Answer:
Rounded to three significant figures:
(a) [tex]2 \times 575\; \rm nm = 1150\; \rm nm = 1.15\times 10^{-6}\; \rm m[/tex].
(b) [tex]\displaystyle \left(1 + \frac{1}{2}\right) \times (575\;\rm nm) \approx 863\; \rm nm = 8.63\times 10^{-7}\; \rm m[/tex].
Explanation:
Consider a double-slit experiment where a wide beam of monochromatic light arrives at a filter with a double slit. On the other side of the filter, the two slits will appear like two point light sources that are in phase with each other. For each point on the screen, "path" refers to the length of the segment joining that point and each of the two slits. "Path difference" will thus refer to the difference between these two lengths.
Let [tex]k[/tex] denote a natural number ([tex]k \in \left\lbrace0,\, 1,\, 2,\, \dots\right\rbrace[/tex].) In a double-split experiment of a monochromatic light:
A maximum (a bright fringe) is produced when light from the two slits arrive while they were in-phase. That happens when the path difference is an integer multiple of wavelength. That is: [tex]\text{Path difference} = k\, \lambda[/tex].Similarly, a minimum (a dark fringe) is produced when light from the two slits arrive out of phase by exactly one-half of the cycle. For example, The first wave would be at peak while the second would be at a crest when they arrive at the screen. That happens when the path difference is an integer multiple of wavelength plus one-half of the wavelength: [tex]\displaystyle \text{Path difference} = \left(k + \frac{1}{2}\right)\cdot \lambda[/tex].MaximaThe path difference is at a minimum (zero) at the center of the screen between the two slits. That's the position of the first maximum- the central maximum, a bright fringe where [tex]k = 0[/tex] in [tex]\text{Path difference} = 0[/tex].
The path difference increases while moving on the screen away from the center. The first order maximum is at [tex]k = 1[/tex] where [tex]\text{Path difference} = \lambda[/tex].
Similarly, the second order maximum is at [tex]k = 2[/tex] where [tex]\text{Path difference} = 2\, \lambda[/tex]. For the light in this question, at the second order maximum: [tex]\text{Path difference} = 2\, \lambda = 2 \times 575\; \rm nm = 1.15\times 10^{-6}\; \rm m[/tex].
Central maximum: [tex]k = 0[/tex], such that [tex]\text{Path difference} = 0[/tex].First maximum: [tex]k = 1[/tex], such that [tex]\text{Path difference} = \lambda[/tex].Second maximum: [tex]k = 2[/tex], such that [tex]\text{Path difference} = 2\, \lambda[/tex].MinimaThe dark fringe closest to the center of the screen is the first minimum. [tex]\displaystyle \text{Path difference} = \left(0 + \frac{1}{2}\right)\cdot \lambda = \frac{1}{2}\, \lambda[/tex] at that point.
Add one wavelength to that path difference gives another dark fringe- the second minimum. [tex]\displaystyle \text{Path difference} = \left(1 + \frac{1}{2}\right)\cdot \lambda[/tex] at that point.
First minimum: [tex]k =0[/tex], such that [tex]\displaystyle \text{Path difference} = \frac{1}{2}\, \lambda[/tex].Second minimum: [tex]k =1[/tex], such that [tex]\displaystyle \text{Path difference} = \left(1 + \frac{1}{2}\right)\cdot \lambda[/tex].For the light in this question, at the second order minimum: [tex]\displaystyle \text{Path difference} = \left(1 + \frac{1}{2}\right)\cdot \lambda = \left(1 + \frac{1}{2}\right)\times (575\; \rm nm) \approx 8.63\times 10^{-7}\; \rm m[/tex].
You have a cup with 50cm filled with water. How much pressure will the water act on the bottom of the cup? The density of water is 1000kg/m^3 and g = 10N/kg
Answer:
5000 N/m².
Explanation:
The following data were obtained from the question:
Density (d) = 1000 kg/m³
Acceleration due to gravity (g) = 10 N/kg
Height (h) = 50 cm = 50/100 = 0.5 m
Pressure (P) =.?
Pressure is related to density and height by the following equation:
P = dgh
Where
P is the pressure.
d is the density.
g is the acceleration due to gravity.
h is the height.
With the above formula, we can obtain the pressure at the bottom of the cup as follow:
P = dgh
P = 1000 x 10 x 0.5
P = 5000 N/m²
Therefore, the pressure at bottom of the cup is 5000 N/m².
A body decelerates uniformly to a constant speed and after some time it accelerates uniformly Draw the shape of speed time graph for such a motion . Label the three sections of this graph. What is the quantity which is measured by the area occupied under speed time graph ?
Answer:
here I am just giving an idea of how the graph will be like ...
In the pic..
Hope it helped u if yes mark me BRAINLIEST!
Tysm!
:)
A construction worker uses an electrical device to attract fallen nails and sharp objects
from a construction site. What is causing the attraction of the metal objects?
O An electrical wave oscillating perpendicular to the electrical device.
O An electrical charge radiating perpendicular to the wire
O Amagnetic wave radiating perpendicular to an electrical device
O A magnetic wave and electrical current moving in opposite directions
Answer:
is the last one, a magnetic wave and electrical current moving in opposite directions
Explanation:
opposite directions always attract in magnetic waves and fields
A long, straight, horizontal wire carries a left-to-right current of 40 A. If the wire is placed in a uniform magnetic field of magnitude 3.7 ✕ 10−5 T that is directed vertically downward, what is the resultant magnitude of the magnetic field 22 cm above the wire (in T)?
Answer:
The magnitude of the resultant of the magnetic field is [tex]4.11\times10^{-5}\ T[/tex]
Explanation:
Given that,
Current = 40 A
Magnetic field [tex]B=3.7\times10^{-5}\ T[/tex]
Distance = 22 cm
We need to calculate the magnetic field
Using formula of magnetic field
[tex]B'=\dfrac{\mu_{0}I}{2\pi r}[/tex]
Where, r = distance
I = current
Put the value into the formula
[tex]B'=\dfrac{4\pi\times10^{-7}\times20}{2\pi\times0.22}[/tex]
[tex]B'=1.8\times10^{-5}\ T[/tex]
We need to calculate the magnitude of the resultant of the magnetic field
Using formula of resultant
[tex]B''=\sqrt{B^2+B'^2}[/tex]
Put the value into the formula
[tex]B''=\sqrt{(3.7\times10^{-5})^2+(1.8\times10^{-5})^2}[/tex]
[tex]B''=4.11\times10^{-5}\ T[/tex]
Hence, The magnitude of the resultant of the magnetic field is [tex]4.11\times10^{-5}\ T[/tex]
What did Bohr's model of the atom include that Rutherford's model did not have?
a nucleus
energy levels
electron clouds
smaller particles
Answer:
The correct option is energy levels
Explanation:
Rutherford's model of an atom suggests that an atom has a tiny positively charged central mass (now called the nucleus) which is surrounded by electrons (negatively charged) in a cloud-like manner.
Bohr's model went a bit further than the Rutherford's model in describing an atom by suggesting that the electrons which surrounds in the nucleus travel in fixed circular orbits. This description by Bohr was able to describe the energy levels of orbitals which assumes that smallest orbitals have the lowest energy while the largest orbitals have the highest energy.
Answer:
energy levels
hope this helped!
Explanation:
What is pin hole camera?
Answer:
Explanation:
Pinhole camera is a simple camera. It does not have a lens. The light passes from a hole and an inverted image is formed on the opposite side of the box.
Write the relation between:
1) applied force and pressure.
2) surface area of contact and pressure.
realtion between applied force.and pressure is more force exerts more pressure whereas less force exerts less pressure
confused in another one
Answer:
See below
Explanation:
1) Applied Force and Pressure
Pressure = Force / Area
This shows that Applied force and pressure are in direct relationship. This means that If the Applied force is more, the Pressure is also More and vice versa.
2) Surface Area of Contact and Pressure
Pressure = Force / Surface Area of Contact
This shows that Pressure and Surface area of contact are inversely related. This means that if pressure is increased on an object, the surface area of contact decreases and vice versa.
Select the correct answer. Rita is a registered dietician. What does her work entail? A. prescribing medication for clients B. cooking healthy meals for students C. demonstrating how to use gym equipment D. making recommendations for healthy eating habits
Answer:
D
Explanation:
The answer is D because:
A) Only doctors are allowed to prescribe medications.
B) Rita is not a chef/cook.
C) Rita is not a personal trainer
D) The job of a dietican is to provide reccomendations to their clients in order for them to implement a healthy lifestyle via consuming what is best for them.
Hope this helps :)
Answer:
D.) Making recommendations for healthy eating habits
Explanation: PLATO :)))
Is the ultraviolet ray monochromatic or polychromatic?
Answ
In real world application Ultraviolet is not a color as it it can’t be seen by the human eye. It is a high frequency part of the Suns electromagnetic radiation. Even though UltraViolet sounds like a color, the Ultra in this case signifies that it is beyond Violet and thus beyond the visible part of the electromagnetic spectrum. They are not depicted with a color on spectrum charts, since we can’t see it we can’t truly classify it as a color no more than can we equate the other parts of the spectrum like XRays, Gamma Rays and Radio Waves with colors. These and other non-visible parts of the spectrum are measured instead with wavelengths. So the answer is no they would not be monochromatic, or any color at all.
Red, Orange, Yellow, Green, Blue, Indigo and Violet are the visible colors of the electromagnetic spectrum. They, combined together are called white light and our atmosphere acts like a prism to divide them into separate and apparently distinct colors. Outside the visible Red you have Infrared which is invisible to the human eye and is the heat we feel from the sun. Outside the Violet end of the visible spectrum is where UVA, UVB and UVC are found, and these are the eye and skin damaging rays. UV rays are also invisible to the human eye (but visible to certain birds of prey such as raptors
Explanation:
Which is one use for radioactive isotopes? sanitation architecture meteorology archaeology
Answer:
Archaeology
Explanation:
Radioisotopes are radioactive atoms of an element in which their atoms contain excess energy making them unstable. When broken down they become more stable releasing radiations.
Carbon 14 is a radioactive isotope that is used in archaeology to study and estimate the lifespan and age of organic materials such as wood, leather. Carbon 14 can be used to estimate the ages of materials up to 50000 to 60000 years.
Answer:
archaeology
Explanation:
what is SI unit System ? why has SI system been developed ? Give reasons
Explanation:
SI is the international system of units
It was developed to express magnitudes and quantities
The transmutation of a radioactive uranium isotope, 234/92U , into a radon isotope, 222/86Rn , involves a series of three nuclear reactions. At the end of the first reaction, a thorium isotope,230/90Th , is formed and at the end of the second reaction, a radium isotope, 226/88Ra , is formed. In both the reactions, an alpha particle is emitted. Write the balanced equations for the three successive nuclear reactions.
Answer:
See explanation below
Explanation:
234/92U--------> 230/90Th + 4/2He
230/90Th----->226/88Ra + 4/2He
There are various modes of radioactive decay. One of them is alpha decay.
Alpha decay involves the loss of an alpha particle from a nucleus. When this occurs, the mass number of the daughter nucleus is four units less than that of the parent while the atomic number of the daughter nucleus is two units less than that of its parent as shown in the equations above.
An alpha particle is akin to a helium nucleus in terms of mass and charge
I need help pls now plleeeeeeeeaaassseeeee
Answer:
[tex]r = \frac{v}{i} = v = ri \\ i = \frac{v}{r} [/tex]
A high-voltage powerline operates at 500000 V-rms and carries an rms current of 500 A. If the resistance of the cable is 0.050Ω/km, what is the resistive power loss in 200 km of the powerline?
Answer:
2,500,000W or 2.5MW
Explanation:
The power lost due to resistance is given by I^2R. We must first obtain R as follows;
Resistance per kilometer= 0.050Ω/km
Distance covered= 200km
R = 200km x 0.050Ω/km = 10Ω
The lost power as a 500A current passes through the powerline is:
P = I²R
P= 500² x 10
P= 2,500,000 W or 2.5MW
The resistive power loss in 200 km of the powerline is of 2.5 MW.
Given data:
The root mean square voltage is, V' = 500000 V.
The magnitude of current through the power line is, I =500 A.
The magnitude of resistance of cable is, R = 0.050 Ω/km.
The length of powerline is, L = 200 km.
Whenever there is a flow of current through the wire, then there are various losses out of which the power loss is a major factor. The mathematical expression for the power loss is given as
P = I²R
Solving as,
P= 500² x 10
P= 2,500,000 W or 2.5MW
Thus, we can conclude that the resistive power loss in 200 km of the powerline is of 2.5 MW.
Learn more about the resistive power loss here:
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An atom of unknown element Z has mass number of 39 and an atomic number of 18. How many protons and how many neutrons are in this atom? Show your work
Answer:
proton:18
neutron:39-18=21
Can someone explain how the weight of the block is 10.26N, with reference to an appropriate law of motion?
this process is called parellelogram method of resolving vectors.
A fish inside the water 12cm below the surface looking up through the water sees the outside world contained in a circular horizon. If the refractive index of water is 4/3 the radius of circle is
Answer:
13.6 cm
Explanation:
From Snell's law:
n₁ sin θ₁ = n₂ sin θ₂
In the air, n₁ = 1, and light from the horizon forms a 90° angle with the vertical, so sin θ₁ = sin 90° = 1.
Given n₂ = 4/3:
1 = 4/3 sin θ
sin θ = 3/4
If x is the radius of the circle, then sin θ is:
sin θ = x / √(x² + 12²)
sin θ = x / √(x² + 144)
Substituting:
3/4 = x / √(x² + 144)
9/16 = x² / (x² + 144)
9/16 x² + 81 = x²
81 = 7/16 x²
x ≈ 13.6
A 0.149 kg glider is moving to the right on a frictionless, horizontal air track with a speed of 0.710 m/s . It has a head-on collision with a 0.308 kg glider that is moving to the left with a speed of 2.27 m/s . Suppose the collision is elastic.1. Find the magnitude of the final velocity of the 0.157kg glider.
2. Find the magnitude of the final velocity of the 0.306kg glider.
Answer:
v1 = −2.201946 m/s ( to the left)
v2 = 0.7780534 m/s ( to the right)
Explanation:
Given the following :
Mass of first glider (m1) = 0.149kg
Initial Speed of first glider (u1) = 0.710 m/s
Mass of second glider (m2) = 0.308kg
Initial Speed of second glider (u2) = 2.27m/s
For elastic collision:
m1u1 + mu2u2 = m1v1 + m2v2
Where V1 and v2 = final velocities if the body after collision.
Taking right as positive ; left as negative
u1 = 0.710m/s ; u2 = - 2.27m/s
u1 - u2 = - (v1 - v2)
0.710 - - 2.27 = - v1 + v2
v2 - v1 = 2.98 - - - - (1)
From:
m1u1 + mu2u2 = m1v1 + m2v2
(0.149 * 0.710) + ( 0.308 * - 2.27) = (0.149 * v1) + (0.308 * v2)
0.10579 + (-0.69916) = 0.149 v1 + 0.308v2
−0.59337 = 0.149 v1 + 0.308v2
Dividing both sides by 0.149
v1 + 2.067v2 = −0.59337 - - - - - (2)
From (1)
v2 = 2.98 + v1
v1 + 2.067(2.98 + v1) = −0.59337
v1 + 6.16 + 2.067v1 = −0.59337
3.067v1 = −0.59337 - 6.16
3.067v1 = −6.75337
v1 = −6.75337 / 3.067
v1 = −2.201946 m/s ( to the left)
From v2 = 2.98 + v1
v2 = 2.98 + (-2.201946)
v2 = 0.7780534 m/s ( to the right)
Light, heat, electricity, sound are examples of
Answer: Energy
Explanation: Light, heat, electricity, sound are examples of energy
One glass microscope slide is placed on top of another with their left edges in con- tact and a human hair under the right edge of the upper slide. As a result, a wedge of air exists between the slides. An interference pattern results when monochromatic light is incident on the wedge. What is observed at the left edge of the slides? a. A dark fringe b. A bright fringe c. Impossible to determine
Answer:
A dark fringe
¿Por qué una persona situada debajo de las ramas de un árbol ve caer una hoja con diferente tipo de movimiento que una persona que corre cerca del árbol?
Answer:
Therefore the laws of physics are the same for the two observers, whoever is standing under the tree observes a vertical movement of free fall.
The person who is running observes a movement parabolic
Explanation:
To answer this question we must establish that as two people have inertial reference systems from which to make their observations, the inertial systems are systems with constant velocity.
Therefore the laws of physics are the same for the two observers, whoever is standing under the tree observes a vertical movement of free fall.
The person who is running observes a movement parabolic composed of the vertical movement and horizontal movement ladies go running, therefore it is a parabolic movement
Traslate
Para responder eta pregunta debemos establecer que as dos personas tiene sistema de referencia inerciales de des donde realizar sus observación, los sistema inerciales son sistema con velocidad constante.
Por lo tanto las leyes de la fisica son la misma para los dos observadores, el que esta parado bajo el árbol observa un movimiento vertical de caída libre.
La persona que va corriendo observa un movimiento compuesto por el movimiento vertical y damas movimiento horizontal ir corriendo, por lo cual es un movimiento parabólico
do you think distance and time are relevant terms in describing motion?
Answer:
yes
Explanation:
because motion is relevant
Answer:
Motion is mathematically defined as displacement, distance, velocity, acceleration, speed, and time. The motion of a body is recognized by adding a frame of reference to an observer and measuring the change in position of the body related to that frame with the change in time.
PLS HELP ME Define Derived Quantities ?
Derived Quantities
Explanation: Those physical quantities which are derived from fundamental quantities are called derived quantities and their units are called derived units. e.g., velocity, acceleration, force, work etc.
Answer:
These are quantities calculated from two or more measurements
Explanation:
They can't me measured directly.
They can only be computed.
They are calculated in PHYSICAL SCIENCE.
hope it helps.
What form of energy does a block of chocolate have?
Answer:
Chemical Energy
Explanation:
A missile is moving 1350 m/s at a 25° angle it needs to hit a target 23,500 m away in a 55° direction in 10.2 seconds what is the magnitude of its final velocity
Answer:
3504 m/s
Explanation:
Let x be the horizontal component of distance
y - vertical component of distance
t-time
ax- horizontal component of acceleration
ay-Vertical component of acceleration
Vx-horizontal component of velocity
Vy-Vertical component of velocity
horizontally: x = V_x ×t + ½×a_x×t²
plugging the values we get
23500× cos 55º = 1350×cos25.0º × 10.20 + ½×a_x× (10.20)²
⇒ax = 19.2 m/s²
Moreover,
V'x = V_x + a_x×t = 1350×cos25.0º + 19.2×10.20= 1419 m/s
similarly in vertical direction:
y = V_y×t + ½×a_y×t²
23500×sin55º = 1350×sin25.0º×10.20s + ½×a_y×(10.20)²
⇒a_y = 258 m/s²
Also,
V'y = V_y + a_y×t = 1350×sin25.0º + 258×10.20 = 3204 m/s
Therefore
V = √(V'x² + V'y²) = 3504 m/s
therefore, magnitude of final velocity of missile=3504 m/s
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At what altitude the value of ‘g’ would become one fourth (¼)of the surface of the earth?
Answer:
Explanation:
For acceleration due to gravity g , the expression is
g = GM / R² , where G is gravitational constant M is mass of the earth and R is radius of the earth .
At height h , let the value of it becomes g / 4 , so
g / 4 = GM / ( R + h )²
dividing
4 = [( R+ h)² / R² ]
2 = (R + h) / R
2 = 1 + h / R
h / R = 1
h = R
So at height equal to radius of the earth , acceleration due to gravity becomes 1 /4 of value on the surface of the earth .
A charge (uniform linear density = 8.8 nC/m) lies on a string that is stretched along an x axis from x = 0 to x = 3.1 m. Determine the magnitude of the electric field at x = 5.2 m on the x axis.
Answer:
answer= 73.1256 [tex]i[/tex]
Explanation:
The electric charge linear density is equal to 8.8 x[tex]10^{-9}[/tex]
the length of the string is 3.1m
The magnitude of the electric field at the length of the string equal to 5.2 meters can be calculated with the formula ;
- E = λ / 4πε₀ [ [tex]l[/tex] / α ( α +
Solution:
E = 8.8 x[tex]10^{-9}[/tex] / 4πε₀ [ 3.1/ 5.2( 5.2 + 3.1) ] [tex]i[/tex]
= 1018.0995 [0.07183] [tex]i[/tex]
= 73.1256 [tex]i[/tex]
A mass, M, is at rest on a frictionless surface, connected to an ideal horizontal spring that is unstretched. A person extends the spring 30 cm from equilibrium and holds it at this location by applying a 10 N force. The spring is brought back to equilibrium and the mass connected to it is now doubled to 2M. If the spring is extended back 30 cm from equilibrium, what is the necessary force applied by the person to hold the mass stationary there
Answer:
The necessary force applied by the person to hold the mass stationary there is 10 N
Explanation:
We are told that this person extends the spring 30 cm from equilibrium and holds it at this location by applying a 10 N force.
Thus, based on Hooke's law formula which is F = k Δx, we can say that the mass attached to the spring does not change the spring constant. Thus, the
same resistive spring force will still be in place and in turn, the same stretching force of 10N would still be required.
Thus;
The necessary force applied by the person to hold the mass stationary there is 10 N
Comic-strip hero Superman meets an asteroid in outer space and hurls it at 800 m/s, as fast as a bullet. The asteroid is a thousand times more massive than Superman. In the strip, Superman is seen at rest after the throw. Taking physics into account, what would be his recoil speed (in km/s)?
Answer:
800km/s
Explanation:
Initial momentum = final momentum
the total momentum is zero, Before the release of the asteroid , but Superman and the asteroid are not moving.
So, according to the Conservation of momentum the total momentum when the astronaut is been thrown will equals to zero . Then we can say
Initial momentum = final momentum
Because the momentum of the Superman immediately the asteroid is been thrown is equal to the momentum of the asteroid
Momentum =(mass ×velocity)
the mass of the asteroid i= 1000M
Given velocity = 800 m/s,
momentum =(1000M)(800 m/s)
= 800,000M m/s.
to get the answer, we need to divide by Superman's mass, M, which gives his recoil velocity of 800,000 m/s.
But we're told to convert to km/ s
We know that 1m/s=0.001km/s
=(800,000M m/s)× (0.001km/s)
=800km/s
Therefore, his recoil speed (in km/s) is 800km/s
Den pushes a desk 400 cm across the floor. He exerts a force of 10 N for 8 s to move the desk. What is his power output? (Power: P = W/t) 1.25 W 5 W 40 W 500 W
Answer:
5 W
Explanation:
The formula of the power is:
● P = W/t
W is the work and t is the time needed to do it(in seconds)
Let's calculate first the work that the force exerced:
W = Vector F . Vector d
D is the distance ( here 400 cm wich is 4 m)
Make a representation to see how are the vectors F and V.(picture below)
The vector F and d are colinear since Den is pushing the desk on the ground.
● W = 4 × 10 = 40 J
J is Joule
■■■■■■■■■■■■■■■■■■■■■■■■■■
● P = W / t
● P = 40/ 8
● P = 5 W
The power output of the force of 10N for 8 seconds to move the desk is 5 watts. Thus, the correct option is B.
What is Power?Power is the amount of energy which is transferred or converted per unit time. In the SI system of Units, the unit of power is the watt, which is equal to one joule per second time.
We Know, P = W/t
where, P = Power,
W = Work done,
t = Time taken
P = F × s/t
where, F = Force applied,
s = distance travelled,
t = time taken
Here, F = 10N
s = 400cm = 4m
t = 8 sec
Substitute their values into the expression,
P = 10 × 4/8
P = 10 × 1/2
P = 5 Watt
So, the power output will be 5 watts.
Therefore, the correct option is B.
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