Answer: I think it is c
Explanation: hope this helps
Write pseudocode for a function that translates a telephone number with letters in it (such as 1-800-FLOWERS) into the actual phone number. Use the standard letters on a phone pad.
Answer:
Explanation:
Function telToNumbers with one parameter of a String input for the telephoneNumber
String var newTelephoneNum;
for loop through telephoneNumber {
Char var currentChar = current Character in the loop;
currentChar to lower Case;
Switch statement (currentChar) {
case "a" or "b" or "c" : newTelephoneNum += "2"; break;
case "d" or "e" or "f" : newTelephoneNum += "3"; break;
case "g" or "h" or "i" : newTelephoneNum += "4"; break;
case "j" or "k" or "l" : newTelephoneNum += "5"; break;
case "m" or "n" or "o" : newTelephoneNum += "6"; break;
case "p" or "q" or "r" or "s" : newTelephoneNum += "7"; break;
case "t" or "u" or "v" : newTelephoneNum += "8"; break;
case "w" or "x" or "y" or "z" : newTelephoneNum += "9"; break;
default : newTelephoneNum += currentChar; break;
}
}
print newTelephoneNum;
nder a Huffman encoding ofnsymbols with frequenciesf1, f2, . . . , fn, what is the longest a codewordcould possibly be
Answer:
The longest codeword that could possibly be for "n" symbol is n-1 bits.
Explanation:
From the given information:
Suppose we are to consider a set of frequencies [tex]\mathtt{f_1,f_2,f_3 ...,f_n}[/tex], for which f is a symbol for the length n. Therefore, the longest codeword that could possibly be for "n" symbol is n-1 bits.
However, during the encoding for "n" in conjunction with n-2, then the possibilities for n are; [tex]\mathtt{\dfrac{1}{2}, \dfrac{1}{4}, ... \dfrac{1}{2^{n-2}}}[/tex]
We can conclude that the longest codeword that could possibly be for "n" symbol is n-1 bits.
Write code which takes a sentence as an input from the user and then prints the length of the first word in that sentence.
Hint: think about how you know where the first word ends - you may assume that the sentence contains more than one word.
Input a code in the following:
/* Lesson 3 Coding Activity Question 4 */
import java.util.Scanner;
public class U2_L3_Activity_Four{
public static void main(String[] args){
/* Write your code here */
}
}
import java.util.Scanner;
public class U2_L3_Activity_Four {
public static void main(String[] args) {
Scanner scan = new Scanner(System.in);
System.out.println("Enter a sentence.");
String sent = scan.nextLine();
int count = 0;
for (int i = 0; i < sent.length(); i++){
char c = sent.charAt(i);
if (c != ' '){
count++;
}
else{
break;
}
}
System.out.println("The first word is " + count +" letters long");
}
}
We check to see when the first space occurs in our string and we add one to our count variable for every letter before that. I hope this helps!
Following are the java code to the given question:
import java.util.Scanner;//import package
public class U2_L3_Activity_Four //defining a class U2_L3_Activity_Four
{
public static void main(String[] args) //defining main method
{
String s;//defining String variable
int x,v=0;//dclaring integer variable x,v
Scanner obx = new Scanner(System.in);//creating Scanner class Object
System.out.println("Enter a sentence.");//print message
s = obx.nextLine();//input string value
for (x = 0; x < s.length(); x++)//defining loop to count string length
{
char c = s.charAt(x);//defining char variable that hold char value
if (c != ' ')//defining if that check space value
{
v++;
}
}
System.out.println("The first word is " + v +" letters long");//print length of first word
}
}
Output:
Please find the attached file.
Program Explanation:
Import package.Defining a class U2_L3_Activity_Four, inside the class main method is declared.Defining a string variable "s" and an integer variable "x,v=0", and a scanner class object is created that inputs string value.In the next step, a for loop is defined that checks the first word in the string value and prints its length value.Learn more:
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If you need to download something for a class, first
Answer:
left click, then click save image
Explanation:
Answer:
first try to do it on kami, then on Google docs, then on doc-hub
Which choices correctly describe an Else
statement? Check all that apply.
a conditional statement that will show
different information if the answer to the If
statement is true
a conditional statement that will show
different information after the If statement
answer is false
a statement that contains the code to be
executed when the If value is false or zero
a conditional statement that runs a piece of
code when all program statements are true
Answer: B C
Explanation:
Answer:B,C,D
Explanation:
How can you enter Task Manager in Windows? Select 3 options. right-click the taskbar and choose Start Task Manager right-click the taskbar and choose Manage Tasks press Ctrl + Shift + Tab press Ctrl+Alt+Delete and then click Task Manager press Ctrl + Alt + Esc
Answer:
Press [Ctrl]+[Shift]+[Esc] and Windows Task Manager will launch instantly
Explanation:
Answer:
1. Press Ctrl+Alt+Delete and then click Task Manager
2. right-click the taskbar and choose Start Task Manager
3. Press Ctrl+Alt+Esc
Explanation:
Took the test. If you are on a windows computer you can also test the answers to see what works and what does not.
ANSWER THIS CORRECTLY TO GET BRAINLY
What is a row of data in a database called?
a
Field
b
File
c
Record
d
Title
On his website, Mario has a video that visitors must click to play. He wants the video to play automatically when the page loads. What attribute should Mario add to the
A. controls
B. loop
C. autoplay
D. play
Answer:
C: AutoPlay
Explanation:
it is C because the definition of AutoPlay is: a functionality that causes a video, audio file, etc. to play automatically, without action from a user.
Write an If/else statement to check whether host is online. If it is online, then print system is online otherwise print system is unreachable.
Answer:
from socket import *
hostname = input('Enter the host to be scanned: ')
ip_add = gethostbyname(hostname)
connections = [ ]
for i in range(133, 136):
s = socket(AF_INET, SOCK_STREAM)
conn = s.connect_ex((ip_add, i))
print(conn)
connections.append(conn)
if 0 in connections:
print ('Host is online')
s.close()
else:
print ('system is unreachable')
Explanation:
The python source code above scans for all the available range of ports in the provided hostname, if any port is available, the host is online else the program print the error message "system is unreachable.
Information technology
Answer:
Study or use of systems
Explanation:
especially, computers, telecommunications for storing retrieving and sending some informations
Answer:
Information technology is the use of computers to store, retrieve, transmit and manipulate data, or information, often in the context of business or other enterpise.
PLEASE ANSWER QUICK
How can improving one’s reasoning skills also improve one’s performance on the job?
A. If one can improve one’s reasoning, one can also improve one’s physical fitness and athletic performance.
B. If one can improve one’s reasoning, one can perform anything.
C. High-performing workers always work reasonable schedules.
D. High-performing workers are able to analyze sophisticated streams of data and solve complex problems.
Answer: C
Explanation:
For the sake of maximizing hardware utilization in a multicore system with a many to many threading model, the relationship of the number of user threads U to the number of kernel threads K to the number of CPU cores P should be:
Answer:
"U > K > P" would be the appropriate answer.
Explanation:
When performing or executing the software, user threads (U) could easily be accomplished and therefore are typically wide in the amount to provide excellent or excellent performance. Multiple kernel threads could indeed be appointed to every other core as well as try to emulate the algorithm for scheduling.4.2 code need help plz someone 15 points if u help
def func():
total = 0
while True:
pet = input("What pet do you have? ")
if pet == "rock":
return
total += 1
print("You have a {} with a total of {} pet(s)".format(pet, total))
func()
We wrapped our code in a function so that whenever the user enters rock, we can simply return and exit the function. If you have any other questions, I'll do my best to answer them.
A database has one physical schema and one conceptual (logical) schema but many external schemas (views).
a) True
b) False
Answer:
true
Explanation:
A database has one physical schema and one conceptual (logical) schema but many external schemas (views): a. True.
A database refers to a structured (organized) collection of data that are stored on a computer system and usually accessed in various ways such as electronically.
In database management, a database schema can be defined as a structure which is typically used to represent the logical design of the database. Thus, it denotes how data are stored (organized) and the relationships existing in a database management system (DBMS).
Generally, there are two (2) main types of a database schema and these include;
Physical database schema: it is only one per database.Conceptual (logical) schema: it is only one per database.However, there are multiple number of external schemas (views) for each database because it is what an end user is interested in.
Read more on database here: https://brainly.com/question/3259292
label parts of camera
Answer:
Viewfinder.
Pentaprism.
Focusing Screen.
Condenser Lens.
Digital Sensor.
Shutter. ...
Display. ...
Electronics.
Explanation:
To italicize text located within a text box, which grouping would you use? Effects Text Font Typography
Answer:
Font
Explanation:
It seems like the only real answer from reading the lesson
what is the first things u do upon seeing this sheet?
Answer:
umm ok
Explanation:
plz mark brainlyest
Using range(1,101), make two list, one containing all even numbers and other containing all odd numbers. How can I do this on Python
Answer:
even = []
odd = []
for i in range(1,101):
if i % 2 == 0:
even.append(i)
else:
odd.append(i)
Using range(1,101), the list of even and odd number can be done in python as follows;
odd_numbers = []
even_numbers = []
for i in range(1, 101):
if i%2 == 0:
even_numbers.append(i)
else:
odd_numbers.append(i)
print(even_numbers)
print(odd_numbers)
The variable odd_numbers is initialise with an empty list
The variable even_numbers is initialise with an empty list.
Then we loop through the range 1 to 101 as required.
If the looped numbers is divided by 2 without a remainder then the number is appended to the empty list even_numbers.
Else if it has a remainder, the looped number are appended to the empty list, odd_numbers.
Then we print the even_numbers and odd_numbers.
learn more about python here; https://brainly.com/question/14157737?referrer=searchResults
When would you insert a merge field?
A. when updating the source document
B. when choosing which information you want to enter into a letter
C. when choosing which information you want to insert in a merged letter
D. when creating a document
Answer:
Once you have a data source connected to your document, adding merge fields is a way to personalize a document with information from the data source.
Corina has added animations to objects on a particular slide within a presentation. She needs to reorder the animations. How should she achieve this goal?
A. Use the Preview button.
B. Access the Advanced timeline.
C. Use the Animation pane.
D. Delete and recreate the animations in the correct order.
I think it's B but im not 100% sure sorry if im wrong
Answer: C
Explanation:
Write function that ask for input from a user. Use this input as input for the countdown function that we wrote using the while loop. If the user types 'end', the program exits, otherwise it keeps going.
Answer:
Written in Python:
def myfunction():
userinput = input("User input: ")
while(userinput != "end"):
countdown(userinput)
userinput = input("User input: ")
Explanation:
This line defines the function
def myfunction():
This line prompts user for user input
userinput = input("User input: ")
The following while loop checks if userinput is not "end". It continues execution until user input "end"
while(userinput != "end"):
countdown(userinput) If yes, the input is passed to the countdown function for execution
This line prompts user for another user input
userinput = input("User input: ")
Please note the above code segment assumes that countdown() function has already been written and defined
What question did the use of a telescope by Hubble answer?
A
Is Earth the center of the universe
B
Is the sun the center of the universe
C
How do the planets move in the solar system
D
Are there more galaxies beyond the Milky Way
Answer:
The Answer is D
The Electronic Age began in the
A. 1940s
B. 1970s
C. 1980s
D. 1990s
Answer:
1940
Explanation:
Please help!! I’ll mark you brainly
Answer:
1. raster and vector
2. Resolution
3. Color depth
4. Forms, Shapes
5. Tone
6. Balance
7. White space
8. Aspect ratio
9. Focus
10. cropping
Hope this helped :)
Help me! I’ll mark you brainly ! Please help me I need this now
Explanation: For number 3 I would say shade and darkness.
Compute the decimal representation for each of the following numbers.
a. (1100110)2
b. (346)7
c. (1024)8
d. (3B2)16
e. (AF72)16
f. (120121)3
g. (A22)11
Answer:
[tex](1100110)_2= 102_{10[/tex]
[tex](346)_7= 181_{10[/tex]
[tex](1024)_8 = 532_{10[/tex]
[tex](3B2)_{16} = 946_{10[/tex]
[tex](AF72)_{16}= 44914_{10[/tex]
[tex](120121)_3= 421_{10[/tex]
[tex](A22)_{11} = 1234_{10}[/tex]
Explanation:
Required
Convert to decimal
To do this we get the position of individual digits (starting from the rightmost digit).
Then each digit is multiplied by the base raise to power its position.
Lastly, we sum the results of the products.
Following the above steps, we have:
[tex]a.\ (1100110)_2[/tex]
[tex]= 1 * 2^6 + 1 * 2^5 + 0 * 2^4 + 0 * 2^3 + 1 * 2^2 + 1 * 2^1 + 0 * 2^0[/tex]
[tex]= 1 * 64 + 1 * 32 + 0 * 16 + 0 * 8 + 1 * 4 + 1 * 2 + 0 * 1[/tex]
[tex]= 64 + 32 + 0 + 0 + 4 + 2 + 0[/tex]
[tex]= 102[/tex]
Hence:
[tex](1100110)_2= 102_{10[/tex]
[tex]b.\ (346)_7[/tex]
[tex]= 3 * 7^2 + 4*7^1 + 6 * 7^0[/tex]
[tex]= 3 * 49 + 4*7 + 6 * 1[/tex]
[tex]= 147 + 28 + 6[/tex]
[tex]= 181[/tex]
Hence:
[tex](346)_7= 181_{10[/tex]
[tex]c.\ (1024)_8[/tex]
[tex]= 1 * 8^3 + 0 * 8^2 + 2 * 8^1 + 4 * 8^0[/tex]
[tex]= 1 * 512+ 0 * 64 + 2 * 8 + 4 * 1[/tex]
[tex]= 512+ 0 + 16 + 4[/tex]
[tex]= 532[/tex]
Hence:
[tex](1024)_8 = 532_{10[/tex]
[tex]d.\ (3B2)_{16[/tex]
[tex]= 3 * 16^2 + B * 16^1 + 2 * 16^0[/tex]
[tex]= 3 * 256 + B * 16 + 2 * 1[/tex]
B represents 11, so we have:
[tex]= 3 * 256 + 11 * 16 + 2 * 1[/tex]
[tex]= 768 + 176 + 2[/tex]
[tex]= 946[/tex]
Hence:
[tex](3B2)_{16} = 946_{10[/tex]
[tex]e.\ (AF72)_{16[/tex]
[tex]= A * 16^3 + F * 16^2 + 7 * 16^1 + 2 * 16^0[/tex]
[tex]= A * 4096 + F * 256 + 7 * 16 + 2 * 1[/tex]
A represents 10 and F, 15; So, we have:
[tex]= 10 * 4096 + 15 * 256 + 7 * 16 + 2 * 1[/tex]
[tex]= 40960 + 3840 + 112 + 2[/tex]
[tex]= 44914[/tex]
Hence:
[tex](AF72)_{16}= 44914_{10[/tex]
[tex]f.\ (120121)_3[/tex]
[tex]= 1 * 3^5 + 2*3^4 + 0*3^3 + 1*3^2 + 2*3^1 + 1*3^0[/tex]
[tex]= 1 * 243 + 2*81 + 0*27 + 1*9 + 2*3 + 1*1[/tex]
[tex]= 243 + 162 + 0 + 9 + 6 + 1[/tex]
[tex]= 421[/tex]
Hence:
[tex](120121)_3= 421_{10[/tex]
[tex]g.\ (A22)_{11[/tex]
[tex]= A * 11^2 + 2 * 11^1 + 2 * 11^0[/tex]
[tex]= A * 121 + 2 * 11 + 2 * 1[/tex]
A represents 10, so we have:
[tex]= 10 * 121 + 2 * 11 + 2 * 1[/tex]
[tex]= 1210 + 22+ 2[/tex]
[tex]= 1234[/tex]
Hence:
[tex](A22)_{11} = 1234_{10}[/tex]
Which input value causes the loop body to execute a 2nd time, thus outputting "In loop" again? { String s = "Go"; while ((!s.equals("q"))&& (!s.equals("")) System.out.println("In loop"); 5 - scnr.nextO;
a) "Quit"
b) "q" only
c) "Q only
d) Either "q" or "Q"
Answer:
a) "Quit"
c) "Q only
Explanation:
Given
String s = "Go";
while ((!s.equals("q"))&& (!s.equals(""))) {
System.out.println("In loop");
s = scnr.next();
}
Required
What input causes another execution
Analyzing the while condition
while ((!s.equals("q"))&& (!s.equals("")))
This can be split into:
!s.equals("q")) && (!s.equals(""))
Meaning
When s is not equal to "q" and when s is not an empty string
In other words,
the loop will be executed when user input is not "q" and user input is not empty.
So, from the list of given options: The loop both will be executed when:
a) Input is "Quit"
c) Input is Q only
Input of q will terminate the loop, hence b and d are incorrect
This is the department that is responsible for hiring, firing, training, new employees for the business or corporation.
Group of answer choices
Human Resources
Information Technology
Advertising
Marketing
Answer:
Explanation:
human resources
hoped this helped
Which logic correctly describes an algorithm to find the smallest of the three numbers a, b, and c and store the smallest number in small?
A.
If a is less than b, then set a to small, else set b to small, else set c to small.
B.
If a is less than b, then set small to a, else set small to b.
If c is less than small, then set small to c.
C.
If a is less than b, then set small to b, else set small to c.
If c is less than small, then set small to a.
D.
If a is less than small, then set small to a.
If b is less than small, then set small to b.
If c is less than small, then set small to c.
Answer:
D
Explanation:
Answer:
B. If a is less than b, then set small to a, else set small to b.
If c is less than small, then set small to
Explanation:
Plato correct!!
Determine the number of character comparisons made by the brute-force algorithm in searching for the pattern GANDHI in the text
THERE_IS_MORE_TO_LIFE_THAN_INCREASING_ITS_SPEED
(Assume that the length of the text-it is 47 characters long- is known before the search starts).
Answer:
Total number of character comparison = 43
Explanation:
Using the Brute force algorithm
The string of n characters is known as text, and the string of m characters is known as the pattern.
From the given information:
The text (n)=THERE_IS_MORE_TO_LIFE_THAN_INCREASING_ITS_SPEED
The pattern (m) = GANDHI
The total no of characters that we have in the text = 47
The total number of characters in pattern = 6
For a brute force algorithm;
Since; the first character of the pattern does not exist in the text, then the number of trials made can be attempted can be expressed as = n – m + 1
= 47 – 6 + 1
= 47 – 5
= 42
Thus; the algorithm will attempt the trial 42 times.
Now, for loop in the algorithm to run 42 times, the G in the pattern will have to align against the for T in the text, and in the last case, it will be aligned against the last space.
On each attempted trial, the algorithm will make one unsuccessful comparison.
However, at the trial at which the G in the pattern Is aligned with the G in the text, there will be two successful comparisons.
Hence, we can calculate the total number of character comparison as follows:
Total number of character comparison = [tex]\mathbf{\bigg ( ( 42 - (no. \ of \ failed \ comparison) ) \times 1 + (1 \times ( Two \ successful \ comparisons) ) \bigg ) }[/tex]
Total number of character comparison = ( (( 42 – 1) × 1 ) + ( 1 × 2) )
Total number of character comparison = 41 + 2
Total number of character comparison = 43
