Answer:
L = 0.16 yd, W = 0.22 yd
Step-by-step explanation:
Dimensions of play ground 23/147 yd x 3/14 yd
reducing factor 2/147
Let the original length is L.
[tex]L - \frac{2L}{147} = \frac{23}{147}\\\\L\frac{143}{147} = \frac{23}{147}\\\\L=\frac{23}{143} yd[/tex]
L = 0.16 yd
Let the width is W.
[tex]W - \frac{2W}{147} = \frac{3}{14}\\\\W\frac{143}{147} = \frac{3}{14}\\\\W=0.22 yd[/tex]
Matthew earns extra money by doing odd jobs for his neighbors. He charges a flat fee of $20 plus $7 per hour for each job. If he earned $90 for a job he did last week, how many hours did he work?
Answer:
10 hours
Step-by-step explanation:
ok so we know he is getting payed $20 + $7 every hour so what i would do is keep the multiply the 7 till you get 70 so thats 7x10=70 and 70+20=90 so he worked for 10 hours last week :) i hope this helps, i tried my best to explain it
Enter an equation in point-slope form for the line.
Slope is −6 and (1, 1) is on the line.
Answer:
y - 1 = -6(x - 1)
General Formulas and Concepts:
Algebra I
Point-Slope Form: y - y₁ = m(x - x₁)
x₁ - x coordinate y₁ - y coordinate m - slopeStep-by-step explanation:
Step 1: Define
Identify
Point (1, 1)
Slope m = -6
Step 2: Find Equation
Substitute in variables [Point-Slope Form]: y - 1 = -6(x - 1)Identify the level of measurement of the data, and explain what is wrong with the given calculation. Ina set of data, alert levels are represented as 1 for low, 2 for medium, and 3 for high. The average mean of the 522 alert levels is 1.3. The data are at the ________ level of measurement. a. Nominalb. Ordinalc. Ratiod. IntervalWhat is wrong with the given calculation?a. Such data should not be used for calculations such as an average.b. One must use a different method to take the average of such datac. The true average is 2.5d. There is nothing wrong with the given calculation.
Answer:
(1) Ordinal
(2) Such data should not be used for calculations such as an average.
Step-by-step explanation:
Given
[tex]1 \to Low[/tex]
[tex]2 \to Medium[/tex]
[tex]3 \to High[/tex]
[tex]Average = 1.3[/tex]
Solving (a): The level of measurement
When observations are presented in ranks such as:
[tex]1 \to Low[/tex]
[tex]2 \to Medium[/tex]
[tex]3 \to High[/tex]
The level of measurement of such observation is ordinal
Solving (b): What is wrong with the computation?
Ordinal level of measurement are not numerical values whose average can be calculated because they are used as ranks.
Hence, (a) is correct
Romans Food Market, located in Saratoga, New York, carries a variety of specialty foods from around the world. Two of the store's leading products use the Romans Food Market name: Romans Regular Coffee and Romans DeCaf Coffee. These coffees are blends of Brazilian Natural and Colombian Mild coffee beans, which are purchased from a distributor located in New York City. Because Romans purchases large quantities, the coffee beans may be purchased on an as-needed basis for a price 10% higher than the market price the distributor pays for the beans. The current market price is $0.47 per pound for Brazilian Natural and $0.62 per pound for Colombian Mild. The compositions of each coffee blend are as follows: Blend
Bean Regular DeCaf
Brazilian Natural 75% 40%
Columbian Mild 25% 60%
Romans sells the regular blend for $3.60 per pound and the Decaf blend for $4.40 per pound. Romans would like to place an order for the Brazilian and Columbian coffee beans that will enable the production of 1000 pounds of Romans Regular coffee and 500 pound of Romans DeCaf coffee. The production cost is $0.80 per pound for the Regular blend. Because of the extra steps required to produce DeCaf, the production cost for the DeCaf blend is $1.05 per pound. Packaging costs for both products are $0.25 per pound. Formulate a linear programming model that can be used to determine the pounds of Brazilian Natural and Columbian Mild that will maximize the total contribution to profit. What is the optimal solution and what is the contribution profit?
Answer:
z(max) = 2996.13 $
x₁ = 968 x₂ = 430 ( quantities of regular and Decaf coffee respectevely)
Total quantity of BN = 898 pounds
Total quantity of CM = 500 pounds
Step-by-step explanation:
Cost of the beans
Brazilian natural = Price market + 10 % = 0.47 + 0.047
BN Cost = 0.517 $/lb
Clombian Mild = Price market + 10 % = 0.62 + 0.062
CM Cost = 0.682 $/lb
Composition of the coffee blend
Regular coffee 0.75 BN + 0.25 CM
De Caf coffee 0.40 BN + 0.60 CM
PRICES
Regular Roman = 3.60 $
Decaf = 4.40 $
Production costs:
Regular Roman = 0.80 $/lb
Decaf = 1.05 $/lb
Packaging costs: 0.25 $/Lb both
Profit = Price - cost
Profit of regular coffee = 3.60 - 0.80 - 0.25 -Cost of bean
for regular coffee cost of BN + CM
BN is : 0.75*BN cost = 0.75*0.517 = 0.38775 and
CM is : 0.25*0.682 = 0.1705
Profit of regular coffee = 1.99175 $
Profit for Decaf coffee = 4.4 - 1.05 - 0.25 - ( 0.517*0.4 + 0.6*0.682)
Profit for Decaf coffee = 4.4 - 1.30 - 0.616
Profit for Decaf coffee = 2.484 $
Let´s call x₁ pounds of regular coffee and x₂ pounds of Decaf coffee then:
Objective Function is:
z = 1.99175*x₁ + 2.484*x₂ to maximize
Subject to:
Availability of beans for 1000 pounds of Regular coffee means:
750 pounds of BN + 250 pounds of CM
Availability of beans for 500 pounds of Decaf coffee means
200 pounds of BN + 300 pounds of CM
Then 750 + 200 = 900 pounds of BN
And 250 + 300 = 550 pounds of CM
Availability of beans for 1000 pounds of Decaf coffee correspond to
0.75 *x₁ + 0.40*x₂ ≤ 900
Availability of beans for 500 pounds of Regular coffee correspond to
0.25*x₁ + 0.60*x₂ ≤ 500
Then the model is:
z = 1.99175*x₁ + 2.484*x₂ to maximize
Subject to:
0.75 *x₁ + 0.40*x₂ ≤ 900
0.25*x₁ + 0.60*x₂ ≤ 500
General constraints x₁ ≥ 0 x₂ ≥ 0 both integers
After 6 iterations optimal solution ( maximum z) is
z(max) = 2996.13 $
x₁ = 968 x₂ = 430
x₁ and x₂ are quantities of Regular and Decaf coffee respectively, to find out quantities of Brazilian Natural and Colombian Mild
we proceed as follows
Regular coffee is : 0.75*968 = 726 pounds of BN
Decaf coffee is : 0.40*430 = 172 pounds of BN
Total quantity of BN = 898 pounds
Regular coffee is : 0.25*968 = 242 pounds of CM
Decaf coffee is : 0.6*430 = 258 pounds of CM
Total quantity of CM = 500 pounds
Solve this
4 X (10 - 3+2)
Answer:
36
Step-by-step explanation:
10-3=7+2=9
4×9=36
36 is the answer
Subtract and show work.
Answer:
[tex]31y^{3} -28y^{2}[/tex]+35y
Step-by-step explanation:
Which operation will solve the following word problem? Jaylene bought a blouse for $20.00. The next day she returned the blouse and got 90% of her money back, she was charged a restocking fee of 10%. How much money did she get back?
Division
Addition
Subtraction
Multiplication
Answer:
division is right i hope you understand
9514 1404 393
Answer:
Multiplication
Step-by-step explanation:
The amount Jaylene got back is 90% of the amount she spent. That value is found by multiplying 90% times $20.
Jaylene got back ...
90% × $20 = $18
Kamala marked the price of a cosmetic item as Rs 400. She offered her customers a discount of 20% and made a loss of Rs 30, what was the actual cost of the item to her?
Answer:
350
Step-by-step explanation:
400- 80 ( 20% discount)
=320+30(loss)
=350
What is the equation of the line that is perpendicular to
and has the same y-intercept as the given line?
(0,0)
(5,0)
O y = x+1
O y = x+5
o y = 5x + 1
O y = 5x + 5
-6 -5 -4 -3 -2 -1
23
4 5 6
Mark this and return
Save and Exit
Nyt
Submit
Answer:
y = 5x + 1
Step-by-step explanation:
Given the coordinate points (0,1) and (5,0)
First, get the slope
Slope m =(0-1)/5-0
m = -1/5
Since the required line is perpendicular, then the required slope is;
M = -1/(-1/5)
M = 5
Since 1the y intecept id (0,1) i.e. 1
Required equation is y = mx+b
y = 5x + 1
This gives the required equation
Note that the coordinate (0,1) was used instead os (0,0)
find the measure of angle c of a triangle ABC, if m
There's a three in the tens
placed
The digit is the ones places is
third multiple of three
It is a two-digit number
Answer:
That number is 39
solve the inequality x^3+4x>5x^2 please show steps and interval notation. thank you.
Answer: [tex]x\in (0,1)\cup (4,\infty)[/tex]
Step-by-step explanation:
Given
In equality is [tex]x^3+4x>5x^2[/tex]
Taking terms one side
[tex]\Rightarrow x^3-5x^2+4x>0\\\Rightarrow x(x^2-5x+4)>0\\\Rightarrow x(x^2-4x-x+4)>0\\\Rightarrow x(x-4)(x-1)>0\\\Rightarrow (x-0)(x-1)(x-4)>0[/tex]
Using wavy curve method
[tex]x\in (0,1)\cup (4,\infty)[/tex]
Does it pay to ask for a raise? A national survey of heads of households showed the percentage of those who asked for a raise and the percentage who got one. According to the survey, of the men interviewed, 21% had asked for a raise and 60% of the men who had asked for a raise received the raise. If a man is selected at random from the survey population of men, find the following probabilities. (Enter your answers to three decimal places.)
Answer:
a) P(man asked for a raise) = 0.21.
b) P(man received raise, given he asked for one) = 0.6.
c) P(man asked for raise and received raise) = 0.126.
Step-by-step explanation:
Conditional Probability
We use the conditional probability formula to solve this question. It is
[tex]P(B|A) = \frac{P(A \cap B)}{P(A)}[/tex]
In which
P(B|A) is the probability of event B happening, given that A happened.
[tex]P(A \cap B)[/tex] is the probability of both A and B happening.
P(A) is the probability of A happening.
Question a:
21% asked for a raise, so:
P(man asked for a raise) = 0.21.
Question b:
Event A: Asked for a raise.
Event B: Received a raise:
21% had asked for a raise and 60% of the men who had asked for a raise received the raise:
This means that [tex]P(A) = 0.21, P(A \cap B) = 0.21*0.6[/tex], thus:
[tex]P(B|A) = \frac{P(A \cap B)}{P(A)} = \frac{0.21*0.6}{0.6} = 0.6[/tex]
P(man received raise, given he asked for one) = 0.6.
Question c:
[tex]P(A \cap B) = 0.21*0.6 = 0.126[/tex]
P(man asked for raise and received raise) = 0.126.
36x^2=y^2
Does the equation define y as a function of x ?
Answer:
ya the equation divides y as a function of x
A circle has a circumference of 2cm. Which statement about the circumference and area is true?
A comparison of the area and circumference is not possible since the area cannot be determinec
The numerical values of the circumference and area of the circle are equal.
The numerical value of the circumference is greater than the numerical value of the area.
The numerical value of the circumference is less than the numerical value of the area.
ОО
Answer:
The numerical values of the circumference and area of the circle are equal.
An item is regularly priced at $84. Ashley bought it on sale for 70% off the regular price.
Use the ALEKS calculator to find how much Ashley paid
Answer:
58.80
Step-by-step explanation:
84 x .7(70%) =58.80
Help please!!!!!!!!!!!
Answer:
AB IS THE ANSWER !!!!!!!!!!
Answer: AB
Step-by-step explanation:
Hi! I don't know if you need help anymore ,but here you go!
Because BC=ED, I asume that AE=AB
angle P and angle Q are complementary. The measure of angle Q is 33.5°. What is the measure of angle P?
Answer:
56.5 degrees
Step-by-step explanation:
Because complementary angles are when their sum is 90, you get the equation:
P + Q = 90
Since Q is 33.5,
P + 33.5 = 90
Subtracting 33.5 from both sides,
P = 56.5
I need help with this word problem.
Answer:
$3.22 per square feet
Step-by-step explanation:
To solve, I usually set up an equation:
sq ft = 12 1/2 = 1
$ 40.21 x
Then, use cross multiplication.
(12 1/2)x=40.21
Divide both sides by 12 1/2 or 12.5
x = 3.2168
Round to the hundredths place [because we're dealing with money]
$3.22
I hope this helps!
Answer:
3.22 per sq ft
Step-by-step explanation:
Take the total cost and divide by the amount of tiles
40.21 / 12.5
3.2168 per sq ft
Rounding to the nearest cent
3.22 per sq ft
Find the slope of the line that passes through the two points. 4,4 & 4,9
HELPPPPPPP
Answer:
is 22
Step-by-step explanation:
Answer:
It doesn't have a slope?
Step-by-step explanation:
Knowing that the slope equation is y2-y1/x2-x1
9-4 5
----- = ------ = 0
4-4 0
this means that the slope is 0...
A large on-demand, video streaming company is designing a large-scale survey to determine the mean amount of time corporate executives watch on-demand television. A small pilot survey of 10 executives indicated that the mean time per week is 12 hours, with a standard deviation of 3 hours. The estimate of the mean viewing time should be within 0.25 hour. The 95% level of confidence is to be used. How many executives should be surveyed? (Use z Distribution Table.)
How many executives should be surveyed? (Round the final answer to the next whole number.)
Answer:
554 executives should be surveyed.
Step-by-step explanation:
We have that to find our [tex]\alpha[/tex] level, that is the subtraction of 1 by the confidence interval divided by 2. So:
[tex]\alpha = \frac{1 - 0.95}{2} = 0.025[/tex]
Now, we have to find z in the Z-table as such z has a p-value of [tex]1 - \alpha[/tex].
That is z with a pvalue of [tex]1 - 0.025 = 0.975[/tex], so Z = 1.96.
Now, find the margin of error M as such
[tex]M = z\frac{\sigma}{\sqrt{n}}[/tex]
In which [tex]\sigma[/tex] is the standard deviation of the population and n is the size of the sample.
Standard deviation of 3 hours.
This means that [tex]\sigma = 3[/tex]
The 95% level of confidence is to be used. How many executives should be surveyed?
n executives should be surveyed, and n is found with [tex]M = 0.25[/tex]. So
[tex]M = z\frac{\sigma}{\sqrt{n}}[/tex]
[tex]0.25 = 1.96\frac{3}{\sqrt{n}}[/tex]
[tex]0.25\sqrt{n} = 1.96*3[/tex]
[tex]\sqrt{n} = \frac{1.96*3}{0.25}[/tex]
[tex](\sqrt{n})^2 = (\frac{1.96*3}{0.25})^2[/tex]
[tex]n = 553.2[/tex]
Rounding up:
554 executives should be surveyed.
PLEASE HELP
The function in the table is quadratic:
TRUE
FALSE
Answer:
False
Step-by-step explanation:
Each f(x) increases by 8 therefore this equation is a linear function. If you where to graph it would be a straight line
Hope this helped :)
Answer:
False
Step-by-step explanation:
The slope is the same between all pounts which means the function is linear.
Hope this helps!
The functions f(x) and g(x) are shown on the graph.
f(x) = x2
What is g(x)?
10-
If(x)
1
х
10
-5
5
10
g(x)
-10
A. g(x) = (– x)2 - 3
B. g(x) = – x2 + 3
c. g(x) = (-x)2 + 3
D. g(x) = -X2 - 3
Answer:
[tex]g(x) = -x^2 + 3[/tex]
Step-by-step explanation:
Given
[tex]f(x) = x^2[/tex]
Required
Determine g(x)
First, shift f(x) down by 3 units
The rule is:
[tex]f'(x) = f(x) - 3[/tex]
So:
[tex]f'(x) = x^2 - 3[/tex]
Next, reflect f'(x) across the x-axis to get g(x)
The rule is:
[tex]g(x) = -f(x)[/tex]
So, we have:
[tex]g(x) = -(x^2 - 3)[/tex]
Open bracket
[tex]g(x) = -x^2 + 3[/tex]
Answer:
D
Step-by-step explanation:
I figured out the hard way
Solve the expression using the correct order of operations.
0.75x3.2+ (9.1)2-((-2.3)-(-0.9))2
Answer:
[tex]0.75 * 3.2+ (9.1)^2-((-2.3)-(-0.9))^2 = 83.25[/tex]
Step-by-step explanation:
Given
[tex]0.75 * 3.2+ (9.1)^2-((-2.3)-(-0.9))^2[/tex]
Required
Solve
Start with the bracket
[tex]0.75 * 3.2+ (9.1)^2-((-2.3)-(-0.9))^2 = 0.75 * 3.2+ (9.1)^2-(-1.4)^2[/tex]
Evaluate all exponents
[tex]0.75 * 3.2+ (9.1)^2-((-2.3)-(-0.9))^2 = 0.75 * 3.2+ 82.81-1.96[/tex]
Evaluate all products
[tex]0.75 * 3.2+ (9.1)^2-((-2.3)-(-0.9))^2 = 2.4+ 82.81-1.96[/tex]
[tex]0.75 * 3.2+ (9.1)^2-((-2.3)-(-0.9))^2 = 83.25[/tex]
Marla scored 70% on her last unit exam in her statistics class. When Marla took the SAT exam, she scored at the 70th percentile in mathematics. Explain the difference in these two scores.
Answer:
The difference is that Marla's exam in her statistics class was graded by percent of correct answers, in her case 70%, while the SAT is graded into a curve, taking other students' grades also into account, and since she scored in the 70th percentile, Marla scored better than 70% of the students.
Step-by-step explanation:
Marla scored 70% on her last unit exam in her statistics class.
This means that in her statistics class, Marla got 70% of her test correct.
When Marla took the SAT exam, she scored at the 70th percentile in mathematics.
This means that on the SAT exam, graded on a curve, Marla scored better than 70% of the students.
Explain the difference in these two scores.
The difference is that Marla's exam in her statistics class was graded by percent of correct answers, in her case 70%, while the SAT is graded into a curve, taking other students' grades also into account, and since she scored in the 70th percentile, Marla scored better than 70% of the students.
[tex](v+6)^{2}=2v^{2}+14v+12[/tex]
Answer:
v=-6 or 4
Step-by-step explanation:
Answer:
the answer would be 5
Step-by-step explanation:
have to do the question multiply add and divide to find your answer
Find m angle NML; m angle QML=115^ and m angle NMQ=28^
Answer:
We're provided - m ∠ QML = 115° , m ∠ NMQ = 28° and we're asked to find out m ∠ NML. Set up an equation and solve for m ∠ NML.[tex] \large{ \tt{❀ \: m \: \angle \: NML= m \: \angle \:QML + m \: \angle \: NMQ}}[/tex]
[tex] \large{ \tt{⤇m \: \angle \:NML= 115 \degree + 28 \degree }}[/tex]
[tex] \boxed{ \large{ \tt{⤇ \: m \: \angle \:NML = 143 \degree }}}[/tex]
Hence , Our final answer is 143° . Hope I helped! Let me know if you have any questions regarding my answer and also notify me , if you need any other help! :)▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁
What do you add to 2 7/8 to make 5
Answer:
2 1/8
Step-by-step explanation:
7/8 is the same as 0.875 and therefore you need 0.125 also known as 1/8 to make it a whole number. When you add it to the already existing whole 2 you get three. Subtract three from five to make two which is what you need to add on top to finally get 5.
There are 4 contestants in a beauty pageant. How many results are possible for the first, second, and third place?
Explanation:
There are 4 choices for first place, 3 choices for second place, and 2 choices for third place. Overall, there are 4*3*2 = 24 permutations.
Determine if a quadrilateral with the given vertices is an isosceles trapezoid. Show and explain all steps to prove or disprove.
A(3, 3) B(5, 3) C(8,1) D(1,1)
Answer:
No, a quadrilateral with the given vertices is not an isosceles trapezoid.
Step-by-step explanation:
We are given that
A(3,3), B(5,3), C(8,1), D(1,1)
Slope formula:
[tex]m=\frac{y_2-y_1}{x_2-x_1}[/tex]
Slope of AB=[tex]\frac{3-3}{5-3}=0[/tex]
Slope of BC=[tex]\frac{1-3}{8-5}=\frac{-2}{3}[/tex]
Slope of CD=[tex]\frac{1-1}{1-8}=0[/tex]
Slope of AD=[tex]\frac{1-3}{1-3}=1[/tex]
Slope of AB=Slope of CD
When slopes of two lines are equal then the lines are parallel.
Therefore, AB is parallel to CD.
When one pair of quadrilateral is parallel then the quadrilateral is trapezoid.
[tex]\implies [/tex]ABCD is a trapezoid.
Distance formula:
[tex]\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}[/tex]
Using the formula
Length of BC=[tex]\sqrt{(8-5)^2+(1-3)^2}[/tex]
Length of BC=[tex]\sqrt{9+4}=\sqrt{13}[/tex] units
Length of AD=[tex]\sqrt{(1-3)^2+(1-3)^2}[/tex]
Length of AD=[tex]\sqrt{4+4}=2\sqrt{2}[/tex]
Length of AD is not equal to length of BC.
Hence, trapezoid is not an isosceles trapezoid.
