Magicians often use ‘flash powder’ in their acts. Flash powder contains 69.0% potassium chlorate (31.9% K, 28.9% Cl, 39.2% O) and the remainder is aluminium. Calculate the percentage composition by mass of each element in flash powder

Answers

Answer 1

Answer:

[tex]\rm K[/tex]: approximately [tex]22.0\%[/tex].

[tex]\rm Cl[/tex]: approximately [tex]19.9\%[/tex].

[tex]\rm O[/tex]: approximately [tex]27.0\%[/tex].

[tex]\rm Al[/tex]: [tex]31.0\%[/tex].

Explanation:

Consider a [tex]100\; \rm g[/tex] sample. There would be [tex]69.0\% \times 100\; \rm g = 69.0\; \rm g[/tex] of [tex]\rm KClO_{3}[/tex] and [tex]100.0\; \rm g - 69.0\; \rm g = 31.0\; \rm g[/tex] of [tex]\rm Al[/tex].

Out of that [tex]69.0\; \rm g[/tex] of [tex]\rm KClO_{3}[/tex]:

[tex]31.9\%[/tex] (by mass) would be [tex]\rm K[/tex]: [tex]31.9\% \times 69.0\; \rm g \approx 22.0\; \rm g[/tex].

[tex]28.9\%[/tex] (by mass) would be [tex]\rm Cl[/tex]: [tex]28.9\% \times 69.0\; \rm g \approx 19.9\; \rm g[/tex].

[tex]39.2\%[/tex] (by mass) would be [tex]\rm O[/tex]: [tex]39.2\% \times 69.0\; \rm g \approx 27.0\; \rm g[/tex].

Overall, the composition (by mass) of each element in this mixture would be:

[tex]\rm K[/tex]:

[tex]\begin{aligned} & \frac{31.9\% \times 69.0\; \rm g}{100\; \rm g} \\ =\; & 31.9\% \times 69.0\% \\ \approx \; & 22.0\%\end{aligned}[/tex].

[tex]\rm Cl[/tex]:

[tex]\begin{aligned} & \frac{28.9\% \times 69.0\; \rm g}{100\; \rm g} \\ =\; & 28.9\% \times 69.0\% \\ \approx \; & 19.9\%\end{aligned}[/tex].

[tex]\rm O[/tex]:

[tex]\begin{aligned} & \frac{39.2\% \times 69.0\; \rm g}{100\; \rm g} \\ =\; & 39.2\% \times 69.0\% \\ \approx \; & 27.0\%\end{aligned}[/tex].

[tex]\rm Al[/tex]:

[tex]\begin{aligned}& \frac{100\; \rm g - 69.0\; \rm g}{100\; \rm g} \\ =\; & 100\% - 69.0\% \\ =\; & 31.0\%\end{aligned}[/tex].


Related Questions

where do you write salt and suger why​

Answers

Answer:

here: "salt and sugar"

Explanation:

I dunno, looks pretty, gives 5 points. even tough any context is missing

but seriously:

salt and sugar look the same. just someone with a split personality

If a quantity of this substance existed as a solid at a pressure of 0.75 atm and a temperature of 50°C, what phase
change(s) would occur if the temperature increased to 500°C?
a. Freezing and deposition
b. Melting and freezing
c. Condensation and sublimation
d. Melting and vaporization

Answers

Possibly d or could be a

1. Necesitas un "cubo concentrado" (de esos que se usan para sazonar las comidas Maggie, ricostilla) dos vasos de vidrio o plástico y agua (caliente y fría). 2.Agrega al vaso con agua fria la mitad de un cubo concentrado y déjala reposar unos minutos. Prepara el segundo vaso con agua caliente y agrégale la otra mitad del cubo. 3. Argumenta tus observaciones en relación con lo observado y con la teoria vista. ¿Como influye la temperatura en este experimento?​

Answers

Respuesta:
El cubo Maggie es un sazonador que contiene caldo de pollo y grasas, por lo que se disuelve fácilmente al entrar en contacto con el agua caliente gracias a que la temperatura que derrite las grasas y se vuelven líquidas, mientras que con el agua fría no puede disolverse así de rápido ya que las grasas siguen en estado sólido.

How many moles of electrons is required to deposit 5.6g of iron from a solution of iron (2) tetraoxosulphate(6)

Answers

Answer:

0.20 mol

Explanation:

Let's consider the reduction of iron from an aqueous solution of iron (II).

Fe²⁺ + 2 e⁻ ⇒ Fe

The molar mass of Fe is 55.85 g/mol. The moles corresponding to 5.6 g of Fe are:

5.6 g × 1 mol/55.85 g = 0.10 mol

2 moles of electrons are required to deposit 1 mole of Fe. The moles of electrons required to deposit 0.10 moles of Fe are

0.10 mol Fe × 2 mol e⁻/1 mol Fe = 0.20 mol e⁻

0.20 mol of electrons is required to deposit 5.6g of iron from a solution of iron (2) tetraoxosulphate(6)

 The reduction of iron from an aqueous solution of iron (II).

[tex]Fe^{+2} +2e^{-} \rightarrow Fe[/tex]

The formula for number of moles is as follows:-

[tex]Number \ of \ moles=\frac{Mass}{Molar\ mass}[/tex]

The molar mass of Fe is 55.85 g/mol. The moles corresponding to 5.6 g of Fe are:

[tex]5.6 g \times\frac{1\ mol}{55.85\ g} = 0.10 \ mol[/tex]

2 moles of electrons are required to deposit 1 mole of Fe. The moles of electrons required to deposit 0.10 moles of Fe are:-

[tex]0.10 mol Fe\times\frac{2\ mol\ e^{-} }{1\ mol\ e^{-}} = 0.20 \ mol e^{-}[/tex]

Hence, 0.20 mol of electrons is required to deposit 5.6g of iron.

To know more about:-

brainly.com/question/12513822

a 3.81 g sample of NaHCO3 was completely decomposed. After decomposition, Na2CO3 had mass of 2.86g. Determine mass of H2CO3 produced.

Answers

Answer:

1.67g H2CO3 are produced

Explanation:

Based on the reaction:

2NaHCO3 → Na2CO3 + H2CO3

2 moles of NaHCO3 produce 1 mole of Na2CO3 and 1 mole of H2CO3

To solve this question we need to find the moles of Na2CO3 = Moles of H2CO3. With their moles we can find the mass of H2CO3 as follows:

Moles Na2CO3 -Molar mass: 105.99g/mol-

2.86g Na2CO3 * (1mol/105.99g) = 0.02698 moles Na2CO3 = Moles H2CO3

Mass H2CO3 -Molar mass: 62.03g/mol-

0.02698 moles  * (62.03g/mol) =

1.67g H2CO3 are produced

. Why a chlorine atom with an atomic number of 17 will be negatively charged when its valance shell gains an electron.

Answers

Explanation:

When chlorine bonds and becomes stable, (had a full outer electron shell), because we know that chlorine has 7 electrons in it’s outer shell, it requires 1 to gain noble gas structure. So, when if bonds with an element and then becomes stable, the gaining of an electron means it becomes a negatively charged ion. (an ion being a charged particle.)

Between reaction of magnesium powder and lead oxide which is oxidized in the reaction and which is oxidizing agent

Answers

Answer:

Mg is oxidized and Pb is the oxidizing agent

Explanation:

Which of the following materials is acidic?

A.lemon juice
B.a baking soda solution
C.drain cleaner
D.milk of magnesia

Answers

Answer:

lemon juice............

Las lineas verticales que constituyen la regla de la lluvia se conoce como

Answers

Answer:

Lines of longitude

Explanation:

Lines of direction and lines of longitude are horizontally and vertically lines, respectively.

The phrases vertical and horizontal are frequently used to define directions: a vertical line runs up and down, whereas a horizontal line crosses.

Determine which elements or compounds are products in the
follow reaction equation:

Answers

Answer: D is the answer since it is the product of this equation

Explanation: HOPE I AM RIGHT AND IT HELPS!!!

need more explanation feel free to comment in the comment box

PLZ HELL ME WITH MY WORK​

Answers

Answer:

Ba

Explanation:

unfortunately we had to cancel it owining ....... the bad weather. ​

Answers

The missing options are;

A) in

B) to

C) of

D) about

Answer:

B: To

Explanation:

In the question, for the gap to be filled, we need to find a preposition that will show the direction of the reason for canceling.

The most appropriate one will be "to" because it is the one that most qualifies the reason for canceling as a result of bad weather.

Which of the following about a balanced chemical reactions is
NOT true?
O A properly written chemical equation will include the states of matter
for every substance in the reaction.
O The number of atoms of each element must be the same for both
reactants and products.
A balanced chemical equation must follow the Law of Conservation
of Matter
A balanced chemical equation must always include coefficients on
every reactant and product.

Answers

Answer:

A balanced chemical equation must always include coefficients on every reactant and product.

Explanation:

A balanced chemical equation does not need to include coefficients on every reactant and product.

For example, below is a balanced chemical equation in which the reactants and the products have no coefficients whatsoever:

NaOH(aq) + HCl (aq) -----> NaCl (s) + H2O (l)

Of course, a properly written chemical equation must include the states of matter of all the substances in the reaction and the number of atoms of each element must balance both in the reactant and product sides of the equation. Generally, a balanced chemical equation must obey the law of conservation of matter which opines that matter can neither be created nor destroyed but can only be converted from one form to another.

Hence, that a balanced chemical equation must always include coefficients on every reactant and product is not true.

How many Calcium (CA) atoms are in carbon tetrachloride​

Answers

Answer:

5

Explanation:

Carbon tetrachloride has molecular formula as  CCl4 , so from this it is evident that there are 4 atoms of Chlorine & 1 atom of carbon is present, in total 5 molecules are present in carbon tetra

Answer:

its 5

Explanation:

¿Que es bacteria y un virus ?
es para hoy por favor ayúdeme

Answers

i) Las bacterias son organismos microscópicos unicelulares que prosperan en diversos entornos. Estos organismos pueden vivir en el suelo, el océano y dentro del intestino humano.

ii) Un virus es un agente infeccioso submicroscópico que se replica solo dentro de las células vivas de un organismo. Los virus infectan todas las formas de vida, desde animales y plantas hasta microorganismos, incluidas bacterias y arqueas.

Los antibióticos solo son necesarios para tratar ciertas infecciones causadas por bacterias. Las enfermedades virales no pueden tratarse con antibióticos. Cuando tomar antibióticos no sea lo indicado, pídale a su profesional de atención médica consejos sobre cómo aliviar los síntomas y sentirse mejor.
Enfermedad común
Causa común
¿Se necesitan antibióticos?
Bacteria
Bacteria o virus
Virus
Infección estreptocócica de la garganta (strep)

Tosferina

Infección de las vías urinarias

Sinusitis
Tal vez
Infección del oído medio
Tal vez
Bronquitis/resfriado con congestión de pecho (en niños y adultos)*
No*
Resfriado común/moqueo
No
Dolor de garganta (excepto por infección estreptocócica)
No
Influenza (gripe)
No

Balance the following chemical equations.
Fe + H2S04 ------->Fe2(SO4)3 + H2
C2H6 + O2-------> H2O + CO2
KOH + H3PO4 ------->K3PO4 + H2O
SnO2 + H2-------> Sn + H2O
NH3 + O2 ------->NO + H2O
KNO3 + H2CO3-------> K2CO3 + HNO3
B2Br6 + HNO3 ------->B(NO3)3 + HBr
BF3 + Li2SO3 ------->B2(SO3)3 + LiF
9. (NH4)3PO4 + Pb(NO3)4-------> Pb3(PO4)4 + NH4NO3
SeCl6 + O2 ------->SeO2 + Cl2

Answers

Answer:

fe oo andffffe

aiejand iefjwe

eekkfwefwe f

opw fwfwfew

efefwefwefwi

Explanation:

Cavendish’s name for hydrogen gas was "inflammable air." The word inflammable means "to burn." (Note that in is not a prefix in this word.) Why did Cavendish use this name?

Answers

Answer:

The gas formed in the experiment could catch fire easily. So, he named the gas inflammable air.

This was the answer straight from Plato. I hope that this helped you, please mark me the brainiest, like and rate my answer if it did! :)

Explanation:

This was the answer straight from Plato. I hope that this helped you, please mark me the brainiest, like and rate my answer if it did! :)

Answer:

The gas formed in the experiment could catch fire easily. So, he named the gas inflammable air.

Explanation: your welcome

Consider the half reactions below for a chemical reaction.
ZnZn2+ (aq) + 2e
Cu?" (aq) + 2e → Cu(s)
What is the overall equation for this chemical reaction?
Zn(s)+ Cu?* (aq) —>Zn2+ (aq) + Cu(s)
O Zn(s) + Cu2+ (aq) — Cu2+ (aq) + 2e-
O Zn2*(aq) + Cu(s) —> Cu2* (aq) + Zn(s)
O Zn2+ (aq) + 22 —> Cu2(aq) + 2e

Answers

Answer:

Option A:

Zn(s) + Cu^(2+) (aq) → Cu(s) + Zn^(2+)(aq)

Explanation:

The half reactions given are:

Zn(s) → Zn^(2+)(aq) + 2e^(-)

Cu^(2+) (aq) + 2e^(-) → Cu(s)

From the given half reactions, we can see that in the first one, Zn undergoes oxidation to produce Zn^(2+).

While in the second half reaction, Cu^(2+) is reduced to Cu.

Thus, for the overall reaction, we will add both half reactions to get;

Zn(s) + Cu^(2+) (aq) + 2e^(-) → Cu(s) + Zn^(2+)(aq) + 2e^(-)

2e^(-) will cancel out to give us;

Zn(s) + Cu^(2+) (aq) → Cu(s) + Zn^(2+)(aq)

hii pls help me to balance chemical equation

calcium hydroxide + hydrochloric acid ------> calcium chloride + water​

Answers

Answer:

1 Ca(OH)2 + 2 HCl ---> 1 CaCl2 + 2 H2O

1.37 gram of cupric oxide on reduction with hydrogen gas gives 1.098gram of copper and in next experiment 1.17 gram of copper produce 1.476gram of copper oxide illustrate this satisfy law of definite proportion

Answers

Answer: This satisfies the law of definite proportion or constant proportion and it can be proven below.

Explanation:

The law of constant or definite proportion states that all pure samples of the same compound no matter how they are made; are made up of the same elements combined in the same proportion by mass. The can be verified by finding the ratio of copper to oxygen in the both experiment listed above.

In the first experiment:

1.37 g of cupric oxide contains 1.098 g copper therefore oxygen = 1.37 − 1.098

=0.272 g

The ratio of copper to oxygen is=

1.098 ÷ 0.272

= 4:1

In the SECOND or next experiment:

1.476 g of cupric oxide contains 1.17 g copper Therefore oxygen = 1.476−1.17

=0.306g

The ratio of copper to oxygen is =

=1.176 ÷ 0.306

=3.8:1

Which is approximately≃4:1.

In conclusion, despite the different methods of the experiments, composition of copper of copper in the two different samples are the same and the cupric oxide obtained from different sources contain the same elements ( copper and oxygen) combined in the SAME ratio.

In the following acid-base reaction,
Cl- is the
HCI(g) + H2O(l) →H30+(aq) + Cl(aq)
acid
base
conjugate
base

Answers

Answer:

conjugate base

Explanation:

The following equation is given in this question:

HCI(g) + H2O(l) → H30+(aq) + Cl-(aq)

In accordance to Brønsted–Lowry acid–base theory, an acid is a substance that loses an hydrogen ion (H+) or proton in an aqueous solution. This theory further indicated that the substance formed after an acid loses its hydrogen ion is called a CONJUGATE BASE.

In the above equation, HCl is the acid because it loses H+ while the substance formed after the loss of H+, which is Cl- is a conjugate base.

Write the empirical formula for the hydrated KAl(SO4)2, based on your experimental results and answer to Question 2. Show all work including units.
Hint: if the ratio of moles of H2O to moles of anhydrous KAl(SO4)2 was 4, then the empirical formula would be: KAl(SO4)2•4H2O.

Answer to Question 2:
Ratio of 2:3

Answers

Answer:

Therefore mole ratio is [tex]H_{2}O[/tex] : [tex]KAl(SO_{4} )_{2}[/tex] is 12 :1  

Empirical formula is [tex]KAl(SO_{4} )_{2}. 12 H_{2}O[/tex].

Explanation:

The chemical formula of a hydrate  

Moles of anhydrous [tex]KAl(SO_{4} )_{2}[/tex]  

Molar mass of [tex]KAl(SO_{4} )_{2}[/tex] = 258.21 g /mol  

Mass of anhydrous [tex]KAl(SO_{4} )_{2}[/tex] = [mass of aluminum cup + alum after 2nd heating] –[ mass of empty cup]  

                                                   = 3.5 g – 2.4 g  

                                                   = 1.1 g

Moles of [tex]KAl(SO_{4} )_{2}[/tex]= mass / molar mass  

                                    = 1.1 g / 258.21 g per mol  

                                   = 0.00426 mol [tex]KAl(SO_{4} )_{2}[/tex]

The mole ratio of the H2O to [tex]KAl(SO_{4} )_{2}[/tex]

Mole ratio = moles of H2O/ moles of [tex]KAl(SO_{4} )_{2}[/tex]

                  = 0.05 mol H2O / 0.00462 mol [tex]KAl(SO_{4} )_{2}[/tex]

                 = 11.7

We can round the 11.7 to closest whole number = 12

Therefore mole ratio is [tex]H_{2}O[/tex] : [tex]KAl(SO_{4} )_{2}[/tex] is 12 :1  

Empirical formula = [tex]KAl(SO_{4} )_{2}. 12 H_{2}O[/tex]  

So we have 12 moles of water as the water of hydration in the empirical formula.  

Alum hydrate is that the white crystalline solid after heating it'll start melting due to the water of hydration present in it then again solid will remain within the aluminum cup once all the water is given off within the sort of vapors.  

b) if the scholar used 2.20 g of the sample but within the calculation, he started with 2.0 g sample then  

when the mass of water is calculated using this data the mass of water is going to be higher therefore it gives more moles of water within the hydrate.  

So the final answer is going to be artificially high.

Which particles have about the same mass?
O A. Neutrons and protons
O B. Electrons and protons
O C. Electrons and neutrons
O D. Electrons, neutrons, and protons
SUBMI

Answers

Answer:

A

Explanation:

Electrons are significantly smaller than neutrons and protons.

Electrons have a diameter of less than 10^-16 centimeters, whereas protons and neutrons have a radius of about 10^-13 centimeters.

A. neutrons and protons, they are roughly the same size and electrons are much smaller

Element 'X' forms a chloride with the formula XCl2, which is a solid with high melting point. X would most likely be in the same group of the periodic table as:

I) Si
2) Al
3) Mg
4) Na



pls pls answer fast ​

Answers

Answer:

Mg

Explanation:

Mg forms 2+ ions and mgcl2 has a melting point over 700°C I believe.

Which of the following are true for an element?       (i)Atomic number= number of protons + number of electrons      (ii)Mass number = number of protons+ number of neutrons      (iii)Atomic mass= number of protons= number of neutrons      (iv)Atomic number = number of protons = number of electrons​

Answers

Answer:

ii and iv

Explanation:

atomic mass is the sum of protons and neutrons

protons ( postively charged) usually have the same number like electrons( negatively charged)

can anyone help me in my chemistry homework?​

Answers

Answer:

what is in your chemistry home work I can try for...

Answer:

1: A substance made by mixing other substances together.

2: Solutions, Suspensions, Colloids and Emulsion.

3: A particular kind of matter with uniform properties.

4: A homogenous mixture is that mixture in which the components mix with each other and its composition is uniform throughout the solution. A heterogenous mixture is that mixture in which the composition is not uniform throughout and different components are observed.

5: A solution is a homogeneous mixture of two or more components in which the particle size is smaller than 1 nm. Common examples of solutions are the sugar in water and salt in water solutions, soda water, etc. In a solution, all the components appear as a single phase.

6: A solution forms when one substance dissolves in another. The substance that dissolves is called the solute. The substance that dissolves it is called the solvent. For example, polar solvents dissolve polar solutes, and nonpolar solvents dissolve nonpolar solutes.

7: Common examples of suspension include the mixture of chalk and water, muddy water, the mixture of flour and water, a mixture of dust particles and air, fog, milk of magnesia, etc. Q2. Give the definition of suspension. Ans: A suspension is a heterogeneous mixture of two or more substances.

8: The Tyndall effect is light scattering by particles in a colloid or in a very fine suspension.

Explanation:

Cuál es tejidos conforman el sistema de tejido fundamental

Answers

Explanation:

Los tejidos que conforman el tejido fundamental son los siguientes:

-Parénquima

-Colénquima

-Esclerénquima.

El tejido fundamental constituye la parte principal del cuerpo de la planta porque intervienen en funciones tan importantes para el desarrollo  y sostenimiento de la planta como el proceso de  la fotosíntesis, el almacenamiento de agua y  de  nutrientes .

Nồng độ mol của 200ml dung dịch Nacl chứa 0,5 mol chất tan là :

Answers

Answer:

Explanation:

2,5M

Answer:

2,5m

Explanation:

c=n:v

What volume of 0.200 M Na2CO3 (Mm = 106 g/mol) solution contains 53.0 g of Na2CO3?

Question 1 options:

0.200 L of solution


0.400 L of solution


0.500 L of solution


1.60 L of solution


2.50 L of solution

Answers

Answer:

volume in Liter = 2.50 L

Explanation:

Given:

Na2CO3 = 0.2 M

Molar mass of Na2CO3 = 106 g/mol

Mass of Na2CO3 solution = 53 gram

Find:

Volume of Na2CO3

Computation:

Number of mol of Na2CO3  = (53 g) / (1.06 x 10² g/mol)

Number of mol of Na2CO3  = 0.5 mol

M = Number of mol / volume in Liter

0.2 = 0.5/ volume in Liter

volume in Liter = 0.5 / 0.2

volume in Liter = 2.50 L

what mass of aluminium is produced from 100g of aluminium oxide?

Answers

Answer:

This answer is 108g mass of aluminum is produced from 100g of aluminum oxide

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