In a certain Algebra 2 class of 21 students, 12 of them play basketball and 14 of them
play baseball. There are 5 students who play neither sport. What is the probability
that a student chosen randomly from the class plays basketball or baseball?​

Answers

Answer 1

Answer:

Explanation:

We know there are 21 students in all, so that should be the denominator in this answer.

Then, to find the numerator, we need to find the number of students that play basketball and the number of students that play baseball, assuming that none of them play both sports. Just add those two numbers to get the numerator, and then put it on top of the 21.

You either typed this question incorrectly, or there is a mistake, because there are more kids that play basketball or baseball than there are students in the class.


Related Questions

Which areas does acid rain most likely form before rain

Answers

In the clouds
I think

The dnsity of aluminum is 2. 70 g/mL. if the mass of a piece of aluminum is 244 grams, what is the volume of the aluminum

Answers

27.0 g

Explanation:
The density of a substance tells you the mass of exactly one unit of volume of said substance.
In your case, aluminium is said to have a density of
density Al
=
2.70 g
.
cm

3
This tells you that every
1 mL
of aluminium has a mass of
2.70 g
.
All you have to do now is use the density of aluminium as a conversion factor to go from cubic centimenters of aluminium to grams
10.0
cm
3

2.70 g
1
cm
3
=
27.0 g
−−−−−
The answer is rounded to three sig figs.

[tex]3x + 2y + 2z = 19\\3x + y + z = 14\\[/tex]
If the equations above are true, which of the following is the value of y + z?

(A.) -5
(B.) -4
(C.) 0
(D.) 4
(E.) 5

Answers

Answer:

The answer is E

Explanation:

Before we find the value of 5, let's find x by using the elimination process for the two given equation.

2(3x + y + z = 14) → 6x + 2y + 2z = 28

3x + 2y + 2z = 19

-6x + 2y + 2z = 28

-3x = -9

x = 3

Now plug in 3 into both of the given equations, which will give you your new equation, then subtract them:

3(3) + 2y + 2z = 19 → 9 + 2y + 2z = 19

3(3) + y + z = 14 →   - 9 + y + z = 14

Our answer is: y + z = 5

Our value is 5

Optional: If you want to make sure it's 5, plug-in any random numbers for y and z that equals 5. For example: 3 + 2, 1 + 4, 5 + 0, 6 + (-1), etc...

Once you choose the numbers you can plug them into the two new given equations. For me, I decided to let y = 1 and z = 4:

9 + 2(1) + 2(4) = 19     9 + (1) + (4) = 14

9 + 2 + 8 = 19            9 + 1 + 4 = 14

19 = 19                       14 = 14

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