The value of the money including inflation after 6 years will be $6510.64.
What is inflation?The rate at which prices grow over a specific time period is known as inflation. Inflation is often measured in broad terms, such as the general rise in prices or the rise in a nation's cost of living. But it may also be computed more precisely for some products, like food, or for services, like a haircut, for instance. In any situation, inflation refers to how much more costly the pertinent collection of products and/or services has grown over a predetermined time frame, most frequently a year.
Given that, Inflation is running at 1.1% per year when you deposit $5,000 in an account earning 4.4% compounded continuously.
deposit amount (P) = $ 5000
Rate (r) = 4.4 %
Time (t) = 6 years
Compound continuously
Amount (A)= 5000 e⁰°⁰⁴⁴ˣ ⁶
A = $ 6,510.64098
A = $ 6510.64
Total accumulated money after 6 years = $ 6,510.64
value of money decreases due to inflation
The real value of money after n years with the rate of inflation i = 1.1%
yₙ = A( 1 / (1+i) )ⁿ
y₆ = 6510.64 (1 / ( 1 + 0.011))⁶
y₆ = 6,097.008
Real value of money = $ 6,097.01
Therefore, after 6 years real value of the money including inflation will be $ 6,097.01.
Learn more about inflation here:
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This question difficult and i need some help would anyone please help me
Answer:
x = 30
F = 130
G = 50
Step-by-step explanation:
f and g are supplementary which means they add to 180
5x-20 + 3x - 40 = 180
Combine like terms
8x - 60 = 180
Add 60 to each side
8x-60+60 = 180+60
8x = 240
Divide by 8
8x/8 = 240/8
x = 30
F = 5x -20 = 5*30 -20 = 150 -20 = 130
G = 3x-40 = 3*30 -40 = 90-40 = 50
Answer:
Because a straight line = 180, we can find x like this :
(5x - 20) + (3x - 40) = 180
Step 1 - collect like terms
8x - 60 = 180
Step 2 - Move terms around to isolate x
8x = 180 + 60
Step 3 - Divide both sides by 8
x = 30
Now you can find the value of the angles by plugging in x
∠f = (5 x 30) - 20
= 130 degrees
∠g = (3 x 30) - 40
= 50 degrees
We can check to see if this works by adding them up
130 + 50 = 180, so this is correct
Hope this helps! I would really appreciate a brainliest if possible :)
Crystal left her running shoes at school yesterday. Today she walked 44 miles to school to get her shoes, she ran home along the same route, and the total time for both trips was 22 hours. Crystal walked and ran at constant speeds, and she ran 33 miles per hour faster than she walked.
What was Crystal’s walking speed in miles per hour?
Answer:
We can conclude that her walking speed is 2.1 miles per hour.
Step-by-step explanation:
We have the relation:
Speed = distance/time.
Here we know:
She walked for 44 miles.
And she ran along the same route, so she ran for 44 miles.
The total time of travel is 22 hours, so if she ran for a time T, and she walked for a time T', we must have:
T + T' = 22 hours.
If we define: S = speed runing
S' = speed walking
Then we know that:
"and she ran 33 miles per hour faster than she walked."
Then:
S = S' + 33mi/h
Then we have four equations:
S'*T' = 44 mi
S*T = 44 mi
S = S' + 33mi/h
T + T' = 22 h
We want to find the value of S', the speed walking.
To solve this we should start by isolating one of the variables in one of the equations.
We can see that S is already isoalted in the third equation, so we can replace that in the other equations where we have the variable S, so now we will get:
S'*T' = 44mi
(S' + 33mi/H)*T = 44mi
T + T' = 22h
Now let's isolate another variable in one of the equations, for example we can isolate T in the third equation to get:
T = 22h - T'
if we replace that in the other equations we get:
S'*T' = 44mi
(S' + 33mi/h)*( 22h - T') = 44 mi
Now we can isolate T' in the first equation to get:
T' = 44mi/S'
And replace that in the other equation so we get:
(S' + 33mi/h)*( 22h -44mi/S' ) = 44 mi
Now we can solve this for S'
22h*S' + (33mi/h)*22h + S'*(-44mi/S') + 33mi/h*(-44mi/S') = 44mi
22h*S' + 726mi - 44mi - (1,452 mi^2/h)/S' = 44mi
If we multiply both sides by S' we get:
22h*S'^2 + (726mi - 44mi)*S' - (1,425 mi^2/h) = 44mi*S'
We can simplify this to get:
22h*S'^2 + (726mi - 44mi - 44mi)*S' - (1,425 mi^2/h) = 0
22h*S'^2 + (628mi)*S' - ( 1,425 mi^2/h) = 0
This is just a quadratic equation, the solutions for S' are given by the Bhaskara's equation:
[tex]S' = \frac{-628mi \pm \sqrt{(628mi)^2 - 4*(22h)*(1,425 mi^2/h)} }{2*22h} \\S' = \frac{-628mi \pm 721 mi }{44h}[/tex]
Then the two solutions are:
S' = (-628mi - 721mi)/44h = -30.66 mi/h
But this is a negative speed, so this has no real meaning, and we can discard this solution.
The other solution is:
S' = (-628mi + 721mi)/44h = 2.1 mi/h
We can conclude that her walking speed is 2.1 miles per hour.
20. Find the measure of < DEG. (G.CO.C.10)
4
E
A. 25
B. 8
(3y + 4) A (5y-10)
C. 30
水
D
F
Click to add speaker notes
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O
c
3
PO
.
a
Answer:
A. 25
Step-by-step explanation:
From the diagram given, we can deduce that <D EG = <F EG
Therefore:
3y + 4 = 5y - 10
Collect like terms and solve for y
3y - 5y = -4 - 10
-2y = -14
Divide both sides by -2
y = -14/-2
y = 7
✔️m<D EG = 3y + 4
Plug in the value of y
m<D EG = 3(7) + 4
m<D EG = 25°
Does anyone know the answer to this? Algebra 2
I have to find the answers to
Find cos 0
Find tan 0
Find csc 0
Find sec 0
Find cot 0
And what terminal of the angle falls in which quadrant? 1-4?
Answer:
Step-by-step explanation:
Sinθ = [tex]\frac{\text{Opposite side}}{\text{Hypotenuse}}[/tex]
If, sinθ = -[tex]\frac{1}{2}[/tex] and π < θ < [tex]\frac{3\pi }{2}[/tex]
Since, sinθ is negative, angle θ will be in IIIrd quadrant.
And the measure of angle θ will be (180° + 30°)
θ = 210°
It's necessary to remember that tangent and cotangent of angle θ in quadrant III are positive.
Therefore, cos(210°) = [tex]-\frac{\sqrt{3} }{2}[/tex]
tan(210°) = [tex]\frac{1}{\sqrt{3} }[/tex]
csc(210°) = [tex]-\frac{1}{2}[/tex]
sec(210°) = [tex]-\frac{2}{\sqrt{3} }[/tex]
cot(210°) = √3
A rectangular storage container with an open top is to have a volume of 14 cubic meters. The length of its base is twice the width. Material for the base costs 10 dollars per square meter. Material for the sides costs 8 dollars per square meter. Find the cost of materials for the cheapest such container.
Answer:
C(min) = 277.95 $
Container dimensions:
x = 2.822 m
y = 1.411 m
h = 3.52 m
Step-by-step explanation:
Let´s call x and y the sides of the rectangular base.
The surface area for a rectangular container is:
S = Area of the base (A₁) + 2 * area of a lateral side x (A₂) + 2 * area lateral y (A₃)
Area of the base is :
A₁ = x*y we assume, according to problem statement that
x = 2*y y = x/2
A₁ = x²/2
Area lateral on side x
A₂ = x*h ( h is the height of the box )
Area lateral on side y
A₃ = y*h ( h is the height of the box )
s = x²/2 + 2*x*h + 2*y*h
Cost = Cost of the base + cost of area lateral on x + cost of area lateral on y
C = 10*x²/2 + 8* 2*x*h + 8*2*y*h
C as function of x is:
The volume of the box is:
V(b) = 14 m³ = (x²/2)*h 28 = x²h h = 28/x²
C(x) = 10*x²/2 + 16*x*28/x² + 16*(x/2)*28/x²
C(x) = 5*x² + 448/x + 224/x
Taking derivatives on both sides of the equation we get:
C´(x) = 10*x - 448/x² - 224/x²
C´(x) = 0 10x - 448/x² - 224/x² = 0 ( 10*x³ - 448 - 224 )/x² = 0
10*x³ - 448 - 224 = 0 10*x³ = 224
x³ =22.4
x = ∛ 22.4
x = 2.822 m
y = x/2 = 1.411 m
h = 28/x² = 28 /7.96
h = 3.52 m
To find out if the container of such dimension is the cheapest container we look to the second derivative of C
C´´(x) = 10 + 224*2*x/x⁴
C´´(x) = 10 + 448/x³ is positive then C has a minimum for x = 2.82
And the cost of the container is:
C = 10*(x²/2) + 16*x*h + 16*y*h
C = 39.82 + 158.75 + 79.38
C = 277.95 $
How would this quadrilateral be best classified, and what is the measure of Angle B?
Answer:
The quadrilateral is Rhombus
B=70°
Step-by-step explanation:
110+110+z+z=360
220+2z=360
2z=360-220
2z=140
z=140/2
Therefore, z=70
So Angle B=70
Since z= Angle B=Angle D
A.85
B.98
C.102
D.34
Answer:
C. 102Step-by-step explanation:
[tex]{hope it helps}}[/tex]
A matinee ticket costs $6 per adult and $1 per child. On a certain day, the total number of adults (a) and children (c) who saw a movie was 35, and the total money collected was $70. Which of the following options represents the number of children and the number of adults who saw a movie that day, and the pair of equations that can be solved to find the numbers?
7 children and 28 adults
Equation 1: a + c = 35
Equation 2: 6a − c = 70
7 children and 28 adults
Equation 1: a + c = 35
Equation 2: 6a + c = 70
28 children and 7 adults
Equation 1: a + c = 35
Equation 2: 6a + c = 70
28 children and 7 adults
Equation 1: a + c = 35
Equation 2: 6a − c = 70
Answer:
28 children and 7 adults
Equation 1: a + c = 35
Equation 2: 6a + c = 70
Step-by-step explanation:
If the total number of people at the movie was 35 people, one of the equations will be a + c = 35.
If $70 was collected in total, the other equation will be 6a + c = 70.
Now, solve this system of equations:
a + c = 35
6a + c = 70
Solve by elimination by multiplying the top equation by -1, then adding the equations together:
-a - c = -35
6a + c = 70
Add these together, and solve for a:
5a = 35
a = 7
Since there were 35 people in total, find how many children attended by subtracting 7 from 35:
35 - 7
= 28
So, there were 28 children and 7 adults.
The equations used were: a + c = 35 and 6a + c = 70
So, the correct answer is:
28 children and 7 adults
Equation 1: a + c = 35
Equation 2: 6a + c = 70
Workers employed in a large service industry have an average wage of $9.00 per hour with a standard deviation of $0.50. The industry has 64 workers of a certain ethnic group. These workers have an average wage of $8.85 per hour. Calculate the probability of obtaining a sample mean less than or equal to $8.85 per hour. (Round your answer to four decimal places.)
Answer:
The probability of obtaining a sample mean less than or equal to $8.85 per hour=0.0082
Step-by-step explanation:
We are given that
Average wage, [tex]\mu=[/tex]$9.00/hour
Standard deviation,[tex]\sigma=[/tex]$0.50
n=64
We have to find the probability of obtaining a sample mean less than or equal to $8.85 per hour.
[tex]P(\bar{x} \leq 8.85)=P(Z\leq \frac{\bar{x}-\mu}{\frac{\sigma}{\sqrt{n}}})[/tex]
Using the values
[tex]P(\bar{x}\leq 8.85)=P(Z\leq \frac{8.85-9}{\frac{0.50}{\sqrt{64}}})[/tex]
[tex]P(\bar{x}\leq 8.85)=P(Z\leq \frac{-0.15}{\frac{0.50}{8}})[/tex]
[tex]P(\bar{x}\leq 8.85)=P(Z\leq -2.4)[/tex]
[tex]P(\bar{x}\leq 8.85)=0.0082[/tex]
Hence, the probability of obtaining a sample mean less than or equal to $8.85 per hour=0.0082
Solve for 5x + 11 ≤ 67 = ?
9I will give brainliest.)
Answer:
x ≤ 11.20
Step-by-step explanation:
solve it like a regular equation
5x ≤ 67 - 11
5x ≤ 56
x ≤ 11 1/5
x ≤ 11.20
An employer has a staff of eighty actuaries, ten of whom are student actuaries. A student actuary is allowed a total of ten weeks off per year (52 weeks in a year) for studying, vacation, and sick days. A non-student actuary is given four weeks off a year. It is assumed that all actuaries use all of the weeks off allocated to them. The actuary Mr. Taylor is at work today. What is the probability that he is a student?
Answer:
0.1111
Step-by-step explanation:
From the given information;
Number of staffs in the actuary = 80
Out of the 80, 10 are students.
i.e.
P(student actuary) = 10/80 = 0.125
number of weeks in a year = 52
off time per year = 10/52 = 0.1923
P(at work || student actuary) = (50 -10/52)
= 42/52
= 0.8077
P(non student actuary) = (80 -10)/80
= 70 / 80
= 0.875
For a non-student, they are only eligible to 4 weeks off in a year
i.e.
P(at work | non student) = (52-4)/52
= 48/52
= 0.9231
∴
P(at work) = P(student actuary) × P(at work || student actuary) + P(non student actuary) × P(at work || non studnet actuary)
P(at work) = (0.125 × 0.8077) + ( 0.875 × 0.9231)
P(at work) = 0.1009625 + 0.8077125
P(at work) = 0.90868
Finally, the P(he is a student) = (P(student actuary) × P(at work || student actuary) ) ÷ P(at work)
P(he is a student) = (0.125 × 0.8077) ÷ 0.90868
P(he is a student) = 0.1009625 ÷ 0.90868
P(he is a student) = 0.1111
Find the length of the third side. If necessary, round to the nearest tenth
[tex]\huge\bold{Given:}[/tex]
Length of the base = 8
Length of the hypotenuse = 17
[tex]\huge\bold{To\:find:}[/tex]
The length of the third side ''[tex]x[/tex]".
[tex]\large\mathfrak{{\pmb{\underline{\orange{Solution}}{\orange{:}}}}}[/tex]
[tex]\longrightarrow{\purple{x\:=\: 15}}[/tex]
[tex]\large\mathfrak{{\pmb{\underline{\red{Step-by-step\:explanation}}{\red{:}}}}}[/tex]
Using Pythagoras theorem, we have
(Perpendicular)² + (Base)² = (Hypotenuse)²
[tex]\longrightarrow{\blue{}}[/tex] [tex]{x}^{2}[/tex] + (8)² = (17)²
[tex]\longrightarrow{\blue{}}[/tex] [tex]{x}^{2}[/tex] + 64 = 289
[tex]\longrightarrow{\blue{}}[/tex] [tex]{x}^{2}[/tex] = 289 - 64
[tex]\longrightarrow{\blue{}}[/tex] [tex]{x}^{2}[/tex] = 225
[tex]\longrightarrow{\blue{}}[/tex] [tex]x[/tex] = [tex]\sqrt{225}[/tex]
[tex]\longrightarrow{\blue{}}[/tex] [tex]x[/tex] = [tex]15[/tex]
Therefore, the length of the missing side [tex]x[/tex] is [tex]15[/tex].
[tex]\huge\bold{To\:verify :}[/tex]
[tex]\longrightarrow{\green{}}[/tex] (15)² + (8)² = (17)²
[tex]\longrightarrow{\green{}}[/tex] 225 + 64 = 289
[tex]\longrightarrow{\green{}}[/tex] 289 = 289
[tex]\longrightarrow{\green{}}[/tex] L.H.S. = R. H. S.
Hence verified.
[tex]\huge{\textbf{\textsf{{\orange{My}}{\blue{st}}{\pink{iq}}{\purple{ue}}{\red{35}}{\green{♨}}}}}[/tex]
Pls help I don’t understand this one pls
Answer:
15=225
20= 400
Step-by-step explanation:
the small 2 means multiply that number two times :)
Answer:
[tex]15^2\\[/tex] = 225
[tex]20^{2}[/tex] = 400
Step-by-step explanation:
[tex]x^{2}[/tex] = [tex]x[/tex] × [tex]x[/tex]
basically it's the number times itself
15 × 15 = 225
20 × 20 = 400
A money box contains only 10-cent
and 20-cent coins. There are 33
coins with a total value of $4.60.
How many coins of each?
Answer:
Below in bold.
Step-by-step explanation:
x + y = 33 where x = 10 cent coin and y = 20 cent coin
10x + 20y = 460
Multiply first equation by 10:
10x + 10y = 330
Subtract this from the second equation:
10y = 130
y = 13
So there are 13 20c coins
and 33 - 13 = 20 10c coins.
Assume for a paired-samples t test: N= 17, Mdifference = 467.72, s = 264.50. What is the effect size statistic?
Answer:
bbbbbhbbvcgccfggfgggggggggihh
Use technology to help you test the claim about the population mean, mu, at the given level of significance, alpha, using the given sample statistics. Assume the population is normally distributed.
Claim: μ>1220;α=0.08; σ=211.67.
Sample statistics: x=1235.91,n=300
Identify the null and alternative hypotheses and calculate the standardized test statistic.
Answer:
H0 : μ = 1220
H1 : μ > 1220
Test statistic = 1.30
Step-by-step explanation:
Sample mean, x = 1235.91
Standard deviation, σ = 211.67
Sample size, n = 300
The hypothesis :
Null ; H0 : μ = 1220
Alternative ; H1 : μ > 1220
Tbe test statistic :
(x - μ) ÷ (σ/√(n))
(1235.91 - 1220) ÷ (211.67/√(300))
15.91 / 12.220773
= 1.3018
= 1.30
I’ll give brainlist to best answer
Answer:
12.25
Step-by-step explanation:
Expression
x^2 + 2y
x = 2.5
y = 3
x^2 = 6.25
2y = 3*2 = 6
x^2 + 2y = 6.25 + 6
x^2 + 2y = 12.25
Answer:
12.25
Step-by-step explanation:
We find the equation x^2 + 2y when x = 2.5 and y = 3.
We just have to replace x with 2.5 and y with 3 in the equation:
x^2 becomes 2.5^2
2y becomes 2 * 3 (When a variable is next to a number it means multiply)
So we get 2.5^2 + 2 * 3
We first do 2.5^2. 2.5^2 is the same as 2.5 * 2.5, which equals 6.25
Next we do 2 * 3 which equals 6
So it is 6.25 + 6, which is 12.25
Listed below are the commissions earned ($000) last year by a sample of 15 sales representatives at Furniture Patch Inc.
$4.3 $6.1 $7.4 $10.7 $13.1 $13.6 $14.7 $16.5 $17.1 $17.4 $18.7 $22.3 $36.7 $43.2 $79.4
Required:
a. Determine the mean, median, and the standard deviation.
b. Determine the coefficient of skewness using Pearson.
Answer:
Mean = 21.413
Median = 16.5
Standard deviation = 19.182
0.768
Step-by-step explanation:
Given the data :
Ordered data, X : 4.3 6.1 7.4 10.7 13.1 13.6 14.7 16.5 17.1 17.4 18.7 22.3 36.7 43.2 79.4
The sample size, n = 15
The mean, m= ΣX / n = 321.2 / 15 = 21.413
The median, Md:
1/2(n + 1)th term
1/2 (15 +1) th term
1/2(16) = 8th term
Median = $16.5
The standard deviation, s = √[Σ(x - m)²/ n]
The standard deviation obtained using a calculator is ; 19.182
Coefficient of skewness : = 3(m - Md) / s
= 3(21.413 - 16.5) / 19.182
= 14.739 / 19.182
= 0.768
Kyle buys a bag of cookies that contains 4 chocolate chip cookies, 9 peanut butter cookies, 9 sugar cookies and 7 oatmeal cookies. What is the probability that Kyle randomly selects a sugar cookie from the bag, eats it, then randomly selects a peanut butter cookie
The diameter of the circle below is 82cm. Work out the radius of the circle
Answer:
Radius = 41
Step-by-step explanation:
Diameter/2=radius
82/2 =41
Answer:
Radius=41
Step-by-step explanation:
Preamble
Diameter=82
Radius=?
Formula
Radius=diameter/2
Radius=82/2
reduce the fraction
82/2=82÷2/2÷2=41/1
therefore radius=41
if $1995 .00 is Shared equally among 7 men, how much would each get?
Anwer:$285
Explaination: Division method
$1995.00÷7=$285
Razon trigonometría que se requiere para calcular la altura de la torre si desde una distancia de 50 m se observa su punto mas alto con un ángulo de 48
Answer:
se supone que debes usar el SINE RATIO ya que se trata del lado opuesto y la hipotenusa.
de moirve's
(√3-i ÷ √3+i)^6 = 1
(√3 - i ) / (√3 + i ) × (√3 - i ) / (√3 - i ) = (√3 - i )² / ((√3)² - i ²)
… = ((√3)² - 2√3 i + i ²) / (3 - i ²)
… = (3 - 2√3 i - 1) / (3 - (-1))
… = (2 - 2√3 i ) / 4
… = 1/2 - √3/2 i
… = √((1/2)² + (-√3/2)²) exp(i arctan((-√3/2)/(1/2))
… = exp(i arctan(-√3))
… = exp(-i arctan(√3))
… = exp(-iπ/3)
By DeMoivre's theorem,
[(√3 - i ) / (√3 + i )]⁶ = exp(-6iπ/3) = exp(-2iπ) = 1
Suppose that IQ scores have a bell-shaped distribution with a mean of 97 and a standard deviation of 17. Using the empirical rule, what percentage of IQ scores are between 46 and 148
Answer:
99.7% of IQ scores are between 46 and 148.
Step-by-step explanation:
The Empirical Rule states that, for a normally distributed random variable:
Approximately 68% of the measures are within 1 standard deviation of the mean.
Approximately 95% of the measures are within 2 standard deviations of the mean.
Approximately 99.7% of the measures are within 3 standard deviations of the mean.
In this problem, we have that:
Mean of 97, standard deviation of 17.
What percentage of IQ scores are between 46 and 148?
97 - 3*17 = 46
97 + 3*17 = 148
Within 3 standard deviations of the mean, so:
99.7% of IQ scores are between 46 and 148.
Find the constant of variation when t varies directly as s, and t =
260 when s = 65.
Answer:
4
Step-by-step explanation:
Use the direct variation equation, y = kx.
Replace y with t, and replace x with s:
y = kx
t = ks
Plug in 260 as k and 65 as s, then solve for k (the constant of variation):
t = ks
260 = k(65)
4 = k
So, the constant of variation is 4.
i already have A but I do not have B
Answer:
-4 , -1 , -2 , 0 , +1 , +3
Step-by-step explanation:
Answer:
the integers -4,-2,-1,0, +1, +3
Step-by-step explanation:
because when you put them in order you find which pairs are located between -5 and +5
-8,-4,-2,-1,0,+3,+8,+9
which tells you that
-4,-2,-1,0, +1, +3 are between -5 and +5
HCF of the numbers divisible be
3 between 21 and 30 is ___
Answer:
3
Step-by-step explanation:
Numbers between 21 and 30 divisible by 3 are 24 and 27. so you get the HCF of the two.
Which graph shows the solution to this system of inequalities?
y>-1/3x+1
y>2x-3
Given:
The system of inequalities is:
[tex]y>-\dfrac{1}{3}x+1[/tex]
[tex]y>2x-3[/tex]
To find:
The graph of the given system of inequalities.
Solution:
We have,
[tex]y>-\dfrac{1}{3}x+1[/tex]
[tex]y>2x-3[/tex]
The related equations are:
[tex]y=-\dfrac{1}{3}x+1[/tex]
[tex]y=2x-3[/tex]
Table of values for the given equations is:
[tex]x[/tex] [tex]y=-\dfrac{1}{3}x+1[/tex] [tex]y=2x-3[/tex]
0 1 -3
3 0 3
Plot (0,1) and (3,0) and connect them by a straight line to get the graph of [tex]y=-\dfrac{1}{3}x+1[/tex].
Similarly, plot (0,-3) and (3,3) and connect them by a straight line to get the graph of [tex]y=2x-3[/tex].
The signs of both inequalities are ">". So, the boundary line is a dotted line and the shaded region or each inequality lie above the boundary line.
Therefore, the graph of the given system of inequalities is shown below.
please help me to do I want primeter and area of this
If you were given a fractional strip, that did not have any subdivisions marked like this one pictured below, how would you determine the fractional amount of the bar that is shaded?
9514 1404 393
Answer:
it depends on the accuracy and resolution required of the answer
Step-by-step explanation:
The shaded portion appears to be about half the length of the unshaded portion, suggesting the shaded amount is 1/3.
__
Using a pair of dividers, one could determine the number of times the shaded portion fits into the whole bar. Depending on how much is left over, the process could repeat to determine the approximate size of the remaining fraction relative to the bar or to the shaded portion. (Alternatively, one could replicate the length of the bar to see what integer number of shaded lengths fit into what integer number of whole lengths.)
One could measure the shaded part and the whole bar with a ruler, then determine the relative size of the shaded part by dividing the first measurement by the second. The finer the divisions on the ruler, the better the approximation will be.
