Answer:
$66
Step-by-step explanation:
$75
75*.8 =60
60*1.1= $66
(Find m∠IGH) m∠IGH=
Answer:
angle IGH = 50 degree
Step-by-step explanation:
triangle GHI is an isosceles triangle because it's two sides are equal.
if angle I is 50 degree then angle G is also 50 degree becasue in isosceles triangle the base angles are equal.
A bicycle tire has a radius of 10 inches. To the nearest inch, how far does the tire travel when it makes 4 revolutions?
Answer: 251.2 inches.
Step-by-step explanation: You have to multiply 4*2*π*radius. So, simply multiply 4*2*3.14*10. It would come out as 251.2 inches.
A pyramid with a triangular base has a volume of 50cm³. If the base and the height of the triangular base are 5cm and 8cm respectively, find the height of the pyramid ?
Answer:
h = 7.5 cm
Step-by-step explanation:
Firstly, we find the area of the triangular base
Mathematically, we have the area of a triangle as;
A = 1/2 * b * h
A = 1/2 * 5 * 8 = 20 cm^2
Mathematically, we have the formula as;
V= 1/3 * A * h
A is base area and h is height
50 = 1/3 * 20 * h
20h = 3 * 50
20h = 150
h = 150/20
h = 7.5 cm
EG is the angle bisector of
Answer:
the remaining angle will be 32
cz angle bisector cuts an angle in two equal parts hooe it may help u
The polynomial function 1x) = 5x^5+16/5x-3
is graphed below
Which is a potential rational root of f(x) at point P?
What is the product?
(5r − 4)(r2 − 6r + 4)
5r3 − 34r2 + 44r − 16
5r3 − 4r2 + 14r − 16
5r3 − 6r − 16
5r3 + 10r − 16
Answer:
5r³ - 34r² + 44r - 16
Step-by-step explanation:
[tex] \small \sf \: (5r − 4)(r² − 6r + 4)[/tex]
use the distributive property
5r × (r² − 6r + 4) - 4× (r² − 6r + 4)
5r³ - 30r² + 20r - 4r² + 24r - 16
combine like terms
5r³ - 30r² - 4r² + 20r + 24r - 16
5r³ - 34r² + 44r - 16
The product of the expressions is 5r^3 - 34r^2 + 44r - 16
What is a product?The product of two expression is done by multiplying the expressions
The product expression is given as:
[tex](5r - 4)(r^2 - 6r + 4)[/tex]
Expand the expression
[tex]5r^3 - 30r^2 + 20r - 4r^2 + 24r - 16[/tex]
Collect like terms
[tex]5r^3 - 30r^2 - 4r^2 + 20r + 24r - 16[/tex]
Evaluate the like terms
[tex]5r^3 - 34r^2 + 44r - 16[/tex]
Hence, the product of the expressions is 5r^3 - 34r^2 + 44r - 16
Read more about product at:
https://brainly.com/question/4344214
Question 2 (Essay Worth 10 points)
(03.01 MC)
Look at the rectangle and the square:
A rectangle PQRS and square LMNO are drawn side by side. The length SR of the rectangle is labeled as 12 inches, and the width QR is labeled as 6 inches. The side LM of the square is labeled as 6 inches.
Sam says that the length of diagonal SQ is two times the length of diagonal OM.
Is Sam correct? Justify your answer and show all your work. Your work should state the theorem you used to find the lengths of the diagonals.
Answer:
Sam is incorrect.
Step-by-step explanation:
Using Pythagorean Theorem, we can find the length of diagonal SQ as 13.4 (6^2 + 12^2 = c^2, 36 + 144 = c^2, sqrt(180) = c, c is approx 13.4). We can do the same for diagonal OM (6^2 + 6^2 = c^2, 36 + 36 = c^2, 72 = c^2, sqrt(72) = c, c is approx 8.5). Sam is therefore incorrect because 13.4 is not double of 8.5.
Answer:
Sam is incorrect.
Step-by-step explanation:
Sam is incorrect. By using the Pythagorean theorem, we can find out what each diagonal is equal to.
Starting with diagonal SQ...
6^2 + 12^2
= 36 + 144
= 180
Square root of 180?
= 13.41
Diagonal OM...
6^2 + 6^2
= 36 + 36
= 72
Square root of 72?
= 8.48
Therefore, Sam is incorrect because 8.4 isn't half of 13.4.
Determine whether the triangles are congruent. Explain your reasoning .
SAS (Side, Angle, Side) or ASA (Angle, Side, Angle)
Answer:
Ty
Step-by-step explanation:
Jade has seven cards. Each card is labeled with a letter. A B C D E F G H J Jade picks one of her cards at random. Find the probability that the card she picks is a) labelled F, b) labelled with a letter in her name JADE c) labelled with a letter that has at least one line of symmetry
Answer:
(a) [tex]\frac{1}{7}[/tex]
(b) [tex]\frac{4}{7}[/tex]
(c) [tex]\frac{5}{7}[/tex]
Step-by-step explanation:
Probability (P) of an event is the likelihood that the event will occur. It is given by;
P = number of favourable outcomes ÷ total number of events in the sample space.
Given letters of cards:
A B C D E F G H J
∴ Total number of events in sample space is actually the number of cards which is 7
If a card is picked at random;
(a) the probability P(F), that it is labelled F is given by;
P(F) = number of favourable outcomes ÷ total number of events in the sample space.
The number of favourable outcomes for picking an F = 1 since there is only one card labelled with F.
∴ P(F) = 1 ÷ 7
=> P(F) = [tex]\frac{1}{7}[/tex]
(b) the probability P(N), that it is labelled with a letter in her name JADE is given by;
P(N) = P(J) + P(A) + P(D) + P(E)
Where;
P(J) = Probability that it is labelled J
P(A) = Probability that it is labelled A
P(D) = Probability that it is labelled D
P(E) = Probability that it is labelled E
P(J) = [tex]\frac{1}{7}[/tex]
P(A) = [tex]\frac{1}{7}[/tex]
P(D) = [tex]\frac{1}{7}[/tex]
P(E) = [tex]\frac{1}{7}[/tex]
∴ P(N) = [tex]\frac{1}{7}[/tex] + [tex]\frac{1}{7}[/tex] + [tex]\frac{1}{7}[/tex] + [tex]\frac{1}{7}[/tex]
∴ P(N) = [tex]\frac{4}{7}[/tex]
(c) the probability P(S), that it is labelled with a letter that has at least one line of symmetry is;
P(S) = P(A) + P(B) + P(C) + P(D) + P(E) + P(H)
Where;
P(A) = Probability that it is labelled A
P(B) = Probability that it is labelled B
P(C) = Probability that it is labelled C
P(D) = Probability that it is labelled D
P(E) = Probability that it is labelled E
P(H) = Probability that it is labelled H
Cards with letters A, B, C, D, E and H are selected because these letters have at least one line of symmetry. A line of symmetry is a line that cuts an object into two identical halves. Letters A, B, C, D, E and H can each be cut into two identical halves.
P(A) = [tex]\frac{1}{7}[/tex]
P(B) = [tex]\frac{1}{7}[/tex]
P(C) = [tex]\frac{1}{7}[/tex]
P(D) = [tex]\frac{1}{7}[/tex]
P(E) = [tex]\frac{1}{7}[/tex]
P(H) = [tex]\frac{1}{7}[/tex]
∴ P(S) = [tex]\frac{1}{7}[/tex] + [tex]\frac{1}{7}[/tex] + [tex]\frac{1}{7}[/tex] + [tex]\frac{1}{7}[/tex] + [tex]\frac{1}{7}[/tex]
∴ P(S) = [tex]\frac{5}{7}[/tex]
Which sequence is geometric?
Answer:
4th option
Step-by-step explanation:
in geometric sequences the number is multiplied or divided by same number continuously
in the 4th option we can see that the number 1 is multiplied by 4 continuously so the correct answer would be that.
Find all solutions to the equation in the interval [0, 2pie]. Enter the solutions in increasing order. cos 2x = sin x
Answer:
cos2x=sinx
<=> 1-2sin^{2}x =sinx
solve and we have x=3pie/2, x=pie/6,x= 5pie/6
Step-by-step explanation:
फरक परेछ? A person deposited Rs. 80,000 in bank 'P' for 2 years at the rate of 10% annual compound interest. But after one year bank has changed the policy and decided to pay semi-annual compound interest at the same rate. What is the percentage difference between compound interests of the first year and second year? Give reason with calculation,
Answer:
you nepali me nepali all are nepalese nepalese are only unintelligent
find the measure of the missing angle (#4 btw)
Answer:
Step-by-step explanation:
1)
∠1 = ∠2 {Angles opposite to equal angles are equal}
∠1 = ∠2 = x
x +x + 55 = 180 {angle sum property of triangle}
2x + 55 = 180
2x = 180 - 55
2x = 125
x = 125/2
x = 62.5
∠1 = 62.5
2) ∠2 = 62.5
3) ∠3 = 55 {Vertically opposite angles are congruent}
4) ∠4 + 105 = 180 {linear pair}
∠4 = 180 - 105
∠4 = 75
5) ∠3 + ∠4 + ∠5 = 180 {Angle sum property of triangle}
55 + 75 +∠5 = 180
130 + ∠5 = 180
∠5 = 180 - 130
∠5 = 50
please i have 15 minutes
Answer:
[tex] x = \dfrac{-\log 7}{\log 7 - \log 2} [/tex]
Step-by-step explanation:
[tex] 2^x = 7^{x + 1} [/tex]
Take the log of both sides.
[tex] \log 2^x = \log 7^{x + 1} [/tex]
Use properties of log.
[tex] x \log 2 = (x + 1) \log 7 [/tex]
[tex] x \log 2 = x \log 7 + \log 7 [/tex]
[tex] x \log 2 - x \log 7 = \log 7 [/tex]
[tex] x(\log 2 - \log 7) = \log 7 [/tex]
[tex] x = \dfrac{\log 7}{\log 2 - \log 7} [/tex]
[tex] x = \dfrac{\log 7}{-(\log 7 - \log 2)} [/tex]
[tex] x = \dfrac{-\log 7}{\log 7 - \log 2} [/tex]
could anyone help me with this?
Answer:
93.4 cm²
Step-by-step explanation:
Area of the shaded region = area of the square - area of half of the circle
Area of the shaded region = s² + ½(πr²)
Where,
r = 6.2 cm
s = length of square = diameter of circle = 2*r = 2*6.2
s = 12.4 cm
Plug in the values
Area of the shaded region = 12.4² - ½(π × 6.2²)
= 153.76 - 60.381411
= 93.378589
≈ 93.4 cm² (nearest tenth)
The bus ride was 35 minutes long. If the ride ended at 12:05 a.m., what time did the ride begin?
Answer:
11:30 A.M.
Step-by-step explanation:
Answer:
11:30
Step-by-step explanation:
12.05- 35 min and its 11:30
hope that helps bby<3
Can someone help me? It's urgent and thank you!
Also pls look at the other 2 pictures!
Answer:
14x^3 LCD
(35x+4) / 14x^3
Step-by-step explanation:
5 /2x^2 + 2 / 7x^3
We need to find the least common denominator
2x^2 =2 *x*x
7x^2 = 7*x*x*x
x*x is common so we need to multiply that by 2*7*x
The least common denominator is 2*7*x*x*x = 14 x^3
To add the two, multiply to get the common denominator)
5/2x^2 * (7x/7x) + 2/7x^3 *(2/2)
35x/14x^3 + 4/14x^3
(35x+4) / 14x^3
Solve for x. Round to the nearest tenth, if
necessary.
I hope this is help full to u
thank you
Answer:
x = 3.8
Step-by-step explanation:
take 53 degree as reference angle
using cos rule
cos 53 = adjacent/hypotenuse
0.60 = x /6.3
0.60*6.3 = x
3.78 = x
3.8 = x ( after converting the answer to nearest tenth)
When an algebraic expression can be written as the product of two or more expressions, then each of these expressions is called a ____________of the given expression.
[tex] \huge\boxed{\mathfrak{Answer}}[/tex]
=> Factor.
When an algebraic expression can be written as the product of two or more expressions, then each of these expressions is called a factor of the given expression.
[tex] \sf \: It's \: called \: a \: \boxed{\underline{\bf \: factor}}[/tex]
When an algebraic expression can be written as the product of two or more expressions, then each of these expressions is called a [tex]\boxed{\underline{\bf \: factor}}[/tex]of the given expression.
A shoe repairman is working with his assistant, who takes 1.5 times as long to repair a pair of shoes.
Together they can fix 10 pairs of shoes in six hours. How long does it take the repairman to fix one pair
of shoes by himself?
Answer:
1/2 or 0.5 hours
Step-by-step explanation:
r = time for repairman to fix one pair of shoes.
a = time for assistant to fix one pair of shoes.
a = r×1.5
x×r + y×a = 6
x = number of pairs of shoes repaired by repairman.
y = number of pairs of shoes repaired by assistant.
x+y = 10
y = 10-x
x = y×1.5 (based on the a/r ratio : as the assistant needs 1.5 times longer, the repairman will have repaired 1.5 times more pair of shoes in the same time)
y = 10 - y×1.5
y + y×1.5 = 10
2.5×y = 10
y = 4
=> x = 6
6×r + 4×r×1.5 = 6
6×r + 6×r = 6
12×r = 6
r = 6/12 = 1/2 or 0.5 hours
NO WRONG ANSWER PLEASE PO
[tex] |? \times \fracwarning [/tex]
ok no no no wrong wrong answer
Answer:2. okra
Step-by-step explanation:
Help me please
How many solutions does the equation
x -4 = 12 - 2x have? Explain.
- ? .
Answer: one solution.
Step-by-step explanation:
[tex]\dfrac{2}{3} x-4=12-2x\\\\\dfrac{2}{3} x+2x=12+4\\\\2\dfrac{2}{3} x=16\\\\\dfrac{8}{3} x=16\\\\8x=16 \cdot 3\\\\8x=48\\\\x=\dfrac{48}{8} =6[/tex]
This equation has one solution: x = 6.
Write the expression as either the sine, cosine, or tangent of a single angle. cos(pi/5) cos(pi/7)+sin(pi/5)sin (pi/7)
Answer:
cos(2π/35)
General Formulas and Concepts:
Pre-Algebra
Order of Operations: BPEMDAS
Brackets Parenthesis Exponents Multiplication Division Addition Subtraction Left to RightPre-Calculus
Sum/Difference Formula [cosine]: [tex]\displaystyle cos(x \pm y) = cos(x)cos(y) \mp sin(x)sin(y)[/tex]Step-by-step explanation:
Step 1: Define
Identify
cos(π/5)cos(π/7) + sin(π/5)sin(π/7)
Step 2: Simplify
Sum/Difference Formula [cosine]: cos(π/5)cos(π/7) + sin(π/5)sin(π/7) = cos(π/5 - π/7)Subtract: cos(π/5 - π/7) = cos(2π/35)what is the common difference for this arthimitic sequence? -8, -13, -18, -23
a. 5
b. -5
c. -28
d. -21
Please help I’ll give brainliest
Answer:
D. 12m^3n^5
Step-by-step explanation:
Answer:
12m³n⁵
Step-by-step explanation:
3 · 4 = 12
m² · m = m³
n³ · n² = n⁵
Therefore, 3m²n³ · 4mn² = 12m³m⁵
13. Find the roots of the quadratic equation by using the quadratic formula and factorization method (i) x 2 – + 10 = 0
Answer:
x = 5 or -2
Step-by-step explanation:
The general quadratic formula is expressed as;
ax²+bx+c = 0
Given
x² - 3x -10 = 0
a = 1, b = -3 and c = -10
x = -(-3)±√(-3)²-4(1)(-10)/2(1)
x = 3±√9+40/2
x = 3±√49/2
x = 3±7/2
x = 3+7/2 or 3-7/2
x = 10/2 or -4/2
x = 5 or -2
By Factorization
x² - 3x -10 = 0
x² - 5x+2x -10 = 0
x(x-5)+2(x-5) = 0
(x-5)(x+2) =0
x - 5 =0 and x+2 = 0
x = 5 or -2
Can someone help giving branliest to first correct answer
?????????????????????????????????????????????????????
Answer:
??????
Step-by-step explanation:
Answer:
The radius of the circle is 2 units.
Step-by-step explanation:
The radius is half the diameter, therefor you must divide the diameter (4) by 2, and you get 2 units.
Which of the following is true about a linear function? (4 points) Select one: a. It may curve in some parts and be horizontal in others. b. It must cross the origin. c. It has a constant rate of change. d. It must contain only positive values.
Option c: It has a constant rate of change.
A graph of f(x)=acos(bx) is shown, where b is a positive constant. Determine the values of a and b.
Answer:
Option (1)
Step-by-step explanation:
Equation of the given wave function,
f(x) = acos(bx)
Here, a = amplitude of the wave
Period of the wave = [tex]\frac{2\pi }{B}[/tex]
From the graph attached,
Amplitude = [tex]\frac{4-(-4)}{2}[/tex]
= [tex]\frac{4+4}{2}[/tex]
= 4
Period of the wave = π - 0
= π
From the formula of the period,
Period = [tex]\frac{2\pi }{b}[/tex]
[tex]\pi =\frac{2\pi }{b}[/tex]
b = 2
Therefore, a = 4 and b = 2.
Option (1) will be the answer.
