Answer:
x = 3, x = 9
Step-by-step explanation:
When solving this problem, keep the general format of a logarithm in mind:
[tex]b^x=y\\log_b(y)=x[/tex]
Where, (b) represents the base, (x) is the exponent, and (y) is the evalutaor. Please note that others might use slightly different terminotoly than what is used in this answer.
One is given the following expression, and is asked to solve for the parameter (x);
[tex]log_5(x-4)=1-log_5(x-8)[/tex]
First, manipulate the exquestion such that all of the logarithmic expressions are on one side. Use inverse operations to do this.
[tex](log_5(x-4))+(log_5(x-8))=1[/tex]
Now use the Logarithmic Base Change rule to simplify. The Logarithmic Base Change rule states the following;
[tex]log_b(x)=\frac{log(x)}{log(b)}[/tex]
Remember, if no base is indicated in a logarithm, then the logarithm's base is (10). Apply the Logarithmic Base Change rule to this problem;
[tex]\frac{log(x-4)}{log(5)}+\frac{log(x-8)}{log(5)}=1[/tex]
Now remove the denominator. Multiply all terms in the equation by the least common denominator; ([tex]log(5)[/tex]) to remove it from the denominator on the left side.
[tex](\frac{log(x-4)}{log(5)}+\frac{log(x-8)}{log(5)}=1)*(log(5))[/tex]
[tex]log(x-4)+log(x-8)=log(5)[/tex]
All logarithms have the same base, the left side of the equation has the addition of logarithms. This means that one can apply the Logarithm product rule. The logarithm product rules the following;
[tex]log_b(x*y)=(log_b(x))+(log_b(y))[/tex]
This rule can be applied in reverse to simplify the left side of the equation. Rather than rewriting the product of logarithms as two separate logarithms being added, one can rewrite it as one logarithm getting multiplied.
[tex]log(x-4)+log(x-8)=log(5)[/tex]
[tex]log((x-4)(x-8))=log(5)[/tex]
Now used inverse operations to bring all of the terms onto one side of the equation:
[tex]log((x-4)(x-8))=log(5)[/tex]
[tex]log((x-4)(x-8))-log(5)=0[/tex]
Similar to the Logarithm product rule, the Logarithm quotient rule states the following;
[tex]log_b(x/y)=(log_b(x))-(log_b(y))[/tex]
One can apply this rule in reverse here to simplify the logarithms on the left side:
[tex]log((x-4)(x-8))-log(5)=0[/tex]
[tex]log(\frac{(x-4)(x-8)}{5})=0[/tex]
The final step in solving this equation is to use the Logarithm of (1) property. This property states the following:
[tex]log_b(1)=0[/tex]
When applying this property here, one can conclude that the evaluator must be equal to (1), therefore, the following statements can be made.
[tex]log(\frac{(x-4)(x-8)}{5})=0[/tex]
[tex]\frac{(x-4)(x-8)}{5}=1[/tex]
Inverse operations,
[tex]\frac{(x-4)(x-8)}{5}=1[/tex]
[tex](x-4)(x-8)=5[/tex]
[tex](x-4)(x-8)-5=0[/tex]
Simplify,
[tex](x-4)(x-8)-5=0[/tex]
[tex]x^2-12x+32-5=0[/tex]
[tex]x^2-12x+27=0[/tex]
Factor, rewrite the quadratic expression as the product of two linear expressions, such that when the linear expressions are multiplied, the result is the quadratic expression:
[tex]x^2-12x+27=0[/tex]
[tex](x-3)(x-9)=0[/tex]
Now use the zero product property to solve. The zero product property states that any number times (0) equals (0).
[tex]x=3,x=9[/tex]
Hello,
I suppose the question is solve for x.
[tex]\displaystyle log_5\ (a)=\dfrac{ln (a)}{ln (5)} \\\\log_5(x-4)=1-log_5(x-8)\\\\\dfrac{ln(x-4)}{ln(5)} =1- \dfrac{ln(x-8)}{ln(5)}\\\\ln(x-4)=ln(5)-ln(x-8)\\\\ln(x-4)+ln(x+8)=ln(5)\\\\ln((x-4)*(x-8))=ln(5)\\\\(x-4)*(x-8)=5\\\\x^2-12x+27=0\\\\\Delta=12^2-4*27=36=6^2\\\\x=9\ or\ x=3\\\\Sol=\{3,9\}\\[/tex]
For Moderators,
this is a mathematical resolution without any bla-bla sentences that you will easily find. (I can not do it sorry)
Match the expression with its name. 6x3 - 9x + 3
Answer:
x is 1.7 add it by three and its 18 you can do this by doing 9 times 1.7 which gets you 15 and add it with three and it equals 6 times 3
Step-by-step explanation:
A rectangle with an area of 3990 cm2 is x centimeters wide and (x+4) centimeters long. To the nearest tenth of a centimeter, the width and length are
Answer: width:60.2 cm
Length: 64.2 cm
Step-by-step explanation:
Given
The area of the rectangle is [tex]3990\ cm^2[/tex]
Width of the rectangle is [tex]x\ cm[/tex]
Length of the rectangle is [tex]x+4\ cm[/tex]
Area of the rectangle is the product of length and width
[tex]\therefore 3990=(x+4)x\\\Rightarrow 3990=x^2+4x\\\Rightarrow x^2+4x-3990=0\\\Rightarrow x=60.198\ or\ -65.198\ cm\\\text{Neglecting negative term}\\\Rightarrow x=60.198\approx 60.2\ cm[/tex]
Width of the rectangle is [tex]60.2\ cm[/tex]
Length of the rectangle is [tex]60.2+4=64.2\ cm[/tex]
Use the figure to find the Total Area.
Answer:
60
Step-by-step explanation:
Multiply length times width times height
Answer:
C or 104
Step-by-step explanation:
I assume this is surface area, and I don't know what kinda sadist person would make everyone learn in "Total Area," but it is what it is.
So, to find total area, we need to literally multiply every different number with the other.
(You should not do it the way I did, as I did it in the easiest and simpliest way to understand possible.)
Actually, you get the length, width, and height of a figure and do what is below pretty much.
You multiply the length by the width, the length by the height, and the width by the height (doesn't have to be in this order, this is just to make it easy to remember which ones you did.)
We multiply the
5 * 6
5 * 2
and then the
6 * 2
This accounts for every possible case, as multiplying 2 * 5 gives the same thing as the second expression anyways.
So we then solve these three expressions.
5 * 6 = 30
5 * 2 = 10
and then the
6 * 2 = 12
And we add them to get
30 + 10 + 12
= 52.
Then we multiply by 2, because there are two cases of each face of the shape.
You need to remember that there is 3 other faces on the shape you are looking at, it's just that the shape/figure is facing you in a way that you can't see them.
After multiplying by 2, we get
52 * 2
= 104, which is C.
TAKE A SCREENSHOT NOT A PICTURE AS WE DON'T NEED TO SEE SOME 420P MONITOR FROM 1987 THAT SHOWS EVERY PIXEL PLEASE AND THANK YOU :D
Consider triangle GHJ in the figure below.
please help :)
Answer:
The picture isnt really showing for me
Step-by-step explanation:
It's either me or the picture.
Alina has a spinner that has 5 equal sections: red, blue, green, purple, and orange. She spins the spinner 200 times. About how many times should Alina expect the spinner to land on either purple or orange?
40
80
100
120
Answer:
The answer to this question is 80 times.
Answer:
80
Step-by-step explanation:
pls anyone.. I need it
Step-by-step explanation:
here u have answer of your question dear
What is the image of (-5,-5) after a dilation by a scale factor of 3 centered at the origin
Answer:
(-15,-15)
Explanation:
The dilation of 3 to the image means that each coordinate point is multiplied by 3. So, multiplying -5*3 gets you -15.
SEE QUESTION IN IMAGE
Answer:
1.54
Step-by-step explanation:
First, we can take into account that mean = sum / number of students. Therefore, we can find the sum of each group of students, as
1.67 = sum / 20
1.50 = sum / 16
1.40 = sum / 14
Multiplying each equation by the number of students in the group to isolate the sum, we get
1.67 * 20 = 33.4
1.50 * 16 = 24
1.40 * 14 = 19.6
We can sum these up to get the total sum of all three groups of students, resulting in
33.4 + 24 + 19.6 = 77
As mean = sum / number of students, we can say that
total mean = total sum / total number of students
total mean = 77 / (20+16+14)
= 77/50
= 1.54
Simply Square Roots of 45
[tex] \sqrt{45} [/tex]
Answer:
[tex] 3\sqrt{5} [/tex]
Step-by-step explanation:
Find the largest factor of 45 that is a perfect square.
The factors of 45 are 1, 3, 5, 9, 15, 45.
The largest perfect square is 9.
Now breakup 45 into a product which has 9 as a factor.
45 = 9 * 5
[tex] \sqrt{45} = \sqrt{9 \times 5} = \sqrt{9} \times \sqrt{5} = 3\sqrt{5} [/tex]
Which expression is equivalent to
X^4
Jdnzusjdnekdjdnkdkelef
Given the function g(x) = x2 + 5x + 1, determine the average rate of change of
the function over the interval -9 < x < -2.
Answer:
-6
Step-by-step explanation:
The average rate of change of a function, f(x), on interval [a,b] is (f(b)-f(a))/(b-a).
So the avereage rate of change of a function, f(x)=x^2+5x+1, on [-9,-2] is
(f(-2)-f(-9))/(-2--9)
(f(-2)-f(-9))/(7)
Stop!
To find f(-2), you replace x in f(x) = x^2 + 5x + 1, with (-2) giving you f(-2)=(-2)^2+5(-2)+1=4-10+1=-6+1=-5.
To find f(-9), you replace x in f(x) = x^2 + 5x + 1, with (-9) giving you f(-2)=(-9)^2+5(-9)+1=81-45+1=36+1=37.
Continue!
(f(-2)-f(-9))/(7)
=(-5-37)/7
=(-42)/7
=-42/7
=-6
Simplify the following:
a. 9 sinA +33 cosec A + 10 sin A - 13 cosec A
Answer:
19 sin + 20 cosec
explanation
9 sin A + 10 sinA + 33 -13 cosecA
19 sin + 20 cosec
the population of a small city grows by 600 every year. If there were 900 people initially, find the population of the city 60 years after the city was first established
Answer:
36900
Step-by-step explanation:
It's a linear function with equation P(t)=900+600*t. P(60)=900+600*60=36900
Answer:
36,900
Step-by-step explanation:
First do 600 times 60=36,000
Next add 900
36,000+900=36,900
theres your answer :)
Suatu jenis bakteri, setiap detik akan membelah diri menjadi dua, jika pada saat permulaan ada 5 bakteri, berapakah jumlah bakteri setelah 10 detik? (geometric series=deret geometri)?
Answer:
Vc. Tính giai cấp
Step-by-step explanation:
What is the length of ST?
Answer:
14.49 inches......I think this help you.....I am not dam sure this is right or not....
Chocolate bars come in packs of 8 and graham crackers come in packs of 12. What is the smallest number of chocolate bars and graham crackers we would need to buy so we don't have any left over?
Answer:
3 chocolate bars, and 2 graham crackers
Someone forgot the marshmallows...... :P
Step-by-step explanation:
Chocolate bars = 8 pack
Graham Crackers = 12pack
To have no crackers or chocolate left over, we need to find LCM
Factors of 8:
8, 16, 24, 32, 40, 48, 56, 72....
Factors of 12:
12, 24, 36, 48, 60, 72
The smallest LCM is 24
Chocolate bars:
24/8 = 3
Graham Crackers:
24/12 = 2
If my answer is incorrect, pls correct me!
If you like my answer and explanation, mark me as brainliest!
-Chetan K
Answer:
3 packs of chocolate and 2 packs of crackers
Step-by-step explanation:
the lowest common multiple of 8 and 12 is 24. We can determine this by prime factorization:
Prime factors of 8: 2 x 2 x 2
Prime factors of 12: 2 x 2 x 3
multipyling the bottom rungs of our factor tree we get: 2 x 2 x 2 x 3 = 24.
If you need me to draw the factor tree, just ask.
Help ASAP plssss! Thanks
Points are
(-2,-2)(4,4)[tex]\\ \sf\longmapsto \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}[/tex]
[tex]\\ \sf\longmapsto \sqrt{(4+2)^2+(4+2)^2}[/tex]
[tex]\\ \sf\longmapsto \sqrt{6^2+6^2}[/tex]
[tex]\\ \sf\longmapsto \sqrt{36+36}[/tex]
[tex]\\ \sf\longmapsto \sqrt{72}[/tex]
[tex]\\ \sf\longmapsto 8.4[/tex]
Ellie wants to double her savings
of $5000 by investing her money
for 20 years.
What interest rate does
she need to look for?
Give your answer to 1 d.p.
Answer: Interest rate she needs to look for is 5%
Step-by-step explanation:
P = 5000
A = 5000*2 = 10,000
T = 20 yrs
R = ?
now
I = A-P
I = 10,000-5000
I = 5000
Now
R = 100*I/P*T
R = 100*5000/5000*20
so, R = 5%
The measures of two angles of a triangle are 36 degree and 75 degree . The length of the shortest side of a triangle is 10 cm . The length of longest side of the triangle is:?
use trigonometry to find the unknown side (round to 1 decimal)
Answer:
a = 7.5
Step-by-step explanation:
Using the sine ratio in the right triangle and the exact value
sin30° = [tex]\frac{1}{2}[/tex] , then
sin30° = [tex]\frac{opposite}{hypotenuse}[/tex] = [tex]\frac{a}{15}[/tex] = [tex]\frac{1}{2}[/tex] ( cross- multiply )
2a = 15 ( divide both sides by 2 )
a = 7.5
Joe and JoAnn each bought 12 ounces of coffee in a 16 ounce cup. Joe drank 2 ounces of his coffee and then added 2 ounces of cream. JoAnn added 2 ounces of cream, stirred the coffee well, and then drank 2 ounces. What is the resulting ratio of the amount of cream in Joe's coffee to that in JoAnn's coffee
Answer:
[tex]Ratio = 7:6[/tex]
Step-by-step explanation:
Given
Initially
[tex]Joe = 12oz[/tex] -- coffee
[tex]JoAnn = 12oz[/tex] -- coffee
Joe drank 2oz coffee; So, we have:
[tex]Joe = 12oz - 2oz[/tex]
[tex]Joe = 10oz[/tex] --- coffee
Joe added 2oz cream; So, we have:
[tex]Joe = 10oz[/tex] --- coffee [tex]Joe = 2oz[/tex] --- cream
JoAnn added 2oz cream and stirred. So, we have:
[tex]Joe = 12oz[/tex] --- coffee [tex]JoAnn = 2oz[/tex] --- cream
[tex]Total = 14oz[/tex]
JoAnn drank 2oz from the drink; the amount of drink JoAnn drank is:
[tex]JoAnn = \frac{Cream}{Total}[/tex]
[tex]JoAnn = \frac{2}{14}[/tex]
[tex]JoAnn = \frac{1}{7}[/tex]
Amount of cream left is:
[tex]Amount = [1- \frac{1}{7}] *2[/tex]
Take LCM
[tex]Amount = [\frac{7-1}{7}] * 2oz[/tex]
[tex]Amount = \frac{6}{7} * 2oz[/tex]
[tex]Amount = \frac{12}{7}oz[/tex]
So, we have:
[tex]Joe = 2oz[/tex] --- cream
[tex]JoAnn = \frac{12}{7}[/tex] cream
The ratio is:
[tex]Ratio = 2:\frac{12}{7}[/tex]
Multiply by 7
[tex]Ratio = 14:12[/tex]
Divide by 2
[tex]Ratio = 7:6[/tex]
Will give brainliest to the first person
Please decide !!!!!!!!
9514 1404 393
Answer:
6 pours
Step-by-step explanation:
Here are two 6-step solutions. The four digits represent the contents of the 9,5,4,2 containers (in that order) after a single pour. The starting condition is 9000.
Solution 1:
7002 — 9 > 27200 — 2 > 53240 — 9 > 43510 — 4 > 53312 — 5 > 23330 — 2 > 4Solution 2:
5040 — 9 > 45400 — 4 > 51440 — 9 > 41530 — 4 > 51332 — 5 > 23330 — 2 > 9An aircraft carrier can travel 450 km in the same time a container ship travels 300 km. If the aircraft carrier was travelling 5 km/h faster what was the speed of the container ship?
Answer:
10 Km/h
Step-by-step explanation:
Let the speed of the container ship be y
The speed of the aircraft = y + 5
Next, we shall determine the time taken by the aircraft to travel 450 Km. This can be obtained as follow:
Speed of aircraft (Sₐ) = y + 5
Distance travelled (dₐ) = 450 Km
Time for aircraft (tₐ) =?
Speed = distance / time
Sₐ = dₐ / tₐ
y + 5 = 450 / tₐ
Cross multiply
(y + 5) × tₐ = 450
Divide both side by (y + 5)
tₐ = 450 / (y + 5)
Finally, we shall determine the speed of the carrier. This can be obtained as follow:
Speed of container ship (S꜀) = y
Distance travelled (d꜀) = 300 Km
Time for container ship (t꜀) = Time for aircraft (tₐ)
Time for aircraft (tₐ) = 450 / (y + 5)
t꜀ = tₐ
t꜀ = 450 / (y + 5)
Speed = distance / time
S꜀ = d꜀ / t꜀
y = 300 ÷ 450 / (y + 5)
y = 300 × (y + 5) / 450
y = (300y + 1500) / 450
Cross multiply
450y = 300y + 1500
Collect like terms
450y – 300y = 1500
150y = 1500
Divide both side by 150
y = 1500 / 150
y = 10 Km/h
Thus, the speed of the container ship is 10 Km/h.
How much money will be in a bank account after 3 years if $9 is deposited at an interest rate of 5% compounded annually? Round to the nearest tenth.
Answer:
Step-by-step explanation:
$13.1
Translate the phrase into an algebraic expression.
The product of 9 and y
Answer:9*y or 9y
Step-by-step explanation:
Today, 6 friends went out for lunch. Their total bill was $27.60, including tax and gratuity. They decided to split the bill equally and each paid with a $10 bill. How much money will each person get back?
Step-by-step explanation:
Right, okay, so this is a bit of a weird one. Let's go step by step.
"Today, 6 friends went out for lunch." = The number 6 is gonna be in our equation somewhere.
"Their total bill was $27.60" = so is the number 27.6
"They decided to split the bill equally" = 27.6 "split equally" (aka divided by) 6 friends is 4.6
"each paid with a $10 bill" = This is where it gets a lil weird. So, if they divided the bill among them, none of their amounts are gonna be anywhere near ten dollars. This is one of those questions that wouldn't really happen in real life. People would probably use fives instead, but whatever. So a number we'll be using for something is 10.
"How much money will each person get back?" = So we have to find the amount they all paid (10) minus the amount each one had to pay (4.6).
To put it all into a full equation...
10 - ( 27.6 / 6 )
Divide.
10 - 4.6
Subtract.
5.4
Put back into money form.
$5.40
Answer:
Each person will get back $5.40.
Answer:
if each paid a $10 bill, in total they paid $60 (cuz 10 x 6)
60 - 27.60 = 32.4
32.4/6 = 5.4 (divide the change between 6 people)
Each person will get $5.40 back.
hope it helps :)
n the graph below determine how many real solutions the quadratic function has, and state them, if applicable. List solutions in order from left to right on the graph, or least to greatest. If the function has only one solution, type the solution in both of the boxes. If there are no real solutions type “none” in both boxes.
Answer:
There are no real solutions.
Step-by-step explanation:
There are 3 options.
2 real solutions: This happens if in the graph, each arm intersects the x-axis, this means that there are two different values of x such that the equation:
a*x^2 + b*x + c
is equal to zero.
Another way to see this, is if the determinant:
b^2 - 4*a*c
is larger than zero.
1 real solution: This happens when the vertex of the graph intersects the x-axis. This means that there is a single value of x such that:
a*x^2 + b*x + c
is equal to zero.
Another way to see this is if the determinant:
b^2 - 4*a*c
is larger equal zero.
No real solution: if in the graph we can not see any intersection of the x-axis, then we do not have real solutions (only complex ones).
Another way to see this is if the determinant:
b^2 - 4*a*c
is smaller than zero.
Now that we know this, let's look at the graph.
We can see that the vertex is below the x-axis, and the arms of the graph go downwards. So the arms will never intersect the x-axis (and neither the vertex).
So the graph does not intersect the x-axis at any point, which means that there are no real solutions for the quadratic equation.
The correct answer would be "none"
Masson misses 25% of free throws hoBew many free throws did he attempt if he missed 52
Answer:
13
Method:
Split 52 in half, then split that in half again
Answer:
208
Step-by-step explanation:
if he MISSED 52 then that's 25% of what he threw so to solve this you would go 52x4
Factorize. a^4-a^2+2a-1
Answer:
(a²-a+1)(a²+a-1)
Step-by-step explanation:
[tex]Formula\ to\ use:\\x^2-2xy+y^2=(x-y)^2\\\\x^2-y^2=(x-y)(x+y)\\\\a^4-a^2+2a-1\\\\=a^4-(a^2-2a+1)\\\\=a^4-(a-1)^2\\\\=(a^2-(a-1))(a^2+(a-1))\\\\\\=(a^2-a+1)(a^2+a-1)\\[/tex]
