Mathematics I need help

9514 1404 393

Answer:

  A)  collinear

Step-by-step explanation:

"Parallel" and "perpendicular" are descriptors of pairs of lines and planes. They do not apply to pairs of points.

The two points have different coordinates, so are distinct, rather than coincident.

Of these words, the only applicable choice is "collinear."

__

Additional comment

Any pair of distinct points is collinear. Two points define a line, and two points on the same line are collinear.

We can conclude that if (c, f(c)) is a point of inflection of the graph of f and f'' exists in an open interval that contains c, then f''(c)=0.

The process of finding derivatives of a function is called differentiation in calculus. A derivative is the rate of change of a function with respect to another quantity.

We can prove this statement using the First Derivative Test and Fermat's Theorem.

First, we know from the First Derivative Test that at a point of inflection, the first derivative of the function (in this case, f') must equal 0. Therefore, at the point (c, f(c)), f'(c) = 0.

Next, we can apply Fermat's Theorem. This theorem states that if a function f has a local maximum or minimum at c, then f'(c) = 0. Since the point (c, f(c)) is a point of inflection, we can apply Fermat's Theorem to say that f'(c) = 0.

Now, since f'' exists in an open interval that contains c, we can use the fact that if f'(c) = 0, then f''(c) = 0.

Therefore, we can conclude that if (c, f(c)) is a point of inflection of the graph of f and f'' exists in an open interval that contains c, then f''(c)=0.

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Answer:

Hello,

Answer

[tex]\sigma=457,95...[/tex]

Step-by-step explanation:

p(z<a)=0.9

p(z<1.29)=0.9015

p(z<1.28)=0.8997

using linear interpolation: with 4 decimals

p(z<1.282)<0.9

[tex]\dfrac{1628-1500}{\sigma} =1.282\\\\\sigma =\dfrac{1628-1500}{1.282}\\\\\sigma=457,95...\\[/tex]

Answer:

Step-by-step explanation:

Answer:

c

Step-by-step explanation:

Since the the identities of the survey takers were kept secret, it would be anonymous. If it wasn't anonymous, then people would know who took the survey.

Since the survey results were released online for analyses, it is not confidential. If it were to be confidential, then the survey distributors would have kept the results to themseles.

Answer:

D.

Step-by-step explanation:

.

The number of planes that can be drawn that pass through point A is 1.

A perpendicular line creates an angle of 90° with a line or a plane. If a line exists to be drawn from a point to a line or a plane it can only be one. In this case, a line exists to be drawn through a point A to a plane P. If the line stands to be perpendicular, then it exists only one.

Therefore, the correct answer is option D. 1.

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what

Step-by-step explanation:

pretty sure its 25 percent

Answer:

25%

Step-by-step explanation:

if you take half of 50 it is 25 so all of it is used or 25%

Hope this helps <3 Comment if you want more thanks and be sure to give brainliest (4 left) <3

Step-by-step explanation:

Ru Tu yulyryosuyyyhlsgjpcbmb kvjvlcykxnlvdlbvhck

chgkbhlxyovk m.

chchhlzixhvkh

Answer:

it is important because the number of people who are infected by the disease is rising

Answer:

8:6

or

4:3

Step-by-step explanation:

Answer:

what this makes bi sense haha

Step-by-step explanation:

but ok

Answer:

The answer is 8

Step-by-step explanation:

Answer:

8

Step-by-step explanation:

2/5x-8/5y+x+½y

2/5(1)-8/5(-6)+1+½(-6)

2/5+48/5+1-3

10-2

8

HOPE SO IT HELPS YOU

Answer:

Isosceles.

Step-by-step explanation:

It's an isosceles triangle because 2 sides  are congruent ( 2 are 23 yds long).

I think its C: 2 hours. sry if its wrong

Answer:

15 more were sold on friday then thursday

Step-by-step explanation:

Answer:

D) 50% of the students surveyed spend at least two hours online each day.

50% of the students surveyed spend at least two hours online each day.

Hence option d is correct.

Given that,

Number of students who spend at least two hours online = 100

Total number of students surveyed = 200

To calculate the percentage of students who spend at least two hours online each day,

we can use the formula:

percentage = (number of students who spend at least two hours online / total number of students surveyed) x 100%

Plugging in the values from the problem, we get:

percentage = (100 / 200) x 100% = 50%

Therefore, we can conclude that 50% of the students surveyed spend at least two hours online each day.

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Step-by-step explanation:

KI=yf/p+n + yr/u

(p+n) KI - yrp/u -yrn/u = yf

pKI - yrp/u = yf - nKI + yrn/u

p(KI - yr/u) = yf - nKI + yrn/u

p = (1/KI-yr/u)(yf-nKI+yrn/u)

Answer:

17 don't play any

Step-by-step explanation:

12+9+8+4=33

33-50=17

Answer:

Step-by-step explanation:

new length=15+x

width=19+x

then area=(15+x)×(19+x)=285+15x+19x+x²=x²+34x+285 ft²

original area=15×19=285 ft²

then 285+98=x²+34x+285

or

x²+34x-98=0

x²+34x+17²=98+17²

(x+17)²=98+289=387

x+17=√387=3√43

x=3√43-17 ft

Answer:

i dont know lol

Step-by-step explanation:

[tex]\huge\text{Hey there!}[/tex]

[tex]\mathsf{\dfrac{9}{10}+\dfrac{7}{15}}[/tex]

[tex]\large\textsf{FIRST: FIND the LCD (Lowest Common Denominator) then solve}\\\large\textsf{from there!}[/tex]

[tex]\large\textsf{If you have calculated it correctly, you should have came up with \underline{\bf 30}}\\\large\textsf{as your LCD (Lowest Common Denominator).}[/tex]

[tex]\mathsf{= \dfrac{9\times3}{10\times3}+ \dfrac{7\times2}{15\times2}}[/tex]

[tex]\mathsf{9\times3=\bf 27}\\\mathsf{10\times3=\bf 30}\\\\\mathsf{7\times2=\bf 14}\\\mathsf{15\times2=\bf 30}[/tex]

[tex]\mathsf{= \dfrac{27}{30}+\dfrac{14}{30}}[/tex]

[tex]\mathsf{= \dfrac{27+14}{30}}[/tex]

[tex]\mathsf{27+ 14=\bf 41}\\\\\mathsf{30+0=\bf 30}[/tex]

[tex]\mathsf{= \dfrac{41}{30}}\large\textsf{ which you could convert to }\mathsf{1 \dfrac{11}{30}}[/tex]

[tex]\boxed{\boxed{\large\textsf{ANSWER: }\bf \dfrac{41}{30} \large\textsf{ or }\mathsf{\bf 1 \dfrac{11}{30}\large\textsf{ because they both equal the same thing}}}}}\huge\checkmark[/tex]

[tex]\large\text{Good luck on your assignment and enjoy your day!}[/tex]

~[tex]\frak{Amphitrite1040:)}[/tex]

Answer:

Since [tex]n(1-p) = 3.72 < 10[/tex], the normal curve cannot be used as an approximation to the binomial probability.

100% probability that greater than 26 out of 124 software users will call technical support.

Step-by-step explanation:

Test if the normal curve can be used as an approximation to the binomial probability by verifying the necessary conditions.

It is needed that:

[tex]np \geq 10[/tex] and [tex]n(1-p) \geq 10[/tex]

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

[tex]P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}[/tex]

In which [tex]C_{n,x}[/tex] is the number of different combinations of x objects from a set of n elements, given by the following formula.

[tex]C_{n,x} = \frac{n!}{x!(n-x)!}[/tex]

And p is the probability of X happening.

Can be approximated to a normal distribution, using the expected value and the standard deviation.

The expected value of the binomial distribution is:

[tex]E(X) = np[/tex]

The standard deviation of the binomial distribution is:

[tex]\sqrt{V(X)} = \sqrt{np(1-p)}[/tex]

Normal probability distribution

Problems of normally distributed distributions can be solved using the z-score formula.

In a set with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the z-score of a measure X is given by:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

When we are approximating a binomial distribution to a normal one, we have that [tex]\mu = E(X)[/tex], [tex]\sigma = \sqrt{V(X)}[/tex].

Out of 124 software users

This means that [tex]n = 124[/tex]

Assume the probability that a given software user will call technical support is 97%.

This means that [tex]p = 0.97[/tex]

Conditions:

[tex]np = 124*0.97 = 120.28 \geq 10[/tex]

[tex]n(1-p) = 124*0.03 = 3.72 < 10[/tex]

Since [tex]n(1-p) = 3.72 < 10[/tex], the normal curve cannot be used as an approximation to the binomial probability.

Consider the probability that greater than 26 out of 124 software users will call technical support.

The lowest possible probability of those is 27, so, if it is 0, since it is considerably below the mean, 100% probability of being greater. We have that:

[tex]P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}[/tex]

[tex]P(X = 27) = C_{124,27}.(0.97)^{27}.(0.03)^{97} = 0[/tex]

1 - 0 = 1

100% probability that greater than 26 out of 124 software users will call technical support.

Answer:

I don't understand the first question  with " र" ???

Step-by-step explanation:

b)

1)

f(x)=x and g(x)=(2x-3)^5 so (fog)(x)=g(f(x))=g(x)=(2x-3)^5

2)

f(x)=x^5 and g(x)=2x-3 so (fog)(x)=g(f(x))=g(x^5)=(2x-3)^5

Answer:

https://linksharing.samsungcloud.com/ul5cX9oOmhzt

Answer: (3a + 1) (a + 3)

Step-by-step explanation:

Concept:

Here, we need to know the idea of factorization.

It is like "splitting" an expression into a multiplication of simpler expressions. Factoring is also the opposite of Expanding.

Solve:

Given = 3a² + 10a + 3

STEP ONE: separate 3a² into two terms

3a

a

STEP TWO: separate 3 into two terms

3

1

STEP THREE: match the four terms in ways that when doing cross-multiplication, the result will give us 10a.

3a     1

a       3

When cross multiply, 3a × 3 + 1 × a = 10a

STEP FOUR: combine the expression horizontally to get the final factorized expression.

3a  ⇒   1

a   ⇒    3

(3a + 1) (a + 3)

Hope this helps!! :)

Please let me know if you have any questions

Answer:

I don't know ans OK bro because I can't understand your language what are you writing

Answer:

answer is 0.4

Step-by-step explanation: