Answer:
c. 4 and 42
Step-by-step explanation:
Given
[tex]p = 4[/tex] -- independent variables
[tex]n = 47[/tex] ---- observations
Required
The numerator and denominator degrees of freedom
The denominator degrees of freedom is:
[tex]df =n - p - 1[/tex]
[tex]df =47 - 4 - 1[/tex]
[tex]df =42[/tex]
For the numerator, we have:
[tex]df = p[/tex]
[tex]df = 4[/tex]
During a basketball practice, Steph Curry made 234 three point shots in 45 minutes,
In the same practice, his teammate Klay Thompson made 168 three point shots in 34 minutes.
1) Find the unit rates of both players of shots made per each minute
2) Which player was making more shots at a higher rate?
I needsdd helppppp pleaseeeee
Answer:
1) 5.2, and 4.94117647
2) Steph curry
Step-by-step explanation:
can someone help me solve this?
Answer:
[tex]\sqrt{x} -\frac{16}{\sqrt{x} }[/tex]
Step-by-step explanation:
A classmate walks into class and states that he has an extra ticket to a chamber orchestra concert on Friday night. He asks everyone in the class to put their name on a piece of paper and put it in a basket. He plans to draw from the basket to choose the person who will attend the concert with him. If there are 38 other people in class that night, what is your chance of being chosen to attend the concert
Answer:
2.56% chance of being selected
Step-by-step explanation:
Given
[tex]n = 39[/tex] --- you and 38 others
Required
Chance of you being selected
To do this, we simply calculate the probability using:
[tex]Pr(x) = \frac{n(x)}{n}[/tex]
Where:
[tex]n(x)= 1[/tex] --- i.e you are just 1 person
So:
[tex]Pr(x) = \frac{1}{39}[/tex]
[tex]Pr(x) = 0.0256[/tex]
Express as percentage
[tex]Pr(x) = 2.56\%[/tex]
Which choice correctly shows the line y =
2x+3?
А
B
HN
N
1-3 -2 -1 1 2 3 4
-1
NH
-4 -3 -2 -1
1 2 3 4
D
c
2
1
1-3-2-1
1
2 3 4
-4 -3 -2
1 2 3
-1
-2
The diagram shows the right-angled triangle. (a) Calculate the area.
(b) Calculate the perimeter
Step-by-step explanation:
no diagram visible. there is nothing to calculate.
Answer:
No diagram
Step-by-step explanation:
For area of right angled triangle 1/2 × base× height
Perimeter plus three sides of the triangle
Suppose 47% of the population has a college degree. If a random sample of size 460 is selected, what is the probability that the proportion of persons with a college degree will differ from the population proportion by greater than 5%
Answer:
387287i32
Step-by-step explanation:
i did it
Roulette is a casino game that involves spinning a ball on a wheel that is marked with numbered squares that are red, black, or green. Half of the numbers 1 - 36 are colored red and half are black and the numbers 0 and 00 are green. Each number occurs only once on the wheel. What is the probability of landing on an even number and a number greater than 17? (A number is even if it is divisible by 2. 0 and 00 are considered even as well.)
Answer:
the wording (punctuation) of the question can lead to different interpretations....
I assume that the question was >17 & even which is "5/19",
BUT... it can also be read as two questions
first >17 which is "10/19"
and second an even number which is "9/19"
BUT !!! I think that the question answer is 5/19
Step-by-step explanation:
Even Number = 18/38 = 9/19
greater 17 = 20/38 = 10/19
Even & greater 17 = 10/38 = 5/19
Meghan sells advertisements for a radio station. Each 30 second ad costs $20 per play, and each 60 second ad
costs $35 per play. Meghan sold 12 ads for $315. She wrote the system below letting x represent the number of 30
second ads and y represent the number of 60 second ads.
X+ y = 12
20x+35y = 315
What is the solution to the system of equations?
Need answers ASAP!!!!
Answer:
usai964s46s694s4o6s64694s946649s469 opps
Answer:
[tex](x,y)=(7,5)[/tex]
Step-by-step explanation:
Megan's equation will be:
[tex]20x+35y=315[/tex]
[tex]x+y=12[/tex]
Substitute [tex]x=12-y[/tex] in the first equation:
[tex]20(12-y)+35y=315[/tex]
[tex]15y=75[/tex]
[tex]y=75/15[/tex]
[tex]y=5[/tex]
Find x:
[tex]x=12-5[/tex]
[tex]x=7[/tex]
Where x and y represent 30-second and 60-second ads sold, we find that Meghan's sales were:
[tex](x,y)=(7,5)[/tex]
hope this helps....
According to the graph above, College R showed
the greatest change in enrollment between which
two decades?
Given:
The graph that shows the ennoblement for college R between 1950 and 2000.
To find:
The two decades that has the greatest change in enrollment.
Solution:
From the given graph, it is clear that the change in the enrollment is:
From 1950 to 1960 is [tex]4-3.5=0.5[/tex] thousand.
From 1960 to 1970 is [tex]5-4.5=1.5[/tex] thousand.
From 1970 to 1980 is [tex]5.5-5=0.5[/tex] thousand.
From 1980 to 1990 is [tex]6.5-5.5=1[/tex] thousand.
From 1990 to 2000 is [tex]7-6.5=0.5[/tex] thousand.
The two decades 1960-1970 and 1980-1990 have the greatest change in enrollment.
Answer:1980 to 1990
Step-by-step explanation:
Which of the following values cannot be probabilities? 3/5, 2, 0, 1, −0.45, 1.44, 0.05, 5/3 Select all the values that cannot be probabilities.
Given:
The numbers are [tex]\dfrac{3}{5},2,0,1,-0.45, 1.44[/tex].
To find:
All the values that cannot be probabilities.
Solution:
We know that,
[tex]\text{Probability}=\dfrac{\text{Favorable outcomes}}{\text{Total outcomes}}[/tex]
The minimum value of favorable outcomes is 0 and the maximum value is equal to the total outcomes. So, the value of probability lies between 0 and 1, inclusive. It other words, the probability lies in the interval [0,1].
[tex]0\leq \text{Probability}\leq 1[/tex]
From the given values only [tex]\dfrac{3}{5}, 0, 1[/tex] lie in the interval [0,1]. So, these values can be probabilities.
The values [tex]2,-0.45, 1.44[/tex] does not lie in the interval [0,1]. So, these values cannot be probabilities.
Therefore, the correct values are [tex]2,-0.45, 1.44[/tex].
The Power in a circuit is given by the formula P=I^{2}R, where I is the Current and R is the Resistance. If the Resistance is always constant at 500, the Current is 1, and dI/dt = -0.5, then dP/dt = -500.
True or false and please show work. Thank you
True
Step-by-step explanation:
[tex]P(t) = I^2(t)R[/tex]
Taking the derivative of P(t) with respect to time,
[tex]\dfrac{dP(t)}{dt} = 2I(t)\dfrac{dI(t)}{dt}R[/tex]
[tex]\:\:\:\:\:\:\:\:= 2(1)(-0.5)(500) = -500[/tex]
This exercise uses the population growth model. The population of a certain species of fish has a relative growth rate of 1.9% per year. It is estimated that the population in 2010 was 11 million. (a) Find an exponential model n(t)
Answer:
n(t) = 11e^0.019t
Step-by-step explanation:
The estimated population in 2010 = 11,000,000 = initial population
The growth rate = 1.9% per year = 1.9/100 =
The exponential growth model follows the general form :
n(t) = ae^rt
a = Initial population ; r = growth rate ; t = period
Hence, we have ;
n(t) = 11e^0.019t in millions
Two functions, A and B, are described as follows: Function A y = 9x + 4 Function B The rate of change is 3 and the y-intercept is 4. How much more is the rate of change of function A than the rate of change of function B?
2
3
6
9
Answer:
[tex]{ \tt{rate \: of \: change \: in \: A = 9}}[/tex]
Rate of change in function A is two times than that in function B
Atomic No.
Element
Atomic Wt.
Europium
To take a systematic sample, first choose any number between one and five and write it here: k-23
Using the atomic number to count off elements, let the k value you just chose represent the first element in your
sample. Then, count off every fifth element thereafter. For instance, if you chose k-2, your sample will include
Helium (2), Nitrogen (7), Magnesium (12), and so forth. List each atomic number and atomic weight, starting with k
and adding 5 to the atomic number cach time.
Atomic No. Element
Atomic Wt.
3. Lithium 6.94
63
Isla6
8
v४
16
oxygen
Erbium 167.26
13 nluminum 24.98 23 Tantalum
180.45
18 Argon
39.95
28
platinum
195.DK
23 Vanadium 50.94 83 Bismuth 208.48
Niin
28
86
158.69
Radium 226
33
Arsenic 74.92
93 Neptunium 237
38 Strontium
98
87.62
Californium 251
43 Technutium 98
103 Lawrencium 262
UR
cocaina [12.41
108
Hassium
277
Iodine 126.9
113
No element
o
658 Cerium 140:11 118 Unumactiun
63
294
Find the mean atomic weight of this sample and enter it here: x xytomate : 137
AP statistics
Answer:
Atomic No.
Element
Atomic Wt.
Europium
To take a systematic sample, first choose any number between one and five and write it here: k-23
Using the atomic number to count off elements, let the k value you just chose represent the first element in your
sample. Then, count off every fifth element thereafter. For instance, if you chose k-2, your sample will include
Helium (2), Nitrogen (7), Magnesium (12), and so forth. List each atomic number and atomic weight, starting with k
and adding 5 to the atomic number cach time.
Atomic No. Element
Atomic Wt.
3. Lithium 6.94
63
Isla6
8
v४
16
oxygen
Erbium 167.26
13 nluminum 24.98 23 Tantalum
180.45
18 Argon
39.95
28
platinum
195.DK
23 Vanadium 50.94 83 Bismuth 208.48
Niin
28
86
158.69
Radium 226
33
Arsenic 74.92
93 Neptunium 237
38 Strontium
98
87.62
Californium 251
43 Technutium 98
103 Lawrencium 262
UR
cocaina [12.41
108
Hassium
277
Iodine 126.9
113
No element
o
658 Cerium 140:11 118 Unumactiun
63
294
Find the mean atomic weight of this sample and enter it here: x xytomate : 137
AP statistics
Step-by-step explanation:
Find the value of z, the measure of the subtended arc.
86°
47°
188°
94°
Answer:
188 degrees
Step-by-step explanation:
The measure of the arc is the center angle, that is double of the circumference one
94 * 2 = 188 degrees
GET 95 POINTS Let f(x) = 1/x and g(x)=x² + 6x. What
two numbers are not in the domain of fᵒg?
Separate your answers with a comma.
Answer:
hey there hope this answer helps you out
Step-by-step explanation:
we have two functions f(x) and g(x) such that
[tex]f(x) = \frac{1}{x} [/tex]
and
[tex]g(x) = {x}^{2} + 6x[/tex]
solving for f ° g, we'll substitute the x in f(x) by the value of g(x)
[tex]fog = \frac{1}{g(x)} [/tex]
[tex]fog \: = \frac{1}{ {x}^{2} + 6x } [/tex]
taking x common in denominator
[tex]fog = \frac{1}{x(x + 6)} [/tex]
for a function to exist it should not have 0 in its denominator
checking the values of x for which the denominator of f ° g becomes 0 :-
x = 0 and x = -6so the function doesn't exist at values x = 0, -6
So, 0, -6 cannot be in the domain of f°gProve that: (secA-cosec A) (1+cot A +tan A) =( sec^2A/cosecA)-(Cosec^2A/secA)
Step-by-step explanation:
[tex](\sec A - \csc A)(1 + \cot A + \tan A)[/tex]
[tex]=(\sec A - \csc A)\left(1 + \dfrac{\cos A}{\sin A} + \dfrac{\sin A}{\cos A} \right)[/tex]
[tex]=(\sec A - \csc A)\left(1 + \dfrac{\cos^2 A + \sin^2 A}{\sin A\cos A} \right)[/tex]
[tex]=(\sec A - \csc A)\left(\dfrac{1 + \sin A \cos A}{\sin A \cos A} \right)[/tex]
[tex]=\left(\dfrac{\frac{1}{\cos A} - \frac{1}{\sin A}+\sin A - \cos A}{\sin A\cos A}\right)[/tex]
[tex]=\dfrac{\sin A - \sin A \cos^2A - \cos A + \cos A\sin^2A}{(\sin A\cos A)^2}[/tex]
[tex]=\dfrac{\sin A(1 - \cos^2A) - \cos A (1 - \sin^2 A)}{(\sin A\cos A)^2}[/tex]
[tex]=\dfrac{\sin^3A - \cos^3A}{\sin^2A\cos^2A}[/tex]
[tex]=\dfrac{\sin A}{\cos^2A} - \dfrac{\cos A}{\sin^2A}[/tex]
[tex]=\left(\dfrac{1}{\cos A}\right)\left(\dfrac{\sin A}{1}\right) - \left(\dfrac{1}{\sin^2A}\right) \left(\dfrac{\cos A}{1}\right)[/tex]
[tex]=\sec^2A\csc A - \csc^2A\sec A[/tex]
aulo uses an instrument called a densitometer to check that he has the correct ink colour.
For this print job the acceptable range for the reading on the densitometer is 1.8 ± 10%.
What is the acceptable range for the densitometer reading?
Answer:
The range is from 1.62 to 1.98.
Step-by-step explanation:
We have to solve for the percentage of the particular value if the range of the answer should be +/- 10% of the particular value.
The value given is 1.8, we thus want to find 10% of that: 1.8 * 10/100 = 0.18
Then, add this value to the original value of 1.8: 1.8+0.18 = 1.98
Furthermore, subtract .18 from from the original value of 1.8: 1.8-0.18 = 1.62
The range will be between these two numbers, so the range is from 1.62 to 1.98.
Evaluate these questions 27(1/3)2
Answer:
18
Step-by-step explanation:
1/3 of 27 is 9. 9 times 2 is 18.
How many 10 digits numbers have no two digits the same and do not start with 0 or 1?
Answer:
at least 99
Step-by-step explanation:
each number starting from 2 can be moved 11 times per thing.
The function f(x)=0.21x + 13.8 can be used to predict diamond production. For this function, x is the number of years after 2000, and f(x) is the value in billions of dollars) of the year's diamond production. Use this function to predict diamond production in 2006. The diamond production in 2006 is predicted to be $billion. (Type an integer or a decimal.) Enter your answer in the answer box ?
Answer:
[tex]\boxed {\boxed {\sf \$15.06 \ billion }}[/tex]
Step-by-step explanation:
We are given the function f(x). This is the value of diamond production for the year in billions.
[tex]f(x)= 0.21x+13.8[/tex]
We want to find the value of the diamond production in 2006.
We know that x is the number of years after 2000. The year 2006 was 6 years after 2000 because 2006 - 2000 = 6. Therefore, x (years after 2000) is equal to 6. We can substitute 6 in for x.
[tex]f(6)= 0.21(6)+ 13.8[/tex]
Solve according to PEMDAS (Parentheses, Exponents, Multiplication, Division, Addition, Subtraction).
Multiply 0.21 and 6.
[tex]f(6)= 1.26+13.8[/tex]
Add 1.26 and 13.8
[tex]f(6)=15.06[/tex]
Remember the answer is in billions of dollars.
[tex]f(6)= \$ 15.06 \ billion[/tex]
Diamond production in 2006 is expected to be worth 15.06 billion dollars.
Here are two steps from the derivation of the quadratic formula.
What took place between the first step and the second step?
Answer:
Factoring a perfect square trinomial.
Step-by-step explanation:
The left side was able to be simplified via factoring.
What is the y-intercept of the graph of y = 2.5x? a. 2.5 c. 0 b. 1 d. -1
Answer:
answer is C
Step-by-step explanation:
General equation of a line is expressed as shown:
y = mx+c where;
m is the slope or gradient of the line
c is the intercept of the line
Given the equation of the line graph as y =2.5x
Comparing the given equation with the general equation, it is seen that m = 2.5 and c = 0 (since there is no value for the intercept)
Based on the explanation, the y-intercept of the graph is therefore 0
Answer:
B
Step-by-step explanation:
To find the x-intercept, substitute in
0 for y and solve for x
To find the y-intercept, substitute in 0 for x and solve for y
x-intercept(s): None
y-intercept(s): (0,1)
simplify 3xy + x 2 - 4xy + 2xupper2y
Q.No.4. Ali is hiking on the hill, whose height is given by f(u,v)=n^2 e^((u+n)/(v+n)). Currently, he is positioned at point (3,5). Find the direction at which he moves down the hills quickly. (5 points) Where n is the product of first and second digit of your arid number e.g. 19-arid-435 take n=4x3=12
Answer:
///////
Step-by-step explanation:
Find the solution set.
The solution set for 5v2 – 125 = 0
Escreva a matriz A = (aij) do tipo 3x4 sabendo que aij = 3i – 2j.
Answer:
[tex]A = \left[\begin{array}{cccc}1&-1&-3&-5\\4&2&0&-2\\7&5&3&1\end{array}\right][/tex]
Step-by-step explanation:
A = (aij)
i representa a linha e j a coluna.
Tipo 3x4
Isto implica que a matriz tem 3 linhas e 4 colunas.
aij = 3i – 2j.
Primeira linha:
[tex]a_{1,1} = 3(1) - 2(1) = 1[/tex]
[tex]a_{1,2} = 3(1) - 2(2) = -1[/tex]
[tex]a_{1,3} = 3(1) - 2(3) = -3[/tex]
[tex]a_{1,4} = 3(1) - 2(4) = -5[/tex]
Segunda linha:
[tex]a_{2,1} = 3(2) - 2(1) = 4[/tex]
[tex]a_{2,2} = 3(2) - 2(2) = 2[/tex]
[tex]a_{2,3} = 3(2) - 2(3) = 0[/tex]
[tex]a_{2,4} = 3(2) - 2(4) = -2[/tex]
Terceira linha:
[tex]a_{3,1} = 3(3) - 2(1) = 7[/tex]
[tex]a_{3,2} = 3(3) - 2(2) = 5[/tex]
[tex]a_{3,3} = 3(3) - 2(3) = 3[/tex]
[tex]a_{3,4} = 3(3) - 2(4) = 1[/tex]
Matriz:
A matriz é dada por:
[tex]A = \left[\begin{array}{cccc}1&-1&-3&-5\\4&2&0&-2\\7&5&3&1\end{array}\right][/tex]
In the rhombus, mZ1 = 140. What are mZ2 and mZ3? The diagram is not to scale.
gjgb go ftc in the class is not a short time to be be free and ear is not a short time to
I need help pls!! 20 points I need it!!
Answer: About 6.71 units
Step-by-step explanation:
You use the distance formula: [tex]\sqrt{(x_{2}-x_{1})^{2}+(y_{2}-y_{1})^{2} }[/tex].
Assign the the two points to the variables:
[tex](x_{1}, y_{1}) = (1, 3)\\(x_{2}, y_{2}) = (4, -3)[/tex]
Substitute them in the formula:
[tex]\sqrt{(4-1)^{2}+(-3-3)^{2}}[/tex]
And solve it:
[tex]\sqrt{(4-1)^{2}+(-3-3)^{2}}\\=\sqrt{(3)^{2}+(-6)^{2}}\\=\sqrt{9+36}\\=\sqrt{45}\\=6.71[/tex]
Answer:
I got the answer as 6.70 .here's how
Step-by-step explanation:
c= ( 1,3)
d=(4,-3)
Now , formula of distance
√(x2 - x1)^2 +(y2 - y1)^2
or, √(4-1)^2+(-3-3)^2
or, √(3)^2+(-6)^2
or,√9+36
or√45
√45 = 6.70 units approx
The function f(x) is shown below.
х
-6
-3
f(x)
1
2
5
3
Coon
0
If g(x) is the inverse of f(x), what is the value of f(g(2))?
-6
оооо
5
Answer:
[tex]f(g(2)) = 2[/tex]
Step-by-step explanation:
Given
[tex]x \to f(x)[/tex]
[tex]-6 \to 1[/tex]
[tex]-3 \to 2[/tex]
[tex]g(x) = f^{-1}(x)[/tex] --- inverse
Required
[tex]f(g(2))[/tex]
For two functions f(x) and g(x) where f(x) and g(x)are inverse;
[tex]f(g(x)) = x[/tex]
So, by comparison:
[tex]f(g(2)) = 2[/tex]
