Is there job placement assistance or career services offered? Do they need to obtain more training/schooling for nursing?

Answers

Answer 1
If you need a job placement, you have to have money to pay for it. For nursing to get better, I think training and schooling is very good for nursing. You can search it up if you don’t know.

Related Questions

Antique Accents tracks their daily profits and has found that the distribution of profits is approximately normal with a mean of $17,700.00 and a standard deviation of about $900.00. Using this information, answer the following questions. For full marks your answer should be accurate to at least three decimal places.

Answers

Answer:

a) 0.434

b) 0.983

c) 0.367

Explanation:

The exact question with the given parameters wasn't obtained online, but the same question, albeit with different parameters is then obtained. Hopefully, this Helps to solve the complete question with the required parameters.

Antique Accents tracks their daily profits and has found that the distribution of profis is approximately normal with a mean of $17,700.00 and a standard deviation of about $900.00. Using this information, answer the following questions For full marks your answer should be accurate to at least three decimal places. Compute the probability that tomorrow's profit will be

a) less than $16,791 or greater than $18,231

b) greater than $15,783

c) between $17,997 and $20,130

Solution

This is a normal distribution problem with

Mean = μ = $17,700

Standard deviation = σ = $900

a) less than $16,791 or greater than $18,231. P(x < 16,791) or P(X > 18,231) = P(X < 16,791) + P(x > 18,231)

We first standardize 16,791 and 18,231

The standardized score for any value is the value minus the mean then divided by the standard deviation.

For 16791

z = (x - μ)/σ = (16791 - 17700)/900 = - 1.01

For 18231

z = (x - μ)/σ = (18231 - 17700)/900 = 0.59

To determine the required probability

P(X < 16,791) + P(x > 18,231) = P(z < -1.01) + P(z > 0.59)

We'll use data from the normal probability table for these probabilities

P(X < 16,791) + P(x > 18,231) = P(z < -1.01) + P(z > 0.59)

P(z < -1.01) = 0.15625

P(z > 0.59) = 1 - (z ≤ 0.59) = 1 - 0.7224 = 0.2776

P(X < 16,791) + P(x > 18,231) = P(z < -1.01) + P(z > 0.59) = 0.15625 + 0.2776 = 0.43385 = 0.434 to 3 d.p

b) greater than $15,783. P(x > 15783)

We standardize 15783

z = (x - μ)/σ = (15783 - 17700)/900 = -2.13

To determine the required probability

P(x > 15783) = P(z > -2.13)

We'll use data from the normal probability table for this probability

P(x > 15783) = P(z > -2.13) = 1 - P(z ≤ - 2.13)

= 1 - 0.01659 = 0.98341 = 0.983 to 3 d.p.

c) between $17,997 and $20,130.

P(17,997 < x < 20,130)

We first standardize 17,997 and 20,130

The standardized score for any value is the value minus the mean then divided by the standard deviation.

For 17,997

z = (x - μ)/σ = (17,997 - 17700)/900 = 0.33

For 20,130

z = (x - μ)/σ = (20,130 - 17700)/900 = 2.70

To determine the required probability

P(17,997 < x < 20,130) = P(0.33 < x < 2.70)

We'll use data from the normal probability table for these probabilities

P(17,997 < x < 20,130) = P(0.33 < x < 2.70)

= P(z < 2.70) - P(z < 0.33)

= 0.99653 - 0.62930

= 0.36723 = 0.367 to 3 d.p.

Hope this Helps!!!

Ode to the west wind Which statement best completes the blank in this graphic organizer?
The speaker is openly frightened.
The speaker is desperately hopeful.
The speaker is extremely doubtful.
The speaker is unashamedly excited.

Answers

Answer:

B) The speaker is desperately hopeful.

Explanation:

correct on edg2020

Answer:

b. The speaker is desperately hopeful

Explanation:

Which is an example of a reflex?

A blue jay gathers materials to build a nest in a tree.
A snake searches for food when it becomes hungry.
A bobcat’s eyes adjust to the darkness by allowing more light in.
A goose migrates south around the same time every year.

Answers

C)
A bobcats eyes adjust to the darkness by allowing more light in!

Answer:

C. GOT IT RIGHT ON EDGE 2022

Explanation:

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