Issac wants the equation below to have no solution

Explanation:

Add up those areas to get the final answer

x^2+9x+2x+18 = x^2+11x+18

note the like terms 9x and 2x combine to 11x

The answer is 48 notepads.

Answer:

C and D

Step-by-step explanation:

The data is represented in a box plot given. In a box plot, the min, max, median, Q1, and Q3 are displayed.

If you want to measure the center of the data, you can make use of the median.

Also, an appropriate measure of spread to use is the interquartile range.

Interquartile range = Q3 - Q1.

Better measure of center to use is Mean while better measure of spread is interquartile range.

The correct options for measures of center and spread for the data set is option C and D

The measures of center of data include the mean, median and mode.

The measures of spread include range, mean deviation, variance and standard deviation.

The give dat is a box plot where the min, max, median, Q1, and Q3 are shown.

The best measure of the center of the data, is the median.

The appropriate measure of spread is the interquartile range.

In conclusion, the more appropriate measures of center and spread for the data set is median and interquartile range respectively.

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Answer:

11.4pounds

Step-by-step explanation:

(5.58+4.68)÷0.90

＝11.4(pounds)

9514 1404 393

Answer:

  84 adult tickets

Step-by-step explanation:

Let 'a' represent the number of adult tickets sold. Then (135-a) is the number of child tickets sold, and total revenue is ...

  5.70(135 -a) +9.40(a) = 1080.30

  3.70a = 310.80 . . . . . . . . subtract 769.50 and simplify

  a = 310.80/3.70 = 84

84 adult tickets were sold on Sunday.

Answer:

This triangle is a right triangle

Answer:

A sample of 752 should be taken.

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of [tex]\pi[/tex], and a confidence level of [tex]1-\alpha[/tex], we have the following confidence interval of proportions.

[tex]\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}[/tex]

In which

z is the z-score that has a p-value of [tex]1 - \frac{\alpha}{2}[/tex].

The margin of error is of:

[tex]M = z\sqrt{\frac{\pi(1-\pi)}{n}}[/tex]

90% confidence level

So [tex]\alpha = 0.1[/tex], z is the value of Z that has a p-value of [tex]1 - \frac{0.1}{2} = 0.95[/tex], so [tex]Z = 1.645[/tex].

No preliminary sample is taken

This means that [tex]\pi = 0.5[/tex]

How large should the sample be to be 90% sure that the estimate is within .03 of the population proportion?

This is n for which M = 0.03. So

[tex]M = z\sqrt{\frac{\pi(1-\pi)}{n}}[/tex]

[tex]0.03 = 1.645\sqrt{\frac{0.5*0.5}{n}}[/tex]

[tex]0.03\sqrt{n} = 1.645*0.5[/tex]

[tex]\sqrt{n} = \frac{1.645*0.5}{0.03}[/tex]

[tex](\sqrt{n})^2 = (\frac{1.645*0.5}{0.03})^2[/tex]

[tex]n = 751.7[/tex]

Rounding up:

A sample of 752 should be taken.

Answer:

8

Step-by-step explanation:

by definition:

[tex]log_an=16\\\\log_a\sqrt{n}=log_a n^{\frac{1}{2}}=\frac{1}{2}log_a n=\frac{1}{2}(16)=8[/tex]

Answer:

56 dollars

Step-by-step explanation:

idfk 56 dollars is the answer tho

Answer:

A: True

Step-by-step explanation:

It's true because central tendency is defined as a branch of descriptive statistics that shows the centre of the data distribution.

This central tendency could be mean, median or mode.

Answer:

324 kilometres

What I did was do 36x10 which is 360

Then I did 360-36=24 because the question wants 9x36 not 10x36

The expected count for the cell corresponding to cities with more than 250,000 residents whose name has less than 8 characters is A = 33.45

A mathematical function called a probability distribution explains the likelihood of many alternative values for a variable. Graphs or probability tables are frequently used to represent probability distributions.

The mean of probability distribution is also known as expected value. It is denoted by E ( X ). E(X), or mean μ of a discrete random variable X is calculated by multiplying each value of the random variable by its probability and taking the sum of the values.

E ( X ) = μ = ∑x P ( x )

Given data ,

To find the expected count for the cell corresponding to cities with more than 250,000 residents whose name has less than 8 characters, we need to calculate the expected count for that cell using the formula:

Expected Count = (row total * column total) / grand total

The row total for cities with more than 250,000 residents is 99, and the column total for names with less than 8 characters is 100. The grand total is 296

Expected Count = (99 * 100) / 296

Expected Count ≈ 33.45

Therefore , the expected count for the cell corresponding to cities with more than 250,000 residents whose name has less than 8 characters is approximately 26.67

Hence , the distribution is 33.45

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The complete question is attached below :

Judson collected information about the name length and the population of a random sample of 296 American cities. Here are the results:

Judson wants to perform a X2 test of independence between name length and population. What is the expected count for the cell corresponding to cities with more than 250,000 residents whose name has less than 8 characters?

Answer:

c. 13

Explanation:

f(x) = x² + 4

f(3) = (3)² + 4

= 9 + 4

= 13

Answer:

23 blocks

Step-by-step explanation:

Count the blocks

The back wall has 3 blocks by 5 blocks which is 15 blocks

The front cubs has 4 blocks by 2 blocks = 8 blocks

Add them together = 15+8 = 23 blocks

Answer:

value of 4 in 543007 is 40,000 bc it falls in the 10,000 spot.

Answer:

a bicycle

Step-by-step explanation:

Answer:

B.  A bicycle

Step-by-step explanation:

B.  A bicycle

All the others would most likely be in grams

Answer:

[tex]\frac{x2}{a} - \frac{y2}{b2} = 1[/tex]

Step-by-step explanation:

A hyperbola is the locus of a point such that its distance from a point to two points (known as foci) is a positive constant.

The standard equation of a hyperbola centered at the origin with transverse on the x axis is given as:

[tex]\frac{X2}{16} - \frac{b}{4} = 1[/tex]

The coordinates of the foci is at (±c, 0), where c² = a² + b²

Given that  a hyperbola centered at the origin with x-intercepts +/- 4 and foci of +/-2√5. Since the x intercept is ±4, this means that at y = 0, x = 4. Substituting in the standard equation:

I don't feel like explaining so...

a. = 4

The foci c is at +/-2√5, using c² = a² + b²:

B = 2

Substituting the value of a and b to get the equation of the hyperbola:

[tex]\frac{x2}{a2} - \frac{y2}{b2} = 1[/tex]  

[tex]\frac{x2}{16} - \frac{b2}{4} = 1[/tex]

Answer:

25%

Step-by-step explanation:

We can also show this from the results table below: There are 8 possible outcomes for tossing three coins. Two of these outcomes are either all heads or all tails, Therefore there is a 28=14=0.25=25% chance of getting all heads or all tails.

Answer:

a) Sample space = RR, RB, RG, RY, BB, BR, BG, BY, GG, GR, GB, GY, YY, YR, YB, YG .

probability distribution of outcomes

= (3/14*3/14),  (3/14*4/14),  (3/14*4/14),  (3/14*3/14),  (4/14 *4/14 ), (4/14*3/14), (4/14 * 4/14),  (4/14 * 3/14 ),  ( 4/14 *4/14 ),  (4/14*3/14),  ( 4/14 *4/14 ),  

(4/14*3/14),   (3/14 *3/14 ), (3/14*3/14),  (3/14 *4/14 ), ( 3/14 * 4/14 )

b)  0.0459

c) ( 3/14 * 4/14 ) + ( 3/14 * 4/14 ) + ( 3/14 * 3/14 ) + ------ ( 3/14 * 4/14 )

Step-by-step explanation:

Total number of balls = 3 + 4 + 4 + 3 = 14 balls

3 Red balls = 3/14

4 blue balls  = 4/14

4 green balls = 4/14

3 yellow balls = 3/14

a) Determine the sample space and probability distribution of outcomes

since ball is drawn with replacement

Sample space = RR, RB, RG, RY, BB, BR, BG, BY, GG, GR, GB, GY, YY, YR, YB, YG .

i.e. The sample space has 16 possible combination

probability distribution of outcomes

= (3/14*3/14),  (3/14*4/14),  (3/14*4/14),  (3/14*3/14),  (4/14 *4/14 ), (4/14*3/14), (4/14 * 4/14),  (4/14 * 3/14 ),  ( 4/14 *4/14 ),  (4/14*3/14),  ( 4/14 *4/14 ),  

(4/14*3/14),   (3/14 *3/14 ), (3/14*3/14),  (3/14 *4/14 ), ( 3/14 * 4/14 )

b) Determine  P( R and R )

P ( R and R ) = 3/14 * 3/14

                    = 9/196 =  0.0459

C) Determine probability of drawing two different balls

P( R and B ) + P ( R and G ) + P ( R and Y ) + ------ P ( Y and G )

= ( 3/14 * 4/14 ) + ( 3/14 * 4/14 ) + ( 3/14 * 3/14 ) + ------ ( 3/14 * 4/14 )

Hi there!  

»»————-　★　————-««

I believe your answer is:  

C) x = 16

»»————-　★　————-««  

Here’s why:  

⸻⸻⸻⸻

[tex]\boxed{\text{Solving for 'x'...}}\\\\\frac{x}{2}=8\\-------\\\rightarrow{\frac{x}{2}=8}\\\\\rightarrow(\frac{x}{2}})*2=8*2\\\\\rightarrow\boxed{x=16}[/tex]

⸻⸻⸻⸻

»»————-　★　————-««  

Hope this helps you. I apologize if it’s incorrect.  

Answer:

x = 16

Step-by-step explanation:

х/2 = 8

Multiply each side by 2

x/2*2 = 8*2

x = 16

Answer:

5 (cm)

Step-by-step explanation:

1. according to the condition in ΔABC: AC=BC, m∠C=90°. Then m∠B=m∠A=45° and

2. x=AC=AB/√2; ⇔ x=5 (cm).

Answer:

x=5 cm

Step-by-step explanation:

triangle ABC is an isoceles triangle

so BC=AC and angle A=angle B

BC=X and angle A=theta

angle B and angle A both is theta degree because base angles of an isosceles triangle are equal

to find angle A and B

angle A + angle B + angle c=180 degree (sum of interior angles of a triangle)

theta + theta +90=180

2theta=180-90

2theta=90

theta=90/2

theta=45 degree

sin both angle A and angle B are theta their value is 45 degree.

For side x

now using pythagoras theorem

take theta as reference angle

using sin rule

sin 45=opposite/hypotenuse

[tex]\frac{1}{\sqrt{2} }[/tex] =x/[tex]5\sqrt{2}[/tex]

[tex]\frac{1}{\sqrt{2} } *5\sqrt{2}[/tex]=x

[tex]\frac{5\sqrt{2} }{\sqrt{2} } }[/tex]=x

5=x

Answer: 3/8 yard

Step-by-step explanation:

Since the beetle crawled 1/2 of a yard and the spider crawled 1/8 of a yard. To calculate how much farther the beetle crawl than the spider, we will have to subtract 1/8 from 1/2. This will be:

= 1/2 - 1/8

= 4/8 - 1/8

= 3/8 yard

Therefore, the beetle covered 3/8 yard more.

Answer:

19

Step-by-step explanation:

5 + 4^2 - 6/3

= 5 + 16 - 2

= 21 - 2

= 19

Step-by-step explanation:

l hope it helps mark the brainliest plzz

Answer:

option c is correct

Step-by-step explanation:

(3x^2 + 3)(4 + x^3)

=3x^2(4 + x^3) +3(4 + x^3)

=12x^2 + 3x^5 +12 +3x^3

=3x^5 + 3x^3 + 12x^2 + 12    

Answer:

10.5 is the answer

Step-by-step explanation:

i hope it helps u

Answer:

is the answer y=7? if correct its ok but if the answer didn't match then plesse let me know

Answer:

Matched samples

Step-by-step explanation:

A matched sample is obtained when pairing of treatment values for each subject or observation is performed. This sample obtained from a matched pair is usually called dependent sample and is usually done when each subject in an experiment is subjected to two different treatments usually at different time or stage. Hence, matched samples are used in matching observations to tie different groups.

Answer:

the minimum is 0 and the maximum is 16.

Step-by-step explanation:

For a function f(x), the maximum is defined as:

f(xₐ)

such that:

f(xₐ) ≥ f(x) for every value of x in the domain.

And the minimum is:

f(xₙ)

Such that:

f(xₙ) ≤ f(x)

for every value of x.

Now, in this case we have the function:

f(x) = (-x + 2)^4 in the range  0 < x < 3

First, let's analyze our function.

We can see that the exponent is even, then:

f(x) = (-x + 2)^4

Can be equal to zero or larger than zero.

Then the minimum will be f(x) = 0

To find this, we need to find the value of x such that:

-x +2 = 0

2 = x

Then the minimum is:

f(2) = (-2 + 2)^4 = 0

For the maximum, we can just play with the other values in the range and see which one gives the larger value of f(x).

Again, because f(x) =  (-x + 2)^4 , the maximum will be at the value of x such that:

|-x + 2| is maximized.

As we have a negative sign multiplying x, the smaller value in the range:

x = 0

is the one that maximizes that:

|-0 + 2| = |2| = 2

Evaluating f(x) in x = 0 we get:

f(0) = (0 + 2)^4 = 16

Then the minimum is 0 and the maximum is 16.