In mixture A of candy ingredients there are 3 parts of milk-chocolate for every Z parts peanut separate mixture B. there are 4 parts of nougat for every 3 parts of caramel equat parts of A and combined in one mixing bow what is the ratio of peanut butter to nougat in the bowl

Answer:

[tex]5 \ \frac{73}{100} [/tex]

Step-by-step explanation:

Convert the decimal number to a fraction by placing the decimal number over a power of ten. Since there are

2 numbers to the right of the decimal point, place the decimal number over 10^2 (100). Next, add the whole number to the left of the decimal.

Answer:

5 73/100

Step-by-step explanation:

5.73 = 573

100

= 573

100

as a fraction

To convert the decimal 5.73 to a fraction, just follow these steps:

Step 1: Write down the number as a fraction of one:

5.73 = 5.73

1

Step 2: Multiply both top and bottom by 10 for every number after the decimal point:

As we have 2 numbers after the decimal point, we multiply both numerator and denominator by 100. So,

5.73

1

= (5.73 × 100)

(1 × 100)

= 573

100

.

(This fraction is alread reduced,

As the numerator is greater than the denominator, we have an IMPROPER fraction, so we can also express it as a MIXED NUMBER, thus 573

100

is also equal to 5 73/100

when expressed as a mixed number.

this figure can be divided into three parts one is rectangle other one is semicircle and the third one is one fourth of the circle .so let's find the area of each figure one by one. For the rectangle 12×8 =96

for semicircle that is on the top it has the radius 6 which is a half of 12

so area of the semicircle is

[tex] \frac{1}{2} \pi \: r {}^{2} \\ \frac{1}{2} \times 3.14 \times 6 {}^{2} \\ 3.14 \times 18 \\ 56.52[/tex]

no that's fine. 80 of the 1/4 of the other Circle

[tex] \frac{1}{4} \pi {}^{2} \\ \frac{1}{4} 3.14 \times 8 {}^{2} \\ 3.14 \times 16 \\ 50.24[/tex]

add all these areas

96+56.52+50.24 =202.76

Answer:

90.25πm^2

Step-by-step explanation:

circumference = 2 pie r

then , 19 pie meter = 2 pie r

so radius r = 19 /2 m

therefore ,

area of circle = pie r ^ 2

= 90.25 pie meter square

Answer:

circle circumference formula is 2 pi R

and area of circle pi R ²

19 pi is 2×9.5×pi

so the radius is 9.5

and area is pi 9.5² m² = 90,25 pi m²

Step-by-step explanation:

45.399,45.454,45.545,45.933

9514 1404 393

Answer:

 x = {-4.4, +2.9}

Step-by-step explanation:

We assume you want to solve ...

  2x^2 +3x -41 = -15

Adding 41 and factoring out the leading coefficient gives ...

  2(x^2 +3/2x) = 26

Dividing by 2 makes it ...

  x^2 +3/2x = 13

We can add the square of half the x-coefficient to "complete the square."

  x^2 +3/2x +(3/4)^2 = 13 +(3/4)^2

  (x +3/4)^2 = 13.5625 . . . . write the left side as a square

  x +3/4 = ±√13.5625 . . . . . take the square root

  x = -0.75 ±3.683 = {-4.433, +2.933} . . . . subtract 3/4 and evaluate

The solutions are approximately x = -4.4 and x = 2.9.

Answer:

1) the planning value for the population standard deviation is 10,000

2)

a) Margin of error E = 500, n = 1536.64 ≈ 1537

b) Margin of error E = 200, n = 9604

c) Margin of error E = 100, n = 38416

3)

As we can see, sample size corresponding to margin of error of $100 is too large and may not be feasible.

Hence, I will not recommend trying to obtain the $100 margin of error in the present case.

Step-by-step explanation:

Given the data in the question;

1) Planning Value for the population standard deviation will be;

⇒ ( 50,000 - 10,000 ) / 4

= 40,000 / 4

σ = 10,000

Hence, the planning value for the population standard deviation is 10,000

2) how large a sample should be taken if the desired margin of error is;

we know that, n = [ ([tex]z_{\alpha /2[/tex] × σ ) / E ]²

given that confidence level = 95%, so [tex]z_{\alpha /2[/tex]  = 1.96

Now,

a) Margin of error E = 500

n = [ ([tex]z_{\alpha /2[/tex] × σ ) / E ]²

n = [ ( 1.96 × 10000 ) / 500 ]²

n = [ 19600 / 500 ]²

n = 1536.64 ≈ 1537

b) Margin of error E = 200

n = [ ([tex]z_{\alpha /2[/tex] × σ ) / E ]²

n = [ ( 1.96 × 10000 ) / 200 ]²

n = [ 19600 / 200 ]²

n = 9604

c)  Margin of error E = 100

n = [ ([tex]z_{\alpha /2[/tex] × σ ) / E ]²

n = [ ( 1.96 × 10000 ) / 100 ]²

n = [ 19600 / 100 ]²

n = 38416

3) Would you recommend trying to obtain the $100 margin of error?

As we can see, sample size corresponding to margin of error of $100 is too large and may not be feasible.

Hence, I will not recommend trying to obtain the $100 margin of error in the present case.

Answer:

(0,6)

Step-by-step explanation:

Answer:

(0,6)

Step-by-step explanation:

We need to find the midpoint of the line segment having end points (-4,5) and (4,7). So, here we can use the Midpoint Formula :-

Points :- (-4,5) and (4,7).

Using Midpoint Formula ,

[tex]\rm\implies Midpoint =\bigg(\dfrac{x_1+x_2}{2},\dfrac{y_1+y_2}{2}\bigg)[/tex]

Substitute the respective values ,

[tex]\rm\implies Midpoint =\bigg(\dfrac{-4+4}{2},\dfrac{7+5}{2}\bigg)[/tex]

Simplify the numbers ,

[tex]\rm\implies Midpoint =\bigg(\dfrac{0}{2},\dfrac{12}{2}\bigg)[/tex]

This equals to ,

[tex]\rm\implies \boxed{\blue{\rm Midpoint =\bigg( 0,6\bigg)}}[/tex]

Hence the midpoint is (0,6) .

Answer:

yeah dude they might of. First look around everywhere in ur room before accusing them.

Step-by-step explanation:

good luck

Answer:

[tex]a_n = 8(-5)^{n-1}[/tex]

The fifth term of the sequence is 5000.

Step-by-step explanation:

Geometric sequence:

In a geometric sequence, the quotient between consecutive terms is always the same, called common ratio. The nth term of a geometric sequence is:

[tex]a_n = a_1(r)^{n-1}[/tex]

a = 8; r = -5

Thus:

[tex]a_n = a_1(r)^{n-1}[/tex]

[tex]a_n = 8(-5)^{n-1}[/tex]

Fifth term:

This is [tex]a_5[/tex]. So

[tex]a_5 = 8(-5)^{5-1} = 5000[/tex]

The fifth term of the sequence is 5000.

Answer:i love you

Step-by-step explanation:

Answer:

pls give me brainliest plzzzzz

Answer:

Area = 156 square cm

Step-by-step explanation:

Answer:

h

Step-by-step explanation:

h

Answer: 2 and 3

Step-by-step explanation:

its numbers

Answer:

A and D

Step-by-step explanation:

Total ice cream bars sold = sum of chocolate sold , vanilla and strawberry ice-creams sold.

=(1/2)x2 + (6/11)x + 8 + (5/9)x2 + (2/3) +(1/3)x2 + 4x +(4/3) (Given in the question)

=(25/18)x2 + (50/11)x + 10 (Adding terms corresponding to x2,x ,constant respectively)

Difference in chocolate and strawberry bars =[ (1/2)x2 + (6/11)x + 8] - [(1/3)x2 + 4x +(4/3)]

= (1/6)x2 - (38/11)x +(20/3)

So, the correct options are A and D

Step-by-step explanation:

the answer is in the above image

Answer:

my answer is 225/5 sorry comments for wrong

Answer:

Step-by-step explanation:

1.4 m = 1.4 * 100 = 140.0  = 140 cm

Given:

Chung has 6 trucks and 5 cars in his toy box.

Brian has 4 trucks and 5 cars in his toy box.

To find:

The correct comparison of their ratios of trucks to cars.

Solution:

The ratio of trucks to cars is defined as:

[tex]\text{Ratio}=\dfrac{\text{Number of trucks}}{\text{Number of cars}}[/tex]

Chung has 6 trucks and 5 cars in his toy box. So, the ratio of trucks to cars is:

[tex]\text{Ratio}=\dfrac{6}{5}[/tex]

Brian has 4 trucks and 5 cars in his toy box.

[tex]\text{Ratio}=\dfrac{4}{5}[/tex]

We know that,

[tex]6>4[/tex]

[tex]\dfrac{6}{5}>\dfrac{4}{5}[/tex]

Therefore, the correct option is D.

Answer:

what the guy above me said

Step-by-step explanation:

so yeah he is right points

Answer:

yes but can be simplified

Step-by-step explanation:

area of shaded part = ( area of square - area of circle ) / 4

= [tex]\frac{12^2-\pi (6)^2}{4}[/tex]

= [tex]\frac{144-36\pi }{4}[/tex]

= [tex]\frac{144}{4}[/tex] - [tex]\frac{36\pi }{4}[/tex]

= 36 - 9π

Answer:

31.3

Step-by-step explanation:

Reference angle given = 56.1°

Hypotenuse = 56.1

Adjacent side = x = ?

We would apply CAH, which is:

Cos 56.1° = Adj/Hyp

Cos 56.1° = x/56.1

56.1 × Cos 56.1° = x

31.2895006 = x

x = 31.3 (approximated to the nearest tenth)

Answer:

[tex] \frac{4}{9} [/tex]

Step-by-step explanation:

[tex]p = \frac{favorable \: outcomes}{total \: outcomes} = \frac{4}{9} [/tex]

=============================================================

Explanation:

The probability you get a black marble on the first selection is 2/3 since we have 2 black marbles out of 2+1 = 3 total.

We put the marble back and then we have 2/3 as the probability of selecting another black marble on the second try. Nothing has changed because we put the marble back. That means the events are independent.

So we get (2/3)*(2/3) = 4/9 as the probability of selecting 2 black marbles in a row (with replacement).

Answer:

77,786.251

Step-by-step explanation:

Answer:

77,786.251 is the answer that equals $42,690e(0.03)×(20)

Step-by-step explanation:

hey mate hope this help you...!

Answer:

I think. . . sphere? SO SORRY IF IM WRONG!!

Step-by-step explanation:

Answer:

profit

hope it is helpful to you

Step-by-step explanation:

Markup is the percentage amount by which the cost of a product is increased to arrive at the selling price.

Answer:

1. 8

2 . 11

[tex]3 . \sqrt{128} \ or \ 8 \sqrt2[/tex]

Step-by-step explanation:

[tex]Distance = \sqrt{(x_2 -x_1)^2 + (y_2 - y_1)^2 }[/tex]

1 . ( 5 , - 2 ) and ( 5 , 6 )

  [tex]Distance = \sqrt{(5 -5)^2 + ( 6-(-2))^2} = \sqrt{ 0 + 8^2 } = \sqrt{64} = 8[/tex]

2 . ( 8 , 6 ) and ( - 3 , 6 )

  [tex]Distance = \sqrt{( -3 -8)^2 + ( 6 - 6)^2 } = \sqrt{ (-11)^2 + 0 } = \sqrt { 121 } = 11[/tex]

3. ( 5 , - 2 ) and ( -3 , 6 )

  [tex]Distance = \sqrt{(-3 - 5)^2 + ( 6 --2)^2} = \sqrt{(-8)^2 + ( 8)^2} = \sqrt{ 64 + 64 } = \sqrt{128}[/tex]

          [tex][ \ \sqrt{128} = \sqrt{ 2 \times 64} = \sqrt{ 2 \times 8^2 } = 8 \sqrt{2} \ ][/tex]

Answer:

Below in bold.

Step-by-step explanation:

a. SA = 2π r^2 + 2πrh

2πrh = SA - 2π r^2

h = (SA - 2πr^2)/2πr

When π = 3.14 we have

h = (SA - 6.28r^2)/ 6.28r

b. SA = 6.28*1.5^2 + 6.28*1.5* 5

= 61.23 in^2

Answer:

A)

Step-by-step explanation:

9514 1404 393

Answer:

  (64x^28)/(5y^22)

Step-by-step explanation:

The applicable rules of exponents are ...

  (a^b)^c = a^(bc)

  (a^b)(a^c) = a^(b+c)

  (a^b)/(a^c) = a^(b-c)

__

First, eliminate the outside exponent on the left factor. Then use the above rules to combine factors with the same base.

  [tex]\displaystyle\left(\frac{4x^4}{5y^6}\right)^5\cdot\left(\frac{5^4y^8}{4^2x^{-8}}\right)=\frac{(4^5x^{20})(5^4y^8)}{(5^5y^{30})(4^2x^{-8})}=4^{5-2}5^{4-5}x^{20-(-8)}y^{8-30}\\\\=4^35^{-1}x^{28}y^{-22}=\boxed{\frac{64x^{28}}{5y^{22}}}[/tex]