The bases for the row space and null space of A, we put A into reduced row echelon form and solve for the null space. The dot product of basis vectors shows they are orthogonal.
To find the bases for the row space and null space of A, we perform row operations on A until it is in reduced row echelon form:
[ 1 -1 3 | 5 ] [ 1 -1 3 | 5 ]
[ 2 1 -5 | -9 ] -> [ 0 3 -11 | -19]
[-1 -1 2 | 2 ] [ 0 0 0 | 0 ]
[ 1 1 -1 | -1 ] [ 0 0 0 | 0 ]
The reduced row echelon form of A tells us that there are two pivot columns, corresponding to the first and second columns of A. The third and fourth columns are free variables. Therefore, a basis for the row space of A is given by the first two rows of the reduced row echelon form of A:
[ 1 -1 3 | 5 ]
[ 0 3 -11 | -19]
To find a basis for the null space of A, we solve the system Ax = 0. Since the third and fourth columns of A are free variables, we can express the solution in terms of those variables. Setting s = column 3 and t = column 4, we have:
x1 - x2 + 3x3 + 5x4 = 0
2x1 + x2 - 5x3 - 9x4 = 0
-x1 - x2 + 2x3 + 2x4 = 0
x1 + x2 - x3 - x4 = 0
Solving for x1, x2, x3, and x4 in terms of s and t, we get:
x1 = -3s - 5t
x2 = s + 2t
x3 = s
x4 = t
Therefore, a basis for the null space of A is given by the vectors:
[-3 1 1 0]
[ 5 2 0 1]
To verify that every vector in the row space of A is orthogonal to every vector in the null space of A, we compute the dot product of each basis vector for the row space with each basis vector for the null space:
[ 1 -1 3 | 5 ] dot [-3 1 1 0] = 0
[ 1 -1 3 | 5 ] dot [ 5 2 0 1] = 0
[ 0 3 -11 | -19] dot [-3 1 1 0] = 0
[ 0 3 -11 | -19] dot [ 5 2 0 1] = 0
Since all dot products are equal to zero, we have verified that every vector in the row space of A is orthogonal to every vector in the null space of A.
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_____The given question is incomplete, the complete question is given below:
in excercises 7 and 8 find bases for the row space and null space of a. verify that every vector in the row(a) is orthogonal to every vector in null(a). a = [ 1 -1 3 5 2 1 0 1 -2 -1 -1 1]
Tom’s yearly salary is $78000
Calculate Tom’s fortnightly income. (Use 26
fortnights in a year.)
Fortnightly income =
$
Tom's fortnightly income is $3000.
What is average?In mathematics, an average is a measure that represents the central or typical value of a set of numbers. There are several types of averages commonly used, including the mean, median, and mode.
To calculate Tom's fortnightly income, we need to divide his yearly salary by the number of fortnights in a year:
Fortnightly income = Yearly salary / Number of fortnights in a year
Fortnightly income = $78000 / 26 = $3000
Therefore, Tom's fortnightly income is $3000.
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question - Calculate the Tom's fortnightly income and yearly salary by the number of fortnights in a year .
Find the standard normal area for each of the following Round your answers to the 4 decimal places
The standard normal areas are given as follows:
P(1.22 < Z < 2.15) = 0.0954. P(2 < Z < 3) = 0.0215.P(-2 < Z < 2) = 0.9544.P(Z > 0.5) = 0.3085.How to obtain probabilities using the normal distribution?The z-score of a measure X of a normally distributed variable that has mean represented by [tex]\mu[/tex] and standard deviation represented by [tex]\sigma[/tex] is obtained by the equation presented as follows:
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
The z-score represents how many standard deviations the measure X is above or below the mean of the distribution of the data-set, depending if the obtained z-score is positive(above the mean) or negative(below the mean).The z-score table is used to obtain the p-value of the z-score, and it represents the percentile of the measure X in the distribution.Considering the second bullet point, the areas are given as follows:
P(1.22 < Z < 2.15) = p-value of Z = 2.15 - p-value of Z = 1.22 = 0.9842 - 0.8888 = 0.0954.P(2 < Z < 3) = 0.0215 = p-value of Z = 3 - p-value of Z = 1 = 0.9987 - 0.9772 = 0.0215.P(-2 < Z < 2) = p-value of Z = 2 - p-value of Z = -2 = 0.9772 - 0.0228 = 0.9544P(Z > 0.5) = 1 - p-value of Z = 0.5 = 1 - 0.6915 = 0.3085.More can be learned about the normal distribution at https://brainly.com/question/25800303
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Which is correct answer?
a
b
c
When g be continuous on [1,6], where g(1) = 18 and g(6): = 11. Does a value 1 < c < 6 exist such that g(c) = 12
Yes, because of the intermediate value theoremWhat is intermediate value theorem?The intermediate value theorem is a fundamental theorem in calculus that states that if a continuous function f(x) is defined on a closed interval [a, b], and if there exists a number y between f(a) and f(b), then there exists at least one point c in the interval [a, b] such that f(c) = y.
According to the intermediate value theorem,
since g(x) is a continuous function on the closed interval [1, 6]
since g(1) = 18 is greater than 12, and
g(6) = 11 is less than 12,
there must be at least one value c between 1 and 6 where g(c) = 12.
Therefore, we can conclude that a value of c does exist such that g(c) = 12.
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Solve for the short leg of the 30-60-90 triangle.
Answer:
2
Step-by-step explanation:
The basic 30-60-90 triangle ratio is:
Side opposite the 30° angle: x
Side opposite the 60° angle: x√3
Side opposite the 90° angle: 2x
Here, the side opposite the 90° angle is 4.
This means that 2x = 4 and, thus, x = 2.
Since b is the side opposite the 30° angle, b = x, so it is 2.
Suppose the current cost of gasoline is $2.93 per gallon. Find the current price index number, using the 1975 price of 56.7 cents as the reference value.
Answer:
Step-by-step explanation:
To find the current price index number using the 1975 price of 56.7 cents as the reference value, we can use the formula:
Price Index = (Current Price / Base Price) x 100
Where "Current Price" is the current cost of gasoline, and "Base Price" is the 1975 price of 56.7 cents.
Substituting the values given in the problem, we get:
Price Index = ($2.93 / $0.567) x 100
Price Index = 516.899
Therefore, the current price index number, using the 1975 price of 56.7 cents as the reference value, is 516.899.
If m∠ADB = 110°, what is the relationship between AB and BC? AB < BC AB > BC AB = BC AB + BC < AC
The relationship between AB and BC is given as follows:
AB > BC.
What are supplementary angles?Two angles are defined as supplementary angles when the sum of their measures is of 180º.
The supplementary angles for this problem are given as follows:
<ADB = 110º. -> given<CDB = 70º. -> sum of 180º.By the law of sines, we have that:
AB/sin(110º) = BC/sin(70º).
As sin(110º) > sin(70º), the inequality for this problem is given as follows:
AB > BC.
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Answer:
AB>BC
Step-by-step explanation:
AI-generated answer
Based on the given information, the relationship between AB and BC depends on the measure of angle ZADB. If mZADB is 110°, we can determine the relationship as follows:
Since triangle ABD and triangle CBD share side AB, the larger the angle ZADB, the longer the side AB will be compared to side BC. Therefore, if mZADB is 110°, we can conclude that AB is greater than BC.
In summary, when mZADB is 110°, the relationship between AB and BC is:
AB > BC.
Consider the function h(x) = a(−2x + 1)^5 − b, where a does not=0 and b does not=0 are constants.
A. Find h′(x) and h"(x).
B. Show that h is monotonic (that is, that either h always increases or remains constant or h always decreases or remains constant).
C. Show that the x-coordinate(s) of the location(s) of the critical points are independent of a and b.
Answer:
A. To find the derivative of h(x), we can use the chain rule:
h(x) = a(-2x + 1)^5 - b
h'(x) = a * 5(-2x + 1)^4 * (-2) = -10a(-2x + 1)^4
To find the second derivative, we can again use the chain rule:
h''(x) = -10a * 4(-2x + 1)^3 * (-2) = 80a(-2x + 1)^3
B. To show that h is monotonic, we need to show that h'(x) is either always positive or always negative. Since h'(x) is a multiple of (-2x + 1)^4, which is always non-negative, h'(x) is always either positive or negative depending on the sign of a. If a > 0, then h'(x) is always negative, which means that h(x) is decreasing. If a < 0, then h'(x) is always positive, which means that h(x) is increasing.
C. To find the critical points, we need to find where h'(x) = 0:
h'(x) = -10a(-2x + 1)^4 = 0
-2x + 1 = 0
x = 1/2
Thus, the critical point is at x = 1/2. This value is independent of a and b, as neither a nor b appear in the calculation of the critical point.
A baseball team has home games on Thursday and Sunday. The two games together earn $4064.50 for the team. Thursday's game generates $400.50 less than Sunday's game. How much money
was taken in at each game?
The Sunday game brought in $2232.50, while the Thursday game brought in $1832.00.
What does this gain and loss mean?A company's income, costs, and profit are compiled in a profit and loss (P&L) statement, a financial report. It provides information to investors and other interested parties about a company's operations and financial viability.
The issue informs us that the combined revenue from the two games was $4064.50.
S + (S - 400.50) = 4064.50
Simplifying the left side, we get:
2S - 400.50 = 4064.50
Adding 400.50 to both sides, we get:
2S = 4465
Dividing both sides by 2, we get:
S = 2232.50
So the Sunday game generated $2232.50, and the Thursday game generated $2232.50 - $400.50 = $1832.00.
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Use the graphs shown in the figure below. All have the form f(x) = abª. Which graph has the smallest value for b?
Graph D of the given function has the smallest value for b.
Exponential Function: What Is It?As per name signifies, exponents are used in exponential functions. But take note that an exponential function does not have a constant as its base and a variable as its exponent. One of the following forms can be used for an exponential function.
f (x) = aˣ
According to the graph,y=f(x) >0
f(x)=abˣ , where a>0
So, f(x)=abˣ
When, b<1 f(x) decreases
When, b>1 f(x) increases and the larger the b the steeper the graph
So, graph of D is increasing and is steepest
So, graph D has the smallest value for b.
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Use the parabola tool to graph the quadratic function f(x) = -√² +7.
Graph the parabola by first plotting its vertex and then plotting a second point on the parabola HELP ME PLEASEEE
Using the two points you have plotted, draw the parabola. It should look like a downward-facing curve opening at the vertex (0, 7).
What is parabola?
A parabola is a symmetrical, U-shaped curve that is formed by the graph of a quadratic function.
Assuming you meant [tex]f(x) = -x^2 + 7[/tex], here's how you can graph the parabola using the parabola tool:
Find the vertex
The vertex of the parabola is located at the point (-b/2a, f(-b/2a)), where a is the coefficient of the [tex]x^2[/tex] term and b is the coefficient of the x term. In this case, a = -1 and b = 0, so the vertex is located at the point (0, 7).
Plot the vertex
Using the parabola tool, plot the vertex at the point (0, 7).
Plot a second point
To plot a second point, you can choose any x value and find the corresponding y value using the quadratic function. For example, if you choose x = 2, then [tex]f(2) = -2^2 + 7 = 3[/tex]. So the second point is located at (2, 3).
Therefore, Using the two points you have plotted, draw the parabola. It should look like a downward-facing curve opening at the vertex (0, 7).
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Complete Question:
Use the parabola tool to graph the quadratic function.
f(x) = -√² +7
Graph the parabola by first plotting its vertex and then plotting a second point on the parabola.
Can someone solve this
Note: in dark pen is the questions to solve in light pencil is my answer probably are wrong
The open circle at 3 indicates that 3 is not included in the solution set. This inequality can be read as "X is less than 5" or "X is strictly less than 5."
What is expression?In mathematics, an expression is a combination of numbers, symbols, and operators that represents a value. Expressions can be as simple as a single number or variable, or they can be complex combinations of mathematical operations. For example, 2 + 3 is a simple expression that represents the value 5, while (2 + 3) x 4 - 1 is a more complex expression that represents the value 19. Expressions can be evaluated or simplified using the rules of arithmetic and algebra.
Here,
1. Simplify:
3(4x-2)+ 7X (2-1) + 4 (6+4)+(-8)
Multiplying inside the parentheses first:
12x - 6 + 7x + 4 + 40 - 8
Combining like terms:
19x + 30
Final answer: 19x + 30
2. Graph:
3 > X
This is a simple inequality in one variable (X). To graph it on a number line, we first draw a dot at 3 (since the inequality is strict), and then shade all values less than 3:
<=========o---
The open circle at 3 indicates that 3 is not included in the solution set.
3. Write the inequality:
X < 5
This is a simple inequality in one variable (X). The inequality sign is "less than," and the number on the right-hand side is 5. This inequality can be read as "X is less than 5" or "X is strictly less than 5."
4. Solve for x:
3x - 7 = 42
Adding 7 to both sides to isolate the variable:
3x = 49
Dividing both sides by 3 to solve for x:
x = 16.33 (rounded to two decimal places)
Final answer: x = 16.3
5. Find 32% of $542.50:
To find 32% of $542.50, we can use the formula:
percent * amount = part
where "percent" is the percentage expressed as a decimal, "amount" is the whole amount, and "part" is the result we're looking for.In this case, we have:
0.32 * $542.50 = part
Multiplying:
$173.60 = part
Final answer: $173.60
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I need help with this
Answer:
(x -14)² +(y -7)² = 1²
Step-by-step explanation:
You want the equation of the circle that represents the border of a logo centered 14 m right and 7 m up from the lower left corner of a soccer field. The logo is 2 m in diameter.
Equation of a circleThe equation of a circle with center (h, k) and radius r is ...
(x -h)² +(y -k)² = r²
Since the origin of the coordinate system is the lower left corner of the field, the center is located at (h, k) = (14, 7). The diameter of 2 m means the radius is 1 m. Using these values in the equation, it becomes ...
(x -14)² +(y -7)² = 1²
2 cities are 210 miles apart. If the distance on the map is 3 1/4 inches, find the scale of the map
The scale of the map = 682.5.
How would you define distance in one sentence?We kept a safe distance and followed them. She perceives a separation between her and her brother that wasn't there before. Although they were previously close friends, there was now a great deal of gap between them.
We must calculate the ratio of the distance shown on the map to the real distance between the cities in order to ascertain the scale of the map.
We are aware that there are 210 miles separating the two cities. Let x represent the precise location of this distance on the map. From that, we may establish the ratio:
Actual distance / Map Distance = 210 / x
The distance on the map is indicated as 3 1/4 inches, which is also known as 13/4 inches. When we enter this into the percentage, we obtain:
Actual distance divided by (13/4) = 210 / x
We can cross-multiply and simplify to find x's value:
Actual distance: 682.5 = x * 210 x = 3.25 when 210 * (13/4) Equals x.
Consequently, 3.25 inches on the map represent the actual distance between the cities. We can write: To determine the map's scale:
Actual distance divided by 1 inch on the chart equals 210 miles.
When we replace the values we discovered earlier, we obtain:
1 / 210 = 3.25 / scale
If we solve for the scale, we obtain:
scale = 682.5.
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The breadth of a rectangular playground is 5m shorter than its length. If its perimeter is 130m,find ids length and breadth.
Answer:
Length is 35 m and breadth is 30 mStep-by-step explanation:
Given,
The breadth of a rectangular playground is 5m shorter than its length.Perimeter is 130 mLet length be x and breadth (x - 5).
Perimeter of rectangle is calculated by :
[tex] \: \: \boxed{ \pmb{ \sf{Perimeter_{(rectangle)} = 2(l + b)}}} \\ [/tex]
On substituting the values we get :
[tex]\dashrightarrow \: \: 130 = 2(x + x - 5) \\ [/tex]
[tex]\dashrightarrow \: \: 130 = 2(2x - 5) \\ [/tex]
[tex]\dashrightarrow \: \dfrac{130}{2} = (2x - 5) \\ [/tex]
[tex]\dashrightarrow \: \: 65 = 2x - 5 \\ [/tex]
[tex]\dashrightarrow \: \: 65 + 5 = 2x \\ [/tex]
[tex]\dashrightarrow \: \: 70 = 2x \\ [/tex]
[tex]\dashrightarrow \: \: \frac{70}{2} = x \\ [/tex]
[tex]\dashrightarrow \: \: 35 = x \\ [/tex]
Hence,
Length = x = 35 m.Breadth = x -5 = (35 -5) = 30 mYou have a map that is missing a scale. The distance from Point A to Point B is
five inches on the map, and after driving it, you know it is 250 miles in reality.
The scale of the map in the question is 1 inch = 50 miles.
What is the scale of the map?A scale in a map is a relation that tells us how many units each unit in the map represents. In this case, we know that the distance between two points A and B on the map is 5 inches, while the actual distance between these two places is 250 miles.
Then we start with the relation:
5 inches = 250 miles.
But to get the scale of the map we need to see how many miles one inch represents in the map, then we can divide both sides of the equation by 5 to geT:
5 in = 250 mi
1 in = 250mi/5
1 in = 50 mi
The scale of the map is 1 inch to 50 miles.
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Which expressions are equivalent to 8(3/4y -2)+6(-1/2+4)+1
Answer: 6y + 6
Step-by-step explanation:
To simplify the expression 8(3/4y -2) + 6(-1/2+4) + 1, we can follow the order of operations (PEMDAS):
First, we simplify the expression within parentheses, working from the inside out:
6(-1/2+4) = 6(7/2) = 21
Next, we distribute the coefficient of 8 to the terms within the first set of parentheses:
8(3/4y -2) = 6y - 16
Finally, we combine the simplified terms:
8(3/4y -2) + 6(-1/2+4) + 1 = 6y - 16 + 21 + 1 = 6y + 6
Therefore, the expression 8(3/4y -2) + 6(-1/2+4) + 1 is equivalent to 6y + 6.
A type of wood has a density of 250 kg/m3. How many kilograms is 75,000 cm3 of the wood? Give your answer as a decimal.
Find all relative extrema of the function. Use the Second-Derivative Test when applicable. (If an answer does not exist, enter DNE.) f (x) = x^4 ? 8x^3 + 4relative minimum (x, y) =( )relative maximum(x, y) =( )
The relative maximum of the function is (0, 4), and the relative minimum is (6, -152).
To find the relative extrema of the function f(x) = x^4 - 8x^3 + 4, we first take the derivative of the function:
f'(x) = 4x^3 - 24x^2
Then we set f'(x) = 0 to find the critical points:
4x^3 - 24x^2 = 0
4x^2(x - 6) = 0
This gives us two critical points: x = 0 and x = 6.
Next, we find the second derivative of f(x):
f''(x) = 12x^2 - 48x
We can use the Second-Derivative Test to determine the nature of the critical points.
For x = 0, we have:
f''(0) = 0 - 0 = 0
This tells us that the Second-Derivative Test is inconclusive at x = 0.
For x = 6, we have:
f''(6) = 12(6)^2 - 48(6) = 0
Since the second derivative is zero at x = 6, we cannot use the Second-Derivative Test to determine the nature of the critical point at x = 6.
To determine whether the critical points are relative maxima or minima, we can use the first derivative test or examine the behavior of the function around the critical points.
For x < 0, f'(x) < 0, so the function is decreasing.
For 0 < x < 6, f'(x) > 0, so the function is increasing.
For x > 6, f'(x) < 0, so the function is decreasing.
Therefore, we can conclude that the critical point at x = 0 is a relative maximum and the critical point at x = 6 is a relative minimum.
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Find the generating functions and the associated sequences of: (x+4) ^ 4
Using binomial theorem, the generating function is G(x) = x^4 + 16x^3 + 96x^2 + 256x + 256 while the associated sequence of (x+4)^4 is {1, 16, 96, 256, 256}.
What is the generating functions and associated sequences of the functionTo find the generating function of (x+4)^4, we expand it using the binomial theorem:
[tex](x+4)^4 = C(4,0)x^4 + C(4,1)x^3(4) + C(4,2)x^2(4^2) + C(4,3)x(4^3) + C(4,4)(4^4)[/tex]
where C(n,k) denotes the binomial coefficient "n choose k".
Simplifying the terms, we get:
[tex](x+4)^4 = x^4 + 16x^3 + 96x^2 + 256x + 256[/tex]
Therefore, the generating function of (x+4)^4 is:
[tex]G(x) = x^4 + 16x^3 + 96x^2 + 256x + 256[/tex]
The associated sequence can be read off by finding the coefficients of each power of x:
The coefficient of x^k is the k-th term of the sequence.In this case, the sequence is given by the coefficients of G(x):a₀ = 256a₁ = 256a₂ = 96a₃ = 16a₄ = 1To find the generating function of (x+4)^4, we expand it using the binomial theorem:
(x+4)^4 = C(4,0)x^4 + C(4,1)x^3(4) + C(4,2)x^2(4^2) + C(4,3)x(4^3) + C(4,4)(4^4)
where C(n,k) denotes the binomial coefficient "n choose k".
Simplifying the terms, we get:
(x+4)^4 = x^4 + 16x^3 + 96x^2 + 256x + 256
Therefore, the generating function of (x+4)^4 is:
G(x) = x^4 + 16x^3 + 96x^2 + 256x + 256
The associated sequence can be read off by finding the coefficients of each power of x:
The coefficient of x^k is the k-th term of the sequence.
In this case, the sequence is given by the coefficients of G(x):
a₀ = 256
a₁ = 256
a₂ = 96
a₃ = 16
a₄ = 1
Therefore, the associated sequence of (x+4)^4 is {1, 16, 96, 256, 256}.
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factorise completely[tex]3x²-12xy
Answer:
3x(x - 4y)
Step-by-step explanation:
3x² - 12xy ← factor out 3x from each term
= 3x(x- 4y)
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Find the missing length indicated
Step-by-step explanation:
4)
based on similar triangles and the common ratio for all pairs of corresponding sides we know
LE/LM = LD/LK = DE/EM
because E and D are the midpoints of the longer sides, all of these ratios are 1/2.
1/2 = DE/8
8/2 = 4 = DE
5)
same principle as for 4)
BQ/BA = BR/BC = QR/AC
again, Q and R are the midpoints, so all these ratios are 1/2.
1/2 = QR/10
QR = 10/2 = 5
In an examination,x pupils take the history paper and 3x take the mathematics paper. A. illustrate the data on a venn diagram indicating the number of pupils I'm each region.
B. if the number of pupils taken the examination is 46, find the value of x
If we round up, we get x = 12, which means that 12 students took history and 36 students took mathematics.
What is venn diagram?A Venn diagram is a graphical representation of sets, often used to show relationships between different sets of data. It consists of one or more circles, where each circle represents a set. The circles are usually overlapping to show the relationships between the sets. The region where the circles overlap represents the elements that belong to both sets. The non-overlapping parts of each circle represent the elements that belong to only one of the sets.
Here,
A. To illustrate the data on a Venn diagram, we need to draw two overlapping circles, one for history and one for mathematics. We can label the regions as follows:
The region where the circles overlap represents the students who took both history and mathematics.
The region outside both circles represents the students who did not take either history or mathematics.
The region within the history circle but outside the mathematics circle represents the students who took history but not mathematics.
The region within the mathematics circle but outside the history circle represents the students who took mathematics but not history.
In this diagram, let's assume that x students took history and 3x students took mathematics. Then the total number of students who took the examination is x + 3x = 4x. We can label the regions on the diagram accordingly:
The region where the circles overlap represents the students who took both history and mathematics. Since there are 3x students who took mathematics, and all of them are included in the overlap region, the number of students who took both is 3x.
The region outside both circles represents the students who did not take either history or mathematics. Since there are 46 students in total, and 4x of them took the examination, the number of students who did not take either is 46 - 4x.
The region within the history circle but outside the mathematics circle represents the students who took history but not mathematics. Since x students took history, and 3x took mathematics, the number of students who took history but not mathematics is x - 3x = -2x. However, since we cannot have a negative number of students, we can assume that this region is empty.
The region within the mathematics circle but outside the history circle represents the students who took mathematics but not history. Since there are 3x students who took mathematics, and some of them also took history, the number of students who took mathematics but not history is 3x - 3x = 0. Therefore, this region is also empty.
B. We know that the total number of students who took the examination is 46. Therefore, we have:
x + 3x = 46
4x = 46
x = 11.5
However, since x represents the number of students who took history, it must be a whole number. Therefore, we can round x up or down to the nearest whole number. If we round down, we get x = 11, which means that 11 students took history and 33 students took mathematics.
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find an ordered pair (x, y) that is a solution to the equation. -x+6y=7
Step-by-step explanation:
(-1, 1) is a solution.
because
-(-1) + 6×1 = 7
1 + 6 = 7
7 = 7
correct.
every ordered pair of x and y values that make the equation true is a solution.
(5, 2) would be another solution. and so on.
35% of households say they would feel secure if they had 50000 in savings he randomly selected 8 households and ask them if they would feel secure if they had 50000 in savings find the probability that the number that say that they would feel secure a exactly 5B more than 5 &c at most 5
Probability that precisely 5 people will respond that they would feel comfortable is 0.0808
Probability that more than 5 people will respond that they would feel comfortable is0.1061
Probability that at most 5 people will respond that they would feel comfortable is 0.9747
Probability Definition in MathProbability is a way to gauge how likely something is to happen. Several things are difficult to forecast with absolute confidence.
Solving the problem:35 percent of households claim that having $50,000 in savings would make them feel comfortable. Ask 8 homes that were chosen at random if they would feel comfortable if they had $50,000 in savings.
Binomial conundrum with p(secure) = 0.35 and n = 8.
the likelihood that the number of people who claim they would feel comfortable is
(a) The number exactly five is equal to ⁸C₅ (0.35)5×(0.65)×3=binompdf(8,0.35,5) = 0.0808.
(b) more than five = 1 - binomcdf(8,0.35,4) = 0.1061
(c) at most five = binomcdf(8,0.35,5) = 0.9747.
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A bank requires that the Dotkoms pay their homeowner's insurance, property taxes, and
mortgage in one monthly payment to the bank. If their monthly mortgage payment is $1,711.22,
their semi-annual property tax bill is $3,239, and their annual homeowner's insurance bill is
$980, how much do they pay the bank each month?
Answer: $2,162.06
Step-by-step explanation:
To calculate the total monthly payment to the bank, we need to add up the monthly mortgage payment, the monthly portion of the semi-annual property tax bill, and the monthly portion of the annual homeowner's insurance bill.
First, we need to find the monthly portion of the semi-annual property tax bill. To do this, we divide the semi-annual property tax bill by 6 (since there are 6 months in half a year):
Monthly property tax payment = Semi-annual property tax bill / 6
Monthly property tax payment = $3,239 / 6
Monthly property tax payment = $539.83
Next, we need to find the monthly portion of the annual homeowner's insurance bill. To do this, we divide the annual homeowner's insurance bill by 12 (since there are 12 months in a year):
Monthly homeowner's insurance payment = Annual homeowner's insurance bill / 12
Monthly homeowner's insurance payment = $980 / 12
Monthly homeowner's insurance payment = $81.67
Now we can add up the monthly mortgage payment, the monthly property tax payment, and the monthly homeowner's insurance payment to find the total monthly payment to the bank:
Total monthly payment = Monthly mortgage payment + Monthly property tax payment + Monthly homeowner's insurance payment
Total monthly payment = $1,711.22 + $539.83 + $81.67
Total monthly payment = $2,332.72
Therefore, the Dotkoms pay the bank $2,332.72 each month.
Answer:
Step-by-step explanation:
Using proportions, it is found that they pay the bank $2332.72 each month.
What is a proportion?
A proportion is a fraction of a total amount.
Using proportions, it is found that they pay the bank $2332.72 each month.
What is a proportion?
A proportion is a fraction of a total amount.
Their payments are given by:
Monthly mortgage of $1,711.22.
Semi-annual property tax bill is $3,239, that is, it is paid every 6 months, hence 3239/6 = $539.83.
The rate at which a rumor spreads through a town of population N can be modeled by the equation dt/dx = kx(N−x) where k is a constant and x is the number of people who have heard the rumor. (a) If two people start a rumor at time t=0 in a town of 1000 people, find x as a function of t given k=1/250. (b) When will half the population have heard the rumor?
(a) The function x as a function of t is t = 250ln(499x/998)
(b) Half the population will have heard the rumor approximately 109.86 units of time after it was started.
(a) To solve the differential equation dt/dx = kx(N−x), we can separate the variables and integrate
dt/dx = kx(N−x)
dt/(N-x) = kx dx
Integrating both sides, we get
t = -1/k × ln(N-x) - 1/k × ln(x) + C
where C is the constant of integration.
To find C, we can use the initial condition that two people start the rumor at t=0, so x=2:
0 = -1/k * ln(N-2) - 1/k * ln(2) + C
C = 1/k * ln(N-2) + 1/k * ln(2)
Substituting C back into the equation, we get:
t = -1/k * ln(N-x) - 1/k * ln(x) + 1/k * ln(N-2) + 1/k * ln(2)
Simplifying, we get
t = 1/k * [ln((N-2)x/(2(N-x)))]
Substituting k=1/250 and N=1000, we get:
t = 250ln(499x/998)
(b) We want to find the time t when half the population has heard the rumor, so x = N/2 = 500. Substituting this into the equation we obtained in part (a), we get
t = 250ln(499(500)/998) = 250ln(249/499)
t ≈ 109.86
Therefore, half the population will have heard the rumor approximately 109.86 units of time after it was started.
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What is the difference between the longest and
shortest pieces of scrap wood?
The difference in length between the two pieces of scrap wood is 7/8 inches.
What is the difference between the longest and shortest pieces of scrap wood?
To get the difference we just need to take the difference between the two lenghs.
Remember that we only have pieces of scraph wood if we have an "x" over the correspondent value in the line diagram.
By looking at it we can see that the longest pice measures 5 inches, while the shortest one (there are two of these) measure (4 + 1/8) inches.
The difference is:
5 - (4 + 1/8) = 7/8
The longest piece is 7/8 inches longer.
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Decide if the function is an exponential growth function or exponential decay function, and describe its end behavior using
limits.
Y=(1/6) ^-x
Answer:
The given function is an exponential growth function, not an exponential decay function because as the exponent x increases, the value of y also increases instead of decreasing.
To describe its end behavior using limits, we need to find the limit of the function as x approaches infinity and as x approaches negative infinity.
As x approaches infinity, the exponent -x approaches negative infinity, and the base (1/6) is raised to increasingly larger negative powers, causing the function to approach zero. So, the limit as x approaches infinity is 0.
As x approaches negative infinity, the exponent -x approaches infinity, and the base (1/6) is raised to increasingly larger positive powers, causing the function to approach infinity. So, the limit as x approaches negative infinity is infinity.
Therefore, the end behavior of the function is that it approaches zero as x approaches infinity and approaches infinity as x approaches negative infinity.
Can anyone help thanks!!!!
Answer:
B
Step-by-step explanation:
5^2 is the small square, 4(3x4x1/2) are the 4 triangles
Answer: The answer would be B.
Step-by-step explanation:
Hello.
First, we know that the smaller square is 5, and to find the area of the big square, we need to square 5 to get the area. We also know that C wouldn't be a viable option, so, our only remaining choices are A and B. We know that without the smaller square, there are 4 triangles, and the Area of a Triangle is: 1/2*b*h. So, this also takes A out as an option as well. After this, you will have your answer as B; 5^2 + 4(3 * 4 * 1/2)
(Or, you could have found the Area of the Triangles, and realize that neither A, nor C have those options, making B the answer by default.)
Hope this helps, (and maybe brainliest?)
54.2 consider the competing species model, equaltion 54.1 sketch the phase plane and the trajectories of both population
To sketch the phase plane and trajectories of both populations in the competing species model, plot the population of one species on the x-axis and the population of the other species on the y-axis. Then, plot the isoclines and use them to determine the direction and stability of the population trajectories.
The competing species model is a system of two differential equations that describe the population dynamics of two species competing for the same resources. To sketch the phase plane and trajectories, plot the population of one species on the x-axis and the population of the other species on the y-axis. Then, plot the isoclines, which are curves that represent the values of one species' population at which the other species' population does not change.
The isoclines are found by setting each differential equation to zero and solving for one population in terms of the other. For example, the isocline for species 1 is found by setting dN1/dt = 0 and solving for N2. The resulting equation gives the values of N2 at which the population of species 1 does not change. Plotting these curves on the phase plane divides it into regions where the population of each species increases or decreases.
The direction and stability of the population trajectories can be determined by analyzing the slope of the vector field, which represents the rate of change of the population at each point in the phase plane. Trajectories move in the direction of the vector field, and their stability depends on the curvature of the isoclines. If the isoclines intersect at a single point, it is a stable equilibrium where both populations coexist. If they intersect at multiple points, the stable equilibrium depends on the initial conditions of the populations. If they do not intersect, one species will eventually drive the other to extinction.
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--The question is incomplete, answering to the question below--
"Consider the competing species model, how to sketch the phase plane and the trajectories of both population"
