Answer:
20
Step-by-step explanation:
Multiply 4/7 with 35, this will get you 140/7, which simplifies to 20 employees
Solve for x. round to the nearest tenth, if necessary.
Answer:
29
Step-by-step explanation:
all in all it is 180 so 61 + m (which is 90 because it is a right angle)=151
then 180-151=29
Given a right triangle with an acute angle Θ , if sin Θ = cos Θ , describe what this triangle would look like.
For sinø = cosø, ø = 45°. Because it is right, it is also a right, isosceles triangle
What is the solution to this equation?
log_8 16 + 2log_8x =2
The value of x for the given equation [tex]log_{8}[/tex](16) + 2[tex]log_{8}[/tex](x) = 2 will be 2 so option (B) must be correct.
What is a logarithm?The exponent indicates the power to which a base number is raised to produce a given number called a logarithm.
In another word, a logarithm is a different way to denote any number.
Given the equation
[tex]log_{8}[/tex](16) + 2[tex]log_{8}[/tex](x) = 2
We know that,
xlogb = log[tex]b^{x}[/tex]
So,
2[tex]log_{8}[/tex](x) = logx²
For the same base
logA + logB = log(AB)
So,
[tex]log_{8}[/tex](16) + [tex]log_{8}[/tex](x)² = 2
[tex]log_{8}[/tex](16x²) = 2
We know that
[tex]log_{a}[/tex](b) = c ⇒ b = [tex]a^{c}[/tex]
so,
[tex]log_{8}[/tex](16x²) = 2 ⇒ 8² = 16x²
x = 2 hence x = 2 will be correct answer.
For more about logarithm
https://brainly.com/question/20785664
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Can someone help me in this plz
Answer:
a =2 5
b =50
Step-by-step explanation:
What is the tangent ratio of angle x?
tan x= 20/21
tan x= 21/29
tan x= 20/29
tan x= 21/20
Answer:
[tex]\tan x=21/20[/tex]
Step-by-step explanation:
In any right triangle, the tangent of an angle is equal to its opposite side divided by its adjacent side. (o/a)
For angle [tex]x[/tex], its opposite side is 21 feet and its adjacent side is 20 feet. Therefore, we have:
[tex]\boxed{\tan x=21/20}[/tex]
Be sure to show your work and solve for e:
17 + e + 11 = 56
Hi I need help with this question please!!! I don’t understand it :/
Answer:
- 22.5
Step-by-step explanation:
Substitute x = 3 into f(x) and x = 16 into h(x) , then
[tex]\frac{1}{2}[/tex] g(3) - h(16)
= [tex]\frac{1}{2}[/tex] × - 3(3)² - (2[tex]\sqrt{16}[/tex] + 1)
= [tex]\frac{1}{2}[/tex] × - 3(9) - (2(4) + 1)
= [tex]\frac{1}{2}[/tex] × - 27 - (8 + 1)
= - 13.5 - 9
= - 22.5
What is the range of g ( x ) = 3x − 2, if the domain is { − 1, 0, 1, 2 }?
Answer:
range{-5,4)
Step-by-step explanation:
3(-1)-2= -5
3(2)-2=4
ZEFG and ZGFH are a linear pair, mZEFG = 2n + 16, and mZGFH = 3n+24. What are mZEFG and mZGFH?
mZEFG =
Answer:
m<EFG = 72°
m<GFH = 108°
Step-by-step explanation:
m<EFG = 2n + 16
m<GFH = 3n + 24
Linear pairs are supplementary, therefore,
m<EFG + m<GFH = 180°
Substitute
2n + 16 + 3n + 24 = 180
Add like terms
5n + 40 = 180
5n + 40 - 40 = 180 - 40 (subtraction property of equality)
5n = 140
5n/5 = 140/5 (division property of equality)
n = 28
✔️m<EFG = 2n + 16
Plug in the value of n
m<EFG = 2(28) + 16 = 72°
✔️m<GFH = 3n + 24
Plug in the value of n
m<GFH = 3(28) + 24 = 108°
What is a graph of g(x)=(2/3)x-2?
The graph above or below should answer the question.
A ball is thrown into the air. The path it takes is modeled by the equation: -3t+24t = h, where t is the time in seconds and h is the height of the ball above the ground, measured in feet. Write an inequality to model when the height of the ball is at least 36 feet above the ground. For how long is the ball at or above 36 feet?
Given:
The given equation is:
[tex]-3t^2+24t=h[/tex]
Where, t is the time in seconds and h is the height of the ball above the ground, measured in feet.
To find:
The inequality to model when the height of the ball is at least 36 feet above the ground. Then find time taken by ball to reach at or above 36 feet.
Solution:
We have,
[tex]-3t^2+24t=h[/tex]
The height of the ball is at least 36 feet above the ground. It means [tex]h\geq 36[/tex].
[tex]-3t^2+24t\geq 36[/tex]
[tex]-3t^2+24t-36\geq 0[/tex]
[tex]-3(t^2-8t+12)\geq 0[/tex]
Splitting the middle term, we get
[tex]-3(t^2-6t-2t+12)\geq 0[/tex]
[tex]-3(t(t-6)-2(t-6))\geq 0[/tex]
[tex]-3(t-2)(t-6)\geq 0[/tex]
The critical points are:
[tex]-3(t-2)(t-6)=0[/tex]
[tex]t=2,6[/tex]
These two points divide the number line in 3 intervals [tex](-\infty,2),(2,6),(6,\infty)[/tex].
Intervals Check point [tex]-3(t-2)(t-6)\geq 0[/tex] Result
[tex](-\infty,2)[/tex] 0 [tex](-)(-)(-)=(-)<0[/tex] False
[tex](2,6)[/tex] 4 [tex](-)(+)(-)=+>0[/tex] True
[tex](6,\infty)[/tex] 8 [tex](-)(+)(+)=(-)<0[/tex] False
The inequality is true for (2,6) and the sign of inequality is [tex]\geq[/tex]. So, the ball is above 36 feet between 2 to 6 seconds.
[tex]6-2=4[/tex]
Therefore, the required inequality is [tex]-3t^2+24t\geq 36[/tex] and the ball is 36 feet above for 4 seconds.
-2/3a+5/6a-1/5a-1/6
Answer:
[tex]\frac{-1}{30} a - \frac{1}{6}[/tex]
Step-by-step explanation:
Solve the equation sine Ф=0.6792 for 0°≤Ф≤360
Answer:
42.78⁹, 137.22⁹.
Step-by-step explanation:
sine Ф=0.6792
Angle Ф in the first quadrant = 42.78 degrees.
The sine is also positive in the second quadrant so the second solutio is
180 - 42.78
= 137.33 degres.
An object is launched at 19.6 meters per second (m/s) from a 58.8-meter tall platform. The equation for the
object's height s at time t seconds after launch is s(t) = - 4.9t2 + 19.6t + 58.8, where s is in meters. Create a
table of values and graph the function. Approximately what is the maximum height that the object will get?
O 76.4 meters
113.5 meters
O 78.4 meters
58.8 meters
Answer:
Step-by-step explanation:
The easiest way to do this is to complete the square on the quadratic. This allows us to see what the vertex is and answer the question without having to plug in a ton of numbers to see what the max y value is. Completing the square will naturally put the equation into vertex form:
[tex]y=-a(x-h)^2+k[/tex] where h will be the time it takes to get to a height of k.
Begin by setting the quadratic equal to 0 and then moving over the constant, like this:
[tex]-4.9t^2+19.6t=-58.8[/tex] and the rule is that the leading coefficient has to be a 1. Ours is a -4.9 so we have to factor it out:
[tex]-4.9(t^2-4t)=-58.8[/tex] Now take half the linear term, square it, and add it to both sides. Our linear term is a -4, from -4t. Half of -4 is -2, and -2 squared is 4, so we add a 4 to both sides. BUT on the left we have that -4.9 out front there as a multiplier, so we ACTUALLY added on to the left was -4.9(4) which is -19.6:
[tex]-4.9(t^2-4t+4)=-58.8-19.6[/tex] and now we have to clean this up. The right side is easy, that is -78.4. The left side...not so much.
The reason we complete the square is to create a perfect square binomial, which is the [tex](x-h)^2[/tex] part from above. Completing the square does this naturally, now it's just up to us to write the binomial created during the process:
[tex]-4.9(t-2)^2=-78.4[/tex] Now, move the constant back over and set the equation back equal to y:
[tex]-4.9(t-2)^2+78.4=s(t)[/tex] and we see that the vertex is (2, 78.4). That means that 2 seconds after launch, the object reached its max height of 78.4 meters, the third choice down.
How do I solve this math equation: 7=8-p
Answer:
p = 1
Step-by-step explanation:
7 = 8 - p
7 + p = 8
p = 8-7
p = 1
Answered by Gauthmath
HEELLLPPPPPP what’s the answer????????????????????????? HEELLLLLLLPPPPPPPPPPPPPP
Answer:
(-2,-2)
Step-by-step explanation:
x^2 + y^2 = 9
A circle has an equation of the form
(x-h)^2 + (y-k)^2 = r^2
where the center is at ( h,k) and the radius is r
The circle is centered at (0,0) and has a radius 3
The only point entirely within the circle must have points less than 3
(-2,-2)
if x=2+√5 find the value of x²-1/x²
Answer:
[tex]{ \tt{ {x}^{2} - \frac{1}{ {x}^{2} } }} \\ = { \tt{ {(2 + \sqrt{5} )}^{2} - \frac{1}{ {(2 + \sqrt{5}) }^{2} } }} \\ = { \tt{ \frac{(2 + \sqrt{5} ) {}^{4} - 1}{ {(2 + \sqrt{5} )}^{2} } }} \\ = { \tt{ \frac{(9 + 4 \sqrt{5}) {}^{2} }{ {(9 + 4\sqrt{5}) }}}} \\ = { \tt{9 + 4 \sqrt{5} }}[/tex]
Answer:
[tex]8\sqrt{5}[/tex]
Step-by-step explanation:
[tex]x = 2 + \sqrt{5}\\\\ x^{2} = (2+ \sqrt{5})^{2} \\\\ \ \ \ \ = 2^{2}+2* \sqrt{5}*2+( \sqrt{5})^{2}\\\\[/tex]
[tex]= 4 + 4 \sqrt{5}+5\\\\= 9+4 \sqrt{5}[/tex]
[tex]\frac{1}{x^{2}}=\frac{1}{9+4\sqrt{5}}\\\\=\frac{1*(9-4\sqrt{5}}{(9+4\sqrt{5})(9-4\sqrt{5})}\\\\=\frac{9-4\sqrt{5}}{9^{2}-(4\sqrt{5})^{2}}\\\\=\frac{9-4\sqrt{5}}{81-4^{2}(\sqrt{5})^{2}}\\\\=\frac{9-4\sqrt{5}}{81-16*5}\\\\=\frac{9-4\sqrt{5}}{81-80}\\\\=\frac{9-4\sqrt{5}}{1}\\\\=9-4\sqrt{5}[/tex]
[tex]x^{2}-\frac{1}{x^{2}}= 9 + 4\sqrt{5} -(9 - 4\sqrt{5})\\\\[/tex]
[tex]= 9 + 4\sqrt{5} - 9 + 4\sqrt{5}\\\\= 9 - 9 + 4\sqrt{5} + 4\sqrt{5}\\\\= 8\sqrt{5}[/tex]
Help, please, I'll give brainliest
find the measure of acute angle of a right angle triangle when one angle is 60°
Answer:
30 degrees.
Step-by-step explanation:
Let the acute angle be x.
Then as the 2 acute angles in a right triangle sum to 90 degrees,
x = 90 - 60
= 30.
We used the information we know to give us this equation.
90°+60°+x=180°
We add 90° and 60° to give 150°
150°+x=180°
x must therefore be 30°Multiply. (Use photo). Enter your answer in simplest radical form.
Answer:
72√2
Step-by-step explanation:
3√2 × 2√8 × √3 × √6
The above can be simplified as follow:
3√2 × 2√8 × √3 × √6
Recall
a√c × b√d = (a×b)√(c×d)
3√2 × 2√8 × √3 × √6 = (3×2)√(2×8×3×6)
= 6√288
Recall
288 = 144 × 2
6√288 = 6√(144 × 2)
Recall
√(a×b) = √a × √b
6√(144 × 2) = 6 × √144 × √2
= 6 × 12 × √2
= 72√2
Therefore,
3√2 × 2√8 × √3 × √6 = 72√2
SEE QUESTION IN IMAGE
Answer:
Step-by-step explanation:
[tex]Mean=\frac{all.ages.added.together.of.all.kids}{total.number.of.kids}[/tex] Hopefully, that makes sense! To get the numerator of that problem, we take the number of kids and multiply it by the corresponding age and add them all together. To get the denominator, we add the total number of kids together. That will look like this mathematically, setting the mean equal to 14.44, as stated:
[tex]14.44=\frac{13(15)+14(42)+15X+16(10)+17(3)}{15+42+X+10+3}[/tex] and simplify that a bit to
[tex]14.44=\frac{195+588+15X+160+51}{70+X}[/tex] and a bit more to
[tex]14.44=\frac{994+15X}{70+X}[/tex] and cross multiply
14.44(70 + X) = 994 + 15X and
1010.8 + 14.44X = 994 + 15X and
16.8 = .56X so
X = 30
30 kids are 15 years old for the mean age to be 14.44
d.30
Answer:
Solution given:
x. [tex] \:\:\:[/tex] f. [tex] \:\:\:[/tex] fx
13. [tex] \:\:\:[/tex] 15. [tex] \:\:\:[/tex] 195
14.[tex] \:\:\:[/tex] 42 [tex] \:\:\:[/tex] 588
15. [tex] \:\:\:[/tex] x. [tex] \:\:\:[/tex] 15x
16. [tex] \:\:\:[/tex] 10. [tex] \:\:\:[/tex] 160
17. [tex] \:\:\:[/tex] 3. [tex] \:\:\:[/tex] 51
. n=70+x. [tex]\sum[/tex]=994+15x
we have
mean=sum/n
14.44=[tex]\bold{\frac{\sum}{n}}[/tex]
14.44=[tex]\bold{\frac{994+15x}{70+x}}[/tex]
doing crisscrossed multiplication
(70+x)*14.44=994+15x
1010.8+14.44x=994+15x
15x-14.44x=1010.8-994
0.56x=16.8
x=16.8/0.56
x=30
Parallelogram PARL is similar to parallelogram WXYZ. If AP = 7, PL = 15, and WZ = 45, find the value of c.
Answer:
c = 21
Step-by-step explanation:
**I assume that side WX in my diagram (attached as an image below) is the value of C that we're looking for. ALSO, the sizes and lengths of the parallelograms are NOT to scale.**
If two parallelograms are similar, that means the lengths of the corresponding sides have EQUAL ratios.
PL corresponds with WZ. To get from 15 to 45, you would multiply 15 by 3, so the ratio of the legnths of the corresponding sides between these two parallelograms is 1:3.
With that in mind, we can apply this ratio to find WX.
We know that AP has a length of 7, so we will multiply that by 3, getting a value of 21, and 7:21 ratio is the same as 1:3.
c = 21
Hope this helps (●'◡'●)
If a = 1/2, then a^2=
(A) -1
(B) 4
(C) 0
(D) 1
Answer:
1/4
Step-by-step explanation:
a^2
Let a= 1/2
(1/2)^2
(1/4)
[tex]\huge\textsf{Hey there!}[/tex]
[tex]\mathsf{a^2}\\\\\mathsf{= \ (\dfrac{1}{2})^2}\\\\\mathsf{= \ \dfrac{1}{2}\times\dfrac{1}{2}}\\\\\mathsf{= \ \dfrac{1\times1}{2\times2}}\\\\\mathsf{= \ \bf \dfrac{1}{4}}[/tex]
[tex]\boxed{\boxed{\large\textsf{Therefore, the ANSWER is: }\boxed{\mathsf{\bf \dfrac{1}{4}}}}}\huge\checkmark[/tex]
[tex]\huge\textsf{Good luck on your assignment \& enjoy your day!}[/tex]
~[tex]\frak{Amphitrite1040:)}[/tex]
help asap! what does sinø=
Answer:
-3/5
Step-by-step explanation:
Pythagorean formula :
x^2 + y^2 = r^2
(-8)^2 + (-6)^2 = r^2
64 + 36 = 100
r^2 = 100
r= 10
sin is the y coordinate over the radius :
-6/10
-3/5
What is the equation of the line of reflection? please help, due in 30 minutes!!!
Answer:
The line of reflection is usually given in the form y = m x + b y = mx + b y=mx+by, equals, m, x, plus, b.
Step-by-step explanation:
Answer:
The line of reflection in [tex]y=mx+b[/tex] form is [tex]y=\frac{1}{3} x-2[/tex]
Step-by-step explanation:
Please I need some help!
Answer:
A
Step-by-step explanation:
A compressed by a factor of 1/4 in the y or vertical direction
HHHHELP ME!!!!!! PLZ
Total gasoline = 10 gallons
Gasoline left after 100 miles = 5 gallons
Gasoline used in 100 miles
= Total gasoline - Gasoline left after 100 miles
= 10 gallons - 5 gallons
= 5 gallons
Gasoline used in 1 mile
= Gasoline used in 100 miles/100
= 5 gallons/100
= 0.05 gallons
Pls help me this is my homework
Answer:
C) 840
C) 87
D) 3000-150n
Step-by-step explanation:
Answer:
c
c
d
Step-by-step explanation:
Find the slope between (-2,-2) and (0,-3)
Answer:
Step-by-step explanation:
x1 y1 x2 y2
-2 -2 0 3
ΔY 5
ΔX 2
slope= 2 1/2
B= 3
Y =2.5X +3
4.Find the first five terms of the recursive sequence
Answer:
5, 12, 19, 26, 33
Step-by-step explanation:
Using the recursive rule and a₁ = 5 , then
a₂ = a₁ + 7 = 5 + 7 = 12
a₃ = a₂ + 7 = 12 + 7 = 19
a₄ = a₃ + 7 = 19 + 7 = 26
a₅ = a₄ + 7 = 26 + 7 = 33
The first 5 terms are 5, 12, 19, 26, 33