Jordan is going to a friends birthday party. He couldn’t decide if he should wear a coat so he checked the weather. The weather report showed it would be -11 degrees in the morning but by the afternoon there would be a drastic increase of 73 degrees. Write an equation that represents this situation. Then find the temperature in the afternoon.
plz reply within five minutes and plz give an explanation on your process and how did you approach your problem and ofc loving the question.

Answer:

E. p - 7 + 7 = 22 + 7

Step-by-step explanation:

p - 7 + 7 = 22 + 7 ( -7 + 7 = 0)

p = 22 + 7

p - 7 = 22//

Answer:

Y: 0, x:0

Y:1, x: 3

Y: 2, x: 6

Y: 3, x:9

Step-by-step explanation:

Plug in the x to get the y

Answer:The answer is 4.06

Step-by-step explanation:

Okay I am 98% sure my math could be wrong since I don’t know what the possible answers to the question are but this is what I got.

Answer:

y - 2 = 1/3(x - 3)

Step-by-step explanation:

Point slope form is y - y1 = m(x - x1), where m is the slope and (x1, y1) is a point on the line.

Plug in the slope:

y - y1 = m(x - x1)

y - y1 = 1/3(x - x1)

Plug in the given point:

y - y1 = 1/3(x - x1)

y - 2 = 1/3(x - 3)

So, the correct answer is y - 2 = 1/3(x - 3)

Step-by-step explanation:

Given: [∀x(L(x) → A(x))] →

[∀x(L(x) ∧ ∃y(L(y) ∧ H(x, y)) → ∃y(A(y) ∧ H(x, y)))]

To prove, we shall follow a proof by contradiction. We shall include the negation of the conclusion for

arguments. Since with just premise, deriving the conclusion is not possible, we have chosen this proof

technique.

Consider ∀x(L(x) → A(x)) ∧ ¬[∀x(L(x) ∧ ∃y(L(y) ∧ H(x, y)) → ∃y(A(y) ∧ H(x, y)))]

We need to show that the above expression is unsatisfiable (False).

¬[∀x(L(x) ∧ ∃y(L(y) ∧ H(x, y)) → ∃y(A(y) ∧ H(x, y)))]

∃x¬((L(x) ∧ ∃y(L(y) ∧ H(x, y))) → ∃y(A(y) ∧ H(x, y)))

∃x((L(x) ∧ ∃y(L(y) ∧ H(x, y))) ∧ ¬(∃y(A(y) ∧ H(x, y))))

E.I with respect to x,

(L(a) ∧ ∃y(L(y) ∧ H(a, y))) ∧ ¬(∃y(A(y) ∧ H(a, y))), for some a

(L(a) ∧ ∃y(L(y) ∧ H(a, y))) ∧ (∀y(¬A(y) ∧ ¬H(a, y)))

E.I with respect to y,

(L(a) ∧ (L(b) ∧ H(a, b))) ∧ (∀y(¬A(y) ∧ ¬H(a, y))), for some b

U.I with respect to y,

(L(a) ∧ (L(b) ∧ H(a, b)) ∧ (¬A(b) ∧ ¬H(a, b))), for any b

Since P ∧ Q is P, drop L(a) from the above expression.

(L(b) ∧ H(a, b)) ∧ (¬A(b) ∧ ¬H(a, b))), for any b

Apply distribution

(L(b) ∧ H(a, b) ∧ ¬A(b)) ∨ (L(b) ∧ H(a, b) ∧ ¬H(a, b))

Note: P ∧ ¬P is false. P ∧ f alse is P. Therefore, the above expression is simplified to

(L(b) ∧ H(a, b) ∧ ¬A(b))

U.I of ∀x(L(x) → A(x)) gives L(b) → A(b). The contrapositive of this is ¬A(b) → ¬L(b). Replace

¬A(b) in the above expression with ¬L(b). Thus, we get,

(L(b) ∧ H(a, b) ∧ ¬L(b)), this is again false.

This shows that our assumption that the conclusion is false is wrong. Therefore, the conclusion follows

from the premise.

15

Answer:

"there is exactly one output for each input" is cotrrect

"the graph of a linear function" is correct

Step-by-step explanation:

Answer:

[tex]\displaystyle x \approx 9.9[/tex]

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Equality Properties

Trigonometry

Step-by-step explanation:

Step 1: Define

Identify variables

Angle θ = 64°

Opposite Leg = x

Hypotenuse = 11

Step 2: Solve for x

Answer:

F(-2)= g(-2)

Step-by-step explanation:

F(-2)= g(-2), both function have the same points of intersect.

Answer:

[tex]\triangle FED\sim \triangle JEH[/tex]

Step-by-step explanation:

Both pairs of vertical angles formed at point E are equal. Therefore, the two triangles share two angles. If two triangles share two angles, they must also share the third angle, since the sum of the interior angles of a triangle add up to 180 degrees. Therefore, all three angles of the two triangles are equal, which is a proof of similarity. [tex]\implies \boxed{\triangle FED\sim \triangle JEH}[/tex]

9514 1404 393

Answer:

  ΔDEF ~ ΔHEJ

Step-by-step explanation:

The vertical angles at E are congruent, and the marked angles at F and J are congruent. The two triangles are similar by the AA postulate.

The given portion of the similarity statement names the angles in the order "unspecified", "vertical", and "50°". If we name those angles in the same order in the other triangle, the similarity statement becomes ...

  ΔDEF ~ ΔHEJ

Answer:

No choices listed.

Step-by-step explanation:

9514 1404 393

Answer:

  5/8

Step-by-step explanation:

Since the ratio is common, it can be found from the ratio of any pair of adjacent terms.

  r = 480/768 = (5·96)/(8·96) = 5/8

The common ratio is 5/8.

Answer:

[tex]Pr =\frac{1}{3}[/tex]

Step-by-step explanation:

Given

[tex]S = \{(1, 1) (1, 2) (1, 3) (1, 4) (1, 5) (1, 6)(2, 1) (2, 2) (2, 3) (2, 4) (2, 5) (2, 6)[/tex]

[tex](3, 1) (3, 2) (3, 3) (3, 4) (3, 5) (3, 6)(4, 1) (4, 2) (4, 3) (4, 4) (4, 5) (4, 6)[/tex]

[tex](5, 1) (5, 2) (5, 3) (5, 4) (5, 5) (5, 6)(6, 1) (6, 2) (6, 3) (6, 4) (6, 5) (6, 6)\}[/tex] --- sample space

First, list out all outcomes whose sum is divisible by 5

[tex]A = \{(4,6), (5,5),(6,4)\}[/tex]

So, we have:

[tex]n(A) = 3[/tex]

Next, list out all outcomes that has an outcome of 5 in both rolls

[tex]B = \{(5,5)\}[/tex]

[tex]n(B) =1[/tex]

The required conditional probability is:

[tex]Pr =\frac{n(B)}{n(A)}[/tex]

[tex]Pr =\frac{1}{3}[/tex]

Answer:

[tex]4(3x)^{\frac{3}{2} }[/tex]

Step-by-step explanation:

Answer:

Step-by-step explanation:

Given that:

[tex]y^2 (y^2-4) = x^2(x^2 -5)[/tex]

at point (0, -2)

[tex]\implies y^4 -4y^2 = x^4 -5x^2[/tex]

Taking the differential from the equation above with respect to x;

[tex]4y^3 \dfrac{dy}{dx}-8y \dfrac{dy}{dx}= 4x^3 -10x[/tex]

Collect like terms

[tex](4y^3 -8y)\dfrac{dy}{dx}= 4x^3 -10x[/tex]

[tex]\dfrac{dy}{dx}= \dfrac{4x^3 -10x}{4y^3-8y}[/tex]

Hence, the slope of the tangent line m can be said to be:

[tex]\dfrac{dy}{dx}= \dfrac{4x^3 -10x}{4y^3-8y}[/tex]

At point (0,-2)

[tex]\dfrac{dy}{dx}= \dfrac{4(0)^3 -10(0)}{4(-2)^3-8-(2)}[/tex]

[tex]\dfrac{dy}{dx}= \dfrac{0 -0}{4(-8)+16}[/tex]

[tex]\dfrac{dy}{dx}= 0[/tex]

m = 0

So, we now have the equation of the tangent line with slope m = 0 moving through the point (x, y) = (0, -2) to be:

(y - y₁ = m(x - x₁))

y + 2 = 0(x - 0)

y + 2 = 0

y = -2

Answer:

y=-3x-5

Step-by-step explanation:

(-1, -2) (0, -5)

use slope formula

ΔY = (-5 – -2) = -3

ΔX = (0 – -1) = 1

m = -3

y=mx+b

-5 = -3(0)+b

b = -5

y=-3x-5

Answer:

The answer is C

Hope this helped!

Answer: B

Step-by-step explanation:

Answer:

-5ºC < 5ºC is an inequality that compares temperatures.

B is the correct answer for the multiple choice question.

Answer:

Hi, there the answer is

These are the equations with exactly one solution

-5x + 12 = –12x – 12

-5x + 12 = 5x + 12

-5x + 12 = 5x – 5

Hope This Helps :)

Step-by-step explanation:

First degree equations

A first degree equation has the form

ax + b = 0

There are some special cases where the equation can have one, infinitely many or no solution

If , the equation has exactly one solution

If a=0 and b=0 the equation has infinitely many solutions, because it doesn't matter the value of x, it will always be true that 0=0

If a=0 and  the equation has no solution, because it will be equivalent to b=0 and we are saying it's not true. No matter what x is, it's a false statement.

We have been given some equations, we only need to put them in standard form

-5x + 12 = –12x – 12

Rearranging

7x + 24 = 0

It has exactly one solution because a is not zero

.......................

-5x + 12 = 5x + 12

Rearranging

-10x + 0 = 0

It has exactly one solution because a is not zero

.......................

-5x + 12 = 5x – 5

Rearranging

-10x + 17 = 0

It has exactly one solution because a is not zero

.......................

-5x + 12 = -5x – 12

Rearranging

0x + 24 = 0

It has no solution, no matter what the value of x is, it's impossible that 24=0

Answer: These are the equations with exactly one solution

-5x + 12 = –12x – 12

-5x + 12 = 5x + 12

-5x + 12 = 5x – 5

Answer:

90

Step-by-step explanation:

there is 6 sides of box

2 bigger and 4 smaller

area of bigger side is 5×5 = 25 this is the area of one side as we have 2 sides so are of both sides is 25 + 25 = 50

now come to the smaller sides ( we have 4 here)

are of one side is 2× 5 = 10

so are of all 4 sides is 10× 4 = 40

now we get area of 4 smaller sides and 2 bigger sides

total area of box is 40+ 50 = 90

hope you understand

9514 1404 393

Answer:

  ΔWZT ~ ΔWXY

Step-by-step explanation:

Angle XWY and angle ZWT are vertical angles, so congruent.

The sides on either side of those angles are proportional:

  WZ/WX = WT/WY

  11/22 = 10/20 = 1/2

so, we can claim similarity by the SAS Theorem.

  ΔWZT ~ ΔWXY

Answer:

320 square feet.

Step-by-step explanation:

For the moment, let's put the square back in place. That would make the length 16 + 8 = 24 and the width 16.

L = 24

W = 16

Area = L * W

Area = 24 * 16

Area = 384

Now the next step is to take out the square. It is 8 * 8 = 64

The area of the figure = 384 - 64 = 320 square feet, and that's the answer.

Answer:

320 in^2

Step-by-step explanation:

we need to find the area of this figure

Firstly divide above picture in two parts

1st figure = (16*16)in.

2nd figure = (8*8)in.

Area of 1st figure = 16*16 = 256 in^2

Area of 2nd figure = 8*8 = 64 in^2

Area of whole figure = ( 256 + 64 )in^2

= 320 in^2

Step-by-step explanation:

we can simplify the stuff inside the parentheses to

[tex] \frac{ {x}^{3} }{2y} [/tex]

now we need to multiply it with itself, giving us

[tex] \frac{ {x}^{6} }{4 {y}^{2} } [/tex]

so yeah, D is the correct answer

Answer:

11.7

Step-by-step explanation:

39.1 - 9.2 = 29.9

29.9 - 18.2 = 11.7

Answer:

- 9 + 9i

Step-by-step explanation:

(- 7 + 3i) - (2 - 6i)

- 7 + 3i - 2 + 6i

- 7 - 2 + 9i

- 9 + 9i