-6)^2 then you square root the whole thing and you will have your answer.

Answer:

C: 1/4x + 4 = 3

Step-by-step explanation:

1/4x + 4 = 3

1/4x = 3 - 4

x = - 4

Thus, option c gives out the solution x = - 4.

Hi ;]

4 ≤ -3x - 1 ≤ 9

-3x - 1 ≥ 4  / + 1

-3x ≥ 5  / : (-3)

x ≥ -⁵/₃

-3x - 1 ≤ 9  / + 1

-3x ≤ 10  / : (-3)

x ≤ -¹⁰/₃

Answer:

Parallel lines

Step-by-step explanation:

Answer:

angle 1 + angle 2 = ∠DEB

angle 7 + angle 8 = ∠NEG

angle 1 + angle 6 = ∠NEA

Answer:

False

Step-by-step explanation:

If the graph represented y = 2x + 1, then the y-intercept would be 1. The slope is correct(-ish), the y-intercept is not.

Answer:

7, 8, 9

Step-by-step explanation:

1/5 = 6/30

1/3 = 10/30

Answer:

[tex]a_7=40960x^{33}[/tex]

Step-by-step explanation:

Geometric sequence has explicit form:

[tex]a_n=a \cdot r^{n-1}[/tex] where [tex]a[/tex] is first term and [tex]r[/tex] is the common ratio.

First term here is [tex]a=10x^3[/tex] and [tex]r[/tex] could be found by doing second term divided by first term, [tex]\frac{40x^8}{10x^3}=4x^5[/tex].

Therefore the [tex]n[/tex]th term is given by

[tex]a_n=10x^3 \cdot (4x^5)^{n-1}[/tex].

So the [tex]7[/tex]th term is given by

[tex]a_7=10x^3 \cdot (4x^5)^{7-1}[/tex].

Let's simplify:

[tex]a_7=10x^3 \cdot (4x^5)^{7-1}[/tex]

[tex]a_7=10x^3 \cdot (4x^5)^{6}[/tex]

[tex]a_7=10x^3 \cdot (4^6(x^5)^6)[/tex]

[tex]a_7=10x^3 \cdot (4096x^30)[/tex]

[tex]a_7=40960x^{33}[/tex]

Hi

the slope is the part before. " X"

dont forget the sign !

have fun !

Answer:

5n+3

Step-by-step explanation:

:)

Answer:

[tex]\alpha n=5n+3[/tex]

Step-by-step explanation:

Answer:

11

Step-by-step explanation:

2^10 + 2^10 = 2^x

1024 + 1024 = 2^x

2,048 = 2^x

x = 11

If my answer is incorrect, pls correct me!

If you like my answer and explanation, mark me as brainliest!

-Chetan K

Hi there!  

»»————-　★　————-««

I believe your answer is:  

[tex]x = 11[/tex]

»»————-　★　————-««  

Here’s why:  

⸻⸻⸻⸻

[tex]\boxed{\text{Solving for 'x'...}}\\\\2^{10}+2^{10} = 2^x\\--------------\\\rightarrow 2^{10} = 1024\\\\\rightarrow 1024 + 1024 = 2^x\\\\\rightarrow 2048 = 2 ^x\\\\\rightarrow log(2^x)=log(2048)\\\\\rightarrow xlog(2)=log(2048)\\\\\rightarrow \frac{log(2)}{log(2)} =\frac{log(2048)}{log(2)}\\\\\rightarrow x = \frac{log(2048)}{log(2)}\\\\\rightarrow \boxed{x = 11}[/tex]

⸻⸻⸻⸻

»»————-　★　————-««  

Hope this helps you. I apologize if it’s incorrect.  

Answer:

Mid point of A(9,2) and B(6,44) is (7.5, -1)

Step-by-step explanation:

I. If mid point = [tex]\frac{x_{a} +x_{b} }{2}[/tex], [tex]\frac{y_{a}+ y_{b} }{2}[/tex]

 So (x) = (9 + 6) / 2 = 7.5

       (y) = (2 + (-4)) / 2 = -1

So (x,y) = (7.5, -1)        

Leave more question below, I don't understand you question well.