Match the name of each gas law to the properties it compares. (3 points)
1. Boyle's law
2. Avogadro's law
3. Gay-Lussac's law
a. Volume and moles
b. Pressure and volume
c. Pressure and temperature

Answer:

2.7 °C.kg/mol

Explanation:

Step 1: Calculate the freezing point depression (ΔT)

The normal freezing point of a certain liquid X is-7.30°C and the solution freezes at -9.9°C instead. The freezing point depression is:

ΔT = -7.30 °C - (-9.9 °C) = 2.6 °C

Step 2: Calculate the molality of the solution (b)

We will use the following expression.

b = mass of solute / molar mass of solute × kilograms of solvent

b = 102. g / (162.2 g/mol) × 0.650 kg = 0.967 mol/kg

Step 3: Calculate the molal freezing point depression constant Kf of X

Freezing point depression is a colligative property. It can be calculated using the following expression.

ΔT = Kf × b

Kf = ΔT / b

Kf = 2.6 °C / (0.967 mol/kg) = 2.7 °C.kg/mol

Answer:

sim eu também preciso desta respota

An ether and alkene are formed as by products in the reaction which is a electrophilic addition reaction.

An addition reaction known as an electrophilic addition reaction occurs when a chemical molecule having a double or triple bond has one of its bonds broken and two new bonds are formed. The interconversion of C=C and CC into a variety of significant functional groups, such as alkyl halides and alcohols, is made possible via the key.

The following describes the general mechanism: Hydrogen bromide produces an electrophile, H+, which attacks the double bond to create a carbocation. The production of ions is dominated by secondary carbocation because it is more stable than primary carbocation.

Thus, an ether and alkene are formed as by products in the reaction which is a electrophilic addition reaction.

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Solution :

  Term                                                                      Best description

Eriochrome Black T                                                          EBT

Starting color, before titration                               Pale purple-pink color

Molecule that has a high affinity for metal ions       Chelating agent

Ethylenediaminetetracetic acid                                    EDTA

Color at the completion of titration                           Blue-gray color    

Answer:

See explanation

Explanation:

Conformation refers to the various spatial arrangements of atoms in a molecule that result from free rotation across the carbon-carbon single bond.

There are two possible conformations of cyclohexane. They are; the chair and boat conformations.

We can convert the molecule from one conformation to another by rotation of single bonds.

These conformations are not isomers. Isomers are different molecules while conformers are different spatial arrangements of the same molecule obtained by rotation across carbon-carbon single bonds. Isomers are not obtained by rotation across carbon-carbon single bonds.

Hence, the chair and boat conformers of cyclohexane are obtained by rotation across the carbon-carbon single bond hence they are conformers and not isomers.

Answer:

HCl  is a acid

Explanation:

NaOH is base

Nacl is salt

Answer:

Compare the solubility of silver chloride in each of the following aqueous solutions:

a. 0.10 M AgNO3 More soluble than in pure water.

b. 0.10 M NaCI Similar solubility as in pure water

c. 0.10 M KNO3 Less soluble than in pure water.

d. 0.10 M NH4CH3COO

Explanation:

This is based on common ion effect.

According to common ion effect, the solubility of a sparingly soluble salt decreases in a solution containing common ion to it.

The solubility of AgCl(s) is shown below:

[tex]AgCl(s) <=> Ag^{+}(aq)+Cl^-(aq)[/tex]

So, when it is placed in:

a. 0.10 M AgNO3

Due to common ion effect Ag+, its solubility is less in this solution than in pure water.

b. 0.10 M NaCI :

Due to common ion effect Cl-, its solubility is less in this solution than in pure water.

c. 0.10 M KNO3 :

In this solution there is no presence of common ion.

So, the solubility of AgCl in this solution is similar to that of pure water.

d. 0.10 M NH4CH3COO:

In this solution, AgCl forms a precipitate.

So, the solubility of AgCl is more in this solution compared to pure water.

Answer:

No, the correct empirical formula is [tex]C_3H_7[/tex].

Explanation:

Hello there!

In this case, according to the given information, it turns out necessary for us to bear to mind the fact that empirical formulas must not be expressed in decimal numbers, for that reason, we need to multiply the given empirical formula by 2 to get the correct one:

[tex]C_3H_7[/tex]

Which is now possible.

Regards!

Answer:

soy....plant protein also is found in vegtables and grain products.

The protein that is derived from the plant is soyabean. Protein-rich foods have a rich source of amino acids. Amino acids are required by the body for different cellular activities.

Proteins are present in plant-based foods and animal-based foods. In nature, the plant-based foods that are rich in proteins are soybeans, beans etc. Animal products such as dairy products, milk, and cheese are rich sources of proteins.

Animal-based foods such as eggs, meat, and fish have a good amount of protein. The proteins are made up of amino acids. Peptide bonds connect each amino acid to the next.

Proteins are necessary for the body, as cells need amino acids for both structural and functional support. Not all cells of the body synthesise all amino acids. Some essential amino acids are required by the body and can be taken from external sources such as plants.

Hence, the plant-based protein is soyabean.

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The question is incomplete; the complete question may be the following:

1) Which of the following is a protein source of plant origin?

A)egg

B) Soyabean

C)cheese

D)Milk

Answer:

See Explanation

Explanation:

Rate of reaction refers to how quickly or slowly a reaction proceeds. The rate of reaction depends on certain factors.

Two among the factors that affect the rate of reaction are the concentration of reactants and the surface area of reactants.

The more the concentration of reactants, the faster the rate of reactants because there is a high possibility of collision between reactants. Also, the higher the surface area of reactants, the greater the rate of reaction.

In flour mills and coal mines where there is a large amount (concentration) of combustible materials and the particles are powdered (high surface area), there is a greater risk of explosion due to a high rate of reaction owing to a combination of the two factors discussed above.

Answer:

Explanation:

The most highly stable cycloalkane is cyclohexane. It does not suffer from an angle or torsional strain, and it has the appropriate stability as chain alkanes. Because of the peculiar conformation it takes, this stability leads to the cyclohexane conformation popularly known as the "chair" conformation.

However, from the information given;

The chair conformation structure of  trans-1-bromo-3-methylcyclohexane is carefully drawn and the substituents are appropriately attached in the image below.

Explanation:

2. [tex]2C_2H_6 + 7O_2 \rightarrow 4CO_2 + 6H_2O[/tex]

First, we need to find the number of moles of [tex]CO_2[/tex] at 300K and 1.5 atm using the ideal gas law:

[tex]n= \dfrac{PV}{RT}= \dfrac{(1.5\:\text {atm})(33\:L)}{(0.082\:\text{L-atm/mol-K})(300K)}[/tex]

[tex]=2.0\:\text{mol}\:CO_2[/tex]

Now use the molar ratios to find the number of moles of ethane to produce this much [tex]CO_2[/tex].

[tex]2.0\:\text{mol}\:CO_2 \times \left(\dfrac{2\:\text{mol}\:C_2H_6}{4\:\text{mol}\:CO_2}\right)[/tex]

[tex]=1.0\:\text{mol}\:C_2H_6[/tex]

Finally, convert this amount to grams using its molar mass:

[tex]1.0\:\text {mol}\:C_2H_6 \times \left(\dfrac{30.07\:\text g\:C_2H_6}{1\:\text{mol}\:C_2H_6} \right)[/tex]

[tex]=30.1\:g\:C_2H_6[/tex]

3. [tex]3Zn + 2H_3PO_4 \rightarrow 3H_2 + Zn_3(PO_4)_2[/tex]

Convert 75 g Zn into moles:

[tex]75\:\text g\:Zn \times \left(\dfrac{65.38\:\text g\:Zn}{1\:\text{mol}\:Zn}\right)=1.1\:\text{mol}\:Zn[/tex]

Then use the molar ratios to find the amount of H2 produced.

[tex]1.1\:\text{mol}\:Zn \times \left(\dfrac{3\:\text{mol}\:H_2}{3\:\text{mol}\:Zn}\right)=1.1\:\text{mol}\:H_2[/tex]

Now use the ideal gas law [tex]PV=nRT[/tex] to find the volume of H2 produced at 23°C and 4 atm:

[tex]V= \dfrac{nRT}{P}= \dfrac{(1.1\:\text{mol}\:H_2)(0.082\:\text{L-atm/mol-K})(296K)}{4\:\text{atm}}[/tex]

[tex]=8.9\:\text L\:H_2[/tex]

Answer:

CCl4 can neither form H-bonds with water molecules nor can it break H-bonds in water molecules. Therefore, it is insoluble in water. Ethanol is a polar compound and can form H-bonds with water, which is a polar solvent. Therefore,it is miscible with water in all proportions

Explanation:

FIRSTLY WATER MOLECULES CONTAIN ONE OXYGEN AND TWO HYDROGEN(H2O) .HENCE IN THIS STRUCTURE THE BOND BETWEEN OXYGEN AND HYDROGEN IS COVALENT AND POLARIZABLE .HENCE OXYGEN ATOM ATTRACTS ELECTRONS MORE STRONGLY TOWARDS INWARDS AS COMPARE TO 2 HYDROGEN ATOMS. DUE TO WHICH OXYGEN ATOM GET SLIGHTLY NEGATIVE CHARGE AND 2 HYDROGEN OCCUPY SLIGHTLY POSITIVE CHARGE THAT MAKE WATER A POLAR MOLECULE. :NOW IN ETHANOL(CH3CH2OH),ETHANOL MOLECULE IS FORMED BY 2 CARBON ATOM JOINED BY SINGLE BOND WHICH IS NOT POLAR.IN β CARBON OF ETANOL CARBON IS BONDED TO 3 HYDROGEN ATOMS WHICH MAKES IT NON POLAR DUE TO SYMMETRY BUT α CARBON HAS 2 HYDROGEN AND 1 OH- ION (SAME AS IN THE CASE OF WATER MOLECULE) SO THIS CARBON ATOM BECAMES POLAR AND HENCE ETHANOL MOLECULES BECAMES POLAR. NOW WE KNOW THAT SAME CHARGE REPEL EACH OTHER AND UNLIKE CHARGES ATTRACTS EACH OTHER SO THE SLIGHTHLY POSITIVE CHARGE OF WATER MOLECULE MAKES A BOND WITH THE.

Answer:

C. [tex]H_2S\rightarrow S+2H^++2e^-[/tex]

Explanation:

Hello there!

In this case, according to the given chemical reaction, it turns out possible to realize there is one sulfur atom on each side of the chemical equation but two hydrogen atoms on the left and one on the right, which means the latter must be balanced in agreement to the law of conservation of mass.

In such a way, by setting a 2 on H⁺, the reaction will be balanced:

[tex]H_2S\rightarrow S+2H^+[/tex]

Now, we count the transfer electrons for sulfur from -2 to 0 as 2e⁻ on the right, which will match with the option C.

[tex]H_2S\rightarrow S+2H^++2e^-[/tex]

Regards!

Answer:

(E)-1-phenylbut-1-ene

Explanation:

2-phenyl-4 bromobutane is an amphetamine that contains a phenyl group. It forms a major stable product with other reacting agents.

The major organic product that is obtained from the sequence of the reactions of the 2-phenyl-4 bomobutane when it reacts with [tex]NaN_3[/tex] is the (E)-1-phenylbut-1-ene.

Thus the answer is 2-phenyl-4 bromobutane is an amphetamine that contains a phenyl group. It forms a major stable product with other reacting agents.

The major organic product that is (E)-1-phenylbut-1-ene.

Answer:

Ka = [H⁺] × [CN⁻] / [HCN]

Explanation:

Cyanhydric acid is a weak acid, according to the following equation:

HCN(aq) ⇄ H⁺(aq) + CN⁻(aq)

The acid ionization constant (Ka) is equal to the product of the concentrations of the ions raised to the stoichiometric coefficients divided by the concentration of the undissociated acid raised to its stoichiometric coefficient.

Ka for HCN is:

Ka = [H⁺] × [CN⁻] / [HCN]

Answer:

Concentration C = 0.0189 mol/L

Explanation:

From the given information:

Let consider the formula used in calculating the concentration according to Beer's law:

[tex]\mathtt{A =\varepsilon \times L \times C}[/tex] --- (1)

here;

A = absorbance

ε = coefficient of molar absorptivity

L = path length

C = concentration (mol/L)

Also, from Beer law plot:

y = mx+b

where,

y represent absorbance A

b represents intercept

m represents the coefficient of molar absorptivity ε

and x represents the concentration(C).

replacing the substituted entities

A = ε × C + b ---- (2)

Making the concentration the subject of the above formula:

[tex]C = \dfrac{A-b}{\varepsilon}[/tex]----(3)

From y = 11.589x - 0.0002

A = 11.589 *C - 0.0002

Given that:

A = 0.219

∴

0.219 = 11.589 *C - 0.0002

0.219 + 0.0002 =  11.589 *C

C = 0.2192/11.589

C = 0.0189 mol/L

Answer:

The answer is cell wall

Explanation:

Because it is

Answer:

Bromine will be a liquid

Answer: The volume of NaOH required at the half-equivalence point is 6.21 mL

Explanation:

The chemical equation for the reaction of a weak acid with NaOH follows:

[tex]HA+ NaOH\rightarrow NaA+H_2O[/tex]

From the equation, we can say that NaOH and weak acid is present in a 1 : 1 ratio.

We are given:

Volume of NaOH required at equivalence point = 12.42 mL

The volume of NaOH required at half-equivalence point will be = [tex]\frac{12.42mL}{2}=6.21mL[/tex]

Hence, the volume of NaOH required at the half-equivalence point is 6.21 mL

The volume of NaOH at the half-equivalence point is 6.21 mL

The equivalence point is the point at which equal amount of the acid and base have reacted.

Half equivalence point = Equivalence point / 2

Half equivalence point = 12.42 / 2

Half equivalence point = 6.21 mL

Therefore, we can conclude that the volume of NaOH at the half-equivalence point is 6.21 mL.

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Answer:

Actually, we can answer the problem even without the first statement. All we have to do is write the reaction for the production of sulfur trioxide.

2 S + 3 O₂ → 2 SO₃

The stoichiometric calculations is as follows:

6 g S * 1 mol/32.06 g S = 0.187 mol S

Moles O₂ needed = 0.187 mol S * 3 mol O₂/2 mol S = 0.2805 mol O₂

Since the molar mas of O₂ is 32 g/mol,

Mass of O₂ needed = 0.2805 mol O₂ * 32 g/mol = 8.976 g O₂

Answer:

A solution contains 100mM NaCl, 20mM CaCl2, and 20mM urea. We would say this solution is hypotonic compared to a 300 mOsM solution and hypotonic compared to a cell with 300 mOsM (non-penetrating solutes) interior.

Explanation:

The osmolarity is calculated from the molar concentration of the active particles in the solution. We have a solution that is composed of NaCl, CaCl₂ and urea.

When they are dissolved in water, they dissociate into particles as follows:

NaCl → Na⁺ + Cl⁻  (2 particles per compound)

CaCl₂ → Ca²⁺ + 2 Cl⁻ (3 particles per compound)

urea: not dissociation (1 particle per compound)

Then, we have to calculate the osmolarity of the solution. We multiply the molarity of each compound by the number of particles produced by the compound in water:

Osm = (100 mM NaCl x 2) + (20 mM CaCl₂ x 3) + (20 mM urea x 1) = 280 mOsm

Compared with 300 mOsm, 280 mOsm has a lower osmolarity, so it is a hypotonic solution.

To compare with a cell's osmolarity, we have to consider only the non-penetrating solutes. Urea is considered a penetrating solute for mammalian cells. So, the osmolarity of non-penetrating solutes (NaCl  and CaCl₂) is calculated as:

Osm (non-penetrating solutes) = (100 mM NaCl x 2) + (20 mM CaCl₂ x 3) = 260 mOsm

Therefore, we have:

Compared to 300 mOsm solution ⇒ 280 mOsm solution is a hypotonic solution

Compared to a cell with 300 mOsm ⇒ 260 mOsm solution is hypotonic

Explanation:

can u post a picture of the question ?

it is moss

Explanation:

Answer:

Exothermic

1771 g

Explanation:

Step 1: Write the balanced thermochemical equation

2 S(s) + 3 O₂(g) ⇒ 2 SO₃(g)   ΔH° = -791.4 kJ

Since ΔH° < 0, the reaction is exothermic.

Step 2: Calculate the moles of SO₃ produced when 8753 kJ of energy are released

According to the thermochemical equation, -791.4 kJ are released every 2 moles of SO₃ that are formed.

-8753 kJ × 2 mol/(-791.4 kJ) = 22.12 mol

Step 3: Calculate the mass corresponding to 22.12 moles of SO₃

The molar mass of SO₃ is 80.06 g/mol.

22.12 mol × 80.06 g/mol = 1771 g

Answer:

See explanation

Explanation:

For the first question, we can see that the pressure is constant so we apply Charles law;

V1/T1 =V2/T2

V1T2 = V2T1

V1= 4.5 L

T1= 27 + 273 = 300 K

V2= ?

T2= 127 + 273 = 400 K

V2= V1T2/T1

V2= 4.5 × 400/300

V2= 6L

For question 2, Charles law is also used;

V1/T1 =V2/T2

V1T2 = V2T1

T1= 338 K

V1= 0.480 L

T2= ?

V2= 9.2 L

T2= V2T1/V1

T2= 9.2 × 338/0.480

T2= 6478.3 K

Answer:

Below

Explanation:

Got it right

Check the periodic table, then click electrons

Answer:

5.37 × 10⁻⁴ mol/L

Explanation:

A chemist makes 660. mL of magnesium fluoride working solution by adding distilled water to 230. mL of a 0.00154 mol/L stock solution of magnesium fluoride in water. Calculate the concentration of the chemist's working solution. Round your answer to 3 significant digits.

Step 1: Given data

Step 2: Calculate the concentration of the final solution

We want to prepare a dilute solution from a concentrated one. We can calculate the concentration of the final solution using the dilution rule.

C₁ × V₁ = C₂ × V₂

C₂ = C₁ × V₁ / V₂

C₂ = 0.00154 mol/L × 230. mL / 660. mL = 5.37 × 10⁻⁴ mol/L

Answer:

Amount of reactant after four hours = 4,26 grams

Explanation:

Suppose y denotes the amount of reactant at the time (t)

The given function:

[tex]\dfrac{dy}{dt} = -0.7 y[/tex]

[tex]\dfrac{dy}{y} = -0.7 dt[/tex]

Taking integral on both sides

㏑(y) = -0.7t + c¹

[tex]e^{In(y)}= e^{-0.7t + c^1}[/tex]

[tex]y(t) = Ce ^{-0.7t}[/tex]

At t = 0 ; y (t) = 70

∴

[tex]70 = Ce^{-0.7(0)}[/tex]

C = 70

As such; [tex]\mathtt{y(t) = 70 e^{-0.7*t}}[/tex]

After four hours, the amount of the reactant is:

[tex]\mathtt{y(t) = 70 e^{-0.7*4}}[/tex]

[tex]\mathtt{y(t) = 70 e^{-2.8}}[/tex]

[tex]\mathtt{y(t) = 4.26}[/tex]

Amount of reactant after four hours = 4,26 grams

Answer:

See explanation.

Explanation:

Hello there!

In this case, according to the given information, it turns out possible for us to firstly recall the electron configuration of hydrogen:

[tex]1s^1[/tex]

To realize that the principal quantum number is 1, the angular is 0 as well as the magnetic one; therefore we infer that all the given n's are not allowed, just l=0 is allowed as well as ml=0 yet the rest, are not allowed.

Best regards!