need some help plsss!

Answer:

917 N

Explanation:

917 N, this is your answer!!

Glad to help.

Answer:

Its Friction

Explanation:

the pins are not floating and they are not a magnet and not involved with air

The force, in real life, that will have the least effect on a bowling ball rolling down a lane toward bowling pins is magnetism. The correct option is A.

Magnetism is basically the force which indeed magnets exert when they attract or even repel one another. The movement of electric charges resulting in magnetism.

Every substance is composed of tiny units referred to as atoms. Each atom contains electrons, which are charged particles.

To increase stability, the pins themselves have a low center of gravity. Because they are spherical in shape, they can roll and strike other pins in a variety of directions.

The force acting on the bowling ball is friction and air resistance. The friction force is equal to the friction coefficient multiplied by the normal force, and thus mass times acceleration.

Thus, the correct option is A.

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Explanation:

let v1 = 4.3 m/s

v2 = 12.9 m/s

t = 2 seconds

v2 = v1 + at

12.9 = 4.3 + a×2

2a = 12.9 - 4.3 = 8.6

a = 8.6/2

a = 4.3 m/s^2

The air pressure decrease with increasing altitude as less air above pushes down and the weight of the air above is smaller.

When altitude increases, the amount of gas molecules in the air also decrease.

The air becomes less dense than air nearer to sea level.

When the atmospheric pressure is high at lower altitudes, the density being higher.

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Answer:

6400km is the closest

Explanation:

When a substance is heated, it releases energy, which causes the particles to become more active, vibrating, rotating, and even moving faster. If a substance has enough energy, it can overcome the bonding forces that hold the particles together and change state as a result.

Answer:

deformation : elastic deformation is reversed when the force is removed. inelastic deformation is not fully reversed when the force is removed – there is a permanent change in shape.

Explanation:

tysm

reduction

deflation

these are examples of the opposite of enlarged to make something smaller is really the key thing here

Answer:

Acceleration due to gravity

Answer:

5250N

Explanation:

Weight= Mass × acceleration due to gravity

= 525kg × 10m/s^2

= 5250N

Answer:

Attracting means pulling toward you and repelling means pushing away

Explanation:

Answer: Repelling is when something will not connect with another object. The force will cause a repel between the two objects. Attracting is when something is attracted or being pulled to another object.

Explanation: Hope this helps!

Answer:

Explanation:

Given,

Let Alex be = x years

Then June will be = (7 + x) years

We know that,

Their total combined age is 29 years

Therefore,

By the problem,

=> x + (7 + x) = 29

=> 2x = 29 - 7

=> 2x = 22

=> x = 22 ÷ 2

=> x = 11

So,

Required age of June is = (7 + x) years

= (7 + 11) years

= 18 years (Ans)

Answer:

Give me some hint please

Answer:

Explanation:

Power is the rate of doing work

P = 72 / 1.2 = 60 Watts

Answer:

How do you find the net force?

Explanation:

i think this is want you asked for?

Answer:

Isometric exercises are static and great for people who suffer from joint pain. Isometric exercises, like planks, don't require you to move or bend any joints. Isotonic exercises, like squats, involve straining the muscles while moving the joints and applying a constant amount of weight.

Explanation:

Answer:

Isometric exercises are static and great for people who suffer from joint pain. Isometric exercises, like planks, don't require you to move or bend any joints. Isotonic exercises, like squats, involve straining the muscles while moving the joints and applying a constant amount of weight.

Explanation:

The conservation of momentum and energy allows to shorten the results for the movement of the girl on the trampoline holding the box are:

     a) the girl's speed is v = 4.98 m / s

     b) The speed of the girl + box system is: v_f = 0.996 m / s

     c) the maximum height is: y = 2.05 m

Kinematics studies the movement of bodies, looking for relationships between the position, velocity and acceleration of bodies.

The momentum is defined by the product of mass and the velocity, when a system is isolated the momentum is conserved.

The mechanical energy is the sum of the kinetic energy plus the potential energies, when there is no friction in the system the mechanical energy is conserved.

Let's solve this exercise in parts:

a) Let's use kinematics to find the speed of the girl before she grabs the box

              v² = v₀² - 2 g y₁

              v² = 8² - 2 9.8 2.00

              v = R 24.8 = 4.98 m / s

b) Let's use momentum conservation for when the speed of the girl and the box together. Let's write the moment in two moments.

Initial instant. Just before you grab the box.

              p₀ = M v + 0

Final moment. Right after taking the box

             [tex]p_f[/tex]  = (m + M) [tex]v_f[/tex]

In system this form by the girl and the box therefore it is an isolated system and the momentum is conserved.

           [tex]p_o = p_f[/tex]  

           mv = (m + M) [tex]v_f[/tex]  

           [tex]v_f = \frac{m}{m+M} \ v[/tex]

Let's calculate

           [tex]v_f = \frac{15}{15+ 60} \ 4.98[/tex]  

           [tex]v_f[/tex]  = 0.996 m / s

c) Now we use conservation of energy after the girl has the box.

Starting point. When the girl has the box

           Em₀ = K + U

           Em₀ = ½ (m + M) v² + (m + M) g y₁

Final point. At the highest point of the trajectory

          [tex]Em_f[/tex]  = U

         [tex]Em_f[/tex] = (m + M) g y₁

As there is no friction, the energy is conserved.

           [tex]Em_o = Em_f[/tex]  

          ½ (m + M) v² + (m + M) g y₁ = (m + M) g y

          y = [tex]\frac{v^2}{2g} + y_1[/tex]  

Let's calculate

           y = [tex]\frac{0.996^2}{2 \ 9.8} + 2.0[/tex]

           y = 2.05 m

In conclusion using the conservation of momentum and energy we can shorten the results for the movement of the girl on the trampoline holding the box are:

     a) the girl's speed is v = 4.98 m / s

     b) The speed of the girl + box system is: v_f = 0.996 m / s

     c) the maximum height is: y = 2.05 m

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Answer:

Vbefore = 4.98 m/s

Vafter = 3.98 m/s

Hmax = 2.81 m

Answer:

Antonie van Leeuwenhoek

Explanation:

Answer:30m east

Explanation: 45m-15m=30m, which cancels out the one to the west. All that is left is 30m east.

Is this a test/quiz btw?

Answer:

increase

Explanation:

As acceleration is the time rate of change of velocity

a = Δv/t

with t in the denominator, smaller time values result in greater acceleration values with constant velocity change.

Explanation:

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Answer:

Unchanged

Explanation:

horizontal projection always has initial vertical velocity equal to zero.

gravity works pretty much the same at any point on earth and will accelerate any falling object at the same rate traveling the same vertical distance in the same time. Neglecting air resistance of course.

By the way, Δy is read "delta y" not "angle y" which would be "∠ y"

delta represents a change in something, in this case the y coordinate.

The period of oscillation of the system nearest to three decimal places

= 1.092 seconds

The period of an oscillation occurring in a system is the time taken to complete one cycle.

The formula that is used to calculate the period of oscillation (T) is

                = 2π√[tex]\frac{l}{g}[/tex]

But,

π = 3.14159 (constant)

g= 10m/s² (acceleration due to gravity)

l = 0.302 m

Therefore T = 2 × 3.14159 × √[tex]\frac{0.302}{10}[/tex]

                    = 6.28318 x √0.0302

                    = 6.28318 x 0.17378

                    = 1.09189s

                    = 1.092 seconds ( to the nearest three decimal places)

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Answer:

it would be...

Explanation:

Answer:

F = E q

E = 2.18E-14 / 1.6E-19 = 1.36E5 N/C

The direction of the field will be the same as force on the proton - southerly

Answer:

Samples 2 and 4 are the same liquid

Explanation:

Samples 2 and 4 should be the same liquid because they have the same density as well as the same boiling point. The mass and volumes given do not matter in this case, however they could be used to calculate the density which was already given.

The liquid  present in sample 2 and 4 is same as according to forces of attraction they have same density and boiling points.

Forces of attraction is a force by which atoms in a molecule  combine. it is basically an attractive force in nature.  It can act between an ion  and an atom as well.It varies for different  states  of matter that is solids, liquids and gases.

The forces of attraction are maximum in solids as  the molecules present in solid are tightly held while it is minimum in gases  as the molecules are far apart . The forces of attraction in liquids is intermediate of solids and gases.

The physical properties such as melting point, boiling point, density  are all dependent on forces of attraction which exists in the substances.

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Using Kepler's third law, the average sun -Vesta distance is 2.36 AU.

According to Kepler's laws, the square of the period of revolution of planets are proportional to the cube of their average distances from the sun. Hence, we can write; [tex]T^{2} =r^{3}[/tex]

Where;

T = period of the planet

r = average distance of the planet

When;

T =  3.63 years

r = [tex]\sqrt[3]{T^2}[/tex]

r = [tex]\sqrt[3]{(3.63)^2}[/tex]

r = 2.36 AU

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Answer:

No, it is closer to 1.30

Explanation:

The horizontal distance traveled below the table's edge is 29.4 cm.

The given parameters;

The final velocity of the bullet-block system is calculated as follows;

[tex]m_1 u_1 + m_2u_1 = v(m_1 + m_2)\\\\0.015(630) + 4.9(0) = v(0.015 + 4.9)\\\\9.45 = 4.915 v\\\\v = \frac{9.45}{4.915} \\\\v = 1.923 \ m/s[/tex]

The time for the bullet-block system to reach the ground from the table is calculated as follows;

[tex]h = v_0t + \frac{1}{2} gt^2\\\\h = 0 + \frac{1}{2} gt^2\\\\h = \frac{1}{2} gt^2\\\\2h = gt^2\\\\t^2 = \frac{2h}{g} \\\\t = \sqrt{\frac{2h}{g} } \\\\t = \sqrt{\frac{2\times 0.75}{9.8} }\\\\t = 0.153 \ s[/tex]

The horizontal distance traveled below the table's edge is calculated as follows;

[tex]X = vt\\\\X = 1.923 \times 0.153\\\\X = 0.294 \ m\\\\X = 29.4 \ cm[/tex]

Thus, the horizontal distance traveled below the table's edge is 29.4 cm.

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