Maria tutors history. For each hour that she tutors, she earns 20 dollars. Her earnings, E (in dollars), after tutoring for h hours is given by the following.
E=20h
How much does Maria earn if she tutors for 5 hours?

Answer:

✔️2 sets of corresponding angles

<D and <S

<R and <L

✔️2 sets of corresponding sides

DR and SL

RM and LT

Step-by-step explanation:

When two polygons are congruent, it implies that they have the same shape and size. Therefore, their corresponding angles and sides are congruent to each other.

When naming congruent polygons, the arrangement of the vertices are kept in a definite order of arrangement.

Therefore, Given that polygon DRMF is congruent to SLTO, the following angles and sides correspond to each other:

<D corresponds to <S

<R corresponds to <L

<M corresponds to <T

<F corresponds to <O

For the sides, we have:

DR corresponds to SL

RM corresponds to LT

MF corresponds to TO

FD corresponds to OS.

We can select any two out of these sets of corresponding angles and sides as our answer. Thus:

✔️2 sets of corresponding angles

<D and <S

<R and <L

✔️2 sets of corresponding sides

DR and SL

RM and LT

Answer:

Step-by-step explanation:

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Answer:

Y=6000-400x

Step-by-step explanation:

Y=6000-400x where 6000 is beginning total, x represents how many months have passed, and 400x reduces the total by 400 for x number of months.

Answer and Step-by-step explanation:

Solve for the middle side, then  for x using Pythagorean Theorem.

[tex]A^2 + B^2 = C^2\\\\\\6^2 + 8^2 = C^2\\\\100 = C^2\\\\C = 10\\\\\\\\A^2 + 10^2 = 12^2\\\\A^2 + 100 = 144\\\\A^2 = 44\\\\A^2 = 2\sqrt{11} <-Answer[/tex]

#teamtrees #PAW (Plant And Water)

Answer:

Median = 44

Step-by-step explanation:

Arrange the data in ascending order:

36, 37, 40, 43, 44, 49, 50 , 51, 56.

Choose the number in the middle.

Median = 44

Try this option:

1. the required surface area consists of: A=A₁+A₂+A₃, where

2. A₁=pi*r*l - the surface of the cone:

pi=3.14; r=4/2=2 cm; l=sqrt(6²+2²)=2√10≈6.33 (cm);

A₁=3.14*2*6.33=39.74 (cm²).

3. A₂=a²-pi*r² - the surface of the top plane:

A₂=36-3.14*4=23.43 (cm²).

4. A₃=5*a² - the surface of the five planes of the given cube:

A₃=5*6²=180 (cm²).

5. the required area:

A=39.74+23.43+180=243.17 (cm²).

Answer: 243.17

Answer:

See below and attached

Step-by-step explanation:

Let the number of paintings is x and the number of mugs is y.

We have following inequalities:

The graphical solution is attached.

The solution is:

Answer:

no

Step-by-step explanation:

because it's unequal

Answer:

to blury

Step-by-step explanation:

A. 0

Answer:

Solution given

(x1,y1)=G(3, -2),

(x2,y2)=H(7, -2)

now

slope=(y2-y1)/(x2-x1)=(-2+2)/(7-3)=0/4=0

Answer:

0

Step-by-step explanation:

To find the slope

m= ( y2-y1)/(x2-x1)

 = ( -2 - -2)/ ( 7-3)

   = (-2+2)/(7-3)

   = 0/4

Answer should be 21

=

189

9

=

21

Answer:

The answer would be 25.

4x4=16

16+9=25

Step-by-step explanation:

I believe this is correct, if not feel free to let me know and I will fix it. I'm sorry in advance if it is incorrect.

Answer:

25

Step-by-step explanation:

rewrite the equation

(4x4)+9

do the equation

16+9=25

Answer:

Step-by-step explanation:

Because this is an isosceles trapezoid, the diagonals are congruent. That means that DF is the same length as EG which is 11.

Answer:

Sorry I had to go to dinner here you go hope this helps! :D

Step-by-step explanation:

So, before we start, there are two things we have to go over.

First off, we have "or"

When using or between two probabilitess, you are basically adding them together.

For instance, you first question asks what the probability is of rolling a 5 or a number greater than 3(assuming this is a 6 sided dice).

So, rolling a 5 is a change of 1/6. Since 1 of the 6 dice iwll be 5. The other probability is a 1/2, since 3 of the 6 dice are over 3.

Now lets add these two together because of the "or":

1/2+1/6=3/6+1/6=4/6

So the probabily of rolling a 5 OR rolling a number greater than 3 is 4/6.

This is inclusive, since rolling a 5 is possible and greater than 3.

Now "and" is a bit different and more complex than or is.

Here is an example:

What is the change of rolling a even number or rolling a number above 4?

Well, rolling a even number has a probability of 1/2. Rolling a number above 4 is 1/3.

To find the "and", we multiply the two probabilities.

So 1/3*1/2=1/6

So the probability of rolling a even number and a number above 4 is 1/6.

Now, lets get back to the answers.

So what is the probability of rolling a 2 or a 6?

There is a 1/6 probability to get a 2, and a 1/6 probability to get a 6.

Add it together since they use or:

1/6+1/6=2/6

So the probability of rolling a 2 or a 6 is 2/6, or 1/3.

This is exlusive since you cant roll both a 6 and a 2 at the same time.

Next we have what the probability is of drawing a 6 or a king.

There are 13 different cards in a deck.

There is a 4/52 chance of drawing a 6(spade/heart/etc), and a 4/52 chance of drawing a king. This simplyfies to 1/13 for each.

This is:

1/13+1/13=2/13

So the probability of drawing a 6 or a king is 2/13

This is a exclusive event since a king and 6 cant be drawn at the same time.

Finally, we have:

What is the probability of drawing a queen or a spade?

Again, there is a 4/52 chance of drawing a queen. A spade, however, is different.

13 of the 52 cards can be spades, which simplies to 1/4.

So we have 1/13+1/4=4/52+13/52=17/52

So there is a 17/52 probability of drawing a queen or spade.

This is a inclusive event since it is possible to draw both a spade and queen at the same time.

Hope this answers all your questions and helps you understand what "and" "or" are in probability.

Answer:

2cm

Step-by-step explanation:

First, it is important to define both the radius and diameter. A diameter is the length of a line through the center of a circle that touches two points on the edge.

In the semicircle on the top, if we can imagine it making up a full circle, we can note that the bottom center of the semicircle is the center of the full circle, with the line of length 4cm going right through it. Similarly, for the bottom semicircle, as the line between the semicircles is straight, the diameter for that one is 4cm as well.

The radius is equal to half of the diameter. The diameter is 4cm, so the radius is 4cm/2 = 2cm

Answer:

[tex]y=-x+1[/tex]

Step-by-step explanation:

Slope can be represented as rise over run (change y-values over change in x-values). Since the y-value is changing by -2 every time the x-value is changing by 2, the slope of the line must be [tex]\frac{-2}{2}=-1[/tex].

In slope-intercept form [tex]y=mx+b[/tex], [tex]m[/tex] represents the slope of the line, [tex]b[/tex] represents the y-intercept, and [tex](x, y)[/tex] represent the coordinates of any point the line passes through.

To find [tex]b[/tex], substitute [tex]m=-1[/tex] and any point the line passes through.

Using (1, 0) from the table:

[tex]0=-1(1)+b,\\0=-1+b,\\b=1[/tex]

Thus, the equation of this line is [tex]\boxed{y=-x+1}[/tex]

Answer:

D

Step-by-step explanation:

The answer is:

999^3 = 997002999

Answer:

subtract 5 , m=(-15)

Step-by-step explanation:

15-5

=10

n:

5-10

=(-5)

m:

(-5)-10

=(-15)

hope it help

Answer:  56 degrees approximately

==========================================

Work Shown:

tan(angle) = opposite/adjacent

tan(x) = 15/10

tan(x) = 1.5

x = arctan(1.5)

x = 56.3099 approximately

x = 56 degrees

Note: arctan is the same as inverse tangent

[tex]answer = 3 {x}^{2} {e}^{ {x}^{3} } [/tex]

Answer:

[tex] \displaystyle f'(x) = 3x^2 {e}^{ {x}^{3} } [/tex]

Step-by-step explanation:

we would like to figure out the first derivative of the following:

[tex] \displaystyle f(x) = {e}^{x ^{3} } [/tex]

to do so take derivative In both sides:

[tex] \displaystyle f'(x) = \frac{d}{dx} {e}^{x ^{3} } [/tex]

to differentiate the above we can consider composite function derivation given by

[tex] \rm\displaystyle \frac{d}{dx} f(g(x)) = \frac{d}{dx} f'(g(x)) \times \frac{d}{dx} g'(x)[/tex]

let

g(x)=u

so we obtain:

[tex] \displaystyle f'(x) = \frac{d}{dx} {e}^{u} \times \frac{d}{dx} u[/tex]

substitute back:

[tex] \displaystyle f'(x) = \frac{d}{dx} {e}^{ {x}^{3} } \times \frac{d}{dx} {x}^{3} [/tex]

by using derivation rule we acquire:

[tex] \displaystyle f'(x) = 3x^2 {e}^{ {x}^{3} } [/tex]

and we are done!