The value of the equation (fxg)(-1) is 10.
What is Equation?An equation is a mathematical statement that shows that two expressions are equal. It usually includes variables, which are represented by letters or symbols, and constants, which are fixed values.
What are the different types of Equations?There are several types of equations in mathematics. Here are some of the most common types:
Linear equation: An equation of the form "ax + b = c", where "a", "b", and "c" are constants and "x" is the variable. The graph of a linear equation is a straight line.Quadratic equation: An equation of the form "ax² + bx + c = 0", where "a", "b", and "c" are constants and "x" is the variable. The graph of a quadratic equation is a parabola.
Cubic equation: An equation of the form "ax³ + bx² + cx + d = 0", where "a", "b", "c", and "d" are constants and "x" is the variable. The graph of a cubic equation is a curve that can have one or two humps.
In the given question,
To find (f x g)(-1), we need to evaluate the product of f(-1) and g(-1).
First, we find f(-1):
f(-1) = -3(-1) - 1 = 2
Next, we find g(-1):
g(-1) = -1 - 4 = -5
Now, we can find the product (f x g)(-1):
(f x g)(-1) = f(-1) x g(-1) = 2 x (-5) = -10
Therefore, (f x g)(-1) = -10.
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In 2016, the CDC estimated the mean weight of U.S. women over the age of 20 years old was 168.5 pounds with a standard deviation of 68 pounds.
What is the expected mean for a sample of 150 women?
What is the standard deviation of the mean for a sample of 150 women?
What is the probability of 150 women having a sample mean below 160 pounds?
What is the probability of 150 women having a sample mean above 175 pounds?
What is the probability of 200 women having a sample mean below 160 pounds? Notice the change in sample size.
What is the probability of 200 women having a sample mean above 175 pounds?
Answer:
Notice the change in sample size.
Answer:
1. The expected mean for a sample of 150 women is 168.5 pounds.
2. The standard deviation of the mean for a sample of 150 women is 6.8 pounds.
3. The probability of 150 women having a sample mean below 160 pounds is 0.0849.
4. The probability of 150 women having a sample mean above 175 pounds is 0.0305.
5. The probability of 200 women having a sample mean below 160 pounds is 0.0434.
6. The probability of 200 women having a sample mean above 175 pounds is 0.0153.
The solution is given below. Notice the change in sample size.
What is probability?Probability can be defined as the ratio of the number of favorable outcomes to the total number of outcomes of an event.
here, we have,
given that,
In 2016, the CDC estimated the mean weight of U.S. women over the age of 20 years old was 168.5 pounds with a standard deviation of 68 pounds.
so. we get,
1. The expected mean for a sample of 150 women is 168.5 pounds.
2. The standard deviation of the mean for a sample of 150 women is 6.8 pounds.
3. The probability of 150 women having a sample mean below 160 pounds is 0.0849.
4. The probability of 150 women having a sample mean above 175 pounds is 0.0305.
5. The probability of 200 women having a sample mean below 160 pounds is 0.0434.
6. The probability of 200 women having a sample mean above 175 pounds is 0.0153.
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1. A living room measures 4.75 m by 5.2 m. a. What is the area of the living room? 24.7m b. The area of the game room is one and a half times that of the living room. Fi the living room and the game room.
The area of the living room is 24.7 m², and the area of the game room is 37.05 m².
What is area?Area is the measure of the two-dimensional space occupied by a figure or an object. It is usually expressed in square units such as cm2, m2, or in2. It is used to measure the size of a figure or object, and can also be used to calculate the amount of material required for a project.
The area of a living room measuring 4.75 m by 5.2 m can be calculated using the formula A = l × w, where A is the area, l is the length and w is the width. In this case, A = 4.75 m × 5.2 m = 24.7 m².
To calculate the area of the game room, we must multiply the area of the living room by 1.5. Therefore, the area of the game room is 1.5 × 24.7 m² = 37.05 m².
The area of the living room is 24.7 m², and the area of the game room is 37.05 m².
The area of a room can be used to determine how much furniture can fit in the room or how much floor space is available for activities. Knowing the area of a room is also important for calculating the cost of painting, wallpapering, carpeting, and other flooring materials.
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Decide if the events A and B are mutually exclusive or not mutually exclusive. A card is drawn from a standard deck of 52 playing cards.
Event A: The Result is a club
Event B: The result is a king
Are they mutually exclusive or not mutually exclusive?
Last years freshman class at big state university totaled 5,303 students
URGENT
The 1,262 students who received a merit scholarship, the amount they received varied per student and totaled an average of $3,458 ($454). That amount is 78.2% of the full tuition cost of $4,400.
What is merit?Merit is a term used to describe the quality of something or someone that makes them worthy of recognition or respect. It is an indicator of worthiness and is usually based on a person's ability, effort, or accomplishments. Merit is often used when evaluating an individual or a group for a promotion, hiring, or award. Merit is subjective, as different people have different standards for what merits recognition.
Therefore, 21.8% of the students who received a merit scholarship did not receive enough to cover full tuition. Therefore, the percentage of students who received a merit scholarship and did not receive enough to cover full tuition is 21%.
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What value of Y and Z will make DEF correspond to JKI?
[tex]\bold{Solution:}[/tex]
[tex]\Delta[/tex][tex]DE[/tex][tex]F[/tex] congruent to [tex]\Delta[/tex][tex]JKI[/tex]
[tex]\bold{FD=JI} \text{(corresponding angles of congruent triangles)}[/tex]
[tex]z + 22 = 3z[/tex]
[tex]\text{or,} \ z-3 z= -22[/tex]
[tex]\text{or,} \ -2z = -22[/tex]
[tex]\text{or,} \ z = \bold{11}[/tex]
[tex]\bold{EF=KI} \text{(corresponding angles of congruent triangles)}[/tex]
[tex]5y+13=6y[/tex]
[tex]\bold{y=13}[/tex]
sonny's select the options that will create the correct equation of the estimated population regression line.
The equation of the estimated population regression line is typically written in the form:
y = a + bx
where:
y is the dependent variable (or response variable)
x is the independent variable (or predictor variable)
a is the intercept (the value of y when x = 0)
b is the slope (the change in y for a unit change in x)
To create the correct equation of the estimated population regression line, Sonny should select the following options:
The variable y should be the dependent variable (or response variable).
The variable x should be the independent variable (or predictor variable).
The estimated intercept value should be plugged into the equation for a.
The estimated slope value should be plugged into the equation for b.
So, the correct equation of the estimated population regression line would be:
y = a + bx
where a and b are the estimated intercept and slope values, respectively.
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Mrs. Young has p goats and q cows on his farm. He has 23 fewer cows than goats.
What are the missing values in the table?
PLSSSS QUICK
Step-by-step explanation:
35:12
40:17
45:22
50:27
55:32
HELP ASAP PLEASE! What is the arc length of an arc with radius 18 inches and central angle 22°? Leave the answer in terms of n. Show your work.
Answer:
arc length = 2.2π inches
Step-by-step explanation:
arc length is calculated as
length = circumference of circle × fraction of circle
= 2πr × [tex]\frac{22}{360}[/tex] ( r is the radius )
= 2π × 18 × [tex]\frac{22}{360}[/tex] ( cancel 18 and 360 by 18 )
= 2π × [tex]\frac{22}{20}[/tex]
= [tex]\frac{44}{20}[/tex] π
= 2.2π inches
help plssss explainnn!!
Answer:
[tex]xy^8[/tex]
Step-by-step explanation:
Notice if you have the same base you can ADD the exponent, for example:
[tex]x^{-6} x^{7} =x^{-6+7}=x^{1 }=x[/tex]
[tex]y^{6} y^{2} =y^{6+2}=y^{8 }\\[/tex]
so the answer is
[tex]xy^8[/tex]
Question 4
Let us assume an original starting value of $4 trillion in 2033, but that the actual rate of
decline after 2033 was 10% greater than the 7.6% rate. (Notice that this refers to a 10%
relative increase over the 7.6% rate of decline that was originally estimated in the
lesson, and not an absolute increase of 10 percentage points.) In the questions below,
consider how this would affect the estimated value of the funds in 2038?
What is the new estimated value of the trust funds in 2038? Round to the nearest
The new estimated value of the trust funds in 2038 would be $2.5 trillion.
What is funds?Funds are resources of monetary value that can be used to acquire goods, services, or to meet financial obligations. They are usually obtained through the sale of goods and services or by borrowing. Funds can come from a variety of sources, including individuals, businesses, governments, and other organizations. Funds can be used to purchase assets such as stocks, bonds, real estate, or other forms of investments.
This is because a 10% relative increase over the original estimated 7.6% rate of decline means that the actual rate of decline is 8.36% (7.6% x 1.10 = 8.36%). Applying this rate to the original starting value of $4 trillion, the value of the trust funds in 2038 would be $4 trillion x 0.9164 (which is the equivalent of 1 - 0.0836) = $2.5 trillion.
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The new estimated value of the trust funds in 2038 would be $2.4 trillion.
What is trust fund?A trust fund is a legal arrangement in which a person or organization (the trustor) transfers assets to another person or organization (the trustee) to be managed and distributed for the benefit of a third party (the beneficiary). The trustor sets out a set of instructions (the trust deed) on how the trust funds should be handled, managed, and distributed. The trustee is legally bound to abide by these instructions, and is responsible for the management and distribution of the trust funds according to the trust deed. Trust funds can be used for a variety of purposes, such as providing for a beneficiary's education, medical care, or retirement.
This is because a 10% increase in the rate of decline would result in a rate of decline of 8.36% (7.6% plus 10% of 7.6%).
Using this new rate of decline, the value of the trust funds in 2038 would be $4 trillion multiplied by (1 - 0.0836)⁵,
which is equal to $2.4 trillion.
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Find dz/dt in two ways: by using the Chain Rule, and by first substituting the expressions for x and y to write z as a function of t. Do your answers agree?z= x^2y+xy^2, x = 3t y = t^2
The derivative of the function z= x^2y+xy^2, x = 3t y = t^2 using the chain rule is given by dz/dt = 36t^3 + 15t^4.
Expressions are equals to,
z= x^2y+xy^2
x = 3t
y = t^2
Using the chain rule calculate dz/dt,
which states that if z is a function of x and y,
And x and y are both functions of t, then,
dz/dt = (dz/dx)(dx/dt) + (dz/dy)(dy/dt)
Using these expressions, calculate the value of dz/dt using the chain rule,
z= x^2y+xy^2
This implies,
dz/dx = 2xy + y^2
dz/dy = x^2 + 2xy
x = 3t
⇒ dx/dt = 3
y = t^2
⇒ dy/dt = 2t
Substituting these values into the chain rule formula, we get,
dz/dt = (2xy + y^2)(3) + (x^2 + 2xy)(2t)
= [2(3t)(t^2 ) + (t^2)^2 ]3 + [(3t)^2 + 2(3t)(t^2)](2t )
= [ 6t^3 + t^4 ]3 + [ 9t^2 + 6t^3 ]2t
= 18t^3 + 3t^4 + 18t^3 + 12t^4
= 36t^3 + 15t^4
Substituting the given expressions for x and y into z, we get,
z = (3t)^2(t^2) + (3t)(t^2)^2
= 9t^4 + 3t^5
here also,
dz/dt = 36t^3 + 15t^4
Therefore, the value of the function using the chain rule dz/dt is equals to 36t^3 + 15t^4.
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part b - find the internal axial force in each bar segment using the answer for the support reaction at a determ
As per the axial force, the support reaction at A is equal in magnitude to the axial force that is applied at the other end of the bar.
To determine the support reaction at A, we will draw a free-body diagram of the bar.
Since the bar is fixed at A, the support reaction at that end will be a vertical force, and we will label it as RA.
Using Newton's second law of motion, we can write the equation of equilibrium for the bar in the vertical direction:
ΣFy = 0
where ΣFy is the sum of all the forces in the vertical direction. Since there are only two forces acting on the bar, the axial force and the support reaction, we can write:
-FA + RA = 0
where FA is the axial force that is applied at one end, and RA is the support reaction at the other end.
From this equation, we can solve for RA:
RA = FA
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Complete Question:
Determine the support reaction at A
The axially loaded bar is fixed at A and loaded as shown. Draw a free-body diagram and determine the support reaction at A.
assuming w1, w2, and w3 are 0-1 integer variables, the constraint w1 w2 w3 < 1 is often called a
The constraint w1 w2 w3 < 1, where w1, w2, and w3 are 0-1 integer variables, is often called a packing constraint. The packing constraint w1 w2 w3 < 1 limits the number of variables that can be set to 1 and is used to control the number of items that can be selected in integer programming problems.
A packing constraint is a type of constraint used in integer programming that limits the number of items that can be selected from a set of items. In this case, the constraint limits the number of variables that can take the value 1 to be less than 1.
The term "packing" comes from the idea of packing items into a container. In the context of integer programming, packing constraints are used to limit the number of items that can be "packed" into a container (i.e., set to 1), while ensuring that the total value of the packed items meets certain requirements or constraints.
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Construct a 99% confidence interval of the population proportion using the given information.
x = 75, n = 250
The 99% confidence interval for the population proportion p is :lower bound= 0.225, upper bound 0.375
What does a confidence interval actually mean?
Your estimate's mean is added to and subtracted from by the estimate's range to create a confidence interval. If you repeat your test, within a specific level of confidence, this is the range of values you anticipate your estimate to fall within.
Given that,
n = 250
x = 75
Point estimate = sample proportion = p = x / n = 75/250=0.3
1 - p =1 - 0.3=0.7
At 99% confidence level the z is ,
α = 1 - 99% = 1 - 0.99 = 0.0
α / 2 = 0.01 / 2 = 0.005
Z /2 = Z0.005 = 2.576 ( Using z table )
Margin of error = E = Zα / 2 * √(( p * (1 - p)) / n)
= 2.576 (√((0.3*0.7) /250 )
E = 0.075
A 99% confidence interval for population proportion p is ,
p - E < p < p + E
0.3 -0.075 < p < 0.3 + 0.075
0.225< p < 0.375
The 99% confidence interval for the population proportion p is :lower bound= 0.225, upper bound 0.375.
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Lionfish are considered an invasive species, with an annual growth rate of 65%. A scientist estimates there are 7,000 lionfish in a certain bay after the first year.
Part A: Write the explicit equation for f (n) that represents the number of lionfish in the bay after n years. Show all necessary math work.
Part B: How many lionfish will be in the bay after 6 years? Round to the nearest whole number and show all necessary math work.
Part C: If scientists remove 1,300 fish per year from the bay after the first year, what is the recursive equation for f (n)? Show all necessary math work.
The number of lionfish after 6 years will be 85,609. The recursive equation for [tex]f(n)[/tex] will be [tex]f(n) = 4242.42(1.65)^n - 1300n[/tex].
What is an exponent?Consider the function:
[tex]y = a (1 \pm r)^x[/tex]
Where x is the number of times this growth/decay occurs, a = initial amount, and r = fraction by which this growth/decay occurs.
lionfish are considered an invasive species, with an annual growth rate of 65%.
Then the equation will be
[tex]f(n) = P(1.65)^n[/tex]
[tex]\text{P = initial population}[/tex]
A scientist estimates there are 7,000 lionfish in a certain bay after the first year.
[tex]7000 = P(1.65)[/tex]
[tex]P = 4242.42[/tex]
Then the equation will be
[tex]f(n) = 4242.42(1.65)^n[/tex]
The number of lionfish after 6 years will be
[tex]f(n) = 4242.42(1.65)^6[/tex]
[tex]f(n) = 85608.58[/tex]
[tex]f(n) \cong 85,609[/tex]
If scientists remove 1,300 fish per year from the bay after the first year.
Then the recursive equation for f(n) will be
[tex]f(n) = 4242.42(1.65)^n - 1300n[/tex]
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PLEASEE HELP ITS DUE TONIGHT!!!
Find the area of the shaded region
Answer: 84
Step-by-step explanation:
Area of whole rectangle = lb = 11x9 = 99
Area of Inner rectangle = lb = 5x3 = 15
Area of Shaded region = Area of whole rectangle - Area of Inner rectangle
= 99 - 15
= 84
Answer:
Area of shaded region = 84 units²
Step-by-step explanation:
Area = Area of bigger - Area of smaller
[tex] { \tt{area = (11 \times 9) - (5 \times 3)}} \\ \\ { \tt{area = 99 - 15}} \\ \\ { \tt{area = 84 \: units {}^{2} }}[/tex]
If r and s are constants and r² +rx + 12 is equivalent to (x+3)(x + 5), what is the value of r?
F.:3
H. 7
J. 12
K. Cannot be determined from the given information
Answer:
H. 7
Step-by-step explanation:
Given x² + rx + 12 is equivalent to (x + 3)(x + s), equate the two expressions and expand the right side of the equation:
[tex]\begin{aligned}x^2+rx+12&=(x + 3)(x + s)\\ x^2+rx+12&=x^2 + sx + 3x + 3s\\x^2+rx+12&=x^2 + (s+3)x + 3s\end{aligned}[/tex]
To find the value of r, first find the value of s.
The constant term of the right-hand side must be equal to the constant term of the left-hand side. Therefore:
[tex]\implies 3s = 12[/tex]
Solve for s by dividing both sides of the equation by 3:
[tex]\implies s = 4[/tex]
Compare the coefficients of the terms in x:
[tex]\implies r = s + 3[/tex]
Substitute the value of s into the equation and solve for r:
[tex]\begin{aligned} \implies r &= s + 3\\&= 4 + 3\\&= 7\end{aligned}[/tex]
Therefore, the value of r is 7.
Answer:
[tex]\large\boxed{\sf r = 7 }[/tex]
Step-by-step explanation:
Correct question:- If r and s are constants and r² +rx + 12 is equivalent to (x+3)(x + s), what is the value of r?
Here we are given that , the expression (x+3)(x+s) is equal to r² + rx + 12 .
Firstly, expand the expression (x+3)(x+s) as ,
[tex]\implies (x+3)(x+s) \\[/tex]
[tex]\implies x(x+s)+3(x+s) \\[/tex]
[tex]\implies x^2 + xs + 3x + 3s \\[/tex]
Take out x as common,
[tex]\implies x^2 + (3+s)x + 3s \\[/tex]
Now according to the question,
[tex]\implies x^2 + (3+s)x + 3s = r^2 + rx + 12\\[/tex]
On comparing the respective terms , we get,
[tex]\implies r = 3 + s \\[/tex]
[tex]\implies 3s = 12 \\[/tex]
Solve the second equation to find out the value of s , so that we can substitute that in equation 1 to find "r" .
[tex]\implies 3s = 12 \\[/tex]
[tex]\implies s =\dfrac{12}{3}=\boxed{4} \\[/tex]
Now substitute this value in equation (1) as ,
[tex]\implies r = 3 + s \\[/tex]
[tex]\implies r = 3 + 4 \\[/tex]
[tex]\implies \underline{\underline{ \red{ r = 7 }}} \\[/tex]
and we are done!
Hunter is an hourly employee, and the line that models his total pay in dollars
as it relates to the number of hours he has worked has a slope of 35 and a y
intercept of 25. Which statement is true?
O A. Hunter's wage is $35 an hour, but it appears that he received no
signing bonus.
• B. Hunter's wage is $35 an hour, and it appears that he received a
signing bonus of $25.
O C. Hunter's wage is $25 an hour, but it appears that he received no
signing bonus.
• D. Hunter's wage is $25 an hour, and it appears that he received a
signing bonus of $35.
Answer: C
Step-by-step explanation:
The correct answer is C.
The slope of the line represents the hourly wage, so Hunter's wage is $35 an hour, as given in option A and B. However, the y-intercept of the line represents the starting pay or the pay for zero hours worked. In this case, the y-intercept is 25, which means Hunter received $25 even if he did not work any hours. Hence, option C is correct as it states that Hunter's wage is $25 an hour, but it appears that he received no signing bonus.
The expression 1.05x calculates what change to the value of x?
With comparison to the initial value of x, this signifies an increase of 5%.
What is an illustration of an initial value?If, for instance, we have the mathematical problem y′=2x y ′ = 2 x, then y(3)=7 y (3) = 7 is an initial value, so when these equations are combined, they create an initial-value problem.
The calculation of a 5% increase in the value of x is done by the phrase 1.05x.
We may modify the phrase as follows to understand why:
1.05x = x + 0.05x
Thus, 1.05x is the same as increasing x by 5% from its initial value.
For example, if x = 100, then:
1.05x = 1.05 × 100 = 105
The initial value of x has increased by 5% as a result of this.
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With comparison to the initial value of x, this signifies an increase of 5%. Thus, option A is correct.
What is an illustration of an initial value?If, for instance, we have the mathematical problem y′=2x y ′ = 2 x, then y(3)=7 y (3) = 7 is an initial value, so when these equations are combined, they create an initial-value problem.
The calculation of a 5% increase in the value of x is done by the phrase 1.05x.
We may modify the phrase as follows to understand why:
1.05x = x + 0.05x
Thus, 1.05x is the same as increasing x by 5% from its initial value.
For example, if x = 100, then:
1.05x = 1.05 × 100 = 105
The initial value of x has increased by 5% as a result of this.
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Complete question:
The expression 1.05x calculates what change to the value of x?
a. increase of 5%
b. Power of 5
c. decrease of 5%
d. fraction of 5
I am in my room (State 1). There is a 65% chance that I stay here and do my work like I am supposed to. There is a 35% chance I go get a snack and procrastinate (State 2). Once I have gone to get the snack, there is a 15% chance that I go back to work (go back to State 1), and there is an 85% chance that I get another snack and procrastinate further (stay in State 2).
Create a diagram and a transition matrix for this case.
Answer:
Here is a diagram and transition matrix for this case:
Diagram:
+---(0.65)---> State 1 (work)
|
Start ---+
|
+---(0.35)---> State 2 (procrastinate)
|
+---(0.15)---> State 1 (work)
|
+---(0.85)---> State 2 (procrastinate)
Transition matrix:
| State 1 | State 2 |
----------+-----------+-----------+
State 1 | 1.00 | 0.00 |
----------+-----------+-----------+
State 2 | 0.15 | 0.85 |
----------+-----------+-----------+
In the transition matrix, the rows represent the starting state and the columns represent the ending state. The entries in the matrix represent the probabilities of transitioning from the starting state to the ending state. For example, the entry in row 1 and column 2 (0.00) represents the probability of transitioning from State 1 to State 2, which is 0.00.
Let A and B be events with P(A) = 0.3, P(B) = 0.6, and P(A and B) = 0.03. Are A and B mutually exclusive? Explain why or why not.
Answer:
A and B are not mutually exclusive
Step-by-step explanation:
A and B are not mutually exclusive because P(A and B) > 0. If A and B were mutually exclusive, then they would have no outcomes in common and the probability of their intersection would be zero. However, in this case, they do share some outcomes, since P(A and B) is greater than zero.
In the inequality, x (< with line underneath) 8, represents the number of books on a shelf.
How do you know if 8 is a possible value of x?
Answer:
The numbers 8 and lower are possible values of x.
Step-by-step explanation:
The inequality [tex]x\leq 8[/tex] means x is less than or equal to 8. Therefore, 8 is a possible value of x.
4. A pet store has eight dogs and cats. Three are dogs. What fraction represents the number of cats?
A. 1/4
B. 3/8
C. 1/2
D.5/8
Answer:
Step-by-step explanation:
Number of cats = 8 - 3 = 5
Fraction that are cats [tex]=\frac{5}{8}[/tex]
for autonomous equations, find the equilibria, sketch a phase portrait, state the stability of the equilibria.
Understanding the equilibria, sketching a phase portrait, and determining the stability of equilibria for autonomous equations are important tools for analyzing and understanding the behavior of systems over time.
Autonomous equations are differential equations that do not depend explicitly on time. To find the equilibria of an autonomous equation, we set the derivative of the function to zero and solve for the values of the independent variable that satisfy the equation. These values represent points at which the function does not change over time and are known as equilibrium points.
To sketch a phase portrait for an autonomous equation, we plot the slope field of the function and then draw solutions through each equilibrium point. The resulting graph shows the behavior of the function over time and helps us understand how the solutions behave near each equilibrium point.
The stability of an equilibrium point is determined by examining the behavior of nearby solutions. If nearby solutions move toward the equilibrium point over time, the equilibrium point is stable. If nearby solutions move away from the equilibrium point over time, the equilibrium point is unstable. Finally, if the behavior of nearby solutions is inconclusive, further analysis is needed.
Here is the sketch for [tex]dx/dt = x - x^3[/tex]
/ <--- (-∞) x=-1 (+∞) ---> \
/ \
<--0--> x=-1 x=1 0-->
\ /
\ <--- (-∞) x=1 (+∞) ---> /
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any point on the parabola can be labeled (x,y), as shown. a parabola goes through (negative 3, 3)
The correct standard form of the equation of the parabola is:
[tex]y = -x^2 - 1[/tex].
To find the standard form of the equation of the parabola that passes through the given points (-3, 3) and (1, -1), we can use the general form of the equation of a parabola:
[tex]y = ax^2 + bx + c[/tex] ___________(1)
Substituting the coordinates of the two given points into this equation, we get a system of two equations in three unknowns (a, b, and c):
[tex]3 = 9a - 3b + c[/tex]
[tex]-1 = a + b + c[/tex]
To solve for a, b, and c, we can eliminate one of the variables using subtraction or addition. Subtracting the second equation from the first, we get:
[tex]4 = 8a - 4b[/tex]
Simplifying this equation, we get:
[tex]2 = 4a - 2b[/tex]
Dividing both sides by 2, we get:
[tex]1 = 2a - b[/tex]___________(2)
Now we can substitute this expression for b into one of the earlier equations to eliminate b. Using the first equation, we get:
[tex]3 = 9a - 3(2a - 1) + c[/tex]
Simplifying this equation, we get:
[tex]3 = 6a + c + 3[/tex]
Subtracting 3 from both sides, we get:
[tex]0 = 6a + c[/tex]
Solving for c, we get:
c = -6a __________(3)
Substituting this expression for c into the second equation, we get:
[tex]-1 = a + (2a - 1) - 6a[/tex]
Simplifying this equation, we get:
[tex]-1 = -3a - 1[/tex]
Adding 1 to both sides, we get:
[tex]-3a =0[/tex]
Solving for a, we get:
[tex]a = 0[/tex]
Substituting this value of a into the equation(3) for c, we get:
c = 0
Substituting a = 0 into the equation(2) for b that we found earlier, we get:
[tex]1 = 0 - b[/tex]
Solving for b, we get:
[tex]b = -1[/tex]
Putting the values of a, b and c in (1), we get
[tex]y = -x^2 - 1[/tex]
Therefore, the equation of the parabola that passes through the given points (-3, 3) and (1, -1) is:
[tex]y = -x^2 - 1[/tex]
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Complete question:
A parabola goes through (-3, 3) & (1, -1). A point is below the parabola at (-3, 2). A line above the parabola goes through (-3, 4) & (0, 4). A point on the parabola is labeled (x, y).
What is the correct standard form of the equation of the parabola?
The figure is in the image attached below
10 of 1710 of 17 Questions
Question
Katherine bought 312
pounds of oranges for $1.45
per pound, as well as 434
pounds of potatoes that cost $1.69
for 2
pounds. She gives the cashier a $10.00
bill.
Which equation represents the situation if x
is the amount of change in dollars Katherine should receive?
A 312(1.45)+434(1.69)+x=10
3 and 1 half times 1 point 4 5 plus 4 and 3 fourths times 1 point 6 9 plus x is equal to 10
B 312(1.45)+434(1.692)+x=10
3 and 1 half times 1 point 4 5 plus 4 and 3 fourths times open paren 1 point 6 9 over 2 close paren plus x is equal to 10
C 312(1.45)+434(1.692)−x=10
3 and 1 half times 1 point 4 5 plus 4 and 3 fourths times open paren 1 point 6 9 over 2 close paren minus x is equal to 10
D (312+434)⋅(1.45+1.69)+x=10
HELP ME I WILL GIVE BRAINLIEST
Answer:
6)-56+567)-/(05(-)9
Step-by-step explanation:
Question
Katherine bought 312
pounds of oranges for $1.45
per pound, as well as 434
pounds of potatoes that cost $1.69
for 2
pounds. She gives the cashier a $10.00
bill.
Which equation represents the situation if x
is the amount of change in dollars Katherine should receive?
A 312(1.45)+434(1.69)+x=10
3 and 1 half times 1 point 4 5 plus 4 and 3 fourths times 1 point 6 9 plus x is equal to 10
B 312(1.45)+434(1.692)+x=10
3 and 1 half times 1 point 4 5 plus 4 and 3 fourths times open paren 1 point 6 9 over 2 close paren plus x is equal to 10
C 312(1.45)+434(1.692)−x=10
3 and 1 half times 1 point 4 5 plus 4 and 3 fourths times open paren 1 point 6 9 over 2 close paren minus x is equal to 10
D (312+434)⋅(1.45+1.69)+x=10
HELP ME I WILL GIVE BRAINLIEST
every nonzero real number has a reciprocal. zero does not have a reciprocal. therefore, zero is not a nonzero real number
The given argument is Valid because the conclusion follows the argument logically.
The argument is that "Every nonzero real number has a reciprocal. Zero(0) does not have a reciprocal. Therefore, zero is not a non-zero real number."
The argument can be expressed in logical form as:
⇒ Premise 1: For every nonzero real number x, there exists a reciprocal 1/x.
⇒ Premise 2: Zero does not have a reciprocal.
⇒ Conclusion: Therefore, zero is not a nonzero real number.
This argument is valid because the conclusion logically follows from the premises.
The premises establish that every nonzero real number has a reciprocal, and that zero does not have a reciprocal.
The conclusion then follows logically, as zero is explicitly excluded from the set of nonzero real numbers based on the definition of a reciprocal.
Therefore, the argument is valid.
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The given question is incomplete, the complete question is
Is The Following Argument Valid Or Invalid?
Every nonzero real number has a reciprocal. Zero does not have a reciprocal. Therefore, zero is not a nonzero real number.
A company produced in the first quarter 6,905 pieces in the second quarter the same company produced 795 pieces more than in the first quarter under these conditions how many pieces did the company produce in the first semester?
Answer: 14,605 pieces.
Step-by-step explanation:
In the second quarter, the company produced 795 pieces more than in the first quarter.
So, the total pieces produced in the second quarter can be calculated as:
6905 + 795 = 7700
The total pieces produced in the first semester (two quarters) can be calculated as:
6905 + 7700 = 14,605
Therefore, the company produced 14,605 pieces in the first semester.
The number of pieces the company produced in the first semester was 14,605 pieces.
How many?The question asks to calculate how many pieces a company produced in the first semester, considering the production of two quarters.
In the first quarter, the company produced 6,905 pieces, as indicated in the question.
Already in the second quarter, the company produced 795 more pieces than in the first quarter, which means that the production in the second quarter was:
6,905 + 795 = 7,700 pieces.
To know the company's total production in the first semester, just add the productions of the two quarters:
6,905 + 7,700 = 14,605 pieces
-51+((-5+(-4)) all calculation
Answer:
the answer to that is -31
Find the definite integral of f(x)=
fraction numerator 1 over denominator x squared plus 10x plus 25 end fraction for x∈[5,7]
the definite integral of f(x) over the interval [5, 7] is (-5 / 600).
How to find?
The given function is:
f(x) = 1 / (x² + 10x + 25)
To find the definite integral of this function over the interval [5, 7], we can use the following steps:
Rewrite the function using partial fraction decomposition:
f(x) = 1 / (x² + 10x + 25)
= 1 / [(x + 5)²]
Using partial fraction decomposition, we can write this as:
f(x) = A / (x + 5) + B / (x + 5)²
where A and B are constants to be determined. Multiplying both sides by the common denominator (x + 5)², we get:
1 = A(x + 5) + B
Setting x = -5, we get:
1 = B
Setting x = 0, we get:
1 = 5A + B
= 5A + 1
Solving for A, we get:
A = 0
Therefore, the partial fraction decomposition is:
f(x) = 1 / [(x + 5)²]
= 0 / (x + 5) + 1 / (x + 5)²
Use the formula for the definite integral of a power function:
∫ xⁿ dx = (1 / (n + 1))× x²(n + 1) + C
where C is the constant of integration.
Using this formula, we can find the antiderivative of the function 1 / (x + 5)²:
∫ 1 / (x + 5)² dx = -1 / (x + 5) + C
Evaluate the definite integral over the interval [5, 7]:
∫[5,7] 1 / (x + 5)² dx
= [-1 / (x + 5)] [from 5 to 7]
= (-1 / 12) - (-1 / 10)
= (-5 / 600)
Therefore, the definite integral of f(x) over the interval [5, 7] is (-5 / 600).
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