Jason owns a food truck that sells tacos and burritos. He sells each taco for $4.75 and each burrito for $7.50. Yesterday Jason made a total of $790 in revenue from all burrito and taco sales and there were twice as many burritos sold as there were tacos sold. Write a system of equations that could be used to determine the number of tacos sold and the number of burritos sold. Define the variables that you use to write the system.
:)

Answers

Answer 1

Answer:

4.75t + 7.50b = 790

b = 2t

Step-by-step explanation:

Let t represent the number of tacos that he sold, and let b represent the number of burritos he sold.

4.75t can represent how much money he earned from selling tacos, and 7.50b can represent how much money he earned from selling burritos.

Create an equation that adds these together and sets them equal to 790:

4.75t + 7.50b = 790

Next, create another equation that represents how there were twice as many burritos sold than tacos.

This can be represented by b = 2t.

The system of equations is:

4.75t + 7.50b = 790

b = 2t


Related Questions

Explain how to combine the terms 5x an 3x

Answers

Answer:

below

Step-by-step explanation:

In short, we will add both coefficients together to combine like terms.

3x + 5x → x(3 + 5) → 8x

If you have a value like 2x and 2, you cannot combine them because they do not have the same variable.

Best of Luck!

You add 5x+3x and get 8x

please
[tex] \sin(120) \\ \tan( \frac{3\pi}{4} ) [/tex]
help me I need help​

Answers

Answer:

[tex] \sin(120) \\ = \sin(90 + 30) \\ = \cos(30) \\ = \frac{ \sqrt{3} }{2} \\ \\ \tan( \frac{3\pi}{4} ) \\ = \tan(135) \\ = \tan(90 + 45) \\ = - \cot(45) \\ = - 1[/tex]

[tex]\\ \rm\longmapsto sin120[/tex]

[tex]\\ \rm\longmapsto sin(90+30)[/tex]

[tex]\\ \rm\longmapsto cos30[/tex]

[tex]\\ \rm\longmapsto \dfrac{\sqrt{3}}{2}[/tex]

Now

[tex]\\ \rm\longmapsto tan\left(\dfrac{2\pi}{4}\right)[/tex]

[tex]\\ \rm\longmapsto tan135[/tex]

[tex]\\ \rm\longmapsto -1[/tex]

HELLLPPPPP!!!!!!!!!!!!!!!!!!

Answers

Answer:

1}6 times

Step-by-step explanation:

The highest number of president born in Virginia minus the highest number of president born in Texas

2}Yes.New York and Mast has the same number of president which is four

3}Yes,this can be done using piechart.

4}I am still working on this question

evaluate each algebraic expression for the given values if the variable

[tex](4d)( - 5d)[/tex]
d= -8​

Answers

Answer:

1280

Step-by-step explanation:

4d*(-5d)=-20(d)^2, d=-8. - 20*64=1280

The inequalities x < -5 and -X > -5 are the same.
True
False

Answers

QUESTION-:

The inequalities x < -5 and -X > -5 are the same.

True

False

ANSWER-:

FALSE

!! HOPE ITS HELP U !!

Qualitative manpower is the most valuable assets of an organization

Answers

Answer:

True

Step-by-step explanation:

Office resources can be defined as all those means, facilities or equipments, including manpower that are utilized in the operation of various office procedures on a daily basis. Thus, office resources comprises means of communication, means of transportation, manpower (workers or employees), furniture, computer, etc.

Basically, the proper and efficient utilization of office resources determine the level of success that would be achieved in any office.

In Business management, office resources are generally grouped into five (5) main categories and these include;

I. Communication.

II. Transportation.

III. Material and office supplies.

IV. Sources of income (finance).

V. Manpower (human resources).

Manpower is also referred to as human resources or office personnels and it can be defined as the total number of people working from the lower hierarchy to top hierarchy of an organization, engaged in various jobs or tasks at different levels.

Basically, manpower is considered to be the most important type of office resources because it is vital for achieving the organizational goal.

This ultimately implies that, the most valuable assets of an organization is its qualitative manpower because it comprises human competence, skills and knowledge.

— 12 — бр – (-2)
HELP ASAP

Answers

Answer:

-10 - 6p

Step-by-step explanation:

-12 - 6р - (-2)

~Combine like terms

-10 - 6p

Best of Luck!

[tex]\huge\text{Hey there!}[/tex]

[tex]\huge\textsf{-12 - 6p - (-2)}\\\\\huge\text{COMBINE the LIKE TERMS}\\\huge\textsf{\underline{\underline{-12 - (-2)}} + \underline{\underline{\underline{(-6p)}}}}\\\\\\\huge\text{\underline{\underline{-12 - (-2)}}}\\\huge\textsf{= -12 + 2}\\\huge\textsf{= \bf -10}\\\\\\\huge\textsf{-6p \text{does not have any like terms so it}}\\\huge\textsf{stays the same}\\\\\\\huge\textsf{= \bf -6p - 10}\\\\\boxed{\boxed{\huge\text{Answer: \bf -6p - 10}}}\huge\checkmark[/tex]

[tex]\huge\text{Good luck on your assignment \& enjoy your day!}[/tex]

~[tex]\boxed{\huge\boxed{\frak{Amphitrite1040:)}}}[/tex]

Hi, just need help with this graph problem.

Answers

Answer:

Domain: (-2, 2]

Range: (-5, 4]

General Formulas and Concepts:

Algebra I

Domain is the set of x-values that can be inputted into function f(x) Range is the set of y-values that are outputted by function f(x)Interval Notation: [Brackets] denote inclusion and (Parenthesis) denote exclusion

Step-by-step explanation:

According to the graph, we see that our x values span from -2 to 2. Since -2 is an open dot and 2 is a closed dot, they are exclusive and inclusive, respectively:

(-2, 2] or -2 < x ≤ 2

According to the graph, we see that our y values span from -5 to 4. Since -5 is an open dot and 4 is a closed dot, they are exclusive and inclusive, respectively:

(-5, 4] or -5 < y ≤ 4

Domain is 2,-2 TGATS all I know

3000 dollars is invested in a bank account at an interest rate of 7 percent per year, compounded continuously. Meanwhile, 20000 dollars is invested in a bank account at an interest rate of 5 percent compounded annually.

To the nearest year, when will the two accounts have the same balance?

Answers

9514 1404 393

Answer:

  after 89 years

Step-by-step explanation:

For principal p, interest rate r, and number of years t, the two account balances are ...

  a = p·e^(rt) . . . . continuous compounding

  a = p(1+r)^t . . . . annual compounding

Using the given values, we have

  3000·e^(0.07t) . . . . . compounded continuously

  20000·1.05^t . . . . . . compounded annually

We want to find t so these are equal.

  3000·e^(0.07t) = 20000·1.05^t

  0.15e^(0.07t) = 1.05^t . . . . divide by 20,000

  ln(0.15) +0.07t = t·ln(1.05) . . . . take natural logarithms

  ln(0.15) = t·(ln(1.05) -0.07) . . . . subtract 0.07t

  t = ln(0.15)/(ln(1.05) -0.07) ≈ -1.8971/-0.02121 . . . . . divide by the coefficient of t

  t ≈ 89.4 ≈ 89

The two accounts will have the same balance after 89 years.

30 points PLEASE HELP!!!!
Find the volume of the pyramid.
76.34 ft3
458.06 ft3
916.11 ft3
305.37 ft3

Answers

Answer:

916.11 ft³

Step-by-step explanation:

(9×6)×7.83/2×13/3

= 211.41×13/3

= 916.11 ft³

Answered by GAUTHMATH

Answer:

916.11 ft³

Step-by-step explanation:

If you rolled a die, what is the probability that you would roll a 3 or a 9? Give your answer as a simplified fraction.
P(3 or 9) =

Answers

Answer: P (3 or 9) = 1/6

Step-by-step explanation:

Concept:

Here, we need to know the idea of probability.

Probability is a measure of the likelihood of an event to occur.

If you are still confused, please refer to the attachment below for a graphical explanation.

Solve:

The numbers on a dice: 1, 2, 3, 4, 5, 6

Total numbers = 6

Number of 3 = 1

Number of 9 = 0

P (3 or 9) = Favorable / Total (refer to the attachment below)

P (3 or 9) = (1 + 0) / (6)

P (3 or 9) = 1 / 6

Hope this helps!! :)

Please let me know if you have any questions

A man was traveling by air is allowed a maximum of 20kg luggages .The man has four bags weighing 3.5kg ,15 kg ,2kg and 1.5kg .Find excess weight of his luggage. 2 . Express the excess weight as a percentage of his maximum weight allowed.

Answers

Answer:

See explanation

Step-by-step explanation:

Maximum weight = 20 kg

Bag 1 = 3.5kg

Bag 2 = 15 kg

Bag 3 = 2kg

Bag 4 = 1.5kg

Total weight of bags = 22 kg

Excess weight of his luggage = Total weight of bags - Maximum weight

= 22 kg - 20 kg

= 2 kg

Express the excess weight as a percentage of his maximum weight allowed = excess weight / maximum weight × 100

= 2/20 × 100

= 0.1 × 100

= 10%

Express the excess weight as a percentage of his maximum weight allowed = 10%

please help (picture) 25 points

Answers

Answer:

1) perimeter = sum of all the sides = 3y+9+2y+4+y+3+2y+4 = 8y+20

2) P = 4(5x-2) = 20x-8

I can't figure this out, please help! I'll give a brainliest

Answers

Answer:

u can use pythagoras or sine rule

Step-by-step explanation:

cos-1(9/11)

From the Rule y = -4x+1 fill in the following table

Answers

Answer:

y: 1, -3, -7, -11, -15

Step-by-step explanation:

Substitute the value of x in the chart for the formula given:

y = -4x + 1

For the first column in the x-row, do the following

y = -4(0) + 1

y = 1

And...

y = -4(1) + 1

y = -3

And so on.

Christian has 1/2 of a foot of tape. His friend gives him 3/10 of a foot of tape. How much tape does Christian have now?

Answers

Answer:

4/5 foot

Step-by-step explanation:

Add the lengths together

1/2 +3/10

Get a common denominator

1/2 *5/5  + 3/10

5/10 + 3/10

8/10

Simplify the fraction by dividing the top and bottom by 2

4/5

[tex]\rm \implies \: Total \: \: length \: \: of \: \: tape \: = \: \frac{1}{2} \: + \: \frac{3}{10} \\ [/tex]

Now , we take LCM of denominators.

LCM of 2 and 10 is 10.

[tex]\bf \large \rightarrow \: \: \frac{5 \: + \: 3}{10} \: = \: \frac{8}{10} \\ [/tex]

Now , simplifying the fraction in simplest form.

[tex]\bf \large \rightarrow \: \: \cancel\frac{8 \: \: ^{4} }{10 \: \: ^{5} } \: = \frac{4}{5} \\ [/tex]

Christian have 4/5 foot of tape have now.

How do you fine the answer ? Help me pls

Answers

Answer:

130

Step-by-step explanation:

divide a sum of rs 1110 between A,B and C so that for every rs 8 given to A,B may get Rs 5 and for every Rs 7 given to B ,C may get rs 4​

Answers

In this question, an amount is divided between three parts. From this, relations between the variables are used to find the amount corresponding to each part.

Sum of 1110 between A, B and C:

This means that:

[tex]A + B + C = 1110[/tex]

For every rs 8 given to A,B may get Rs 5

This means that:

[tex]\frac{A}{B} = \frac{8}{5}[/tex]

And thus:

[tex]5A = 8B[/tex]

[tex]A = \frac{8B}{5}[/tex]

For every Rs 7 given to B ,C may get rs 4​

This means that:

[tex]\frac{B}{C} = \frac{7}{4}[/tex]

And thus:

[tex]7C = 4B[/tex]

[tex]C = \frac{4B}{7}[/tex]

Amount of B:

Replacing into the original equation:

[tex]A + B + C = 1110[/tex]

[tex]\frac{8B}{5} + B + \frac{4B}{7} = 1110[/tex]

[tex]\frac{56B + 35B + 20B}{35} = 1110[/tex]

[tex]111B = 1110*35[/tex]

[tex]B = \frac{1110*35}{111}[/tex]

[tex]B = 350[/tex]

Amounts of A and C:

A and C are given as functions of B, so:

[tex]A = \frac{8B}{5} = \frac{8*350}{5} = 560[/tex]

[tex]C = \frac{4B}{7} = \frac{4*350}{7} = 200[/tex]

Thus:

The amount given to A is of Rs 560, to B is of Rs 350 and to C is of Rs 200.

For another problem involving divisions given ratios, you can check https://brainly.com/question/23857756.

A, B and C receive RS. 560, RS. 350 and RS. 200, respectively.

In this problem, we must translate the sentences into mathematical expression. Please notice that systems of linear equations are resoluble if the number of formulas equals the number of variables. In other words, we must have three linear equations for three variables:

1) Divide a sum of RS 1110 between A, B, C:

[tex]a + b + c = 1110[/tex] (1) Var: 3, Eqs: 1  

2) So that for every RS 8 give to A, B may get RS 5:

[tex]\frac{a}{b} = \frac{8}{5}[/tex]

[tex]5\cdot a - 8\cdot b = 0[/tex] (2) Var: 3, Eqs: 2

3) And for every RS 7 given to B, C may get RS 4:

[tex]\frac{b}{c} = \frac{7}{4}[/tex]

[tex]4\cdot b -7\cdot c = 0[/tex] (3) Var: 3, Eqs: 3

Now we solve the resulting system, the solution set of the system is:

[tex]a= 560[/tex], [tex]b = 350[/tex], [tex]c = 200[/tex]

A, B and C receive RS. 560, RS. 350 and RS. 200, respectively.

james cuts 2 of his neighbor's lawn the first is 1000 m long and 100 m wide what is the area

Answers

The formula for area is l(w). This stands for length and width, or long and wide in this problem. I can multiply 1000(100) to get 100,000m. The area of the lawn is 100,000m.

Step-by-step explanation:

The formula for area is l x b. This stands for length and breadth. I can multiply 1000(100) to get 100,000m. The area of the lawn is 100,000 m.

HOPE IT HELPS YOU

MARK ME BRAINLIEST


(

2
,
2
)
(−2,2) under a translation is
(

3
,
5
)
(−3,5). Find the coordinates of the image of the point
(

3
,
1
)
(−3,1) under the same translation.

Answers

Answer:

kslskd बोडलालामसूनिविवल

Geometry, please answer question ASAP

Answers

Answer:

A

Step-by-step explanation:

The inscribed angle IJK is half the measure of its intercepted arc, so

arc IK = 2 × 75° = 150°

The 3 arcs sum to  360° , then

arc IJ = 360° - (150 + 110)° = 360° - 260° = 100° → A

I need help I don't understand this.

Answers

9514 1404 393

Answer:

  ∠4 = 108°

Step-by-step explanation:

Angles 2 and 4 together form a "linear pair". That is, the sum of them is 180°, a "straight angle." They are supplementary.

  ∠4 = 180° -∠2 = 180° -72°

  ∠4 = 108°

PLEASE HELP WILL MARK BRAINLIEST

Answers

Answer:

I believe its negative nonlinear association

Step-by-step explanation:

The line is going down so its definitely negative

And the line is not straight so its not linear

Therefore, its negative nonlinear association

The frequency table represents the job status of a number of high school students. A 4-column table with 3 rows titled job status. The first column has no label with entries currently employed, not currently employed, total. The second column is labeled looking for job with entries 12, 38, 50. The third column is labeled not looking for a job with entries 28, 72, 100. The fourth column is labeled total with entries 40, 110, 150. Which shows the conditional relative frequency table by column? A 4-column table with 3 rows titled job status. The first column has no label with entries currently employed, not currently employed, total. The second column is labeled looking for a job with entries 0.3, nearly equal to 0.33, 1.0. The third column is labeled not looking for job with entries 0.7, nearly equal to 0.65, 1.0. the fourth column is labeled total with entries nearly equal to 0.27, nearly equal to 0.73, 1.0. A 4-column table with 3 rows titled job status. The first column is blank with entries currently employed, not currently employed, total. The second column is labeled Looking for a job with entries 0.12, 0.38, 050. The third column is labeled not looking for a job with entries 0.28, 0.72, 1.00. The fourth column is labeled total with entries 0.4, 1.1, 1.5. A 4-column table with 3 rows titled job status. The first column has no label with entries currently employed, not currently employed, total. The second column is labeled looking for a job with entries 0.24, 0.76, 1.0. The third column is labeled not looking for a job with entries 0.28, 0.72, 1.0. The fourth column is labeled total with entries nearly equal to 0.27, nearly equal to 0.73, 1.0. A 4-column table with 3 rows titled job status. The first column has no label with entries currently employed, not currently employed, total. The second column is labeled looking for job with entries 0.08, nearly equal to 0.25, nearly equal to 0.33. The third column is labeled not looking for a job with entries nearly equal to 0.19, 0.48, nearly equal to 0.67. The f

Answers

Answer:

[tex]\begin{array}{cccc}{} & {Looking\ for\ job} & {Not\ looking} & {Total} & {Employed} & {0.24} & {0.28} & {0.27} & {Not\ Employed} & {0.76} & {0.72} & {0.73}& {Total} & {1} & {1} & {1} \ \end{array}[/tex]

Step-by-step explanation:

The question is not properly formatted (see attachment for the frequency table and the options)

Required

The conditional relative frequency table by column

We have:

[tex]\begin{array}{cccc}{} & {Looking\ for\ job} & {Not\ looking} & {Total} & {Employed} & {12} & {28} & {40} & {Not\ Employed} & {38} & {72} & {110}& {Total} & {50} & {100} & {150} \ \end{array}[/tex]

To get the conditional frequency by column, we simply divide each cell by the corresponding total value (on the last row)

So, we have:

[tex]\begin{array}{cccc}{} & {Looking\ for\ job} & {Not\ looking} & {Total} & {Employed} & {12/50} & {28/100} & {40/150} & {Not\ Employed} & {38/50} & {72/100} & {110/150}& {Total} & {50/50} & {100/100} & {150/150} \ \end{array}[/tex]

[tex]\begin{array}{cccc}{} & {Looking\ for\ job} & {Not\ looking} & {Total} & {Employed} & {0.24} & {0.28} & {0.27} & {Not\ Employed} & {0.76} & {0.72} & {0.73}& {Total} & {1} & {1} & {1} \ \end{array}[/tex]

Consider the reflection of parallelogram PQRS across the line of reflection wy

Answers

Answer:

Consider the reflection of the parallelogram PQRS across the line of reflection wy if RR = 14 Then RZ= If SX=5 then = 5

Step-by-step explanation:

Simplify the expression.
7(5 +t) - 4(t + 4)
7(5 + t) - 4(t + 4) = [

Answers

7(5 + t) - 4(t + 4) =

= 35 + 7t - 4t - 16 =

= 7t - 4t + 35 - 16 = 3t + 19

37. for the graph x= -3
please help

Answers

Answer: 0

Step-by-step explanation:

Slope of x = -3 is infinite / undefined (there is infinite/no defined change in y for a given change in x). Remember, line x = -3 slopes straight up.

Perpendicular means at a 'right angle to'.

The only kind of line that is perpendicular to a vertical line is a horizontal line, which is like y = 15 or y = 5 or something. The slope of such lines is always zero, because there is no change in line's rise for a given run.

Answer: The slope perpendicular to the line is = 0

Explanation:

the line x= -3 is a special case of the equation of a straight line.

It is a vertical line, and since it parallel to the y-axis, it’s slope is undefined

A line perpendicular to it must be a horizontal line parallel to the x-axis

Parallel to the x-axis means the slope = 0

40) what is the area of a rectangular porch measuring 8 ft x 12/f

45) Create a stem and leaf plot to represent this set of data.
30, 62, 32, 63, 43, 77, 48, 78, 49, 82, 51, 84, 60,


please make sure to answer both questions ​

Answers

40. 8 times 12. = 96 ft

Blanca runs 8 laps around the track each day to train for an endurance race. She times each lap to practice her pacing for the race. The table shows the lap times, in seconds, for three days of practice.

A 3-column table with 8 rows. The first column is labeled day 1 lap times (seconds) with entries 83, 92, 91, 89, 94, 93, 88, 84. The second column is labeled day 2 lap times (seconds) with entries 87, 90, 92, 91, 92, 95, 90, 85. The third column is labeled day 3 lap times (seconds) with entries 85, 86, 91, 93, 91, 89, 88, 84.

Which histogram represents Blanca’s lap times for the three days of practice?

A graph shows lap time (seconds) labeled 82 to 98 on the horizontal axis and number of laps on the vertical axis. 1 lap was 82 to 84 seconds. 4 laps were 84 to 86 seconds. 2 laps were 86 to 88 seconds. 4 laps were 88 to 90 seconds. 6 laps were 90 to 92 seconds. 5 laps were 92 to 94 seconds. 2 laps were 94 to 96 seconds. 0 laps were 96 to 98 laps.
A graph shows lap time (seconds) labeled 82 to 98 on the horizontal axis and number of laps on the vertical axis. 1 lap was 82 to 84 seconds. 3 laps were 84 to 86 seconds. 3 laps were 86 to 88 seconds. 5 laps were 88 to 90 seconds. 5 laps were 90 to 92 seconds. 3 laps were 92 to 94 seconds. 3 laps were 94 to 96 seconds. 1 lap was 96 to 98 seconds.
A graph shows lap time (seconds) labeled 82 to 98 on the horizontal axis and number of laps on the vertical axis. 1 lap was 82 to 84 seconds. 3 laps were 84 to 86 seconds. 3 laps were 86 to 88 seconds. 4 laps were 88 to 90 seconds. 6 laps were 90 to 92 seconds. 4 laps were 92 to 94 seconds. 2 laps were 94 to 96 seconds. 1 lap was 96 to 98 laps.
A graph shows lap time (seconds) labeled 82 to 98 on the horizontal axis and number of laps on the vertical axis. 1 lap was 82 to 84 seconds. 4 laps were 84 to 86 seconds. 2 laps were 86 to 88 seconds. 4 laps were 88 to 90 seconds. 6 laps were 90 to 92 seconds. 3 laps were 92 to 94 seconds. 4 laps were 94 to 96 seconds. 0 laps were 96 to 98 laps.

Answers

Answer:

A graph shows lap time (seconds) labeled 82 to 98 on the horizontal axis and the number of laps on the vertical axis. 1 lap was 82 to 84 seconds.  4 laps were 84 to 86 seconds. 2 laps were 86 to 88 seconds. 4 laps were 88 to 90 seconds. 6 laps were 90 to 92 seconds. 5 laps were 92 to 94 seconds. 2 laps were 94 to 96 seconds. 0 laps were 96 to 98 seconds

Step-by-step explanation:

The given table is presented as follows;

[tex]\begin{array}{ccc}Day \ 1 \ lap \ times \ (seconds)&Day \ 2 \ lap \ times \ (seconds)&Day \ 3 \ lap \ times \ (seconds)\\83&87&85\\92&90&86\\91&92&91\\89&91&93\\94&92&91\\93&95&89\\88&90&88\\84&85&84\end{array}[/tex]The number of laps in the range 82 to 84 seconds = 1

The number of laps in the range 84 to 86 seconds = 4

The number of laps in the range 86 to 88 seconds = 2

The number of laps in the range 88 to 90 seconds = 4

The number of laps in the range 90 to 92 seconds = 6

The number of laps in the range 92 to 94 seconds = 5

The number of laps in the range 94 to 96 seconds = 2

The number of laps in the range 96 to 98 seconds = 0

Therefore, the histogram that represents Blanca's lap times for the three days of practice is described as follows;

A graph shows lap time (seconds) labeled 82 to 98 on the horizontal axis and the number of laps on the vertical axis. 1 lap was 82 to 84 seconds.  4 laps were 84 to 86 seconds. 2 laps were 86 to 88 seconds. 4 laps were 88 to 90 seconds. 6 laps were 90 to 92 seconds. 5 laps were 92 to 94 seconds. 2 laps were 94 to 96 seconds. 0 laps were 96 to 98 seconds

Answer: A.

Step-by-step explanation: On Edge!

Can someone help me out

Answers

Answer: V=9.4 cm^3

Step-by-step explanation:

[tex]V=\pi r^2h\\V=\pi (1)^2(3)\\V=9.4cm^3[/tex]

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The third-person omniscient point of view means that readersknow that they are about to watch Herman get a very unpleasantsurpriseOC. The third-person limited point of view means that the audienceknows that Fyodor was eating peanuts but is curious about whathappened during Herman's meetingD. The third-person omniscient point of view means that Fyodordoesn't know that Herman will come back, but the audience doesknow An employee is scheduled to work 40 hours per week at a base rate of $18.50 per hour. In addition to the 40 scheduled hours, the employee is asked to work 8 hours of overtime for one week due to staffing shortages. If overtime is paid at a rate of 1.5 times the base rate, how much will the employee earn for the week? (use $xxx.Xx format) How can you use these resources to help you to understand the text and accomplish the lessons for the reading? Solve for the value of n.n = How are the nervous system and the endocrine system important for teenagers in terms of health, growth, and development? identify the roots of the equation and the multiplicities of the roots 8(x - 2) = 0 Find the measures of angles S and T in the triangle below. Write an equation to represent each function.(image attached) Question in Statistics and Probability 2Petrol samples were taken at three different stations along a national highway to determine whether theoctane rating varied from one station to another. Six petrol specimens of the same category were randomly selected at each station in different days.We are interested to know if there is sufficient evidence to indicate a difference in the mean octanerating at the different stations.State the Null and the Alternative Hypotheses. which of these figures has rotational symmetry Huffman Corporation constructed a building at a cost of $30,000,000. Weighted-average accumulated expenditures (WAAE) were $12,000,000, actual interest was $1,200,000, and avoidable interest was $1,600,000. If the salvage value is $2,400,000, and the useful life is 40 years, depreciation expense for the first full year using the straight-line method isa. $690,000b. $705,000.c. $720,000.d. $735,000. AYUDA DOY CORONA, DEBO ENTREGARLA HOY A LAS 6:00 P.MNecesito descomponer este prrafoUn presente se olvid del pasadoPero pronto Cali empez a verse como un gigante que expanda sus tentculos sin control, se vio henchido y sometido por sus propias fuerzas. En un abrir y cerrar de ojos, entre 1933 y 1958, aument cinco veces su poblacin. Los defensores de la ciudad de hierro no previeron la marea de inmigrantes que llegaron a recorrer las calles y a trabajar en las fbricas. La ciudad en expansin se sali de las manos de sus administradores. Aqu y all se extendan invasiones, barrios piratas y barrios clandestinos. Algunos bordearon la zona del ro y en pocas de invierno sufrieron inundaciones.Urbanizaciones piratas vendieron lotes en tierras inestables sin suministro de agua ni alcantarillado. El crecimiento desmedido de la ciudad de hierro desbord la capacidad de la vieja Cali. El precio del suelo se elev y quienes no podan comprar tierra se fueron a vivir a las altas pendientes del occidente, cerca a las minas de carbn que explotaban para alimentar el ferrocarril. En 1953, la ciudad, constreida y rebasada, empez a buscar maneras de tomar las aguas del ro Cauca y explotar sus tierras aledaas. Para contener las inundaciones construyeron un jarilln en el oriente de la ciudad, crearon canales para la recoleccin de aguas lluvias y estaciones de bombeo.En los aos siguientes Cali continu su expansin desbordada. Miles de inmigrantes llegaban en busca de empleo, otros terminaron desplazados por la violencia en el campo y se asentaron a pelear un espacio en la gran urbe. Muchas comunidades negras llegaban desde los asentamientos del pacfico y el norte del Cauca, mientras comunidades campesinas venan desde parcelas precarias saqueadas por la violencia.Pronto las empresas debieron extender nuevas redes de acueducto y alcantarillado. Al ro Cauca empez a llegar el 70% de las aguas sucias de Cali. Todos los residuos fecales, industriales y hospitalarios vertidos a las alcantarillas desembocaban en las aguas del ro Cauca. Para mitigar el dao y explotar las tierras inundables que bordeaban el cauce, la CVC, la entidad protectora de las aguas y la contaminacin ambiental de la regin, construy un extenso canal que interceptaba los ros Lili, Melndez y Caaveralejo. Estos a su vez ya haban sido interceptados por nuevos sectores de la ciudad y usados como depsitos de desperdicios. Buscaban que los ros desembocaran sobre el canal y que en l se produjera una corriente de agua menor a la corriente natural para que los contaminantes se dispersaran tras su llegada al ro Cauca.Tambin los administradores de los servicios pblicos buscaron un lugar para arrojar las toneladas de basura que, a diario, produca la nueva ciudad de hierro. En 1967 escogieron el suroriente y sobre un antiguo cauce del ro, en una zona de humedal, dispusieron doce mil metros cuadrados, con una profundidad de veinte metros bajo el nivel del mar, para arrojar todos los desechos de la ciudad. Le llamaron el basuro de Navarro, un gigante colector de descomposicin. Which of the following are examples of third party software that banks use? (Select all that apply.) A -compliance reportingB -unencrypted Microsoft Suite C -accounting softwareD -customer relationship management