Lines AB and CD (if present in the picture) are straight lines. Find x. Give reasons to justify your solutions.

Answer:

6+2+(32×2)

6+2+(64)

8+64

72

difference between 72 and 28

72-28

=44

add 44 to make the value 28

Answer:

Step-by-step explanation:

days in september=30

salry paid per day=Rs.160

salary paid in 30 days=160×30=Rs.4800

Answer:

4800

Step-by-step explanation:

In the month of September there are only 30 days. So assuming Sohanlal works the entire month of September we will multiply how much he makes daily which is 160 times the amount of days he works which is 30. this will look like this:

160 × 30 = 4800

Answer:

total candy = 54 bags

y=17

x=37

Step-by-step explanation:

5x + 4y = 253

x-y = 20

x = 20+y

5(20+y) + 4y = 253

100 + 9y = 253

9y = 153

y=17

x=37

Answer:

31.50 mm²

Step-by-step explanation:

A trapezoid is a convex quadrilateral. A trapezoid has at least on pair of parallel sides. the parallel sides are called bases while the non parallel sides are called legs

Characteristics of a trapezoid

It has 4 vertices and edges

If both pairs of its opposite sides of a trapezoid are parallel, it becomes a parallelogram

Area of a trapezoid =  1/2 x (sum of the lengths of the parallel sides) x height

1/2 x ( 7.3 + 5.3) x 5 = 31.50 mm²

Answer:

a) 1/4

b) 1/6

c) 1/12

Step-by-step explanation:

Let S be the sample space.

S={H1,H2,H3,H4,H5,H6,T1,T2,T3,T4,T5,T6}

n(s) =12

Events

A: coin with head and die with prime number .

B:coin with head and die with composite number.

C:coin with tail and die with even prime number.

a) A={H2,H3,H5}

n(A) = 3

P(A) =n(A)/n(S)

=3/12

= 1/4

b) B={H4,H6}

n(B)= 2

P(B) = n(B)/n(S)

= 2/12

= 1/6

c) C ={T2}

n(C) = 1

P(C) = n(C)/n(S)

= 1/12

It looks like the equation is

-sin²(x) = cos(2x)

Recall the half-angle identity for sine:

sin²(x) = (1 - cos(2x))/2

Then the equation can be written as

-(1 - cos(2x))/2 = cos(2x)

Solve for cos(2x):

-1/2 + 1/2 cos(2x) = cos(2x)

-1/2 = 1/2 cos(2x)

cos(2x) = -1

On the unit circle, cos(y) = -1 when y = arccos(-1) = π. Since cosine has a period of 2π, more generally we have cos(y) = -1 for y = π + 2nπ where n is any integer. Then

2x = π + 2nπ

x = π/2 + nπ

In the interval [-π, π], you get two solutions x = -π/2 and x = π/2.

Answer:

15/2 that is the answer man

Answer:

$9.04 /gal

Step-by-step explanation:

1 gallon = 128 oz

8 * 4.23 oz = 33.84 oz

$2.39 /33.84 oz = .0707 $/oz

 .0707 $/oz * 128 = $9.04 $/gal

Answer:

reflection over Y axis

Step-by-step explanation:

Answer:

I believe it is D) a reflection over the Y-axis

Step-by-step explanation

it is going over the Y-axis as if it is a sort of mirror, if it were going over the x-axis it would be flipped upside down, if it was A the shape would be going over the original shape. I don't know how to explain C. (I hope this helped and I hope it was correct lol)

Answer:

B: 0.25 = 1/4

Step-by-step explanation:

Queremos encontrar otra representación del número 0.25

Notar que hay dos decimales luego de la coma, por lo que podemos multiplicar este número y dividir por 100.

0.25 = 0.25*1 = 0.25*(100/100) = (0.25*100)/(100) = 25/100

Ahora tenemos el número escrito como una fracción, la cual debemos simplificar.

25/100

Podemos ver que tanto el numerador como el denominador son multiplos de 5, por lo que podemos dividir ambos por 5:

25/100 = (25/5)/(100/5) = 5/20

Nuevamente, ambos son multiplos de 5, por lo que podemos dividir ambos por 5.

5/20 = (5/5)/(20/5) = 1/4

así tenemos:

0.25 = 25/100 = 5/20 = 1/4

0.25 = 1/4

La opción correcta es B.

Answer:

y + 2.3 = 0.45x

y = 0.45x - 2.3

-2y = 4.2x - 7.8

-2(0.45x - 2.3) = 4.2x - 7.8

-0.90x + 4.6 = 4.2x - 7.8

-0.90x - 4.2x = -7.8 - 4.6

-5.1x = - 12.4

x = -12.4 / -5.1

x = 2.4

y + 2.3 = 0.45x

y = 0.45(2.4) - 2.3

y = 1.08 - 2.3

y = -1.2

solution is : (2.4, - 1.2)

Step-by-step explanation:

Answer:

Hello,

Answer B (-5/3,-4/3)

Step-by-step explanation:

I am going to use the substitution 's method.

[tex]\left\{\begin{array}{ccc}x+y&=&-3\\y&=&2x+2\\\end {array} \right.\\\\\\\left\{\begin{array}{ccc}y&=&2x+2\\x+2x+2&=&-3\\\end {array} \right.\\\\\\\left\{\begin{array}{ccc}y&=&2x+2\\3x&=&-5\\\end {array} \right.\\\\\\\left\{\begin{array}{ccc}x&=&-\dfrac{5}{3} \\\\y&=&2*(-\dfrac{5}{3})+2\\\end {array} \right.\\\\\\\boxed{\left\{\begin{array}{ccc}x&=&-\dfrac{5}{3} \\\\y&=&-\dfrac{4}{3}\\\end {array} \right.\\}[/tex]

Answer:

no change in area

Step-by-step explanation:

The original area is

A = 12*5 = 60 ft^2

The new length and width

l = 12 + .25 (12) = 12+3 =15

w = 5 - .2 (5) =5-1 = 4

The new area is

A = l*w =15*4 = 60 ft^2

The area is the same

=======================================================

Explanation:

Extend segment MN such that it intersects side ST. Mark the intersection as point A. See the diagram below.

We're given that angle MNT is 72 degrees. The angle TNA is equal to 180-(angle MNT) = 180 - 72 = 108 degrees, since angles MNT and TNA add to 180.

For now, focus entirely on triangle TNA. We see from the diagram that T = 34 and we just found that N = 108. Let's find angle A

A+N+T = 180

A+108+34 = 180

A+142 = 180

A = 180-142

A = 38

So angle NAT is 38 degrees.

----------------------------

Since segment MA is an extension of MN, and because MN || SQ, this means MA is also parallel to SQ.

We found at the conclusion of the last section that angle NAT was 38 degrees. Angles QST and NAT are corresponding angles. They are congruent since MA || SQ. This makes angle QST to also be 38 degrees

----------------------------

The angles QSR and QST are a linear pair, so they are supplementary

(angle QSR) + (angle QST) = 180

angle QSR = 180 - (angle QST)

angle QSR = 180 - 38

angle QSR = 142 degrees

Answer:

G. 4 cm

Step-by-step explanation:

28 divided by 7 equals 4.

So, 16 divided by 4 equals 4, which is the answer.

4 is the multiple that relates AABC to ADEF.

Answer:

Equation:  [tex]70=(x+3)x[/tex]

x = -10 or x = 7

x = 7 (width can't be negative)

x + 3 = 10

Step-by-step explanation:

Represent the width of the rectangle by  x.  "The length of a rectangle EXCEEDS the width by 3" means the length is 3 LONGER than the width, so the length is represented by the expression  x + 3.

Area = (length)(width)

70 = (x + 3)x

Multiply out the right side.

[tex]70=x^2+3x\\x^2+3x-70=0[/tex]

Factor the left side.

[tex](x+10)(x-7)=0[/tex]

Each binomial could equal 0, so

[tex]x+10=0 \text{ or }x-7=0\\x=-10\text{ or }x=7[/tex]

The negative solution does not make sense as the width of a rectangle.

x = 7, making the length, x + 3 = 10

Answer:

Pls mark this as brainiest

Step-by-step explanation:

Area of the rectangle = length x breadth

consider 'x' to be width

therefore length = x+3

area = (x+3)*x

Area = 70 square

x = 7

x+3 = 7+3

      = 10

verification

7 x 10

= 70

Answer:

Answer is in attached image

I hope it help...

Given:

The recursive formulae.

To find:

The correct explicit formulae for the given recursive formulae.

Solution:

If the recursive formula of a GP is [tex]f(n)=rf(n-1), f(1)=a, n\geq 2[/tex], then the explicit formula of that GP is:

[tex]f(n)=ar^{n-1}[/tex]

Where, a is the first term and r is the common ratio.

The first recursive formula is:

[tex]f(1)=5[/tex]

[tex]f(n)=3f(n-1)[/tex] for [tex]n\geq 2[/tex].

It is the recursive formula of a GP with a=5 and r=3. So, the required explicit formula is:

[tex]f(n)=5(3)^{n-1}[/tex]

Therefore, the required explicit formula for the first recursive formula is [tex]f(n)=5(3)^{n-1}[/tex].

If the recursive formula of an AP is [tex]f(n)=f(n-1)+d, f(1)=a, n\geq 2[/tex], then the explicit formula of that AP is:

[tex]f(n)=a+(n-1)d[/tex]

Where, a is the first term and d is the common difference.

The second recursive formula is:

[tex]f(1)=5[/tex]

[tex]f(n)=f(n-1)+5[/tex] for [tex]n\geq 2[/tex].

It is the recursive formula of an AP with a=5 and d=5. So, the required explicit formula is:

[tex]f(n)=5+(n-1)5[/tex]

[tex]f(n)=5+5(n-1)[/tex]

Therefore, the required explicit formula for the second recursive formula is [tex]f(n)=5+5(n-1)[/tex].

The third recursive formula is:

[tex]f(1)=5[/tex]

[tex]f(n)=f(n-1)+3[/tex] for [tex]n\geq 2[/tex].

It is the recursive formula of an AP with a=5 and d=3. So, the required explicit formula is:

[tex]f(n)=5+(n-1)3[/tex]

[tex]f(n)=5+3(n-1)[/tex]

Therefore, the required explicit formula for the third recursive formula is [tex]f(n)=5+3(n-1)[/tex].

Answer: 5 s

Step-by-step explanation:

Given

Height of the rocket can be modelled as [tex]h=80-16t^2[/tex]

Rocket will land on earth when it's height becomes 0

[tex]\Rightarrow 80t-16t^2=0\\\Rightarrow t(80-16t)=0\\\\\Rightarrow t=0\ \text{or}\ t=\dfrac{80}{16}=5\ s[/tex]

Neglecting 0 value

Thus, rocket remains in air for 5 s.

Answer:

Students Major

Cheat reporting response

Number of Alcohols taken

Student's Height

Step-by-step explanation:

The Variables are the following:

Categorical variables

1. Major – The student's majors -

Arts & Social Science or STEM

2. Cheat - Response about reporting cheating - Yes or No

Quantitative Variables

3. Alcohol - Number of alcoholic beverages consumed in a typical week

4. Height - Self-reported height (in inches)

Answer:

Step-by-step explanation:

There are a couple of ways you could solve this problem. B is one of them.

The correct answer is going to be Small hypotenuse / Large hypotenuse = tree / building height

Let the tree equal x

100/220 = x / 176           Multiply both sides by 176

100 * 176 / 220 = x

x = 80

Notice that 80 is almost 1/2 of 176 so the answer should be right since 100 is nearly 1/2 of 220

Explanation:

The probability of picking red is 0.13

The probability of picking orange is 0.20

The probability of picking either of these is 0.13+0.20 = 0.33

So the probability of picking neither of them is 1 - 0.33 = 0.67

There's a 67% of this happening.

Answer:

0.34

Step-by-step explanation:

because the probability of red is 20 and the probability of orange is 14 20 + 14 is 34.

Answer:

(x, y) = (5,8)

Step-by-step explanation:

Comparing the ordered pairs we get, x+y=13 and 2=2x-y. Solving it we will get, x=5 and y=8

Given:

The polygon in the given figure are similar.

To find:

The missing side length.​

Solution:

We know that the corresponding sides of similar figures are proportional.

The given polygons are similar, so the their corresponding sides are proportional.

[tex]\dfrac{x}{15}=\dfrac{32}{40}=\dfrac{32}{40}[/tex]

So, the missing values in the equation of proportion are 15, 40, 32 respectively.

On solving the above equation, we get

[tex]\dfrac{x}{15}=\dfrac{4}{5}=\dfrac{4}{5}[/tex]

[tex]\dfrac{x}{15}=\dfrac{4}{5}[/tex]

[tex]x=\dfrac{4}{5}\times 15[/tex]

[tex]x=12[/tex]

Therefore, the value of x is 12.

Answer:

Step-by-step explanation:

Total amount with Gerald = $32

Cost of fuel per gallon = $2.75

Cost of each bottle of windshield = $3

38 miles per gallon. If Gerard must fill his car with enough fuel to drive 250 miles,

Total gallons of fuel = 250 miles / 38 miles

= 6.5789473684210 gallons

Total cost of fuel = Total gallons of fuel × cost per gallon

= 6.5789473684210 × $2.75

= $18.1

Amount left for windshield = Total amount with Gerald - Total cost of fuel

= $32 - $18.1

= $13.9

what is the maximum number of bottles of windshield washer fluid Gerard can buy?

= Amount left for windshield / Cost of each bottle of windshield

= $13.9 / $3

= 4.6333333333333 bottles

Maximum number of bottles =

4 bottles

9514 1404 393

Answer:

  -19.2

Step-by-step explanation:

Fill in the given values and do the arithmetic.

  [tex]\displaystyle x\ \blacksquare\ y=\frac{x}{y}-xy\\\\4\ \blacksquare\ 5=\frac{4}{5}-4\cdot5=0.8-20\\\\\boxed{4\ \blacksquare\ 5=-19.2}[/tex]

Answer:

[tex]\displaystyle d = \sqrt{29}[/tex]

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Algebra I

Algebra II

Step-by-step explanation:

*Note:

The distance formula is derived from the Pythagorean Theorem.

Step 1: Define

Identify

Point (5, 10)

Point (10, 12)

Step 2: Find distance d

Answer:

x=-1  y = 1/3

x = 1  y = 3

x = 3  y = 27

Step-by-step explanation:

y = 3^x

Let x = -1

y = 3^-1 = 1/3^1 = 1/3

Let x = 1

y = 3^1 = 3

Let x = 3

y = 3^3 = 27