Knowledge Check
Find x
x=

Knowledge CheckFind Xx=

Answers

Answer 1

Answer:

x is 44 Hope that helps.


Related Questions

What is the fourth root of 625

Answers

5 is the fifth root of 625 because 5•5•5•5 = 5^4 = 625

The required answer is the fourth root of 625 is 5. In summary, the fourth root of 625 is 5.

To find the fourth root of 625, we need to determine the number that, when raised to the power of 4, equals 625. Here's the step-by-step process:

Step 1: Start with the number 625.

Step 2: Take the fourth root of 625.

Since we're looking for the fourth root, we need to find a number that, when raised to the power of 4, equals 625.

Step 3: Determine the number that, when raised to the power of 4, equals 625.

To find this number, we can use the concept of exponentiation. Let's denote the unknown number as "x". Mathematically, we have [tex]x^4 = 625[/tex]..

Step 4: Solve the equation [tex]x^4 = 625[/tex].

To solve this equation, we need to find the value of x. Taking the fourth root of both sides of the equation, we have [tex]\sqrt[4]{(x^4)} =\sqrt[4] {625}.[/tex]

The fourth root of 625 is (625)^(1/4).

Step 5: Simplify the expression.

We can simplify [tex]\sqrt[4]{ 625}[/tex] as follows:

[tex]\sqrt[4]{ 625} = \sqrt[4]{ 5^4}= 5^{4/4} = 5^1 = 5.[/tex]

Therefore, the fourth root of 625 is 5. In summary, the fourth root of 625 is 5.

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Cylinders A and B are similar solids. The base of cylinder A has a circumference of 47 units. The base of cylinder B
has an area of 97 units.
The dimensions of cylinder A are multiplied by what factor to produce the corresponding dimensions of cylinder B?
+/a N/mm/~ alt

Answers

The factor that produces the corresponding dimensions of cylinder B is: 3/2.

What are Similar Solids?

Similar solids have the same shape but different sizes, and which means the ratio of their corresponding linear measurements are the same.

How to Find the Scale Factor of Similar Solids?

To find the scale factor of similar solids, you can use the formula:

scale factor = (size of the similar solid) / (size of the original solid)

For example, if you have two similar solids, one with a volume of 64 cubic units and the other with a volume of 16 cubic units, the scale factor would be:

scale factor = (16 cubic units) / (64 cubic units) = 1/4

This means that the smaller solid is 1/4 the size of the larger solid.

Given the following:

Circumference of the base of cylinder A = 4π units [the radius = 2 units]

Area of the base of cylinder B = 9π units² [the radius = 3 units]

Scale factor = radius of the base of cylinder B / radius of the base of cylinder A

Scale factor = 3/2

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Complete Question:

Cylinders A and B are similar solids. The base of cylinder A has a circumference of 4π units. The base of cylinder B has an area of 9π units. The dimensions of cylinder A are multiplied by what factor to produce the corresponding dimensions of cylinder B?

Hellllllp meeee please

Answers

Answer: 3

Step-by-step explanation: schoology whack

A lamina occupies the region inside circle x2 +y2 = 2y but outside circle x2 +y2 = 1. Find the center of mass if the density atany point is inversely proportional to its distance from theorigin.
the answer is {0, [3√3/2(3√3-π)]}

Answers

Ф {0, [3√3/2(3√3-π)]}


The poster above has good diagrams ; so , I will just go through the calculations .

The region of integration is with in the circle x ^2+y^2=2y but outside the circle   x^2+y^2=1.

I would convert to polar . With polar , we have  x^2+y^2=r^2 ,x=rcosФ and        y=rsinФ
We thus have the first circle becomes x^2+y^2=2y ⇒r^2=2rsinФ Divide through by r,  and you get r=2sinФ(1).  
This is the upper circle in the previous posters diagrams .

The other equation of a circle becomes :
x^2 + y^2 =  1  ⇒ r^2 = 1 ⇒ r =  1   (2)      
These two curves intersect at :
r= 2sinФ =1 ⇒     sinФ=1/2  ⇒Ф= [tex]\alpha[/tex]/6 or 5[tex]\pi[/tex]/6    
From the previous poster's diagrams , we can see that there is as much mass on either side of the positive. y axis or
Ф=[tex]\pi[/tex]/2 axis in polar ; so , the X  coordinate of the center of mass is zero  
X=0 We can also see from his diagrams that the mass and moment of mass is symmetrical about the Ф=[tex]\pi[/tex]/2
we only need to integrate from Ф=[tex]\pi[/tex]/6 to Ф=[tex]\pi[/tex]/2  ( the answers from to are the same and double )
The differential of area in polar coordinates is
d A=rdrdФ  They say the area mass density is inversely proportional to the distance from the origin .

This can be written as : p=k/r. We can thus say the differential of mass is
d M=PDA=

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Parallel and Perpendicular lines Block

Answers

By observing the figure we can make the pairs as

∠1 ≅ ∠3 ---------(Opposite angles)
∠2 ≅ ∠4 ---------(Opposite angles)
∠5 ≅ ∠7 ---------(Opposite angles)
∠6 ≅ ∠8 ---------(Opposite angles)
∠4 ≅ ∠6 ---------(Alternate angles)
∠3 ≅ ∠5 ---------(Alternate angles)

What are opposite angles and Alternate angles?

Opposite angles are angles that are located opposite each other, with respect to a straight line or a transversal. They are also called vertically opposite angles.

Alternate angles are angles that are located on opposite sides of the transversal and on the same side of the straight line or the transversal. They are also called corresponding angles.

In the given figure,

By observing the opposite angles and alternate angles we can fill the blocks,

∠1 ≅ ∠3 ---------(Opposite angles)

∠2 ≅ ∠4 ---------(Opposite angles)
∠5 ≅ ∠7 ---------(Opposite angles)
∠6 ≅ ∠8 ---------(Opposite angles)


∠4 ≅ ∠6 ---------(Alternate angles)

∠3 ≅ ∠5 ---------(Alternate angles)

Hence, we have found the opposite angles and alternate angles from the figure.

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What is the freezing point, in C, of a 2.75 m solution of C8H18 in benzene?

Answers

The freezing point of the 2.75 m solution of octane in benzene is -8.56 °C.

The freezing point of a solution is the temperature at which the solution becomes a solid. The freezing point of a solution is lower than the freezing point of the pure solvent because the solute particles interfere with the movement of the solvent molecules, which slows down the freezing process.

To determine the freezing point of a solution, we can use the freezing point depression equation:

ΔTf = Kf x molality

where ΔTf is the change in freezing point, Kf is the freezing point depression constant for the solvent, and molality is the concentration of the solute in the solution expressed in moles of solute per kilogram of solvent.

To find the freezing point of a 2.75 m solution of C8H18 (octane) in benzene, we need to know the freezing point depression constant for benzene, which is 5.12 °C/m. We can then use the equation above to calculate the change in freezing point:

ΔTf = 5.12 °C/m x 2.75 m = 14.06 °C

To find the freezing point of the solution, we need to subtract the change in freezing point from the freezing point of the pure solvent. The freezing point of pure benzene is 5.5 °C, so the freezing point of the 2.75 m solution of octane in benzene is:

5.5 °C - 14.06 °C = -8.56 °C

This means that the freezing point of the 2.75 m solution of octane in benzene is -8.56 °C. At this temperature, the solution will become a solid.

consider having two jars with numbers 1,23. find the probability of drawing two numbers from both the jars whose product is even

Answers

The probability of drawing two numbers from both jars whose product is even = 5/9.

Probability refers to potential. A random event's occurrence is the subject of this area of mathematics. The range of the value is 0 to 1. Mathematics has incorporated probability to forecast the likelihood of various events. The degree to which something is likely to happen is basically what probability means. You will understand the potential outcomes for a random experiment using this fundamental theory of probability, which is also applied to the probability distribution. Knowing the total number of outcomes is necessary before we can calculate the likelihood that a specific event will occur.

Total number of outcomes =9

Favorable cases = (1,2), (2,1), (3,2), (2,3), (2,2)

The probability of drawing two numbers from both the jars whose product is even = 5/9

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A video store manager observed that the number of DVDs sold seem to vary inversely as the price per DVD. If the store sells 710 DVDs per week when the price per DVD is $18.90, how many does he expect to sell if he lowers the price to $11.40.

Answers

If the price is reduced to $11.40 the number of DVDs sold will be 1177.

What is an expression?

The mathematical expression combines numerical variables and operations denoted by addition, subtraction, multiplication, and division signs.

Mathematical symbols can be used to represent numbers (constants), variables, operations, functions, brackets, punctuation, and grouping. They can also denote the logical syntax's operation order and other properties.

Given that a video store manager observed that the number of DVDs sold seems to vary inversely to the price per DVD. If the store sells 710 DVDs per week when the price per DVD is $18.90.

The number of DVDs sold for $11.40 will be calculated by forming the inverse equation for the number of DVDs.

N = K / P

Here, N is the number and P is the price and K is the inverse constant.

The value of K will be,

K = N x P

K = 18.90 x 710

K = 13419

The number of DVDs for $11.40 will be,

N = K / P

N = 13419 / 11.40

N = 1177

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(7x6)÷2[{45÷3(7×2-15+6)}+4)​

Answers

Answer:

21/79

Step-by-step explanation:

(7x6)÷2[{45÷3(7×2-15+6)}+4)​

(7*6)/2[{15(7*2-15+6)}+4)

(42)/2[{15(14-15+6)}+4)

(42)/2[{15(5))}+4)

(42)/2[{75}+4)

(42)/2[75 + 4]

(42)/2 * 79

42/2 * 79

21/79

Refer to the photo taken.

a professor at a certain school polled 12 colleagues about the number of meetings they attended in the last five years (x) and the number of papers they submitted to peer reviewed journals (y) during the same period. the summary data are as follows: n

Answers

The number of meetings they attended in the last five years (x) and the number of papers they submitted to peer reviewed journals (y) during the same period is [tex]-8.6+3.15[/tex].

What is formula for slope and intercept is?

[tex]$$\begin{aligned}& b=\frac{n \sum x y-\left(\sum x\right)\left(\sum y\right)}{n \sum x^2-\left(\sum x\right)^2} \\& a=\bar{y}-b \bar{x} \\& \hat{y}=a+b x\end{aligned}$$[/tex]

The slope is

[tex]$$\begin{aligned}b & =\frac{n \sum x y-\left(\sum x\right)\left(\sum y\right)}{n \sum x^2-\left(\sum x\right)^2} \\& =\frac{12 \times 318-(12 \times 4)(12 \times 4)}{12 \times 232-(12 \times 4)^2} \\& =3.15\end{aligned}$$[/tex]

The intercept is

[tex]$$\begin{aligned}a & =\bar{y}-b \bar{x} \\& =4-3.13 \times 4 \\& =-8.6\end{aligned}$$[/tex]

The regression equation is

[tex]$$\begin{aligned}\hat{y} & =a+b x \\& =-8.6+3.15 x\end{aligned}$$[/tex]

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Given: ABCD is a parallelogram with AE = 9x−5, AC = 14x + 34. Find AC

Answers

The value of AC according to given equation of Parallelogram is 188 units.

What is parallelogram?

In elementary geometry, a parallelogram may be a  quadrilateral with 2 pairs of parallel sides. the alternative or facing sides of a quadrangle square {measure} of equal length

Main body:

according to question:

AE = 9X-5

AC = 14X+34

as E is midpoint of AC so , we can say

2AE = AC

2(9x-5)= 14x+34

18x-10= 14x+34

4x = 44

x = 11

Now we need to find AC = 14x+34

                                         = 14*11+34

                                         = 188 units

Hence the value of AC according to given equation of Parallelogram is 188 units.

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Can you help me with this

2. Natalie is selling candles to raise money for her softball team. The team has two different options for selling the candles. The first option is to sell a package of 5 candles for $18. The second option is to sell individual candles for $4 each.
(a) The team wants to earn $1404. How many candles do the members need to sell if they sell candles only in packages? How many candles do they need to sell if they sell only single candles? Explain your answer using an equation for each situation.
(b) Describe at least one advantage of selling the candles in packages. Describe at least one disadvantage of selling the candles in packages

Answers

a) The amounts that the team needs to sell is given as follows:

Packages: 390 candles.Single candles: 351 candles.

b) The advantage and disadvantage is given as follows:

Advantage: Better opportunity cost when a person needs one candle, the person will have to purchase the entire package.Disadvantage: Lower revenue per candle.

How to obtain the amounts?

The amounts needed are found applying the proportion, considering the costs and the number of candles.

A package of 5 candles for $18, hence the number of candles needed to earn $1404, in packages, is given as follows:

5 candles - $18

n candles - $1404

Applying cross multiplication, we have that:

18n = 5 x 1404

n = 5 x 1404/18

n = 390 candles.

With a single candle, the number of candles is calculated as follows:

1404/4 = 351 candles.

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A biologist is studying a plant blight. At the start of their research, the blight covers a circular area with a radius of 5 kilometers. When they re-examine the blight two years later, the area has grown to a circular area with a radius of5.2kilometers. How rapidly did the radius change over the interval? _____Year/km

Answers

Step-by-step explanation:

Area of circle 1= pie r²

=3.14 x 5²

=3.14x 25

= 78.5km²

Area of circle 2=3.14 x 5.2²

= 3.14 x 27.04

= 84.9km²

change in area= 84.9-78.5

=6.4

radius²= 6.4/ 3.14

r²=2.03

r =√2.03

r=1.42

two different two-digit whole numbers are selected at random. what is the probability that their product is less than 200. express your answer as a common fraction. (hints: (l) there are 90 different two-digit numbers, (2) the pair {10, 11} produces the smallest product and the pair {11, 18} produces the largest product less than 200).

Answers

The probability that the product of the two two-digit numbers is less than 200 is given as follows:

43/8010.

How to calculate the probability?

A probability is calculated as the division of the number of desired outcomes in the context of the experiment by the number of total outcomes.

There are 90 different two-digit numbers, hence the number of total outcomes for the product is of:

90 x 89 = 8010.

(the numbers have to be different)

The desired outcomes which result in a product of less than 200 are of given as follows:

10 multiplied by 9 numbers, from 11 to 19.11 multiplied by 10, 12, 13, 14, 15, 16, 17, 18. (8 numbers).12 multiplied by 10, 11, 13, 14, 15, 16. (6 numbers).13 multiplied by 10, 11, 12, 14, 15 (5 numbers).14 multiplied by 10, 11, 12, 13. (4 numbers).15 multiplied by 10, 11, 12, 13. (4 numbers).16 multiplied by 10, 11, 12. (3 numbers).17 multiplied by 10, 11. (2 numbers).18 multiplied by 10, 11. (2 numbers).

Hence the number of desired outcomes is given as follows:

9 + 8 + 6 + 5 + 4 + 4 + 3 + 2 + 2 = 43.

Meaning that the probability is of:

43/8010.

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What is the equation, in stanard form, of a parabola that models the values in the table x-3 0 2 f(x) -8 -2 -28

Answers

The equation of the parabola is f(x)= 7x²+5x-2 when values of the x are -3,0,2 and the f(x) are -8,-2,-28.

Given that,

The values of the x are -3,0,2 and the f(x) are -8,-2,-28

We have to find the equation of the parabola with the x and f(x) values.

We know that,

The equation of the parabola of the form f(x) = ax²+bx+c

So,

-3a-3b+c=-8 ----->equation(1)

c=-2

2a+2b+c=-28 ------>equation(2)

Substituting c=-2 in equation(1) and equation(2)

-3a-3b-1+8=0

-3a-3b+7=0 ------>equation(3)

2a+2b-2+28=0

2a+2b+26=0 ------>equation(4)

Subtracting 2×equation(3) and 3×equation(4)

                               b=5

Substituting in equation(1)

a=7

Therefore, The equation of the parabola is f(x)= 7x²+5x-2 when values of the x are -3,0,2 and the f(x) are -8,-2,-28.

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Witch rate is equivalent to 15 milesper hours

Answers

Answer: 60 miles per 4 gallons. If that's the question.

Step-by-step explanation:

the absolute value of -7-3
negative 7 minus three

Answers

the answer is -10

-7-1=-8
-7-2=-9
-7-3=-10

Which functions have a vertex with a x-value of 0? Select three options.
Of(x) = |x|
f(x) = x + 3
f(x) = 1x + 31
f(x) = 1x1-6
Of(x) = x + 31-6

Answers

The functions that have a vertex at x = 0 are (a) f(x) = |x| and (d) f(x) = |x| - 6

How to determine the function from the vertex

From the question, we have the following parameters that can be used in our computation:

The absolute functions in the options

As a general rule;

A absolute functions can be represented as

f(x) = a|x - h| + k

Where

Vertex = (h, k)

A vertex that has x value of 0 means

(h, k) = (0, k)

So, we have

f(x) = a|x - 0| + k

Evaluate

f(x) = a|x| + k

Looking at the options, we have

f(x) = |x| and f(x) = |x| - 6

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Find the terminal point on the unit circle determined by 11π/6 radians. Use exact values, not decimal approximations.

Answers

The terminal point on the unit circle use exact values are,

( x , y ) = ( [tex]\sqrt{\frac{3}{2} }[/tex] , - [tex]\frac{1}{2}[/tex] )

Decimals are the numbers, which consist of two parts namely, a whole number part and a fractional part separated by a decimal point. For example, 12.5 is a decimal number.

According to the question, it is provided that,

θ =  11π/6 radians

Now,

x = 1.cos(11π/6)

x = cos(11π/6)

x = cos(330°)

x = [tex]\sqrt{\frac{3}{2} }[/tex]

y = 1.sin(11π/6)

y = sin(11π/6)

y = -0.5

y = - [tex]\frac{1}{2}[/tex]

Then,

( x , y ) = ( [tex]\sqrt{\frac{3}{2} }[/tex] , - [tex]\frac{1}{2}[/tex] )

These two represents the terminal points

To find the terminal positions, we merely used the aforementioned equations, equated these two equations, and concluded that the same should be taken into consideration.

It could be figure out by using the x and y points

Therefore

The terminal point on the unit circle use exact values are,

( x , y ) = ( [tex]\sqrt{\frac{3}{2} }[/tex] , - [tex]\frac{1}{2}[/tex] )

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Which statement correctly demonstrates using limits to determine a vertical asymptote of g (x) = StartFraction 2 (x + 4) squared Over x squared minus 16 EndFraction

There is a vertical asymptote at x = 4 because Limit of g (x) as x approaches 4 minus = infinity and limit of g (x) as x approaches 4 plus = negative infinity
There is a vertical asymptote at x = 4 because Limit of g (x) as x approaches 4 minus = infinity and limit of g (x) as x approaches 4 plus = infinity
There is a vertical asymptote at x = –4 because Limit of g (x) as x approaches 4 minus = infinity and limit of g (x) as x approaches 4 plus = negative infinity
There is a vertical asymptote at x = –4 because Limit of g (x) as x approaches 4 minus = negative infinity and limit of g (x) as x approaches 4 plus = infinity

Answers

The correct option that describes the vertical asymptote is; B: There is a vertical asymptote at x = 4 because Limit of g (x) as x approaches 4 minus = infinity and limit of g (x) as x approaches 4 plus = infinity

How to find the vertical asymptote of a function?

A vertical asymptote of a graph is defined as a vertical line x = a where the graph tends toward positive or negative infinity as the inputs approach a.

A vertical asymptote is a value of x for which the function is not defined, that is, it is a point which is outside the domain of a function;

In a graph, these vertical asymptotes are given by dashed vertical lines.

An example is a value of x for which the denominator of the function is 0, and the function approaches infinity for these values of x.

We are given the function;

g(x) = 2(x + 4)²/(x² - 16)

Simplifying the denominator gives;

(x² - 16) = (x + 4)(x - 4)

Thus, our function is;

g(x) = 2(x + 4)²/[(x + 4)(x - 4)]

(x + 4 ) will cancel out to give;

g(x) = 2(x + 4)/(x - 4)

Vertical asymptote:

Point in which the denominator is 0, so:

(x - 4) = 0

x = 4

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A train travels at 80 miles per hour. An equation can be written that compares the time (t) with the distance (d). What is the domain and range?

1. The domain is distance (d) and the range is time (t).

2. The domain is time (t) and the range is distance (d).

3. The domain is time (t) and the range is 80.

4. The domain is 80 and the range is time (t).

Answers

The required answer is the domain is time (t) and the range is a distance (d) i.e. Option 2.

What are domain and range?

The value range that can be plugged into a function is known as its domain. In a function like f, this set represents the x values f(x). The collection of values that a function can take on is known as its range. The values that the function outputs when we enter an x value are in this set.

From the given question, and the above definition of domain and range,

the time (t) acts as an x-values or input value and the distance (d) acts as a y-value or output value

Hence, the domain is time (t) and the range is a distance (d) i.e. Option 2.

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A chi-square test of independence is used when both variables are ___.Group of answer choices a. ratio b. ordinal c. interval d. nominal

Answers

For statement 'A chi-square test of independence is used when both variables are ___.'

b. ordinal

d. nominal

In this question we have been given a statement 'A chi-square test of independence is used when both variables are ___.'

We need to select the correct choices for the given statement.

We know that the Chi-Square Test of Independence is used to test if two categorical variables are associated.

It is a nonparametric test.

It can only compare categorical variables.

The categorical variables are classified as nominal and ordinal variables.

Chi-Square Test is used to test for a statistically significant relationship between nominal and ordinal variables.

Therefore, for a chi-square test of independence is used when both variables ordinal  and nominal.

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If line BG and CF are parallel,then the supplement of BIE = the supplement of GMD. Is this statement correct? Explain your answers

Answers

The supplement of BIE equals the supplement of GMD is a false assertion if lines BG and CF are parallel.

Describe the supplement angle.

Angles with a supplementary sum are those whose sum is 180 degrees. For instance, the total of angle 130° and angle 50° is 180°, hence they are supplementary angles.

Lines BG and CF are parallel, as shown in the figure.

If BIE = X, then its supplement of BIE will be 180 - X;

similarly, if GMD = Y, then its supplement of GMD will be 180 - Y.

Since BG and CF are parallel, the supplements of BIE and GMD are interior angles on the same side ( as shown in figure)

and for parallel line the interior angle on the same side is 180

so 180 - X and 180 -Y there sum should be 180

They cannot be equal

line BG and CF are parallel, then the supplement of BIE = the supplement of GMD are not equal.

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How could you organize the weighting and grades information differently so that Oscar's and Reagan's final grades are given by WG?

Answers

Answer i just need points

Step-by-step explanation: maybe 90

I need. Help with this question

Answers

Derivative of function is 5(2x + 4) * (x² + 4x + 6)⁴.

What is differentiation?

In arithmetic, the derivative of a function of a true variable measures the sensitivity modification of the perform price with relation to a change in its argument. Derivatives are a elementary tool of calculus.

Main body:

by using product rule;

Let = u = x² + 4x + 6

⇒ du/dx = 2x + 4 .

Now y = u⁵

⇒ dy/dx = 5u⁴ .

dy/dx = dy/dx * du/dx = 5u⁴ * (2x + 4)

= 5 * (x² + 4x + 6)⁴ * (2x + 4)

= 5(2x + 4) * (x² + 4x + 6)⁴

hence , derivative of function is 5(2x + 4) * (x² + 4x + 6)⁴.

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answer question below

Answers

The equations that represent a linear function are :

y = 2x - 94x + y = 7y = 1 / 2 x

How to know a linear function?

A linear function is a function that represents a straight line on the coordinate plane.  The degree of a linear equation must be 0 or 1 for each of its variables.

A linear function has the following form. y = mx + b.

A linear function has one independent variable and one dependent variable. The independent variable is x and the dependent variable is y.

Therefore, linear function can be represented in slope intercept form as follows;

y = mx + b

where

m = slopeb = y-intercept

Therefore, the linear function of the equations are as follows;

y = 2x - 94x + y = 7y = 1 / 2 x

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Given the drawing as shown below and that p parallel q, which of the following cannot be supported?​

Answers

Answer: It's B

Step-by-step explanation:

It shows that Angle B is congruent to angle g but it actually isnt

Answer:

B.  ∠b ≅ ∠g

Step-by-step explanation:

Supplementary angles

Two angles whose measures sum to 180°.

Linear Pair

Two adjacent angles that sum to 180° (two angles which when combined together form a straight line).

Same-side Interior Angles Theorem

When two parallel lines are intersected by a transversal, the angles that are interior to the parallel lines and on the same side of the transversal line are supplementary (sum to 180°).

Vertical Angles Theorem

When two straight lines intersect, the opposite vertical angles are congruent.

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Statement A

∠f and ∠h are vertical angles.  Therefore, according to the Vertical Angle Theorem, ∠f ≅ ∠h.

Statement C

As ∠d and ∠h are the interior angles on the same side of the transversal [tex]\ell[/tex], according to the Same-side Interior Angles Theorem, ∠d and ∠h are supplementary.

Statement D

∠a and ∠b are a linear pair, therefore ∠a and ∠b are supplementary.

Therefore, Statement B cannot be supported by the evidence shown.

Find out the missing frequency in the following incomplete distribution
CI F
0-10 3
10-20 ?
20-30 20
30-40 12
40-50 ?
The Value of median and mode are 27 and 26 respectively.

Answers

8 and 7 are missing frequency in the incomplete distribution.

What is Statistics?

Statistics is the discipline that concerns the collection, organization, analysis, interpretation, and presentation of data.

Class Interval                       frequency            Cumulative frequency                  

0 -   10                                         3                                3                

10 - 20                                         a                              3+a                

20 - 30                                       20                           23+a              

30 - 40                                        12                           35+a              

40 - 50                                         b                          35+a+b  

Mode = 26    hence lies in 20 - 30

f of modal class = 20

Mode  = 20  +  10( 20 - a) / (20 - a + 20 - 12)

26 = 20 + 10 (20 - a) / (28 - a)

60(28 - a)  = 10 ( 20 - a)

168 -6a = 200 - 10a

4a = 32

a = 8

Class Interval                       frequency            Cumulative frequency                  

0 -   10                                         3                                3                

10 - 20                                         8                                11                

20 - 30                                       20                              31              

30 - 40                                        12                              43            

40 - 50                                         b                            43+b  

Median = 27

27  =  20  + 10  ( (43 + b)/2 - 11)/ 20

7 =  ( (21 +  b)/ 4

28 =     (21 +  b)

b = 7

Hence, the missing frequencies are 8 and 7.

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Please hurry I have been stuck on this question for a while

One week, Heather opens a bank account with $125. Each week, starting the second week, she deposits $25 into her account.

What is the explicit rule for amount of money Heather has in her account after n weeks?

Enter the simplified answer in the box.

Answers

Answer:

125+25n

Step-by-step explanation:

We are given that

Heather opens a bank account with=$125

Each week she deposited money  into her account=$25

We have to find the explicit rule for the amount of money that has Heather after n weeks.

Heather has money after 1 week=125+25=$150

Heather has money after 2 week=125+2(25)=$175

Heather has money after 3 weeks=125+3(25)=$200

Heather has money after n weeks=125+25(n)

Hence, the explicit rule for the amount of money that has Heather after n weeks is given by

125+25n

i need the answers please

Answers

(7) Slope of line AB = -6/5 and Slope of the line CD = -6/5 and line AB and line CD are parallel in nature.

(8)Slope of line AB = 3/4 and the Slope of line CD = 1 and line AB and line CD is neither parallel nor perpendicular.

(9) We have drawn the graph passing through the point P and parallel to line AB.

(10)We have drawn the graph passing through the point P and perpendicular to line AB.

What is the property of slopes of parallel lines and perpendicular lines?

If two lines are given and they are parallel to each other then the slopes are equal and for perpendicular lines, the product of their slopes is equal to -1.

(7) The line AB is passing through the points (-1, 5/2) and (3/2, -1/2).

   Slope = y2 - y2/x2 - x1

              = (-1/2 - 5/2)/(3/2-(-1))

              = -6/5

   As line AB and line CD are parallel in nature so the slope of line CD is also -6/5.

(8) The line AB is passing through the points (1/2, 1) and (5/2, 5/2).

    Slope = y2 - y2/x2 - x1

              = (5/2 - 1)/(5/2-1/2)

              =3/2/2

             = 3/4

    Line CD is passing through points (1, 1) and (2, 3).

    Slope = y2 - y2/x2 - x1

              = (3 - 1)/(2-1)

              =2/2

             = 1

  As the product of their slopes is not equal to -1.

  So lines are neither parallel nor perpendicular.

(9) Slope of AB can be computed as (-2, 1) and (-5, 5)

     Slope = 5 - 1/-5 + 2

                = 4/-3.

  The slope of line passing through the point P = -4/3 as we have to draw the parallel line.

 Point P = (-1, 3)

Equation of the line :

      y - 3 = -4/3(x + 1)

    3y +9 = -4x - 4

   3y = -4x - 13

Now we can draw the line

(10) Slope of line AB = -4/3

    So the slope of the line passing through point P should be 3/4 in order to be perpendicular to line AB.

     Equation of the line passing through point P:

       y - 3 = 3/4(x - (-1))

       y - 3 = 3/4(x+1)

Hence,

(7) Slope of line AB = -6/5 and Slope of the line CD = -6/5 and line AB and line CD are parallel in nature.

(8)Slope of line AB = 3/4 and the Slope of line CD = 1 and line AB and line CD is neither parallel nor perpendicular.

(9) We have drawn the graph passing through the point P and parallel to line AB.

(10)We have drawn the graph passing through the point P and perpendicular to line AB.

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