Given:
The area of rectangular garden is [tex]x^2-4x-21[/tex] square units.
To find:
The length and width of the cucumber field.
Solution:
The area of a rectangle is:
[tex]A=l\times w[/tex]
Where l is length and w is width of the rectangle.
The area of rectangular garden is [tex]x^2-4x-21[/tex] square units.
We need to find the factors of [tex]x^2-4x-21[/tex] to get the length and width.
[tex]A=x^2-4x-21[/tex]
Splitting the middle term, we get
[tex]A=x^2-7x+3x-21[/tex]
[tex]A=x(x-7)+3(x-7)[/tex]
[tex]A=(x-7)(x+3)[/tex]
Area of a rectangle is the product of length and width.
Therefore, the length and width of the rectangle are [tex](x-7)[/tex] units and [tex](x+3)[/tex] units.
If 12x = 60, what is the last step to solve for x?
A. multiply 12 to both sides
B. subtract 12 from both sides
C. add 12 to both sides
D. divide 12 from both sides
Answer:
D. divide 12 from both sides
Step-by-step explanation:
12x = 60,
Divide each side by 12
12x/12 = 60/12
x = 5
We have to find,
The last step to solve for x,
→ 12x = 60
Then use option (D),
D. divide 12 from the both sides,
→ 12x = 60
→ 12x/12 = 60/12
→ x = 5
Hence, option (D) is last step.
if 5 miles is 8km . Convert 33.7 km into miles
Answer:
20.94021
Step-by-step explanation:
mark me brainlist
Answer:
53.92
Step-by-step explanation:
5 miles = 8 km
1 miles = 1.6 km
33.7 x 1.6 = 53.92
[tex]\frac {n! + (n + 1)!} {n!}[/tex]
help me in this please
(n! + (n + 1)!) / n! = n!/n! + (n + 1)!/n! = 1 + (n + 1) = n + 2
because (n + 1)! = (n + 1)n!.
Um criador de ovelhas possui um total de 36 ovelhas e resolveu vender alguma delas no primeiro dia vendeu metade das ovelhas no segundo dia vendeu um terço e no terceiro dia vendeu a nona parte quantas abelhas sobraram?
Answer:
2 sheep
Step-by-step explanation:
If you have 36 sheep and you sell:
first day 1/2 of them you sold 18
second day 1/3 them you sold 12
On thhe third day 1/9 them you sold 4
Therefore you sold 18 + 12 + 4 = 34
And you still have 2 sheep
9. Solve the system of equations using substitution.
3y = -5x+2.
y = -x + 9
Answer:
y=43/2
Step-by-step explanation:
Find the distance between the lines with equations 7x-2y-2=0 and y=7/2x-10?
a. 2.47 b. 2.48 c. 2.5 d. 2.49
Answer:
the distance between the lines is 2.48
Find the value of each variable.
4V3
b
60°
45°
C
d
Answer:
a = 6, b = 6√2, c = 2√3, d = 6
Step-by-step explanation:
Applying,
sin60° = a/4√3
Therefore,
a = sin60°×4√3
a = (√3/2)(4√3)
a = 3×2
a = 6
Also,
cos60 = c/4√3
c = cos60×4√3
c = 0.5×4√3
c = 2√3
also,
tan45 = a/d
d = a/tan45
d = 6/(1)
d = 6
Also,
sin45 = a/b
b = a/sin45
b = 6/(1/√2)
b = 6√2
Solve using suitable properties. Also mention the names of the property used. -3/4 × 4/5 - 1/2 × 1/4 +4/5 × 7/5
Answer:
0.395
Step-by-step explanation:
We need to solve the given expression.
[tex]-\dfrac{3}{4}\times \dfrac{4}{5}-\dfrac{1}{2}\times\dfrac{1}{4}+\dfrac{4}{5}\times \dfrac{7}{5}[/tex]
We can also write it as :
[tex]-\dfrac{3}{4}\times \dfrac{4}{5}+\dfrac{4}{5}\times \dfrac{7}{5}-\dfrac{1}{2}\times\dfrac{1}{4}\\\\=\dfrac{4}{5}(\dfrac{-3}{4}+\dfrac{7}{5})-\dfrac{1}{2}\times\dfrac{1}{4}[/tex](Distributive property is used)
So,
[tex]=\dfrac{4}{5}\times \dfrac{13}{20}-\dfrac{1}{2}\times\dfrac{1}{4}\\\\=\dfrac{4}{5}\times \dfrac{13}{20}-\dfrac{1}{8}\\\\=\dfrac{13}{25}-\dfrac{1}{8}\\\\=0.395[/tex]
So, the value of the given expression is equal to 0.395.
40 points if helped question is in the picture
Answer:
15 9 3
Step-by-step explanation:
15 9 3
sorry i guessed on this one
but it does work
when they said 3 in the first sentence i helped me guess
Answer:
first term = 15
second term = 9
Third term = 3
Step-by-step explanation:
Let the first term be 3x
Let the second term be = 3x - 6 [ 6 less than first term]
Let the third term be = 1/5 of 3x
[tex]=\frac{1}{5} \times 3x\\\\=\frac{3}{5}x[/tex]
Difference between first and third term = 12
That is ,
[tex]3x - \frac{3}{5}x = 12\\\\\frac{(3x \times 5) - 3x }{5} = 12\\\\15x - 3x = 12 \times 5\\\\12x = 60\\\\x = \frac{60}{12} = 5\\\\Therefore , \ first \ term = 3x = 3 \times 5 = 15\\\\second \term = 3x - 6 = 3( 5) - 6 = 15 - 6 = 9\\\\Third \ term = \frac{1}{5} \times 3x = \frac{1}{5} \times (3 \times 5) = 3[/tex]
Jalen's Mobile Phone Cost Number of minutes, x 150 220 250 275 Cost, y $7.50 $11.00 $12.50 $13.75 If the cost varies directly with the number of minutes Jalen talks on the phone, which equation represents the variation?
Answer:
ok so on the left ill put minutes and on the right ill put dollars
150=7.50
220=11.00
250=12.50
275=13.75
so now lets break this down by dividing the smallest numbers by 2 a couple times
75=3.75(2)
25=1.25(3)
1=0.05(25)
so for every minute on the phone you pay 5 cents
Hope This Helps!!!
Answer:
for every minute on the phone you pay 5 cents, add brainly plz.
Step-by-step explanation:
solve for the measure of x in the drawing shown below
Answer:
50
Step-by-step explanation:
x° = 1/2 * 100°
x° = 50°
x = 50
Find the value of x.
Answer:
The value of x is 18°
Step-by-step explanation:
Sum of the angles are 180°
3x+126=180
3x=180-126
3x=54
x=18
Answered by GAUTHMATH
you have some marbles. when you make a shape of an equilateral triangle, you either have 5 extra, or you need 10 more to complete the shape, how many marbles do you have? how long is one side of your triangle?
I'm giving brainliest to correct answer!
Answer:
110 marbles
side 14
Step-by-step explanation:
Draw triangles using marbles as the sides.
If the side is 2 marbles long, the triangle uses 3 marbles. 1 + 2 = 3
If the side is 3 marbles long, the triangle uses 6 marbles. 1 + 2 + 3 = 6
If the side is 4 marbles long, the triangle uses 10 marbles. 1 + 2 + 3 + 4 = 10
If the side is n marbles long, the triangle uses n(n + 1)/2 marbles.
These numbers are called triangular numbers.
We are looking for the side, n.
n(n + 1)/2 + 5 = (n + 1)(n + 2)/2 - 10
n^2 + n + 10 = n^2 + 3n + 2 - 20
n + 10 = 3n - 18
-n = -14
n = 14
For n = 14
n(n + 1)/2 =
= 14(15)/2
= 105
For n = 15
n(n + 1)/2 =
= 15(16)/2
= 120
105 + 5 = 120 - 10
You have 110 marbles. If you had 5 fewer, 105, you'd have a triangle with sides 14. If you had 10 more, 120, you'd have a triangle with sides 15. Since you have 110, you have 5 too many for side 14 and 10 too few for side 15.
The sides of the triangle is 14.
Find the circumference of a circle with diameter,
d
= 8cm.
Give your answer rounded to 3 SF.
Answer:
25.1 cm
Step-by-step explanation:
c = πd
c = π*8
c = 25.1327412287
Rounded
c = 25.1 cm
Solve for x and y:
x – 3y = -8
3x + 2y = 31
Select one:
O a. (-11,-1)
O b. (11,1)
o c. (5,8)
O d. (7,5)
Answer:
O d. (7,5)
Step-by-step explanation:
x – 3y = -8 (1)
3x + 2y = 31 (2)
From (1)
x = -8 + 3y
Substitute x = -8 + 3y into (2)
3x + 2y = 31 (2)
3(-8 + 3y) + 2y = 31
-24 + 9y + 2y = 31
-24 + 11y = 31
11y = 31 + 24
11y = 55
y = 55/11
y = 5
Substitute y = 5 into (1)
x – 3y = -8 (1)
x - 3(5) = -8
x - 15 = -8
x = -8 + 15
x = 7
(x, y) = (7, 5)
Hey Guys! Can You Please Help Me In My Math
pic is not clear.....
Consider quadrilateral EFGH.
Quadrilateral E F G H is shown. Sides F G and E H are parallel. Angles E and H are congruent. The length of E F is 4 n minus 4, the length of F G is 3 n + 3, and the length of G H is 2 n + 6.
What is the length of line segment GH?
5 units
7 units
16 units
24 units
Given:
In quadrilateral EFGH, [tex]FG\parallel EH,\angleE\cong \angle H,EF=4n-4,FG=3n+3, GH=2n+6[/tex]
To find:
The length of segment GH.
Solution:
Draw a figure according to the given information as shown below.
In quadrilateral EFGH, [tex]FG\parallel EH,\angleE\cong \angle H[/tex], it means the quadrilateral EFGH is an isosceles quadrilateral because base angles are equal.
Now, quadrilateral EFGH is an isosceles quadrilateral, so the sides EF and GH are equal.
[tex]EF=GH[/tex]
[tex]4n-4=2n+6[/tex]
[tex]4n-2n=4+6[/tex]
[tex]2n=10[/tex]
Divide both sides by 2.
[tex]n=\dfrac{10}{2}[/tex]
[tex]n=5[/tex]
Now,
[tex]GH=2n+6[/tex]
[tex]GH=2(5)+6[/tex]
[tex]GH=10+6[/tex]
[tex]GH=16[/tex]
Therefore, the correct option is C.
Answer:
the answer is C
Step-by-step explanation:
:]
Given Q(x) = 7x − 3 and P(x) = 7x3 − 3x2 + 42x − 27, find P(x) Q(x) . (Divide using long division.)
Complete question:
Given Q(x) = 7x − 3 and P(x) = 7x3 − 3x2 + 42x − 27, find P(x) ÷ Q(x) . (Divide using long division.)
Answer:
[tex]\frac{7x^3 \ - \ 3x^2 \ + \ 42x \ - \ 27}{7x \ - \ 3} = \ \ x^2 + 6 \ \ \frac{-9}{7x \ - \ 3}[/tex]
The quotient = x² + 6 and the remainder = - 9
Step-by-step explanation:
Given;
Q(x) = 7x − 3
P(x) = 7x³ − 3x² + 42x − 27
To divide P(x) by Q(x) using long division, we apply the following method;
x² + 6
---------------------------------
7x − 3 √ 7x³ − 3x² + 42x − 27
− (7x³ - 3x²)
-------------------------------------
42x − 27
− (42x − 18)
----------------------------------------
− 9
[tex]Therefore, \ \frac{7x^3 \ - \ 3x^2 \ + \ 42x \ - \ 27}{7x \ - \ 3} = \ \ x^2 + 6 \ \ \frac{-9}{7x \ - \ 3}[/tex]
The quotient = x² + 6 and the remainder = - 9
Helppppp and explain !!!!
Answer:
dat I don't know the answer sorry I could not answer u
Express each of the following quadratic functions in the form of f(x) = a (x - h)²+ k.Then,state the minimum or maximum value,axis of symmetry and minimum or maximum point. (a) f(x) = -2x² + 7x + 4.
Pls help me ans this question,its urgent!!
I'll mark u as the brainliest!
ok this is answer any questions
Im so confused on what do to here
Ans. (a)
SQ and RQ
Ans. (b)
∠RQT
∠TQR
Ans. (c)
Q
Which of the following best describes the line of symmetry?
A. The line that is perpendicular to the design
B. The line that is parallel to the design
C. The line that divides the design into two similar parts
D. The line that divides the design into two congruent parts
Answer:
C the line that divides the design into two similar parts
The line of symmetry divides the design into two similar parts.
What is a line of symmetry?"The line of symmetry can be defined as the axis or imaginary line that passes through the center of the shape or object and divides it into identical halves. "
A line divides a design into two parts.
If the line is described as the line of symmetry, then the two parts that are divided by this line are similar parts.
Learn more about line of symmetry here: https://brainly.com/question/1389470
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Question in the image
Answer:
0.4
Step-by-step explanation:
consider this like some lines overlapping each other.
one line (A) is 0.5 long, the other (B) 0.4 long.
together they are 0.8 long.
that means that they overlap at a length of 0.1 (they share a segment 0.1 long).
of the combined line of 0.8 that has 0.1 of a joined segment, the complimentary part of B is therefore 0.4 (0.8 minus the original length of B).
question in picture | Math
Answer:
Y=4/-2
Step-by-step explanation:
the pair of the lines x^2-3y^2=0 and the straight line x=a enclose a triangle which is
Step-by-step explanation:
x²-3y²=0x=√3y and x-√3yΔOAB is equilateral triangle∴ orthocentre and centroid of ΔOAB concides ∴ orthocentre =( 29/3 ,0)=( x1 + x2 + x3 / 3 , y1 + y2 + y3 / 3 )I NEED BRAINLIEST ✌️ PLZURGENT PLS ANSWER QUICKLY
Answer:
9th is 44 mark me as brainlist
Answer:
Question 9 is perimeter
Three text messages cost 5 cents to send. how much do 150 cost?
Answer:
30 ,,,,,,,, I hope it's helpful for you
3 text messages = 5 cents
So,
1 text messages
= 5 cents/3
= 5/3 cents
So,
150 text messages
= 150 × (5/3 cents)
= 50 × 5 cents
= 250 cents
Determine the solution on the following equation
Answer:
x = 3
Step-by-step explanation:
Step-by-step explanation:
3(8x-8)/2=64
3(8x-8)=64×2
24x-24=128
24x=128+24
24x=152
24x/24=152/24
x=6.3
If ABC~ ADEF and the scale factor from AABC to A DEF is 2, what are the
lengths of DE, EF, and DF, respectively?
E
B
4
2
6
A А
A. 4, 8, 12
B. 2, 8, 12
C. 8, 16, 24
D. 1, 2, 3
Answer:
A. 4, 8, 12
Step-by-step explanation:
there is a scale factor f=2 to "go" from one triangle to the other.
that means all sides of the target triangle are created out of their corresponding side of the source triangle by multiplying them by the scale factor.
so,
2×f = 2×2 = 4
4×f = 4×2 = 8
6×f = 6×2 = 12
The lengths of DE, EF, and DF are 4, 8 and 12 respectively, (option 1)
What are similar triangles?Two triangles are said to be similar if their corresponding sides are in equal ratio and corresponding angles are congruent.
Given that, Δ ABC~ Δ DEF and the scale factor from Δ ABC to Δ DEF is 2
Since, the scale factor is 2, therefore each side of Δ ABC is increased by 2 in Δ DEF
Therefore,
DE = 2AB
EF = 2BC
DF = 2AC
Therefore,
DE = 4
EF = 8
DF = 12
Hence, the lengths of DE, EF, and DF are 4, 8 and 12 respectively, (option 1)\
For more references on similar triangles, click;
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Can somebody help me