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Answer:

Below,...

Step-by-step explanation:

Your equation:

[tex]\frac{63}{7-(2*3)} =\frac{63}{7-6} =\frac{63}{1}=63[/tex]

Hope it helps,... Chow,...!

Answer:

Each child will receive eight fifths of the cupcakes.

5x=8 ; x represents how many cupcakes each child receives.

[tex]\frac{8}{5}[/tex]

Step-by-step explanation:

There are 8 cupcakes in total.

5 children.

Divide 8 by 5. [tex]\frac{8}{5}[/tex]

I hope this helps!

pls ❤ and mark brainliest pls!

Answer:

After 5 seconds

Step-by-step explanation:

One is given the following expression to model to the flight path of a ball:

[tex]h=-16t^2+80t[/tex]

In this problem, one is asked to find the time at which the ball lands on the ground. The easiest way to do so is to factor the expression. Take out factors that both terms have in common. The one will set the equation equal to zero, as this is the height at which one wants to find the time for. Finally, use the zero product property to solve. The zero product property states that any number times zero equals zero. Apply these ideas to the given function:

[tex]h=-16t^2+80t[/tex]

Factor the expression; both terms have a common factor of (-16t):

[tex]h=-16t^2+80t[/tex]

[tex]h=-16t(t-5)[/tex]

Set the equation equal to zero to solve for when the ball has a height of zero or rather lands on the ground:

[tex]h=-16t(t-5)[/tex]

[tex]0=-16t(t-5)[/tex]

Now use the zero product property, this states that any number times zero equals zero. Set each of the factors equal to zero, and solve to find the value of (t) for which the factor will equal zero:

[tex]0=-16t(t-5)[/tex]

[tex]0=-16t[/tex]                          [tex]t - 5 =0[/tex]

Solve for the value (t) using inverse operations,

[tex]0=-16t[/tex]                            [tex]t - 5 =0[/tex]

(divide by (-16)                   (add (5))

[tex]0=t[/tex]                                     [tex]t=5[/tex]

As one can see, the ball started on the ground, therefore at (0) seconds, its height was (0). Then, after (5) seconds the ball landed on the ground, therefore, after (5) seconds its height was again (0).

Answer:

17/30 (0.56)

Step-by-step explanation:

18/20-4/12

Reduce the fraction with 2 and 4: 9/10-1/3

Write all numerators above the least commmon denominator 30: 27-10/30

Subtract: 27-10/30 = 17/30

Answer:

$17.25

Step-by-step explanation:

The tip is 15% of $15.00, or 0.15 * 15 = $2.25

We add that to the meal's cost, which is $15.00

15.00 + 2.25 = 17.25

Answer:

purple.orang.blue.yellow and green

purple.orang.blue.yellow and green

Answer:

Im not certain but I think 7.5% If you get another answer which is different trust them not me if u get one which is the same it should be correct

The interest rate was 7.5% when borrowing $600 for one year and paying $45.00 interest.

Simple interest is defined as interest paid on the original principal and calculated with the following formula:

S.I. = P × R × T, where P = Principal, R = Rate of Interest in % per annum, and T = Time, usually calculated as the number of years. The rate of interest is in percentage r% and is to be written as r/100.

We have been given data as:

Principal (P) = $600

Time (T) = 1 year

Simple interest = $45.00

⇒ Simple interest = P × R × T

Substitute the value of P, and T in the above formula, and solve for R

⇒ 45.00 = 600 × R × 1

⇒ 45.00 = 600R

⇒ R = 45.00/600

⇒ R = 0.075

⇒ R = 7.5/100

⇒ R = 7.5%

Therefore, the interest rate was 7.5%.

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Answer:

semoga jawapan ini dapat membantu

Answer:

a= 11.55

Step-by-step explanation:

If the answer is 8.45, then the variable equals the difference of 20 minus the answer, 8.45

Hope this helps!

Answer:

[tex]tan(\theta)=\frac{\sqrt{21}}{3}[/tex]

Step-by-step explanation:

1. Approach

One is given the following information:

[tex]cos(2\theta)=-\frac{2}{5}[/tex]

One can rewrite this as:

[tex]cos(2\theta)=-0.4[/tex]

Also note, the problem says that the angle ([tex]2\theta[/tex]) is found in the third quadrant.

Using the trigonometric identities ([tex]cos(2\theta)=2(cos^2(\theta))-1[/tex]) and ([tex]cos(2\theta)=1-2(sin^2(\theta))[/tex]) one can solve for the values of ([tex]cos(\theta)[/tex]) and ([tex]sin(\theta)[/tex]). After doing so one can use another trigonometric identity ([tex]tan(\theta)=\frac{sin(\theta)}{cos(\theta)}[/tex]).  Substitute the given information into the ratio and simplify.

2. Solve for [tex](cos(\theta))[/tex]

Use the following identity to solve for ([tex]cos(\theta)[/tex]) when given the value ([tex]cos(2\theta)[/tex]).

[tex]cos(2\theta)=2(cos^2(\theta))-1[/tex]

Substitute the given information in and solve for ([tex]cos(\theta)[/tex]).

[tex]cos(2\theta)=2(cos^2(\theta))-1[/tex]

[tex]-0.4=2(cos^2(\theta))-1[/tex]

Inverse operations,

[tex]-0.4=2(cos^2(\theta))-1[/tex]

[tex]0.6=2(cos^2(\theta))[/tex]

[tex]0.3=cos^2(\theta)[/tex]

[tex]\sqrt{0.3}=cos(\theta)[/tex]

Since this angle is found in the third quadrant its value is actually:

[tex]cos(\theta)=-\sqrt{0.3}[/tex]

3. Solve for [tex](sin(\theta))[/tex]

Use the other identity to solve for the value of ([tex]sin(\theta)[/tex]) when given the value of ([tex]cos(2\theta)[/tex]).

[tex]cos(2\theta)=1-2(sin^2(\theta))[/tex]

Substitute the given information in and solve for ([tex]sin(\theta)[/tex]).

[tex]cos(2\theta)=1-2(sin^2(\theta))[/tex]

[tex]-0.4=1-2(sin^2(\theta))[/tex]

Inverse operations,

[tex]-0.4=1-2(sin^2(\theta))[/tex]

[tex]-1.4=-2(sin^2(\theta))[/tex]

[tex]0.7=sin^2(\theta)[/tex]

[tex]\sqrt{0.7}=sin(\theta)[/tex]

Since this angle is found in the third quadrant, its value is actually:

[tex]sin(\theta)=-\sqrt{0.7}[/tex]

4. Solve for [tex](tan(\theta))[/tex]

One can use the following identity to solve for [tex](tan(\theta))[/tex];

[tex]tan(\theta)=\frac{sin(\theta)}{cos(\theta)}[/tex]

Substitute the values on just solved for and simplify,

[tex]tan(\theta)=\frac{sin(\theta)}{cos(\theta)}[/tex]

[tex]tan(\theta)=\frac{-\sqrt{0.7}}{-\sqrt{0.3}}[/tex]

[tex]tan(\theta)=\frac{\sqrt{0.7}}{\sqrt{0.3}}[/tex]

[tex]tan(\theta)=\frac{\sqrt{\frac{7}{10}}}{\sqrt{\frac{3}{10}}}[/tex]

Rationalize the denominator,

[tex]tan(\theta)=\frac{\sqrt{\frac{7}{10}}}{\sqrt{\frac{3}{10}}}[/tex]

[tex]tan(\theta)=\frac{\sqrt{\frac{7}{10}}}{\sqrt{\frac{3}{10}}}*\frac{\sqrt{\frac{3}{`0}}}{\sqrt{\frac{3}{10}}}[/tex]

[tex]tan(\theta)=\frac{\sqrt{\frac{7}{10}*\frac{3}{10}}}{\sqrt{\frac{3}{10}*\frac{3}{10}}}[/tex]

[tex]tan(\theta)=\frac{\sqrt{\frac{21}{100}}}{\frac{3}{10}}[/tex]

[tex]tan(\theta)=\frac{\frac{\sqrt{21}}{10}}{\frac{3}{10}}[/tex]

[tex]tan(\theta)=\frac{\sqrt{21}}{10}*\frac{10}{3}[/tex]

[tex]tan(\theta)=\frac{\sqrt{21}}{3}[/tex]

Answer:

43.4 yd

Step-by-step explanation:

[tex]45^{2}[/tex]-[tex]12^{2}[/tex]

2025-144=1881

[tex]\sqrt{1881}[/tex]

43.37049

43.4

Answer:

5(x+4)

Step-by-step explanation:

It's basically asking for the sum of a number and four to be multiplied by 5. Since the sum is made up of the unknown number and four, you'd put four and the unknown number in parenthesis while putting five on the outside, making it 5(x+4).

Answer:

y = 1/3mx + b

Step-by-step explanation:

x = 3(y - b)/m

~Multiply m to both sides

mx = -3b + 3y

~Add 3b to both sides

mx + 3b = 3y

~Divide everything by 3

1/3mx + b = y

y = 1/3mx + b

Best of Luck!

[tex]\\ \rm\longmapsto x=\dfrac{3(y-b)}{m}[/tex]

[tex]\\ \rm\longmapsto mx=3(y-b)[/tex]

[tex]\\ \rm\longmapsto mx=3y-3b[/tex]

[tex]\\ \rm\longmapsto 3y=mx+3b[/tex]

[tex]\\ \rm\longmapsto y=\dfrac{1}{3}mx+b[/tex]

Answer:

C

Step-by-step explanation:

Squaring is multiplying a number by itself

Examples:

2 x 2 = 4

3 x 3 = 9

4 x 4 = 16

etc.

AB = AD [Given]

BC = CD [Given]

AC = AC [Same line segment]

So, ΔABC ≅ ΔADC [By SSS congruence criteria]

So, ∠ABC = ∠ADC [CPCT (Corresponding parts of congruent triangles)]

Hence, proved.

Answer:

I hope it will help U.

Answer:

96

Step-by-step explanation:

First, you find the area of RPQ using 1/2×base×height. That is, 1/2×6×8. And the answer is 24. Then you multiply 24 by 4 to get the area of all the sides excluding the base to get 96.

Answer:

The united nations flag the translation can be any of the blue triangles and the reflection if the flag itself as it is symmetrical

Step-by-step explanation:

The united nations flag the translation can be any of blue triangles and the reflection if the flag itself as it is symmetrical.

When a graph is reflected along an axis, say x axis, then that leads the graph to go just in opposite side of the axis as if we're seeing it in a mirror.

If we study it more, you will find that its symmetric, thus each point is equidistant from the axis of reflection as that of the image of that point.

If you're reflecting a point (x,y) along x axis, then its abscissa will stay same but ordinates will negate. Thus (x,y) turns to (x, -y)

Similarly, if you're reflecting a point (x,y) along y axis, the resultant image of the point will be (-x,y)

Therefore, The united nations flag the translation can be any of blue triangles and the reflection if the flag itself as it is symmetrical.

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Answer:

hahaaaaaaaaaaaaaaaaa

Step-by-step explanation:

Answer:

IF the signs ARE same the result is a POSITIVE, if the signs are NOT the same the result is NEGATIVE

Step-by-step explanation:

Answer:

8

Step-by-step explanation:

6x+5=53

6x=48

6x/6=48/6

x=8

Answer:

153*10^3

Step-by-step explanation:

I assumed the first exponential number as 1

[tex]\huge\text{Hey there!}[/tex]

[tex]\huge\boxed{\mathsf{(3.4 \times 10^4)(4.5 \times 10^3)}}\\\huge\boxed{\mathsf{\rightarrow 3.4\times10^4 \times 4.5 \times 10^3}}[/tex]

[tex]\huge\boxed{\mathsf{10^4}}\\\huge\boxed{= 10\times10\times10\times10}\\\huge\boxed{= 100\times100}\\\huge\boxed{= 10,000}\\\\\\\huge\boxed{\mathsf{10^3}}\\\huge\boxed{=10\times10\times10}\\\huge\boxed{= 100\times10}\\\huge\boxed{= 1,000}[/tex]

[tex]\huge\boxed{\rightarrow\mathsf{3.4\times \bold{10,000} \times 4.5 \times \bold{1,000}}}}[/tex]

[tex]\huge\boxed{\mathsf{3.4\times10,000}}\\\huge\boxed{= 34,000}\\\\\\\huge\boxed{\mathsf{4.5\times1,000}}\\\huge\boxed{{= 4,500}}}[/tex]

[tex]\huge\boxed{\mathsf{\rightarrow\bf 34,000\times4,500}}\\\huge\boxed{\rightarrow\mathsf{ORIGINAL \ ANSWER: \frak {153,000,000}}}}[/tex]

[tex]\huge\boxed{\textsf{Your answer: }\mathsf{153\times10^6}}\huge\checkmark[/tex]

[tex]\huge\text{Good luck on your assignment \& enjoy your day!}[/tex]

~[tex]\huge\boxed{\frak{Amphitrite1040:)}}[/tex]

Answer:

i have no idea that's why I need ur help

Answer:

2400

which is not having any remainder as 2400÷60=40

Step-by-step explanation:

Answer:

[tex]2(a + 1) \times (3a + 5)[/tex]

Step-by-step explanation:

[tex]6(a + 1 {)}^{2} + 4(a + 1)[/tex]

➡️ [tex]2(a + 1) \times (3(a + 1) + 2)[/tex]

➡️ [tex]2(a + 1) \times (3a + 3 + 2)[/tex]

➡️ [tex]2(a + 1) \times (3a + 5)[/tex]

Answer:

139,999

Step-by-step explanation:

If the digit sum of n is divisible by 5, the digit sum of n+1 can't physically be divisble by 5, unless we utilise 9's at the end, this way whenever we take a number in the tens (i.e. 19), the n+1 will be 1 off being divisble, so if we take a number in the hundreds, (109, remember it must have as many 9's at the end as possible) the n+1 will be 2 off being divisble, so continuing this into the thousands being three, tenthousands being 4, the hundred thousands will be 5 off (or also divisble by 5). So if we stick a 1 in the beginning (for the lowest value), and fill the last digits with 9's, we by process of elimination realise that the tenthousands digit must be 3 such that the digit sum is divisible by 5, therefore we get 139,999

Notice that a number is only divisible by 5 if it ends in 5 or 0.

Only using this, we will find that the number is 49,999

Suppose we wanted the sum of the digits to end in 5, then we could have something like:

23

2 + 3 = 5

if we add 1, we get:

23 + 1 = 24

2 + 4 = 6

This will happen always.

instead, if we use a 0 as the last digit of the sum, we get:

For example, the simplest one:

19

we have:

1 + 9 = 10

10 is divisible by 5.

if we add 1, we get:

19 + 1 = 20

2 + 0 = 2

2 is not divisible by 5.

We have a  problem again, but this time you can see that the whole structure of the number does change. So we should keep trying with ones and nines.

Now we need to modify our number to the point we get n + 1 to be divisible by 5.

if we add a 9 to the right side of our number, we get:

199

1 + 9 + 9 = 19

clearly, not divisible by 5.

Here we need to add a 1 at the left side to make it divisible by one, so we get:

1199

1 + 9 + 1 + 9 = 20

this is divisible by 5.

now let's add 1:

1,199 + 1 = 1,200

1 + 2 = 3

3 is not divisible by 5.

Now, if you look at the two numbers we used, we can see that:

for 19, the sum of the digits + 1 gave us a 2.

for 1,199, the sum of the digits +1 gave us a 3.

then just let's add two ones and two nines.

We will get:

11,119,999

adding the digits:

1 + 1 + 1 + 1 + 9 +9 +9 +9 = 40

is divisible by 5.

Adding one to our number, we can get:

11,119,999 + 1= 11,120,000

Adding the digits:

1 + 1 + 1 + 2 + 0 + 0+ 0+ 0 = 5

divisible by 5.

Now, we can group the ones together, so instead of the number 11,119,999

we can have 49,999, which is way smaller.

Adding the digits, we get:

4 + 9 + 9 + 9 + 9 = 40

And adding one to our number, we get:

49,999 + 1 = 50,000

Adding the digits:

5 + 0 + 0 +0 + 0 = 5

So we found the smallest number n such that the sum of the digits of n is divisible by 5, and the sum of the digits of n + 1 is also divisible by 5.

If you want to learn more, you can read:

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Answer:

The loss percentage is 37.5%

Step-by-step explanation:

Cost Price = 500 × 100/125 = 400

New selling price = Rs. 250 ⇒ Loss = 400 – 250 = 150

Loss percentage = 100 × 150/400 = 37.5%.

Answer:

63

Step-by-step explanation:

6x + 3y - 9

x = 6

y = 9

6(6) + 3(9)

36 + 27

= 63

[tex]\\ \rm\Rrightarrow 11+7x=-17[/tex]

[tex]\\ \rm\Rrightarrow 7x=-7-11[/tex]

[tex]\\ \rm\Rrightarrow 7x=-28[/tex]

[tex]\\ \rm\Rrightarrow x=\dfrac{-28}{7}[/tex]

[tex]\\ \rm\Rrightarrow x=-4[/tex]

Answer: x = -4

Step-by-step explanation:

Given equation

11 + 7x = -17

Subtract 11 on both sides

11 + 7x - 11 = -17 - 11

7x = -28

Divide 7 on both sides

7x / 7 = -28 / 7

[tex]\boxed{x=-4}[/tex]

Hope this helps!! :)

Please let me know if you have any questions

Answer:

The correct choice is option B. (5, 2)

Step-by-step explanation:

The rotation rule of 180° is = (x ,y) -> ( -x , -y) .

Coordinates of C before the rotation are ( -5 , -2) so according to the rule above they will now be = C'( 5 , 2 ) .

Therefore, the ordered pair for C' is (5, 2) after the 180 degrees rotation.