In the following reaction 6.13 g of water is actually produced, but the theoretical yield of water is 8.17 g. What is the percent yield of this reaction? *

85.0%
72.0%
75.0%
67.0%

In The Following Reaction 6.13 G Of Water Is Actually Produced, But The Theoretical Yield Of Water Is

Answers

Answer 1

Answer:

75.0%

Explanation:

Data obtained from the question. This includes the following:

Actual yield = 6.13g

Theoretical yield = 8.17g

Percentage yield =...?

The percentage yield can be obtain by using the following formula:

Percentage yield = Actual yield /Theoretical yield x 100

Percentage yield = 6.13/8.17 x 100

Percentage yield = 75.0%

Therefore, the percentage yield of water from the reaction above is 75.0%


Related Questions

How many kilograms of solvent (water) must 0.71 moles of KI be dissolved in to produce a 1.93 m solution?

Answers

Answer: kg= 0.37

Explanation:

Use the molality formula.

M= m/kg

using the following balanced chemical equation: PCL5 -> PCL3 + CL2 and knowing that Keq = 7.9, [PCL3] = 0.054M and [CL2] = 0.34M
a. write the Keq expression for the reaction
b. find the [PCL5]
c circle the correct answer: the reaction favored is the (forward, reverse)

Answers

Answer:

see explanations

Explanation:

              PCl₅  =>     PCl₃     +     Cl₂

C(eq):   [PCl₅]       0.054M        0.34M

a.  Keq = [PCl₃][Cl₂]/[PCl₅]

b.  7.9 = (0.054)(0.34)/[PCl₅] => [PCl₅] = (0.054)(0.34)/(7.9) = 0.0023M

c.  If [PCl₃] = 0.054M; [Cl₂] = 0.34M and [PCl₅] = 0.0023M then the reaction is at equilibrium and will not shift forward or in reverse. In order to determine if reaction is not at equilibrium, a set of concentration values needs to be given in problem, used to calculate Qeq and compared to the given Keq value.  The following defines direction of shift ...

Keq  <  Qeq  =>  rxn shifts left

Keq  =  Qeq  =>  rxn is at equilibrium (no shift)

Keq  >  Qeq  =>  rxn shifts right

NOTE: If Keq is listed first followed by Qeq in the above conditions, the inequality symbol indicates direction of shift.

a fertilizer manufacturer makes a batch of 20kg of ammonium nitrate. what mass of ammonia in kg, does the manufacturer need to start with?

Answers

Answer:

[tex]m_{NH_3}=4.25kgNH_3[/tex]

Explanation:

Hello,

In this case, for the production of ammonium nitrate we shall consider the following chemical reaction:

[tex]NH_3+HNO_3\rightarrow NH_4NO_3[/tex]

Hence, since the molar mass of ammonium nitrate is 80 g/mol and the molar mass of ammonia is 17 g/mol, we could compute the required mass of ammonia to produce 20 kg of ammonium nitrate  by using kilo-based units:

[tex]m_{NH_3}=20kgNH_4NO_3*\frac{1kmol}{80kgNH_4NO_3}*\frac{1kmolNH_3}{1kmolNH_4NO_3}*\frac{17kgNH_3}{1kmolNH_3} \\\\m_{NH_3}=4.25kgNH_3[/tex]

Best regards.

If you start with 6 mol of nitrogen gas (N2+) what mass (g) of ammonia (NH4) will be produced?

Answers

Answer:

204g of NH3

Explanation:

The balanced equation for the reaction is given below:

N2 + 3H2 —> 2NH3

Next, we shall determine the number of mole NH3 produced by reacting 6moles of N2. This is illustrated below:

From the balanced equation above,

1 mole of N2 reacted to produce 2 moles of NH3.

Therefore, 6 moles of N2 will react to produce = 6 x 2 = 12 moles of NH3.

Finally, we shall convert 12 moles of NH3 to grams. This is illustrated below:

Number of mole of NH3 = 12 moles.

Molar mass of NH3 = 14 + (3x1) = 17g/mol

Mass of NH3 =..?

Mass = mole x molar mass

Mass of NH3 = 12 x 17

Mass of NH3 = 204g.

Therefore, 204g of NH3 will be produced from the reaction.

The first step that you will do in lab is to prepare approximately 20.0 mL each of the following solutions of NaOH, using the NaCl solution to dilute the concentrated (0.300 M) solution of NaOH. After you prepare each solution, transfer it to a clean 50 mL beaker on top of a labeled piece of paper. 0.200 M NaOH 0.150 M NaOH 0.100 M NaOH 0.050 M NaOH 0.025 M NaOH

Answers

Answer:

0.200 M NaOH: 13.3 mL of the concentrated solution and complete to 20.0mL

0.150 M NaOH: 10.0 mL of the concentrated solution and complete to 20.0mL

0.100 M NaOH: 6.67 mL of the concentrated solution and complete to 20.0mL

0.050 M NaOH: 3.33 mL of the concentrated solution and complete to 20.0mL

0.025 M NaOH: 1.67 mL of the concentrated solution and complete to 20.0mL

Explanation:

It is possible to prepare a solution from a more concentrated one. In the problem, the concentrated solution is 0.300M NaOH. Thus, to prepare 20.0mL of each of the solutions you will need:

0.200 M NaOH: 20.0mL × (0.200M / 0.300M) = 13.3 mL of the concentrated solution and complete to 20.0mL

The ratio between the concentrated solution and the solution you want to prepare is called "dilution factor"

0.150 M NaOH: 20.0mL × (0.150M / 0.300M) = 10.0 mL of the concentrated solution and complete to 20.0mL

0.100 M NaOH: 20.0mL × (0.100M / 0.300M) = 6.67 mL of the concentrated solution and complete to 20.0mL

0.050 M NaOH: 20.0mL × (0.050M / 0.300M) = 3.33 mL of the concentrated solution and complete to 20.0mL

0.025 M NaOH: 20.0mL × (0.025M / 0.300M) = 1.67 mL of the concentrated solution and complete to 20.0mL

Which of the following is not an indication of a chemical change?
A. Fracture Formation
B. Energy transfer
C. Precipitate formation.
D. Gas production

Answers

Answer:

C. precipitate formation.

Explanation:

options C is correct answer.

Answer:

C. precipitate formation.

Explanation:

The percent yield of a reaction in which 52 grams of a reactant is expected to yield 30 grams of product is 25%. What is the actual yield of the reaction? A) 13 grams B) 120 grams C) 208 grams D) 7.5 grams

Answers

Answer:

D) 7.5 grams

Explanation:

Hello,

In this case, since the percent yield is defined by:

[tex]Y=\frac{m^{actual}}{m^{theoretical}} *100\%[/tex]

In such a way, since the percent yield is up to 25% and the expected or theoretical amount is 30 g of the product, the actual yield of the reaction is:

[tex]m^{actual}=\frac{Y*m^{theoretical}}{100\%} =\frac{25\%*30g}{100\%} \\\\m^{actual}=7.5g[/tex]

Therefore the answer is D) 7.5 grams.

Best regards.

Please help! BRAINLIEST to correct answer!!!!

Answers

Answer:

Exothermic Process

Explanation:

An aqueous solution of HNO2 is poured onto a solid pile of SrCO3. Identify the net ionic equation for this reaction.

A) SrCO3(s) + 2 HNO2(aq) → Sr(NO2)2(aq) + HCO3(aq)
B) no reaction occurs
C) Sr2+ + CO32- + 2 H+ → Sr2+ + H2O + CO2(g)
D) SrCO3(s) + 2 HNO2(aq) → Sr(NO2)2 + H2O + CO2(g)
E) SrCO3(s) + 2 H+ → Sr2+ + H2O + CO2(g)

Answers

Answer:

D) SrCO3(s) + 2 HNO2(aq) → Sr(NO2)2 + H2O + CO2(g)

Explanation:

When an acid react with carbonate, it produces nitrate, carbon-dioxide gas and water molecule. When nitrous acid react with Strontium carbonate, three products are formed i. e. Strontium nitrate, carbon-dioxide gas and water. In the reaction, both nitrous acid and Strontium carbonate exchange their partners with each other and forming a different products.

Answer:

Option E is correct.

The net ionic equation is given as

SrCO₃(s) + 2H⁺ → Sr²⁺ + H₂O + CO₂(g)

Explanation:

When acids react with carbonate compounds, it leads to the liberation of CO₂, hence, when an aqueous solution of HNO₂ is poured onto a solid pile of SrCO₃, the balanced overall equation is given as

SrCO₃(s) + 2HNO₂(aq) → Sr(NO₂)₂ + H₂O + CO₂(g)

But for the net ionic reaction, it is obtained by eliminating ions that occur on both sides of the overall reaction. Note that ions exist onlubone the aqueous compounds.

Hence, the two aqueous compounds that exist in the balanced overall equation are

2HNO₂(aq) on the left hand side and Sr(NO₂)₂ on the right hand side

In their ionic form, 2HNO₂ ⇌ 2H⁺ + 2NO₂⁻

And Sr(NO₂)₂ ⇌ Sr²⁺ + 2NO₂⁻

And it is evident that the ion that occurs on both sides and needs to be deleted is NO₂⁻,

Hence, the net ionic equation is

SrCO₃(s) + 2H⁺ → Sr²⁺ + H₂O + CO₂(g)

Hope this Helps!!!

Changes in pressure can have a large effect on equilibrium systems containing gaseous components.

1. changing the concentration of gaseous components
2. adding an inert gas has no effect since the gas does not take part in the reaction, all partial pressures stay the same
3.changing the volume of the reaction vessel. This will cause a shift in the equilibrium position if the number of moles of gas is different on the reactant and product side (so Δn = n products - n reactants)

How would you change the volume for each of the following reactions to increase the yield of the product(s)?1. CaCO3(s) ⇋ CaO(s) + CO2(g) (increase, decrease, no change)2. S(s) + 3F2(g) ⇋ SF6(g) (increase, decrease, no change)3. Cl2(g) + I2(g) ⇋ 2ICl(g) (increase, decrease, no change)

Answers

Answer:

The correct option is 1, since by changing the partial pressures the gas pressures change, the gases go from the zones of higher partial pressure to the zones of lower partial pressure, an example of this is the homeostasis of the human pulmonary alveolus in gas exchange with CO2 and O2.

Explanation:

In the first it increases, in the second the volume is maintained, and in the third reaction it decreases.

Answer:

1. Increase volume.

2. No change.

3. No change.

Explanation:

Hello,

In this case, if we want to shift the reaction rightwards, based on the Le Chatelier's principle we would have to:

1. For this reaction:

[tex]CaCO_3(s) \rightleftharpoons CaO(s) + CO_2(g)[/tex]

- Increase the volume or decrease the pressure, since there are more gaseous moles at the products.

2. For this reaction:

[tex]S(s) + 3F_2(g) \rightleftharpoons SF_6(g)[/tex]

- Do nothing since it is not possible to achieve it as we have the same number of gaseous moles at both reactants and products.

3. For this reaction:

[tex]Cl_2(g) + I_2(g)\rightleftharpoons 2ICl(g)[/tex]

- Do nothing since it is not possible to achieve it as we have the same number of gaseous moles at both reactants and products.

Regards.

Nitrogen gas was collected by water displacement. What was the pressure of the N2 collected if the temperature was 50 degrees celcius?

Answers

Answer:

Explanation:

Atmospheric pressure = 101.325 kPa

vapor pressure of water at 50°C = 12.332 kPa

pressure of N₂ = (Atmospheric pressure) - (vapor pressure of water at 50 oC)

pressure of N₂ = (101.325 kPa) - (12.332 kPa)

pressure of N₂ = 88.993 kPa

Therefore, the pressure of the N₂ collected if the temperature was 50 degrees celcius is 88.993 kPa

Identifying the Body's Responses to
Quick
Check
Which type of response identifies a specific pathogen in the body?
A(n)
response

Answers

Answer:

Specific Immune Response

Explanation:

A specific immune response identifies the pathogen which then allows it to produce antibodies that protect against that SPECIFIC pathogen.

Answer:

immune

Explanation:

pls I need help with these ques. help plsssssssssssssss

Answers

Answer:

q1..no.2 and 4 are aromatic

State whether the following is an example of a physical or chemical change:! 21. Burning a log: ________________________________! 22. Folding a piece of paper: _________________________! 23. Freezing water: _________________________! 24. Bending a copper wire. _________________________!

Answers

Answer:

Physical change

Explanation:

Because it doesn't require any chemical to change

Answer:

Physical change

Physical change

Physical change

Physical change

Explanation:

Plants remove carbon to the atmosphere during

Answers

Answer:

respiration

Explanation:

Plants give out carbon dioxide not only at night but during the day too. It happens because of the process of respiration in which plants take in oxygen and give out carbon dioxide. As soon as the sun rises another process called photosynthesis starts, in which carbon dioxide is taken in and oxygen is given out.

Plants use photosynthesis to capture carbon dioxide and then release half of it into the atmosphere through respiration. Plants also release oxygen into the atmosphere through photosynthesis

What is another term for anode?

Answers

Answer:positive electrode

Explanation:

Anode can also be referred to as positive electrode in a cell

Lifting a box off the floor is an example of what type of force?

A). Natural

B).applied

C).frictional

D).gravitational

Answers

Answer:

It would be applied force.

Explanation:

Hope it helps:)

The temperature of a 350. mL sample of gas increases from 27 °C to 227 °C. What is the final volume of the sample of gas, if the pressure and amount of gas in the container is kept constant?
Group of answer choices

Answers

Answer:

[tex]V_2=583.3mL[/tex]

Explanation:

Hello,

In this case, for the given constant amount and pressure of the, we apply the Charles' law which allows us to understand the volume-pressure behavior as a directly proportional relationship:

[tex]\frac{V_1}{T_1} =\frac{V_2}{T_2}[/tex]

Thus, since we need to compute the volume after the temperature increase (which must be expressed in absolute Kelvins), we obtain V2 as:

[tex]V_2=\frac{V_1T_2}{T_1} =\frac{350.0mL*(227+273.15)K}{(27+273.15)K}\\ \\V_2=583.3mL[/tex]

Best regards.

2. What happens to the pH when you add more H+ ions to a solution that has no buffers?

Answers

It will go over the amount it needs to.

In a titration, 100 mL of 0.026 M HCl (aq) is neutralized by 13 mL of KOH(aq). Calculate the molarity of KOH (aq).

Answers

Answer:

0.2M

Explanation:

Step 1:

Data obtained from the question.

Volume of acid (Va) = 100mL

Molarity of the acid (Ma) = 0.026 M

Volume of base (Vb) = 13mL

Molarity of the base (Mb) =..?

Step 2:

The balanced equation for the reaction. This is given below:

HCl + KOH —> KCl + H2O

From the balanced equation above,

The mole ratio of the acid (nA) = 1

The mole ratio of the base (nB) = 1

Step 3:

Determination of the molarity of the base, KOH. This can be obtained as follow:

MaVa/MbVb = nA/nB

0.026 x100 / Mb x 13 = 1

Cross multiply to express in linear form

Mb x 13 = 0.026 x 100

Divide both side by 13

Mb = 0.026 x 100 / 13

Mb = 0.2M

Therefore, the molarity of the base, KOH is 0.2M

Answer:

0.2M

Explanation:

KOH(aq) + HCl(aq) ⇒  KCl(aq) + H2O(l)

We express the moles of analyte (HCl) and titrant based (KOH) on their molar concentration:

M1 * V1 = M2 * V2

The molarity of the solution is calculated with the following equation:

M2 = V1 x M1 / ​​V2

Where:

V2 = valued sample volume

V1 = volume of titrant consumed (measured with the burette)

M1 = concentration of titrant solution

M2 = concentration of sample

M2 = 100mL * 0.026M / 13mL = 0.2M

What should happen if a good experiment is replicated?
The results will decrease.
The results will increase.
The results will be different.
The results will be similar.

Answers

Answer:

The results will be similar.

The results will be similar

Which shows an isomer of the molecule below?

Answers

Answer:

D

Explanation:

An isomer is a molecule with the same number of atoms as another compound, but they differ in arrangement of the atoms.

Answer:

D

Explanation:

A P E X

How is a niche different than a habitat?

A habitat is more than a physical place; it's a species' role in a specific place and it can change from niche to niche.

A niche is more than a physical place; it's a species' role in a specific place and it can change from habitat to habitat.

A niche and a habitat are the same.

A niche is just a physical place; a habitat is a species' role in a specific place.

Answers

Answer:

A niche is more than a physical place; it's a species' role in a specific place and it can change from habitat to habitat.                  

Explanation:

Niche: In biology, the term "niche" is described as a process through which different organisms tends to fit-in into a specific ecosystem or an ecological community. However, a niche is considered as the "evolutionary result" of a specific species behavioral, morphological, and physiological adaptations associated with its surroundings.

Habitat: In biology, the term "habitat" is described as an environmental or ecological area that is being inhabited by a specific species of plants, animals, or other organisms.

Therefore, a niche is entirely different from a habitat because an organism's niche tends to explain every different aspect of its life whereas its habitat explains the place it lives.

A characteristic that describe a plant that can make its own food is

Answers

Answer:

Photosynthesis

this is correct

what is the reaction?

Answers

Answer:

A chemical reaction is a process in which one or more substances, also called reactants, are converted to one or more different substances, known as products. ... A chemical reaction rearranges the constituent atoms of the reactants to create different substances as products.

Explanation:

Hopefully this is what you needed

Please help!!! Will give BRAINLIEST to right answer!!

Answers

Answer:

Explanation:

∆H positive means heat is required or absorbed -- endothermic

∆H negative means heat is produced or removed -- exothermic

The tribute states of the ancient Aztec empire
were governed directly by the emperor.
made regular payments to the emperor.
acted as powerful independent city-states.
O surrounded the main Aztec city-state.

Answers

Answer:

made regular payments to the emperor.

Explanation:

The Aztec Empire was an alliance of three states: Mexico-Tenochtitlan, Texcoco, and Tlacopan. The area in and around the Valley of Mexico was ruled by these three city-states from 1428 to 1521. The state religion of the empire was polytheistic. The tribute states of the ancient Aztec empire made regular payments to the emperor.

Answer:

B

Explanation:

Question 17 In the Haber reaction, patented by German chemist Fritz Haber in 1908, dinitrogen gas combines with dihydrogen gas to produce gaseous ammonia. This reaction is now the first step taken to make most of the world's fertilizer. Suppose a chemical engineer studying a new catalyst for the Haber reaction finds that 786. liters per second of dinitrogen are consumed when the reaction is run at 222.°C and 0.35atm. Calculate the rate at which ammonia is being produced. Give your answer in kilograms per second. Round your answer to 2 significant digits.

Answers

Answer:

Explanation:

N₂       + 3H₂     =     2 NH₃

1 vol                         2 vol

786 liters               1572 liters

786 liters of dinitrogen will result in the production of 1572 liters of ammonia

volume of ammonia V₁ = 1572 liters

temperature T₁ = 222 + 273 = 495 K

pressure = .35 atm

We shall find this volume at NTP

volume V₂ = ?

pressure = 1 atm

temperature T₂ = 273

[tex]\frac{P_1V_1}{T_1} =\frac{P_2V_2}{T_2}[/tex]

[tex]\frac{.35\times 1572}{495} =\frac{1\times V_2}{ 273 }[/tex]

[tex]V_2 =303.44[/tex] liter .

mol weight of ammonia = 17

At NTP mass of 22.4 liter of ammonia will have mass of 17 gm

mass of 303.44 liter of ammonia will be equal to (303.44 x 17) / 22.4 gm

= 230.28 gm

=.23 kg / sec .

Rate of production of ammonia = .23 kg /s .

CH³C⁴HCOCH³ how many atoms of each element are in one molecule of 2-heptanone

Answers

Answer:

- 7 carbon atoms.

- 14 hydrogen atoms.

- 1 oxygen atom.

Explanation:

Hello,

In this case, for the given compound, heptanone, whose chemical formula is:

[tex]CH_3COCH_2CH_2CH_2CH_2CH_3[/tex]

We can write the molecular formula showing the present atoms of each element:

[tex]C_7H_{14}O[/tex]

In such a way we have:

- 7 carbon atoms.

- 14 hydrogen atoms.

- 1 oxygen atom.

Best regards.

0.5 moles of CO2 have a volume of 50 L and a pressure of 0.8210 atm. What must be the temperature of the gas?

Answers

Answer:

1000 K

Explanation:

Given data

Moles of carbon dioxide (n): 0.5 molesVolume of carbon dioxide (V): 50 litersPressure of carbon dioxide (P): 0.8210 atmospheresTemperature of carbon dioxide (T): ?

We can find the temperature of carbon dioxide using the ideal gas equation.

[tex]P \times V = n \times R \times T\\T = \frac{P \times V}{n \times R} = \frac{0.8210atm \times 50L}{0.5mol \times \frac{0.08206atm.L}{mol.K} }=1000 K[/tex]

The temperature of the gas is 1000 K.

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Anybody know any pros and cons about spaceXs environment Consider the quadratic function:f(x) = x2 8x 9 ?????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????? 1).He gastado 5/8 de mi dinero. Si en lugar de gastar los 5/8 hubiera gastado los 2/5 de mi dinero, tendria ahora 72 soles mas de lo que tengocuanto NO gaste? 2). Si al ao que cumpli 10 aos le sumamos el ao que cumpli 20 , y a este resultado le restas la suma del ao en que naci con mi edad actual , obtendremos el ao actual cuanto resultara sumar mi edad con el ao en que cumplire los 30 aos y restarle el ao en que cumplire los 40 aos? AYUDA CON PROCEDIMIENTO PARA ESTOS DOS EJERCICIOS POR FAVOR what was the life expectancy of 1880 and 1890 in the U.S.? Gavyn can type 2200 words in 40 minutes. Stephen can type 3850 in 70 minutes. Richard can type 3000 words in 50 minutes. Who types at the fastest rate of words per minute? What type of ratio can be a fraction? apart to whole bwhole to part cpart to part dpart to total Part U16 is used by Mcvean Corporation to make one of its products. A total of 18,000 units of this part are produced and used every year. The company's Accounting Department reports the following costs of producing the part at this level of activity: Per Unit Direct materials $ 3.90 Direct labor $ 8.50 Variable manufacturing overhead $ 9.00 Supervisor's salary $ 4.40 Depreciation of special equipment $ 2.80 Allocated general overhead $ 8.00 An outside supplier has offered to make the part and sell it to the company for $28.70 each. If this offer is accepted, the supervisor's salary and all of the variable costs, including the direct labor, can be avoided. The special equipment used to make the part was purchased many years ago and has no salvage value or other use. The allocated general overhead represents fixed costs of the entire company, none of which would be avoided if the part were purchased instead of produced internally. In addition, the space used to make part U16 could be used to make more of one of the company's other products, generating an additional segment margin of $30,000 per year for that product. The annual financial advantage (disadvantage) for the company as a result of buying part U16 from the outside supplier should be: g Which was an important colonial interest for Great Britain following World War I?a. Japanb. Algeriac. Chinad. India An instructor at a major research university occasionally teaches summer session and notices that that there are often students repeating the class. On the first day of class, she counts 105 students enrolled, of which 19 are repeating the class. The university enrolls 15,000 students. 1. An estimate of the population proportion repeating the class is given by: a) 0.0013. b) 0.007. c) 0.181. d)0.046. 2. The instructor wishes to estimate the proportion of students across campus who repeat a course during summer sessions and decides to do so on the basis of this class. Would you advise the instructor against it and why: a) No, because 105 students is a pretty large class. b) Yes, because this class is too small. c) No, because it is completely arbitrary who takes this class. d) Yes, because this class is not a random sample of students. 3. The standard error for the estimated sample proportion is given by: a) 0.025. b) 0.0014. c) 0.0376. d) 0.005. 4. A 95% confidence interval is given by: a) 0.15, 0.23. b) 0.345, 0.453. c) 0.107, 0.255. d) 0.09, 0.272. 5. She hypothesizes that, in general, 10% of students repeat a course. The hypotheses to be tested are: a) H0:p? =0.181 vs. H?:p=0.1 . b) H0:p=0.1 vs. H?:p?0.18 . c) H0:p=0.1 vs. H?:p? =0.181 . d) H0:p=0.1 vs. H?:p?0.1 . 6. The test statistic for this hypothesis is given by: a) 2.575. b) 2.332. c) 2.765. d) 1.96. 7. The P?value for this test is: a) 0.05>P>0.01 . b) P>0.05 . c) 0.01>P>0.005 . d) 0.005>P . 8. Based on the p-value found: a) we have convincing proof that the proportion of students repeating a class during summer sessions is not 10%. b) we have strong evidence that the proportion of students repeating a class during summer sessions is not 10%. c) we have strong evidence that the proportion of students repeating a class during summer sessions is 10%. d) we have no doubt that the proportion of students repeating a class during summer sessions is not 10%. The commander of the United Nations forces in Korea wasa.Thomas Dewey.b.Dwight D. Eisenhower.c.Strom Thurmond.d.Douglas MacArthur. Which of the following is false regarding hands and personal hygiene?Cover wounds with clean bandages and gloves or a finger cot.Nails should be kept short and clean,False fingernails are acceptable.O Gloves should never be used in the place of hand washing. 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