Molly and Lynn both set aside money weekly for their savings. Molly already has $650 set aside and adds $35 each week. Lynn already has $825 set aside but adds only $15 each week. Which inequality could they use to determine how many weeks, w, it will take for Molly’s savings to exceed Lynn’s savings?
Answers
FINAL ANSWER: D
Given : Molly and Lynn both set aside money weekly for their savings.
Molly already has $650 set aside and adds $35 each week.
Lynn already has $825 set aside but adds only $15 each week.
To Find : inequality to determine how many weeks, w, it will take for Molly’s savings to exceed Lynn’s savings
Solution:
Molly already has $650
adds $35 each week.
=> added in w weeks = 35w
After w weeks = 650 + 35w
Lynn already has $825
adds $15 each week.
added in w weeks = 15w
After w weeks = 825 + 15w
Molly’s savings to exceed Lynn’s savings
⇒ 650 + 35w > 825 + 15w
⇒ 20w > 175
⇒ 4w > 35
⇒ w > 35 /4
At least 9 weeks
Answer:
D
Step-by-step explanation:
First, to eliminate some answers you can figure out which way the sign should go. The question wants to know when Molly's savings will be larger so the sign should open towards her side of the equation. Since her savings are represented on the left the sign should be a greater than, >.
Then, figure out where the variables belong. The variable represents the number of weeks that have passed, so they should be multiplied by the number that is affected by the passing of weeks. This is the amount each person saves, aka the independent variable. So the "w" variable should be next to the 35 and 15.
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Step-by-step explanation:
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2x-2+x+2x-2+x=3+7+3+7
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Answers
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Answers
Answer:
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Step-by-step explanation:
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16/4 = 18/y
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What is an exponential function ?An exponential function is where the independent variable is in the exponent. Generally the the independent variable is in the power of a constant term e.
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In the given question f(x) = 8e⁻ˣ
when, x = 0 f(x) = 8
f(x) = 8e⁻ˣ
f(0) = 8e⁰
f(0) = 8
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PLEASE HELP! 50 POINTS
Identify the intervals on which the function is increasing, decreasing or constant. Write your answers in interval notation. Write the end behavior for each function in limit notation.
f(x)=-4x^4+3x^3-2x^2+x-9
(Type a 0 before the decimal to hold the ones place for answers that don't have a value in the ones place. Ex. 0.24)
Use inf for infinity
Answers
2. Page 3. Practice: Use your calculator to sketch a graph of each
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Answers
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[tex]x^4+8x^3-10x^2-104x-192=0[/tex]
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[tex]x-4=0\implies\boxed{x_1=4}[/tex]
[tex]x+8=0\implies\boxed{x_2=-8}[/tex]
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[tex]x^2+4x+4=-2[/tex]
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Answer:
x=4
Step-by-step explanation:
(4-1)(4-3)(4+5)(4+7)=297
3. (02.01)
Solve for x:
wim
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2
-2
-8
-4
Answers
x = -4
Step-by-step explanation:
(x - 4) = 2x
We need an x that when is subtracted by 4 is equal to multiplying it by 2
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(-8) = (-8)
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Answers
Answer:
It will be 31.4 cm rounded off for circumference
It will be 78.53 cm2 rounded off for area
Step-by-step explanation:
Diameter = 10 cm
Radius = 10/2 cm = 5 cm
Circumference = 2×pi×radius
= 2pi×5
= 31.4 cm
Area = pi × r square
= 25 pi
= 78.53cm2
HaLP a beggar in need
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Answer:
C) 2
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Answers
d/dx(3x^2+5x^4-10)
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=6x+20x^3, which is your desired answer
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Answers
9514 1404 393
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(a) The blue line ... solution ... (-6, -2)..
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The second equation describes a line with negative slope and a y-intercept of -4. This is clearly the red line on the graph.
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Answers
Answer:
f(x) = 3ex - e
Step-by-step explanation:
In this equation we have basically the times e by 3x and -1
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here...
e X 3x = 3ex
so let's rewrite the equation
3ex - 1
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3ex - 1e
we don't have to write 1e cause 1e = e, they are the same.
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Given:
[tex]\to f(x)=e^{3x-1}[/tex]
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inverse function=?
Solution:
A function g is the inverse of function F if for [tex]y=f(x), x=g(y)[/tex]
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Answers
Answer:
2(w+3)
Step-by-step explanation:
2(w+3) or 2w+6
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Round your answer to the nearest whole number (percent).
Answers
Answer:
95%
Step-by-step explanation:
Mean , xbar = 64.3; standard deviation, s= 2.4
Using the empirical formula where ;
68% of the distribution is within 1 standard deviation from the mean ;
95% of the distribution is within 2 standard deviation from the mean
percent of heights that lie between 59.5 inches and 69.1 inches.
Number of standard deviations from the mean /
Z = (x - μ) / σ
(x - μ) / σ < Z < (x - μ) / σ
(59.5 - 64.3) / 2.4 < Z < (69.1 - 64.3) / 2.4
-2 < Z < 2
Thia is within 2 standard deviations of the means :
2 standard deviation form the mean = 95% according to the empirical rule.
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Answers
Answer:
-33
Step-by-step explanation:
-p/3-8=3
or,(-p-24)/3=3
or,(-p-24)=9
or,-p=33
Therefore, p=-33
I'm stuck. Can anyone help please?
Answers
log₉(x - 7) + log₉(x - 7) = 1
2 log₉(x - 7) = 1
log₉(x - 7) = 1/2
Take the base-9 antilogarithm of both sides; in other words, make both sides powers of 9:
[tex]9^{\log_9(x-7)} = 9^{1/2}[/tex]
[tex]9^{1/2}[/tex] can also be written as √9 = 3, and [tex]b^{\log_b(a)}=a[/tex], so the equation reduces to
x - 7 = 3
Solve for x :
x = 10
Suppose a certain study reported that 27.7% of high school students smoke.
Random samples are selected from high school that has 632 students.
(i) If a random sample of 60 students is selected, what is the probability that
fewer than 19 of the students smoke?
(ii) If a random sample of 75 students is selected, what is the probability that
more than 17 of the students smoke?
Answers
The correct answer of the question is "0.7062" and "0.835". The further solution is provided below.
Given:
Probability of student smoke,
P = 27.7%
= 0.277
Number of students (n) = 632
[tex]q = 1-p[/tex]
[tex]=1-0.277[/tex]
[tex]=0.723[/tex]
(i)
Here,
Number of students (n) = 60
then,
⇒ [tex]n_P=60\times 0.277[/tex]
[tex]=16.62[/tex]
⇒ [tex]n_q=60\times 0.723[/tex]
[tex]=43.38[/tex]
We can see that [tex]n_P > 10[/tex] and [tex]n_q>10[/tex] so the normal approximation condition are met.
Now,
[tex]\mu = n_P= 16.62[/tex]
[tex]\sigma = \sqrt{n_{Pq}}[/tex]
[tex]= \sqrt{60\times 0.277\times 0.723}[/tex]
[tex]=3.9664[/tex]
Now,
⇒ [tex]P(X<19) = P(X<18.5)[/tex]
[tex]=P(Z_{18.5})[/tex]
The Z-score is:
= [tex]\frac{18.5-16.62}{3.4664}[/tex]
= [tex]0.5423[/tex]
hence,
The probability will be:
⇒ [tex]P(Z_{18.5}) = 0.7062[/tex]
or,
⇒ [tex]P(Z<19) = 0.7062[/tex]
(ii)
Here,
Number of students (n) = 75
[tex]\mu = n_P = 75\times 0.277[/tex]
[tex]=20.775[/tex]
[tex]\sigma = \sqrt{n_{Pq}}[/tex]
[tex]=\sqrt{75\times 0.277\times 0.723}[/tex]
[tex]=3.8756[/tex]
Now,
⇒ [tex]P(X>17) = P(X> 17.5)[/tex]
[tex]=1-P(X \leq 17.5)[/tex]
[tex]=1-P(Z_{17.5})[/tex]
The Z-score is:
= [tex]\frac{17.5-20.775}{3.8756}[/tex]
= [tex]-0.9740[/tex]
then, [tex]P(Z_{17.5}) = 0.165[/tex]
hence,
The probability will be:
⇒ [tex]P(X>17) = 1-0.165[/tex]
[tex]=0.835[/tex]
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A population of values has a normal distribution with μ= 180.1
and σ=100. You intend to draw a random sample of size n=94
What is the mean of the distribution of sample means?
What is the standard deviation of the distribution of sample means?
(Report answer accurate to 2 decimal places.)
Answers
A sample of size n taken from a normally distributed population with mean µ and standard deviation σ has a sample mean of µ and standard deviation of σ/√n.
So the sample mean would still be 180.1, while the sample standard deviation would be 100/√94 ≈ 10.31.
multiply 631.6 by 0.8
Answers
Answer: multiply 631.6 by 0.8 = 505.28
What is the next fraction in each of the following patterns? a. 1⁄40, 4⁄40, 9⁄40, 16⁄40, 25⁄40 . . .? b. 3⁄101, 4⁄101, 7⁄101, 11⁄101, 18⁄101, 29⁄101 . . .? c. 5⁄1, 10⁄2, 9⁄2, 18⁄4, 17⁄8, 34⁄32, 33⁄256 . . .?
Answers
Answer:
a.
[tex] \frac{36}{40} [/tex]
What is the purpose for post tests?
Answers
Answer:
The real reason of post test is to measure it's result in comparison to a pre test and determine d how much student has progressed over a term of instruction.
The decimal for an irrational number never terminates or repeats. The
rational and irrational numbers together form the set of real numbers.
If false, explair:
Answers
Answer:
Step-by-step explanation:
No that is true. I can't make anything more out of it.
A rectangle has a length of 38 meters less than 8 times its width. If the area of the rectangle is 4050 square meters, find the length of the rectangle.
Answers
Let
width be x Length=8x-38Area=4050m^2We know
[tex]\boxed{\sf Area =Length\times Width}[/tex]
[tex]\\ \sf\longmapsto x(8x-38)=4050[/tex]
[tex]\\ \sf\longmapsto 8x^2-38x=4050[/tex]
[tex]\\ \sf\longmapsto 8x^2-38x-4050=0[/tex]
By solving[tex]\\ \sf\longmapsto x=\dfrac{81}{4}\:or\:x=25[/tex]
Take x as 25[tex]\\ \sf\longmapsto Length=8x-38=8(25)-38=200-38=162m[/tex]
