The correct arrangement on the basis of most to least concentration in troposphere will be: Cardon dioxide > Ozone > Carbon mono oxide > Hydroxyl radical.
In this lowest layer, the air is the densest. In actuality, the troposphere makes about 75 percent of the total weight of the atmosphere. The two most common gases are nitrogen (78%) and oxygen (21%), with argon (.9%) and a trace amount of hydrogen ozone (a kind of oxygen) making up the remaining 1% of all gases. The troposphere's temperature and water vapor concentration drop sharply with altitude.
Carbon monoxide background levels across the world vary from 0.06 to [tex]0.14 mg/m^3[/tex] (0.05– 0.12 ppm).
About 3 billion metric tons of ozone are present in the atmosphere as a whole. Even while that may seem like a lot, the atmosphere only makes up 0.00006 percent of it.
The concentration of hydroxyl radical is the minimum.
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1. Use the word bank to fill in the missing words in the sentences below. cathode non-spontaneous reduction acid anode coulomb electrolysis Faraday negative oxidation positive power source spontaneous (0/1pts) is the process of using electrical energy to cause a non-spontaneous reaction to occur. a. electrolysis (-1 pts) Incorrect (0/1pts) b. In an electrolytic cell oxidation occurs at the Choose... (-1 pts) Incorrect (0/1pts) c. In an electrolytic cell reduction occurs at the Choose... (-1 pts) Incorrect (0/1pts) d. In the electrochemical reaction studied today, H* from was reduced to hydrogen gas Choose... (0/1pts) e. When the total cell potential is a positive value, this indicates that the electrochemical reaction is power source (1 pts) Incorrect (0/1pts) f. The represents the amount of electrical charge carried by one mole of electrons. Faraday (-1 pts) Incorrect (0/1pts) g. The power source supplies the energy necessary for a reaction to Choose... occur. (-1 pts) Incorrect.
1. (a) Electrolysis Cause a non- is the process of using ·Spontane electrical energy to cause a non Spontane reaction to occur.
Explanation: direct current is to an electrochemical soupe cell, a reaction that is When normally nonspontaneous can be made to proceed the process is called electrolysis. energy provides electrons for carrying applied externally and The Source of electrical the reaction in a nonspontaneous direction.
1) b) Oxidation always occurs in Anode, in any cell, Whether it would be an electrochemical cell or a galvanic cell. The only difference is the charge, in electrochemical- The cell-cell anode is +vely charged and Cathode is the -ve charged.
so, in an Anode electrolytic cell Oxidation, occurs at the Anode
1) C) reduction always occurs in Cathode for all types of cells. In an electrolytic, all reduction occurs at Cathode
1)(d) Acid releases H+ in Solution, in electro- chemicaly reation, eg, Hcl → H⁺ + c H+ reduce at the cathode to form H₂ gas.
H+ e(⁻) -> 1/2 H2 (g) ↑ 60,
In the electrochemical reaction, studied today, H(+) from Acid Was reduced to hydrogen gas.
1(e) cell potential (E), Δve = - NFE Δve Gibbs Free energy, For Spontaneous reaction to occur, she has to be negative, There for E has to be positive
So, when the total cell potential is a positive value, this Indicates that the Positive electrochemical reaction is Positive.
1) (f) Faraday, represents the amount of electric charge Carried by one mole of electrons.
F (Faraday) = 96500 e/mol Number of electrons per mole, ie Avogrode number Charge of electron 6.023x1023 6.24 X1018 = 96500 C/mol F
1) g) when Δve of a reaction is positive, then the reaction becomes nonspontaneous, i.e. reaction does not occur spontaneously. Therefore we have to add that amount to the System energy that Can drive that reaction to occur.
So, The Power source supplies the energy necessary For a non-spontaneous reaction to occur.
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Identify each statement as True or False. a) The value of K_w applies to any aqueous solution, not just pure water b) Ions that appear on both sides of an equation but undergo no change in a reaction are called spectator ions. c) An aqueous solution containing an equal number of moles of NaF and HF in an aqueous solution is an example of a buffer solution. d) A solution containing a low concentration HCl is a weak acid.
Identify each statement as True or False a) True b) True c) True d) False Not just pure water, but all aqueous solutions are subject to the equilibrium constant Kw.
In pure water, the concentrations of the hydronium and hydroxide ions are identical, making the solution neutral. Based on how much they ionise in water, acids and bases are categorised as strong or weak. - Salt and water are typically produced when acids and bases react. When the amount of hydrogen ions and hydroxide ions are equilibrium in moles, neutralisation takes place. The weak acid neutralises the base when it is introduced to the mixture.
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which of the pairs of compounds below is most likely to form a solution when mixed? view available hint(s)for part a which of the pairs of compounds below is most likely to form a solution when mixed? heptane (c7h16) and acetonitrile (h3ccn) water and ammonia (nh3) sodium chloride (nacl) and pentane (c5h12) ammonia (nh3) and isooctane (c8h18)
Answer:
water and ammonia (nh3)
Explanation:
NH3 + H2O => NH4OH
place the steps for predicting the products of a rxn in order. question 2 options: balance the skeleton equation and add state symbols (when applicable) to create a complete balanced equation write all reactants in ion notation. bond all the ions, reactants and products, to produce a skeleton equation according to the pattern the reactants predict, move the ions only to the correct arrangement as products.
The products of a rxn in order:
1. Balance the skeleton equation and add state symbols (when applicable) to create a complete balanced equation
2. Write all reactants in ion notation.
3. Bond all the ions, reactants and products, to produce a skeleton equation
4. According to the pattern the reactants predict, move the ions only to the correct arrangement as products.
1. Balance the skeleton equation and add state symbols (when applicable) to create a complete balanced equation.
2. Write all reactants in ion notation.
3. Bond all the ions, reactants and products, to produce a skeleton equation.
4. According to the pattern the reactants predict, move the ions only to the correct arrangement as products.
For example, if the reactants are NH4+ and OH- and the predicted products are NH3 and H2O, the skeleton equation would be NH4+ + OH- --> NH3 + H2O.
The process of moving the ions to the correct positions would then be: NH4+ + OH- --> NH4OH --> NH3 + H2O.
5. Once the ions are in the correct positions, double check that the equation is balanced by counting the number of atoms on both sides of the equation (i.e. the number of nitrogen atoms must be the same on both sides, the number of hydrogen atoms must be the same on both sides, and the number of oxygen atoms must be the same on both sides).
6. Move the ions only to the correct arrangement as products: Move the ions to the correct positions to form the products of the reaction. Make sure that the number of atoms on each side of the equation are equal and the state.
7. If the equation is balanced, you have successfully predicted.
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write short note about acid nomenclature
Acids
There are various definitions for an acid. The simplest description of an acid is a chemical molecule with one or more hydrogen atoms that, when dissolved in water, gives forth hydronium ions (H3O+).
Because acids are molecular, they do not assume the expanded three-dimensional structures of ionic substances like NaCl and remain single molecules in their pure form. However, when these molecules are dissolved in water, a positively charged anion and a hydronium ion are produced as a result of the chemical connection between the hydrogen atom and the remainder of the molecule breaking. An equation involving chemicals can represent this:
HCl+H2O→H3O++Cl−
In an inorganic acid's formula, the H of the acid is written first. After the acid dissolves, the anion is all that is left of the acid (apart from the H). Although a significant class of chemicals, organic acids are not covered in this article.
Acid Names
Since all acids contain hydrogen, an acid's name is determined by the anion that it is associated with. These anions come in monatomic and polyatomic forms.
Binary acid names (in aqueous form)
An acid that contains hydrogen and another element is referred to as a binary acid. The majority of binary acids have a halogen in them. The prefix hydro- is used to start an acid name, which is then followed by the base name of the anion and the suffix -ic.
Oxyacids name
An oxyacid is an acid made up of three elements: hydrogen, oxygen, and another one. Typically, the third element is a nonmetal.
a) Oxyanions with the -ite end.
The anion's root is followed by the suffix -ous to form the name of the acid. No prefix is present.
b)Oxyanions that end in -ate.
The anion's root and the suffix -ic are used to identify the acid. No prefix is present.
In conclusion
Acids are molecular substances that discharge hydrogen ions.
The two elements hydrogen and the other make up a binary acid.
Hydrogen, oxygen, and another element are all present in oxyacids.
The anion that is bound to the hydrogen provides the basis for the acid's name.
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why should a magnesium ribbon be cleaned before burning in air?
which of the equations below can be used to solve for the temperature at which a reaction becomes spontaneous?Choose one: -(AG-AS) AH -(AG-AH) -(AG+AH) AS AG I AH - AS
The correct equation for solving for the temperature at which a reaction becomes spontaneous is AH - AS.
This equation is based on the equation for Gibbs Free Energy, which states that AG = AH - TS. In this equation, AG is the Gibbs Free Energy, AH is the enthalpy, T is temperature, and S is the entropy.
Therefore, if one knows the enthalpy and the entropy of a reaction, then one can calculate the temperature at which the reaction becomes spontaneous by subtracting the entropy from the enthalpy. This is because, at a given temperature, a reaction is spontaneous if the Gibbs Free Energy is negative.
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Calculate the molarity of each solution.
A) 38.2 g of KCl in 0.945 L of solution
Express your answer using three significant figures.
B) 64.3 g of C2H6O in 3.8 L of solution
Express your answer using two significant figures.
C) 36.2 mg of KI in 106 mL of solution
Express your answer using three significant figures.
In the first of two experiments, a student is assigned the task of determining the number of moles of water in one mole of MgCl2*nH2O. The student collects the data shown in the following table:
Mass of Empty Container-22.347g
Initial Mass of Sample and Container-25.825g
Mass of Sample and Container after first heating-23.982g
Mass of Sample and Container after second heating-23.976g
Mass of Sample and Container after third heating-23.977g
What I really want to know is how do I find the coefficient in front of H2O. Could you please supply the steps?
The number of moles of water lost when the sample was heated is 0.1026 mol. the formula of hydrated compound is MgCl₂.6H₂O.
When the sample is heated The total number of moles of water lost is given as :
mass of H₂O loss = 25.825 - 23.997
= 1.848 g
moles of H₂O = mass / molar mass
= 1.848 / 18
= 0.1026 mol
mass of anhydrous MgCl₂ = 23.977 - 22.347
= 1.630 g
moles of MgCl₂ = mass / molar mass
= 1.630 / 95.20
= 0.0171 mol
moles of H₂O per MgCl₂ = 0.1026 / 0.0171
= 5.99 = 6 mol
the formula of hydrated compound = MgCl₂.6H₂O
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As a means of distinguishing one individual from another through DNA typing, genetics focus on ______, which are non-coding regions of the DNA.
Genetics focus on short tandem repeats in the DNA, that are non-coding regions.
DNA is a genetic material of human beings, plants and animals. It serves an of carrying information for survival, growth, development, immunity, digestion, metabolism and other significant processes. Besides, it is unique among each individual and hence can be utilised for identification.
DNA typing or fingerprinting is known by several other names. At a specific locus, there repeated units of nitrogenous bases. However, the number varies which can be detected to identify the family relationship, parentage, identity and transplantation.
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If you are going to bake potatoes, and your potatoes are soft and dehydrated, they can be soaked in more firm before baking. Review to make them an isotonic solution a hypotonic solution such as tap water a hypertonic solution made with distilled water and a tablespoon of salt a hypertonic solution such as distilled wate
If you are going to bake potatoes, and your potatoes are soft and dehydrated, they can be soaked in hypotonic solution in a more firm before baking.
Before baking potatoes that are soft and dehydrated, it is important to give them a good soaking to make them firmer.
For this, a hypotonic solution such as salt water is preferred. Start by filling a large bowl with cold water and adding some salt. The salt will help to draw out moisture from the potatoes, making them firmer and more suitable for baking. Submerge the potatoes in the water and let them soak for at least 30 minutes.
Drain the water and pat the potatoes dry with a paper towel. This will remove any excess moisture and help them to crisp up when baking. You can then season the potatoes as desired and bake them as normal. The soaking process helps to rehydrate the potatoes, making them firmer and more suitable for baking.
The salt also helps to draw out moisture, so that when the potatoes are baked, they will be crisp on the outside and fluffy on the inside. The soaking process is an important step in preparing potatoes for baking, as it helps to make them firmer and more suitable for baking.
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AssertionDuring covalent bonding the electronegativity difference of two atoms is less than $$1.7$$ReasonCovalent bond is formed by sharing of electrons between atoms that have same sizeABoth Assertion and Reason are correct and Reason is the correct explanation for AssertionBBoth Assertion and Reason are correct but Reason is not the correct explanation for AssertionCAssertion is correct but Reason is incorrectDBoth Assertion and Reason are incorrect
C
A covalent bond occurs when atoms share one or more pairs of electrons to form a stable molecule. The difference in electronegativity between two atoms plays a role in determining the type of bond formed between them. In general, covalent bonds are formed between atoms with similar electronegativities.
A covalent bond can form between two atoms if the electronegativity difference between them is less than 1.7. However, the size of the atoms is not the determining factor in covalent bond formation. Instead, the atomic electron distribution and electron affinity are very important.
In general, covalent bonding is a key process in chemistry that allows atoms to form stable bonds with each other. It is a key factor in determining the properties of various chemical compounds such as gases, liquids and solids.
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Suppose the galvanic cell sketched below is powered by the following reaction: Mg(s)+PdSO4(aq) MgSO4(aq)+Pd(s) e- E1 E2 sí S2 Write a balanced equation for the half-reaction that happens at the cathode of this cell. Write a balanced equation for the half-reaction that happens at the anode of this cell. Of what substance is El made?
The complete balanced half-cell reaction is as follows:
Mg(s)+PdSO4(aq)---->MgSO4(aq)+Pd(s)
S1 solution= MgSO4 (magnesium sulfate) and S2 solution= PdSO4 (Palladium (II) sulfate)
A chemical reaction that takes place between an oxidizing substance and a reducing substance. The oxidizing substance loses electrons in the reaction, and the reducing substance gains electrons. Oxidation numbers, which are assigned to atoms in molecules by assuming that all bonds to the atoms are ionic. An increase in oxidation number during a reaction corresponds to oxidation, while a decreases corresponds to reduction.
Cathode: Pd^2+(aq)+2e- ---> Pd(s)
At cathode, reduction (gain of e- ) occurs.
At anode: Mg(s) ----> Mg^2+(aq)+2e-
Anode, oxidation (loss of e-) occurs
E1= Mg; (as left side of cell is anode)
E2= Pd; (as right side of cell is cathode)
S1 solution= MgSO4 (magnesium sulfate)
S2 solution= PdSO4 (Palladium (II) sulfate)
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A 59.4 g sample of polystyrene, which has a specific heat capacity of 1.880 J.g ·°C , is put into a calorimeter (see sketch at right) that contains 200.0 g of water. The temperature of the water starts off at 19.0 °C. When the temperature of the water stops changing it's 27.7 °C. The pressure remains constant at 1 atm. Calculate the initial temperature of the polystyrene sample. Be sure your answer is rounded to 2 significant digits.
The polystyrene sample weighs 57.3 grammes in total. We made the assumption in this case that the heat given off by the hot body is equal to the heat absorbed by the cold body temperature.
We made the assumption in this case that the heat given off by the hot body is equal to the heat absorbed by the cold body temperature.
where, = the polystyrene's specific heat
C = water's specific heat
T = polystyrene mass
M = 100.0 g of water mass
T1 is the system's end temperature, while I is the polystyrene's starting temperature.
F is the water's starting temperature.
The weight of the polystyrene is 59.6 g (mpmp).
Once you've entered all the values into the formula above, you'll obtain
Consequently, the polystyrene sample weighs 57.3 grammes.
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An industrially important element contains 26 electrons & 26 protons, rusts in the presence of air & moisture. Identify the element. A) Aluminum B) Iron C) Potassium D) Sodium
There are several variations of the Aldol reaction. Which of the following types ofreactants leads to only one possible product with the Aldol condensation reaction?A) Two different aldehydes with alfa-hydrogens are able to form a single aldolcondensation product.B) Two different ketones with alfa-hydrogens are able to form a single aldolcondensation product.C) Any aldehyde and ketone mixed together can react to form a single condensationproduct.D) Any pair of aldehyde or ketone reactants where one of the reactants has no alfa-hydrogens will lead to a single aldol product.
Option D; Any pair of aldehyde or ketone reactants where one of the reactants has no alfa-hydrogens will lead to a single aldol product.
Aldehydes are carbonyl compounds that are produced both naturally and artificially and are present everywhere in the environment. Aldehydes are reactive species, therefore naturally, they are hazardous to the body. Any member of the family of organic compounds known as an aldehyde contains a carbon atom that also shares a single bond with a hydrogen atom, a double bond with an oxygen atom, and a double bond with another atom or group of atoms (designated R in general chemical formulas and structure diagrams). All aldehydes have what is known as the carbonyl group, a double bond between carbon and oxygen. Many aldehydes have pleasant aromas, and in theory, they are created by dehydrogenating (removing hydrogen) alcohols, which is how the word "aldehyde" originated.
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An electron is released from rest in a uniform electric field of magnitude 2.0×10 4
N/C. Calculate the acceleration of the electron. ( Ignore gravitation.)
When an electron is released from rest in a uniform electric field of magnitude 2.0×10^4N/C the acceleration of the electron is 3.15x10^15m/s2.
Given the magnitude of electric field (E) = 2.0x10^4N/C
The magnitude of the force acting on the electron is F = qE where E is the magnitude of the electric field at its location and q is the charge of electron. q= 1.602x10-19C
From Newton's second law the acceleration of the electron: F = ma
where m is the mass of electron = 9.11x10-31kg
By comparing above two equations we have ma = qE
a = qxE/m = 1.602x10-19 x 2.0x10^4/9.11x10-31 = 3.51x10^15m/s2
Hence the acceleration of the electron = 3.51x10^15ms-2.
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certain types of cancer treatment involve chemicals that disrupt the formation of microfilaments. such chemicals most likely interfere with
Certain types of cancer treatment involve chemicals that disrupt the formation of microfilaments. such chemicals most likely interfere with the Formation of the mitotic spindle.
Chemotherapeutic drugs target cells in various stages of the cell cycle. Understanding how these drugs work helps doctors predict which drugs work well together. Physicians can also plan the frequency of administration of each drug based on cell-phase timing.
Drugs that inhibit mitosis appear to act through a common mechanism of suppressing microtubule dynamics and killing tumor cells. Paclitaxel and vinca alkaloids are the first class of antimitotic agents discovered to inhibit cancer cell growth. Microtubules residing in the cytoplasm begin to depolymerize more rapidly as cells pass through prophase.
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given these acids and their ka values, which sequence lists the corresponding anions in order of increasing base strength?
Instead, the ability of strong acids to liberate hydrogen atoms (H+) into a particular solution determines their classification.
A solution with a pH greater than 7.0 is referred to as a base. Any solution where the percentage of Hydroxide ions is higher than the percentage of H+ ions is said to be basic. While certain bases immediately take H+, others produce OH- ions instead, which then react with hydrogen to create water. Acid: A solution with too many H+ ions. The Latin name for it is acidus, meaning means "sharp" or "sour." Base: An overabundance of OH- ions in a solution. Alkali is another word for base. Aqueous: A primarily water-based solution. Acids enrich solutions with Hydrogen Ions (H+). Hydrogen ions (H+) & chloride ions are produced when hydrochloric (HCl) splits (Cl-).
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ordering vertices according to post-order and pre-order traversals. tree with root vertex d that has a left edge to f, a center edge to b, and a right edge to a. b has a left edge to i, a center edge to h, and a right edge to e. a has a center edge to c. c has a center edge to g. (a) give the order in which the vertices of the tree are visited in a post-order traversal. (b) give the order in which the vertices of the tree are visited in a pre-order traversal.
Preorder Traversal and Postorder Traversal of the tree with root vertex are given below:
Preorder Traversal
Let T be a rooted tree with root r that is ordered. If T only contains r, r is T's preorder traversal. Otherwise, suppose that T. T...., T., are the subtrees at r from left to right in T The pre- order traversal begins by visiting r. It continues by traversing T; in preorder, then T₂ in preorder, and so on, until 7, is traversed in preorder.
Postorder Traversal
Let 7' be an ordered rooted tree with root r. It consists only of r, then is the postorder traversal of T. Otherwise, suppose that T. T....T, are the subtrees at from left to right. The postorder traversal begins by traversing 7; in postorder, then T in postorder,.... then T. in postorder, and ends by visiting r.
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Show that you understand the concept of retrosynthetic analysis by working backwards two steps in the synthesis below. Identify possible combinations of A and B that can lead to the alkyne C):A) B-1 and A-VI B) B-VI and A-1 C) B-III and A-VII D) B-IV and A-VII E) B-1 and A-III F) B-VI and A-VIII
Retrosynthetic analysis is a method for resolving issues with organic syntheses' planning.
In order to accomplish this, a target molecule is converted into simpler precursor structures, regardless of any potential reagent reactivity or interaction. The same approach is used to investigate each precursor substance. Retrosynthesis involves "deconstructing" a target molecule into easily accessible building blocks by imagining bond breaks (disconnections) and changing one functional group into another (functional group interconversions). Chemical literature describes more than practical synthesis processes, each having potential applications and constraints. New techniques also emerge during the synthesis that can change the approach. Retrosynthetic analysis is a concept that was developed by Corey starting in the 1960s.
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During chemistry lab, one lab group decomposes potassium chlorate to collect oxygen gas by water displacement. The total volume is 220 milliliters and is collected at a pressure of 101 kPa at 24°C. The vapor pressure of water at 24°C is found to be 2.98 kPa.
What is the pressure of the oxygen collected?
A 104.28 kPa
B 101.20 kPa
C 98.2 kPa
D 98.02 kPa
According to Dalton's law of partial pressure, the pressure of the oxygen collected is 98.02 kPa.
What is pressure?Pressure is defined as the force applied on an object perpendicular to it's surface per unit area over which it is distributed.Gauge pressure is a pressure which is related with the ambient pressure.
There are various units by which pressure is expressed most of which are derived units which are obtained from unit of force divided by unit of area . The SI unit of pressure is pascal .
In this case, pressure of the oxygen collected is obtained by Dalton's law of partial pressure, as 101-2.98=98.02 kPa.
Thus, the pressure of the oxygen collected is 98.02 kPa.
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Do you think that solids can undergo convection? Explain.
Answer:
it's not possible for a solid material to transfer heat through convection.
Explanation:
This would require more movement within the material, than a solid is capable of.
This brings us to liquids and gases.
Can benzaldehyde hydrogen bond with water
Steam distillation cannot distinguish para hydroxy benzaldehyde from its ortho isomer because it has a higher boiling point and is more soluble in water.
Hydrogen bonds do benzaldehyde have?
We note a relationship between the advent of antiviral characteristics in the compounds and the presence of hydrogen bonds in the benzaldehyde molecules.
The intermolecular hydrogen bonds between the oxygen in the aldehyde and the water molecules as well as the acidic hydrogen from the OH group are present in meta benzaldehyde (B). As a result, the chemical has a higher chance of forming hydrogen bonds with water molecules.
(CH3)2C=O and CCl4 cannot create H-bonds with one another.
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You are working as a research assistant and the four bottles of the solutions needed for the experiment have no labels. The solutions are glucose, hexane, potassium iodide (KI) and ethanol. Using your understanding of physical and chemical properties, chemical reactions and macromolecules composition, design an experiment to determine the identity of the solution found in each bottle.
A chemical substance, pharmaceutical, and dietary supplement all refer to potassium iodide. A metal halide made of potassium and iodide with expectorant and thyroid-protecting effects is known as potassium iodide.
The potassium cation (K+) and the iodide anion form an ionic connection in the metal-halide salt known as potassium iodide (I–). It appears as cubical crystals, powder, or white granules and ranges in colour from colourless to white. It tastes quite salty and unpleasant. Iodine and potassium hydroxide are mixed to create this chemical.
Compounds contain elements in predetermined ratios.
Each compound has a certain set of characteristics.
Only chemical breakdown can separate compounds.
Compound particles only come in one type.
They are all the same, or homogenous.
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Formula fo chemical compound? Copper(1) hypochlorite
The structure of the Copper(1) hypochlorite is ClCuO.
What is the chemical formula?We know that the chemical formula has to do with the way that we are able to show the compound or indeed any other chemical specie on paper. In this case we have the compound that has been shown as Copper(1) hypochlorite.
It should be known that in the IUPAC nomenclature, the name of the compound must be such that we can be able to write the structure of the compound from the name of the compound. This is applied in writing the structure of any compound.
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what is the difference between tertiary alcohol and tertiary compaund
Answer:
Explanation:
TERTIARY ALCOHOL:
The alcohols where the carbon to which the hydroxide group is linked is 3 ' C carbon, as it has 3 alkyl groups attached to it.
TERTIARY COMPOUND:
A carbon attached to 3 other carbons is tertiary compound.
A large flask was found to contain 22.4 L of a gas. The gas turned out to be carbon dioxide. How many moles of carbon dioxide were in
the flask?
mol
Answer: 1 mol .
Explanation:
At STP ; 1 mol of a gas contains a volume of 22.4 L (liters).
the mass of a mixture containing both rice and navy beans was found to be 143.85 g. the rice grains were separated from the navy beans by putting the mixture through a large strainer (the small rice grains fell through the holes, the larger navy beans did not). the mass of the rice that separated out was 4.65 g. use the results of the above experiment to estimate the number of rice grains and navy beans in the mixture.
Based on the mass of the mixtures and the masses of the rice grains and the navy beans;
The number of grains of rice in the mixture is 160 grains
The number of navy beans in the mixture is 2282 navy beans
What is the mass of the heavy beans?The mass of the navy beans is obtained from the mass of the mixture of the rice and navy beans.
The mass of the navy beans is obtained using the formula below:
Mass of navy beans = mass of mixture - mass of the rice grains
The mass of the mixture of the rice and navy beans = 143.85 g
The mass of the rice grains = 4.65 g
assuming the mass of a single grain of rice is 0.029 grams
The number of grains of rice = 4.65 / 0.029
The number of grains of rice in the mixture = 160 grains
Assuming the mass of a single navy bean is 0.0601 g
The number of navy beans = (143.85 - 4.65) / 0.061
The number of navy beans = 2282 navy beans
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Suppose the galvanic cell sketched below is powered by the following reaction: Mg(s)+ SnSO 4(aq) → MgSO4(aq)+ Sn(s) er E1 E2 S1 S2 Write a balanced equation for the half-reaction Write a balanced equation for the half-reaction that happens at the anode of this cell Of what substance is E1 made? Of what substance is E2 made? What are the chemical species in solution S1? What are the chemical species in solution S2?
The balanced chemical equation is, Mg(s)+ SnSO4 (aq.) → MgSO4(aq.)+ Sn(s) .
The half cell reactions are, Sn2+(aq.) + 2e- -----> Sn(s) and Mg(s) ----> Mg2+(aq.) + 2e-
A Half cell reaction is expressed either as an oxidation reaction in which electrons are lost or a reduction reaction where electronic are gained. The reactions occur in an electrochemical cell in which the electrons are lost at the anode through oxidation and consumed at the cathode where the reduction occurs. Half-cell reactions are useful in galvanic and voltaic cells in which the electrons flow from the anode to the cathode through an electrolyte to produce an electromotive force (EMF).
Half cell Reaction at cathode : Reduction
Sn2+(aq.) + 2e- -----> Sn(s)
Half- cell reaction at anode : Oxidation
Mg(s) ----> Mg2+(aq.) + 2e-
E1 is made of Mg
E2 is made of Sn
Chemical species in solution S1 are Mg2+ and SO42- .
Chemical species in solution S2 are Sn2+ and SO42-
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