nen,
Problem: Two towns, A and B, located along the coast of the Pacific Ocean are 30
km apart on a north-south line. From a ship, the line of sight of town A is W30°N,
while that of town B is S400W.
1. How far is the ship from town A?
2. How far is the ship from town B?
​

Answer:

Its the first one | -9 | < | 9 |

Step-by-step explanation:

its false because both sides are identical

Hope this helps!

Answer:

Step-by-step explanation:

Answer:

1 inch= 20 miles. 5*20=100 miles. The answer is 100 miles.

Step-by-step explanation:

On these types of questions just do that every time, then you don't need to ask, for example:

1 foot = 50 miles

If it measures 3 feet.

3*50=150 miles.

If you have any questions regarding my answer, tell me in the comments, and I will answer them.

Answer:

[tex]5xy[/tex]

Step-by-step explanation:

[tex]\mathrm{Factor\:}:5x^2y[/tex]

[tex]5\cdot \:x\cdot \:x\cdot \:y[/tex]

[tex]\mathrm{Factor\:}:10xy^2[/tex]

[tex]2\cdot \:5\cdot \:x\cdot \:y\cdot \:y[/tex]

Common factor:-

[tex]5\cdot \:x\cdot \:y[/tex]

OAmalOHopeO

Answer:

Check the image

Answer:

Step-by-step explanation:

Bola will be 8 years old.

Let Bola's age be x

Dada's age be y

Ayo's age be z

If the sum of ages of Bola, Dada, and Ayo is 32 years, then;

x + y + z = 32

If they share a sum of money in the ratio of their ages, then the ratio of their ages will be x: y: z

Also if Bola gets N400, Dada get-N400 and Ayo get N800, then the total amount of money shared will be expressed as:

T = 400 + 400 + 800

T = N1600

Next is to get the age of Bola

[tex]\frac{age \ of \ bola}{32}* Total \ amount \ shared = Bola's \ Share[/tex]

Substitute the required variables and values into the formula;

[tex]\frac{x}{32}*1600= 400\\50x=400\\x=\frac{400}{50}\\x=8[/tex]

This shows that Bola is 8 years old

Learn more on ratio here: https://brainly.com/question/19473677

Answer:

[tex]C. \ \ \ 86[/tex]°

Step-by-step explanation:

1. Approach

In order to solve this problem, one must first find a relationship between arc (a) and arc (c). This can be done using the congruent arcs cut congruent segments theorem. After doing so, one can then use the secants interior angle to find the precise measurement of arc (a).

2. Arc (a) and arc (c)

A secant is a line or line segment that intersects a circle in two places. The congruent segments cut congruent arcs theorem states that when two secants are congruent, meaning the part of the secant that is within the circle is congruent to another part of a secant that is within that same circle, the arcs surrounding the congruent secants are congruent. Applying this theorem to the given situation, one can state the following:

[tex]a = c[/tex]

3. Finding the degree measure of arc (a),

The secants interior angle theorem states that when two secants intersect inside of a circle, the measure of any of the angles formed is equal to half of the sum of the arcs surrounding the angles. One can apply this here by stating the following:

[tex]86=\frac{a+c}{2}[/tex]

Substitute,

[tex]86=\frac{a+c}{2}[/tex]

[tex]86=\frac{a+a}{2}[/tex]

Simplify,

[tex]86=\frac{a+a}{2}[/tex]

[tex]86=\frac{2a}{2}[/tex]

[tex]86=a[/tex]

Answer:

182/3,3 8/3, 152/3

Step-by-step explanation:

a+b+c=124

a trừ c=  10

4b=c

Answer:

a=29,b=79,c=19

Step-by-step explanation:

a=c+10

b=4c

=> a+b+c=c+10+4c+c=124

=> c=19

=> a= 29, b=79

Answer:

B. 0

Step-by-step explanation:

Rate of change from x = -3 to x = 5

Rate of change = [tex] \frac{f(b) - f(a)}{b - a} [/tex]

where, from the graph, we have:

a = -3, f(a) = -1,

b = 5, f(b) = -1,

Plug in the values

Rate of change = [tex] \frac{-1 -(-1)}{5 - (-3)} [/tex]

Rate of change = [tex] \frac{0}{8} [/tex]

Rate of change = 0

A shape of a trapezoid has exactly one line of symmetry. The correct option is B.

An open, flat object with four straight sides and one pair of parallel sides is referred to as a trapezoid or trapezium.

A balanced and proportionate likeness between an object's two halves is referred to as symmetry in geometry. It implies that one half is the other's mirror image.

A trapezium's non-parallel sides are referred to as the legs, while its parallel sides are referred to as the bases. The legs of a trapezium can also be parallel. The parallel sides may be vertical, horizontal, or angled.

Therefore, the shape of a trapezoid has exactly one line of symmetry. The correct option is B.

To know more about Trapezoids follow

https://brainly.com/question/1410008

#SPJ5

Answer:

640

Step-by-step explanation:

muntiply all the number length width height

Answer:

16 once is the better one.

Answer: 12-ounce bag is better by $0.02 per ounce

Concept:

When coming across questions that ask for a comparison between prices, we should make the final unit [price per object].

In finding [price per object], simply do [Total price / number of objects].

Solve:

A 12-ounce bag of rice costs $4.08

Total price / number of objects = 4.08 / 12 = $0.34 per ounce

A 16-ounce bag of rice costs $5.76

Total price / number of objects = 5.76 / 16 = $0.36 per ounce

$0.36 - $0.34 = $0.02

$0.34 < $0.36, therefore, 12-ounce bag is better by $0.02 per ounce.

Hope this helps!! :)

Please let me know if you have any questions

Answer:

The right answer is:

(a) 0.1456

(b) 18.125, 69.1202, 8.3139

Step-by-step explanation:

Given:

N = 24

n = 5

r = 7

The improperly drilled gearboxes "X".

then,

⇒ [tex]P(X) = \frac{\binom{7}{x} \binom {17}{5-x}}{\binom{24}{5}}[/tex]

(a)

P (all gearboxes fit properly) = [tex]P(x=0)[/tex]

                                               = [tex]\frac{\binom{7}{0} \binom{17}{5}}{\binom{24}{5}}[/tex]

                                               = [tex]0.1456[/tex]

(b)

According to the question,

[tex]X = 91+5[/tex]

Mean will be:

⇒ [tex]\mu = E(x)[/tex]

       [tex]=E(91+5)[/tex]

       [tex]=9E(1)+5[/tex]

       [tex]=9.\frac{nr}{N}+5[/tex]

       [tex]=9.\frac{5.7}{24} +5[/tex]

       [tex]=18.125[/tex]

Variance will be:

⇒ [tex]\sigma^2=Var(X)[/tex]

         [tex]=V(9Y+5)[/tex]

         [tex]=81.V(Y)[/tex]

         [tex]=81.n.\frac{r}{N}.\frac{N-r}{N}.\frac{N-n}{N-1}[/tex]

         [tex]=81.5.\frac{7}{24}.\frac{24-7}{24}.\frac{24-5}{24-1}[/tex]

         [tex]=69.1202[/tex]

Standard deviation will be:

⇒ [tex]\sigma = \sqrt{69.1202}[/tex]

       [tex]=8.3139[/tex]      

Answer:

a) 75

b) 4.33

c) 0.75

d) [tex]3.2 \times 10^{-13}[/tex] probability that no one in a simple random sample of 100 young adults owns a landline

e) [tex]6.2 \times 10^{-61}[/tex] probability that everyone in a simple random sample of 100 young adults owns a landline.

f) Binomial, with [tex]n = 100, p = 0.75[/tex]

g) [tex]4.5 \times 10^{-8}[/tex] probability that exactly half the young adults in a simple random sample of 100 do not own a landline.

Step-by-step explanation:

For each young adult, there are only two possible outcomes. Either they do not own a landline, or they do. The probability of an young adult not having a landline is independent of any other adult, which means that the binomial probability distribution is used to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

[tex]P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}[/tex]

In which [tex]C_{n,x}[/tex] is the number of different combinations of x objects from a set of n elements, given by the following formula.

[tex]C_{n,x} = \frac{n!}{x!(n-x)!}[/tex]

And p is the probability of X happening.

The expected value of the binomial distribution is:

[tex]E(X) = np[/tex]

The standard deviation of the binomial distribution is:

[tex]\sqrt{V(X)} = \sqrt{np(1-p)}[/tex]

75% of all young adults between the ages of 18-35 do not have a landline in their homes and only use a cell phone at home.

This means that [tex]p = 0.75[/tex]

(a) On average, how many young adults do not own a landline in a random sample of 100?

Sample of 100, so [tex]n = 100[/tex]

[tex]E(X) = np = 100(0.75) = 75[/tex]

(b) What is the standard deviation of probability of young adults who do not own a landline in a simple random sample of 100?

[tex]\sqrt{V(X)} = \sqrt{np(1-p)} = \sqrt{100(0.75)(0.25)} = 4.33[/tex]

(c) What is the proportion of young adults who do not own a landline?

The estimation, of 75% = 0.75.

(d) What is the probability that no one in a simple random sample of 100 young adults owns a landline?

This is P(X = 100), that is, all do not own. So

[tex]P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}[/tex]

[tex]P(X = 100) = C_{100,100}.(0.75)^{100}.(0.25)^{0} = 3.2 \times 10^{-13}[/tex]

[tex]3.2 \times 10^{-13}[/tex] probability that no one in a simple random sample of 100 young adults owns a landline.

(e) What is the probability that everyone in a simple random sample of 100 young adults owns a landline?

This is P(X = 0), that is, all own. So

[tex]P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}[/tex]

[tex]P(X = 0) = C_{100,0}.(0.75)^{0}.(0.25)^{100} = 6.2 \times 10^{-61}[/tex]

[tex]6.2 \times 10^{-61}[/tex] probability that everyone in a simple random sample of 100 young adults owns a landline.

(f) What is the distribution of the number of young adults in a sample of 100 who do not own a landline?

Binomial, with [tex]n = 100, p = 0.75[/tex]

(g) What is the probability that exactly half the young adults in a simple random sample of 100 do not own a landline?

This is P(X = 50). So

[tex]P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}[/tex]

[tex]P(X = 50) = C_{100,50}.(0.75)^{50}.(0.25)^{50} = 4.5 \times 10^{-8}[/tex]

[tex]4.5 \times 10^{-8}[/tex] probability that exactly half the young adults in a simple random sample of 100 do not own a landline.

Answer:

Step-by-step explanation:

 L = 4 + w

A = 2P - 4

lw = 2(2l +2w) - 4

lw = 4(l + w) - 4

(w+4)w = 4 ( w+4+w) -4

(w +4)w = 4(2w + 4) - 4

w^2 + 4w = 8w + 16 - 4

w^2 + 4w = 8w + 12

w^2 - 4w - 12 = 0

( w      -       6 )( w  +       2  ) = 0

w - 6 = 0 ----> w = 6 ----> L=10  ---> P = 32  and A = 60

w + 2 = 0 ---> w = -2 <--- width cannot be negative; disqualified/rejected

Answer:

Hello,

[tex]\boxed{y'=2-\dfrac{200}{x^2} }\\[/tex]

Step-by-step explanation:

[tex](f(x)+g(x))'=f'(x)+g'(x)\\\\(2x)'=2*(x)'=2*1=2\\\\(\dfrac{200}{x} )'=200*(x^{-1})'=200*(-1)*x^{-1-1})=-\dfrac{200}{x^2} \\\\\\\boxed{y'=2-\dfrac{200}{x^2} }\\[/tex]

Answer:

[tex] \frac{dy}{dx } = 2 - \frac{200}{ {x}^{2} } [/tex]

Step-by-step explanation:

[tex]the \: equation \: can \: be \: rewriten \: as \\ y = 2x + 200 {x}^{ - 1} \\ \\ now \: differentiate \: the \: equation\ \\ \frac{dy}{dx} = 2 - 200 {x}^{ - 2} \\ \frac{dy}{dx} = 2 - \frac{200}{ {x}^{2} } [/tex]

Answer:

y = -1

Step-by-step explanation:

Part (a)

The standard error (SE) formula is

[tex]\text{SE} = \frac{\sigma}{\sqrt{n}}\\\\[/tex]

where n is the sample size. We're given SE = 2 and sigma = 34, so,

[tex]\text{SE} = \frac{\sigma}{\sqrt{n}}\\\\2 = \frac{34}{\sqrt{n}}\\\\2\sqrt{n} = 34\\\\\sqrt{n} = \frac{34}{2}\\\\\sqrt{n} = 17\\\\n = 17^2\\\\n = 289\\\\[/tex]

So we need a sample size of n = 289 to have an SE value of 2.

========================================================

Part (b)

We'll use SE = 1 this time

[tex]\text{SE} = \frac{\sigma}{\sqrt{n}}\\\\1 = \frac{34}{\sqrt{n}}\\\\1*\sqrt{n} = 34\\\\\sqrt{n} = 34\\\\n = 34^2\\\\n = 1156\\\\[/tex]

Because we require greater precision (i.e. a smaller SE value), the sample size must be larger to account for this. In other words, as SE goes down, then n must go up, and vice versa.

Answer:

Base = 21 while Height = 16

Answer:

-27

Step-by-step explanation:

Let x = 6 and y = -3

[tex]-(6)+7(-3)\\-6-21\\-27[/tex]

The ratio/proportion is young / old = young / old.

We know that one ratio is 3 / 5, so we need to complete the other.

3 / 5 = young / 40

5 goes into 40, 8 times, therefore we need to multiply the numerator by 8 also.

3 x 8 = 24

The younger student is 24 years old.

Hope this helps!

Answer:

24

Step-by-step explanation:

younger : older

3             :5

The older is 40

40/5 = 8

Multiply each by 8

younger : older

3 *8       :5 *8

24         : 40

The younger is 24

Answer:

[tex]x=2[/tex]

Step-by-step explanation:

[tex]\frac{3x-2}{7}-\frac{5x-8}{4}=\frac{1}{14}[/tex]

In order to factor an integer, we need to divide it by the ascending sequence of primes 2, 3, 5.

The number of times that each prime divides the original integer becomes its exponent in the final result.

In here,  Prime number 2 to the power of 2 equals 4.

[tex]\frac{3x-2}{7}-\frac{5x-8}{2^{2} }=\frac{1}{14}[/tex]

First, We need to add fractions-

Rule:-

[tex]\frac{A}{B} +\frac{C}{D} =\frac{\frac{LCD}{B}+\frac{LCD}{D}C }{LCD}[/tex]

LCD = [tex]7 \cdot 2^{2}[/tex]

[tex]\frac{4(3x-2)+7(-(5x-8))}{7*2^{2} } =\frac{1}{14}[/tex]

[tex]x=2[/tex]

OAmalOHopeO

Answer:

A. $15

B. $25

C. 84 peaches

Answer:

a)3dozenx$5=$15

b)60=5 dozen 5x$5=$25

c)35/5=7,7 dozen, 7 x 12= 84

Step-by-step explanation:

Answer:

2) Add 21 to both sides

Step-by-step explanation:

When solving [tex]16x-21=52[/tex] for [tex]x[/tex], our goal to isolate [tex]x[/tex] such that we have [tex]x[/tex] set equal to something.

Therefore, we want to start by adding 21 to both sides. This leaves us with [tex]16x=73[/tex] and we are one step closer to isolating [tex]x[/tex].

Answer:

1500000

Step-by-step explanation:

1 metre = 100 cm

15000metre =15000*100

=1500000

Answer:

[tex]x = y^3+5y[/tex]

Step-by-step explanation:

Complete question

[tex]\frac{x - 5y}{y^3} - 1=0\\[/tex]

Required

Solve for x

We have:

[tex]\frac{x - 5y}{y^3} - 1=0[/tex]

Collect like terms

[tex]\frac{x - 5y}{y^3} = 1[/tex]

Multiply through by [tex]y^3[/tex]

[tex]x - 5y = y^3[/tex]

Make x the subject

[tex]x = y^3+5y[/tex]

Answer:

72.47

Step-by-step explanation:

FV cos 43 = TV

FV (0.73135370161 ) = 53

FV = 72.468 = 72.47

Answer:

A

Step-by-step explanation:

Using the cosine ratio in the right triangle

cos43° = [tex]\frac{adjacent}{hypotenuse}[/tex] = [tex]\frac{TV}{FV}[/tex] = [tex]\frac{53}{FV}[/tex] ( multiply both sides by FV )

FV × cos43° = 53 ( divide both sides by cos43° )

FV = [tex]\frac{53}{cos43}[/tex] ≈ 72.47 ( to 2 dec. places )

Answer:

A computer parts company wants to make a rectangular memory board that has a perimeter of 28 centimeters and a diagonal length of 10 centimeters. Find the dimensions of the board. Consider the length to be the longer side.: Call the two sides L & W: the perimeter 2L + 2W = 28 Simplify, divide by 2 L + W = 14 L = (14-W); use this form for substitution

Step-by-step explanation:

==========================================================

Explanation:

x = width

y = length

both x and y are positive real numbers, and the units of which are in cm.

The perimeter of any rectangle is found by saying

P = 2*(length+width)

P = 2*(x+y)

Plugging in P = 14 leads us to

P = 2*(x+y)

14 = 2*(x+y)

14/2 = x+y

7 = x+y

Solve for one of the variables. Let's say we solve for y. That should get us y = 7-x which we'll use a bit later.

--------------

Notice how the diagonal forms two identical right triangles. The legs of which are x and y as defined earlier. The hypotenuse is 5, which is the diagonal length.

Use the pythagorean theorem to help solve for x

a^2 + b^2 = c^2

x^2 + y^2 = 5^2

x^2 + (7-x)^2 = 25 ... plug in y = 7-x

x^2 + 49 - 14x + x^2 = 25 ... use FOIL rule

2x^2-14x+49 = 25

2x^2-14x+49-25 = 0

2x^2-14x+24 = 0

2(x^2-7x+12) = 0

x^2-7x+12 = 0

(x-3)(x-4) = 0

x-3 = 0 or x-4 = 0

x = 3 or x = 4

If x = 3, then y = 7-x = 7-3 = 4

If x = 4, then y = 7-x = 7-4 = 3

We have this symmetry going on. If x is one of 3 or 4, then y is the other of those values. Because x = 3 and y = 4, or vice versa, this means we have a 3-4-5 right triangle (well to be fair we have two identical copies of such a triangle to form the rectangle).

Therefore, the dimensions of the rectangular board is 3 cm by 4 cm. The order doesn't matter so you could easily say "4 cm by 3 cm" to mean the same thing.

--------------

Check:

P = perimeter

P = 2*(length+width)

P = 2*(x+y)

P = 2*(3+4)

P = 2*7

P = 14

That helps confirm the answer.

9514 1404 393

Answer:

  C. EGD

Step-by-step explanation:

A major arc is typically named using the end points and a point on the arc. Here, the end points are E and D, and points on the major arc include C, G, and F. The major arc ED could be named any of

Of course, the reverse of any of these names could also be used: DCE, DGE, DFE.