Answer:
its number 2 and if its a mutable answers writ 3 also
The probabilities are: (i) P(A) = 1/6
(ii) P(B) = 38/55
(iii) P(A ∩ B) = 1/110
(iv) P(A|B) ≈ 0.00152
To calculate the probabilities, let's first find the total number of ways to choose 3 balls out of the 12 balls.
Total number of ways to choose 3 balls out of 12 = 12C3 = (12 * 11 * 10) / (3 * 2 * 1) = 220
(i) P(A): Probability that all three balls selected are red.
Number of ways to choose 3 red balls out of 7 red balls = 7C3 = (7 * 6 * 5) / (3 * 2 * 1) = 35
P(A) = Number of favorable outcomes / Total number of outcomes = 35 / 220 = 1/6
(ii) P(B): Probability that the sum of the numbers on the three balls is equal to 6.
The possible combinations that sum up to 6 are: (2, 2, 2), (2, 2, 1), and (1, 1, 3).
Number of ways to choose 3 balls such that their sum is 6:
- For (2, 2, 2), we have 1 choice for each color, so 1 * 1 * 1 = 1 way.
- For (2, 2, 1), we have 1 choice for each color, so 1 * 1 * 1 = 1 way.
- For (1, 1, 3), we have 6 choices for the first red ball (all are labeled '1'), 5 choices for the second red ball (since one '1' is already taken), and 5 choices for the green ball labeled '3', so 6 * 5 * 5 = 150 ways.
Total number of ways to choose 3 balls with sum 6 = 1 + 1 + 150 = 152
P(B) = Number of favorable outcomes / Total number of outcomes = 152 / 220 = 38/55
(iii) P(A ∩ B): Probability that all three balls selected are red and the sum of their numbers is equal to 6.
From the above calculations, we know that there are 1 way to choose (2, 2, 2) and 1 way to choose (2, 2, 1) such that all three balls are red and the sum is 6.
P(A ∩ B) = Number of favorable outcomes / Total number of outcomes = 2 / 220 = 1/110
(iv) P(A|B): Probability that all three balls selected are red, given that the sum of their numbers is equal to 6.
P(A|B) = P(A ∩ B) / P(B) = (1/110) / (38/55) = (1/110) * (55/38) ≈ 0.00152 (rounded to five decimal places).
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An educational psychologist wondered whether there was a relationship between the amount of academic pressure a high school student felt and their plans for college. They surveyed a random sample of 300 high school students throughout the country about their college plans and whether they felt academic pressure. Here are the responses and partial results of a chi-square test (expected counts appear below observed counts):
Chi-square test:
Planned years of college vs. feeling academic pressure now
O years Up to 4 years Up to 4 years More than 4 years Total
Yes 31 48 161 240
31.2 48 160.8
No 8 12 40 60
7.8 12 40.2
Total 39 60 201 300
They want to use these results to carry out a xạ test of independence. Assume that all conditions for inference were met. What are the values of the test statistic and P-value for their test?
What are the values of the test statistic and P-value for their test?
A. x² = 0.002;
0.001 < P-value < 0.0025
B. x² = 0.002;
P-value > 0.25
C. x² = 0.007;
0.005 < P-value < 0.01
D. x² = 0.007;
P-value > 0.25
Answer:
D. x² = 0.007;
P-value > 0.25
Step-by-step explanation:
The observed and expected values are given below :
Yes____31 48 161 ____240
______31.2 48 160.8
No ____ 8 12 40_____ 60
______7.8 12 40.2
Total __ 39 60 201 ___300
The Chisquare statistic, χ²:
Σ(Observed - Expected)²/ Expected
Chi-Squared Values:
0.00128205 __ 0 __ 0.000248756
0.00512821 __ 0 __ 0.000995025
(0.00128205 + 0 + 0.000248756 + 0.00512821 + 0 + 0.000995025 )
= 0.007654041
The degree of freedom = (row - 1) * (column - 1)
Degree of freedom = (2-1)*(3-1) = 1*2= 2
The Pvalue = 0.9962
Pvalue > 0.25
You are working as an office apprentice for the bksb Newcastle Arena. You are helping collect a customer satisfaction survey for the arena. Enter the following replies into the table below.
Answer:
Step-by-step explanation:
Solve:
n = 8
4
O n = 2
0 n = 12
Ô n = 24
0 n = 32
Answer:
1/4 n = 8
n = 8 * 4
n = 32
so option 4 i.e.
n = 32. is the ans
Answer:
n=32
Step-by-step explanation:
Given :
[tex]\frac{1}{4} n=8[/tex]
Now,
Value of n can be calculated as :
[tex]\frac{1}{4} n=8[/tex]
n=8×4
n=32
Therefore, option (D) is correct.
What is the standard form of 14587.25
Answer:
fourteen thousand five hundred and eighty seven point twenty five.
Step-by-step explanation:
The given number is 14587.25.
We need to write it in standard form.
7 is in ones place, 8 is in tens place, 5 is in hundreds place, 4 is in thousands place and 1 is in ten-thousands place.
So,
14587.25 = fourteen thousand five hundred and eighty seven point twenty five.
Can you solve this problem
Answer:
x = 18
Step-by-step explanation:
8 x 18 - 3 = 141
A rectangular Carrer has a perimeter of 240cm breadth of 50cm.What is it's length
Step-by-step explanation:
The perimeter of a rectangle is the length of all its 4 sides. Formula to calculate the perimeter of a rectangle is:
Perimeter of Rectangle = 2 × Length + 2 × Breadth
The perimeter can be represented using a model as below.
Perimeter = Length + Breadth + Length + Breadth
= 2 × Length + 2 × Breadth
Length + Breadth = Perimeter ÷ 2
Is 9/54 equivalent to 1/3
Answer: No.
Step-by-step explanation:
9/54 is equal to 1/6
Answer:
no, it is not
Step-by-step explanation:
9/54 can be simplified by dividing both sides by 3, getting 3/18. you can do this again and get 1/6. significantly smaller that l/3
Consider the expression 63+81 how can you use the distributive property and the gcf to find an equivalent expression?explain how you can check your answer
Step-by-step explanation:
63+81
gcf = 9
63÷9=7, 81÷9=9
so, 63+81 = (9×7)+(9×9)
= 9×(7+9)
63+81 = 144
9x(7+9) = 9×16 = 144
A bicycle shop owner offers five styles of mountain bikes for $450, $275, $675, $490, and $300. He wants to increase the mean price but keep the median price and range of prices the same. Suggest a new set of prices for the five styles
Answer:
275, 350, 450, 550, 675
Step-by-step explanation:
Arrange in order
275, 300, 450, 490, 675
range 275 to 675
median 450
mean 438
---------------------------
Raise 300 to 350
Raise 490 to 550
New set of prices
275, 350, 450, 550, 675
range 275 to 675 same
median 450 same
mean 460 increased
Answer:
One set of prices could be: {275,300,450,600,675}
Another set could be: {275,300,450,600,675}
There are many other solutions possible.
====================================================
Explanation:
A = {450, 275, 675, 490, 300}
B = {275, 300, 450, 490, 675}
Set A is the original set of values in the order they were given to you. Set B is the sorted version of set A from smallest to largest.
The mean is found by adding up the values and dividing by 5 (because there are five items in the set).
The mean is (275+300+450+490+675)/5 = 2190/5 = 438. The shopkeeper wants to increase the mean to something larger, but keep the median and range the same.
The median is the middle most number. In set B, we can see that is 450. So the median is 450. We want to keep the median the same at 450.
The range is the difference in min and max
range = max - min = 675-275 = 400
We want to keep the range at 400
---------------------------
There are a number of ways to increase the mean, while keeping the median and range the same.
Let's say we keep the min and max the same. In order to increase the mean, we need to increase the 490 (second largest value) to something larger. Let's bump that up to 600 for instance.
Recomputing the mean gets us
(275+300+450+600+675)/5 = 2300/5 = 460
The old mean was 438 and the new mean is now 460. The mean has increased. This is due to the larger price pulling on the mean to get the mean to increase.
The median is still 450 because it's still in the direct middle of set C
C = {275,300,450,600,675}
The range is still the same as well because we haven't changed the min and max.
---------------------------
So one possible set could be
C = {275,300,450,600,675}
We could also have
D = {275,400,450,500,675}
The difference is that the 300 bumped to 400, and the 600 dropped to 500. You should find that the median and range are the same, while the mean is 460.
There are many possible solutions here.
On a coordinate plane, a line goes through (negative 3, negative 3) and (negative 1, 5). What is the equation of the line parallel to the given line with an x-intercept of 4?
Answer:
4, -16
Step-by-step explanation:
i need to see the steps for simplifying 3(m-5)+m
Answer:
4m - 15
Step-by-step explanation:
a( x + y) = ax + ay
[tex]3( m - 5 ) + m\\\\3m - 15 + m \\\\4m - 15[/tex]
Answer:
4m-15
Step-by-step explanation:
Distrubite 3 through the parentheisis
3m-15+m
Collect like terms
4m-15
Solve the equation for x in terms of c.
2/3(cx+1/2)-1/4=5/2
Answer:
Step-by-step explanation:
The answer you have chosen is not correct. Let's walk through the simplification process, shall we?
Begin by adding over the 1/4, after you find the common denominator, that is. 5/2 with a denominator of 4 is 10/4:
[tex]\frac{2}{3}(cx+\frac{1}{2})=\frac{11}{4}[/tex] and then multiply both sides by the reciprocal of 2/3:
[tex]cx+\frac{1}{2}=\frac{33}{8}[/tex] then subtract the 1/2 in the form of 4/8 (common denominator and all...) to get
[tex]cx=\frac{29}{8}[/tex] and finally divide both sides by c to get
[tex]x=\frac{29}{8c}[/tex] That's choice C.
what'd the greatest common factor (GCF) for each pair of numbers. 25, 55 The GCE IS
Answer:
5
Step-by-step explanation:
5 l 25,55
l 5,11
find the area of the triangle 15cm, 18cm, 5cm
Answer:
38
Step-by-step explanation:
Answer:
[tex]32.62\:\mathrm{cm^2}[/tex]
Step-by-step explanation:
The area of a triangle with side lengths [tex]a[/tex], [tex]b[/tex], and [tex]c[/tex] is given by:
Let [tex]s=\frac{a+b+c}{2}[/tex] (semi-perimeter)
[tex]A=\sqrt{s(s-a)(s-b)(s-c)}[/tex]
We're given three side lengths with lengths 15 cm, 18 cm, and 5 cm. Therefore, the semi-perimeter, [tex]s[/tex], is equal to [tex]\frac{15+18+5}{2}=\frac{38}{2}=19[/tex].
Thus, the area of this triangle is:
[tex]A=\sqrt{19(19-18)(19-15)(19-5)},\\A=\sqrt{19\cdot 1\cdot 4\cdot 14},A=\sqrt{1064}=32.6190128606\approx \boxed{32.62\:\mathrm{cm^2}}[/tex]
Police response time to an emergency call is the difference between the time the call is first received by the dispatcher and the time a patrol car radios that it has arrived at the scene. Over a long period of time, it has been determined that the police response time has a normal distribution with a mean of 9.6 minutes and a standard deviation of 2.3 minutes. For a randomly received emergency call, find the following probabilities. (For each answer, enter a number. Round your answers to four decimal places.)
a. between 5 and 10 min
b. less than 5 min
c. more than 10 min
Answer:
a) 0.5447
b) 0.0228
c) 0.4325
Step-by-step explanation:
Normal Probability Distribution:
Problems of normal distributions can be solved using the z-score formula.
In a set with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the z-score of a measure X is given by:
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.
Normal distribution with a mean of 9.6 minutes and a standard deviation of 2.3 minutes.
This means that [tex]\mu = 9.6, \sigma = 2.3[/tex]
a. between 5 and 10 min
This is the p-value of Z when X = 10 subtracted by the p-value of Z when X = 5. So
X = 10
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
[tex]Z = \frac{10 - 9.6}{2.3}[/tex]
[tex]Z = 0.17[/tex]
[tex]Z = 0.17[/tex] has a p-value of 0.5675
X = 5
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
[tex]Z = \frac{5 - 9.6}{2.3}[/tex]
[tex]Z = -2[/tex]
[tex]Z = -2[/tex] has a p-value of 0.0228
0.5675 - 0.0228 = 0.5447 probability that a randomly received emergency call is between 5 and 10 minutes.
b. less than 5 min
p-value of Z when X = 5, which from item a), is 0.0228, so 0.0228 probability that a randomly received emergency call is of less than 5 minutes.
c. more than 10 min
1 subtracted by the p-value of Z when X = 10, which, from item a), is of 0.5675.
1 - 0.5675 = 0.4325
0.4325 probability that a randomly received emergency call is of more than 10 minutes.
What are the values of A, B, C, and D?
A = 0; B = 1; C = -3; D = 3
A = 0; B = 1; C = 3; D = -3
A = 1; B = 0; C = -3; D = 3
A = 1; B = 0; C = 3; D = -3
Don’t know real answer
The values of A, B, C and D are (d) A = 1, B = 0, C = 3 and D = -3
How to solve for A, B, C and D?From the question, we have:
x^3 + 8x - 3 = Ax^3 + 5Ax + Bx^2 + 5B + Cx + D
Collect like terms
x^3 + 8x - 3 = Ax^3 + Bx^2 + 5Ax + Cx + 5B + D
By comparing the coefficients, we have:
Ax^3 = x^3
Bx^2 = 0
5Ax + Cx = 8x
5B + D = -3
Remove the x factors
A = 1
B = 0
5A + C = 8
5B + D = -3
Substitute A = 1 in 5A + C = 8
5(1) + C = 8
Solve for C
C = 3
Substitute B = 0 in 5B + D = -3
5(0) + D = -3
Solve for B
D = -3
Hence, the values of A, B, C and D are (d) A = 1, B = 0, C = 3 and D = -3
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what is a bank statement
Step-by-step explanation:
a printed record of the balance in a bank account and the amounts that have been paid into it and withdrawn from it, issued periodically to the holder of the account.
The answer and how to find the answer
Answer:
x = 1.9
Step-by-step explanation:
Thanks to a theorem we can use this proportion
10.47 : 4.44 = 4.44 = x
x = (4.44^2)/10.47 = 1,882865 = 1.9
Question 7(Multiple Choice Worth 1 points)
(02.08 LC)
To follow appropriate safety procedures, what should soccer players wear?
Goggles
Helmets
Mouth pieces
Shin guards
Answer:
The answer is Mouth pieces
The piece of safety equipment that should be worn when painting a ceiling is safety goggles. The correct option is c.
What are safety goggles?Safety goggles are worn on the eyes. They are worn to get safety from sun, wind, and dust. If we work in a factory or some mechanical work, then goggles are must save eyes.
Here, we have,
When working with the ceiling, it has a chance to damage your eyes with the plaster and paint, so wearing safety goggles is necessary.
Thus, the correct option is c. safety goggles, in regard to being worn when painting a ceiling.
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Complete question:
Which of these pieces of safety equipment should be worn when painting a ceiling
a knee guards
b helmet
c safety goggles
d mouth guard
(a+b)²=hihihihihihihihiihihihi
Answer:
(a+b)²=a²+b²+2ab
Step-by-step explanation:
The square of sum of two terms is equal to the squared plus squared plus times product of and . In mathematics, the plus whole squared algebraic identity is called in three ways. The square of sum of two terms identity.
The top of the Boulder Dam has an angle of elevation of 1.2 radians from a point on the Colorado River. Measuring the angle of elevation to the top of the dam from a point 155 feet farther down river is 0.9 radi- ans; assume the two angle measurements are taken at the same elevation above sea level. How high is the dam?
Answer:
382.925 feets
Step-by-step explanation:
The solution diagram is attached below :
Converting radian measurement to degree :
radian angle * 180/π = degree angle
1.2 * 180/π = 68.755°
0.9 * 180/π = 51.566°
Height of dam is h:
Using trigonometry :
Tan θ = opposite / Adjacent
Tan 68.755° = h / x
h = x Tan 68.755° - - - (1)
Tan 51.566° = h / (155+x)
h = (155+x) tan 51.566° - - - (2)
Equate (1) and (2)
x Tan 68.755 = (155+x) Tan 51.566
x Tan 68.755 = 155tan 51.566 + x tan 51.566
x Tan 68.755 = 195.32311 + x Tan 51.566
x Tan 68.755 - x Tan 51.566 = 195.32311
x(tan 68.755 - tan 51.566) = 195.32311
x * 1.3120110 = 195.32311
1.3120110x = 195.32311
x = 195.32311 / 1.3120110
x = 148.87307
Using :
h = x Tan 68.755
h = 148.87307 * tan(68.755)
h = 382.92539
h = 382.925 feets
In a random sample of 150 customers of a high-speed internet provider, 63 said that their service had been interrupted one or more times in the past month. Find a 95% confidence interval for the proportion of customers whose service was interrupted one or more times in the past month.
Answer:
The correct answer is "0.3410, 0.4990".
Step-by-step explanation:
Given values are:
[tex]n=150[/tex]
[tex]p=\frac{63}{150}[/tex]
[tex]=0.42[/tex]
At 95% confidence interval,
C = 95%
z = 1.96
As we know,
⇒ [tex]E=z\sqrt{\frac{p(1-p)}{n} }[/tex]
By substituting the values, we get
[tex]=1.96\sqrt{\frac{0.42\times 0.58}{150} }[/tex]
[tex]=1.96\sqrt{\frac{0.2436}{150} }[/tex]
[tex]=0.0790[/tex]
hence,
The confidence interval will be:
= [tex]p \pm E[/tex]
= [tex]0.42 \pm 0.079[/tex]
= [tex](0.3410,0.4990)[/tex]
Which is equivalent to f/125)*? O 125+ 0 1254 125" C. 125/11
Answer:
I think choose (1)
[tex]125 ^{ \frac{1x}{3} } [/tex]
What is the value of the expression 3m-4.2 If m equals 2.1
Answer:
2.1
Step-by-step explanation:
Given :
3m-4.2 where, m=2.1
Now,
3(2.1)-4.2
6.3-4.2
2.1
Answer is 2.1
Receipt-of-goods discounts tend to be offered in cases where?
I WILL MARK BRAINLIEST TO WHOEVER ANSWERS CORRECTLY FIRST
Answer:
2 liter = 2000 ml
2000/250 = 8 bottles Step-by-step explanation:
Find the area of the composite figure.
Answer:
25m²
Step-by-step explanation:
it might be helpful for you
Ms. Harlow had 56 tickets. She gave 2 tickets to each of her 21 students.
Which set of equations shows how many tickets Mrs. Harlow had left?
21 x 2 = 42
OA)
56 - 42 = 14
56 - 21 = 35
ОВ)
35 - 2 = 33
21 x 2 = 42
OC)
56 + 42 = 98
56 - 21 = 35
OD)
35 + 2 = 37
Answer: 56 - 42
Step-by-step explanation: She gave 2 to EACH of her 21 students. So 2 * 21 = 42. 56 - 42
A box has two balls, one white and one red. We select one ball, put it back in the box, and select a second ball (sampling with replacement). Find the probability of the following events:
a. Let F = the event of getting the white ball twice.
b. Let G = the event of getting two balls of different colors.
c. Let H = the event of getting white on the first pick.
d. Are F and G mutually exclusive?
e. Are G and H mutually exclusive?
Answer:
See explanation
Step-by-step explanation:
Given
Represent the balls with the first letters
[tex]W =1[/tex]
[tex]R =1[/tex]
Solving (a): P(F) --- White balls twice
The event of F is:
[tex]F = \{(W,W)\}[/tex]
So:
[tex]P(F) = P(W) * P(W)[/tex]
[tex]P(F) = \frac{n(W)}{n} * \frac{n(W)}{n}[/tex]
[tex]P(F) = \frac{1}{2} * \frac{1}{2}[/tex]
[tex]P(F) = \frac{1}{4}[/tex]
Solving (b): P(G) --- two different colors
The event of G is:
[tex]G = \{(W,R),(R,W)\}[/tex]
So:
[tex]P(G) = P(W) * P(R) + P(R) * P(W)[/tex]
[tex]P(G) = \frac{n(W)}{n} * \frac{n(R)}{n} + \frac{n(R)}{n} * \frac{n(W)}{n}[/tex]
[tex]P(G) = \frac{1}{2} * \frac{1}{2} + \frac{1}{2} * \frac{1}{2}[/tex]
[tex]P(G) = \frac{1}{4} + \frac{1}{4}[/tex]
[tex]P(G) = \frac{1}{2}[/tex]
Solving (c): P(H) --- White picked first
The event of H is:
[tex]H = \{(W,R),(W,W)\}[/tex]
So:
[tex]P(H) = P(W) * P(R) + P(W) * P(W)[/tex]
[tex]P(H) = \frac{n(W)}{n} * \frac{n(R)}{n} + \frac{n(W)}{n} * \frac{n(W)}{n}[/tex]
[tex]P(H) = \frac{1}{2} * \frac{1}{2} + \frac{1}{2} * \frac{1}{2}[/tex]
[tex]P(H) = \frac{1}{4} + \frac{1}{4}[/tex]
[tex]P(H) = \frac{1}{2}[/tex]
Solving (d): F and G, mutually exclusive?
We have:
[tex]F = \{(W,W)\}[/tex]
[tex]G = \{(W,R),(R,W)\}[/tex]
Check for common elements
[tex]n(F\ n\ G) = 0[/tex]
Hence, F and G are mutually exclusive
Solving (e): G and G, mutually exclusive?
We have:
[tex]G = \{(W,R),(R,W)\}[/tex]
[tex]H = \{(W,R),(W,W)\}[/tex]
Check for common elements
[tex]n(G\ n\ H) = 1[/tex]
Hence, F and G are not mutually exclusive
Given the quadriceps function ,y=ax2+bc+c what happens to the graph when "a" is a positive?
Answer:
When "a" is positive, the parabola opens upwards and the vertex is the minimum value.
Step-by-step explanation:
