An algorithm for navigating or searching through tree or graph data structures is called depth-first search. The algorithm begins at the root node (choosing an arbitrary node to serve as the root node in the case of a graph) and proceeds to investigate each branch as far as it can go before turning around.
Thus, the basic concept is to begin at the root or any other random node, mark that node, then advance to the next nearby node that is not marked. This process is repeated until there are no more adjacent nodes that are unmarked. Then go back and look for more unmarked nodes to cross. Print the path's nodes lastly.
To solve the issue, adhere to the instructions listed below:
Make a recursive function that accepts a visited array and the node's index.
STEP -1
// C++ program to print DFS traversal from
// a given vertex in a given graph
#include <bits/stdc++.h>
using namespace std;
// Graph class represents a directed graph
// using adjacency list representation
class Graph {
public:
map<int, bool> visited;
map<int, list<int> > adj;
// function to add an edge to graph
void addEdge(int v, int w);
// DFS traversal of the vertices
// reachable from v
void DFS(int v);
};
void Graph::addEdge(int v, int w){
adj[v].push_back(w); // Add w to v’s list.}
void Graph::DFS(int v)
{
// Mark the current node as visited and
// print it
visited[v] = true;
cout << v << " ";
// Recur for all the vertices adjacent
// to this vertex
list<int>::iterator i;
for (i = adj[v].begin(); i != adj[v].end(); ++i)
if (!visited[*i])
DFS(*i);
}
// Driver's code
int main()
{
// Create a graph given in the above diagram
Graph g;
g.addEdge(0, 1);
g.addEdge(0, 2);
g.addEdge(1, 2);
g.addEdge(2, 0);
g.addEdge(2, 3);
g.addEdge(3, 3);
cout << "Following is Depth First Traversal"
" (starting from vertex 2) \n";
// Function call
g.DFS(2);
return 0;
STEP- 2
Time complexity: O(V + E), where V is the number of vertices and E is the number of edges in the graph.
Auxiliary Space: O(V), since an extra visited array of size V is required.
Pseudocode:
Depth_First_Search(matrix[ ][ ] ,source_node, visited, value)
{
If ( sourcce_node == value)
return true // we found the value
visited[source_node] = True
for node in matrix[source_node]:
If visited [ node ] == false
Depth_first_search ( matrix, node, visited)
end if
end for
return false //If it gets to this point, it means that all nodes have been explored.
//And we haven't located the value yet.
}
final answer-
A tree data structure or a graph's vertices can be searched using a recursive technique called t. Beginning with the first node of graph G, the depth-first search (DFS) algorithm digs down until it reaches the target node, also known as the node with no children.
The DFS method can be implemented using a stack data structure due to its recursive nature. The DFS algorithm implementation procedure is comparable to that of the BFS algorithm.
The following describes how to implement DFS traversal step-by-step. -
Create a stack with all of the graph's vertices in it first.
Select whatever vertex you want to use as the first vertex in the traverse, and add it to the stack.
uses for the DFS algorithm
The following list of uses for the DFS algorithm includes:
The topological sorting can be implemented using the DFS algorithm.
It can be applied to determine the routes connecting two vertices.
It can also be used to find graph cycles.
DFS technique is also applied to puzzles with a single solution.
If a graph is bipartite or not, it can be determined using DFS.
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If f(x) = x³ + 14x² + 61x + 84, which of the following is not a factor of f(x)?
A fair coin is tossed 10 times. Find the probability of satisfying the condition that that the coin does not land on tails twice in a row
The probability of tossing 10 tails in a row is [tex]\frac{1}{1024}[/tex]
A probability is a number that reflects the chance or likelihood that a particular event will occur. Probabilities can be expressed as proportions that range from 0 to 1, and they can also be expressed as percentages ranging from 0% to 100%.
Given that,
When a fair coin is tossed 10 times, the sample size (n) is:
n = [tex]2^{10}[/tex]
This is so because a fair coin has 2 sides.
So, we have:
n = 1024
There is only one occurrence of having 10 tails in a row in the 1024 possible outcomes.
So, the probability is:
P = [tex]\frac{1}{1024}[/tex]
Therefore,
The probability of tossing 10 tails in a row is [tex]\frac{1}{1024}[/tex]
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Eli and Amy brought in 3 packs of stickers to give out to their two classes. They had enough for Mrs. O’s 21 students, Mrs. L's 24 students and even had 15 stickers left over! How many stickers were in each pack?
ill give brainliest semester ends tommorow
Answer: We can set up the equation 21 stickers/pack + 24 stickers/pack + x stickers/pack = 15 stickers.
We can solve this equation to find that x, the number of stickers in each pack, is equal to 6 stickers/pack. Answer: 6
Answer: 20
Step-by-step explanation:
24 + 21 = 45
45 + 15 = 60
60 / 3 = 20
You win an online auction for a toy. Your winning bid of $30 is 60% of your maximum bid. How much more were you willing to pay for the toy than you actually paid?
Answer:
I was willing to pay $20 more for the toy than I actually paid.
Step-by-step explanation:
Let us take the maximum bid be y
So,
(y × 60) ÷ 100 = 30
60y/100 = 30
60y/100 × 100 = 30 × 100
60y = 3000
60y/60 = 3000/60
y = 50
60% of $50 is $30
So,
50 - 30 = 20
Thus, I was willing to pay $20 more for the toy than I actually paid.
Four friends paid a total of $32 for bowling. What is the ratio $32 for 4 people written as a unit rate?
Answer:
$8 per person
Step-by-step explanation:
32 divided by 4 is 8
32 : 4 = 8 : 1
3. "Seventeen less than twice a number is -49."
Answer: the number is -16
Step-by-step explanation: if you add 17 to -49, you will get -32. you do this because it is 17 less than NOT more than. that would be called inverse operations. then, you divide that number by 2 to get -16. again, you use inverse operations because you are going backwards to try and find the number.
Answer: -16
Step-by-step explanation: So, to solve, we should write an equation. It should look like this:
2x - 17 = -49
So, using inverse operations, we would add 17 to - 49, which is -32, then divide that by 2, which would be -16. I hope this helped!
P.S. our new equation would look like 2(16) - 17 = -49
32-17 = 49
32 + -17 = 49
49 = 49
It checks out.
Reshawn read 25 pages of his book each day until he finished the book. His book was 400 pages long. Which sketch represents this solution
Graph (C) which has points (0, 400) and (16, 0) represent the solution to the given situation of Rashawn.
What is a graph?In mathematics, a graph is a visual representation or diagram that shows facts or values in an ordered way.
The relationships between two or more items are frequently represented by the points on a graph.
Graphs and charts are useful visual aids because they make information accessible and quick to understand.
Therefore, it is not unexpected that print and electronic media frequently use graphs.
When data is displayed as a graph rather than a table, it can often be easier to understand because the graph might show a pattern or comparison.
So, Rashawn consumed 25 pages of his book daily till it was finished. There were 400 pages in his book.
400 / 25 = 16 days is the estimated number of days he needs to finish the book.
He will have 400 pages finished in 0 days and 0 pages in 16 days.
As a result, the situation is represented by a graph with a line segment in the first quadrant.
Days are shown on the x-axis, and Pages left are listed on the y-axis.
The line segment's ends are (0, 400) and (16, 0).
Therefore, graph (C) which has points (0, 400) and (16, 0) represent the solution of the given situation of Rashawn.
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Complete question:
Rashawn read 25 pages of his book each day until he finished the book. His book was 400 pages long.
Which sketch represents this situation?
a) A graph in the first quadrant containing a line segment. The x axis is labeled Days and the y axis is labeled Pages remaining. The endpoints of the line segment are begin ordered pair 0 comma 400 end ordered pair and begin ordered pair 25 comma 0 end ordered pair.
b) A graph in the first quadrant containing a line segment. The x axis is labeled Days and the y axis is labeled Pages remaining. The endpoints of the line segment are begin ordered pair 0 comma 16 end ordered pair and begin ordered pair 400 comma 0 end ordered pair.
c) A graph in the first quadrant containing a line segment. The x axis is labeled Days and the y axis is labeled Pages remaining. The endpoints of the line segment are begin ordered pair 0 commas 400 end ordered pair and begin ordered pair 16 commas 0 ends ordered pair.
d) A graph in the first quadrant containing a line segment. The x axis is labeled Days and the y-axis is labeled Pages remaining. The endpoints of the line segment are begin ordered pair 0 commas 25 ends ordered pair and begin ordered pair 400 commas 0 ends ordered pair.
A train travels at 80 miles per hour. An equation can be written that compares the time (t) with the distance (d). What is the domain and range?
1. The domain is distance (d) and the range is time (t).
2. The domain is time (t) and the range is distance (d).
3. The domain is time (t) and the range is 80.
4. The domain is 80 and the range is time (t).
The required answer is the domain is time (t) and the range is a distance (d) i.e. Option 2.
What are domain and range?
The value range that can be plugged into a function is known as its domain. In a function like f, this set represents the x values f(x). The collection of values that a function can take on is known as its range. The values that the function outputs when we enter an x value are in this set.
From the given question, and the above definition of domain and range,
the time (t) acts as an x-values or input value and the distance (d) acts as a y-value or output value
Hence, the domain is time (t) and the range is a distance (d) i.e. Option 2.
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A lamina occupies the region inside circle x2 +y2 = 2y but outside circle x2 +y2 = 1. Find the center of mass if the density atany point is inversely proportional to its distance from theorigin.
the answer is {0, [3√3/2(3√3-π)]}
Ф {0, [3√3/2(3√3-π)]}
The poster above has good diagrams ; so , I will just go through the calculations .
The region of integration is with in the circle x ^2+y^2=2y but outside the circle x^2+y^2=1.
I would convert to polar . With polar , we have x^2+y^2=r^2 ,x=rcosФ and y=rsinФ
We thus have the first circle becomes x^2+y^2=2y ⇒r^2=2rsinФ Divide through by r, and you get r=2sinФ(1).
This is the upper circle in the previous posters diagrams .
The other equation of a circle becomes :
x^2 + y^2 = 1 ⇒ r^2 = 1 ⇒ r = 1 (2)
These two curves intersect at :
r= 2sinФ =1 ⇒ sinФ=1/2 ⇒Ф= [tex]\alpha[/tex]/6 or 5[tex]\pi[/tex]/6
From the previous poster's diagrams , we can see that there is as much mass on either side of the positive. y axis or
Ф=[tex]\pi[/tex]/2 axis in polar ; so , the X coordinate of the center of mass is zero
X=0 We can also see from his diagrams that the mass and moment of mass is symmetrical about the Ф=[tex]\pi[/tex]/2
we only need to integrate from Ф=[tex]\pi[/tex]/6 to Ф=[tex]\pi[/tex]/2 ( the answers from to are the same and double )
The differential of area in polar coordinates is
d A=rdrdФ They say the area mass density is inversely proportional to the distance from the origin .
This can be written as : p=k/r. We can thus say the differential of mass is
d M=PDA=
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Error Analysis.
Use mathematical reasoning and appropriate terminology to describe (with words) and correct the error (with work) in simplifying each rational expression.
Error Analysis 1:(x-3)/(x+7)
Error Analysis 2:(x(x-7)(x+3))/2(x+1)(x+9)(x+5)
What is meant by error analysis?Error analysis is a procedure that is usually used to identify the cause of the issue when pupils continually make mistakes. The method entails going over a student's work and looking for patterns of misinterpretation. Mathematical errors can occur for a variety of reasons and can be factual, procedural, or conceptual. The study of the kind and quantity of mistake, or uncertainty, that might be present in the solution to a problem is known as error analysis in mathematics. This issue is particularly common in practical disciplines like statistics and numerical analysis. The teacher can examine a student's errors on a worksheet, test, or progress monitoring tool to do an error analysis for mathematics. In order to grade each problem, the teacher should mark each wrong digit in the student's response, starting from the RIGHT, going to the LEFT for addition, subtraction, and multiplication problems.
Error Analysis 1:
(x²-x-6)/(x²+9x+14)
=(x-3)(x+2)/(x+2)(x+7)
=(x-3)/(x+7)
Error Analysis 2:
(x²-6x-27)/(2x²+2x)÷(x²+14x+45)/(x²)
=(x(x-7)(x+3))/2(x+1)(x+9)(x+5)
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Refer to the above diagram. Economies of scale: A) are evident over the entire range of output. B) occur over the OQ range of output. C) begin at output 03. D) occur only over the
Economies of scale occur when average cost declines with an increase in output. This occurs up to output level Q1.
Diseconomies of scale occur when average cost increases with an increase in output. This begins at output level Q3.
The phenomenon known as economies of scale occurs when the size or magnitude of the production generated by a business increases while the average cost per unit of output decreases.
The Long Run Average Cost Curve demonstrates how a firm's average expenses change over time. The shift from point A to point B illustrates how the cost per unit decreases as the curve slopes down. Because of economies of scale, the average cost grows less proportionally to output over the downward sloping region of the curve.
Minimum efficient scale is the level of output where economies of scale have been fully exploited.
A competitive firm produces at the minimum point of ATC in the long run and thus achieves productive efficiency.
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Max found a car he wants to buy that costs $16,000. He can
afford to pay $250 a month for the car. His bank offers him a car
loan of 7.3%. How will the length of his loan be for this payment
amount?
Answer: To calculate the length of a loan, you need to know the total cost of the loan, the monthly payment amount, and the interest rate. In this case, the total cost of the car is $16,000, the monthly payment amount is $250, and the interest rate is 7.3%.
First, you need to calculate the total interest that will be paid on the loan. This can be done by multiplying the total cost of the loan by the interest rate, and then dividing by 100 to convert the result to a percentage. In this case, the total interest paid would be $16,000 * 7.3 / 100 = $1,168.
Next, you need to subtract the total interest from the total cost of the loan to find the total amount of the loan that will be used to pay for the car. In this case, the total amount of the loan used to pay for the car would be $16,000 - $1,168 = $14,832.
Finally, you can use this total amount and the monthly payment amount to calculate the length of the loan by dividing the total amount by the monthly payment amount. In this case, the length of the loan would be $14,832 / $250 = 59.32 months, or just over four years. The answer is 59.32 months.
Step-by-step explanation:
a professor at a certain school polled 12 colleagues about the number of meetings they attended in the last five years (x) and the number of papers they submitted to peer reviewed journals (y) during the same period. the summary data are as follows: n
The number of meetings they attended in the last five years (x) and the number of papers they submitted to peer reviewed journals (y) during the same period is [tex]-8.6+3.15[/tex].
What is formula for slope and intercept is?
[tex]$$\begin{aligned}& b=\frac{n \sum x y-\left(\sum x\right)\left(\sum y\right)}{n \sum x^2-\left(\sum x\right)^2} \\& a=\bar{y}-b \bar{x} \\& \hat{y}=a+b x\end{aligned}$$[/tex]
The slope is
[tex]$$\begin{aligned}b & =\frac{n \sum x y-\left(\sum x\right)\left(\sum y\right)}{n \sum x^2-\left(\sum x\right)^2} \\& =\frac{12 \times 318-(12 \times 4)(12 \times 4)}{12 \times 232-(12 \times 4)^2} \\& =3.15\end{aligned}$$[/tex]
The intercept is
[tex]$$\begin{aligned}a & =\bar{y}-b \bar{x} \\& =4-3.13 \times 4 \\& =-8.6\end{aligned}$$[/tex]
The regression equation is
[tex]$$\begin{aligned}\hat{y} & =a+b x \\& =-8.6+3.15 x\end{aligned}$$[/tex]
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Write the complex equation 8 + 3; in trigonometric form.
The complex equation 8 + 3; in trigonometric form is z = 8.544[cos(20.6) + isin(20.6)}.
What is trigonometric form ?
Here, we'll utilize that fundamental transformation to recast z = a + bi in a different (sometimes more practical) form that is based on the polar transformation. The trigonometric form of a complex number is the name of this new representation.
Given
8 + 3i
Required
Rewrite in trigonometric form.
The trigonometric form of a complex equation is
z = r[cosθ + isinθ]
Let a = 3 and b = 8
Where
r is calculated by
r² = b² + a²
And
θ is calculated by
θ = arctan(a/b)
Substituting 3 for a and 8 for b
r² = a² + b² becomes
r² = 3² + 8²
r² = 9 + 64
r² = 73
√r² = √73
r = √73
r = 8.544
Calculating θ
θ = arctan(a/b) becomes
θ = arctan(3/8)
θ = arctan(0.375)
θ = 20.556°
θ = 20.6 --- Approximated
Hence, z = r[cosθ + isinθ] becomes
z = 8.544[cos(20.6) + isin(20.6)}
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Which set of factors corresponds to a third-degree polynomial with rational coefficients that has zeros x=2 and x=3i
(x-2)(x²+9) is set of factors corresponds to a third-degree polynomial with rational coefficients.
What is polynomial?
In arithmetic, a polynomial is an expression consisting of indeterminates and coefficients, that involves solely the operations of addition, subtraction, multiplication, and positive-integer powers of variables.
Main body:
as the polynomial with rational coefficients that has zeros x=2 and x=3i
(x-2) and (x-3i) are factors of third-degree polynomial.
so ,
⇒(x-2)(x-3i)
solving (x-3i)
x = 3i
squaring both sides,
x² = -9
so , (x²+9) is a factor.
hence , (x-2)(x²+9) is set of factors corresponds to a third-degree polynomial with rational coefficients.
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What is the fourth root of 625
The required answer is the fourth root of 625 is 5. In summary, the fourth root of 625 is 5.
To find the fourth root of 625, we need to determine the number that, when raised to the power of 4, equals 625. Here's the step-by-step process:
Step 1: Start with the number 625.
Step 2: Take the fourth root of 625.
Since we're looking for the fourth root, we need to find a number that, when raised to the power of 4, equals 625.
Step 3: Determine the number that, when raised to the power of 4, equals 625.
To find this number, we can use the concept of exponentiation. Let's denote the unknown number as "x". Mathematically, we have [tex]x^4 = 625[/tex]..
Step 4: Solve the equation [tex]x^4 = 625[/tex].
To solve this equation, we need to find the value of x. Taking the fourth root of both sides of the equation, we have [tex]\sqrt[4]{(x^4)} =\sqrt[4] {625}.[/tex]
The fourth root of 625 is (625)^(1/4).
Step 5: Simplify the expression.
We can simplify [tex]\sqrt[4]{ 625}[/tex] as follows:
[tex]\sqrt[4]{ 625} = \sqrt[4]{ 5^4}= 5^{4/4} = 5^1 = 5.[/tex]
Therefore, the fourth root of 625 is 5. In summary, the fourth root of 625 is 5.
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Can you help me with this
2. Natalie is selling candles to raise money for her softball team. The team has two different options for selling the candles. The first option is to sell a package of 5 candles for $18. The second option is to sell individual candles for $4 each.
(a) The team wants to earn $1404. How many candles do the members need to sell if they sell candles only in packages? How many candles do they need to sell if they sell only single candles? Explain your answer using an equation for each situation.
(b) Describe at least one advantage of selling the candles in packages. Describe at least one disadvantage of selling the candles in packages
a) The amounts that the team needs to sell is given as follows:
Packages: 390 candles.Single candles: 351 candles.b) The advantage and disadvantage is given as follows:
Advantage: Better opportunity cost when a person needs one candle, the person will have to purchase the entire package.Disadvantage: Lower revenue per candle.How to obtain the amounts?The amounts needed are found applying the proportion, considering the costs and the number of candles.
A package of 5 candles for $18, hence the number of candles needed to earn $1404, in packages, is given as follows:
5 candles - $18
n candles - $1404
Applying cross multiplication, we have that:
18n = 5 x 1404
n = 5 x 1404/18
n = 390 candles.
With a single candle, the number of candles is calculated as follows:
1404/4 = 351 candles.
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Determine whether the integers in each of these sets are pairwise relatively prime. a) 11, 15, 19 b) 14, 15, 21 c) 12, 17, 31, 37 d) 7, 8, 9, 11
Note that Option A is pairwise and is relatively prime.
Option B is not relatively primeOption C is also a relatively primeOption D is also relatively prime.What does it mean for a list of integers to be pairwise relatively prime?If every pair of elements in a list of integers is relatively prime, the list is pairwise relatively prime. For example, the numbers 121, 122, and 123 are relatively prime pairwise (even though they are each composite).
You can tell if a set of numbers are relatively prime if they do not share a common factor other than ±
Looking at set a:
11, 15, 19
Writing their prime factorization
11 = 11
15 = 3 x 5
19 = 19, hence since any pair of these numbers does not have any common factor, hence they are relatively prime.
Looking at set b:
14, 15, 21
Writing their prime factorization, we have:
14 = 7 x 2
15 = 3 x5
21 = 3 x 7
15, and 21 share a common factor of 3 while
14 and 21 share a common factor of 7, therefore, they are NOT relatively prime.
Looking at set c)
12, 17, 31, 37
Writing their prime factorization,
12 = 3 x 2²
17 = 17
31 = 31
37 = 37
In this case, no pair of these numbers have any common factor. Hence they are relatively prime.
Looking at set d)
7,8,9, 11, spelling out their prime factorization
7=7
8=2³
9=3²
11=11
Thus, any pair of these numbers do not have a common factor, hence they are relatively prime.
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W is the midpoint of SU, TU ⊥ SU and SU ⊥ SV. Complete the proof that Δ SVW ≅ Δ UTW.
Statement Reason
1. W is the midpoint of SU Given
2. TU ⊥ SU Given
3. SU ⊥ SV Given
4. ∠S ≅ ∠U All right angles are congruent
5. ∠ SVW ≅ ∠ UTW Definition of midpoint
6. Δ SVW ≅ Δ UTW.
The proof that Δ SVW ≅ Δ UTW is given by ASA congruence criterion.
What do you mean congruence of triangle?Two triangles are said to be congruent if all three corresponding sides are equal and all the three corresponding angles are equal in measure. These triangles can be slides, rotated, flipped and turned to be looked identical. If repositioned, they coincide with each other.
The symbol of congruence is’ ≅’.
Given:W is the midpoint of SU
⇒ SW = WUTU ⊥ SU and SU ⊥ SV
To prove:Δ SVW ≅ Δ UTW
Proof:In Δ SVW and Δ UTWSW = UW (given)
∠S ≅ ∠U (given)
∠ SVW ≅ ∠ UTW (vertically opposite angle)
Therefore, Δ SVW ≅ Δ UTW (by ASA congruence criterion)
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Write an equation and solve.
When two times the difference of a number x and three is increased by five, the result is nine. What is the number?
With all this information, and reading our question carefully, we can decipher the following:
9(n-3) = 3 + (9n + 3n)
9n - 27 = 3 + (9n +3n) (Step 1. Distributive Property)
9n - 27 = 3 + 12n (Step 2. Combine like terms; 9n + 3n = 12n)
-9n -9n (Step 3. Subtract 9n from both sides to isolate the variable)
______________
-27 = 3 + 3n
-3 -3 (Step 4. Subtract 3 from both sides)
________________
-30 = 3n
----- ----
3 3 (Step 5. Divide 3 from both sides)
________________
-10 = n
Therefore, n = -10
What is Distributive property?Distributive property explains that the operation performed on numbers, available in brackets that can be distributed for each number outside the bracket. It is one of the most frequently used properties in Maths. The other two major properties are commutative and associative property.The distributive property is easy to remember. There are a number of properties in Maths which will help us to simplify not only arithmetical calculations but also the algebraic expressions. In this article, you will learn what is distributive property, formula, and solved examples.to learn more about distributive property refer to:
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Given: ABCD is a parallelogram with AE = 9x−5, AC = 14x + 34. Find AC
The value of AC according to given equation of Parallelogram is 188 units.
What is parallelogram?
In elementary geometry, a parallelogram may be a quadrilateral with 2 pairs of parallel sides. the alternative or facing sides of a quadrangle square {measure} of equal length
Main body:
according to question:
AE = 9X-5
AC = 14X+34
as E is midpoint of AC so , we can say
2AE = AC
2(9x-5)= 14x+34
18x-10= 14x+34
4x = 44
x = 11
Now we need to find AC = 14x+34
= 14*11+34
= 188 units
Hence the value of AC according to given equation of Parallelogram is 188 units.
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Each of the 9 reindeer have 8 jingle bells on their collar. There are 12 more bells on the reins. How many bells in all?
Answer: 84 bells
Step-by-step explanation:
12 + 9x8
84
let w represent the number of attempted experiments to get one experiment that is not successful. the random variable w has a geometric distribution with mean 4 and standard deviation 3.5. which of the following is the best interpretation of the standard deviation? responses a single value randomly selected from the distribution of w will vary from 4 by 3.5 attempted experiments. a single value randomly selected from the distribution of w will vary from 4 by 3.5 attempted experiments. a single value randomly selecte
The best interpretation of the standard deviation on this problem is given as follows:
A single value randomly selected from the distribution of w will vary from 4 by 3.5 attempted experiments.
How to interpret the standard deviation?The standard deviation of a data-set is calculated as the square root of the sum of the differences squared between each observation of the data-set and the mean, divided by the number of observations in the data-set.
The interpretation of this calculation is that the standard deviation represents by how much each value of the distribution is expected to vary from the mean, on average.
This means that the correct statement is given as follows:
A single value randomly selected from the distribution of w will vary from 4 by 3.5 attempted experiments.
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State the Domain, Range, in interval notation.
Domain:
Range:
The range and domain of the graph shown is
domain -4 ≤ x < ∞
range ∞ ≤ x < 3
How to find the domain and the rangeAll of a function's x-values, or inputs, make up the domain, and all of a function's y-values, or outputs, make up the range.
The domain of a graph is every value in the graph, from left to right.
Examining the curve the extreme left has x coordinate value of -4 and the right end have an arrow which means the value continues. this is written as
-4 ≤ x < ∞
The graph's entire range, from lower to higher numbers, in the vertical line represents the range.
Examining the curve the lowest point the curve reached in y-coordinate have an arrow which means the value continues and the top end have the value of 3. this is written as
∞ ≤ x < 3
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-3/2 passes through (-4, 3)
what is the y intercept and equation
(in slope intercept form)
Jeremy has 3/4 pound of fish food if fish food is used to feed 24 fish how much food is there for each fish
Answer:
There is 1/32 pound food for each fish
Step-by-step explanation:
24 fish = 3/4 pound food
1 fish = (3/4)/24 pound food = 1/32 pound food
(Problem solved by using unitary method)
Which properties determine whether a quadrilateral is a parallelogram?
A. both pairs of opposite sides of a quadrilateral are both congruent and parallel
B. one pair of opposite sides of a quadrilateral is both congruent and parallel
C. it has 4 right angles
D. one pair of opposite sides of a quadrilateral is parallel
c is the answer. jdjsisiao
What is the slope-intercept equation for this line?
Answer:
y = -1/2x - 2
Step-by-step explanation:
y = mx+b, m = -1/2, and b (the y-intercept) is -2.
i need the answers please
(7) Slope of line AB = -6/5 and Slope of the line CD = -6/5 and line AB and line CD are parallel in nature.
(8)Slope of line AB = 3/4 and the Slope of line CD = 1 and line AB and line CD is neither parallel nor perpendicular.
(9) We have drawn the graph passing through the point P and parallel to line AB.
(10)We have drawn the graph passing through the point P and perpendicular to line AB.
What is the property of slopes of parallel lines and perpendicular lines?
If two lines are given and they are parallel to each other then the slopes are equal and for perpendicular lines, the product of their slopes is equal to -1.
(7) The line AB is passing through the points (-1, 5/2) and (3/2, -1/2).
Slope = y2 - y2/x2 - x1
= (-1/2 - 5/2)/(3/2-(-1))
= -6/5
As line AB and line CD are parallel in nature so the slope of line CD is also -6/5.
(8) The line AB is passing through the points (1/2, 1) and (5/2, 5/2).
Slope = y2 - y2/x2 - x1
= (5/2 - 1)/(5/2-1/2)
=3/2/2
= 3/4
Line CD is passing through points (1, 1) and (2, 3).
Slope = y2 - y2/x2 - x1
= (3 - 1)/(2-1)
=2/2
= 1
As the product of their slopes is not equal to -1.
So lines are neither parallel nor perpendicular.
(9) Slope of AB can be computed as (-2, 1) and (-5, 5)
Slope = 5 - 1/-5 + 2
= 4/-3.
The slope of line passing through the point P = -4/3 as we have to draw the parallel line.
Point P = (-1, 3)
Equation of the line :
y - 3 = -4/3(x + 1)
3y +9 = -4x - 4
3y = -4x - 13
Now we can draw the line
(10) Slope of line AB = -4/3
So the slope of the line passing through point P should be 3/4 in order to be perpendicular to line AB.
Equation of the line passing through point P:
y - 3 = 3/4(x - (-1))
y - 3 = 3/4(x+1)
Hence,
(7) Slope of line AB = -6/5 and Slope of the line CD = -6/5 and line AB and line CD are parallel in nature.
(8)Slope of line AB = 3/4 and the Slope of line CD = 1 and line AB and line CD is neither parallel nor perpendicular.
(9) We have drawn the graph passing through the point P and parallel to line AB.
(10)We have drawn the graph passing through the point P and perpendicular to line AB.
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Cathy was not watching her dog's eating habits and his weight went from 40 pounds to 48
pounds. By what percentage did the dog's weight increase?
Answer:
Step-by-step explanation:
To find the percentage increase in the dog's weight, you can use the following formula:
percentage increase = (final value - initial value) / initial value x 100%
In this case, the initial value is 40 pounds and the final value is 48 pounds, so the percentage increase is:
percentage increase = (48 - 40) / 40 x 100% = 8 / 40 x 100% = 20%
Therefore, the dog's weight increased by 20%.
