Answer:
CI 96 % = ( - 0.1128 ; 0.0728 )
CI 95% = ( - 0.1087 ; 0.6878 )
The two intervals contain 0 value therefore we can support that there is not statistics difference between the two groups with confidence level of 96 % and 95%
Step-by-step explanation:
Boys sample:
sample size n₁ = 200
x₁ number of boys saying their parents are very involved in their lives
= 93
p₁ = x₁/n₁ = 93/200 = 0.465 then q₁ = 1 - p₁ q₁ = 1 - 0.465 q₁ = 0.535
Girls sample
sample size n₂ = 300
x₂ number of girls saying their parents are very involved in their lives
= 172
p₂ = x₂/n₂ = 172/ 300 = 0.573 then q₂ = 1 -0.573 q₂ = 0.427
CI 96 % α = 4 % α = 0.04 α/2 = 0.02
p₁ - p₂ = 0.465 - 0.573 = - 0.168
CI 96 % = ( p₁ - p₂ ) ± z(c) * SE
z(c) for α = 0.02 z(c) = - 2.05
SE = √ (p₁*q₁)/n₁ + (p₂*q₂)/n₂
SE = √ ( 0.465*0.535)/200 + (0.573*0.427)/300
SE = √ 0.00124 + 0.000815
SE = √ 0.00205
SE = 0.0453
CI 96 % = ( -0.02 ± ( 2.05 * 0.0453 ) )
CI 96 % = ( -0.02 ± ( 0.0928 ))
CI 96 % = ( - 0.1128 ; 0.0728 )
a) CI 95% α = 5 % α = 0.05 α/2 = 0.025
SE = 0.0453
z(c) for 0.025 is from z-table z(c) = 1.96
CI 95% = ( - 0.02 ± 1.96 * 0.0453)
CI 95% = ( - 0.02 ± 0.08878 )
CI 95% = ( - 0.1087 ; 0.6878 )
The lifespan, in years, of a certain computer is exponentially distributed. The probability that its lifespan exceeds four years is 0.30. Let f(x) represent the density function of the computer's lifespan, in years, for x>0. Determine an expression for f(x).
Answer:
The correct answer is "[tex]0.300993e^{-0.300993x}[/tex]".
Step-by-step explanation:
According to the question,
⇒ [tex]P(x>4)=0.3[/tex]
We know that,
⇒ [tex]P(X > x) = e^{(-\lambda\times x)}[/tex]
⇒ [tex]e^{(-\lambda\times 4)} = 0.3[/tex]
∵ [tex]\lambda = 0.300993[/tex]
Now,
⇒ [tex]f(x) = \lambda e^{-\lambda x}[/tex]
By putting the value, we get
[tex]=0.300993e^{-0.300993x}[/tex]
The following multiple regression printout can be used to predict a person's height (in inches) given his or her shoe size and gender, where gender = 1 for males and 0 for females.
Regression Analysis: Height Versus Shoe Size, Gender
Coefficients
Term Coef SE Coef T-value P-value
Constant 55.24 1.05 52.61 0.000
Shoe Size 1.164 0.13 0.000
Gender 2.574 0.489 5.26 0.000
Required:
a. Find the value of the test statistic for shoe size.
b. Is the regression coefficient of shoe size statistically significant?
c. Does the variable shoe size belong in the model?
d. Interpret the regression coefficient of Gender.
Answer:
a. 8.95
b. it is
c. yes it belongs
d. males are 2.574 taller than females on average.
Step-by-step explanation:
GIven the regression outpuit that we have in this question, the value of the t test statistics for the shoe size can be solved as
a. test statistic = 1.164/0.13
t test = 8.95
b. the regression coefficient of shoe size is 1.164, this is statistically significant
c. Yes the variable shoe size does belong to the model.
d. The regression coefficient of gender shows that on the average, while holding other variables constant, males are 2.574 inches taller than the their female counterparts.
angle 1 is congruent to angle 2 prove p is parallel to q
You'll need 2 more lines to complete this two column proof.
---------------------
Line 4
For the "statement" portion, you'll say something like [tex]\angle 2 \cong \angle 3[/tex]
The reason for this statement is "transitive property"
We're basically combining lines 1 and 3 to form this new line.
The transitive property is the idea that if A = B and B = C, then A = C. We connect the statements like a chain.
---------------------
Line 5
The statement is what you want to prove since this is the last line.
So the statement is [tex]p || q[/tex]
The reason is "converse of corresponding angles theorem"
As you can probably guess, this theorem says "If two corresponding angles are congruent, then the lines are parallel".
Can someone please help me with my hw 20 points?
Answer:
The first equation; x-2y=8
Step-by-step explanation:
Hi there!
We're told that Ty wants to isolate x in one of the equations. To do so in either, he will need to use inverse operations to cancel out values and leave just x remaining on one side of the equation.
In the second equation, he would need to subtract both sides by 6y and then divide both sides by 4 to isolate x. It's a two-step process.
However, in the first equation, he only needs to add 2y to both sides to isolate x.
I hope this helps!
Answer:
using the first equation
cause Being that the first equation has the simplest coefficients (1, -2, for x, and y respectively), it seems logical to use it to develop a definition of one variable in terms of the other
Use the definition of a Taylor series to find the first four nonzero terms of the series for f(x) centered at the given value of a.
f(x)= 7x e^x, a= 0
Hi there!
[tex]\large\boxed{p(x) = 7x + 7x^2 + \frac{7}{2}x^3 + \frac{7}{6}x^4}[/tex]
Recall a Taylor series centered at x = 0:
[tex]p(x) = f(0) + f'(0)(x) + \frac{f''(0)}{2}x^{2} + \frac{f'''(0)}{3!}x^{3} + ...+ \frac{f^n}{n!}x^n[/tex]
Begin by finding the derivatives and evaluate at x = 0:
f(0) = 7(0)e⁰ = 0
f'(x) = 7eˣ + 7xeˣ f'(0) = 7e⁰ + 7(0)e⁰ = 7
f''(x) = 7eˣ + 7eˣ + 7xeˣ f''(0) = 7(1) + 7(1) + 0 = 14
f'''(x) = 7eˣ + 7eˣ + 7eˣ + 7xeˣ f'''(0) = 21
f⁴(x) = 7eˣ + 7eˣ + 7eˣ + 7eˣ + 7xeˣ f⁴(0) = 28
Now that we calculated 4 non-zero terms, we can write the Taylor series:
[tex]p(x) = 0 + 7x + \frac{14}{2}x^2 + \frac{21}{3!}x^3 + \frac{28}{4!}x^4[/tex]
Simplify:
[tex]p(x) = 7x + 7x^2 + \frac{7}{2}x^3 + \frac{7}{6}x^4[/tex]
Please help NO LINKS
Use cylindrical shells to find the volume of the solid obtained by rotating the region bounded by
y
=
x
2
,
y
=
0
, and
x
=
5
,
about the
y
-axis.
V
=
Answer:
[tex]\displaystyle V = \frac{625 \pi}{2}[/tex]
General Formulas and Concepts:
Algebra I
FunctionsFunction NotationGraphingCalculus
Integrals
Integration Rule [Reverse Power Rule]: [tex]\displaystyle \int {x^n} \, dx = \frac{x^{n + 1}}{n + 1} + C[/tex]
Integration Rule [Fundamental Theorem of Calculus 1]: [tex]\displaystyle \int\limits^b_a {f(x)} \, dx = F(b) - F(a)[/tex]
Integration Property [Multiplied Constant]: [tex]\displaystyle \int {cf(x)} \, dx = c \int {f(x)} \, dx[/tex]
Integration Property [Addition/Subtraction]: [tex]\displaystyle \int {[f(x) \pm g(x)]} \, dx = \int {f(x)} \, dx \pm \int {g(x)} \, dx[/tex]
Shell Method: [tex]\displaystyle V = 2\pi \int\limits^b_a {xf(x)} \, dx[/tex]
[Shell Method] 2πx is the circumference[Shell Method] 2πxf(x) is the surface area[Shell Method] 2πxf(x)dx is volumeStep-by-step explanation:
Step 1: Define
y = x²
y = 0
x = 5
Step 2: Identify
Find other information from graph.
See Attachment.
Bounds of Integration: [0, 5]
Step 3: Find Volume
Substitute in variables [Shell Method]: [tex]\displaystyle V = 2\pi \int\limits^5_0 {x(x^2)} \, dx[/tex][Integrand] Multiply: [tex]\displaystyle V = 2\pi \int\limits^5_0 {x^3} \, dx[/tex][Integral] Integrate [Integration Rule - Reverse Power Rule]: [tex]\displaystyle V = 2\pi \bigg( \frac{x^4}{4} \bigg) \bigg| \limits^5_0[/tex]Evaluate [Integration Rule - FTC 1]: [tex]\displaystyle V = 2\pi \bigg( \frac{625}{4} \bigg)[/tex]Multiply: [tex]\displaystyle V = \frac{625 \pi}{2}[/tex]Topic: AP Calculus AB/BC (Calculus I/I + II)
Unit: Applications of Integration
Book: College Calculus 10e
HELP ASAP I WILL GIVE BRAINLIST
Convert 7π OVER 4 radians to degrees. Which quadrant does this angle lie in?
What are the sine, cosine and tangent of the angle 7π over 4? Be sure to show and explain all work.
Answer:
7π/4 radians = 315°, Quadrant IV
sin(315°) = -√2/2
cos(315°) = √2/2
tan(315°) = -1
Step-by-step explanation:
Solve by using matrices. 2x – y +2 + w = -3 x + 2y – 3z + w = 12 3x - y - + 2w = 3 -2x + 3y + 2 – 3w = -3
Some symbols and numbers are missing. I assume the system is supposed to read
2x - y + 2z + w = -3
x + 2y - 3z + w = 12
3x - y - z + 2w = 3
-2x + 3y + 2z - 3w = -3
In matrix form, this is
[tex]\begin{bmatrix}2&-1&2&1\\1&2&-3&1\\3&-1&-1&2\\-2&3&2&-3\end{bmatrix}\begin{bmatrix}x\\y\\z\\w\end{bmatrix}=\begin{bmatrix}-3\\12\\3\-3\end{bmatrix}[/tex]
which we can strip down to the augmented matrix,
[tex]\left[\begin{array}{cccc|c}2&-1&2&1&-3\\1&2&-3&1&12\\3&-1&-1&2&3\\-2&3&2&-3&-3\end{array}\right][/tex]
Now for the row operations:
• swap rows 1 and 2
[tex]\left[\begin{array}{cccc|c}1&2&-3&1&12\\2&-1&2&1&-3\\3&-1&-1&2&3\\-2&3&2&-3&-3\end{array}\right][/tex]
• add -2 (row 1) to row 2, -3 (row 1) to row 3, and 2 (row 1) to row 4
[tex]\left[\begin{array}{cccc|c}1&2&-3&1&12\\0&-5&8&-1&-27\\0&-7&8&-1&-33\\0&7&-4&-1&21\end{array}\right][/tex]
• add 7 (row 2) to -5 (row 3), and row 3 to row 4
[tex]\left[\begin{array}{cccc|c}1&2&-3&1&12\\0&-5&8&-1&-27\\0&0&16&-2&-24\\0&0&4&-2&-12\end{array}\right][/tex]
• multiply through rows 3 and 4 by 1/2
[tex]\left[\begin{array}{cccc|c}1&2&-3&1&12\\0&-5&8&-1&-27\\0&0&8&-1&-12\\0&0&2&-1&-6\end{array}\right][/tex]
• add -4 (row 4) to row 3
[tex]\left[\begin{array}{cccc|c}1&2&-3&1&12\\0&-5&8&-1&-27\\0&0&0&3&12\\0&0&2&-1&-6\end{array}\right][/tex]
• swap rows 3 and 4
[tex]\left[\begin{array}{cccc|c}1&2&-3&1&12\\0&-5&8&-1&-27\\0&0&2&-1&-6\\0&0&0&3&12\end{array}\right][/tex]
• multiply through row 4 by 1/3
[tex]\left[\begin{array}{cccc|c}1&2&-3&1&12\\0&-5&8&-1&-27\\0&0&2&-1&-6\\0&0&0&1&4\end{array}\right][/tex]
• add row 4 to row 3
[tex]\left[\begin{array}{cccc|c}1&2&-3&1&12\\0&-5&8&-1&-27\\0&0&2&0&-2\\0&0&0&1&4\end{array}\right][/tex]
• multiply through row 3 by 1/2
[tex]\left[\begin{array}{cccc|c}1&2&-3&1&12\\0&-5&8&-1&-27\\0&0&1&0&-1\\0&0&0&1&4\end{array}\right][/tex]
• add -8 (row 3) and row 4 to row 2
[tex]\left[\begin{array}{cccc|c}1&2&-3&1&12\\0&-5&0&0&-15\\0&0&1&0&-1\\0&0&0&1&4\end{array}\right][/tex]
• multiply through row 2 by -1/5
[tex]\left[\begin{array}{cccc|c}1&2&-3&1&12\\0&1&0&0&3\\0&0&1&0&-1\\0&0&0&1&4\end{array}\right][/tex]
• add -2 (row 2) and 3 (row 3) and -1 (row 4) to row 1
[tex]\left[\begin{array}{cccc|c}1&0&0&0&-1\\0&1&0&0&3\\0&0&1&0&-1\\0&0&0&1&4\end{array}\right][/tex]
Then the solution to the system is (x, y, z, w) = (-1, 3, -1, 4).
The triangles are similar. If QR = 9, QP = 6, and TU = 19, find TS. Round to the nearest tenth.
A) 16
B) 12.7
C) 2.8
D) 28.5
Answer:
TS = 12.7
Step-by-step explanation:
From the question given above, the following data were obtained:
QR = 9
QP = 6
TU = 19
TS =?
Since the triangles are SIMILAR, then,
QR / TU = QP / TS
With the above equation, we can obtain the value of TS as follow:
QR = 9
QP = 6
TU = 19
TS =?
QR / TU = QP / TS
9 / 19 = 6 / TS
Cross multiply
9 × TS = 19 × 6
9 × TS = 114
Divide both side by 9
TS = 114 / 9
TS = 12.7
PLEASE HELP!!! WILL GIVE BRAINLIEST!!!!
Finding the line of best fit is something a Machine Learning Model would do.
This particular ML model is called "Linear Regressor" or "Linear Regression Model". Look it up and there are definitely calculators for it, as it is relatively simple.
You can also, if you know how to use ML libraries and code, use Python to determine the value of [tex]b[/tex].
Hope this helps.
Which of the following are rational numbers?
Hi there!
»»————- ★ ————-««
I believe your answer is:
{7, -5, (2/3), 5.79}
»»————- ★ ————-««
Here’s why:
Rational numbers are numbers that could be written as a fraction with two integers.⸻⸻⸻⸻
[tex]\boxed{\text{\underline{\textbf{Some Examples of Rational Numbers Are...}}}}\\\\\rightarrow \text{Integers}\\\\\rightarrow \text{Perfect Squares}\\\\\rightarrow \text{Terminating Decimals}\\\\\rightarrow \text{Recurring Decimals}[/tex]
⸻⸻⸻⸻
7 and -5 are integers, so they are rational. [tex]\frac{2}{3}[/tex] is already a fraction with integers. It is rational.5.79 is a terminating decimal. It is rational.The number π is a famous irrational number. It does not terminate nor repeat. [tex]\sqrt{13}[/tex] is not a perfect square. It is irrational.[tex]\sqrt{-4}[/tex] is a perfect square, but it is simplified to a complex number. Complex numbers are not rational.⸻⸻⸻⸻
The rational numbers are {7, -5, (2/3), 5.79}.
⸻⸻⸻⸻
»»————- ★ ————-««
Hope this helps you. I apologize if it’s incorrect.
Which statement is true about quadrilateral ABCD with vertices A(2, 8), B(3, 11), C(4, 8), and D(3, 5)?
Answer:
The quadrilateral is a rhombus
Step-by-step explanation:
Given
[tex]A = (2, 8)[/tex]
[tex]B = (3, 11)[/tex]
[tex]C = (4, 8)[/tex]
[tex]D=(3, 5)[/tex]
Required
The true statement
Calculate slope (m) using
[tex]m = \frac{y_2 - y_1}{x_2 - x_1}[/tex]
Calculate distance using:
[tex]d= \sqrt{(x_2 - x_1)^2 + (y_2 -y_1)^2}[/tex]
Calculate slope and distance AB
[tex]m_{AB} = \frac{11 - 8}{3 - 2}[/tex]
[tex]m_{AB} = \frac{3}{1}[/tex]
[tex]m_{AB} = 3[/tex] -- slope
[tex]d_{AB}= \sqrt{(3 - 2)^2 + (11 -8)^2}[/tex]
[tex]d_{AB}= \sqrt{10}[/tex] -- distance
Calculate slope and distance BC
[tex]m_{BC} = \frac{8 - 11}{4 - 3}[/tex]
[tex]m_{BC} = \frac{- 3}{1}[/tex]
[tex]m_{BC} = -3[/tex] -- slope
[tex]d_{BC} = \sqrt{(4-3)^2+(8-11)^2[/tex]
[tex]d_{BC} = \sqrt{10}[/tex] --- distance
Calculate slope CD
[tex]m_{CD} = \frac{5 - 8}{3 - 4}[/tex]
[tex]m_{CD} = \frac{- 3}{- 1}[/tex]
[tex]m_{CD} = 3[/tex] -- slope
[tex]d_{CD} = \sqrt{(3-4)^2+(5-8)^2}[/tex]
[tex]d_{CD} = \sqrt{10}[/tex] -- distance
Calculate slope DA
[tex]m_{DA} = \frac{8 - 5}{2 - 3}[/tex]
[tex]m_{DA} = \frac{3}{- 1}[/tex]
[tex]m_{DA} = -3[/tex] -- slope
[tex]d_{DA} = \sqrt{(2-3)^2 + (8-5)^2}[/tex]
[tex]d_{DA} = \sqrt{10}[/tex]
From the computations above, we can see that all 4 sides are equal, i.e. [tex]\sqrt{10}[/tex]
And the slope of adjacent sides are negative reciprocal, i.e.
[tex]m_{AB} = 3[/tex] and [tex]m_{CD} = -3[/tex]
[tex]m_{CD} = 3[/tex] and [tex]m_{DA} = -3[/tex]
The quadrilateral is a rhombus
Question 3
A 70kg patient has approximately 8 pints of blood. The patient donates 470mL of blood.
Approximately what fraction of his body's blood is this? (one pint = 568mL)
Step-by-step explanation:
Given that,
The mass of a patient = 70 kg
A 70kg patient has approximately 8 pints of blood.
The patient donates 470mL of blood.
We know that,
1 pint = 568 mL
8 pints = 4544 mL
Required fraction,
[tex]\dfrac{470}{4544}=0.1\\\\=\dfrac{1}{10}[/tex]
So, the required fraction is approximately [tex]\dfrac{1}{10}[/tex].
Write an expression for the sequence of operations described below.
double t, subtract v from the result, then subtract u from what you have
Do not simplify any part of the expression.
Step-by-step explanation:
Double t
t+t=2t
Subtract v
2t-v
Subtract u
2t-v-u
What is net cash flow
Find the mean or average of these savings accounts $215, $156,$318, $75, and $25
Answer:
157.8
Step-by-step explanation:
Add them all up to get 789 and divide them by 5 as there are five numbers to get the answer:)
Helppp and explain than you
Answer:
1) x = 2
Step-by-step explanation:
Hope it helps. I'll try to solve the second one too
9514 1404 393
Answer:
x = 2(-5, 4, 6)Step-by-step explanation:
1. Substitution can work for this.
2x +3(4x -5) = 13
14x = 28 . . . . . add 15
x = 2 . . . . . . . divide by 14
__
2. The equation z=6 eliminates all but the 1st and 3rd choices. Using that value in the first equation gives ...
x + y + 6 = 5
x + y = -1
Only the 3rd choice satisfies this equation.
(x, y, z) = (-5, 4, 6)
One angle of a triangle is twice as large as another. The measure of the third angle is 60° more than that of the smallest angle. Find the measure of each angle.
The measure of the smallest angle is º
Please help :)
Answer:
The measure of the smallest angle is 30º
Step-by-step explanation:
Let the angles be:
[tex]x \to[/tex] the first angle (the smallest)
[tex]y \to[/tex] the second angle
[tex]z \to[/tex] the third angle
So, we have:
[tex]y = 2x[/tex]
[tex]z=x + 60[/tex]
Required
Find x
The angles in a triangle is:
[tex]x + y +z = 180[/tex]
Substitute values for y and z
[tex]x + 2x +x + 60 = 180[/tex]
[tex]4x + 60 = 180[/tex]
Collect like terms
[tex]4x = 180-60[/tex]
[tex]4x = 120[/tex]
Divide by 4
[tex]x = 30[/tex]
Help. I will be guessing on this, but I want to make sure this is on here so no one has to guess like I am. Help a brother out
Answer:
Line 3
Step-by-step explanation:
→ Calculate gradient
[tex]\frac{6-3}{4-2} =1.5[/tex]
Answer:
Line 3
Step-by-step explanation:
(0,0) & ( 4 , 6)
[tex]Slope = \frac{y_{2}-y_{1}}{x_{2}-x_{1}}\\\\=\frac{6-0}{4-0}\\\\=\frac{6}{4}\\\\=\frac{3}{2}\\\\=1\frac{1}{2}[/tex]
Suppose that the walking step lengths of adult males are normally distributed with a mean of 2.5 feet and a standard deviation of 0.4 feet. A sample of 45 men’s step lengths is taken. Step 1 of 2 : Find the probability that an individual man’s step length is less than 1.9 feet. Round your answer to 4 decimal places, if necessary.
Answer:
0.0668 = 6.68% probability that an individual man’s step length is less than 1.9 feet.
Step-by-step explanation:
Normal Probability Distribution:
Problems of normal distributions can be solved using the z-score formula.
In a set with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the z-score of a measure X is given by:
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.
Normally distributed with a mean of 2.5 feet and a standard deviation of 0.4 feet.
This means that [tex]\mu = 2.5, \sigma = 0.4[/tex]
Find the probability that an individual man’s step length is less than 1.9 feet.
This is the p-value of Z when X = 1.9. So
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
[tex]Z = \frac{1.9 - 2.5}{0.4}[/tex]
[tex]Z = -1.5[/tex]
[tex]Z = -1.5[/tex] has a p-value of 0.0668
0.0668 = 6.68% probability that an individual man’s step length is less than 1.9 feet.
I can’t remember how to solve this?
Answer:
Step-by-step explanation:
[tex]\frac{(5.27+x)}{2} =-4.51[/tex],[tex]\frac{8.21+y}{2} = 1.37[/tex]
(3.75,-5.47)
Marco can paddle his canoe at a rate of 6 miles per hour on unmoving water. However, today Marco is canoeing down (with the current), and then back up (against the current), a river that's moving at a rate of 1 mile per hour, so the current affects his rate of speed. If it takes Marco 6 total hours to go x miles downstream and then return to his starting point, how far downstream does he travel?
A) 1.25 miles
B) 2.5 miles
C) 5 miles
D) 17.5 miles
Answer:
S = v1 t1 = 7 t1 traveling downstream
S = v2 t2 = 5 t2 traveling upstream
7 t1 = 5 t2
7 (6 - t2) = 5 t2 since t1 + t2 = 6
42 - 7 t2 = 5 t2
t2 = 42 / 12 = 3.5 hrs so t1 = 2.5 hrs
S = 7 t1 = 7 * 2.5 = 17.5 mi
Also, S = 5 t2 = 5 * 3.5 = 17.5 mi
what graph shows the solution to the equation below log3(x+2)=1
Answer:
The solution to the equation log3(x+2)=1 is given by x=1
Step-by-step explanation:
We are given that
[tex]log_3(x+2)=1[/tex]
We have to find the graph which shows the solution to the equation log3(x+2)=1.
[tex]log_3(x+2)=1[/tex]
[tex]x+2=3^1[/tex]
Using the formula
[tex]lnx=y\implies x=e^y[/tex]
[tex]x+2=3[/tex]
[tex]x=3-2[/tex]
[tex]x=1[/tex]
For two consecutive numbers, five times the number that is less is 3 more than 4 times the greater number, What are the numbers
This is due on 7/1/2021 at 8AM PST. Someone please help?
what is the slope of the function, represented by the table of values below?
A. -2
B. -3
C. -4
D. -6
Answer:
B. -3
Step-by-step explanation:
Given the data points below, compute the sum of squared errors for the regression equation
Y
=
2
+
3
X
.
X
0
3
7
10
Y
5
5
27
31
Answer:
The sum of squared errors for the regression equation is 62.
Step-by-step explanation:
The sum of squared errors can be computed as follows:
X Y Y* = 2 + 3X Y - Y* (Y - Y*)^2
0 5 2 3 9
3 5 11 -6 36
7 27 23 4 16
10 31 32 -1 1
20 68 68 0 62
From the above, we have:
Error = Y - Y*
Error^2 = (Y - Y*)^2
Sum of squared errors = Sum of Error^2 = Total of (Y - Y*)^2 = 62
Therefore, the sum of squared errors for the regression equation is 62.
solve the equation 11n - 17 = 49
Answer:
The correct answer is =6.
Step-by-step explanation:
Solution,
Given;
11−17=49
or,11n-17=49
or,11−17+17=49+17
or,11=66
or,n=66/11
#n=6
HOPE IT HELPED♥︎
find the h.c.f. if 84 and 72
Answer:
12
Step-by-step explanation:
First lets list all the factors of these numbers
72: 1,2 3,4,6,8,9,12,18,24,36,72
84: 1 , 2 , 3 ,4 , 6 , 7 , 12 , 14 , 21 , 28 , 42 , 84
Now lets find the biggest number that is a factor of both 84 and 72
as we can see the highest number that is the factor of both 84 and 72 is 12
12 is the hcf
The weights of certain machine components are normally distributed with a mean of 5.19 ounces and a standard deviation of 0.05 ounces. Find the two weights that separate the top 8% and the bottom 8%. These weights could serve as limits used to identify which components should be rejected
Answer:
The weight that separate the top 8% by 5.2605 and the weight that separate bottom 8% by 5.1195.
Step-by-step explanation:
We are given that
Mean,[tex]\mu=5.19[/tex]
Standard deviation,[tex]\sigma=0.05[/tex]
We have to find the two weights that separate the top 8% and the bottom 8%.
Let x1 and x2 the two weights that separate the top 8% and the bottom 8%.
Z-value for p-value =0.08 =[tex]-1.41[/tex]
For 8% bottom
[tex]Z=\frac{x_1-\mu}{\sigma}=-1.41[/tex]
[tex]\frac{x_1-5.19}{0.05}=-1.41[/tex]
[tex]x_1-5.19=-1.41\times 0.05[/tex]
[tex]x_1=-1.41\times 0.05+5.19[/tex]
[tex]x_1=5.1195[/tex]
For 8% top
p-Value=1-0.08=0.92
Z- value=1.41
Now,
[tex]\frac{x_2-5.19}{0.05}=1.41[/tex]
[tex]x_2-5.19=1.41\times 0.05[/tex]
[tex]x_2=1.41\times 0.05+5.19[/tex]
[tex]x_2=5.2605[/tex]
(x1,x2)=(5.1195,5.2605)
PLESE HELp ANYONE. SOLVE ABC. ROUND YOUR ANSWERS TO THE NEAREST HUNDREDTH IF NECESSARY
Answer:
C=25°
a=11
b=12
Step-by-step explanation:
Find angle c,since angles in a triangle add up to 180 and we know angleA andB angle C will be
65+90+C=180
C=180-155
C=25°
To find a
use trig ratios
tanA=opposite/adjacent
tan65=a/5
a=tan65×5
a=10.72 round off to 11
To find b
sinC=opposite/hypotenuse
sin25=5/b
sin25 b=5
b=11.8 or rather 12
Answer:
Step-by-step explanation:
First find side a and to find this calculate tan 65
Tan 65 = [tex]\frac{opposite \ side}{adjacent\ side}=\frac{a}{5}\\\\[/tex]
2.144 = a/5
a = 2.144 * 5
b² = a² + c²
= 121+25
= 146.
b = √146 = 12.08 = 12
a = 10.72 = 11
Now find Tan C
[tex]Tan \ C = \frac{5}{10.72}\\\\Tan \ C = 0.4664\\[/tex]
C = tan⁻¹ 0.4664
C = 25°
