No they are not the same.
We can plug in x = 0 to get
11-2x = 11-2(0) = 11-0 = 11
2x-11 = 2(0)-11 = 0-11 = -11
We get the results 11 and -11 for the expressions 11-2x and 2x-11 respectively. Since we got different outputs, this is enough to show that the expressions are not the same. They would need to produce the same outputs for any given x value.
On a graph, y = 11-2x and y = 2x-11 are two different lines to show they are not the same expression.
note: if you plug in x = 11/2 = 5.5, then both outputs are the same; otherwise, you'll get different outputs.
Find the term of each sequence.
32, 80, 200, ...5th term
Answer:
t5 = 1250
Step-by-step explanation:
Each term is derived by multiplying the previous term by 2.5
t2 = t1 * 2.5
t2 = 32 * 2.5
t2 = 80
===========
tn = a*b^(n - 1)
t3 = 32*2.5^2
t3 = 200
That's just to test the formula. It does work.
===============
t5 = 32*2.5^(5 -1)
t5 = 32*2.5^4
t5 = 1250
Which equation represents a population of 300 animals that decreases at an annual rate of 23%? A. p=300(1.23)t B. p=300(1.77)t C. p=300(0.77)t D. p=300(0.23)t
For a given initial quantity A, a decrease of x% can be written as:
A - A*(x%/100%) = A*(1 - x%/100%)
With this, we need to construct an exponential decrease equation for the given situation, and we will find that the equation is:
P(t) = 300*(0.77)^t
Now let's see how we found that.
In this case, we know that:
The initial number of animals is 300.
They decrease at an anual rate of 23%.
This means that after the first year, the population will be:
P(1) = 300 - 300*(23%/100$) = 300*( 1 - 0.23) = 300*(0.77)
After another year, the population decreases again, so we get:
P(2) = 300*(0.77) - 300*(0.77)*(23%/100$) = 300*(0.77)^2
Here we already can see the pattern, the population in the year t, we will get:
P(t) = 300*(0.77)^t
Then we can see that the correct option is C.
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△ABCis reflected to form △A′B′C′. The vertices of △ABC are A(-1, 3), B(2, 4), and C(-5, 6). The vertices of △A′B′C′ are A′(3, −1), B′(4, 2), and C′(6, −5). Which reflection results in the transformation of △ABC to △A′B′C′? Reflection across the x-axis reflection across the y-axis reflection across y = x reflection across y=−x
Answer:
reflection across y = x
Step-by-step explanation:
Transformation is the movement of a point from its initial position to a new position. If a shape is transformed, all its point are also transformed. Types of transformation is reflection, rotation, transformation and dilation.
If a point is reflected across the x axis, the x coordinate is the same but the y coordinates is negated. If X(x, y) is reflected across the x axis the new point is X'(x, -y)
If a point is reflected across the y axis, the y coordinate is the same but the x coordinates is negated. If X(x, y) is reflected across the y axis the new point is X'(-x, y)
If a point is reflected across y = x, the x coordinate and y coordinates are interchanged. If X(x, y) is reflected across the y=x axis the new point is X'(y, x)
If a point is reflected across y = -x, the x coordinate and y coordinates are interchanged and both negated. If X(x, y) is reflected across the y=ix axis the new point is X'(-y, -x)
The vertices of △ABC are A(-1, 3), B(2, 4), and C(-5, 6). The vertices of △A′B′C′ are A′(3, −1), B′(4, 2), and C′(6, −5). The reflection of △ABC to form △A′B′C′ shows a reflection across x axis since the x and y coordinates are interchanged
Answer:
reflection across y = x
Step-by-step explanation:
Find the exact value of cos A in simplest radical form.
Answer:
[tex] \cos(A) = \frac{2 \sqrt{6} }{7} [/tex]Step-by-step explanation:
Since we are finding cos A we have
[tex] \cos(A) = \frac{AC}{AB} [/tex]From the question
AC = √96
AB = 14
Substitute the values into the above formula
That's
[tex] \cos(A) = \frac{ \sqrt{96} }{14} [/tex]We have the final answer as
[tex] \cos(A) = \frac{2 \sqrt{6} }{7} [/tex]Hope this helps you
order of operation
3⋅6−2+2
Answer:
18
Step-by-step explanation:
3⋅6−2+2
Use PEMDAS = Parentheses, Exponent, Multiplication, Division, Addition, Subtraction
First we multiply, then add or subtract so,
18 - 2 + 2
Now we subtract,
16 + 2
Now we add,
18
I'm doing a task which involves magic v's, a maths pattern which has the rule of having the same total on each side. For e.g.
6 5
3 4
2
Is a magic v because each side adds up to 11. I need to make magic V's with the number 2-6 and 3-7. There are 24 possibilities for each number set.
Answer:
--1-- (of set 23456)
2 4
5 3
6
--2-- (of set 23456)
2 3
5 4
6
--3-- (of set 23456)
2 5
6 3
4
--4-- (of set 23456)
2 3
6 5
4
--5-- (of set 23456)
3 5
4 2
6
--6-- (of set 23456)
3 2
4 5
6
--7-- (of set 23456)
3 6
5 2
4
--8-- (of set 23456)
3 2
5 6
4
--9-- (of set 23456)
3 5
6 4
2
--10-- (of set 23456)
3 4
6 5
2
--11-- (of set 23456)
4 5
3 2
6
--12-- (of set 23456)
4 2
3 5
6
--13-- (of set 23456)
4 6
5 3
2
--14-- (of set 23456)
4 3
5 6
2
--15-- (of set 23456)
5 4
2 3
6
--16-- (of set 23456)
5 3
2 4
6
--17-- (of set 23456)
5 6
3 2
4
--18-- (of set 23456)
5 2
3 6
4
--19-- (of set 23456)
5 6
4 3
2
--20-- (of set 23456)
5 3
4 6
2
--21-- (of set 23456)
6 5
2 3
4
--22-- (of set 23456)
6 3
2 5
4
--23-- (of set 23456)
6 5
3 4
2
--24-- (of set 23456)
6 4
3 5
2
--1-- (of set 34567)
3 5
6 4
7
--2-- (of set 34567)
3 4
6 5
7
--3-- (of set 34567)
3 6
7 4
5
--4-- (of set 34567)
3 4
7 6
5
--5-- (of set 34567)
4 6
5 3
7
--6-- (of set 34567)
4 3
5 6
7
--7-- (of set 34567)
4 7
6 3
5
--8-- (of set 34567)
4 3
6 7
5
--9-- (of set 34567)
4 6
7 5
3
--10-- (of set 34567)
4 5
7 6
3
--11-- (of set 34567)
5 6
4 3
7
--12-- (of set 34567)
5 3
4 6
7
--13-- (of set 34567)
5 7
6 4
3
--14-- (of set 34567)
5 4
6 7
3
--15-- (of set 34567)
6 5
3 4
7
--16-- (of set 34567)
6 4
3 5
7
--17-- (of set 34567)
6 7
4 3
5
--18-- (of set 34567)
6 3
4 7
5
--19-- (of set 34567)
6 7
5 4
3
--20-- (of set 34567)
6 4
5 7
3
--21-- (of set 34567)
7 6
3 4
5
--22-- (of set 34567)
7 4
3 6
5
--23-- (of set 34567)
7 6
4 5
3
--24-- (of set 34567)
7 5
4 6
3
Step-by-step explanation:
This javascript code is extremely brute-force, but it does the job:
function checkIfInSet(i, set) {
return i.toString().split('').sort().join('') === set;
}
function checkIfMagic(s) {
return (parseInt(s[0]) + parseInt(s[1]) == parseInt(s[3]) + parseInt(s[4]))
}
function printMagic(s) {
console.log(`${s[0]} ${s[4]}`);
console.log(` ${s[1]} ${s[3]}`);
console.log(` ${s[2]}\n`);
}
function checkSet(set) {
let counter = 1;
for(let i=1; i<99999; i++) {
if (checkIfInSet(i, set) && checkIfMagic(i.toString())) {
console.log(`--${counter++}-- (of set ${set})`);
printMagic(i.toString());
}
}
}
checkSet('23456');
checkSet('34567');
Em um posto de combustível, o litro da gasolina estava custando R$2,40.Um cliente gastou R$72,00 para encher o tanque de seu carro. O valor do litro da gasolina sofreu 2 aumentos sucessivos,ambos de 10%. Quando o mesmo cliente gastara para encher o tanque do seu carro, após esees aumentos
Answer:
english i think u need hekp
Find the distance between the two points (-4,4) and (1,0)
Answer:
The answer is
[tex] \sqrt{41} \: \: \: units[/tex]Step-by-step explanation:
The distance between two points can be found by
[tex] \sqrt{ ({x _{1} - x_{2} })^{2} + ({y_{1} } - y_{2} )^{2} } [/tex]
where
( x1 , y1) and ( x2 , y2) are the points
So the distance between (-4,4) and (1,0) is
[tex] \sqrt{( { - 4 - 1})^{2} + ( {4 - 0})^{2} } [/tex][tex] = \sqrt{ ({ - 5})^{2} + {4}^{2} } [/tex][tex] = \sqrt{25 + 16} [/tex]We have the final answer as
[tex] \sqrt{41} \: \: \: units[/tex]Hope this helps you
...................................................
Answer:
11.21157846 =x
Step-by-step explanation:
We know log b (a) = c can be written as b^c =a
log 3 (x) = 2.2
3^2.2 = x
11.21157846 =x
Answer:
[tex]\large \boxed{\sf \bold{A.} \ x=11.21}[/tex]
Step-by-step explanation:
[tex]\large \sf log_3 (x)=2.2[/tex]
Solve this by converting the logarithmic statement into its equivalent exponential form, using the relationship:
[tex]\large \sf log_b(y)=x[/tex]
[tex]\large{\sf y=b^x}[/tex]
Apply the relationship.
[tex]\large \sf log_3 (x)=2.2[/tex]
[tex]\large \sf x=3^{2.2}[/tex]
[tex]\large \sf x=11.21157845...[/tex]
[tex]\large \sf x \approx 11.21[/tex]
Samantha’s college runs on a trimester schedule so she receives a bill 3 times a year for tuition. Each trimester costs $1,450, and Samantha must complete 2 years of college to receive her degree. The average cost for books each trimester is $350. Approximately what will be the total cost for Samantha to get her degree?
Answer:
10800
Step-by-step explanation:
1 trimesters cost = 1450 + 350 $
2 year -> 6 trimester
1800$ x 6 = 10800 $
solving polynomial(2x+8)(-3y-8)
Answer:
-6xy - 16x -24y -64
Step-by-step explanation:
(2x+8)(-3y-8) =
To find the answer,
First multiply, the first number on both sides,
2x * -3y = -6xy
Then the first number on the left side and the second number on the right side,
2x * -8 = -16x
Then the second number on the left side and the first number on the right side,
8 * -3y = -24y
Then the second number on the left side and the second number on the right side,
8 * -8 = -64
Now add all the answers,
-6xy -16x -24y -64
Answer:
-6xy-16x-24y-64
Step-by-step explanation:
(2x+8)(-3y-8)
Foil
First 2x*-3y = -6xy
outer -8*2x = -16x
inner -3y *8 = -24y
last -8*8 = -64
Add them together
-6xy-16x-24y-64
What is the other endpoint of a segment with a midpoint of M(6, 1) and an endpoint S(5,-3)?
ANSWERS ASAP!!!!
Answer:
(7, 5)
Step-by-step explanation:
(x+5)/2, ( y-3)/2)=(6,1)
(x+5)/2=6, x= 7
( y-3)/2=1, y=5
A. 115
B. 167
C. 126
D. 96
Answer:
126
Step-by-step explanation:
Let x be the missing length
The triangles are similar:
● UE/140 = 45/x
From the graph we deduce that:
● UE = 140 - 90 = 50
Replace UE by its value
● 50/ 140 = 45/x
Switch x and 50
● x / 140 = 45/50
45/50 is 9/10 wich is 0.9
● x/140 = 0.9
Multiply 0.9 by 140
● x = 140 × 0.9
● x = 126
Answer:
I think its c 126
Step-by-step explanation:
5. Eight adults and six children travel in a cable car.
Estimate the total mass of the people in the cable car.
Answer: 1880 pounds
Step-by-step explanation: when you take the average adult weight, around 160 lbs. you multiply that by eight. you get 1280. then you estimate that each of the children weigh around 100 lbs, then you add 600 to 1280 and get 1,880 lbs
write 1,245 in word form
Answer:
One thousand two hundred and forty five.
Hope this helps! （づ￣3￣）づ╭❤～
Step-by-step explanation:
HELP ME PLZZzzzzzzzz
Answer:
5 cm
Step-by-step explanation:
The volume (V) of milk in the container is calculated as
V = 8 × 15 × 12 = 480 cm³
After change of position with depth d then
8 × 15 × d = 480
120d = 480 ( divide both sides by 120 )
d = 4 cm
Please help me with this
verifying, by putting [tex] \theta=60^{\circ}[/tex]
LHS≠RHS
hence the question is FALSE
Find the area of the following rectilinear figure.
Answer:
Area : 14+10+40=64 square unit
Step-by-step explanation:
the area of the top rectangle with sides 2 and 7
A=2*7=14 square unit
the area of the middle rectangle with sides : (7-5)=2 and side (7-2)=5
Area=5*2=10 square unit
the bottom rectangle : sides 10 and 4
Area=10*4=40
add the areas : 14+10+40=64 square unit
Need help please! Oh and the options are
A. 2/3
B. 1/5
C. 4/15
D. 2/7
Answer:
C. 4/15There are 15 spaces in total with 4 shaded columnsStep-by-step explanation:
Answer:
Hey there!
The answer would be C. 4/15.
4/5(1/3)=4/15
Let me know if this helps :)
can someone help me with this graphical method equation 3x + 5y = -2 7x - 8y = 15
Answer:
x = 1
y = -1
Step-by-step explanation:
3x + 5y = -2
7x - 8y = 15
=> -8y = 15 - 7x
=> -y = 15/8 - 7/8x
=> y = -15/8 + 7/8x
3x + 5(-15/8 + 7/8x) = -2
=> 3x -75/8 + 35/8x = -2
=> 24/8x - 75/8 + 35/8x = -16/8
=> 59/8x - 75/8 = -16/8
=> 59/8x = 59/8
=> x = 59/8 x 8/59
=> x = 472/472
=> x = 1
x = 1
So, 3x + 5y = -2
=> 3 (1) + 5y = -2
=> 3 + 5y = -2
=> 5y = -5
=> y = -5/5
=> y = -1
So, x = 1
=> y = -1
Identify the relation that is not a function. weight of an apple to the apple's cost time of day to the temperature at that time weight of a person to a person's height phone number to a person's name
Let x = weight and y = height. It is possible to have a certain weight correspond to multiple heights. This means the input x has multiple output y values. Therefore, we cannot have a function here. A function is only possible if for any x input, there is exactly one y output. The x value must be in the domain.
A shipping company borrows $70 million at 5% p.a. compound interest to build a new cruise ship. If it repays the debt after 3 years, how much interest will the company pay?
Answer:
about 11.03 million
Step-by-step explanation:
Use the equation I = P(1+r/100)^n - P (I is the compound interest, P is the principle, r is the rate percent, and n is the number of years):
Substitute the values given:
I = 70,000,000(1 + 5/100)^3 - 70,000,000
Use a calculator to solve and you will get ~11.03 million.
The formula for the amount earned with compound interest after n years is given as:
A = P [tex](1 + r/n)^{nt}[/tex]
P = principal
R = rate
t = time in years
n = number of times compounded in a year.
The interest the company paid is $11 million.
What is compound interest?It is the interest we earned on the interest.
The formula for the amount earned with compound interest after n years is given as:
A = P [tex](1 + r/n)^{nt}[/tex]
P = principal
R = rate
t = time in years
n = number of times compounded in a year.
We have,
P = $70 million
r = 5%
t = 3 years
n = 1
A = 70 ( 1 + 0.05)³
A = 70 ( 1.05)³
A = 70 x 1.05 x 1.05 x 1.05
A = $81 million
The amount of interest.
= A - P
= 81 - 70
= $11 million
Thus,.
The interest the company paid is $11 million.
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A blue print for a house has a scale of 1:10. A wall in the blueprint is 8in. What is the length of the actual wall?
6.67. inches
80 feet
969 feet
6.67 feet
Answer:
80 feet
Step-by-step explanation:
1 inch represents 10 feet
Then 8 inches represent = 8 × 10
= 80 feet
Having trouble.. help?
Answer:
(A) [tex]y = x+3[/tex]
Step-by-step explanation:
Using the values of (-6, -3), (3,6), and (5,8) we can substitute the values into each equation and see if the equation meets the requirements for all 3.
Let's test A first.
[tex]-3 = -6+3[/tex]
Correct, let's try the second pair.
[tex]6 = 3+3[/tex]
Correct, let's try the third pair.
[tex]8 = 5+3[/tex]
So yes, this equation works.
For fun, let's try the other equations.
Let's test B.
[tex]-3 = -6-3[/tex]
This is not true as -6 -3 = -9. So this equation is immediately ruled out.
Let's test C.
[tex]-3 = 2\cdot-6[/tex]
Again this doesn't work, as -6 times 2 is -12. So this equation is also ruled out.
Let's try D.
[tex]-3 = \frac{1}{2}\cdot-6[/tex]
This works, as half of -6 is -3 - however the equation will only work if all 3 pairs work for it.
Let's try the second pair.
[tex]6 = \frac{1}{2}\cdot3[/tex]
This doesn't work, as half of 3 is 1.5. This equation is also ruled out.
Therefore, A is the only equation that works with these pairs.
Hope this helped!
The diagram shows 2 straight line , PQ and QR
Find the equation of QR
Help me to explain :)
Answer:
Step-by-step explanation:
We first need to find h. Since h is the x coordinate of Q, and Q is on the line 3x + 4y = 6, we will plug in the x value of h and the y value of 3 and solve for h:
3h + 4(3) = 6 and
3h + 12 = 6 and
3h = -6 so
h = -2
The coordinates for Q are (-2, 3). Now we can use that to find the slope of the line QR:
[tex]m=\frac{8-3}{3-(-2)}=\frac{5}{5}=1[/tex]
So the slope of QR is 1. Now we will choose one of the coordinates on line QR as our x and y coordinates to write the equation for the line in point slope form then in standard form:
y - 8 = 1(x - 3) and
y - 8 = x - 3 and
y - x = 5 or
-x + y = 5. If your teacher does not want you to lead with a negative:
x - y = -5 would be your equation in standard form.
Given the sequence 4, 8, 16, 32, 64, ..., find the explicit formula. A. an=10(2n−1) B. an=5(2n−1) C. an=4(2n−1) D. an=20(2n−1)
Answer:
. an=4(2n−1)
Step-by-step explanation:
is 7.2 a repeating or terminating decimal
Answer: terminating
Step-by-step explanation:
Answer:
7.2 is a terminating decimal.
Step-by-step explanation:
Terminating decimals are decimals that have an end point. The decimal does not continue to go on and on with numbers but, it stops at one number which makes it terminating.
Repeating decimals are decimals that go on and on with the same number or same patterns of numbers.
So, since 7.2 has an endpoint, then it is a terminating decimal.
8 m minus 6 less or equal than 10
Hi there! :)
Answer:
[tex]\huge\boxed{m\leq 2}[/tex]
Equation:
8m - 6 ≤ 10
Add 6 to both sides:
8m ≤ 16
Divide both sides by 8:
8m/8 ≤ 16/8
m ≤ 2
Answer:
8m - 6≤ 10
m≤2
Step-by-step explanation:
8m - 6≤ 10
Add 6 to each side
8m - 6+6≤ 10+6
8m ≤ 16
Divide each side by 8
8m/8 ≤16/8
m≤2
1 - Os coeficientes numéricos de uma equação do 2º grau (ax² + bx + c = 0), são números reais representados pelas letras “a, b e c”. Para que uma equação do 2º grau possa existir, é necessário que o coeficiente “a” seja DIFERENTE de: * 1 ponto a) -2 b) -1 c) 0 d) 1 2) Usando o método de Tentativa e Erro, visto na aula, qual das alternativas abaixo representa uma raiz da equação: x²-5x+6=0 * 1 ponto a) x = 0 b) x = 1 c) x = 2 c) x = -2
Answer:
1) La opción correcta es;
c) 0
2) La opción correcta es;
c) x = 2
Step-by-step explanation:
1) La forma general de una ecuación cuadrática se puede escribir en la forma;
a · x² + b · x + c = 0
Dónde;
a, y b son los coeficientes de x², x y c es el término constante
Por tanto, para que exista un polinomio de 2º grado es necesario que el coeficiente a sea diferente de 0
De lo que tenemos;
(0) × x² + b · x + c = 0, lo que da;
(0) × x² + b · x + c = b · x + c = 0 que es una ecuación lineal o un polinomio de primer grado
Por tanto, la opción correcta es c) 0
2)
La ecuación dada se presenta como sigue;
f (x) = x² - 5 · x + 6 = 0
Usando el método de prueba y error, tenemos;
Cuando x = 0
f (0) = 0² - 5 · (0) + 6 = 6 que no es igual a 0 y, por lo tanto, no es una solución
Cuando x = 1
f (1) = (1) ² - 5 · (1) + 6 = 1 que no es igual a 0 y por lo tanto, no es una solución
Cuando x = 2
f (2) = (2) ² - 5 · (2) + 6 = 0 que es igual a 0 y por lo tanto, es una solución
Cuando x = -2
f (1) = (-2) ² - 5 × (-2) + 6 = 20 que no es igual a 0 y por lo tanto, no es una solución
Por tanto, la opción correcta es c) x = 2
The product of (4z2 + 7z – 8) and (–z + 3) is –4z3 + z2 + z – 24.
The product of (4z² + 7z – 8) and (–z + 3) is -4z³ + 5z² + 29z - 24
How to find product of expressions(4z² + 7z – 8) and (–z + 3)
= -4z³+ 12z² - 7z² + 21z + 8z - 24
collect like terms= -4z³ + 5z² + 29z - 24
Therefore, the product of (4z² + 7z – 8) and (–z + 3) is -4z³ + 5z² + 29z - 24
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