Integrate the following:
[tex]\displaystyle \int \frac{x^2}{x^2+x+3}\, dx[/tex]

Answers

Answer 1

Answer:

[tex]\int {\frac{x^2}{x^2+x+3} } \, dx = - \frac{5\sqrt{11} }{11}arctan(\frac{\sqrt{11}(2x+1) }{11} ) - \frac{1}{2}ln|x^2+x+3| +x + C[/tex]

General Formulas and Concepts:

Pre-Algebra

Distributive Property

Algebra I

Completing the SquareRearranging Variables

Algebra II

Long Division

Calculus

U-Substitution[Integration Trick 1] Numerator Split[Integration Trick 2] Completing the SquareIntegration Rule 1: [tex]\int {cf(x)} \, dx = c\int {f(x)} \, dx[/tex]Integration Rule 2: [tex]\int {f(x)+g(x)} \, dx =\int {f(x)} \, dx + \int {g(x)} \, dx[/tex]Integration 1: [tex]\int {\frac{1}{u} } \, du =ln|u| + C[/tex]Integration 2: [tex]\int {\frac{du}{u^2+a^2} } = \frac{1}{a} arctan(\frac{u}{a} )+C[/tex]Integration 3: [tex]\int {x^n} \, dx = \frac{x^{n+1}}{n+1} +C[/tex]

Step-by-step explanation:

Step 1: Define

[tex]\int {\frac{x^2}{x^2+x+3} } \, dx[/tex]

Step 2: Simplify Function

We do long division to simplify the function inside the function.

See Attachment for Long Division Work.

Once we do long division, our function becomes [tex]1-\frac{x+3}{x^2+x+3}[/tex]

Now we rewrite our Integral: [tex]\int ({1-\frac{x+3}{x^2+x+3} }) \, dx[/tex]

Step 3: Integrate Pt. 1

Distributive Integral [Int Rule 1]:                    [tex]\int {1} \, dx - \int {\frac{x+3}{x^2+x+3} } \, dx[/tex]Integrate 1st Integral [Int 3]:                          [tex]x - \int {\frac{x+3}{x^2+x+3} } \, dx[/tex]

Step 4: Identify Variables Pt.1

Set variables for u-substitution.

u = x² + x + 3

du = (2x + 1)dx

Step 5: Integrate Pt. 2

Rewrite Integral [Int Rule 1]:                                                                [tex]x - \frac{1}{2} \int {\frac{2(x+3)}{x^2+x+3} } \, dx[/tex]Distribute 2 [Alg]:                                                                             [tex]x - \frac{1}{2} \int {\frac{2x+6}{x^2+x+3} } \, dx[/tex]Rewrite Integral [Alg]:                                                                      [tex]x - \frac{1}{2} \int {\frac{2x+1+5}{x^2+x+3} } \, dx[/tex]Rewrite Integral [Int Trick 1]:                                       [tex]x - \frac{1}{2} [\int {\frac{2x+1}{x^2+x+3} } \, dx + \int {\frac{5}{x^2+x+3} } \, dx ][/tex](2nd Int) Complete the Square:                              [tex]x - \frac{1}{2} [\int {\frac{2x+1}{x^2+x+3} } \, dx + \int {\frac{5}{(x+\frac{1}{2})^2 + \frac{11}{4} } } \, dx ][/tex]

Step 6: Identify Variables Pt. 2

Set variables for u-substitution for 2nd integral.

z = x + 1/2

dz = dx

a = √(11/4)

Step 7: Integrate Pt. 3

[Integrate] U-Substitution:                                 [tex]x - \frac{1}{2} [\int {\frac{1}{u} } \, du + \int {\frac{5}{z^2 + (\sqrt{\frac{11}{4}})^2} } \, dz ][/tex]Rewrite Integral [Int Rule 1]:                                     [tex]x - \frac{1}{2} [\int {\frac{1}{u} } \, du + 5\int {\frac{dz}{z^2 + (\sqrt{\frac{11}{4}})^2} } ][/tex]Integrate 1st Integral [Int 1]:                                       [tex]x - \frac{1}{2} [ln|u| + 5\int {\frac{dz}{z^2 + (\sqrt{\frac{11}{4}})^2} } ][/tex]Integrate 2nd Integral [Int 2]:                            [tex]x - \frac{1}{2} [ln|u| + 5(\frac{1}{\sqrt{\frac{11}{4}}}arctan(\frac{z}{\sqrt{\frac{11}{4} } } ) ) ][/tex]Distribute 5 [Alg]:                                                 [tex]x - \frac{1}{2} [ln|u| + \frac{5}{\sqrt{\frac{11}{4}}}arctan(\frac{z}{\sqrt{\frac{11}{4} } } ) ][/tex]Distribute -1/2 [Alg]:                                           [tex]x - \frac{1}{2}ln|u| - \frac{5}{2\sqrt{\frac{11}{4}}}arctan(\frac{z}{\sqrt{\frac{11}{4} } } )[/tex]Rationalize [Alg]:                                                   [tex]x - \frac{1}{2}ln|u| - \frac{5\sqrt{11} }{11}arctan(\frac{z}{\sqrt{\frac{11}{4} } } )[/tex]Resubstitute variables [Alg]:                              [tex]x - \frac{1}{2}ln|x^2+x+3| - \frac{5\sqrt{11} }{11}arctan(\frac{x+\frac{1}{2} }{\sqrt{\frac{11}{4} } } )[/tex]Simplify/Rationalize [Alg]:                     [tex]x - \frac{1}{2}ln|x^2+x+3| - \frac{5\sqrt{11} }{11}arctan(\frac{\sqrt{11}(2x+1) }{11} )[/tex]Rewrite [Alg]:                                [tex]- \frac{5\sqrt{11} }{11}arctan(\frac{\sqrt{11}(2x+1) }{11} ) - \frac{1}{2}ln|x^2+x+3| +x[/tex]Integration Constant:                            [tex]- \frac{5\sqrt{11} }{11}arctan(\frac{\sqrt{11}(2x+1) }{11} ) - \frac{1}{2}ln|x^2+x+3| +x + C[/tex]

And we have our final answer! Hope this helped you on your Calculus Journey!

Integrate The Following: [tex]\displaystyle \int \frac{x^2}{x^2+x+3}\, Dx[/tex]
Answer 2

hope this will help you........

Integrate The Following: [tex]\displaystyle \int \frac{x^2}{x^2+x+3}\, Dx[/tex]

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Which pair of angles are complementary but not adjacent?

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Step-by-step explanation:

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statement is true?
O Line p must be drawn in plane B.
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Answer: the second one

Step-by-step explanation:

I’m smart I have al a’s

The true statement is - Line p must be drawn so that it can lie in the same plane as line l.

What is plane?

"It is a two-dimensional flat surface with no edges or thickness."

What are parallel lines?

"Two lines in the same plane that are at equal distance from each other and never meet."

For given question,

Planes A and B are shown.

If a new line, p, is drawn parallel to line l,  must be drawn so that it can lie in the same plane as line l.

Line l lie in plane A.

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Step-by-step explanation:

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Step-by-step explanation:

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The length and width of one rectangle are 8 and 5.

The width of the other rectangle is 5, but its length is unknown so we label it `x`.

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Answer:

fksfk

Step-by-step explanation:

Answer: x is 8

Step-by-step explanation:

4 T =
fl OZ
(T = Tablespoons)

Answers

Answer:

2 fl oz

Step-by-step explanation:

Answer:

4 tablespoons is = to 2 fl oz

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Step-by-step explanation:

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97

Explanation:

Buddy- 6

Hermey-3

____________________________________________________________

It takes Buddy 94 years to be 100 so you would add 94 to both boys ages!

6+94=100 years old!

3+94= 97 years old!

Answer:

He is going to be 50 years old

Step-by-step explanation:

if he was 3 when his brother was 6 then it would mean that when his brother is 100 he should be 50  because that would be half. You can divide it if you want some extra proof :)

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Answers

Answer:

4.35/5= 0.87 liters

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Step-by-step explanation:

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Answer:

-1/4

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Answers

Given :

Claudia spends $2.15 day for lunch.

Her cafeteria lunch account has a balance of 48.00 .

To Find :

The maximum number of days, d that she can eat without adding money to her lunch account.

Solution :

Number of days she can eat without adding money in her account is :

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B
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Answers

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Step-by-step explanation:

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Answers

Answer:

7

Step-by-step explanation:

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Answers

Answer:

1. x < -2

2. x < -9

Step-by-step explanation:

1. x + 15 < 13

Minus 15 on both sides.

x + 15 - 15 < 13 - 15

+15 - 15 makes a 0.

x < -2

2. x + 11 < 2

Minus 11 on both sides.

x + 11 - 11 < 2 - 11

+11 - 11 makes a 0.

x < -9

Answer:

1. x < -2

2. x < -9

3. x < 15

Step-by-step explanation:

Treat the < and > symbols as an equals sign to make it less confusing to solve. Then solve for x like you normally would.

1. x+ 15 = 13

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Step-by-step explanation:

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Answers

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3. 180 - (53+68) = 59

The answer is B. 59°

4.
Part A: The measure of a is 70°.

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Answers

Answer:

27/8

Step-by-step explanation:

first you would convert -.5 to -1/2 and add everything up by getting the same denominator

Answer:

3.375

Step-by-step explanation:First convert the 2 1/4 and the 1 5/8

then you just add it with the 0.5 or just use a calculator  

2 1/4 = 9/4

1 5/8= 13/8

okay now do this ---> 0.5 + 9/4 +13/8 =3.375

Five friends went to Madrid. The return flight was $25 more than the outgoing flight. Airport taxes were $21 for each flight for each person. The overall cost was $595. What was the price of the return flight for each person?

Answers

Answer:

$98

Step-by-step explanation:

21 × 5 ( since there are 5 friends )

= 105

595 - 105 = 490 (total cost for all 5 of the return flight)

490 ÷ 5 = 98

$ 98 for each person.

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Answer: The last choice, 2x + 3y = 10

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Answers

m2 is 49 and m1 is 131

Answer:

m1 =131 degrees

m2=49 degrees

Step-by-step explanation:

Alternate interior angles are always congruent, so they will be equal to each other, so m1=131 degrees.

Straight angles always add up to 180 degrees, so 180-131=49, so m2=49 degrees

Abby bought one package of cookies that weighed 24 ounces and another package that weighed 2 pounds 2 ounces. What was the combined weight of the two packages of cookies she bought?

Answers

Answer: If you place 10 packages per box, each box will weigh 10(3 lb 4 oz). This is 30 lb 40 oz. For 4 boxes you would have 4(30 lb 40 oz). This is 120 lb 160 oz. To put you answer in the correct form you need to change the 160 oz to pounds and ounces. 16 oz is equal to 1 pound, so divide 160 by 16. The 160 oz is equivalent to 10 lbs. Therefore the total weight of 4 boxes is 120 + 10 which equals 130 lbs.

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Evaluate the expression 10m - 11
if m=4

Answers

Answer:

is the answer 45444.2453 jd

Step-by-step explanation:

Answer:

10m -11 ( plug in the given value for m)

10 (4) -11  (do multiplication first because of PEMDAS)

40 -11  (subtract)

29 (the answer)

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Answers

Answer:  B) 6 minutes

============================================================

Explanation:

Let's find the slope of the table. This will tell us the rate of change.

m = slope

m = (y2-y1)/(x2-x1)

m = (25250 - 26375)/(2 - 1) .... I used the first two rows

m = -1125/1

m = -1125

The slope of -1125 means the plane's altitude is decreasing at a rate of 1125 feet per minute. This is the descent speed.

Since we're told the initial altitude was 27500 ft, this means b = 27500

This means y = mx+b turns into y = -1125x+27500

x is the number of minutes and y is the altitude at time x

As a way to check this, plug in various x values of the table. You should get corresponding y values that match the table. I'll let you do this part.

------------------

Now plug in y = 16250 and solve for x

y = -1125x+27500

16250 = -1125x+27500

-1125x+27500 = 16250

-1125x = 16250-27500

-1125x = -11250

x = -11250/(-1125)

x = 10

It takes 10 minutes after the descent period has started, for the pilot to get to 16,250 ft.

Since the pilot was contacted at the x = 4 minute mark, this means 10-4 = 6 minutes is the duration needed for the pilot to go from 23,000 ft to 16,250 ft.

A private college allows local residents to use athletic facilities such as the gym and the pool for a fee. The college charges a one time registration fee of $25 and also charges a fee of $18 per semester of use. complete the table to show the total cost of using the athletic facilities after each semester listed.

Answers

Step-by-step explanation:

1) 43

2) 61

3) 79

4)97

5)115

Answer:

popoverlover20 is correct I got it right

Step-by-step explanation:

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