Kim performed a transformation on rectangle ABCD to create rectangle A'B'C'D', as shown in the figure below: A(-1,2) B(-1,5) C(-3,5) D(-3,2) A'(-1,-2) B'(-1,-5) C'(-3,-5) D'(-3,-2)
What transformation did Kim perform to create rectangle A'B'C'D? (5 points)
A)Reflection across the y-axis
B)Rotation of 270 degrees counterclockwise about the origin
C)Reflection across the x-axis
D)Rotation of 90 degrees counterclockwise about the origin

Answers

Answer 1

Answer:

C) Reflection across the x-axis.

Step-by-step explanation:

From Linear Algebra we define the reflection across the x-axis is for [tex]P(x,y) =(x,y)[/tex]:

[tex]P'(x,y) = (x, -y)[/tex] (1)

If we know that [tex]A(x,y) = (-1, 2)[/tex], [tex]B(x,y) =(-1,5)[/tex], [tex]C(x,y) = (-3, 5)[/tex] and [tex]D(x,y) =(-3, 2)[/tex], then the reflected points are, respectively:

[tex]A'(x,y) = (-1, -2)[/tex]

[tex]B'(x,y) = (-1,-5)[/tex]

[tex]C'(x,y) = (-3,-5)[/tex]

[tex]D'(x,y) = (-3,-2)[/tex]

In consequence, Kim performed a reflection across the x-axis to create triangle A'B'C'D'. The correct answer is C.

Answer 2

This question is based on the reflection of x- axis. Hence the correct answer is C, reflection across the x-axis.

Given:

Transform  rectangle ABCD to rectangle A'B'C'D',

The vertices of rectangle ABCD is A(-1,2) B(-1,5) C(-3,5) D(-3,2).

The vertices of rectangle A'B'C'D is A'(-1,-2) B'(-1,-5) C'(-3,-5) D'(-3,-2).

We need to determined the transformation that Kim perform to create rectangle A'B'C'D.

From Linear Algebra we define the reflection across the x-axis is for,

P(x,y) = (x,y)

P(x,y) = (x,-y)                                .....(1)

It is given that  A(-1,2), B(-1,5), C(-3,5) and D(-3,2).

Therefore from equation (1)  above point becomes,

A'(x,y) = (-1,-2)

B'(x,y) =(-1,-5)

C'(x,y) =(-3,-5)

D'(x,y) =(-3,-2)

Therefore, It is observe that Kim performed a reflection across the x-axis to create triangle A'B'C'D'. Hence the correct answer is C, reflection across the x-axis.

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2) m =(4+√52)/2=2+√ 13 = 5.606

Step-by-step explanation

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The middle term is,  -4m  its coefficient is  -4 .

The last term, "the constant", is  -9

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Step-2 : Find two factors of  -9  whose sum equals the coefficient of the middle term, which is   -4 .

     -9    +    1    =    -8

     -3    +    3    =    0

     -1    +    9    =    8

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Equation at the end of step 1:

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2.1      Find the Vertex of   y = m2-4m-9

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Each parabola has a vertical line of symmetry that passes through its vertex. Because of this symmetry, the line of symmetry would, for example, pass through the midpoint of the two  x -intercepts (roots or solutions) of the parabola. That is, if the parabola has indeed two real solutions.

Parabolas can model many real life situations, such as the height above ground, of an object thrown upward, after some period of time. The vertex of the parabola can provide us with information, such as the maximum height that object, thrown upwards, can reach. For this reason we want to be able to find the coordinates of the vertex.

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Parabola, Graphing Vertex and X-Intercepts :

Root plot for :  y = m2-4m-9

Axis of Symmetry (dashed)  {m}={ 2.00}

Vertex at  {m,y} = { 2.00,-13.00}

m -Intercepts (Roots) :

Root 1 at  {m,y} = {-1.61, 0.00}

Root 2 at  {m,y} = { 5.61, 0.00}

Add  9  to both side of the equation :

  m2-4m = 9

Now the clever bit: Take the coefficient of  m , which is  4 , divide by two, giving  2 , and finally square it giving  4

Add  4  to both sides of the equation :

 On the right hand side we have :

  9  +  4    or,  (9/1)+(4/1)

 The common denominator of the two fractions is  1   Adding  (9/1)+(4/1)  gives  13/1

 So adding to both sides we finally get :

  m2-4m+4 = 13

Adding  4  has completed the left hand side into a perfect square :

  m2-4m+4  =

  (m-2) • (m-2)  =

 (m-2)2

Things which are equal to the same thing are also equal to one another. Since

  m2-4m+4 = 13 and

  m2-4m+4 = (m-2)2

then, according to the law of transitivity,

  (m-2)2 = 13

The Square Root Principle says that When two things are equal, their square roots are equal.

Note that the square root of

  (m-2)2   is

  (m-2)2/2 =

 (m-2)1 =

  m-2

Now, applying the Square Root Principle to  Eq. #2.2.1  we get:

  m-2 = √ 13

Add  2  to both sides to obtain:

  m = 2 + √ 13

Since a square root has two values, one positive and the other negative

  m2 - 4m - 9 = 0

  has two solutions:

 m = 2 + √ 13

  or

 m = 2 - √ 13

 

Solving    m2-4m-9 = 0 by the Quadratic Formula .

According to the Quadratic Formula,  m  , the solution for   Am2+Bm+C  = 0  , where  A, B  and  C  are numbers, often called coefficients, is given by :

                                   

           - B  ±  √ B2-4AC

 m =   ————————

                     2A

 In our case,  A   =     1

                     B   =    -4

                     C   =   -9

Accordingly,  B2  -  4AC   =

                    16 - (-36) =

                    52

Applying the quadratic formula :

              4 ± √ 52

  m  =    —————

                   2

Can  √ 52 be simplified ?

Yes!   The prime factorization of  52   is

  2•2•13

To be able to remove something from under the radical, there have to be  2  instances of it (because we are taking a square i.e. second root).

√ 52   =  √ 2•2•13   =

               ±  2 • √ 13

 √ 13   , rounded to 4 decimal digits, is   3.6056

So now we are looking at:

          m  =  ( 4 ± 2 •  3.606 ) / 2

Two real solutions:

m =(4+√52)/2=2+√ 13 = 5.606

or:

m =(4-√52)/2=2-√ 13 = -1.606

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QUICK PLZ ILL GIVE BRAINLIEST

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Answer:

13 so yeah it correect

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