Mathematics High School

Jim buys a skateboard for $200. The value of the skateboard depreciates by 15% each year
since buying it. Create a function to represent the value of the skateboard, f(2), in dollars,
after 3 years since buying it.

Answers

Answer 1

Answer: f(x)=200•(0.85)^x

Step-by-step explanation:

C(t) is the actual value of the function at time t

Co is the initial value of C at t=0

r is the decaying rate, expressed in decimal

Depreciation is often modeled as an exponential decay function. Since Jim bought a skateboard for Co=$200, its value will depreciate by r=15% = 0.15 each year since buying it.

Related Questions

You pay $11.20 to buy drink boxes for the football team. Each drink box cost $0.40. How many drink boxes did
you buy?

Answers

I think it’s uhhhh I think it’s uhhhhh carrot

The cylinder shown here has a height of 7 centimeters and a radius of 4 centimeters. What is the area of the base of the cylinder? Express your answer in terms of 1. Do not include units (cm2) in your answer. Use pi to represent the n symbol. For example: 321 would be typed as 32pi​

Answers

Answer: 16pi

Step-by-step explanation:

14 is 33 1/2% of what number?

Answers

Answer:

41.79

Step-by-step explanation:

c = 14 * 100/33.5 = 1400/33.5 = 2800/67

= 41.79104

ik you want the points
plzz​

Answers

Answer:

Line 1: Undefined

Line 2: -4/3

Line 3: 4/3

Line 4: Undefined

Line 5: 7/3

Line 6: -7/3

Line 7: 0

Line 8: 0

Line 9: Undefined

Line 11: 0

Line 10 & 12: Undefined

Step-by-step explanation:

Use the slope formula (you can just search up the slope formula)

Also, always remember that a vertical line's slope will be undefined and a horizontal line's slope will be 0 (zero).

I hope this helps!

What is the value of x?
A. 6
B. 5
c. 4
D.3

Answers

Answer:

D

Step-by-step explanation:

CD is an angle bisector and divides the opposite side into segments which are proportional to the other 2 sides, that is

[tex]\frac{BC}{AC}[/tex] = [tex]\frac{BD}{AD}[/tex] , substitute values

[tex]\frac{4}{3}[/tex] = [tex]\frac{x}{2.25}[/tex] ( cross- multiply )

3x = 9 ( divide both sides by 3 )

x = 3 → D

heyyy wanna help mee

Answers

Answer: Only j = 2

============================================

Explanation:

Let's solve for j

[tex]\frac{96}{j} \ge 40\\\\96 \ge 40j\\\\\frac{96}{40} \ge j\\\\2.4 \ge j\\\\j \le 2.4[/tex]

In the second step, I multiplied both sides by j. If j is a positive number, then the inequality sign will not flip. All of the answer choices are positive numbers, so we don't have to worry about the inequality sign flipping.

The last step shows that j = 2.4 or j < 2.4

So j is 2.4 or smaller.

Of the list given to us, only j = 2 fits the description, since something like j = 8 is not 2.4 or smaller.

---------------------------

If j = 2, then,

[tex]\frac{96}{j} \ge 40\\\\\frac{96}{2} \ge 40\\\\48 \ge 40\\\\[/tex]

which is a true statement since 48 is larger than 40. This shows that j = 2 is a solution.

Something like j = 8 does not work because

[tex]\frac{96}{j} \ge 40\\\\\frac{96}{8} \ge 40\\\\12 \ge 40\\\\[/tex]

which is false because 12 is not equal to 40 or larger than 40. This means j = 8 is not a solution. You should find that j = 12 and j = 3 lead to similar false statements.

Of the list given, j = 2 is the only solution.

Answer:[tex]\boxed{\boxed{\sf{j=2}}}[/tex]Solution Steps:

______________________________

1.) Solve using j = 12:Plug in 12: [tex]\frac{96}{12}[/tex] ≥ [tex]40[/tex]Divide 96 by 12: [tex]=8[/tex] Compare: [tex]8[/tex] ≥ [tex]40[/tex]

So this is False.

2.) Solve using j = 8:Plug in 8: [tex]\frac{96}{8}[/tex] ≥ [tex]40[/tex]Divide 96 by 8: [tex]=12[/tex] Compare: [tex]12[/tex] ≥ [tex]40[/tex]

So this is False.

3.) Solve using j = 2:Plug in 2: [tex]\frac{96}{2}[/tex] ≥ [tex]40[/tex] Divide 96 by 2: [tex]=48[/tex]Compare: [tex]48[/tex] ≥ [tex]40[/tex]

So this is True.

4.) Solve using j = 3:Plug in 3: [tex]\frac{96}{3}[/tex] ≥ [tex]40[/tex]Divide 96 by 3: [tex]=32[/tex] Compare: [tex]32[/tex] ≥ [tex]40[/tex]

So this is False.

______________________________

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