What is gravitational force??
Answer:
the force of attraction between all masses in the universe
Explanation:
Have a nice day :)
calculate the density of a solid of mass 20kg if it occupies a volume of 4m³
Answer:
Density=Mass/Volume
=20/4 kg/m^3
=5 kg/m^3
what is force??????
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Answer:
A force is a push or pull upon an object resulting from the object's interaction with another object. Whenever there is an interaction between two objects, there is a force upon each of the objects. ... Forces only exist as a result of an interaction.
Brian has an object suspended in the air. It has a mass of 100 kg and is 25 meters above the ground. What is the object’s potential energy?
Explanation:
the PE = Weight x g x Height above ground where g is the gravitational constant (9.8m/s^2)
so tge PE = 100 x 9.8 x 25 = 24500 J
Por una resistencia de 10 Ω fluyen 5A. ¿Cuál será la diferencia de potencial que se le debe aplicar a la resistencia?
Answer:
V = 50 volts
Explanation:
Given that,
Resistance, R = 10 ohms
Current, I = 5 A
We need to find the potential difference across the circuit. We know that,
V = IR
Put all the values,
V = 5 × 10
V = 50 volts
Hence, the potential difference is equal to 50 volts.
in The unit of power is a
derived unite
The unit of power is
a derived unit be con
CAY
Answer:
Watts
Explanation:
The SI unit for power is the watt (W), where 1 watt equals 1 joule/second (1 W=1 J/s).
calcula el peso de una persona que viaja a la luna cuya masa es de 105 kg
Answer:
W = 170.62 N
Explanation:
The given question is, "calculate the weight of a person traveling to the moon whose mass is 105 kg".
We need to find the weight of a person on the Moon.
The weight of an object is given by :
W = mg
Where
g is acceleration due to gravity on Moon, g = 1.625 m/s2
W = 105 kg × 1.625 m/s²
W = 170.62 N
Hence, the weight of the person is 170.62 N.
what simple machine is a Window Screen
AnswER PIZZA?
Explanation:
desde lo alto de una antena de telefono se lanza una peloota de tenis, la antena mide 150 metros. se mide el alcance horizontal y cae a unos 70 metros de su base. Calcular: a)La velocidad horizontal inicial con a que fue lanzada la pelota. b) La velocidad vertical con la cual llega la pelota al piso
Explanation:
las respuestas están en la foto de arriba
Si se tiene un gato hidráulico y se aplica una fuerza en el Area 1, se refleja otra fuerza en el Area 2, teniendo en cuenta la siguiente condición A1 < A2. Podemos afirmar que las fuerzas son:
Answer:
the forces are proportional to their areas of application
Explanation:
In a hydraulic jack, Pascal's principle is used, that the pressure in an incompressible liquid is the same at the same height, whereby the pressure on both sides of the jack are the same
P₁ = P₂
the pressure is defined by
P = F / A
we substitute
[tex]\frac{F_1}{A_1} = \frac{F_2}{A_2}[/tex]
F₂ = [tex]\frac{A_2}{A_1} \ F_1[/tex]
therefore the force is F₂> F₁
Therefore the forces are proportional to their areas of application
What 3 factors should be considered when designing a lighting rod?
Explanation:
A lightning rod (US, AUS) If lightning hits the structure:-
It will preferentially strike the rod and be conducted to ground through a wire.
Instead of passing through the structure, where it could start a fire or cause electrocution.
The parts of a lightning protection system are air terminals (lightning rods or strike) and all of the connectors and supports to complete the system.
Una persona A tiene cierta cantidad de masa y una persona B tiene la mitad de masa de la persona A ¿como es el peso de B respecto al de A?
Answer:
El peso de la persona B es la mitad del peso de la persona A.
Explanation:
El peso de la persona B puede calcularse con la siguiente ecuación:
[tex] P_{B} = m_{B}g [/tex] (1)
En donde:
[tex]m_{B}[/tex]: es la masa de la persona B
g: es la gravedad
Dado que la persona B tiene la mitad de la masa de la persona A, tenemos:
[tex] m_{B} = \frac{m_{A}}{2} [/tex] (2)
En donde:
[tex]m_{A}[/tex]: es la masa de la persona A
Al introducir la ecuación (2) en (1) nos queda:
[tex] P_{B} = \frac{m_{A}}{2}g [/tex] (3)
Sabemos que el peso de la persona A está dado por:
[tex] P_{A} = m_{A}g [/tex] (4)
Entonces, al introducir la ecuación (4) en (3) tenemos:
[tex] P_{B} = \frac{P_{A}}{2} [/tex]
Por lo tanto, el peso de la persona B es la mitad del peso de la persona A.
Espero que te sea de utilidad!
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Answer:
Stimulants are a group of drugs that result in increased activity in the body. Sometimes referred to as “uppers,” these drugs are frequently abused due to their performance-enhancing and euphoric effects. Generally, those who abuse stimulants experience heightened energy levels and enhanced focus.
Stimulants speed up mental and physical processes, which can produce desirable effects in the short-term by increasing levels of dopamine in the brain. While users may feel great due to the short-term effects of stimulants, long-term abuse of these drugs can have significant consequences, which is why it is so important for those who abuse the drugs to get help as quickly as possible.
Explanation:
hope this works
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Un móvil viaja inicialmente con una velocidad de 55 m/s, al cabo de cierto tiempo, su velocidad es de 115 m/s, de repente frena bruscamente con una desaceleración de 14, 500 m/s2. ¿qué distancia recorrerá antes de frenar?
Answer:
Distancia, S = 2.84 metros
Explanation:
Dados los siguientes datos;
Velocidad inicial = 55 m/s
Velocidad final = 115 m/s
Deceleración = 14500 m/s²
Para encontrar qué tan lejos viajaría el automóvil, usaríamos la tercera ecuación de movimiento;
V² = U² + 2aS
115² = 55² + 2*14500*S
13225 = 3025 + 29000S
29000S = 13225 - 3025
29000S = 10200
S = 29000/10200
Distancia, S = 2.84 metros
A 500 kg sports car accelerates uniformly from rest reaching a speed of 30 m/s in 6 seconds .Find the distance travelled by the car in 6 second
Answer:
the distance traveled by the sports car is 90 m
Explanation:
Given;
mass of the sports car, m = 500 kg
initial velocity of the sports car, u = 0
final velocity of the sport car, v = 30 m/s
time of motion of the car, t = 6 s
The distance traveled by the sports car is calculated as;
[tex]s = (\frac{u+v}{2} )t\\\\s = (\frac{0+30}{2} ) \times 6\\\\s = 15 \times 6\\\\s = 90 \ m[/tex]
Therefore, the distance traveled by the sports car is 90 m
Suggest two ways in which the boy could balance the beam?
Answer:
Hope this is what you were looking for!
Explanation:
1) So, if we are talking about balancing a straight stick (beam), he could put a finger from each hand on either side of it and move them together. As a result of friction his fingers will meet at the balance point.
2) Method of trial and error.
Un automóvil se anuncia con una potencia de 600 hp y cuando se prueba en una subida pesada, alcanza una velocidad máxima de 45 km/h ¿cuál es la fuerza máxima que le imprime el motor?
Answer:
The force is 35808 N.
Explanation:
Power, P = 600 hp = 600 x 746 W = 447600 W
speed, v = 45 km/h = 12.5 m/s
Let the force is F.
P = F v
447600 = F x 12.5
F = 35808 N
What is cerebellum ?
For its size, the common flea is one of the most accomplished jumpers in the animal world. A 2.50-mm-long, 0.460 mg flea can reach a height of 15.0 cm in a single leap. a) Calculate the kinetic energy per kilogram of mass. b) If a 79.0 kg, 2.00-m-tall human could jump to the same height compared with his length as the flea jumps compared with its length, how high could the human jump
Answer:
1.47 J/kg
120 m
Explanation:
The maximum height it can jump in a single leap 15 cm, = 0.15 m
to get the kinetic energy per kg of mass, we need to find the takeoff speed. The take off speed can be calculated by using the formula
v = [tex]\sqrt{2gh}[/tex]
where h = 0.15
v = [tex]\sqrt{2 * 9.81 * 0.15}[/tex]
v = [tex]\sqrt{2.94}[/tex]
v = 1.715 m/s
energy per kg of mass =
1/2 * (1.715) = 1.47 J/Kg
TJe height a human can jump when compared to the flea is
2 m/2.5 mm * 15 cm =
2/0.0025 *0.15 =
800 * 0.15 = 120 m
Can someone help me with this one :") thanks
when a wooden block floats in water displaces 0.006 cubic of the water find the weight of the wooden block when it is in air
Answer:
solve it with the formula 1−0.4=0.6, 0.6Vρg=Vρbg where ρb
Explanation:
The buoyant force acting on an immersed body is equal to the weight of the fluid displaced by it, if the fluid is in rest. In this case, the fluid is accelerating upwards so the buoyant force must also provide the displaced fluid force to accelerate. Therefore, buoyant force will be fVρgeff where V = volume of body and f = fraction of volume of body immersed in fluid and geff=g+a=1.5g.
The buoyant force acting on an immersed body is equal to the weight of the fluid displaced by it, if the fluid is in rest. In this case, the fluid is accelerating upwards so the buoyant force must also provide the displaced fluid force to accelerate. Therefore, buoyant force will be fVρgeff where V = volume of body and f = fraction of volume of body immersed in fluid and geff=g+a=1.5g.When fluid is at rest: f=
The buoyant force acting on an immersed body is equal to the weight of the fluid displaced by it, if the fluid is in rest. In this case, the fluid is accelerating upwards so the buoyant force must also provide the displaced fluid force to accelerate. Therefore, buoyant force will be fVρgeff where V = volume of body and f = fraction of volume of body immersed in fluid and geff=g+a=1.5g.When fluid is at rest: f=⇒ρb=0.6ρ.
The buoyant force acting on an immersed body is equal to the weight of the fluid displaced by it, if the fluid is in rest. In this case, the fluid is accelerating upwards so the buoyant force must also provide the displaced fluid force to accelerate. Therefore, buoyant force will be fVρgeff where V = volume of body and f = fraction of volume of body immersed in fluid and geff=g+a=1.5g.When fluid is at rest: f=⇒ρb=0.6ρ.In the second case: 1.5fVρg=Vρbg+Vρba=1.5Vρbg⇒fρ=ρb⇒f=0.6.
The buoyant force acting on an immersed body is equal to the weight of the fluid displaced by it, if the fluid is in rest. In this case, the fluid is accelerating upwards so the buoyant force must also provide the displaced fluid force to accelerate. Therefore, buoyant force will be fVρgeff where V = volume of body and f = fraction of volume of body immersed in fluid and geff=g+a=1.5g.When fluid is at rest: f=⇒ρb=0.6ρ.In the second case: 1.5fVρg=Vρbg+Vρba=1.5Vρbg⇒fρ=ρb⇒f=0.6.Thus, the fraction of immersed volume remains the same.
The buoyant force acting on an immersed body is equal to the weight of the fluid displaced by it, if the fluid is in rest. In this case, the fluid is accelerating upwards so the buoyant force must also provide the displaced fluid force to accelerate. Therefore, buoyant force will be fVρgeff where V = volume of body and f = fraction of volume of body immersed in fluid and geff=g+a=1.5g.When fluid is at rest: f=⇒ρb=0.6ρ.In the second case: 1.5fVρg=Vρbg+Vρba=1.5Vρbg⇒fρ=ρb⇒f=0.6.Thus, the fraction of immersed volume remains the same.Body will float with 40% of the volume above water surface.
can i have the physical science grade 12 june 2021 paper (common paper)
Answer:
u have to purchase it via online e-commerce platforms
Answer:
what your crazy anong pong common paper
50 points question (Who is known as father of science)Albert Einstein
Answer:
Albert Einstein is known as the father of science.
Se conecta una pila de 1.5 volt a una luz led de color rojo, el led se enciende mientras esté conectado a la pila. De esta stuación se afirma que:
Answer:
Se requiere corriente para que brille la luz.
Explicación:
Una batería de 1,5 voltios está conectada a una luz LED roja, el LED se enciende siempre que esté conectado a la batería. A partir de esta situación se afirma que se requiere corriente para que brille la luz. La batería tiene corriente eléctrica almacenada que permite que la luz brille hasta que la corriente eléctrica esté presente en la batería. Esta batería se puede cargar durante un período de tiempo cuando está llena, se puede recuperar durante muchas horas.
calculate the density of a pure substance if 100cm cubed of it has a mass of 20 grams
Answer:
5
Explanation:
20 x 5 = 100
explain the derivation of Newton's third and second law.
Answer:
Consider an isolated system of 2 bodies A & B. An isolated system means where there is no external force acting.Now let F be the force acting on B by A & F be the force acting on A by B.Now rate of change of momentum of A =dpA/dt and rate of change of momentum of B =d pB/dt
thus FAB=d pB/dt (i)......
FBA=dpA/dt (ii)........
Adding 1 and 2 we get FAB+FBA=d pB/dt+dpA/dt =d(pB+pA)/dt
But if no force is applied momentum will also be 0 because no velocity will be there so rate of change of momentum will also be 0
thus d(pA+pB)/dt=0
therefore FAB+FBA=0
or,FAB=-FBA
(3RD LAW OF MOTION)
Is the path of light visible in a Suspension? Give reason.
Answer:
Answer:It is due to tyndall effect that the path of a light ray passing through a suspension is visible. The particles in suspension scatter the beam of light making it clearly visible.
Answer:
it is due to the Tyndall effect so the path of light is visible in a suspension but in solution the path of light is not visible
PLEASE HELP ME!
1. Figure 5.20 shows a graph of displacement against time for a wave.
(a) What is meant by amplitude?
(b) Determine the period of oscillation, T. Then, calculate the frequency of oscillation.
2. Compare and contrast progressive wave and stationary wave.
Answer:
a) A = 3 cm, b) T = 0.4 s, f = 2.5 Hz,
2) A standing wave the displacement of the wave is canceled and only one oscillation remains
Explanation:
a) in an oscillatory movement the amplitude is the highest value of the signal in this case
A = 3 cm
b) the period of oscillation is the time it takes for the wave to repeat itself in this case
T = 0.4 s
the period is the inverse of the frequency
f = 1 /T
f = 1 /, 0.4
f = 2.5 Hz
2) a traveling wave is a wave for which as time increases the displacement increases, in the case of a transverse wave the oscillation is perpendicular to the displacement and in the case of a longitudinal wave the oscillation is in the same direction of the displacement.
A standing wave occurs when a traveling wave bounces off some object and there are two waves, one that travels in one direction and the other that travels in the opposite direction. In this case, the displacement of the wave is canceled and only one oscillation remains.
Con respecto a las magnitudes longitud del péndulo y periodo, ¿por qué la línea de mejor ajuste de los puntos-dato de la distribución indica que sí hay relación entre ambas magnitudes?
Answer:
Por que existe una relación entre dichas magnitudes.
Para un pendulo perfecto de largo L, sabemos que el periodo esta definido como:
[tex]T = 2*\pi *\sqrt{L/g}[/tex]
Donde:
pi = 3.14
L = largo del péndulo
g = aceleración gravitatoria = 9.8 m/s^2
Entonces podemos ver que el periodo es proporcional a la raíz cuadrada de la longitud del péndulo.
Esto es por lo que al analizar datos de un experimento se debería observar una relación entre esas magnitudes.
